Answer: 10^5
Explanation:
Diana hangs a lead cylinder with a force of 12 N from a model bridge.
Which vector(s) accurately illustrates the reaction force of the bridge on the lead cylinder?
The action and reaction law allows us to find that the reaction force, the weight of the cylinder, is:
12 N force directed upward
Newton's third law or action and reaction law, establishes that if two bodies interact with each other the force that one applies to the other, is equal in magnitude to the force of the second on the first but in the opposite direction, that is, all forces act in pairs one in each body that interact.
Forces with these characteristics are called action and reaction.
In this case we have a hanging cylinder, with the cylinder it has mass so the weight is 12 N it acts on the table in a downward direction, let's say this is the action force.
In response to this force, the table exerts a force on the cylinder of equal magnitude but in the opposite direction, which is why it is directed upwards.
let's analyze the force diagram
When analyzing the forces shown in the diagram, the forces of equal magnitude to the weight are the first twoThe weight is directed downward, the answer must be directed upward.
In conclusion using theaction and reaction law we find that the answer for reaction force is:
12 N force directed upward
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Question 4 of 10 Which three components define a person's overall health? A. Mental and emotional health B. Social health C. Physical health D. Public health
Answer:
physical, social, and mental
Explanation:
Answer:
A,B,C
Explanation:
These three maintain the overall health of the person being. Take for instance an example a cake, it has layers that make the overall cake. So it is with the persons health, it takes all three of these feilds to make the overall health.
Jenny puts a book on her desk. Jenny’s book has an area of 200 cm2.It exerts a pressure of 0.05 N/cm2 on the desk. What is the weight of the book? *
A computational model predicts the maximum kinetic energy a roller coaster car can have given its mass, the speed at the highest point of its journey, and the height of the highest point. The mass is 250 kg, and the highest point of the journey is at 30m, where the cart is at rest. What is the maximum kinetic energy?
A. 113500 J
B. 468750 J
C. 0 J
D. 73500 J
Answer:
D
Explanation:
The decrease in potential energy is equal to the increase in kinetic energy.
mgh
250 x 9.8 x 30
=73, 500
Answer:
73,500 J
Explanation:
100% Correct
Students are asked to design an experiment about Newton’s 2nd Law. One student decides to roll a marble down a ramp into a pile of sand to measure the force impact.
Which variable should she manipulate to best exemplify the relationship explained by this law?
A.She should use a heavier marble, because the marbles will roll at the same rate of acceleration but more mass will produce a larger impact force.
B.She should increase the slope of the ramp by propping it up to higher height, because a steeper ramp will cause a greater rate of acceleration and a larger impact force.
C.She should use a heavier marble, because a bigger marble will accelerate more quickly down the ramp and cause a greater impact force.
D.She should decrease the slope of the ramp, because a ramp with a smaller slope will allow the ball more time to build up speed and cause a greater impact force.
Answer:
A
Explanation:
Trust me I just took it !
Jake and Amir are both standing on identical skateboards and
perform a physics experiment in which they push off one
another to move. Jake is taller and more massive than Amir. If
Jake pushes with 20 N of force, what force would he feel
backwards away from Amir? F= N
Answer: 20
Explanation:
If Jake pushes with 20 N of force, the force that he would feel backwards away from Amir is 20N
Force simply means the strength or energy that can later the position of an object. Force can also be described as a push or pull.
It should be noted that since Jake pushes with 20 N of force, the force that he would feel backwards away from Amir will be the exact force that was used in pushing.
This will therefore be 20 Newton as well.
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a car travels west at 40 km/h
a man on a bike travels at 10 km/h
what is the speed of the car relative to the speed of the bicycle ?
Answer:
The car is going 0 km/h more than the bike
Explanation:
What is the period of a rotating object if it spins 24 times in 13 seconds?
Answer:
The period is 0.54 seconds
Explanation:
Period (T)
Is the time required for a rotating object to make one complete revolution around a circular path.
If it takes a time t to complete n revolutions, the period is:
[tex]\displaystyle T=\frac{t}{n}[/tex]
The rotating object spins n=24 times in t=13 seconds, thus its period is:
[tex]\displaystyle T=\frac{13}{24}[/tex]
T = 0.54 sec
The period is 0.54 seconds
How do invasive species impact long term biodiversity in an economy?
Answer:
Invasive species alter and degrade the environment, and have a negative effect on both native species and the people who live and work there. The impacts of invasive species include: Reduced biodiversity. Decreased availability and quality of key natural resources.
Explanation:
Hope this helps!
plzzzz help me this is due today. only need help with these two questions and the element is oxygen.
How do protons, neutrons, and electrons differ in terms of their electrical charges and locations within the atom?
Describe the four fundamental forces. Which of these forces are involved in chemical bonding?
Answer: thanks for the point
Explanation:
What is a material that can dissolve in another material called?
Slippery
Physical
Soluble
Insoluble
Answer:A material that can dissolve in another material called Soluble
Explanation:
Answer:
Option 3.
Soluble is the correct/best answer choice.
it takes 5100 N of force to accelerate a ford mustang 3 m/s2 what is the mass of the car
Answer:
1700 kg
Explanation:
The mass of the ford mustang car be 1700 kg.
What is mass?In physics, mass is a quantitative measurement of inertia, a basic characteristic of all matter. It essentially refers to a body of matter's resistance to changing its speed or location in response to the application of a force.
The change caused by an applied force is smaller the more mass a body has. The kilograms serves as the unit of mass in the International System of Units (SI).
Given parameters:
Force applied on the ford mustang car: F = 5100 N.
Acceleration of the ford mustang car: a = 3 m/s^2.
So, The mass of the ford mustang car be = force/acceleration
= 5100/3 kg.
= 1700 kg.
Hence, the mass of the ford mustang car be 1700 kg.
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If you are trying to hit a baseball as far as possible, you would want to:
apply a small force over a short time
apply a small force over a long time
apply a large force over a short time
apply a large force over a long time
A car travels 14 km due west, then does a
U-turn, and travels 43 km due west.
I. What total distance has the car
traveled?
II.
What is the total displacement of the
car?
III. If the entire trip took 3.20 hours.
determine the average speed of the
car. Give
your answer in both
km hour, and m s. (show
conversion)
IV. If the entire trip took 2.50 hours.
determine the average velocity of
the car. Give your answer in both
km h, and mph (show conversion)
Explanation:
It is given that,
A car travels 14 km due west, then does a U-turn and travels 43 km due east (when it takes U-turn, it will change direction from west to east)
i. Total distance = total path covered
= 14 km + 43 km
= 57 km
ii. Let east is positive and west is negative.
Displacement = final position-initial position
= 43-14
= 29 km
iii. If time taken in the entire trip = 3.2 hours
Average speed = distance/time
[tex]s=\dfrac{57\ km}{3.2\ h}\\\\=17.81\ km/h[/tex]
1 km/h = 0.2777 m/s
17.81 km/h = 4.94 m/s
iv. If time taken in the entire trip = 2.5 hours
Average velocity = displacement/time
[tex]v=\dfrac{29\ km}{2.5\ h}\\\\=11.6\ km/h[/tex]
1 km/h = 0.621 mph
11.6 km/h = 7.2 mph
Henc, this is the required solution.
Biker 1 is on a motorcycle facing West is initially at rest. The motorcycle speeds up from rest to 25 mph in three seconds.
Biker 2 is right by his side to start. He speeds up from rest to 85 mph in eight seconds.
Which biker has a greater acceleration?
Biker 1's acceleration:
(25 mph) / (3 s) = ((25 mi/h) • (1/3600 h/s)) / (3 s) ≈ 0.00231 mi/s²
Biker 2's acceleration:
(85 mph) / (8 s) = ((85 mi/h) • (1/3600 h/s)) / (8 s) ≈ 0.00295 mi/s²
Biker 2 has the greater acceleration.
The radius of the planet Mercury is 2.43 x 10^6m and its mass
is 3.2 x 10^23 kg. What is the speed of a satellite in orbit
265.000 m above the surface?
[tex]\huge\boxed{Option D}[/tex]
_____________________________________DATA:Radius of Mercury = [tex]R_m[/tex] = [tex]2.43x10^6m[/tex]
Mass of Mercury = [tex]M_m = 3.2x10^{23}m[/tex]
Distance Satellite above the surface of the Mercury = d = 265,000m
Gravitational Constant = [tex]G = 6.67x10^{-11} \frac{N.m^2}{kg^2}[/tex]
_____________________________________SOLUTION:Since the Satellite is orbiting around the Planet Mercury, due to the centripetal force, and Centripetal force is the force that acts towards the center of the circle, Whereas The gravitational force also acts towards the center of the circle thus we can say that Centripetal force is equal or same as centripetal force. So,
[tex]F_g =F_C[/tex]
Fg is Given by,
[tex]F_g = \frac{GM_MM_S}{r^2}[/tex]
Fc is Given by,
[tex]F_c=\frac{M_SV^2}{r}[/tex]
Where,
G is Gravitational Constant
[tex]M_e[/tex] is mass of Planet Mercury
[tex]M_S[/tex] is Mass of Satellite
r(small letter) is the distance between the center of the Planet Mercury and the satellite.
V is velocity of satellite
_____________________________________Now,
[tex]\frac{GM_MM_S}{r^2} =\frac{M_SV^2}{r}[/tex]
[tex]V = \sqrt\frac{GM_M}{r}[/tex]
r can also be written as,
[tex]V = \sqrt\frac{GM_M}{R_M +d}[/tex]
Substitute the variables,
[tex]V = \sqrt{\frac{(6.67x10^{-11})x(3.2x10^{23})}{2695000}[/tex]
Simplify the equation,
V = 2814 [tex]\frac{m}{s}[/tex]
Approximately,
V = 2800 [tex]\frac{m}{s}[/tex]
_____________________________________Best Regards,'Borz'In how many ways can chemical reaction takes place? what are they?
Answer:
Chemists classify chemical reactions in a number of ways: by type of product, by types of reactants, by reaction outcome, and by reaction mechanism. Often a given reaction can be placed in two or even three categories, including gas-forming and precipitation reactions.
Explanation:
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A 8.0\,\text {kg}8.0kg8, point, 0, start text, k, g, end text box is released from rest at a height y_0 =0.25\,\text my 0 =0.25my, start subscript, 0, end subscript, equals, 0, point, 25, start text, m, end text on a frictionless ramp. The box slides from the ramp onto a rough horizontal surface. The box slides 2.0\,\text m2.0m2, point, 0, start text, m, end text horizontally until it stops.
Answer:
μ = 0.125
Explanation:
To solve this problem, which is generally asked for the coefficient of friction, we will use the conservation of energy.
Let's start working on the ramp
starting point. Highest point of the ramp
Em₀ = U = m h y
final point. Lower part of the ramp, before entering the rough surface
[tex]Em_{f}[/tex] = K = ½ m v²
as they indicate that there is no friction on the ramp
Em₀ = Em_{f}
m g y = ½ m v²
v = [tex]\sqrt{2gy}[/tex]
we calculate
v = √(2 9.8 0.25)
v = 2.21 m / s
in the rough part we use the relationship between work and kinetic energy
W = ΔK = K_{f} -K₀
as it stops the final kinetic energy is zero
W = -K₀
The work is done by the friction force, which opposes the movement
W = - fr x
friction force has the expression
fr = μ N
let's write Newton's second law for the vertical axis
N-W = 0
N = W = m g
we substitute
-μ m g x = - ½ m v²
μ = [tex]\frac{v^{2} }{2 g x}[/tex]
Let's calculate
μ = [tex]\frac{2.21^{2}}{2\ 9.8\ 2.0}[/tex]
μ = 0.125
A 8.0 kg box is released from rest at a height y0 = 0.25 m on a frictionless ramp. The box slides from the ramp onto a rough horizontal surface. The box slides 2.0 m horizontally until it stops.
What is the friction coefficient of the horizontal surface?
Answer: 0.125
Help please! I hope the given possibles help
Answer:
The answer is "[tex]5.184 \times 10^{23}[/tex] kg"
Explanation:
Given:
[tex]g= 6.003 \ \frac{m}{s^2}\\\\G= 6.67 \times 10^{-11} \ \frac{N - m^2}{kg^2}\\\\M=?\\\\radius= 2,400 \ km\\\\[/tex]
Calculating diameter:
[tex]Diameter =radius \times 2[/tex]
[tex]=24\times 10^5 \times 2\\\\=48 \times 10^5 \ m[/tex]
The formula for mass calculation:
[tex]\to g = G \times \frac{M}{(\frac{d^2}{4})}\\\\\to g=G\times \frac{4M}{d^2}\\\\\to 4M= \frac{g \times d^2}{G} \\\\\to M= \frac{g \times d^2}{4G} \\\\[/tex]
[tex]=\frac{6.003 \times (48 \times 10^{5})^2}{4 \times 6.67 \times 10^{-11}}\\\\=\frac{6.003 \times 2,304 \times 10^{10}}{26.68\times 10^{-11}}\\\\=\frac{13,830.912 \times 10^{10}}{26.68\times 10^{-11}}\\\\=518.4 \times 10^{21}\\\\= 5.184 \times 10^{23}\\\\[/tex]
A box is sitting stationary on a long level ramp on level ground. The coefficient of static friction is (1.0). One end of the ramp is slowly lifted higher and higher. What is the angle of the ramp with respect to the ground when the box begins slidig?
Answer:
45 degrees
Explanation:
Given that the coefficient of friction, [tex]\mu=1.0[/tex]
Let the angle of the ramp be [tex]\theta[/tex].
The gravitational force acting downward [tex]=mg[/tex]
The normal reaction by the ramp on the box, [tex]N=mg\cos\theta[/tex]
So, the maximum frictional force that can act on the box, [tex]f= \mu N[/tex]
The force along with the plane in the direction of sliding, [tex]F = mg\sin\theta[/tex]
When the box begins sliding, the F must have to overcome the frictional force,f.
So, F=f
[tex]mg\sin\theta=\mu N \\\\mg\sin\theta=\mu mg\cos\theta \\\\\frac {\sin\theta}{\cos\theta}=\mu \\\\\tan\theta=\mu \\\\\theta=\tan^{-1}\mu \\\\[/tex]
Putting the value of \mu, we have
[tex]\theta=\tan^{-1}1[/tex]
[tex]\theta=45[/tex] degrees.
Hence, the angle of the ramp with respect to the ground when the box begins sliding is 45 degrees.
1. A large ocean liner floating in the sea has a volume of
375 000 m² and displaces 50 000 m² of sea water. Determine the
density and mass of the ship. Explain why, despite being made
of metal, the ship is able to float.
Answer:
Density of the ship :133.33 kg/m³
Mass of the ship :50,000,000 kg
Ships are able to float on water because they displace a volume that equals their own weight
Explanation:
The formula for density is ;
Density = Mass/Volume
But the mass of displaced fluid is give by the formula;
m=ρV where ρ is density of the fluid and V is volume of water displaced
Volume of liner= 375000 m³
Volume displaced = 50000 m³
The volume of the water displaced is equal to mass of the liner
I m³ = 1000 kg
50000 m³ = 50000*1000 =50,000,000 kg
50,000,000 kg ----------mass of the ship
So if ;
m= 50,000,000 kg
v= 375000 m³
ρ = m/V
ρ = 50,000,000/375000
ρ = 50,000,000/375000
ρ =133.33 kg/m³
Ships are able to float on water because they displace a volume that equals their own weight. Additionally, the air contained in the spaces of the ship inside is much less dense than density of water aiding in the floating process.
Please help! Will mark brainliest!
Answer:
im pretty sure its d
Explanation:
Assuming that the acceleration of an object due to gravity is ag = 10 m/s2, it is possible to find the distance an object falls when dropped by using the equation ay = \frac{1}{2} ag t2. Using this value for gravity, how far would an object drop after 5.0 s?
105 m
125 m
135 m
115 m
Answer:
125 m
Explanation:
i just did the edpuzzle
What energy transformations take place from the outlet charger to the ringing phone?
Explain how the Law of Conservation of Energy applies to the energy
transformations that occur from the outlet charger to the ringing phone.
Answer:
Chemical energy transformations take place from the outlet charger to the ringing phone.
Explanation:
chemical energy
While charging the mobile electrical energy gets transformed into chemical energy. Most of the contemporary mobile phone batteries are lithium-ion batteries where the power is saved by the chemical transformations in the ionic structure of the battery. When the power gets into the mobile phone it is transformed and collected as chemical energy inside of the battery and when we utilize the mobile the earlier saved chemical energy is again transformed into electrical energy.
The energy transformation that takes place from the outlet charger to the
ringing phone is electrical energy from the outlet is converted to chemical
energy and back to electrical energy and sound energy when the phone is
being used and ringing.
The charger provides a source of electrical energy which gets converted to
chemical energy stored in the battery. During use, the chemical energy gets
converted to electrical energy to power the phone and to sound energy
when it rings with heat energy being dissipated also.
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What are the forces that resist motion that make Newton's 1st Law hard to completely visualize on Earth?
A car of mass 1500 kg starting from rest can reach a speed of 20
m/s within 10 seconds. Calculate the accelerating force of the car
engine.
Explanation:
F=MA
F=1500 * 2
F=3000N
After 4 half-lives, I ended up with 10 gram sample of
Carbon-14. What was the original amount of Carbon-14
that I started with?
Answer:
80g
Explanation:
The half - life is the time taken for half of radioactive substance to decay to half of its original composition.
After 4 half lives, the carbon - 14 sample is 10grams
Now let us trace the decay of this substance;
At the 3rd half life, it will have double the amount at the 4th half life;
2 x 10 = 20g
At the 2nd half life, there will be double the amount at the 3rd half life;
20 x 2 = 40g
Originally, we are going to have;
40 x 2 = 80g
What two things does force depend on
A teacher opens a window on a cold day. Which statement explains why the room starts to feel cooler? (1 point)
0 Air moves from the areas of higher temperature to areas of lower temperature
O Cold air is moving into the room from outside.
0 The density of the air is lower on the inside than on the outside
0 The kinetic energy of the air molecules outside is higher than the kinetic energy of the air molecules inside.
Answer:
Air moves from the areas of higher temperature to areas of lower temperature.
Explanation:
this is because hotter temperatures seek out colder temps.
hope this helped!
When a teacher opens a window on a cold day. the room starts to feel cooler because air moves from the areas of higher temperature to areas of lower temperature.
What is convection of heat transfer?The transfer of heat between two bodies by currents of moving gas or fluid is known as convective heat transfer. In free convection, air or water rises and is replaced by a cooler parcel of air or water as it moves away from the hot body.
As air moves from the areas of higher temperature to areas of lower temperature, when the teacher opens a window on a cold day, the air in the room moves out side and cold air takes the position inside the room. So, it feels cooler then.
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In a hydraulic lift, a 620 N force is exerted on a 0.20 m2 piston in order
to support a weight that is placed on a2.0 m2 piston. How much pressure is
exerted on the narrow piston? How much weight(force) can the wide piston lift?
Answer:
Pressure on the narrow piston = 3100 [tex]N/m^2[/tex]
The wider piston can lift the weight up-to 6200 N
Explanation:
Given that the area of the narrow piston = 0.2 [tex]m^2[/tex]
Applied force on the narrow piston, [tex]F_{in}[/tex]= 620 N
Area of the larger piston = 2.0 [tex]m^2[/tex].
As pressure = force/ area,
So. pressure exerted on the narrow piston, [tex]P= 620/0.2=3100 N/m^2[/tex]
There is liquid in between the narrow piston and the larger piston and according to Pascal's law, the pressure inside any liquid is uniformly distributed.
As the narrow piston is applying the pressure on the liquid which is equal to the external pressure applied on the narrow piston, i.e 3100 [tex]N/m^2[/tex].
So, the uniformly distributed pressure in the fluid is 3100 [tex]N/m^2[/tex].
Now, the liquids apply pressure on the larger piston,
as force = Area x pressure, so the applied on the larger piston, [tex]F_{out}[/tex], by the liquid is
[tex]F_{out} = 3100\times2=6200[/tex] N
Hence, the wider piston can lift the weight up-to 6200 N.