What's the formula for an arc of a circle?

Answer:

What are you trying to do you have not Explained to us

Step-by-step explanation:

Step-by-step explanation:

1) C

2) B

5) C

6)D

7) D

8) B

9) Figure not clear

10) C

11) D

12) B

13) D

14) A

15) D

P.S try to do ur own tests

Answer:

the x is 538

Step-by-step explanation:

sorry if im not right

Answer

Force a perfect square trinomial on the left side. Take the square root of both sides and solve for

3√  3, − 5 − 3 √ 3

Step-by-step explanation:

Answer:

14000

Step-by-step explanation:

The number in the thousands place is 4 so we look at the number after it which is 2:

Using the rounding rule, the number 2 is below 5 so we keep the 4 at 4:

So our answer is 14000.

Answer:

14000

Step-by-step explanation:

Since they are asking for us to round it to the nearest thousands, we have to look at the hundreds place to figure out whether we should round up or down. The number in the hundreds place is 2, and that means we round down to 14000 ("four or less, let it rest. five or more, raise the score").

Therefore, 14295.67 rounded to the nearest thousand is 14000.

I hope this helps! Have a lovely day!! :)

Answer:

2√6

using pythagoras theorem:

a² + b² = c²

Answer:

Step-by-step explanation:

The length of the third side can be determined using pythogoras theorem. Keep in mind that pythogoras theorem can only be used when finding the missing side length of a right triangle.

[tex]\text{Pythagoras theorem: (Longest side})^{2} = (\text{Leg of right triangle}_{1} ) ^{2} + (\text{Leg of right triangle}_{2} )^{2}[/tex]

In this triangle, we are given that:

Substitute the measures into the pythogoras theorem:

[tex](7})^{2} = (5 ) ^{2} + (\text{Leg of right triangle}_{2} )^{2}[/tex]

Simplify both sides of the equation:

[tex]\rightarrowtail (7 \times 7}) = (5 \times 5) + (\text{Leg of right triangle}_{2} )^{2}[/tex]

[tex]\rightarrowtail49 = 25 + (\text{Leg of right triangle}_{2} )^{2}[/tex]

Subtract 25 both sides:

[tex]\rightarrowtail49 - 25 = 25 - 25 +(\text{Leg of right triangle}_{2} )^{2}[/tex]

[tex]\rightarrowtail24 = (\text{Leg of right triangle}_{2} )^{2}[/tex]

Square root both sides and simplify:

[tex]\rightarrowtail\sqrt{24} = \sqrt{(\text{Leg of right triangle}_{2} )^{2}}[/tex]

[tex]\rightarrowtail\sqrt{3 \times 2\times 2 \times 2} = \sqrt{(\text{Leg of right triangle}_{2} )^{2}}[/tex]

[tex]\rightarrowtail2\sqrt{3 \tim \times 2} = \text{Leg of right triangle}_{2}[/tex]

[tex]\rightarrowtail\boxed{2\sqrt{6} \ \text{units} = \text{Leg of right triangle}_{2}}[/tex]

Answer:

See below ↓↓↓

Step-by-step explanation:

Part A

Total length = Side 1 + Side 2

Part B

Length of 3rd side = Perimeter - [Side 1 + Side 2]

Part C

Yes, as the resulting polynomial has a finite value we can conclude that polynomials are closed under addition and subtraction.

Part A: The total length of the two sides of the triangle is [tex]5x^2+7x-4[/tex]. This is obtained by adding the given two sides.

Part B: The length of the third side is [tex]5x^3-x^2-8x+1[/tex]. This is obtained by subtracting the sum of two sides from the perimeter of the triangle.

Part C: Yes, the Part A and Part B answers show that the polynomials are closed under addition and subtraction. This is because the expressions have like terms.

Given that, a triangle has two sides of length [tex]3x^2-2x-1[/tex] and [tex]9x+2x^2-3[/tex]

The perimeter of the triangle is [tex]5x^3+4x^2-x-3[/tex]

Part A:

To find the total length of two sides, adding the two side

⇒ [tex](3x^2-2x-1)+9x+2x^2-3\\[/tex]

⇒ [tex]5x^2+7x-4[/tex]

(adding the like terms w.r.t their sign)

Part B:

To find the length of the third side, subtract the sum of two sides from the perimeter.

⇒ [tex](5x^3+4x^2-x-3)-(5x^2+7x-4)[/tex]

⇒ [tex]5x^3-x^2-8x+1[/tex]

Part C:

From Part A and Part B, it is proved that the polynomials undergo addition and subtraction. Hence, it is justified.

Therefore, Part A, Part B, and Part C were obtained.

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Answer:

-4

Step-by-step explanation:

<symbol means squared or increase and so does ( )

Answer:

can you clear more I don't understand

According to the information, it can be inferred that the volume of the ice cream is close to 207.33 cm³

To calculate the volume of the maxicool, we must calculate the volume of the sphere of ice cream, and the volume of the cone that is filled with ice cream.

V = [tex]\frac{4}{3}[/tex] × π × R³

V = [tex]\frac{4}{3}[/tex] × π × 3³

V = 113.09 cm³

V = [tex]\frac{1}{3}[/tex] × π × R² × h

V = [tex]\frac{1}{3}[/tex] × π × 3² × 10

V= 94.24 cm³

Finally we must add both values to know the total volume of the maxicool.

113.09 + 94.24 = 207.33 cm³

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Answer:

a movement one single movement cultivating one group

Answer: C

Step-by-step explanation:

Answer:

On a linear graph, the rate of change is called the slope of a line

Step-by-step explanation:

Hope this helps

The complete statement is, on a linear graph, the rate of change is called the slope of a line.

We know lines have various types of equations, the general type is

Ax + By + c = 0, and the equation of a line in slope-intercept form is

y = mx + b.

Where slope = m and b = y-intercept.

the slope is the rate of change of the y-axis with respect to the x-axis and the y-intercept is the (0,b) where the line intersects the y-axis at x = 0.

From the above concepts we now know that, on a linear graph, the rate of change is called the slope of a line.

It can also be defined as, (y₂ - y₁)/(x₂ - x₁).

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Answer:

An exponent is a number that is to a certain value, like 5^2.

The ^2 means multiply by itself by itself ONCE,

so it would be 5x5.

5^3 means multiply it by itself TWO TIMES,

and going on and on.

Let's say you have a test and the question it's asking is to simplify 5^4.

It's 5x5x5x5, multiplying it by itself FIVE TIMES.

Hope this helped!

Answer:

for number 6 the width is 24 and the blank after the length of 9 is 12 and after 48 width it is 60. your welcome.

Answer:

Mean = 8 gerbils

MAD = 4.29 gerbils

Step-by-step explanation:

Find the mean:

Mean= 0+3+6+9+11+13+14 ÷ 7

Mean = 56 ÷ 7

Mean = 8 gerbils

you have to find the distance of each value of gerbil from the mean

8,5,2,1,3,5,6

MAD = 9+6+3+0+2+4+5 ÷ 7

MAD = 30 ÷ 7

MAD = 4.29  gerbils

Answer:

3090%

Step-by-step explanation:

425.89 - 395.00 = 30.89

Round to the nearest tenth = 30.9

Convert to a percentage = 3090%

As shown, to obtain the blue quilt block pattern, we have to rotate the parallelogram.

A parallelogram is a quadrilateral consisting of pairs of parallel sides.

To obtain the blue quilt block pattern, we have to rotate the parallelogram. This rotation allows the parallelogram to take on a new orientation, and when it is positioned correctly, it creates the blue quilt block pattern. The process of rotating the parallelogram may seem simple, but it is a critical step in achieving the desired quilt design. It requires attention to detail and precision to ensure that the parallelogram is correctly rotated, and the resulting blue quilt block pattern is aligned correctly.

Moreover, the correct rotation of the parallelogram can significantly impact the overall appearance of the quilt, and even a slight misalignment can make a noticeable difference. Therefore, it is important to carefully follow the instructions to rotate the parallelogram to achieve the intended blue quilt block pattern.

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Answer:

0.6%

Step-by-step explanation:

40% is the percentange of how many students play an instrument. (the whole) 20% is how many freshmen play. (part)

30% are the freshmen. 30% is over 100%.

20 x 100= 2000 and 40 x 30= 1200.

With the answers we got (2000 and 1200) we divide!!

2000÷1200=0.6

Which means the probabillity that the student is a random freshmen is 0.6% :)

Answer:

<DFE

Step-by-step explanation:

Verticle angles are when they are directly apart and equal. So,

Answer:

6

Step-by-step explanation:

, , , , ,, , , , , , , , ,sssss

Step-by-step explanation:

It is given that, the sum of two positive integers is 31 and the sum of the squares of these numbers is 625 and we are to find the smaller of the numbers.

So, let the two positive integers be x and y.

Therefore,

[tex] \\ {\longrightarrow \pmb{\sf {\qquad x + y = 31 \: \: ........ \: (i) }}} \\ \\[/tex]

[tex]{\longrightarrow \pmb{\sf {\qquad x {}^{2} + y {}^{2} = 625 \: ...... \: (ii)}}} \\ \\[/tex]

Now, From the first equation we have,

[tex]\\ {\longrightarrow \pmb{\sf {\qquad x + y = 31 }}} \\ \\ [/tex]

[tex] {\longrightarrow \pmb{\sf {\qquad y = 31 - x \: ...... \: (iii)}}} \\ \\ [/tex]

Now, substituting the value of y in equation (ii) we get :

[tex] \\ {\longrightarrow \pmb{\sf {\qquad x {}^{2} + (31 - x) {}^{2} = 625}}} \\ \\ [/tex]

[tex]{\longrightarrow \pmb{\sf {\qquad x {}^{2} + (31 {}^{2} - 2.x.31 + x{}^{2} ) = 625}}} \\ \\ [/tex]

[tex]{\longrightarrow \pmb{\sf {\qquad x {}^{2} + (961 - 62x + x{}^{2} ) = 625}}} \\ \\ [/tex]

[tex]{\longrightarrow \pmb{\sf {\qquad x {}^{2} + 961 - 62x + x{}^{2} - 625 = 0}}} \\ \\ [/tex]

[tex]{\longrightarrow \pmb{\sf {\qquad 2 x {}^{2} + 336 - 62x = 0}}} \\ \\ [/tex]

[tex]{\longrightarrow \pmb{\sf {\qquad 2 x {}^{2} - 62x + 336 = 0}}} \\ \\ [/tex]

[tex]{\longrightarrow \pmb{\sf {\qquad 2( x {}^{2} - 31 + 168) = 0}}} \\ \\[/tex]

[tex]{\longrightarrow \pmb{\sf {\qquad \frac{2}{2} ( x {}^{2} - 31 + 168) = \frac{0}{2} }}} \\ \\[/tex]

[tex]{\longrightarrow \pmb{\sf {\qquad x {}^{2} - 31 + 168 = 0}}} \\ \\[/tex]

Now using the quadratic formula :

[tex]{\longrightarrow \pmb{\sf {\qquad x = \frac{ - b \pm \sqrt{ {b}^{2} - 4ac} }{2a} }}} \\ \\[/tex]

Where,

[tex] \\ [/tex]

[tex]{\longrightarrow \pmb{\sf {\qquad x = \frac{ - (- 31) \pm \sqrt{ {31}^{2} - 4(1)(168)} }{2(1)} }}} \\ \\[/tex]

[tex]{\longrightarrow \pmb{\sf {\qquad x = \frac{ 31 \pm \sqrt{ 961 -672} }{2(1)} }}} \\ \\[/tex]

[tex]{\longrightarrow \pmb{\sf {\qquad x = \frac{ 31 \pm \sqrt{ 289} }{2(1)} }}} \\ \\[/tex]

[tex]{\longrightarrow \pmb{\sf {\qquad x = \frac{ 31 \pm 17 }{2(1)} }}} \\ \\[/tex]

Now, we have two equations,

[tex]{\longrightarrow \pmb{\sf {\qquad x = \frac{ 31 + 17 }{2} \: ... .....\: (iv)}}} \\ \\[/tex]

[tex]{\longrightarrow \pmb{\sf {\qquad x = \frac{ 31 - 17 }{2} ... .....\: (v)}}} \\ \\[/tex]

So, Equation (iv) :

[tex] \\ {\longrightarrow \pmb{\sf {\qquad x = \frac{ 31 + 17 }{2} }}} \\ \\ [/tex]

[tex]\\ {\longrightarrow \pmb{\sf {\qquad x = \frac{ 48 }{2} }}} \\ \\ [/tex]

[tex]\\ {\longrightarrow \pmb{\sf {\qquad x = 24 }}} \\ \\ [/tex]

Now, Equation (v) :

[tex] \\ {\longrightarrow \pmb{\sf {\qquad x = \frac{ 31 - 17 }{2}}}} \\ \\ [/tex]

[tex]{\longrightarrow \pmb{\sf {\qquad x = \frac{ 14 }{2}}}} \\ \\ [/tex]

[tex]{\longrightarrow \pmb{\sf {\qquad x = \: 7}}}\\ \\ [/tex]

Now, we are to find the value of y.

Substituting the value of x (24) in equation (iii) :

[tex] \\ {\longrightarrow \pmb{\sf {\qquad y = 31 - x \:}}} \\ \\ [/tex]

[tex]{\longrightarrow \pmb{\sf {\qquad y = 31 - 24 \:}}} \\ \\ [/tex]

[tex]{\longrightarrow \pmb{\sf {\qquad y = 7 \:}}} \\ \\ [/tex]

Again, Substituting the value of x (7) in equation (iii) :

[tex]\\ {\longrightarrow \pmb{\sf {\qquad y = 31 - x \:}}} \\ \\ [/tex]

[tex] {\longrightarrow \pmb{\sf {\qquad y = 31 - 7 \:}}} \\ \\ [/tex]

[tex]\\ {\longrightarrow \pmb{\sf {\qquad y = 24 \:}}} \\ \\ [/tex]

Therefore,

[tex] \\ [/tex]

So, The smaller of the numbers is 7 .

The sum of two positive integers is 31. If the sum of the squares of these numbers is 625, find the smaller of the numbers.

This question belongs to quadratic equations so we have to find the answer by making equation and solving it .

According to question , sum of two positive integers is 31 . So ,

According to question , sum of square

of these numbers is 625 . So ,

From equation 1 ( x + y = 31 ) , Value

of x :

Now , putting value of x in eq. 2 :

Solving it by using middle term

splitting :

First number ,

Second Number ,

According to question ,

Sum of numbers is equal to 31 :

Sum of squares of these numbers is equal to 625 :

Answer:

20 and greater than 20

__________________________________________________________

Ask me in the comments box.

Answer:

69

Step-by-step explanation:

Find the area of the rectangle. 15 x 3 = 75.

Find the area of the cut-out triangle.
1/2bh

1/2(3(4))

1/2(12)

6

75 - 6 = 69.

Answer: C (0,5)

Step-by-step explanation:

So firstly you're going to try to solve the inequality, so what I did first is used the second equation because if I divide both sides by 3, I'm able to get the y by itself:

6x+3y>/=15, 6/3=2, 3/3=1, 15/3= 5

So now its: 2x+y>/=5

now I should get the y by itself by subtracting 2x from both sides to get

y>/=15-2x, now if we wanted to plug it in to the top equation, we could make it as, y=15-2x because the it is GREATER THAN OR EQUAL TO.

so to plug it in to the first equation we get:

6x-2(15-2x)<10,

x<4, to find y we just plug it in to any equation now we have x, so I did

6(3)-2y<10

18-2y<10

-18        -18

-2y<10

divide both sides by -2 (flips the equation sign)

y>4,

So take consider both X and Y values, C would be correct because X is less than four and 0 is less than four, and 5 is greater than four.

Answer:

The deck's width is 9 feet
The deck's area is 18 feet

Correct po yan

Hope it helps po

Answer:

Deck Width: 6 Feet

Deck Area: 72 Feet Squared

Step-by-step explanation:

[l = length, w = width, f = feet, p = perimeter, a = area]

A = l x w

P = 2l + 2w [l = 12f, p = 36f]

P = 2l + 2w

=> 36f = 2 (12f) + 2w

=> 36f = 24f + 2w

=> 36f - 24f = 2w

=> 12f = 2w

=> 2w/2 = 12f/2

=> W = 6f

Therefore: Width = 6 Feet

A = l × w

A = 12f × 6f

A = 72f^2

Therefore: Area = 72 Feet Squared

keeping in mind that Mt Everest is 8000 meters, or namely 8 Kilometers, Check the picture below.