What steps could the company take to help ensure that electric engines become the dominant design?

The correct option is (c) 0.5 .

The magnetic field experienced by the patient's protons is 0.5 Tesla.

What is a magnetic field in simple terms?

The area in which the force of magnetism acts around a magnetic material or a moving electric charge is known as the magnetic field. A diagram that shows the magnetic field and how a magnetic force is distributed inside and outside of a magnetic substance.

While opposite poles (north and south) are drawn to one another, the same poles repel one another. The north-seeking poles of the iron's atoms line up in the same direction when it is rubbed against a magnet. A magnetic field is produced by the force that the aligned atoms produce.

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The complete question is:

"If the precessional frequency of the protons net magnetization is approximately 21 MHz, a ____ Tesla magnetic field is being experienced by the patient's protons?

(a) 2.0

(b) 1.5

(c) 0.5

(d) 0.3"

The period of pendulum is still the same at 1.4 seconds.

We need to know about pendulum experiment to solve this problem. The pendulum is a simple experiment to calculate gravitational acceleration. The gravitational acceleration can be calculated by

g = 4π² . L / T²

where g is gravitational acceleration, L is the length of the string and T is the period.

From the question above, we know that:

L = 0.5 meters

m1 = 1 kg

θ = 12⁰

m2 = 2 . m1

T1 = 1.4 seconds

Find the period of pendulum

g = 4π² . L / T²

T² = 4π² . L / g

T = √(4π² . L / g)

The period of a pendulum does not depend on the mass of the object, hence the period is still the same at 1.4 seconds.

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It is a false statement that Scientific study can always be categorized as belonging to only one of the three major categories of sciences.

A scientific study involves an investigation into issues that has to do a scientific topic. There are three main branches of science which are physics, chemistry and biology. However most of the research in science is interdisciplinary. It involves a synergy between the various fields of science.

Thus, it is a false statement that Scientific study can always be categorized as belonging to only one of the three major categories of sciences.

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We must use the principles of the balance of forces to resolve this exercise.

What is centrifugal force?

A hypothetical force called centrifugal force, which is unique to particles traveling in a circle, is a force that has the same strength and dimensions as the centripetal force, but acts in the opposite direction.

The force exerted on the satellite by the planet in this specific instance must be equal to the centrifugal force, that is

Fg =Fe

GMm/ r^2 = mw^2r

Where,

G = Gravitational Universal Constant

M = Mass of earth

m = mass of satellite

r = Distance/Orbit

By changing and rearranging the equation to find the orbit using the idea of Period through the Angular Velocity, we have,

r = 1.44 x 10^7 m

The orbit is 14400 kilometers

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The distance from the milky way galaxy to the most distant galaxies in the observable universe would be approximately 1.34 kilometers on a scale in which the MIlky Way Galaxy was the size of a marble(about 1 cm).

The MIlky Way is the galaxy that includes our solar system along with billions of stars.

To measure distances in space, we use the unit light year. One light year is the distance travelled by light in year. 1 light year is equal to 9.5 trillion km.

The size of MIlky Way is about 1,00,000 light years and the distance from the MIlky Way to the most distant galaxies in the observable is 13.4 billion light years.

Therefore, the distance from the milky way galaxy to the most distant galaxies in the observable universe would be approximately 1.34 kilometers on a scale in which the MIlky Way Galaxy was the size of a marble(about 1 cm).

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Energy for this electronic transition is ΔE=0.572eV frequency is ν=1.38×[tex]10^{14}[/tex] [tex]s^{-1}[/tex] and wavelength is 2.17×[tex]10^{-6}[/tex] m

The Bohr Model for the energy of an electron in a hydrogen atom gives us:

E=−[tex]\frac{13.6}{n^{2} }[/tex] eV

Where n is the principle quantum no

For the transition 7→4 the difference in energy is given by:

ΔE= -[tex]\frac{13.6}{49}[/tex]+[tex]\frac{13.6}{16}[/tex] eV

ΔE=0.85-0.277

ΔE=0.572eV

To convert this to Joules we multiply by the electronic charge:

ΔE=0.572×1.6×[tex]10^{-19}[/tex]=9.16×[tex]10^{-20}[/tex]J

(b)

To find the frequency of the emitted photon we use the Planck expression:

ΔE=hν

∴ν=ΔE/h=(9.16×[tex]10^{-20}[/tex])÷(6.626×[tex]10^{-34}[/tex])[tex]s^{-1}[/tex]

ν=1.38×[tex]10^{14}[/tex] [tex]s^{-1}[/tex]

To find the wavelength

λ=c/ν

(3×[tex]10^{8}[/tex])/(1.38×[tex]10^{14}[/tex]) m

=2.17×[tex]10^{-6}[/tex] m

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Percentage of probability of drawing a black card followed by drawing a heart = 13%

Total cards in a deck of cards = 52

Total black cards in a deck of cards = 26

Probability of drawing a black card = (26/52) = (1/2)

Percentage of probability of drawing a black card = (1/2) × 100 = 50 %

Total hearts in a deck of cards = 13

There are 26 black card in a deck of 52 cards . Once the black card is drawn we are left with total of 51 cards. So, we can write

Probability of then drawing a heart = (13/51)

To get the probability of drawing a black card followed by drawing a heart we need to multiply the fractions together, so we can write

Probability of drawing a black card followed by drawing a heart = (1/2) × (13/51) = (13/102)

Percentage of probability of drawing a black card followed by drawing a heart = (13/102) × 100 = 12.74% = 13% (after round off)

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(a) The minimum time interval needed before it can come to rest is t = 10.17 sec for a jet which is travelling at a a speed of 87 m/s, and its acceleration can have a maximum magnitude of 8.55 m/s2

(b) yes the jet can land on a small tropical island airport where the runway is 0.800 km long.

(c) The jet is safe to land.

Acceleration is the rate at which an object's velocity with respect to time changes. It is a vector quantity to accelerate (in that they have magnitude and direction). The direction of the net force acting on an object determines the direction of its acceleration. According to Newton's Second Law, an object's acceleration is the result of two factors working together: the object's mass, which varies depending on the materials it is made of, and the net balance of all external forces acting on it. The magnitude of an object's acceleration is inversely proportional to the object's mass.

The SI unit for acceleration is [tex]m/sec^{2}[/tex].

Use the formula to calculate the time required to stop the jet

v = u + at

0 = 87 + (-8.55)t

t = [tex]\frac{87}{8.55}[/tex]

t = 10.17 sec

Use the following formula to calculate the distance travelled by the jet is,

[tex]x = ut + \frac{1}{2} at^{2}[/tex]

= [tex]( 87 \times 10.17) + \frac{1}{2} (-8.55) (10.17)^{2}[/tex]

= 884.79 - 884.31

=.48m

Yes, the can land on a small tropical island airport where the runway is 0.800 km long.

The jet is safe to land.

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The calculated value is 5:2.

The reciprocal of the focal length is used to calculate a lens's power. In diopter's, lens power is expressed (D). Positive focal lengths and positive power values are characteristics of convergent (convex) lenses. Negative focal lengths and negative power values are characteristics of diverging (concave) lenses.

Given that a N l =1.25 and a Ng =1.5

The focal length of a glass (g) lens in a medium (m) may be calculated using the formula

f1= (mNg 1) [1/R1/ 1/R2].

fa1 = (aNg1) [1/R1/ 1/R 2] while the lens is in the air.

When the lens is submerged in liquid, f l1 = (aNg 1) [1/R 1/1/R2] =1.5/1.25, which divides equation 1 by equation 2, and

fi/fa = (1.5/1.251)/ (1.51)

=5/2 or

Pa / Pi = 5/2 (since f=1/P).

Therefore, Pa:Pi= 5:2.

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For an object in uniform circular motion, its velocity and acceleration vectors are always perpendicular to each other at every point in the path is true.

Circular motion refers to the movement of a body part around the perimeter of a circle or in a circular motion. It may rotate at a fixed speed and angular rate or it may rotate at a variable rate, making it either uniform or non-uniform. A three-dimensional body's components move in circles as it rotates around a fixed axis. The center of mass of a body moves according to the equations of motion. In circular motion, the distance between the body and a fixed point on the surface stays constant.

Examples of circular motion include an artificial satellite circling the Earth at a constant altitude, ceiling fan blades spinning around a hub, and a rotating disc.

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Yes the motion is accelerated.

We have a artificial satellite that moves at a steady 25,000 km/hr in a circular orbit around earth.

We have to determine whether or not it is accelerated.

An artificial Satellite is a man - made artificial body placed in orbit round the earth or moon or another planet in order to collect information or for communication.

According to the question -

v = 25000 km/hr

Now for the motion to be accelerated the velocity must change with respect to time. But, the velocity here is constant. It should be kept in mind that the velocity is a vector quantity, its magnitude is constant but its direction keeps on changing in circular motion, and hence, its acceleration also changes.

Hence, yes the motion is accelerated.

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The smallest change in average temperature that can be measured is 0.0475°C

Average sound speed in deep sea = v=1480m/s

from California to south pacific, sound waves travel 7.7 x [tex]10^{6}[/tex] m distance

smallest time change detected = 1s

The time required for the sound wave to travel the given distance without any change in temperature can be calculated as

t =x/v

=7.7 x [tex]10^{6}[/tex] / 1480

=5202 s

The new time required for the waves,

t1 = t -[tex]\delta t[/tex] =5202-1 =5201s

Now we have to calculate the new sound speed.

v1 = x/t1 = [tex]\frac{7.7 *10^6}{5202}[/tex] =1480.19 m/s

so change in the speed of sound

[tex]\delta v = v1 - v[/tex]

= 1480.19 - 1480 = 0.19 m/s

Then it is given that

[tex]\delta v[/tex] = (4 m/s/°C) [tex]\delta T[/tex](°C)

Formulating,

0.19 m/s = (4 m/s/°C) [tex]\delta T[/tex](°C)

[tex]\delta T[/tex] = 0.19/4

=0.0475°C

Thus, the smallest change in temperature is 0.0475°C

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The charge will be equal to 4.07 x 10⁻¹⁰ coulombs.

The term "electric field" refers to the physical field that surrounds electrically charged particles and pulls or attracts all other charged particles nearby.

Use the following formula E = Kq / r² Since the electric field is 573 N/C

The distance of the midpoint of the charge.

r = 1/2 x 16 = 8 cm = 0.08m.

573 = (8.998 x 10⁹) x q) / (0.08)²

573 x 0.0064 = 8.998 x 10⁹ x q

q = (573 x 0.0064)/ 8.998 x 10^(9)

q =3.6672 / 8.998 x 10⁹

q = 4.07 x 10⁻¹⁰ coulombs

Therefore, the charge will be equal to 4.07 x 10⁻¹⁰ coulombs.

The complete question is given below:-

The electric field midway between two equal but opposite point charges is 573 n/c , and the distance between the charges is 16.0 cm. Calculate the magnitude of the charge.

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The sine components of the velocity of the boat will balance out the velocity of the river making an angle of 37° with the vertical.

Every vector can be broken into some components, these components on vector addition would again give the resultant vector.

The components of the vector act independently.

Given:

Velocity of the boat in still water = 20km/h

Velocity of the river stream= 12km/h

We want the boat to go directly opposite to the starting point without any drift. For this one component of the boat's speed should be acting parallel to the speed of the stream and cancelling its effect in the motion of the boat.

Therefore preventing the drift of the boat now with the other perpendicular speed vector component the boat will cross the river.

Assumption:

The boat goes at an angle p with the vertical or perpendicular to the river stream.

v is the resultant speed of the boat

u is the velocity of the stream

According to the question:

v × sin(p) = u

Sin(p) = 0.6

p = 37°

Therefore, The sine components of the velocity of the boat will balance out the velocity of the river making an angle of 37° with the vertical.

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The charge deposited on the object is 150000 C.

Charge can be defined as the product of current and time. The S.I unit of charge is coulombs (C.)

To calculate the charge deposited on the object, we use the formula below

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1\

Hence, the charge deposited on the object is 150000 C.

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The wind chill index will increase, if the temperature remains the same but the wind speed increases.

Wind is the customary improvement of air or various gases near with a planet's surface. Turns occur on an extent of scales, from whirlwind streams persevering through a few minutes, to neighborhood breezes made by warming of land surfaces and persevering through two or three hours, to overall breezes coming about as a result of the differentiation in maintenance of daylight based energy between the climate zones in the world. The two essential drivers of tremendous degree natural scattering are the differential warming between the equator and the posts, and the turn of the planet (Coriolis influence). Inside the wildernesses and subtropics, warm low streams an over area and undeniable levels can drive rainstorm dispersals. In ocean front areas the sea breeze/land breeze cycle can describe close by breezes; in locales that have a variable area, mountain and valley breezes can win.

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The net force is in the first case is 13 N and in the second case is 55 N.

All mass-bearing objects are attracted by gravitational force. Because it consistently attempts to bring masses together rather than push them apart, the gravitational force is referred to as attractive.

As we know, the gravitational force is given by:

[tex]\rm F = \dfrac{Gm_1m_2}{r^2}[/tex]

Where G is the gravitational constant.

m1 and m2 are masses.

r is the distance between the masses.

It is given that:

Two forces are given:

The two forces act in opposite directions:

= 34 - 21

= 13 N

Both forces act in the same direction:

= 34 + 21

= 55 N

Thus, the net force is in the first case is 13 N and in the second case is 55 N.

The question is incomplete the complete question is:

find the strength of the net force produced by a 34-n force and a 21-n force in each of these cases.

The two forces act in opposite directions.

Both forces act in the same direction.

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At the maximum height ( top ) position, the ball's speed is minimum so at this point the magnitude of the acceleration at a minimum.

In mechanics, acceleration is the rate at which the velocity of an object changes in relation to time. Acceleration is vector quantity (in that they have magnitude and direction). The direction of the net force acting on an object determines its acceleration. the extent of an object's acceleration as per Newton's Second Law. Such negative accelerations are typically produced by retrorocket burning in spacecraft. Since both acceleration and deceleration are changes in velocity, they are considered equally. Passengers experience each of these accelerations (tangential, radial, and deceleration) until their relative (differential) velocities are equal to the acceleration caused by the change in speed.

At most extreme level position the upward part of speed is generally zero. By then the ball just has level speed and minimum magnitude of acceleration.

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At the speed of 0.44 c as a fraction of c, the moving rod will have a length of 80% that of an identical rod at rest.

The speed of the light is c.

c = 3.0 × 10⁸ m/a

Let the length of the moving rod be L.

Let the length of the rod at rest be l.

Length contraction of the rod is,

[tex]L= \sqrt{ 1 - \frac{ v ^{2} }{c ^{2} } \times l} [/tex]

The length of the moving rod is,

Length of moving road = 80% of the length of the rod at rest.

L = 80 % of the l.

[tex] = \frac{80}{100} [/tex]

= 0.80 l

The moving rod will have a length 80% that of an identical rod at rest at the speed of,

[tex]L ^{2} = (1 - \frac{ v ^{2} }{c ^{2} } )\times l ^{2} [/tex]

[tex] \frac{L ^{2}}{l ^{2} }= (1 - \frac{ v ^{2} }{c ^{2} } )[/tex]

[tex]v ^{2} = (1 - \frac{L ^{2}}{l ^{2} }) \: {c^{2} } [/tex]

[tex]v ^{2} = ( \sqrt{1 - \frac{L ^{2}}{l ^{2} }}) \: {c^{2} } [/tex]

[tex]= ( \sqrt{ 1 - \ \frac{0.80 \: l^{2}}{l ^{2} }}) \: {c^{2} } [/tex]

[tex] = \sqrt{( 1 - 0.80) } c[/tex]

v = 0.44 c

Therefore, at the speed of 0.44 c as a fraction of c, the moving rod will have a length of 80% that of an identical rod at rest.

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The correct answer is transient airflows under the combined motion of a  door and the force of buoyancy.

However, the combined airflow characteristics generated by door motion, ventilation airflow, and thermal impacts have not yet been thoroughly defined. Door motion has been acknowledged as playing a part in the confined conveyance between indoor and outdoor regions. This study employed dynamic CFD simulation to look at the transient airflow characteristics and amount of air exchange generated by door motions in a thermally stratified environment with displacement ventilation. The results show that at a door angle of 30°, there is a 40% air exchange even though only 15% of the overall door motion process is used during the initial phase. Two important contributing factors are the temperature difference between the air inside and outside, as well as the rotational speed of the  door.

The thermal convective flow may have a considerable impact on the airflow pattern through the doorway when the door motion is slow enough and the temperature difference is greater than 3 °C. The amount of air exchange rises linearly with door motion speed when there is no difference in temperature between the internal and exterior spaces. When buoyant force and door motion are coupled, a modest door speed yields minimal air exchange. Only the air temperatures close to the door are impacted by door movement. In the displacement ventilated room, a single door open and close cycle does not considerably reduce the overall temperature stratification. The research findings may help to improve knowledge of the consequences of dynamic disturbances in thermally stratified environments as well as offer recommendations for decreasing door motion-induced pollutant movement.

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Fe/Fg = 4.2 x 10⁴² is the gravitational attraction.

Gm²/r² the gravitational attraction between two electrons is given by, where G is the gravitational constant, m is the electron mass, and r is the distance between the two electrons.

r = the distance between two electrons the size of the charge on each electron, or q, is 1.6 x 1019 C.

The mass of one electron, or m, is 9.1 x 1031.

The Coulomb force of repulsion is expressed mathematically as

Fe equals (9 x 109) k q/r2 (1.6 x 10-19) ²/r²

Fg = Gm2/r2 = 6.67 x 1011 is the formula for the gravitational force of attraction. (9.1 x 10⁻³¹) ²/r²

The formula for calculating Fe/Fg is [(9 x 109) (1.6 x 1019) 2/r2] / [(6.67 x 1011). (9.1 x 10^-31) ⁻³/r²]

Fe/Fg = 4.2x10⁴²

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The potential difference is needed to give a helium nucleus (q=2e) 75.0 keV of kinetic energy is 37.5kV.

Potential difference is the difference in amount of energy that charge carriers have between two points in a circuit.

**Measured in Volts: **Potential difference is measured in volts (V) and is also called voltage. The energy is transferred to the electrical components in a circuit when charge carriers pass through them. We use a voltmeter to measure the potential difference (or voltage).

The potential Difference formula:** V = I x R**

The potential difference (which is the same as voltage) is equal to amount of current multiplied by the resistance. A potential difference of one Volt is equal to the one Joule of energy being used by one Coulomb of charge when it flows between two points in a circuit.

For the above question:

The kinetic energy K given to helium nucleus is equal to its potential energy, which is

E=q ∆ V

where q=2e is the charge of helium nucleus, and  is the potential difference applied to it.

Since we know kinetic energy, we have

E= K= 75 keV= q ∆ V

and from this we can find potential difference:

∆V= K/q= 75keV/2e= 37.5 kV

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Answer:

It would crash into the thing it's orbiting.

Explanation:

Since it's not going fast enough to counter the pull of gravity.

Both horizontal and vertical acceleration is produced by the jet engines. While it does contribute to vertical acceleration, gravity has no effect on horizontal acceleration.

there's a particular value or velocity for the horizontal component. with out accounting for air resistance, the horizontal factor is regular for the duration of the flight.

Horizontal velocity affects the variety however not the period of an airborne object. Gravity reasons a downward vertical acceleration that has a price of 9.8 m/s/s.

This vertical acceleration reasons a downward projectile's vertical velocity to vary by 9.8 m/s in keeping with 2nd. The movement of a projectile's horizontal axis is unrelated to its vertical axis.

A projectile's trajectory is determined by using pace in two dimensions. The x and y components of the projectile, respectively, describe its horizontal and vertical pace. Meters are the devices used to signify each horizontal and vertical distances (m).

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Answer:

671.22 mi/hr

Explanation:

[tex](\frac{300 m}{s} )(\frac{1mi}{1609m} )(\frac{3600s}{1hr} )=\frac{(300)(3600)}{1609} =671.22mi/hr[/tex]

Hope this helps

It is necessary to cut off the first few dots because a small distance between dots means the object was moving slow during that time interval.

Uniform velocity is the state in which a body travels the same distance in the same amount of time.

The average velocity of a body is represented by the variable v in the equation (d = v t). If the magnitude and direction of the velocity do not change over time, the body is said to be moving at a uniform speed.

An example of constant velocity, or when a body moves with increasing speed at regular intervals, is the rotation of the Earth.

Uniform velocity is the state in which a body travels the same distance in the same amount of time. The average velocity of a body is given in the equation (d = v t), and its magnitude and direction are constant across time.

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Potassium-41, 19 protons, 19 electrons, 22 neutrons is the correct name, number of protons, neutrons, and electrons for the following ₁₉⁴¹K.

The correct option is B.

The chemical element with the atomic number 19 and the letter K is potassium. Potassium is a silvery - white metal that may be cut with a knife quickly and painlessly. After only a few seconds of exposure, atmospheric oxygen and potassium metal combine to form flaky, white potassium peroxide.

Your potassium level may be affected by a medicine you're taking, or it may be brought on by a medical problem that needs to be treated. The underlying cause of low potassium is treated, which may entail potassium supplementation.

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The complete question is -

What is the correct name, number of protons, neutrons, and electrons for the following ₁₉⁴¹K.

A- Potassium -19, 19 protons, 19 electrons, 22 neutrons

B- Potassium-41, 19 protons, 19 electrons, 22 neutrons

C- Potassium-19, 41 protons, 41 electrons, 19 neutrons

D- Potassium-41, 41 protons, 41 electrons, 19 neutrons

Answer:

I think it's A

Explanation:

potential energy is energy waiting to move right?

Answer is Zero.

By multiplying the standard deviation of one variable (x) by the standard deviation of the other variable, the Pearson correlation coefficient, denoted by the symbol r, is calculated.

A scatter plot diagram is a graphic representation of data where these two variables are simultaneously observed.

The two variables x and y grow in x when y increases, which is referred to as having a positive slope in a positive correlation.

On the other hand, the correlation between x and y is said to be negative and the accompanying regression line has a negative slope when there is an increase in x and a drop in y. On rare occasions, x and y may not seem to be related. Accordingly, the scatter plot diagram's data typically form a nearly perfect circle and are considered to have zero correlation.

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(a) The moment about B is 800 lb.in

(b) The magnitude of the force P is 51.3lb

(c) The smallest force P is 44.4lb

(a)

As we know,

[tex]M_{B} = r_{CIB}F_{N}[/tex]

[tex]M_{B}[/tex] = [tex]4[/tex] × [tex]200[/tex]

= 800 lb.in

The moment about B is 800 lb.in

(b)

By using the formula,

[tex]M_{B} =r_{AIB}Psin[/tex]θ

θ = 120°

Then, [tex]800[/tex] = [tex]18[/tex] × [tex]Psin120[/tex]°

P = 51.3lb

The magnitude of the force P is 51.3lb

(c)

P must be perpendicular to the line connecting points A and B in order for it to be minimal.

Using the formula,

[tex]M_{B} = dP_{min}[/tex]

[tex]800[/tex] = [tex]18[/tex] × [tex]P_{min}[/tex]

[tex]P_{min}[/tex] = 44.4lb

The smallest force P is 44.4lb

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