What potential difference is needed to give a helium nucleus (q=2e) 75.0 kev of kinetic energy?

Answers

Answer 1

The potential difference is needed to give a helium nucleus (q=2e) 75.0 keV of kinetic energy is 37.5kV.

What is potential difference?

Potential difference is the difference in amount of energy that charge carriers have between two points in a circuit.

**Measured in Volts: **Potential difference is measured in volts (V) and is also called voltage. The energy is transferred to the electrical components in a circuit when charge carriers pass through them. We use a voltmeter to measure the potential difference (or voltage).

The potential Difference formula:** V = I x R**

The potential difference (which is the same as voltage) is equal to amount of current multiplied by the resistance. A potential difference of one Volt is equal to the one Joule of energy being used by one Coulomb of charge when it flows between two points in a circuit.

For the above question:

The kinetic energy K given to helium nucleus is equal to its potential energy, which is

E=q ∆ V

where q=2e is the charge of helium nucleus, and  is the potential difference applied to it.

Since we know kinetic energy, we have

E= K= 75 keV= q ∆ V

and from this we can find potential difference:

∆V= K/q= 75keV/2e= 37.5 kV

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Related Questions

the total time it takes a projectile fired straight up at 10 m/s to reach the top of its path and return to its starting point is about

Answers

The total time it takes a project fired straight up at 10m/s and Return to its starting point is about time, t= 2s.

At top speed v=0,

V= urate

0=10+ -g×t

t=1 sec

Top to Bottom it will take one more sec

t= 1+1

t=2 sec/s.

What is total time duration?

Unless there has been a break in service of less than twelve (12) months, in which case the employee will get an adjusted seniority date upon restoration to a Unit 6 classification, Total Time is calculated as the amount of time since the hire date.

During a gap in employment, an employee is not permitted to gain seniority. When an employee returns to a Unit 6 classification after more than twelve (12) months of absence, their starting seniority date is reset entirely.

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If you drove 90km/hr for 2 hours, and 35km/hr for 0.5 hours, what would your average speed be

Answers

Answer:

1,25m.s^-1

Explanation:

Speed=distance /time

=90000/72000

When a dilute gas expands quasi-statically from 0.50 to 4.0 l, it does 250 j of work. assuming that the gas temperature remains constant at 300 k, what is the change in the internal energy of the gas?

Answers

The change in the internal energy of the gas is ΔE int =0 J.

Q=250J heat is absorbed by the gas in this process.

What is  ​isothermal process?

A thermodynamic process known as an isothermal process keeps the system's temperature constant. Because heat is transferred into or out of the system so slowly, thermal equilibrium is preserved.

Givens:

Vi =0.5 L=0.5×10^ −3 m^3

Vf =4.0 L=4.0×10^−3 m^3

W= 250 J

T= 300 K

Because the gas temperature is constant, the process is ISOTHERMAL. As a result, the system's internal energy is constant.

ΔE int =0 J

We know that, ΔE int =Q−W

And we are aware that there has been no change in the system's inherent energy.

Therefore,0=Q−W

Q=W=250J

Q=250J

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Question:

When a dilute gas expands quasi-statically from 0.50 to 4.0 L, it does 250 J of work. Assuming that the gas temperature remains constant at 300 K, (a) what is the change in the internal energy of the gas? (b) How much heat is absorbed by the gas in this process?

9. insulators (nonmetals) have a higher be than metals, and it is more difficult for photons to eject electrons from insulators. discuss how this relates to the free charges in metals that make them good conductors.

Answers

Nonmetals do not conduct electricity or eject electrons when hit by photons.

What is an insulator?

An insulator is a material that does not allow electric current to pass through it. A metal is a material that is able to conduct electricity. We know that metals are able to conduct electricity and are also able to eject electrons when hit by photons.

All these goes back to the nature of the metals and the nonmetals. We know that the difference between the valence band and the conduction band in nonmetals is so wide. This prevents the promotion of electrons from the valance band to the condition band.

As such, nonmetals do not conduct electricity or eject electrons when hit by photons.

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A scientist stated that rock layer C is the oldest and rock layer A is the youngest. Based on
the scientist's conclusion, what can you infer about the geologic history of the rock layers?
Explain your answer.

Answers

Based on the scientist’s conclusion, we can infer that older rocks are pushed toward the bottom, whereas younger rocks are present at the top of all of the layers. This is stated in the Law of Superposition; a rock in an undisturbed sequence is younger than that which is below it and older than that which is above it.

how does the current motion of hnlc on oahu compare to the direction of pacific plate motion relative to the hawaiian hotspot over the past million years?

Answers

Now the islands are moving more north compared to before compare to the direction of pacific plate motion relative to the hawaiian hotspot over the past million years.

The Pacific Ocean's ocean floor is made up of multiple plates. In relation to the plate holding North America and to hot areas rising through the mantle from below the plates, the largest one, the Pacific Plate, is moving north-west (they generate islands like Hawaii). The plate is travelling around Hawaii at a rate of 7 cm per year.

A hot spot that provided magma produced deep under the mantle of the earth, which was used to create the long volcanic chain, did so over the course of about 70 million years. Over the course of around 70 million years, a hot spot supplied magma that was formed deep under the earth's interior (mantle), pushing its way through the earth's surface and ocean floor to construct volcanic islands.

The hot point continuously created new volcanoes on the Pacific Plate, creating the volcanic chain, while the Pacific Plate was shifted by tectonic forces inside the Earth.The Pacific Plate will move in the direction and at the rate determined by the distances between and the approximate ages of several of the Hawaiian volcanoes.

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How many walking paces are there approximately as you walk down Main Street (0.25 miles)?
1 mile = 5280 feet;
1 foot = 12 inches;
22 inches = 1 walking pace

Answers

The number of walking paces as you walk down main street (0.25 miles) is 720 walking paces

How to convert 0.25 mile to feet

1 mile = 5280 feet

Therefore,

0.25 mile = (0.25 mile × 5280 feet) / 1 mile

0.25 mile = 1320 feet

How to convert 1320 feet to inches

1 feet = 12 inches

Therefore,

1320 feet = (1320 feet × 12 inches) / 1 feet

1320 feet = 15840 inches

How to convert 15840 inches to walking pace

22 inches = 1 walking pace

Therefore,

15840 inches = (15840 inches × 1 walking pace) / 22 inches

15840 inches = 720 walking paces

Thus, we can conclude that as you walk down main street (0.25 miles), there are 720 walking paces

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5. A ball is dropped from rest at a height of 25.0 m above the ground. A. How fast is the ball moving when it is 10.0 m above the ground? B. How much time is required for it to reach the ground level? Ignore the effects of air resistance.​

Answers

A. The ball is moving 17.15 m/s when it was 10 m above the ground

B. The time required for the ball to reach the ground is 2.26 s

How to determine the time to fall till 10 m above the ground Initial velocity (u) = 0 m/sAcceleration due to gravity (g) = 9.8 m/s²Height (h) = 25 - 10 = 15 mTime (t) = ?

h = ½gt²

15 = ½ × 9.8 × t²

15 = 4.9 × t²

Divide both side by 4.9

t² = 15 / 4.9

Take the square root of both side

t = √(15 / 4.9)

t = 1.75 s

A. How to determine the velocity when the ball is 10 m above the ground Time till 10 m above the ground (t) = 1.75 sAcceleration due to gravity (g) = 9.8 m/s²Velocity (v) = ?

v = gt

v = 9.8 × 1.75

v = 17.15 m/s

B. How to determine the time taken to reach the groundInitial velocity (u) = 0 m/sAcceleration due to gravity (g) = 9.8 m/s²Height (h) = 25 mTime (t) = ?

h = ½gt²

25 = ½ × 9.8 × t²

25 = 4.9 × t²

Divide both side by 4.9

t² = 25 / 4.9

Take the square root of both side

t = √(25 / 4.9)

t = 2.26 s

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. a free jet is a stream of fluid exhausted to the atmosphere (such as sketched below). the pressure of the fluid inside the free jet is usually assumed to be atmospheric pressure. however, if we do not neglect surface tension, the pressure in jet should be slightly higher than atmospheric pressure. thus, consider a free jet of water with velocity v

Answers

According to the question, the change in pressure for the jetstream is  14.54Pa.

What is pressure?

The force applied perpendicularly to an object's surface expressed as a symbol (p or P) is the force divided by the area of the object's surface. The pressure when compared to the surrounding air pressure is known as gauge pressure. Pressure is expressed using a number of different units. The SI unit of pressure, the pascal (Pa), for instance, is equal to one newton per square meter (N/m²). Some of these measurements are the result of dividing a unit of force by a unit of area.

Explanation:

Given;

jet's diameter,d = 10⁻²m

temperature, t = 20°C

Surface tension acts only on the lines AB and CD.

Consider the equilibrium of forces;

∑F = 0

P₁-P₀ = 2σ/d

here surface tension σ = 0.0727 N/m

P₁-P₀ = 2×0.0727/10⁻²

        = 14.54 Pascal

Hence, the change in pressure of the jetstream is 14.54 Pascal.

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Ok someone help me brainlest will be given
1.With what will a car hit a tree if the car has a mass of 3,000 kg acceleration of m/s^2
2.What force would be needed to make 10kg bowling ball acceleration of 3m/s^2
3. What would be the mass of a truck if it is accelerating at a rate of 5m/s^2 and hits a parked car with a force of 14000 N
4.What is the acceleration of a softball if it has a mass of 0.50 kg and hits the catcher's glove with a force of 25 N
5.How much does a suitcase weigh if has a mass of 22.5 kg
6. What would the mass of a rock falling from the sky if it hits the ground with the force of 147N
7.Find the acceleration of the stacks of books pictured if the stack has a total mass 1.5 kg
8. A kg model airplane is traveling at a speed 33m/s.
The operator than increases the speed up to 45 m/s in seconds
How much force did the engine need in order to make this change.

Answers

Answer:

According to Newton's second law of motion, the acceleration of a body is directly proportional to the force acting on the body and inversely proportional to its mass. The formula for this law is

a

=

F

m

, from which we get the formula

F

=

m

a

. When mass is in kg and acceleration is in

m/s/s

or

m/s

2

, the unit of force is

kgm/s

2

, which is read as kiligram-meter per second squared. This unit is replaced with an N in honor of Isaac Newton. Your problem can be solved as follows:

Known/Unknown:

m

=

3000kg

a

=

2m/s

2

Equation:

F

=

m

a

Solution:

F

=

m

a

=

3000kg

x

2m/s

2

=

6000kgm/s

2

=

6000N

Explanation:

find the net force σf⃗ 3 acting on particle 3 due to the presence of the other two particles. report you answer as a magnitude σf3 and a direction θ measured from the positive x axis.

Answers

Therefore, the net force acting on particle 3 is 139.68 × 10—5 N, and the angle made it by with at the +x axis is 19.1°.

The charge of particle 1 is q1.

q1 = -6.6nC

The charge of particle 2 is q2.

q2 = -13.2 nC

Sides of the equilateral triangle = 3 cm = 3 × 10 —² m.

The force acting on particle 1 is,

[tex]F _{1} = \frac{kq_{1} q_{3}}{a ^{2} } [/tex]

[tex] = \frac{9 \times 10 ^{9} \times 6.6 \times 10 ^{ - 9} \times 8 \times 10 ^{ - 9} }{9 \times 10 ^{ - 4} } [/tex]

[tex]F _{1} = 52.8 \times 10 ^{ - 5} \: N[/tex]

[tex]F _{1} = F _{1} \: cos(60°)i + F _{1} \: sin(60°)j[/tex]

[tex]= ( - 26.4 \: i \: + 45.7 \: j \: ) ×10 ^{ - 5} [/tex]

The force acting on particle 2 is,

[tex] = \frac{9 \times 10 ^{9} \times 3.2 \times 10 ^{ - 9} \times 8 \times 10 ^{ - 9} }{9 \times 10 ^{ - 4} } [/tex]

[tex] = - 105.6 \times 10 ^{ - 5} \: j[/tex]

The net force acting on particle 3 is,

[tex]F_{Net} =F _{1} + F _{2}[/tex]

[tex] = ( - 132 \times 10 ^{ - 5} \: i + 45.7 \times 10 ^{ - 5} \: j)[/tex]

[tex]F_{Net} =139.68 \times \: 10 ^{ - 5} \: N[/tex]

Thus, the net force acting on particle 3 is 139.68 × 10—5 N.

Let the angle made by it with at the +x axis be θ.

[tex]cos \: θ = \frac{ - 132 \times 10 ^{ - 5} }{139.6 \times 10 ^{ - 5} } [/tex]

θ = 19.1°

Therefore, the net force acting on particle 3 is 139.68 ×

10—5 N and the angle made it by with at the +x axis is 19.1°.

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QUESTION 17

IF a particular galaxy has a total mass of 10 to the 47 grams and the average star in that galaxy has a mass of 10 to the 33
grams, approximately how many stars are there in that galaxy? Give your answer to the nearest whole power of 10 by
entering the exponent only.

Answers

The number of stars present in the galaxy is 10 raised to the power of 14. So the exponent is equal to 14.

Given in the question

Total mass of the particular galaxy = 10 to the power of 47 grams

The average mass of the star in the galaxy = 10 to the power of 33 grams

We know that the total mass of the galaxy which is a collection of several thousand stars is equal to the sum of all the stars present in it. Also, the total mass of the galaxy can be calculated by multiplying the average mass of a star in the galaxy by the number of stars that are there in the galaxy.

So, Total mass = Average mass × Number of stars in the galaxy

Number of stars in the galaxy = Total mass of the galaxy/ Average mass of the star

Put in the values, we get

Number of stars in the galaxy = 10^47/10^33

Number of stars in the galaxy = 10^(47-33)

Number of stars in the galaxy = 10^14

So, the number of stars present in the galaxy is 10 raised to the power of 14. So the exponent is equal to 14.

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a baseball player is dashing toward home plate with a speed of 4.7 m/s when she decides to hit the dirt. she slides for 1.5 s , just reaching the plate as she stops (safe, of course).

Answers

The deceleration of the player is -3.13 m/s² if the baseball player is dashing toward home plate with a speed of 4.7 m/s when she decides to hit the dirt. she slides for 1.5 s.

What is linear acceleration?

It is defined as the rate of change in linear velocity with respect to time. It is also known as linear acceleration.

It is given that:

A baseball player is dashing toward home plate with a speed of 4.7 m/s when she decides to hit the dirt. she slides for 1.5 s

As we know,

From the acceleration formula:

a = (v2 - v1)/t

a = (0 - 4.7)/1.5

a = -3.13 m/s²

Thus, the deceleration of the player is -3.13 m/s² if the baseball player is dashing toward home plate with a speed of 4.7 m/s when she decides to hit the dirt. she slides for 1.5 s.

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A car starts from rest and accelerates uniformly for a distance of
204 m over an 6.5-second time interval. The car's acceleration
is _____ m/s².

Answers

Answer: 8.10m/s

Explanation:

using second eq of motion s=ut+1/2at

2

as u=0, a=

t

2

2s

=

5.21

2

2∗110

=8.10m/s

2

Limits of Measurement (page 19)
12. Circle the letter of each expression that has four significant figures.
a. 1.25 x 10¹
12.51
c. 0.0125
d. 0.1255
13 Is the following sentence true or false? The precision of a

Answers

Option B has four significant figures.

The number of significant single digits (0 through 9 inclusive) in the coefficient of an expression in scientific notation is referred to as significant figures. The amount of precision or assurance an engineer or scientist uses to state a quantity is indicated by the number of significant figures in a statement. Rounding off an expression once a calculation is completed yields significant figures. The number of significant figures in the result of any computation must be equal to or less than the number of significant figures in the expression or component with the least accuracy. The digits in a number that have significance in terms of accuracy or precision are known as significant figures. Any digit that is not zero is among them. As in 3003 or 45.60009, there are zeros in between non-zero digits.

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a tire has a tread pattern with a crevice every 2.20 cm. each crevice makes a single vibration as the tire moves. what is the frequency of these vibrations if the car moves at 43.0 m/s?

Answers

The frequency of these vibrations if the car moves at 43.0 m/s is 1954.54 Hz.

Given that,

The speed of the car = 43m/s.

or the speed of the car = 4300cm/s

A tire has a tread pattern with a crevice = 2.20cm

Since the crevice hits every 2.20cm,

This happens,

= 4300cm / 2.20

= 1954.54.

Therefore,

The frequency is 1954.54Hz

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Explain how the measurement of the speeds of individual galaxies in a cluster of galaxies can be used to determine the mass of the cluster of galaxies.

Answers

By Applying Newton's law of gravitation to this speeds, we can deduce the mass of the cluster.

What is a galaxy?

A galaxy is a collection of stellar remnants, stars, interstellar gas, dust, and dark matter that is gravitationally bound to each other. The name comes from the Greek word galaxias, which translates to mean "milky" and refers to the Milky Way galaxy, which houses the Solar System. Galaxies range in size from dwarfs with fewer than one hundred million (108) stars to the largest galaxies known as supergiants with one hundred trillion (1014) stars, each orbiting its galaxy's center of mass. Galaxies are thought to contain an average of 100 million stars.

Therefore, the speeds of individual galaxies can be used to determine the mass of the cluster of galaxies  by the method of measuring the speeds and positions of the galaxies in a cluster as they orbit. And then, applying Newton's law of gravitation to this speeds, we can deduce the mass of the cluster.

Determination of mass of cluster using speeds of galaxies orbiting the center:

a) determine a cluster's average speed and redshift measurements

b) To determine each galaxy's individual speed, deduct this average from the galaxy's overall speed.

c) calculate cluster mass using newtons universal law of gravitation and individual speed

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What is the change in energy experienced by an electron in a hydrogen atom that undergoes an n = 2 to n = 1 transition?

Answers

The change in energy is -10.2 eV.

We need to know about transition energy to solve this problem. Electrons in a hydrogen atom can move to another level of energy. It is also called a transition. In this process, electrons will absorb or release their energy to move. The transition energy can be determined as

ΔE = E2 - E1

where ΔE is transition energy, E2 is the final state of energy and E1 is the initial state of energy.

The state energy of a hydrogen atom can be calculated by

E = -(13.6) / n² eV

where n is the number of energy states.

From the question above, we know that

n1 = 2

n2 = 1

By substituting the following parameter, we get

ΔE = E2 - E1

ΔE = -(13.6) / n2² - (-(13.6) / n1²)

ΔE = -(13.6) / 1² - (-(13.6) / 2²)

ΔE = 3.4 - 13.6

ΔE = -10.2 eV

The transition energy is minus because electrons emit the energy to move.

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Determine the longest wavelength of light capable to remove an electron from a sample of potassium metal, if the binding energy for an electron in k is 1. 76 × 103 kj/mol.

Answers

The longest wavelength of light capable to remove an electron from a sample of potassium metal is 1.136 x 10^-19 m.

The binding energy is the amount of energy needed to bind the electron to the element.

If energy equal to or more than the binding energy is provided, electrons will be removed from the metal.

The energy(E) of a light wave is calculated using the following formula,

E = hc/λ

In the above formula

h = Planck’s Constant = 6.626 x 10^-34 J s

c = speed of light

λ = wavelength of light

Putting E = 1.76 x 10^6 J in the formula

1.76 x 10^6 = 6.626 x 10^-34 x 3 x 10^8/lambda

λ = 1.136 x 10^-19 m.

Thus, the longest wavelength of light capable to remove an electron from a sample of potassium metal is 1.136 x 10^-19 m.

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The longest wavelength of light capable to remove an electron from a sample of potassium metal is 1.136 x 10^-19 m.

The binding energy is the amount of energy needed to bind the electron to the element.

If energy equal to or more than the binding energy is provided, electrons will be removed from the metal.

The energy(E) of a light wave is calculated using the following formula,

E = hc/λ

In the above formula

h = Planck’s Constant = 6.626 x 10^-34 J s

c = speed of light

λ = wavelength of light

Putting E = 1.76 x 10^6 J in the formula

1.76 x 10^6 = 6.626 x 10^-34 x 3 x 10^8/lambda

λ = 1.136 x 10^-19 m.

Thus, the longest wavelength of light capable to remove an electron from a sample of potassium metal is 1.136 x 10^-19 m.

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Why state of body and body at rest and body moving with constant velocity are equal?

Answers

This is Newton's first law of motion, which says it's due to the motion being opposed by unseen resistive forces such as friction and air resistance.

Newton's first law of motion :

Newton's first law states that unless compelled to change its state by the action of an external force, every object is going to remain stationary or in uniform motion in a straight line. Inertia is the tendency to resist changes in a state of motion.

If an accident occurs or the brakes are suddenly applied to the car, the body will tend to continue its inertia and move forward, which will almost certainly prove fatal. Seat belts are used to prevent such accidents by preventing your body from moving forward in inertia and thus avoiding danger.

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If the final pressure is 0.500 times the initial pressure, what is the ratio of the final density to the initial density?

Answers

By ideal gas approximation, the final to initial density ratio is 1/2.

We need to know about the ideal gas theory to solve this problem. The ideal gas is assumed that there is no interaction between particles in a gas. It can be determined by the equation

P . V = n . R . T

where P is pressure, V is volume, n is the number of moles gas, R is the ideal gas constant (8.31 J/mol.K) and T is temperature.

From the question above, we know that

P2 = 0.5 P1

Pressure is inversely proportional to pressure, hence it can be written as

P ~ (1/V)

Assuming the temperature does not change, the ratio of pressure is

P1 / P2 = (1/V1) / (1/V2)

P1 / P2 = V2 / V1

P1 / 0.5P1 = V2 / V1

V2 = 2 V1

Find the density ratio

ρ2 / ρ1 = (m/V2) / (m/V1)

ρ2 / ρ1 = V1 / V2

ρ2 / ρ1 = V1 / 2V1

ρ2 / ρ1 = 1 / 2

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if a penny has mass 2.56 g, what charge (magnitude and sign) on the penny is necessary to levitate the penny? (2)

Answers

The charge on the penny is necessary to levitate the penny, the magnitude is 3*10^-4C and sign is negative.

What is charge?

Charged matter experiences a force when it is exposed to an electromagnetic field due to the physical property of electric charge. Positive or negative charges can exist in an electric field (commonly carried by protons and electrons respectively). A neutral object is one that carries no net charge. The early understanding of how charged particles interact is today known as classical electrodynamics, and it is still true for issues that do not demand for taking into account quantum phenomena. Electric charge is a conserved property; the net charge of an isolated system, which is the sum of the positive and negative charges, cannot change.

According to Newton's second law -

∑fy= ma

fe-mg=ma

Fe= ma + mg

qE = 3*10^-3*0.19 + 3*10^3*9.81

qE= 30 * 10^-3

q= 30*10^3/100 = 30*10^-5

q= 3*10^-4C

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A mass attached to a spring is displaced from its equilibrium position by 5cm and released. The system then oscillates in simple harmonic motion with a period of 1s. If that same mass–spring system is displaced from equilibrium by 10cm instead, what will its period be in this case?.

Answers

The time period remains the same = 1 sec.

We have a mass–spring system.

We have to determine the period of oscillation if mass–spring system is displaced from equilibrium by 10cm and not from 5cm.

What is the formula to calculate the time period of mass - spring system?

The time period is given by -

[tex]$T = 2\pi \sqrt{\frac{M}{K} }[/tex]

According to the question -

For x = 5 cm the time period is 1 seconds.

The time period is directly proportional to [tex]$\sqrt{\frac{M}{K} }[/tex] and it is not dependent on x.

So the time period remains the same = 1 sec only and only is the spring - mass system is the same.

Hence, the time period remains the same = 1 sec.

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Atoms, in which the number of electrons does not equal the number of protons, are called.

Answers

Atoms, in which the number of electrons does not equal the number of protons, are  referred to what we call ions.

What is an Ion?

This refers to an atom or molecule which has a net electric charge as a result of the gain or loss of electrons which is the part of the subatomic particle actively involved in a chemical reaction.

Due to the electrons involvement in a reaction, it doesn't equal the number of protons and results in the formation of ions in which the positive ions are the ones which donate electrons and negative ions accept electrons.

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You are renting a car which is reported to achieve 10.1 km/l. what is its mileage in miles/gal?

Answers

The renting car that is reported to achieve 10.1 km/L its mileage in miles/gal is: 23.75 miles/gal

To solve this problem, we have to do the conversion of units with the given information.

Information about the problem:

Mileage (Km/L) = 10.1 Km/L1 mile is equivalent to 1.61 km1 gal is equivalent to 3.785 L

Converting the units from km/L to miles/gal, we get:

10.1 Km/L * (1 miles / 1.60934 km) * (3.785 L  1 gal) = 23.75 miles/gal

10.1 Km/L is equivalent to 23.75 miles/gal

What is unit conversion?

It is the transformation of a value expressed in one unit of measurement into an equivalent value expressed in another unit of measurement of the same nature.

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The stemplot below shows the heights (in inches) of students in a clas
5
25569
2477
6
7 01
Which of the following is a height of a student in the class?
OA. 69 inches
OB. 47 inches
O C. 77 inches
OD. 70 inches

Answers

D. The height of a student in the class from the given data is 70.

What is stem plot?

A stem plot is a way to plot data where the data is split into stems (the largest digit) and leaves (the smallest digits).

Heights of the students in the class

5, 25, 56, 92, 47, 76, 70, 1

Thus, the height of a student in the class from the given data is 70.

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you walk 9.6km in 4.5h , what the average speed​

Answers

the answer would come to: 2.13 km/h

In the lewis formula for hydrazinium ion, n2h5 , the total number of lone electron pairs around the two nitrogen atoms is:________

Answers

In the Lewis formula for hydrazinium ion, N 2H 5 +, the total number of lone electron pairs around the two nitrogen atoms is 1.

What is Lewis structure?

Lewis structures, often referred to as Lewis dot formulas, Lewis dot structures, electron dot structures, or Lewis electron dot structures (LEDS), are diagrams that depict the interactions of atoms inside molecules as well as any lone pairs of electrons that may be present. Any molecule with a covalent link, as well as coordination compounds, can have a Lewis structure. Gilbert N. Lewis, who described it in his 1916 article, The Atom and the Molecule, gave the Lewis structure its name. Lewis structures add lines between atoms to represent shared pairs in a chemical bond, extending the idea of the electron dot diagram.

The two nitrogen atoms are surrounded by just one lone electron pair in the hydrazinium ion's Lewis formula, n2h5+.

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a skier travels 84m in 6s, what the average speed?​

Answers

Answer:88.3 m/s

Explanation:

a ball rolls off the top of a 1.75 m high ramp inclined at angle 30.0◦moving at 5.87 m/s. (note: the ball goes off the top of the ramp similarly to a bicycle going off a jump.)

Answers

The acceleration ax = 3.03 m/s^2 and the ay = 1.75 m/s^2.

Calculation

It is given that

h = 1.75m

[tex]\theta[/tex]= 30°

Vo = 5.87 m/s

Now Vox= Vo cos[tex]\theta[/tex]

= 5.87 x cos30° = 5.08 m/s

Voy = Vo sin[tex]\theta[/tex] = 2.94 m/s

Tan[tex]\theta[/tex] = h/x

⇒ x =h/tan[tex]\theta[/tex]

⇒ x = 3.03m

y = h = 1.75m

Now, v for the ball is given by

V = Vo + [tex]\sqrt{10gh/7}[/tex]

= Vo + [tex]\sqrt{10*9.81*1.75/7}[/tex]

V = 5.87 + 4.95 = 10.82m/s

⇒ Vx = Vcos[tex]\theta[/tex] = 9.37 m/s

and Vy = 5.41 m/s

a = 5/7 gsin[tex]\theta[/tex]

So, ax = 5/7 gsin[tex]\theta[/tex] x cos[tex]\theta[/tex]

ax = 5/14 gsin(2[tex]\theta[/tex])

ax = 5/14 x 9.81 x sin60°

ax= 3.03 m/s^2

and ay = 5/7gsin[tex]\theta[/tex] x sin[tex]\theta[/tex] = 5/7 gsin^2[tex]\theta[/tex]

= 5/7 x 9.81 x sin^2 30°

⇒ ay = 1.75 m/s^2

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