What polynomial identity should be used to prove that 40 = 49 − 9?

a
Difference of Cubes

b
Difference of Squares

c
Square of a Binomial

d
Sum of Cubes

Answers

Answer 1

A polynomial identity that should be used to prove that 40 = 49 − 9 is: B. Difference of Squares.

What is a polynomial function?

A polynomial function is a mathematical expression which comprises  variables (intermediates), constants, and whole number exponents with different numerical value, that are typically combined by using the following mathematical operations:

AdditionMultiplication (product)Subtraction

In Mathematics, the standard form for a difference of two (2) squares is modeled or represented by this mathematical expression:

a² - b² = (a + b)(a - b).

Where:

a and  b are numerical values (numbers or numerals).

Given the following equation:

40 = 49 − 9

40 = 7² - 3³

40 = (7 + 3)(7 - 3).

40 = (10)(4)

40 = 40 (proven).

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Related Questions

If these two figures are similar, what is the measure of the missing angle?

Answers

If the two figures are similar, then the missing angle equals 70°.

I didn't really get it when my teacher tried to explain this

Answers

The formula for determining the volume of a cylinder is expressed as

V = pi * r^2h

Where

V represents volume of cylinder

pi is a constant whose value is 3.142

r represents radius of cylinder

h represents height of cylinder

From the information given,

h = 10

r = 3

V = 3.142 * 3^2 * 10

V = 282.78 in^3

The closest measurement is option A

A local band was interested in the average song time for rock bands in the 1990s. They sampled eight different rock bands and found that the average time was 3.19 minutes with a standard deviation of 0.77 minutes.
Calculate the 95% confidence interval (in minutes) for the population mean.

Answers

The 95% confidence interval (in minutes) for the population mean is of:

(2.55, 3.83).

What is a t-distribution confidence interval?

The bounds of the confidence interval are given according to the following rule:

[tex]\overline{x} \pm t\frac{s}{\sqrt{n}}[/tex]

In which the parameters are described as follows:

[tex]\overline{x}[/tex] is the sample mean.t is the critical value.n is the sample size.s is the standard deviation for the sample.

The distribution is used when the standard deviation of the population is not known, only for the sample.

In the context of this problem, the values of the parameters are given as follows:

[tex]\overline{x} = 3.19, s = 0.77, n = 8[/tex]

The critical value, using a t-distribution calculator, for a two-tailed 95% confidence interval, with 8 - 1 = 63 df, is t = 2.3646.

Then the lower bound of the confidence interval is calculated as follows:

[tex]\overline{x} - t\frac{s}{\sqrt{n}} = 3.19 - 2.3646\frac{0.77}{\sqrt{8}} = 2.55[/tex]

The upper bound is calculated as follows:

[tex]\overline{x} + t\frac{s}{\sqrt{n}} = 3.19 + 2.3646\frac{0.77}{\sqrt{8}} = 3.83[/tex]

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59.25 ÷ 0.75 = 1.06 × 7.3 =on chart. will send image

Answers

For the division, notice that we can multiply both numbers by 100, to get the following:

[tex]\begin{gathered} 59.25\cdot100=5925 \\ 0.75\cdot100=75 \end{gathered}[/tex]

then, we can make the long division:

therefore, the result of 59.25 ÷ 0.75 is 79

For the multiplication, we can write the following:

notice that since both factors have 2 digits and 1 digit each after the decimal point, the final result will have 3 digits after the decimal point,

Therefore, the result of 1.06 × 7.3 is 7.738

Conner plans to plow a field in one day. Before lunch he plows 15 acres, which is 30% of the field. Howmany acres will he have to plow after lunch in order to finish the field?

Answers

Solution:

Let the total field to plow be 100 %

According to the question,

The field plowed before lunch is shown below:

15 acres field = 30%

30 % field = 15 acres

1 % field = 15/30 acres

The field plow after lunch is 70%.

[tex]\begin{gathered} 70\text{ \% of field = }\frac{15}{30}\times70 \\ =35\text{ acres} \end{gathered}[/tex]

Final Answer:

Therefore, the field to plow after lunch in order to finish the field is 35 acres.

The endpoints are a side of a rectangle ABCD in the coordinate plane at A(3,4), B(6,1) Find the equation of the line the given segment The line segment is line Segment AB

Answers

The endpoints are a side of a rectangle ABCD in the coordinate plane at A(3,4), B(6,1) Find the equation of the line the given segment

The line segment is line Segment AB​

step 1

Find the slope of segment AB

m=(1-4)/(6-3)

m=-3/3

m=-1

step 2

Find the equation of the line in slope intercept form

y=mx+b

we have

m=-1

point (3,4)

substitute

4=(-1)*(3)+b

4=-3+b

b=4+3

b=7

therefore

the equation of segment AB is

y=-x+7

How do I solve and what would the answer be?

Answers

[tex]\mathrm{A\: function\: g\: is\: the\: inverse\: of\: function\: f\: if\: for}\: y=f\mleft(x\mright),\: \: x=g\mleft(y\mright)\: [/tex]

To find the inverse of a function:

[tex]f(x)=\frac{2}{x-5}[/tex]

We will follow the steps below

Step 1: Replace f(x) witth y

[tex]y=\frac{2}{x-5}[/tex]

Step 2: interchange x with y

[tex]x=\frac{2}{y-5}[/tex]

Step 3: Make y the subject of the formula

[tex]\begin{gathered} y-5=\frac{2}{x} \\ \\ y=\frac{2}{x}+5 \end{gathered}[/tex]

Thus, the inverse of the function is:

[tex]y=\frac{2}{x}+5[/tex]

H is the circumcenter of triangle BCD, BC=18, and HD=14. Find CH.

Answers

Given that H is the circumcenter of the triangle.

It means, the length between each vertex point of the triangle and the point H is the radius of the circle.

Thus, the line DH=CH=BH are the radius of the circle.

It is given that DH=14.

Therefore CH=14.

Hence the value of CH is 14.

write 0.751 as a percentage

Answers

To convert decimal numbers to percentage, what we need to do is to multiply the decimal number by 100, and we will get the representation as a percentage.

In this case we have the decimal number:

[tex]0.751[/tex]

We multiply that number by 100 to write is as a percentage:

[tex]0.751\times100=71.5[/tex]

Answer: 75.1%

10 ft to 8 ft The percent of change is

Answers

The percent of change is​ computed as follows:

[tex]\text{percent of change = }\frac{new\text{ value }-previous\text{ value}}{previous\text{ value}}\cdot100[/tex]

Substituting with data:

[tex]\begin{gathered} \text{ percent of change = }\frac{8-10}{10}\cdot100 \\ \text{ percent of change =}-20\text{ \%} \end{gathered}[/tex]

Complete the proof that the point (-2, V5 ) does or does not lle on the circle centered at the origin and containing the point (0,3). Part 1 out of 4 The radius of the circle is

Answers

We will have the following:

*First: We have that the equation of the circle will be given by:

[tex](x-h)^2+(y-k)^2=r^2[/tex]

Here (h, k) is the coordinate of the center of the circle and r is the radius of the circle.

*Second: We will replace the center of the circle and determine the radius:

[tex]x^2+y^2=r^2[/tex]

*Third: We determine the radius of the circle by using the point given:

[tex](0)^2+(3)^2=r^2\Rightarrow r^2=9\Rightarrow r=3[/tex]

*Fourth: We have the following expression representing the circle:

[tex]x^2+y^2=9[/tex]

So, we replace the point (-2, sqrt(5)) to determine whether or not it belongs to the circle, that is:

[tex](-2)^2+(\sqrt[]{5})^2=9\Rightarrow4+5=9\Rightarrow9=9[/tex]

Thus proving that the point (-2, sqrt(5)) does lie in the circle.

Debra is playing a role-playing game with her friends. She will roll dice to determine if her character unlocks a treasure chest. The probability of her unlocking the treasure chest is 3/10. Find the odds in favor of her character unlocking the treasure chest.

Answers

Answer:

Explanation:

Probability of Debra unlocking the treasure chest, P(unlocking) = 3/10

Probability of Debra not unlocking the treasure chest,

P( not unlocking) = 1 - 3/10

P( not unlocking) = 7/10

[tex]undefined[/tex]

The function P(x) is mapped to I(x) by a dilation in the following graph. Line p of x passes through (negative 2, 4) & (2, negative 2). Line I of X passes through (negative 4, 4) & (4, negative 2).© 2018 StrongMind. Created using GeoGebra. Which answer gives the correct transformation of P(x) to get to I(x)?

Answers

When we're dilating a line, we can either multiply the function value by a constant

[tex]f(x)\to kf(x)[/tex]

or the argument of the function

[tex]f(x)\to f(kx)[/tex]

Since the y-intercept of both functions is the same, then the multiplied quantity was the argument of the function.

We want to know the constant associated to the transformation

[tex]I(x)\to I(kx)=P(x)[/tex]

We have the following values for both functions

[tex]\begin{gathered} I(-4)=4,\:I(4)=-2 \\ P(-2)=4,\:P(2)=-2 \end{gathered}[/tex]

For the same y-value, we have the following correlations

[tex]\begin{gathered} I(-4)=P(-2)=P(\frac{1}{2}\cdot-4) \\ I(4)=P(2)=P(\frac{1}{2}\cdot4) \\ \implies I(x)=P(\frac{1}{2}x) \end{gathered}[/tex]

and this is our answer.

[tex]I(x)=P(\frac{1}{2}x)[/tex]

Consider the line y= 3/5x-3Find the equation of the line that is parallel to this line and passes through the point (3, 4).Find the equation of the line that is perpendicular to this line and passes through the point (3, 4).

Answers

a) y = 3/5x + 11/5

b) y = -5/3x + 9

Explanation:[tex]\begin{gathered} a)\text{ }y\text{ = }\frac{3}{5}x\text{ - 3} \\ \text{compare with equation of line:} \\ y\text{ = mx + b} \\ m\text{ =slope, b = y-intercept} \\ m\text{ =slope = 3/5} \\ b\text{ = -3} \end{gathered}[/tex]

For a line to be parallel to another line. the slope of the 1st line will be equalt to the slope of the 2nd line:

slope of 1st line = 3/5

So, the slope of the 2nd line = 3/5

Given point: (3, 4) = (x, y)

To get the y-intercept of the second line, we would insert the slope and the point into the equation of line

[tex]\begin{gathered} y\text{ = mx + b} \\ 4\text{ = }\frac{3}{5}(3)\text{ + b} \\ 4\text{ = 9/5 + b} \\ 4\text{ - }\frac{\text{9}}{5}\text{ = b} \\ \frac{20-9}{5}\text{ = b} \\ b\text{ = 11/5} \end{gathered}[/tex]

The equation of line parallel to y = 3/5x - 3:

[tex]\begin{gathered} y\text{ = mx + b} \\ y\text{ = }\frac{3}{5}x\text{ + }\frac{11}{5} \end{gathered}[/tex][tex]b)\text{ line perpendicular to y = 3/5x - 3}[/tex]

For a line to be perpendicular to another line, the slope of one will be the negative reciprocal of the second line

Slope of the 1st line = 3/5

reciprocal of 3/5 = 5/3

negative reciprocal = -5/3

slope of the 2nd line (perpendicular) = -5/3

We need to get the y-intercept of the perpendicular line:

[tex]\begin{gathered} \text{given point: (3,4) = (x, y)} \\ y\text{ = mx + b} \\ m\text{ of the perpendicular = -5/3} \\ 4\text{ = }\frac{-5}{3}(3)\text{ + b} \\ 4\text{ = -5 + b} \\ 4\text{ + 5 = b} \\ b\text{ = 9} \end{gathered}[/tex]

The equation of line perpendicular to y = 3/5x - 3:

[tex]\begin{gathered} y\text{ = mx + b} \\ y\text{ = }\frac{-5}{3}x\text{ + 9} \end{gathered}[/tex]

Use one or more transformations to transform the pre-image (purple) onto the image (white). helppp

Answers

The transformation required to transform the preimage in purple to the image in white is

Rotation 180 degreesTranslation to the right 14 unitsTranslation down 4 units

What is transformation?

Transformation is the term used to  describe when a body is repositioned  or makes some movement.

Some of the movements involved in transformation are:

Rotation Translation and so onHow to transform the pre- image to the image

The movement can start in several ways however we stick to this as described

The first movement is rotation by 180 degrees about the topmost edge at the left side.The next step is translation 14 units to the right. This gets the preimage exactly on top of the imageFinally, translation 4 units down

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I need help figuring out how to write out this problem correctly.

Answers

Answer

[tex]\frac{\sqrt{10}}{11}[/tex]

Step-by-step explanation

Given the expression:

[tex]\sqrt{\frac{10}{121}}[/tex]

Distributing the square root over the division and evaluating the square root at the denominator:

[tex]\begin{gathered} \frac{\sqrt{10}}{\sqrt{121}} \\ \frac{\sqrt{10}}{11} \end{gathered}[/tex]

The sum of 4 times a number and 5 is the same as the difference of the number and 7

Answers

Answer:

4nx5=n-7

-7/19

Step-by-step explanation:

Let's Write this equation step by step.

The sum of 4 times a number and 5

That means: 4nx5

The difference of the number and 7

That means: n-7

Now, combine:

4nx5=n-7

-7/19

State whether the given set of lines are parallel, perpendicular or neither.3x-2y=56y-9x=6The lines are Answer

Answers

Two lines are parallel if:

[tex]m1=m2[/tex]

Two lines are perpendicular if:

[tex]m1\cdot m2=-1[/tex]

---------------------

Let's rewrite the given equations in the slope-intercept form:

[tex]\begin{gathered} 3x-2y=5 \\ y=\frac{3}{2}x-\frac{5}{2} \\ -------- \\ 6y-9x=6 \\ y=\frac{3}{2}x+1 \end{gathered}[/tex]

Since:

[tex]\begin{gathered} m1=m2 \\ \frac{3}{2}=\frac{3}{2} \\ \end{gathered}[/tex]

We can conclude that the lines are parallel.

You are scuba diving at 120 feet below sea level. You begin to ascend at a rate of 4 feet per second.a. Where will you be 10 seconds after you begin your ascension? b. How long will it take to reach the surface?

Answers

The ascension can be modeled using the function:

[tex]d(t)=d_0-r\cdot t[/tex]

Where d is the number of feet below the sea level at time t (in seconds), d₀ is the initial "depth", and r is the ascension rate.

From the problem, we identify:

[tex]\begin{gathered} r=4\text{ feet per second} \\ d_0=120\text{ feet} \end{gathered}[/tex]

Then:

[tex]d(t)=120-4t[/tex]

a)

After 10 seconds, we have t = 10:

[tex]\begin{gathered} d(10)=120-4\cdot10=120-40 \\ \\ \Rightarrow d(10)=80\text{ feet} \end{gathered}[/tex]

After 10 seconds, we will be 80 feet below sea level.

b)

To find how long will it take to reach the surface, we need to solve the equation d(t) = 0.

[tex]\begin{gathered} d(t)=0 \\ 120-4t=0 \\ 4t=120 \\ \\ \therefore t=30\text{ seconds} \end{gathered}[/tex]

We will reach the surface after 30 seconds.

concetta had a 2kg bag of flour. she used 180g of flour to make biscotti. how many kilograms of flour are left in the bag?

Answers

Answer

The amount of flour left in the bag = 1.82 kg

Explanation

Concetta had 2 kg of flour.

She uses 180 g of the flour to make biscotti.

We are then asked to calculate how much flour is left in kilograms.

Amount of flour left = (Initial Amount of flour) - (Amount of flour used)

Initial amount of flour = 2 kg

Amount of flour used = 180 g = 0.18 kg

Amount of flour left = (Initial Amount of flour) - (Amount of flour used)

Amount of flour left = 2 - 0.18 = 1.82 kg

Hope this Helps!!!

Over a set of 5 chess games, Yolanda's rating increased 10 points, increased 4 points,
decreased 21 points, increased 23 points and decreased 8 points.
Her rating is now 1647.
What was her rating before the 5 games?
A. 1639
B. 1649
C. 1655
D. 1661

Answers

Answer:

C. 1655

Step-by-step explanation:

+10, +4, -21, +23, -8

Adding all those terms together we get 8

1647 + 8 = 1655

Find the equation of the line described. Write your answer in standard form. Vertical and containing (10,14)

Answers

We have here a special case where the line is vertical. In this case, the line has an "infinite" slope (or it is not defined). Therefore, since the line is vertical and contains the point (10, 14), the line is given by the equation:

[tex]x=10[/tex]

The standard form of the line is given by the general equation:

[tex]Ax+By=C[/tex]

Then, we can rewrite the equation as follows:

[tex]x+0y=10[/tex]

We can see that this line contains the point (10,14):

We can see that the vertical line, x + 0y = 10 passes through the point (10, 14).

In summary, the line is given by x + 0y = 10 (A = 1, B = 0, C = 10).

End Behavior Graphically

Answers

We will investigate how to determine the end behaviours of polynomial functions.

The function given to us is:

[tex]f(x)=123x^3+9x^4-786x-3x^{5^{}}-189x^2\text{ + 1260}[/tex]

Whenever we try to determine the end-behaviour of any function. We are usually looking for value of f ( x ) for the following two cases:

[tex]x\to\infty\text{ and x}\to-\infty[/tex]

The most important thing to note when dealing with end-behaviour of polynomial functions is that the behaviour is pre-dominantly governed by the highest order term of a polynomial. The rest of the terms are considered small or negligible when considering end-behaviours of polynomials.

The highest order terms in the given function can be written as:

[tex]f(x)=-3x^5[/tex]

Then the next step is to consider each case for the value of ( x ) and evaluate the value of f ( x ) respectively.

[tex]\begin{gathered} x\to\infty \\ f\text{ ( }\infty\text{ ) = -3}\cdot(\infty)^5 \\ f\text{ ( }\infty\text{ ) = -3}\cdot\infty \\ f\text{ ( }\infty\text{ ) = -}\infty \end{gathered}[/tex]

Similarly repeat the process for the second case:

[tex]\begin{gathered} x\to-\infty \\ f\text{ ( -}\infty\text{ ) = -3}\cdot(-\infty)^5 \\ f\text{ ( -}\infty\text{ ) = 3}\cdot\infty \\ f\text{ ( -}\infty\text{ ) = }\infty \end{gathered}[/tex]

Combining the result of two cases we get the following solution:

[tex]As\text{ x}\to\text{ }\infty\text{ , y}\to\text{ -}\infty\text{ and as x}\to-\infty\text{ , y}\to\text{ }\infty[/tex]

Correct option is:

[tex]\text{Option C}[/tex]

i inserted a picture of the question can you please list the answers as well

Answers

Solution

We want to find the equation of the line given in the graph

We can see the four points on the graph where the line pass through

The points are

[tex](4,4),(2,3),(0,2),(-4,0)[/tex]

We first obtain the slope (m)

The formula for finding the slope is given as

[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]

Using the points (0,2) and (-4,0) (indeed we can pick any two points, we will still obtain the same answer)

Here

[tex]\begin{gathered} x_1=0 \\ y_1=2 \\ x_2=-4 \\ y_2=0 \end{gathered}[/tex]

[tex]\begin{gathered} m=\frac{y_2-y_1}{x_2-x_1} \\ m=\frac{0-2}{-4-0} \\ m=\frac{2}{4} \\ m=\frac{1}{2} \\ m=0.5 \end{gathered}[/tex]

We can use any of the points above to find the equation

Equation of a line is given by

[tex]y-y_1=m(x-x_1)[/tex]

Using (4,4)

[tex]y-4=0.5(x-4)[/tex]

Option D is correct

Using (2,3)

Eighth grad Checkpoint: Understand functions 6NP Which of these relations are functions? Select all that apply. X y 20 -12 12 9 17 2 2013 11 14 -7 3 6 -8 15 16 6 -18 16 15 9 20 15 -9 -5 12 -13 4 20 -18 10 17 13 2. 8 15 Submit

Answers

In a function, any x-value is related to at most 1 y-value.

In the first table, x = 20 and x = 17 are related to 2 different y-values. Then, it is not a function.

In the second table, x = 9 is related to 2 different y-values. Then, it is not a function.

The third and fourth tables are functions

What are the coefficient(s) in the following expression:
x² + 2x-5xy-y+3y¹
2,4
A
B
C
D
1, 2, 5, 1,3
2,-5, 3
1, 2, 5, 1, 3

Answers

Step-by-step explanation:

based on the expression you wrote here, the correct answer is

1, 2, -5, -1, 3

since none of your answer options show this, you must have made a mistake either with the expression itself or with the answer options.

please choose in your original the one matching my answer above.

Given the function f(x)={4x+7 if x<0 6x+4 if x>0 _

Answers

Given:

[tex]f(x)=\begin{cases}4x+7ifx<0{} \\ 6x+4ifx\ge0{}\end{cases}[/tex]

Required:

To find the value of f(-8), f(0), f(4), and f(-100)+f(100).

Explanation:

f(-8) :

Clearly -8<0,

So

[tex]\begin{gathered} f(x)=4x+7 \\ f(-8)=4(-8)+7 \\ =-32+7 \\ =-25 \end{gathered}[/tex]

f(0) :

Clearly 0=0,

[tex]\begin{gathered} f(x)=6x+4 \\ =6(0)+4 \\ =4 \end{gathered}[/tex]

f(4) :

Clearly 4>0,

[tex]\begin{gathered} f(x)=6x+4 \\ f(4)=6(4)+4 \\ =24+4 \\ =28 \end{gathered}[/tex]

f(-100)+f(100) :

-100<0

[tex]\begin{gathered} f(x)=4x+7 \\ f(-100)=4(-100)+7 \\ =-400+7 \\ =-393 \end{gathered}[/tex]

100>0

[tex]\begin{gathered} f(x)=6x+4 \\ f(100)=6(100)+4 \\ =600+4 \\ =604 \end{gathered}[/tex][tex]\begin{gathered} f(-100)+f(100)=-393+604 \\ \\ =211 \end{gathered}[/tex]

Final Answer:

[tex]\begin{gathered} f(-8)=-25 \\ \\ f(0)=4 \\ \\ f(4)=28 \\ \\ f(-100)+f(100)=211 \end{gathered}[/tex]

need help with part a with a summary and all work shown to help me understand better

Answers

ANSWER:

[tex]\left(16u^{\frac{1}{3}}\right)^{\frac{3}{4}}=8\sqrt[4]{u}[/tex]

STEP-BY-STEP EXPLANATION:

We have the following expression:

[tex]\left(16u^{\frac{1}{3}}\right)^{\frac{3}{4}}[/tex]

When you raise an exponent to another exponent, multiply therefore:

What is a quadrilateral that has reflection symmetry, but not rotation symmetry?

Answers

The quadrilaterals, parallelogram,square, rectangle has rotational symmetry but no reflectional symmetry

A trapezoid has neither a rotational symmetry nor a reflectional symmetry

But for an isosceles with only one pair of parallel sides has a reflectional symmetry but no rotational symmetry

Thus, the correct answer is

an isosceles with only one pair of parallel sides

The con 3720bertar What can be interpreted from the youtercept of the functionRachel must pay $37 per month to use the gymRachel must pay $20 per month to use the gymRachel must pay a $37 membership fee to join the gymRachel must pay a $20 membership fee to join the samMaria wants to rent a car. She learns that the total daily costcated using the formula C = 5x + 30. hereseS driven that day. What does the constanteseer

Answers

f(x) = 37x + 20

Answer:

Option D, $20 is the membership beause it is a fixed cost, it does not depend on the amount of months

Other Questions
please be quickdont guess Multiple part question Here are the needed details:Five rotations took 5.15 seconds 1 rotation took 1.07s Distance from shoulder to elbow is 29 cm distance from shoulder to middle of the hand is 57cm.Questions:2. A how far in degrees did the hand travel during the five rotations?B. How far in radians did the hand travel during the five rotations?C. How far in meters did the hand travel during the five rotations?3. A. What was the average angular speed (degrees/s and rad/s) of the hand?B. What was the average linear speed (m/s) of the hand?C. Are the answers to a and b the same or different? Explain.4. A. What was the average angular acceleration (degrees/s squared and rad/s squared) of the hand. How do you know?B. What was the average centripetal acceleration (m/s squared) of the hand?C. Are the answers to a and b the same or different. Explain.5. A. How far (degrees and rad) did the elbow travel during the five rotations?B. How far (m) did the elbow travel during the five rotations?C. How do these compare to the hand? Why are they the same and or/different?6. A. What was the average angular speed (degrees/s and rad/s) of the elbow?B. What was the average linear speed (m/s) of the elbow?C. How do these compare to the hand? Why are they the same and or/different?7. A. What was the average angular acceleration (degrees/s squared and rad/s squared) of the elbow?B. What was the average centripetal acceleration (m/s squared) of the elbow?C. How do these compare to the hand? Why are they the same and or/ different? Which of the following statements accurately explains the relationship between time of day and water transport through the plants? (Answer choices in the photo, and a graph.) What verb tense should you use when describing a scene in a novel?past tensePerfect tensepresent tensefuture tense x^2+5x21=0complete the square a user is able to access privileged administrative features with an account that is not granted administrator rights. which type of vulnerability is this? a large population of laboratory animals has been allowed to breed randomly for a number of generations. after several generations, 25% of the animals display a recessive trait (a2a2), the same percent as at the beginning of the breeding program. the rest of the animals show the dominant phenotype, with heterozygotes indistinguishable from the homozygous dominants. what proportion of the population is most likely heterozygous (a1a2) for this trait? If f (x) = 4x^3 - 25x^2 154x+ 40 and (x - 10) is a factor, what are the remaining factors? Solve for y Simplify your answer as much as possible Find by linear equation. Solve negative 2 times y plus seven fifths times y equals negative 4 minus three fifths times y minus 2 for y. y = 0 y = 13 No solution Infinite solutions theres 2 fill in the blank boxes and 3 drop down menus, below i will list the options in the drop down menus.box 1 - apply quotient identities, apply Pythagorean identities, apply double-number identities, apply even-odd identities.box 2 - apply cofunction identities, use the definition of subtraction, apply even-odd identities, Write as one expresssion combine like terms.box 3 - apply cofunction identities, apply double-number identities, apply Pythagorean identities, apply even-odd identities. Find the zeros by using the quadratic formula and tell whether the solutions are real or imaginary. F(x)=x^28x+2 help me please :"))))))))))) Question 13 (3 points)Intel's microprocessors have a 1.8% chance of malfunctioning. Determine theprobability that a random selected microprocessor from Intel will not malfunction.Write the answer as a decimal. during the twentieth century, while some acting teachers were focused on the inner workings of the actor, other acting teachers were focused on the blank side of performance. multiple choice question. intellectual emotional monetary physical Which of the following best describes terms that have the same degree in the same radicand? A. like rational termsB. like fractional termsC. like radical termsD. like polynomial terms Which of the following options correctly represents the complete factored form of the polynomial F(x)= x - x2 - 4x-6? Which statements are correct interpretations of this graph?(multiple choice!) (please don't be rude.)There are 3 g of dietary fiber in every 2 tomatoes.There are 1.5 g of dietary fiber per tomato.There are 0.7 g of dietary fiber per tomato.There are 2 g of dietary fiber in every 3 tomatoes. how do we do this one there two parts to i t Determine the height of the lift, in metres, above the gym floor. show all your work algebraically. round to the nearest cm, if necessary.