Answer:
The quantity which have both magnitude and direction is called vector quantity
A physical Quantity, which has magnitude, direction and units But must follow the traingle law of vector addition
Example:- Force, velocity acceleration displacement etc.
Two blocks, with masses m1= 1.5kg and m2= 2.5kg approach each other
with initial velocities; V1= 2.0 m/s and V2i= 3.0 m/s. The two blocks
collide, in a totally inelastic collision, what is their common final velocity
after collision? *
Answer:
2.625 m/s
Explanation:
This is a momentum question. Momentum is conserved which means that all the starting momentum must be accounted for.
1.5 kg * 2 m/s + 2.5 kg * 3 m's = (1.5 + 2.5)kg * x m/s
3 kg m/s + 7.5 kg m/s = 4 kg * x
10.5 kg m/s = 4 kg x
10.5 / 4 = x
x = 2.625 m/s
inelastic means that after the collision, the masses stick together as though they were one.
Q2 ) Starting from rest on a level road a girl can reach a speed of 5m/s in 10 s on her bicycle, find
A) the acceleration
Answer:
0.5m/s²
Explanation:
Given parameters:
Initial velocity = 0m/s
Final velocity = 5m/s
Time taken = 10s
Unknown:
Acceleration of the bicycle = ?
Solution:
Acceleration is the rate of change of velocity with time.
Acceleration = [tex]\frac{v - u}{t}[/tex]
v is the final velocity
u is the initial velocity
t is the time taken
Insert the parameters and solve;
Acceleration = [tex]\frac{5-0}{10}[/tex] = 0.5m/s²
Someone answer these questions please???
Answer:
a. same
b. less
c. less
Explanation:
you can use the position, time, acceleration equation
xf=xi + vi*t+(at^2)/2
you can say the final distance will greater for X than Y
using acceleration for gravity a=9.81m/s^2
a. both X and Y will have the same acceleration due to gravity
b. to solve for final speed vf=vi+gt
since the initial velocity is 0 and X will take longer to fall, Y will hit the ground with less speed
c. as mentioned before, X will take longer to fall; therefore Y will have less time of descent.
A ball is thrown vertically upwards with a velocity of 9.8 m/s. Its velocity after 1 second will be
[ Take g = 9.8 ms¯²]
9.8 m/s
19.6 m/s
Zero
2.45 m/s
[tex] \LARGE{ \underline{\underline{ \purple{ \bf{Required \: answer:}}}}}[/tex]
GiveN:
Initial velocity = 9.8 m/s²Accleration due to gravity = -9.8 m/s²Time taken = 1 sTo FinD:
Final velocity of the ball?Step-by-step Explanation:
Using the first Equation of motion,
⇒ v = u + gt
⇒ v = 9.8 + -9.8(1)
⇒ v = 0 m/s
The final velocity is hence 0 m/s.
Note:While solving questions of under gravity motions using equations of motion, remember the sign convection to avoid mistakes.You can consider positive above the ground and negative for towards it.Importance of measurement
Answer:
Without the ability to measure, it would be difficult for scientists to conduct experiments or form theories. Not only is measurement important in science and the chemical industry, but it is also essential in farming, engineering, construction, manufacturing, commerce, and numerous other occupations and activities.
Explanation:
Make sure to edit so you're not copy-writed and if this was helpful could I please get brain-list
please help! i need the answers asap!!! 10 points!!!!!
Answer:
Hydrogen and helium
Answer:
1. iron, nickel, calcium, sodium, and magnesium
2. nuclear fusion
Explanation:
I googled it
A pumpkin is thrown horizontally off of a building at a speed of 2.5 m/s and travels a horizontal distance of 12 m before hitting the ground.
What was the initial height of the pumpkin?
What was the final vertical velocity of the pumpkin?
Answer:
-47.04
Explanation:
Divide 12 m by 2.5 m/s which equals 4.8s
And then use 4.8s to multiply it with -9.8
4.8(-9.8)= -47.04 m/s
Hope this helped!! :)
The initial height of the pumpkin is 23.52m and the final vertical velocity of the pumpkin is 47.04 m/s.
Laws of motion:Initial horizontal speed, u = 2.5 m/s
horizontal distance covered , d = 12m
So the time taken is:
t = d/u
t = 12/2.5 s
t = 4.8s
Now, the initial vertical speed, v = 0
So the vertical distance traveled by the pumpkin will be equal to the initial height of the pumpkin:
s = vt + ¹/₂gt²
s = 0.5 × 9.8 × 4.8 m
s = 23.52m
Final vertical velocity:
v' = v + gt
v' = 9.8 × 4.8 m/s
v' = 47.04 m/s
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Each box in the Punnett square is equal to _____
1/2
25%
3/4
50%
Answer:
I think it's 3/4 or 25% i am not sure
Based on its location on the periodic table, which element could be used for
electrical wiring?
A. Argon (Ar)
B. Bromine (Br)
c. Aluminum (AI)
D. Phosphorus (P)
Physical activity increases your risk for coronary artery disease. true false
Answer:
false here is why :)
Explanation:
Regular, moderate-intensity physical activity reduces the risk of developing coronary heart disease and can reduce the likelihood of dying from heart disease.
hope this helped.
An object has a coefficient of kinetic friction of 0.2 and a normal force of 30N. Find the force of kinetic friction.
Answer:
Force of kinetic friction, Fk = 6N
Explanation:
Given the following data;
Coefficient of kinetic friction, μ = 0.2
Normal force, Fn=30N
To find the Force of kinetic friction;
Mathematically, the force of kinetic friction is given by the formula;
Fk = μFn
Where;
Fk represents the force of kinetic friction. μ represents the coefficient of friction. Fn represents the normal force.Substituting into the equation, we have;
Fk = 0.2*30
Fk = 6N
Therefore, the force of kinetic friction is 6N.
A force that is present between two moving objects or surfaces is called kinetic friction. It is estimated in newtons (N) and is calculated by:
[tex]\rm F_{k} =\rm \mu _{\rm k} F_{n}[/tex]
Where, [tex]\rm F_{k}[/tex] = frictional force, [tex]\mu _{\rm k}[/tex] = coefficient, [tex]\rm F_{n}[/tex] = normal force.
The kinetic friction of the object is 6N.
The kinetic friction can be estimated as:
Given,
Coefficient of kinetic friction ([tex]\mu[/tex]) = 0.2Normal force [tex]\rm F_{n}[/tex] = 30 NSubstituting values in the formula:
[tex]\rm F_{k} =\rm \mu _{\rm k} F_{n}[/tex]
[tex]\begin{aligned}\rm F_{k} &= 0.2 \times 30\\\\\rm F_{k} &= 6 \rm N\end{aligned}[/tex]
Therefore, 6N is the frictional force.
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Moon A has a mass of 3M and a radius of 2R. Moon B has a mass of 4M and a radius of R. What is the ratio of the force of gravitational attraction of Moon A for Moon B to the force of gravitational attraction of Moon B for Moon A?
A.) 1:1
B.) 1:5.3
C.) 5.3:1
D.) 0.75:4
Answer:
c
Explanation:
5.3" (and any subsequent words) was ignored because we limit queries to 32 words.
How could sound waves damage solid objects like a spacecraft?
5. Describe the trip from your home to school using the words
position, distance, displacement, and speed.
My commute to school is a constant distance, but the time it takes to get there fluctuates owing to traffic.
What is displacement?If an object moves with respect to a reference frame, such as when a passenger travels to the back of an airliner or a professor moves to the right with respect to a whiteboard, the item's position changes.
This change in location is described as displacement.
My commute to school is a constant distance, but the time it takes to get there fluctuates owing to traffic,
The initial and the final position of the commute is the same, but the displacement varies with the route which affects my car's speed and where it is in line at stop lights.
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15 POINTS URGENT DUE IN 5 MINUTES :(
please don’t troll.
A. A woman hiked on a trail up a mountainShe slowed down as it became more steep. She stopped at the top to take in the view below. Then she continued on the trail and walked down the other side of the mountain.
B. A truck driver left a warehouse and drove on a highway at a constant speed before he stopped for lunch. To make up for lost time, he drove faster when he got back on the highway. He unloaded his haul and drove quickly back to the warehouse.
C. A woman drove her car up steep bill and stopped at a red lightWhen the light turned green she continued to drive up the rest of the hill until she reached the gas station. She stopped to buy gas and then drove down the other side of the hill towards her office.
D. A man ran in a race and accelerated steadily for the first hour. He then continued briefly at a constant pace while he had the lead. When other runners began to catch up he accelerated againHe then continued at a constant high speed. He became overtired and slowed down until he had to completely stop running.
Answer:
D now go to ur good life :)
Explanation:
Answer:
blah
Explanation:
blah
Which type of image can be projected on a screen?
real
plane
imaginary
virtual
This Is My Last Question PLZ Help
Answer:
A real image.
Explanation:
A real image is formed by real interaction of rays, hence it is possible to project it on a screen. And where a virtual image is drawn via back tracing the path of reflected rays, hence they don't meet in reality.
After our sun leaves the main sequence it will most likely...
A.) become a supergiant and explode in a supernova explosion
B.) become a giant and eventually form a black hole
C.) become a supergiant and eventually form a dwarf star
D.) become a giant and eventually form a dwarf star
Answer:
c
Explanation:
NEED HELP TODAY
Which of the following is true about the speed of light?
A. It depends on the wavelength
B. In a vaccum, it is a constant value that does not depend on the observer
C. It is the slowest in a vacuum unless the observer is moving towards the source
D. In a vacuum, it varies depending on the color of the light
Answer:
I am pretty sure it is B My friend hope you are well
Explanation:
Answer:
B- It is a constant when the light is traveling in a vacuum.
Explanation:
"Light in a vacuum always travels at the same speed." Those additional three words in a vacuum are very important. A vacuum is a region with no matter in it. So a vacuum would not contain any dust particles (unlike a vacuum cleaner, which is generally full of dust particles)
A large truck of mass 5000 kg is travelling at 5.0 m/s.
A motorbike has a mass of 200 kg. Both the truck and the motor bike have the same kinetic energy
What is the speed of the motorbike?
A 25 m/s
B 10 m/s
C 125m/s
D 2.5 m/s
Answer:
A - 25m/s
Explanation:
The velocity of the motorbike will be 25 m/s in order to ensure that the truck and the motor bike have the same kinetic energy.
What is Kinetic Energy?The kinetic energy of the body is by the virtue of its motion.
Given is a large truck of mass 5000 kg which is travelling at 5.0 m/s and a motorbike that has a mass of 200 kg. Both the truck and the motor bike have the same kinetic energy.
The Kinetic energy of the truck will be -
E[T] = 1/2 mv² = 1/2 x 5000 x 25 = 2500 x 25 = 62500 joules
Then Kinetic energy of the motorbike will be -
E[M] = 1/2 x 200 x v²
E[M] = 100v² joules
Now-
E[T] = E[M]
100v² = 62500
v² = 625
v = 25 m/s
Therefore, the velocity of the motorbike will be 25 m/s in order to ensure that the truck and the motor bike have the same kinetic energy.
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10. A golf ball is propelled with an initial velocity of 60
meters per second at 37° above the horizontal. The
horizontal component of the golf ball's initial veloc-
ity is
the horizontal component of the golf ball's initial velocity is 47.92 m/s.
The given parameters;
initial velocity of the golf, v = 60 m/s
angle of projection of the golf, Ф = 37°
The horizontal component of the golf ball's initial velocity is calculated as follows;
[tex]v_0_x = v\times cos(\theta)\\\\[/tex]
[tex]v_0_x[/tex] = 60 m/s x cos (37)
[tex]v_0_x[/tex] = 60 m/s x 0.7986
[tex]v_0_x[/tex] = 47.92 m/s
Thus, the horizontal component of the golf ball's initial velocity is 47.92 m/s.
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While john is traveling along a straight in interstate highway, he notices that the mile marker reads 242 mm. John travels until he reaches the 147 km marker and then retraces his path to the 161km marker. What is John's resultant displacement from the 242km marker? How far has he traveled answer in units of km
Complete Question
While john is traveling along a straight in interstate highway, he notices that the mile marker reads 242 km. John travels until he reaches the 147 km marker and then retraces his path to the 161 km marker. What is John's resultant displacement from the 242 km marker? How far has he traveled answer in units of km
Answer:
The resultant displacement [tex]\Delta x _{1 , 3} = 81 \ km[/tex]
The total distance traveled by john is [tex]x_t =109 \ km[/tex]
Explanation:
From the question we are told that
The first position of john from the finish point is [tex]x_1 = 242 \ km[/tex]
The second position of john from the finish point is [tex]x_2 = 147 \ km[/tex]
The third position of john from the finish point is [tex]x_3 = 161 \ km[/tex]
Generally the displacement from the 242 km marker is mathematically represented as
[tex]\Delta x _{1 , 3} = x_1 - x_3[/tex]
Here we used [tex]x_3[/tex] instead of [tex]x_2[/tex] because [tex]x_3[/tex] is further than [tex]x_2[/tex] from the finish point
=> [tex]\Delta x _{1 , 3} = 81 \ km[/tex]
Generally the total distance traveled by John is mathematically evaluated as
[tex]x_t = [x_1 - x_2 ] + [x_3 - x_2][/tex]
=> [tex]x_t = [242 - 147 ] + [161 - 147][/tex]
=> [tex]x_t =109 \ km[/tex]
A 60 kg adult and a 30kg child are passengers on a rotor ride at an amusement park as shown in the diagram above. When the rotating hollow cylinder reaches a certain constant speed, v, the floor moves downward. Both passengers stay "pinned" against the wall of the rotor, as shown in the diagram below.
The magnitude of the frictional force between the adult and the wall of the spinning rotor is F. What is the magnitude of the frictional force between the child and the wall of the spinning rotor?
Answer:
fr ’= ½ F
Explanation:
For this exercise we use the translational equilibrium equation, on the axis parallel to the wall
fr - W = 0
fr = W
for the adult man they indicate that the friction force is equal to F
F = M g
we write the equilibrium equation for the child
fr ’= w’
fr ’= m g
in the statement they tell us that the mass of the adult is 2 times the mass of the child
M = 2m
we substitute
fr ’= M / 2 g
fr ’= ½ Mg
we substitute
fr ’= ½ F
therefore the force of friction in the child is half of the friction in the adult
Question 2 The gravitational force between two objects with identical masses that are 10 m apart, is 2.67 x10-10 N. To the nearest kg, what is the mass of each object? -11 Nom? Se G= Universal Gravitational Constant = 6.67 x 10 kg? 2 kg O O 10 kg 20 kg O 200 kg
Answer 888990,0 kg
Explanation:
888990,0 kg is the mass of the object.
What is Gravitational force?
Any two mass-containing objects are attracted to one another by the gravitational force. Because it consistently attempts to pull masses together rather than pushing them apart, the gravitational force is known as attractive.
Newton's Universal Law of Gravitation is what it is known as.
Admittedly, you aren't pushing on those other objects all that much because you don't have a very large mass. Additionally, items that are very far apart from one another do not clearly tug on one another.
Therefore, 888990,0 kg is the mass of the object.
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suppose you want to model girlfriend of a baby orangutan which type of model would you choose
Answer:
That model grilfriend would probably only want me for the cash and would talk to a million other guys...but the baby orangutan would love me and I would be able to take care of a cute baby!!:)
Explanation:
what's the difference between food chain and food web. i will give brainliest.
Answer:
Food chain is a linear transfer of energy from the producer to the consumer
producer →primary consumer → secondary consumer → tertiary consumer while food web is the interconnection of two or more food chains
anybody wana play imvu or 2k
A runner is training and runs past meter mark 65 and starts a stopwatch. After the runner passes meter mark 15 the stopwatch stops at 8 seconds. What was the runners velocity?
Question 5 options:
-6.25 m/s
6.25 m/s
8.13 m/s
-1.88 m/s
Answer:
-6.25 m/s
Explanation:
i took the quiz
An instrument used to detect the current in a
circuit is called
Answer:
Ammeter
Explanation:
An ammeter is used to measure current.
An aeroplane accelerates from rest at a rate
of 25m/s² for 3 s .calculate final velocity
Answer:
The final speed is 75 m/s
Explanation:
Constant Acceleration Motion
It's a type of motion in which the velocity of an object changes uniformly in time.
Being a the constant acceleration, vo the initial speed, vf the final speed, and t the time, the following relation applies:
[tex]v_f=v_o+at[/tex]
The airplane comes from rest (vo=0) accelerating at a=25 m/s^2 for t=3 s.
The final speed is:
[tex]v_f=0+25~m/s^2\cdot 3~s[/tex]
[tex]v_f=75~m/s[/tex]
The final speed is 75 m/s
would someone just answer this now?
Answer:
x=36.5 m
Explanation:
Rectangular Components of a Vector
A vector can be expressed as an ordered pair (x,y) where x is the x-coordinate, and y is the y-coordinate of a rectangular system.
It can also be given as a magnitude-angle pair (r,θ) where θ is measured from the positive x-axis. It's also known as polar coordinates.
The conversion from polar to rectangular coordinates is:
[tex]x=r\cos \theta[/tex]
[tex]y=r\sin\theta[/tex]
We are given the vector as a magnitude r=47.3 m and at an angle θ=39.4°. The x-component of the vector is:
[tex]x=47.3\cos (39.4^\circ)[/tex]
Using a scientific calculator to find the trigonometric function:
[tex]x=47.3\cdot 0.7716[/tex]
x=36.5 m