What is the theoretical yield when 1.1134 g of gold (III) oxide is reacted with 20.0 L of H2 at 1.000 atm and 800K.

Answers

Answer 1

The theoretical yield of the gold is 0985 g

What is the theoretical yield?

Recall that the yield is defined as the mass of the product that is obtained in the reaction. Let us recall that a chemical reaction must involve the interaction of the reactants so as to obtain in a given amount, the products of the particular reaction that is in question.

Now;

Number of moles of the gold (III) oxide  = 1.1134 g/442 g/mol = 2.5 * 10^-3 moles

We can get the number of moles of the hydrogen from the ideal gas equation;

PV = nRT

n = PV/RT

n = 1.000 atm  * 20.0 L/0.082 atm LK-1mol-1 *  800K

n = 0.3 moles

Given that the mole ratio of the reaction is 1 mole of the oxide to three moles of hydrogen;

1 mole of gold (III) oxide reacts with 3 moles of hydrogen

2.5 * 10^-3 moles of gold (III) oxide reacts with 2.5 * 10^-3 moles *  3 moles /1 mole

= 7.5 * 10^-3 mole of hydrogen

Hence the hydrogen is present in excess.

The theoretical yield =

1 mole of the oxide produced 2 moles of the gold

2.5 * 10^-3 moles of the oxide produced 2.5 * 10^-3 moles * 2 moles/1 mole

= 5 * 10^-3 moles of gold

Theoretical yield = 5 * 10^-3 moles of gold * 197 g/mol

= 0985 g

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Related Questions

What do I do to fill out the table, what belongs where ?

Answers

1) Write the proper formula for Mg2+ and Br-

Balance the charges.

Mg2+: Multiply by 1. This gives a total of two positive charges.

Br-: Multiply by 2. This gives a total of two negative charges.

Use multipliers as subscripts

[tex]\text{MgBr}_2[/tex]

2) Write the proper formula for Al3+ and O2-

Al3+: Multiply by 2. This gives a total of six positive charges.

O2-: Multiply by 3. This gives a total of six negative charges.

Use multipliers as subscripts

[tex]Al_2O_3[/tex]

A solution is made using 80.1 g of dimethyl ether (MM = 46.07 g/mol) and 110.0 g of methanol (MM = 32.04 g/mol). What is the molality of the dimethyl ether in the solution?​

Answers

The molality of the dimethyl ether in the solution is 15.8m

What is molarity ?

Molality (m), or molal concentration, is the amount of a substance dissolved in a certain mass of solvent. It is defined as the moles of a solute per kilograms of a solvent.

Moles of dimethyl ether= 80.1/46.07 = 1.74 moles

Molarity = moles of solute/ mass of solvent * 1000

                1.74/110*1000 = 15.8m

The molality of the dimethyl ether in the solution is 15.8m

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NEVERMINDDDDDDDDDDDDDDD

Answers

Answer:

what is this free

branliest?

Which of the following is a combination reaction?A) C) N2 (g) + 02 (g) → 2NO (g)-BB) KOH (aq) + HNO3 (aq) → HN20 (/) + KNO3 (aq)CA) CaCl2 (aq) + Na2SO4 (aq) → CaSO4 (s) + 2NaCl (aq)DD) AgNO3 (aq) + NaCl (aq) - AgCl (s) + NaNO3 (aq)

Answers

Combination (also called synthesis): Where two elements or one compound and one element will bond and form a new compound as a product, the representation for this reaction is:

A + B -> AB

The only option that follows this description of Combination reaction is the first reaction:

N2 + O2 -> 2 NO

In Peft A, we saw that the theoretical yield of aluminum oxide is 1.50 mol. Calculate the percent yield if the actual yield ofaluminum oxide is 0.885 mol .Express your answer with the appropriate units.D View Available Hint(s)

Answers

Explanation:

The theoretical yield of our reaction is 1.50 moles, the actual yield of aluminum oxide is 0.885 moles. The percent yield is:

percent yield = actual yield/theoretical yield * 100 %

percent yield = 0.885 moles/(1.50 moles) * 100 %

percent yield = 59.0 %

Answer: The percent yield is 59.0 %.

What are some assumptions and observations of this map, relating to the use of relations and polynomials?

Answers

ANSWER

STEP-BY-STEP EXPLANATION

A 51.72 g sample of a substance is initially at 23.5 °C. After absorbing 2547 J of heat, the temperature of the substance is 123.4 °C. What is the specific heat ( ) of the substance?

Answers

The heat absorbed or released by a substance is given by the following formula:

[tex]Q=m\cdot Cp\cdot(T2-T1)[/tex]

Where Q is the heat absorbed or released, m is the mass of the substance, Cp is the specific heat, T2 is the final temperature and T1 is the initial one.

We know the values of Q, m, T2 and T1 because they are given by the question statement, and we have to find the value of Cp.

Solve the equation for Cp and use the given values to find its value:

[tex]\begin{gathered} Cp=\frac{Q}{m\cdot(T2-T1)} \\ Cp=\frac{2547J}{51.72g(123.4\degree C-23.5\degree C)} \\ Cp=\frac{0.49J}{g\degree C} \end{gathered}[/tex]

The specific heat of the substance is 0.49J/g°C.

The sheet of gold foil Rutherford used was 304 mm wide and 0.016 mm thick. What maximum length of gold foil could be made from 1.10 x 103 g of gold?

Answers

The maximum length of gold foil could be 1171.7 cm made from 1.10 x 10³ g of gold.

What is the density?

The density of an object can be described as the mass per unit volume. The average density is equal to the total mass divided by its total volume.

The mathematical formula of the density of the material can be expressed as follows:

Density = Mass/Volume

The density of a substance is an intrinsic property as it doesn't depend on its size and the S.I. unit of the density is Kg/m³.

Given the width of the gold foil, w = 304 mm = 30.4 cm

The height or thickness of the foil, h = 0.016 mm = 0.0016 cm

The density of the gold foil, d = 19.3 g/cm³

The mass of the gold given, m = 1100 g

The volume of the foil = m/d = 1100/ 19.3 = 56.99 g/cm³

As we know that the volume of  gold foil , V = l × w × h

l = V/(w × h)

l = 56.99/(30.4 × 0.0016)

l =1171.7 cm

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Choose the effect of acid you think is most important, and justify your choice.​

Answers

The effect of acid you think is most important because chemical that can donate a hydrogen ion to other molecule

Acid is an that in water solution taste sour and changes blue litmus to red and react to some metal to liberate hydrogen react with bases to form salt and and also promote chemical reaction and the effect of acid is the chemical that can donate hydrogen ion to other molecule and the result in other molecule changing shape and possibly breaking apart

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A process that may lead to gamates containing too many or too few chromosomes is called?

(A) Recombination

(B) Crossing over

(C) Karyogenesis

(D) Nondisjunction

Answers

Answer:

D) Nondisjunction

Explanation:

Nondisjunction happens when a chromosome pair doesn't separate during meiosis. A result is one of the gamates has to any chromosome, while others have much less.

The volume of a gas is 200 mL at 330.0 kPa what will the volume be when the pressure is reduced to 45.0 kPa assuming the temperature remains constant

Answers

Answer

V2 = 1466.7 mL

Explanation

Given:

Volume 1 = 200 mL

Pressure 1 = 330.0 kPa

Pressure 2 = 45.0 kPa

Required: Volume 2

Solution:

To solve this problem we will use Boyles law

P1V1 = P2V2

V2 = P1V1/P2

V2 = (330.0 kPa x 200 mL)/45.0 kPa

V2 = 1466.7 mL

How many liters of oxygen gas are required to burn 6.82 L of acetylene (C2H2) at STP?

Answers

17.05 L of O₂ are needed to react with 6.82 L of acetylene gas C₂H₂ at STP.

The reaction to the given question is :

2 C₂H₂ + 5 O₂ → 4 CO₂ + 2 H₂O

From the equation we see

2 moles of C₂H₂ react with 5 moles of O₂

According to the equation,

        2 liters of Acetylene reacts with  =  5 liters of O₂

So,

             6.82 L Acetylene will produce  =  X L of O₂

Solving for X,

                         X  =  ( 6.82 L × 5 L ) ÷ 2 L

                         X  =  17.05 L of O₂

Thus, 17.05 L of O₂ is needed to react with 6.82 L of acetylene gas C₂H₂.

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100 points!
Why rusting is a chemical change?
1-A new reactant is formed
2-A new product is formed
3-There is increased activation energy
4-A new substance is not formed

Answers

Answer: 4

Explanation:

Why are valence electrons so important?A.They determine what element on the periodic table the atom is.B.They do not form any bonds.C.They are the electrons that participate in chemical reactions.D.They are in the nucleus of the atom.

Answers

Answer:

Explanation:

C

Answer:

I think the answer to your question is option A.

7. A given sample of gas is held in a container with the volume of 6.02 L with a temperature of 59.5℃ at a pressure of 1.20 atm. What is the final pressure when the sample of gas is administered to a new volume of 10.0 L at 20.2℃?

Answers

The final pressure when the sample of gas is administered to the new volume and temperature is 0.64 atm.

What is the final pressure when the sample of gas?

Combined gas law put together both Boyle's Law, Charles's Law, and Gay-Lussac's Law. It states that "the ratio of the product of volume and pressure and the absolute temperature of a gas is equal to a constant.

It is expressed as;

P₁V₁/T₁ = P₂V₂/T₂

Given the data in the question;

Initial volume V₁ = 6.02LInitial pressure P₁ = 1.20 atmInitial temperature T₁ = 59.5℃ = ( 59.5 + 273.15 )K = 332.65KFinal volume V₂ = 10.0L Final temperature T₂ = 20.2℃ = ( 20.2 + 273.15 )K = 293.35KFinal pressure P₂ = ?

To determine the final pressure of the gas, plug the given values into the formula above and solve for P₂.

P₁V₁/T₁ = P₂V₂/T₂

P₁V₁T₂ = P₂V₂T₁

P₂ = P₁V₁T₂ / V₂T₁

P₂ = ( 1.20 atm × 6.02L × 293.35K ) / ( 10.0L × 332.65K )

P₂ = ( 2119.1604 KLatm ) / ( 3326.5 KL )

P₂ = 0.64 atm

Therefore, the final pressure of the gas is 0.64 atm.

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According to Newton's Second Law, which of the following is TRUE?

Answers

Answer: the second one

Explanation:

Answer:

there's no answer choices?

WILL MARK BRAINLIEST! THIS IS DUE TODAY

1) Isotopes of certain____ elements that spontaneously emit ____ and ____ from the ___.

2) In a nuclear fusion reaction, two small, light ____(hydrogen atoms) combine under extreme ____ and pressure to form one larger, heavier nucleus (helium).

Answers

1)Isotopes of certain radioactive elements that spontaneously emit radiation and rays from the nuclei.

2)In a nuclear fusion reaction, two small, light 'nuclei' (hydrogen atoms) combine under extreme 'temperature' and pressure to form one larger, heavier nucleus (helium).

What are nuclear fusion ?

The Sun and other stars are powered by nuclear fusion reactions. A heavier nucleus is created when two light nuclei fuse together in such a fusion reaction. So because mass of the emerging single nucleus is smaller than that of the combined mass of the two initial nuclei, the process generates electricity. Remaining mass is converted to energy.

Why nuclear fusion is not possible?

Normal electrostatic forces between positively charged nuclei prohibit them from coming close enough to smash and allow fusion to occur, hence fusion is not feasible.

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5. 10.1 grams of hydrogen gas is contained in a volume of 5.00 L at a temperature of 37.5℃. Find the pressure of the gas.

Answers

Answer: 2607.31 pa

Explanation:

n = 10.1/2 = 5.05 mol

Now, according to ideal gas equation,

PV = nRT

⇒ P × 5 = 5.05 × 8.314 × (37.5 +273)

⇒P = 2607.31 Pa

A sheet of gold weighing 10.7 g and at a temperature of 19.8°C is placed flat on a sheet of iron weighing 18.7 g and at a temperature of 53.3°C. What is the final temperature of the combined metals? Assume that no heat is lost to the surroundings.

Answers

A sheet of gold weighing 10.7 g and at a temperature of 19.8 °C is placed flat on a sheet of iron weighing 18.7 g and at a temperature of 53.3 °C. the final temperature of the combined metals is 48.87 °C.

given that :

weight of gold , m= 10.7 g

temperature, T = 19.8 °C

weight of iron , m = 18.7 g

temperature, T = 53.3 °C

final temperature t = ?

specific heat for gold , c = 0.12 J/ g °C

specific heat for iron , c =  0.45 J/ g °C

now, using the specific heat formula we get :

( mc ΔT ) + ( mc ΔT ) = 0

( 10.7 × 0.12 ×( t - 19.8 )  +  ( 18.7 × 0.45 × (t - 53.3 ) = 0

(1.28 t - 25.4) + ( 8.41 t - 448.2 ) = 0

9.69 t = 473.6

t = 48.87 °C

Thus, A sheet of gold weighing 10.7 g and at a temperature of 19.8 °C is placed flat on a sheet of iron weighing 18.7 g and at a temperature of 53.3 °C. the final temperature of the combined metals is 48.87 °C.

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35.A substance that affects the speed of a chemical reaction without itself being chemically changed is called a...Select one:a. catalyst.b. product.c. reactant.d. yield.

Answers

Answer

A. catalyst

Explanation

Catalyst, in chemistry, any substance that increases the rate of a reaction without itself being consumed.

Write formulas or names as appropriate for each of the following acids. 1. Hydroiodic acid 2. Carbonic acid 3. Chlorous acid 4. Sulfuric acid 5. Phosphorous acid 6. HCN (aq) 7. H2C2O4 (aq) 8. HNO2 (aq) 9. H2Cr2O7 (aq) 10. HMnO4 (aq)

Answers

ANSWER

The chemical formula of Hydroiodic acid is HI

EXPLANATION

Hydroiodic acid is formed from a reaction between hydrogen and iodine resulting into an aqueous solution of Hydrogen iodide

[tex]\begin{gathered} H^{+_{}}+I^-\rightarrow HI_{(aq)} \\ \end{gathered}[/tex]

Hence, the chemical formula of Hydroiodic acid is HI

Follow these steps to write the balanced chemical equation for the reaction between nitric acid and iron (III)hydroxide.1. Start by writing the proper names of the products below (separated by a + sign).Nitric acid +Iron (III) hydroxide I2. Next, write the full, balanced molecular equation with the correct chemical formulas, includingcoefficients.3. Finally, write the net ionic equation for this reaction below, including ionic charges.

Answers

[tex]\begin{gathered} Fe(OH)_{3(s)}+3HNO_{3(aq)}\rightarrow Fe(NO_3)_{3(aq)}+3H_2O_{(l)} \\ Complete\text{ }Ionic\text{ }Equation:Fe(OH)_3+3H^++3NO_3^-\rightarrow Fe_^{3+}+3NO_3^-+3H_2O \\ Net\text{ }Ionic\text{ }Equation:Fe(OH)_{3(aq)}+3H_{(aq)}^+\rightarrow Fe_{(aq)}^{3+}+3H_2O_{(l)} \end{gathered}[/tex]

A single electron in an orbital has quantum numbers n = 2, ℓ = 0, mℓ = 0, ms = ½. what are the quantum numbers for the next electron added to this atom?

Answers

The quantum numbers for the next electron added to this atom are  n = 2, ℓ = 0, mℓ = 0, ms = -½

The set of numbers used to explain the placement and strength of the electron in an atom are called quantum numbers. There are 4 quantum numbers, particularly, main, azimuthal, magnetic, and spin quantum numbers. The values of the conserved portions of a quantum gadget are given by quantum numbers.

The price of n tiers from 1 to the shell of the outermost electron of that atom. The important quantum variety may be determined by way of searching the period (numbered row) of the element on the periodic table. The principal quantum numbers of electrons inside the S-block and P-block are similar to the period range.

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F-F covalent bond is slightly polarTrue or false and why?

Answers

Answer:

False. F-F would be a covalent apolar molecule.

Explanation:

As we have two elements bonded of the same element, in this case, F (fluorine), they would be sharing electrons, making that the bonding is covalent but there are no charges, because they're the same element, so it would be a completely covalent apolar molecule.

Two atoms with atomic numbers 12 and 17 would

bond to form an ionic compound
bond to form a covalent compound
bond to form a metallic lattice
not bond with each other

Answers

Answer:

bond to form a covalent bond

Explanation:

a covalent bond is formed when two atoms share electron pairs.

1. Explain why sulfur has a larger atomic radius than chlorine, even though chlorine has more protons, neutrons and electrons.

Answers

Sulphur has a larger atomic radius than chlorine, even though chlorine has more protons, neutrons and electrons because sulfur is to the left of chlorine in the periodic table.

What is atomic radius?

Atomic radius is defined as the distance between the atomic nucleus of an atom to the electron which is located at the outermost shell of the atom.

In the periodic table, the elements are being arranged in groups and periods with respect to their various atomic mass and numbers.

The atomic radius decreases across the period but increases down the group of the periodic table.

Therefore, sulphur would probably have a larger atomic radius when compared with chloride because it is located to the left of chloride in the periodic table.

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30.The type of chemical reaction represented by the following equation is....HBr + NaOH ---> H2O + NaBrSelect one:a. decomposition. b. double displacement.c. single displacement.d. synthesis.

Answers

Answer:

b. Double displacement.

Explanation:

It is a double displacement reaction, because in this case, hydrogen atom in HBr is replaced by a sodium atom (from NaOH), and the sodium atom (in NaOH) is replaced by another H atom from HBr molecule, to form H2O.

If 22.4 mL of 0.25 M sodium hydroxide are required
neutralize 15.0 mL of a hydroiodic acid solution, how
many grams of hydrogen iodide were dissolved in the
solution?

Answers

According to the concept of molar concentration,0.715 g of hydrogen iodide are dissolved in the solution.

What is molar concentration?

Molar concentration is defined as a measure by which concentration of chemical substances present in a solution are determined. It is defined in particular reference to solute concentration in a solution . Most commonly used unit for molar concentration is moles/liter.

The molar concentration depends on change in volume of the solution which is mainly due to thermal expansion. Molar concentration is calculated by the formula, molar concentration=mass/ molar mass ×1/volume of solution in liters.

In terms of moles, it's formula is given as molar concentration= number of moles /volume of solution in liters.

Using the formula of M₁V₁=M₂V₂ molarity of HI is determined,that is ,M₂=0.25×22.4/15=0.373 M.

For determining the mass is determined by using the formula,mass=0.373×127.911×0.015=0.715 g

Thus, 0.715 g of hydrogen iodide are required for making the solution.

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Consider the following reaction for the production of NO2.2 NO(g) + O2(g) → 2 NO2(g)What mass of O2 in g is required to produce 15 L NO2 at 344 K and 752 mm Hg? (R = 0.08206 L⋅atm/mol⋅K)

Answers

The question requires us to calculate the mass of reactant (O2) necessary to obtain 15 L of the product (NO2) under the conditions given.

The following information was provided by the question:

- Balanced chemical reaction: 2 NO(g) + O2(g) → 2 NO2(g)

- Final volume of NO2: 15 L

- Pressure: P = 752 mmHg

- Temperature: 344 K

- Gas constant: R = 0.08206 L⋅atm/mol⋅K

To solve this question, we'll need to go through the following steps:

1) calculate the number of moles that corresponds to 15 L of NO2, considering the temperature and pressure given;

2) use the stoichiometric relation to calculate the necessary amount of O2 to produce the previously calculated number of moles of NO2

3) use the molar mass of O2 and the value calculated on step 2 to obtain the necessary mass of O2

Next, we'll solve the problem following these steps:

1) To calculate the number of moles of NO2, we'll use the following equation:

[tex]P\times V=n\times R\times T[/tex]

where P is the pressure, V is the volume of gas, n is the number of moles, R is the constant of gases and T is the temperature.

If we rearrange the equation to calculate the number of moles, we'll have:

[tex]n=\frac{P\times V}{R\times T}[/tex]

Note that the problem provided all necessary information for this calculation, but the pressure given (752 mmHg) needs to be converted into atm to match the constant provided.

To do that, we'll use the following:

1 atm = 760 mmHg

Thus, we need to divide the value provided by 760:

[tex]P=752\text{ mmHg}\times\frac{1\text{ atm}}{760\text{ mmHg}}=0.989\text{ atm}[/tex]

Now, we can apply the values of pressure, volume and temperature, as well as the constant provided, to the equation written above:

[tex]n=\frac{(0.989\text{ atm)}\times(15\text{ L)}}{(0.08206\text{ L.atm/mol.K)}\times(344\text{ K)}}=0.525\text{ mol}[/tex]

So far, we have that the volume of NO2 to be produced (15 L) corresponds to 0.525 mol under the conditions of pressure and temperature provided.

2) Next, we use the chemical reaction to calculate the number of moles of O2 required to produce 0.525 mol of NO2.

From the reaction, we have that 1 mol of O2 leads to 2 mol of NO2. Then, we use this to calculate how many moles of O2 would produce 0.525 moles of NO2:

1 mol O2 --------------- 2 mol NO2

x -------------------------- 0.525 mol NO2

Solving for x, we have:

[tex]x=\frac{(1\text{ mol O2)}\times(0.525\text{ mol NO2)}}{(2\text{ mol NO2)}}=0.263\text{ mol O2}[/tex]

Now, we know that 0.263 moles of O2 are necessary to produce 15 L of NO2

3) The last step is calculate the mass of O2 that corresponds to 0.263 moles of this compound.

To do this, we need the molar mass of O2. Since the atomic mass of oxygen is 15.99 u, the molar mass of O2 is:

molar mass O2 = (2 * 15.99) = 31.98 g/mol

With this information, we can calculate the mass of 0.263 moles of O2:

1 mol O2 -------------------- 31.98 g O2

0.263 mol O2 ------------ y

Solving for y, we have:

[tex]y=\frac{(0.263\text{ mol O2)}\times(31.98\text{ g O2)}}{(1\text{ mol O2)}}=8.41\text{ g O2}[/tex]

Therefore, the mass of O2 necessary to produce 15 L of NO2 under the conditions given is 8.41 g.

What kind of energy transfer happens when you hang Christmas lights?

Answers

Answer: For example, Christmas lights transform electrical energy into thermal energy and light energy.

Explanation: so it either thermal or light, most likely light.

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