what is the solution to |2x-8|<6 ?

Kevin put in 40 regular hours last week in addition to 4 hours at the overtime rate. He received $756 in gross pay. The hourly rate of Kevin is $126.

Given that,

Kevin put in 40 regular hours last week in addition to 4 hours at the overtime rate.

He received $756 in gross pay.

We have to find the hourly rate of Kevin.

Let h be the hourly rate.

Then

1.5h be the overtime rate.

Reg pay+ Overtime pay=Total pay

40h+4(1.5h)=756

40h+6h=756

46h=756

h=756/40

h=$126

Therefore, the hourly rate of Kevin is $126.

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The total surface area of the cylinder is [tex]477.28cm ^2[/tex]

It is given that radius is 4 cm and height is 15 cm .

Putting r = 4 cm and h = 15 cm in equation (1) , we get

[tex]A=2\pi \times4(4+15)\\A=8\times3.14\times19\\A=477.28cm^2[/tex]

Hence , the area is 477.28

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The complete question is mention below :

What is the total surface area of cylinder with radius 4cm and height 15cm​

Answer:

23

Step-by-step explanation:

because that is the answer I think

Answer:

23degrees

Step-by-step explanation:

Because that is what I think and l haven't learned much but I think it's 23 degrees

Answer:

x=2.5

Step-by-step explanation:

Answer:

I think the question is incomplete!

Step-by-step explanation:

But the answer might be 5!

Answer:

Step-by-step explanation:

375355

Answer:

  f(1/x) = (7x+3)/(2x+6)

  g(x-2) = √(x² -13x +22)

Step-by-step explanation:

Given equations for f(x) and g(x), you want to find simplified equations for f(1/x) and g(x-2).

Substituting the argument for the variable, we have ...

  [tex]f\left(\dfrac{1}{x}\right)=\dfrac{3\cdot\dfrac{1}{x}+7}{6\cdot\dfrac{1}{x}+2}\\\\\boxed{f\left(\dfrac{1}{x}\right)=\dfrac{7x+3}{2x+6}}[/tex]

Substituting the argument for the variable, we have ...

  [tex]g(x-2)=\sqrt{(x-2)^2-9(x-2)}=\sqrt{x^2-4x+4-9x+18}\\\\\boxed{g(x-2)=\sqrt{x^2-13x+22}}[/tex]

Step-by-step explanation:

You didn't put any answer choices but two distinct lines intersecting each other at 90°, or a right angle, are called perpendicular lines. Here, AB is perpendicular to XY because AB and XY intersect each other at 90°.

The price of the T-shirt is $ 12

The price of the Sweatshirt is $ 22

Let the Price of a T-shirt is  $x, then the Price of a Sweatshirt is $(x+10)

In The Given Question, 50 T-shirts and 40 Sweatshirts are sold at $1480

Then,

50x + 40(x+100) = 1480

50x + 40x + 100 =1480

90x + 400 = 1480

90x = 1480 - 400

90x = 1080

x= [tex]\frac{1080}{90}[/tex]

x = 12

The price of the T-shirt is $ 12 and the Price of the Sweatshirt is $ 22

The price of the T-shirt is $ 12

The price of the Sweatshirt is $ 22

A price is the amount of money that is (often not negatively) exchanged from one party to another in exchange for their goods or services. The cost of production may go by another name in some circumstances. If a product is classified as a "good" in a commercial exchange, its price is most likely to be referred to as such. However, there will be alternative titles for this thing if it is a "service." For instance, the graph at the bottom will display various circumstances.

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Answer: There are 17 nickels and 8 dimes

what is the prevention of corruption finish give my answer to me

.

Answer:

0.81m²

Step-by-step explanation:

0.45 × 1.8 = 0.81m²

Answer:

The percent of change is a percent of increase. The percent of change is 200%.

Step-by-step explanation:

Hope this helps!

Answer:

it make do yourself ddhdjsjjsjsjsjsjsjsbsddjaoqbsgbeepoftkjs

The equation for the line through the point (-7,-4) and parallel to the line y = 8x - 4 in point-slope form is y = 8x + 52

The first equation is given as

y = 8x - 4

The slope of the above equation is

m = 8

Parallel lines have equal slope

So, the slope of the other line is

m = 8

The equation is then calculated as

y = m(x - x1) + y1

Where

m = 8

(x1, y1) = (-7, -4)

So, we have

y = 8(x + 7) - 4

Expand

y = 8x + 56 - 4

Evaluate the difference

y = 8x + 52

Hence, the equation for the line through the point (-7,-4) and parallel to the line y = 8x - 4 in point-slope form is y = 8x + 52

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Step-by-step explanation:

500+40+6+220+88000=

88766

Answer:

8.125 i think im not to sure

Step-by-step explanation:

Answer:

40

Step-by-step explanation:

Multiply each number of choices to get the total amount of choice combinations available.

5 syrup flavours * 2 types of coffee * 4 types of milk = 40 combinations.

5 * 2 * 4 = 40.

A numerical expression to represent the greatest total number of fish that could be in both aquariums is Number in Tiger barb + number in giant danios.

The Greatest number of fishes that could be in both aquariums is 14.

We are given that;

Tiger barbs = 30 gallon aquarium

Giant danios = 20 gallon aquarium

Tiger barb = volume / length

Tiger barb = 30 / 3

Tiger barb = 10 fishes

Giant danios = volume / length

Giant danios = 20 /5

Giant danios = 4 fishes

Numerical expression is:

Number in Tiger barb + number in giant danios

= 10 + 4 = 14

Therefore, the correct numerical expression that represents the greatest total number of fish that could be in both aquariums is Number in Tiger barb + number in giant danios.

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Your question was incomplete. Please refer the content below:

There are tiger barbs in a 30-gallon aquarium and giant danios in a 20-gallon aquarium

Use the rule to solve this problem. The rule for the number of fish in an aquarium is to allow 1 gallon of water for each inch of length.

Giant Danio=5 inch length

Tiger barb=3 inch length

What is the correct numerical expression that represents the greatest total number of fish that could be in both aquariums?

When the Saffron bales 324 pastries in the morning and some in the afternoon, if she sells 584 pastries and at the end of the day she has 52 pastries left, the total number of pastries in the afternoon is 312

The  total number of pastries she sells=584 pastries

The number of pastries left at the end of the day=52 pastries

The total number of pastries she bakes=584+52

=636 pastries

Number of pastries she bakes in the morning=324 pastries

Subtract the number of pastries bakes in the morning from the total number of pastries she bakes

Number of pastries she bakes in the morning=636-324

=312 pastries

Hence, when the Saffron bales 324 pastries in the morning and some in the afternoon, if she sells 584 pastries and at the end of the day she has 52 pastries left, the total number of pastries in the afternoon is 312

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[tex]3\% = \frac{3}{100} = 0.03[/tex]

Answer:

A

Step-by-step explanation:

because 3 percent is 3/100 so move the decimal point 2 over to make it 0.03.

Answer:

See explanation

Step-by-step explanation:

f(x) ==> 4f(x-1)

1. f(x) ==> f(x-1)      Translate the graph 1 unit to the right

2. f(x-1) ==> 4f(x-1) Vertical stretch by a factor of 4

f(x) ==> -f(2x)

1. f(x) ==> f(2x)     Horizontal compression by a factor of 1/2

2. f(2x) ==> -f(2x)    Reflection over the x-axis

f(x) ==> f(-x)+2

1. f(x) ==> f(-x)     Reflection over the y-axis

2. f(-x) ==> f(-x)+2    Translate the graph 2 units up.

Answer:

1)  Translated 1 unit right and stretched vertically by a factor of 4.

2)  Compressed horizontally by a factor of ¹/₂ and reflected in the x-axis.

3)  Reflected in the y-axis and translated 2 units up.

Step-by-step explanation:

Transformations

For a > 0

[tex]f(x+a) \implies f(x) \: \textsf{translated $a$ units left}[/tex]

[tex]f(x-a) \implies f(x) \: \textsf{translated}\:a\:\textsf{units right}[/tex]

[tex]f(x)+a \implies f(x) \: \textsf{translated}\:a\:\textsf{units up}[/tex]

[tex]f(x)-a \implies f(x) \: \textsf{translated}\:a\:\textsf{units down}[/tex]

[tex]\begin{aligned} y =a\:f(x) \implies & f(x) \: \textsf{stretched/compressed vertically by a factor of $a$} \\& \textsf{If }a > 1 \textsf{ it is stretched by a factor of $a$}\\& \textsf{If }0 < a < 1 \textsf{ it is compressed by a factor of $a$}\end{aligned}[/tex]

[tex]\begin{aligned} y=f(ax) \implies & f(x) \: \textsf{stretched/compressed horizontally by a factor of $\dfrac{1}{a}$} \\ & \textsf{If }a > 1 \textsf{ it is compressed by a factor of $\dfrac{1}{a}$}\\ & \textsf{If }0 < a < 1 \textsf{ it is stretched by a factor of $\dfrac{1}{a}$}\end{aligned}[/tex]

[tex]y=-f(x) \implies f(x) \: \textsf{reflected in the $x$-axis}[/tex]

[tex]y=f(-x) \implies f(x) \: \textsf{reflected in the $y$-axis}[/tex]

Given:  

Transformations

[tex]f(x-1) \implies f(x) \: \textsf{translated}\:1\:\textsf{unit right}[/tex]

[tex]4\:f(x) \implies f(x) \: \textsf{stretched vertically by a factor of}\: 4[/tex]

Given:

[tex]-f(2x)[/tex]

Transformations

[tex]f(2x) \implies f(x) \: \textsf{ compressed horizontally by a factor of $\dfrac{1}{2}$}[/tex]

[tex]-f(x) \implies f(x) \: \textsf{reflected in the} \: x \textsf{-axis}[/tex]

Given:

[tex]f(-x)+2[/tex]

Transformations

[tex]f(-x) \implies f(x) \: \textsf{reflected in the} \: y \textsf{-axis}[/tex]

[tex]f(x)+2 \implies f(x) \: \textsf{translated}\:2\:\textsf{units up}[/tex]

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The line segment's slope represents the period during which the speed decreases is b. The slope is -10.

The slope of a line segment measures the steepness of the line segment.

The slope is the ratio of the rise (the change in vertical height, y, between the endpoints) over the run (the difference in horizontal length, x, between the endpoints.

Elapsed Time (sec)     Speed (mph)

1                                        45

2                                       35

3                                       25

4                                       15

5                                       15

6                                       15

The Slope of the line segment during speed decreases = y₂ - y₁ ÷ x₂ - x₁.

= (35 - 45) / (2 - 1)

= -10/1

= -10

Thus, b. The slope is -10.

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We get that the solution for this inequalities will be x ≤ - 4.5.

We are given the inequalities:

- 2 x - 3 ≥ 6 or 3 ( x - 4 ) < - 6

For - 2 x - 3 ≥ 6:

Add 3 to both sides:

- 2 x - 3 + 3 ≥ 6 + 3

- 2 x ≥ 9

Divide both sides by - 2

- 2 x / - 2 ≤ 9 / - 2

x ≤ - 4.5

For 3 ( x - 4 ) < - 6:

Divide both sides by 3

x - 4 < - 6

Add 4 to both sides:

x - 4 + 4 < - 6 + 4

x < - 2

We get

x ≤ - 4.5 or x < -2

x will then be:

x ≤ - 4.5

Therefore, we get that the solution for this inequalities will be x ≤ - 4.5.

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The ratio of the amount of time spent doing homework to the amount of time spent watching TV is 1/12.

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Sort the ensuing actions according to how they affect the general ledger accounts. Drag and drop software.

Allocate overhead costs to jobs

Debit Raw Materials Inventory

Pay factory utilities

Credit Factory Overhead

Purchase indirect material

Debit Factory Overhead

Use indirect materials

Debit Work in Process Inventory

Direct labor used

Credit Raw Materials Inventory

The following actions' effects on the general ledger accounts are matched to them:

1. When you divide up overhead expenses among jobs: Give factory overhead credit.

2. When paying production overhead: debit the factory utilities.

3. When you buy indirectly produced material: Debit the inventory of raw supplies.

4. Using indirect materials results in: Credit the inventory of raw commodities.

5. Direct labor used: Debit Work in Process Inventory.

Explanation:

1. When you divide up overhead expenses among jobs: Give factory overhead credit. Factory overhead is a cost that cannot be directly attributed to the goods but is incurred throughout the manufacturing process of completed goods.

2. When paying production overhead: debit the factory utilities. Factory overhead is defined as a cost incurred during the production of completed goods that is not directly related to the products.

3. When you buy indirectly produced material: Debit the inventory of raw supplies. The cost of all resources, such as component components, that a company has on hand but have not been used in the manufacture of finished items or work in progress is included in the raw materials inventory.

4. Using indirect materials results in: Credit the inventory of raw commodities. The total cost of all resources, like as component components, that a company has on hand but haven't been used to produce finished goods or work in progress is known as raw materials inventory.

5. Debit work in process inventory for direct labor utilized.

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Diana's second time was faster by 0.84 yards.

Th speed of the first race will be:

= Distance / Time

= 300 / 65

= 4.62 yards per second

The speed of the second race will be:

= 300 / 55

= 5.46 yard per second.

The difference will be:

= 5.46 - 4.62

= 0.84 yards

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