Answer:
[tex]slope = \frac{y _{2} - y _{1} }{x _{2} - x _{1} } \\ = \frac{( - 9 - ( - 5))}{(6 - ( - 5))} \\ = \frac{ - 4}{11} \\ slope = - \frac{4}{11} [/tex]
Which pair of expressions is equivalent? 2(x + 5) and 2x + 10 B. 3x – 6 + 4x + 9 and 7x + 15 0. C. 4y - 2) and 4y - 2 0 D. 5y + 12 - 3y and 2y – 12
Answer:
A
Step-by-step explanation:
the equivalent pair of expression are 2(x+5)and 2x+10
Which set of side lengths form a right triangle?
2 inches, 3 inches, 4 inches
6 inches, 8 inches, 10 inches
8 inches, 9 inches, 11 inches
10 inches, 12 inches, 13 inches
Answer:
It’s 10 inches, 12 inches, 13 inches
Step-by-step explanation:
Factor the expression using the GCF. 44-11 I NEED HELP PLEASE!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Answer:
11(4-1)
Step-by-step explanation:
11 is the greatist common factor of 44 and 11 so you factor an 11 out of both terms
44/11=4
11/11=4
Therefore the answer is 11(4-1)
jason voorhes was buying hocky masks. 1 hockey mask cost 10 dollars how much does 10 masks it cost in all?
Answer:
$100
Step-by-step explanation:
since 1 hockey mask costs $10 and you need 10 masks you can multiply 10x10 and you will get 100
In the rectangle, find the length of AD.
Answer:
required answer is 9 of your question
For which line is the slope least?
The diagram shows two squares constructed on the sides of a rectangle. Write an expression for the area of Square C in terms of the areas of Square A and Rectangle B. Then simplify to find the area. (N RN.1.1-2 HELP PLSSS
Step-by-step explanation:
Since area of Square A = 7 ft²,
Side length of Square A = √7 ft.
Length of Rectangle B = √7 ft
Width of Rectangle B = 4/√7 ft
Hence Area of Square C
= (4)² / (√7)² ft² = 16/7 ft².
The area of Square C is the square of the height of the Rectangle B.
Correct responses:
[tex]\underline{Area \ of \ square \ C = \dfrac{\left(Area \ of \ Rectangle \ B \right)^2}{Area \ of \ Square \, A} }[/tex][tex]Area \ of \ square \ C = \underline{\dfrac{16}{7}} \, ft.^2[/tex]Methods used for finding the area of Square CThe given area of square A = 7 ft.²
The given area of rectangle, B = 4 ft.²
Let s represent the side length of square C and let S represent the side length of square A, we have;
Area of rectangle B = S × s = S·s
Area of square A = S × S = S²
Area of square C = s × s = s²
[tex]\mathbf{\dfrac{(Area \ of \ rectangle \ B)^2}{Area \ of \ square \ A } } = \dfrac{\left(S \cdot s \right)^2}{S^2} = \dfrac{S^2 \cdot s^2}{S^2} = s^2 = Area \ of \ square \ C[/tex]
Therefore, the expression for the area of Square C in terms of the area
of Square A and Rectangle B is presented as follows;
[tex]\underline{Area \ of \ Square \ C = \dfrac{ \left (Area \ of \ rectangle \ B \right)^2}{\left(Area \ of \ square \ A\right)}}[/tex]Which gives;
[tex]\underline{Area \ of \ square \ C = \dfrac{\left(4 \, ft.^2 \right)^2}{7 \, ft.^2}}[/tex]By simplification, we have;
[tex]\mathbf{\dfrac{\left(4 \, ft.^2 \right)^2}{7 \, ft.^2}} = \dfrac{16}{4} \, ft.^2[/tex]
[tex]Area \ of \ square \ C = \underline{ \dfrac{16}{7}} \, ft.^2[/tex]Learn more about squares and rectangles here:
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i need help pls help me
Answer:
yes
Step-by-step explanation:
Answer:
18
Step-by-step explanation:
you have to multiply 2/3 by 27 km
Which equation represents the line that is parallel to y = 2 and passes through (-1,-6)?
Answer:
y=-6
Step-by-step explanation:
the line needs to be vertical to be parallel to y=2, and pass through (-1,-6)
Evaluate functions from their graph f(-5)=
Answer:
7
Step-by-step explanation:
(-5,7) lies in the graph!
Which data sets have outliers? Check all that apply
14,21,24,25,27,32,35
15,30,35,41,44,50,78
16,32,38,39,41,42,58
17,23,28,31,39,45,75
18,30,34,38,43,45,68
Answer:
C.16, 32, 38, 39, 41, 42, 58
and
E.18, 30, 34, 38, 43, 45, 68
its C. & E.
they both have outliers lol
Eidoskaijsizjzkxkxdkjajjsjeksjsii
Answer:
Yes, Yes, No, Yes
Step-by-step explanation:
what does 72 x ? = 300
Answer: 25/6
Step-by-step explanation:
Answer:
? = 4.1667
Step-by-step explanation:
300/72 = 4.1667
Hope this Helps! :)
Have any questions? Ask below in the comments and I will try my best to answer.
-SGO
You are running a concession stand at a basketball game. You are selling hot dogs and
sodas.Each hot dog costs $1.50 and each soda costs $ 0.50. At the end of the night, you made a total of
$78.50. You sold a total of 87 hot dogs and sodas combined. You musſt report the number of hot dogs
sold and the number of sodas sold. How many hot dogs were sold and how many sodas were sold?
Answer: 52
Step-by-step explanation: Friend me and yes that is right!
A $96.00 item is marked down by 25%
what is the new cost of the item?
round if needed
Answer:
$72.00
Step-by-step explanation:
Answer:
$72
Step-by-step explanation:
25% of $96 = [tex]\frac{25}{100}[/tex] × [tex]\frac{96}{1}[/tex] [tex]\frac{25}{100}[/tex] × [tex]\frac{96}{1}[/tex] = [tex]\frac{2400}{100}[/tex] [tex]\frac{2400}{100} = 24[/tex] $96 - $24 = $72I hope this helps!
Solve the inequality -2/9b>-12
Answer:
1/2
Step-by-step explanation:
Let f(x) = 16 – x^2 , g(x) = 4 – x. Find (fg)(x) and its domain
Which graph represents the solution to the system of inequalities?
{y<−4x+1
{y≥−14x
Answer:
1st graph on line 2
Step-by-step explanation:
5(-6 + 4)=..................
Answer:
-10
Step-by-step explanation:
5(-6 + 4)
=-30+20
=-10
Answer:
-10 or just 10 in general
Step-by-step explanation:
Twins Isaac and Isaiah were just born. Isaac weighs 6 pounds 2 ounces and Isaiah weighs 5 pounds 4 ounces. How many ounces do Isaac and Isaiah weigh together?
-4x + 12 = -6x
Step 1: Add 4x to both sides:
12 = -6x + 4x
Step 2: Combine like terms:
12 = -2x
uh- this is the correct way to answer the problem....
−4x+12=−6x
Step 1: Add 6x to both sides.
−4x+12+6x=−6x+6x
2x+12=0
Step 2: Subtract 12 from both sides.
2x+12−12=0−12
2x=−12
Step 3: Divide both sides by 2.
[tex]\frac{2x}{2}[/tex] = [tex]\frac{-12}{2}[/tex]
x=−6
does anyone know this please help
Answer:
It is the 3rd graph
Step-by-step explanation:
It is the only one that shows a porpotional relationship.
Answer:
sry mate.....
............
An integer can be positive, negative, or _____. opposite zero equivalent
Answer:
Zero is nor a positive or negative number, so im guessing the answer is 0.
Step-by-step explanation:
is the product of 18 negative numbers and 20 positive numbers a positive number or negative
Answer:
positive
Step-by-step explanation:
even negatives = positive
whatever positives = positive
positive*positive = positive
Solve 2x + 2y = -28 2x - 2y = 26
Answer:
x=−y−14
Step-by-step explanation:
Answer:
x = none y = -27
Step-by-step explanation:
2x + 2y = -28 + 2x - 26
-2x -2x
__________________
2y = -28 - 26
2y = -54
y = -27
Find all solutions in the interval [0, 2pi).
tanx+ secx =1
a) x=pi/4
b) x=0
c) x=5pi/4
d) no solution
Answer:
1 should be the answer bi
Step-by-step explanation:
Use the rules of significant figures to answer the following question:
54.313 × 12.09
A. 657
B. 660
C. 656.64
D. 656.6
Need help if u do I will put brainliest
Find the unit tangent vector at the given value of t for the following parameterized curves.
r(t)= ⟨7–√e^t,3e^t,3e^t⟩
, for 0≤t≤1
; t=ln 2
Answer:
[tex]T(ln2)[/tex][tex]= <\sqrt{145} , \frac{6\sqrt{2} }{\sqrt{145} } , \frac{6\sqrt{2} }{\sqrt{145} } >[/tex]
Step-by-step explanation:
Given : [tex]r(t)=<7-\sqrt{e^t}, 3e^t,3e^t > .........(i)[/tex]
We first have to differentiate of equation [tex](i)[/tex]
[tex]r'(t) = < \frac{\sqrt{e^t} }{2} , 3e^t,3e^t> ..........(ii)[/tex]
Now to get a unit tangent vector at the given value of [tex]t[/tex], we put [tex]t = ln2[/tex] in equation [tex](ii)[/tex]
[tex]r'(ln2) = < \frac{\sqrt{e^{ln2}} }{2} , 3e^{ln2},3e^{ln2}>[/tex]
[tex]= <\frac{1}{\sqrt{2} } ,6,6>[/tex] [∵[tex]e^{lna}=a[/tex]]
Now to get a unit tangent vector , we will divide our vector [tex]r'(ln2)[/tex] by its magnitude. So let's first find the magnitude.
[tex]|r'(ln2)|=\sqrt{(\frac{1}{\sqrt{2} } )^2 +6^2+6^2}[/tex]
[tex]= \sqrt{\frac{1}{2}+36+36 }[/tex]
[tex]= \sqrt{\frac{145}{2} }[/tex]
Now we can find the our unit tangents vector.
[tex]T(ln2)=\frac{r'(ln2)}{|r'(ln2)|}[/tex]
[tex]= \frac{<\frac{1}{\sqrt{2}} ,6,6> }{\sqrt{\frac{145}{2}} }[/tex]
[tex]= <\frac{\frac{1}{\sqrt{2} } }{\sqrt{\frac{145}{2}} } ,\frac{6}{{\sqrt{\frac{145}{2}} }}, \frac{6}{{\sqrt{\frac{145}{2}} }} >[/tex]
[tex]= <\sqrt{145} , \frac{6\sqrt{2} }{\sqrt{145} } , \frac{6\sqrt{2} }{\sqrt{145} } >[/tex]
Hence, [tex]T(ln2)[/tex] [tex]= <\sqrt{145} , \frac{6\sqrt{2} }{\sqrt{145} } , \frac{6\sqrt{2} }{\sqrt{145} } >[/tex]
what is the answer pls i need help
Answer:
A because you have to mutiply 3 x 2 and it gives you 6