Answers
Always remember that the slope is the number of units on the Y-axis in relation to the X movement.
A horizontal line always has a slope of 0. (it is not increasing in the Y-axis)
Related Questions
ok so the question is Write an expression to rubbers in the area of the figure the figure is a right triangle with 2X -2 and 4X plus 2 in the answer to that is 4X to the power of 2 - 2X -2 and that's part a and amp RP is what would the area be if X equals negative 2
Answers
ANSWERS
a) A = 4x² - 2x - 2
b) if x = -2, A = 18 units²
EXPLANATION
The area of a triangle is the length of the base, multiplied by its height and divided by 2:
[tex]A=\frac{b\cdot h}{2}[/tex]In this triangle, b = 4x + 2 and h = 2x - 2. The area is:
[tex]A=\frac{(4x+2)(2x-2)}{2}[/tex]We can simplify this expression. First we have to multiply the binomials in the numerator:
[tex]\begin{gathered} A=\frac{4x\cdot2x-4x\cdot2+2\cdot2x-2\cdot2}{2} \\ A=\frac{8x^2-8x+4x-4}{2} \\ A=\frac{8x^2-4x-4}{2} \end{gathered}[/tex]Now, using the distributive property for the division:
[tex]\begin{gathered} A=\frac{8x^2}{2}-\frac{4x}{2}-\frac{4}{2} \\ A=4x^2-2x-2 \end{gathered}[/tex]For part b, we just have to replace x with -2 in the expression above and solve:
[tex]\begin{gathered} A=4(-2)^2-2(-2)-2 \\ A=4\cdot4+4-2 \\ A=16+2 \\ A=18 \end{gathered}[/tex]Translate the sentence into an equation.Eight more than the quotient of a number and 3 is equal to 4.Use the variable w for the unknown number.
Answers
We are to translate into an equation
Eight more than the quotient of a number and 3 is equal to 4.
Let the number be w
Hence, quotient of w and 3 is
[tex]\frac{w}{3}[/tex]Therefore, eight more than the quotient of a number and 3 is equal to 4
Is given as
[tex]\frac{w}{3}+8=4[/tex]Solving for w
we have
[tex]\begin{gathered} \frac{w}{3}=4-8 \\ \frac{w}{3}=-4 \\ w=-12 \end{gathered}[/tex]Therefpore, the equation is
[tex]\frac{w}{3}+8=4[/tex]What is the area of this triangule? h = 12 in, b = 3 in
Answers
Answer:
Area = 18
Explanation:
The area of a triangle is given by
Area = 1/2 height * base length
Now in our case
height = 12 in, base length = 3 in; therefore, the area is
Area = 1/2 * 12 * 3
Area = 6 * 3
Area = 18
Which is our answer!
Consider the following sets
U = {1,2,3,4,5,6,7,8,9,10,11,12,13}
A= {1,2,3,4,7}
B = {3,4,5,6}
Find the set (A U B)’
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The elements in the set (A u B)' are is {8,9,10,11,12,13}
How to determine the value of the set?The definitions of the sets and the elements are given as
Universal Set, U = {1,2,3,4,5,6,7,8,9,10,11,12,13}Set A= {1,2,3,4,7}Set B = {3,4,5,6}The set to calculate is represented by the notation
(A u B)'
Start by calculating the set A u B
This means that we combine the sets A an B without repetition
So, we have
A u B = {1, 2, 3, 4, 5, 6, 7}
Next, we calculate (A u B)'
This represents the sets in U that are not in A u B
So we have
(A u B)' = {8,9,10,11,12,13}
Hence, the value of the set is {8,9,10,11,12,13}
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Hello! Need some help on part c. The rubric, question, and formulas are linked. Thanks!
Answers
Explanation:
The rate of increase yearly is
[tex]\begin{gathered} r=69\% \\ r=\frac{69}{100}=0.69 \end{gathered}[/tex]The number of lionfish in the first year is given beow as
[tex]N_0=9000[/tex]Part A:
To figure out the explicit formula of the number of fish after n years will be represented using the formula below
[tex]P(n)=N_0(1+r)^n[/tex]By substituting the formula, we will have
[tex]\begin{gathered} P(n)=N_{0}(1+r)^{n} \\ P(n)=9000(1+0.69)^n \\ P(n)=9000(1.69)^n \end{gathered}[/tex]Hence,
The final answer is
[tex]f(n)=9,000(1.69)^n[/tex]Part B:
to figure out the amoutn of lionfish after 6 years, we wwill substitute the value of n=6
[tex]\begin{gathered} P(n)=9,000(1.69)^{n} \\ f(6)=9000(1.69)^6 \\ f(6)=209,683 \end{gathered}[/tex]Hence,
The final answer is
[tex]\Rightarrow209,683[/tex]Part C:
To figure out the recursive equation of f(n), we will use the formula below
From the question the common difference is
[tex]d=-1400[/tex]Hence,
The recursive formula will be
[tex]f(n)=f_{n-1}-1400,f_0=9000[/tex]If y varies directly with x and y = 48 when x = -4, write the equation that represents this direct variation relationship12 345
Answers
Answer
The equation that represents the direct variation relationship between y and x is
y = -12x
Explanation
We are told that y varies directly with x.
y = 48 when x = -4.
We are then told to write the equation that represents this direct variation relationship.
In mathematical terms, y varies directly with x is written as
y ∝ x
If we introduce a constant of variation, k, we can then write this relationship as
y = kx
To now fully write this relationship, we need to solve for k.
y = 48 when x = -4.
y = kx
48 = k × -4
48 = -4k
-4k = 48
Divide both sides by -4
(-4k/-4) = (48/-4)
k = -12
We can then put in the value of k obtained
y = kx
y = -12x
The equation given is
3y = 10x
Recall that variation is represented as
y ∝ x
And written as
y = kx
So, we can convert 3y = 10x into this form and establish the direct variation and obtain the value of k.
3y = 10x
Divide both sides by 3
(3y/3) = (10x/3)
y = (10x/3)
which is similar to y = kx
k = (10/3)
So, option A is correct.
Hope this Helps!!!
E is the midpoint of DF, DE = 2x + 4 and EF = 3x - 1 how do I find the value of x, DE, EF and DF
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We know that
E is midpoint of DF, that means DE is equal to EF, so we can form the following equation
[tex]DE=EF[/tex]Replacing the given equations, we have
[tex]\begin{gathered} 2x+4=3x-1 \\ 4+1=3x-2x \\ x=5 \end{gathered}[/tex]Now, we replace this value in each equation to find each part of the segment.
[tex]\begin{gathered} DE=2x+4=2(5)+4=10+4=14 \\ EF=3x-1=3(5)-1=15-1=14 \end{gathered}[/tex]Therefore, each part of the segment is 14 units, and DF is 28.Translate the sentence into an inequality.Twice the difference of a number and 2 is at least −28.Use the variable x for the unknown number.
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To answer this question we have to identify the elements of the inequality.
1. The difference of a number and 2 is represented by the expression: x-2.
2. Twice the difference (...) is represented by the expression: 2(x-2).
3. At least is represented by the sign greater than or equal to ≥.
4. The result is -28.
By putting these all together we obtain the inequality:
[tex]2(x-2)\ge-28[/tex]It means that the answer is 2(x-2) ≥ -28.
Find the difference.5 - 12 = don’t be specific be quick i leave. a good review
Answers
Given:
5 - 12
To find the difference , all we have to do is to perform the subtraction. The result of subtraction is called the difference.
Subtract 12 from 5.
Thus, we have:
5 - 12 = -7
Therefore, the difference between 5 and 12 is -7
in the figure below, RTS is an isosceles triangle with sides SR=RT, TVU is an equilateral triangle, WT is the bisected of angle STV, points S, T, and U are collinear, and c= 40 degrees.I'm completely lost and have to answer for a, b+c, f, b+f, a+d, e+g
Answers
Step 1: Concept
Triangle SRT is an isosceles triangle with equal base angles a = b
Triangle TUV is an equilateral triangle with all angles equal: g = d = h
Step 2: Apply sum of angles in a triangle theorem to find angle a and b.
[tex]\begin{gathered} a+b+c=180^o \\ c=40^o \\ \text{Let a = b = x} \\ \text{Therefore} \\ x\text{ + x + 40 = 180} \\ 2x\text{ = 180 - 40} \\ 2x\text{ = 140} \\ x\text{ = }\frac{140}{2} \\ x\text{ = 70} \\ a\text{ = 70 and b = 70} \end{gathered}[/tex]Step 3:
2) a = 70
3) b + c = 70 + 40 = 110
Step 4:
Since WT is a bisector of angle STV,
Angle f = e = x
b + f + e = 180 sum of angles on a straight line.
b = 70
70 + x + x = 180
2x = 180 - 70
2x = 110
x = 110/2
x = 55
Hence, f = 55
4) f = 55
5) f + b = 55 + 70 = 125
Step 5:
Since triangle TUV is an equilateral triangle, angle g = h = d = 60
g = 60
h = 60
d = 60
6) Angle a + d = 70 + 60 = 130
7) e + g = 55 + 60 = 115
How many ways can we arrange five of the seven Harry Potter books on a shelf if Harry Potter and The Chamber of Secrets must be one of them?
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There are 7 Harry potter books and 5 books needs to be arranged.
One of the five place is filled by book "Harry Potter and The Chamber of Secrets" and remaining 4 places must be filled by remaining 6 books.
So number of ways are,
[tex]\begin{gathered} 1\cdot^6P_4=1\cdot\frac{6!}{(6-4)!} \\ =1\cdot\frac{6\cdot5\cdot4\cdot3\cdot2\cdot1}{2\cdot1} \\ =1\cdot6\cdot5\cdot4\cdot3 \\ =360 \end{gathered}[/tex]So there are 360 ways in which 5 of 7 Harry pooter book can be arranges such that " Harry Potter and The Chamber of Secrets" must included.
Determine the value for which the function f(u)= -9u+8/ -12u+11 in undefined
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ANSWER
[tex]\frac{11}{12}[/tex]EXPLANATION
A fraction becomes undefined when its denominator is equal to 0.
Hence, the given function will be undefined when:
[tex]-12u+11=0[/tex]Solve for u:
[tex]\begin{gathered} -12u=-11 \\ u=\frac{-11}{-12} \\ u=\frac{11}{12} \end{gathered}[/tex]That is the value of u for which the function is undefined.
the sum of the measure of angle m and angle r is 90
Answers
Given:
The sum of measure of angle m and r is 90 degrees.
At noon a private plane left Austin for Los Angeles, 2100 km away, flying at 500 km/h. One hour later a jet left Los Angeles for Austin at 700 km/h. At what time did they pass each other?
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4x-6a(8x)/98y Solve for x
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1) Solving for x, the following equation:
We're going to isolate the x variable on the left:
[tex]4x-6a\frac{8x}{98y}[/tex]Question
In a pet store, the small fishbowl holds up to 225 gallons of water. The large fishbowl holds up to 213 times as much water as the small fishbowl.
Eloise draws this model to represent the number of gallons of water the large fishbowl will hold.
How many gallons of water does the large fishbowl hold?
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The number of gallons that the large fishbowl holds would be = 47,925 gallons.
What are fishbowls?The fishbowls are containers that can be used to transport liquid substance such as water and food products such as fish. This can be measured in Liters, millilitres or in gallons.
The quantity of water the small fishbowl can take = 225 gallons.
The quantity of water the large fish bowl can take = 213(225 gallons)
That is, 213 × 225= 47,925 gallons.
Therefore, the quantity of water that the large fishbowl can hold is 47,925 gallons.
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Using the information provided in the given table, determine how much monthly income would be necessary to budget in order to cover the expenses of attending a local college for the 9-month academic year. Round your answer to the nearest cent, if necessary.
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We have to add all the annual expenses:
[tex]9122+10612+1109+732+1092+1197+132[/tex][tex]=23,996[/tex]However, this quantity we obtained are the annual expenses, then, we have to divide them by the months of the academic year:
[tex]\frac{23996}{9}[/tex][tex]=2666.22[/tex]Answer: $2,666.22
4 students from a class of 15 are going to be chosen to be on the dance committee. Findthe number of different 4-person committees that can be made.
Answers
Answer:
[tex]C(15,4)=1365\text{ different committees}[/tex]Step-by-step explanation:
This situation can be approached using the formula for combinations:
[tex]\begin{gathered} C(n,r)=\frac{n!}{r!(n-r)!} \\ \text{where,} \\ n=\text{ number of possible items that can be }selected \\ r=\text{ number of items that were selected} \end{gathered}[/tex]Therefore, solve for n=15 and r=4.
[tex]\begin{gathered} C(15,4)=\frac{15!}{4!(15-4)!} \\ C(15,4)=1365\text{ different committees} \end{gathered}[/tex]Identify the rate of change and Intial Value in this equationy = 3x +6
Answers
The rate of change is 3.
The initial value is 6.
Step - by - Step Explanation
What to find?
• Rate of change.
,• Initial value.
Given:
y = 3x + 6
The rate of change is also the same as the slope.
To find the slope of the gien equation, compare the equation with y=mx + b.
Where m is the slope (rate of change).
Comparing the two equations, m = 3
Hence, the rate of change is 3.
The initial value also known as the y-intercept, is the value of y at x=0.
y = 3(0) + 6
y = 6
Hence, the initial value is 6.
You have an investment account that has a balance of $50,000. If the account iscompounded daily and has an interest rate of 4%, how much did you originally depositinto the account 10 years ago?
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Since we know the future alue of the account, using the formula for the compounded interest with n = 365 (since the account is compounded daily), t=10, r = 4% and A=50000 in the following equation:
[tex]A=P(1+\frac{r}{n})^{n\cdot t}[/tex]using these values and solving for P, we get:
[tex]\begin{gathered} 50000=P(1+\frac{0.04}{365})^{365\cdot10} \\ \Rightarrow P=\frac{50000}{(1+\frac{0.04}{365})^{3650}}=33516.74 \\ P=33,516.74 \end{gathered}[/tex]therefore, the original amount deposited 10 years ago is $33,516.74
A red die is tossed and then a green dieis tossed. What is the probability thatthe red die shows a six or the green dieshows a six?Hint: The two events are not mutually exclusive. So to the find theprobability of the union, use:P(A or B) = P(A) + P(B) - P(A and B)[?]
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Let's call the event of the red die to show a six as event A, and the event of the green die to show a six as event B.
The theoretical probability is defined as the ratio of the number of favourable outcomes to the number of possible outcomes. On both dices, we have 6 possible outcomes(the numbers from 1 to 6), with one favourable outcome(the number 6), therefore, the probabilities of those events are:
[tex]P(A)=P(B)=\frac{1}{6}[/tex]Each roll is independent from each other, then, the probability of both events happening simultaneously is given by their product:
[tex]P(A\:and\:B)=P(A)P(B)[/tex]Using the additive rule of probability, we have the following equation for our problem:
[tex]\begin{gathered} P(A\:or\:B)=P(A)+P(B)-P(A\:and\:B) \\ =P(A)+P(B)-P(A)P(B) \\ =\frac{1}{6}+\frac{1}{6}-\frac{1}{6^2} \\ =\frac{2}{6}-\frac{1}{36} \\ =\frac{12}{36}-\frac{1}{36} \\ =\frac{12-1}{36} \\ =\frac{11}{36} \end{gathered}[/tex]the probability that the red die shows a six or the green die shows a six is 11/36.
determine the -domain- and -range- of the graphanswer in interval notation
Answers
Explanation: Let's consider two things
- Domain = represented by the minimum and maximum x-values
- Range = represented by the minimum and maximum y-values
Step 1: Let's take a look at the picture below
As we can see above
max x-value = + ∞
min x-value = - ∞
max y-value = 4
min y-value = - ∞
Final answer: So the final answer is
[tex]\begin{gathered} \text{domain}\Rightarrow(-\infty,+\infty) \\ \text{range}\Rightarrow(-\infty,4) \end{gathered}[/tex].
2. The length of one side of the square is the square root ofits area. Use the table tofind the approximate length of one side of the square. Explain how you used thetable to find this information
Answers
we know that
the area of a square is equal to
A=b^2
where
b is the length side
Apply square root both sides of the formula we have
[tex]\sqrt{A}=b[/tex]I need this practice problem answered I will provide the answer options in another pic
Answers
The inverse of a matrix can be calculated as:
[tex]\begin{gathered} \text{When} \\ A=\begin{bmatrix}{a} & {b} & {} \\ {c} & {d} & {} \\ {} & {} & \end{bmatrix} \\ \text{Then A\textasciicircum-1 is:} \\ A^{-1}=\frac{1}{ad-bc}\begin{bmatrix}{d} & -{b} & {} \\ {-c} & {a} & {} \\ {} & {} & \end{bmatrix} \end{gathered}[/tex]Then, let's start by calculating the inverse of the given matrix:
[tex]\begin{gathered} \begin{bmatrix}{4} & {1} & {} \\ {-2} & {3} & {} \\ {} & {} & \end{bmatrix}^{-1}=\frac{1}{4\cdot3-1\cdot(-2)}\begin{bmatrix}{3} & -{1} & {} \\ {-(-2)} & {4} & {} \\ {} & {} & \end{bmatrix} \\ \begin{bmatrix}{4} & {1} & {} \\ {-2} & {3} & {} \\ {} & {} & \end{bmatrix}^{-1}=\frac{1}{14}\begin{bmatrix}{3} & -{1} & {} \\ {2} & {4} & {} \\ {} & {} & \end{bmatrix} \end{gathered}[/tex]The problem says he multiplies the left side of the coefficient matrix by the inverse matrix, thus:
[tex]\begin{gathered} \begin{bmatrix}{4} & {1} & {} \\ {-2} & {3} & {} \\ {} & {} & \end{bmatrix}^{-1}\begin{bmatrix}{4} & {1} & {} \\ {-2} & {3} & {} \\ {} & {} & \end{bmatrix}\cdot\begin{bmatrix}{x} & {} & {} \\ {y} & {} & {} \\ {} & {} & {}\end{bmatrix}=\begin{bmatrix}{4} & {1} & {} \\ {-2} & {3} & {} \\ {} & {} & \end{bmatrix}^{-1}\begin{bmatrix}{2} & {} & {} \\ {-22} & {} & {} \\ {} & {} & {}\end{bmatrix} \\ \end{gathered}[/tex]*These matrices will be the options to put on the first and second boxes.
Then:
[tex]\begin{gathered} \begin{bmatrix}{x} & {} & {} \\ {y} & {} & {} \\ {} & {} & {}\end{bmatrix}=\frac{1}{14}\begin{bmatrix}{3} & -{1} & {} \\ {2} & {4} & {} \\ {} & {} & \end{bmatrix}\cdot\begin{bmatrix}{2} & {} & {} \\ {-22} & {} & {} \\ {} & {} & {}\end{bmatrix}\text{ This is for the third box} \\ \begin{bmatrix}{x} & {} & {} \\ {y} & {} & {} \\ {} & {} & {}\end{bmatrix}=\frac{1}{14}\begin{bmatrix}{3\times2+(-1)\times(-22)} & & {} \\ {2\times2+4\times(-22)} & & {} \\ {} & {} & \end{bmatrix}=\frac{1}{14}\begin{bmatrix}{28} & & {} \\ {-84} & & {} \\ {} & {} & \end{bmatrix}\text{ This is the 4th box} \\ \begin{bmatrix}{x} & {} & {} \\ {y} & {} & {} \\ {} & {} & {}\end{bmatrix}=\begin{bmatrix}{28/14} & & {} \\ {-84/14} & & {} \\ {} & {} & \end{bmatrix}=\begin{bmatrix}{2} & & {} \\ {-6} & & {} \\ {} & {} & \end{bmatrix}\text{ And finally this is the last box} \end{gathered}[/tex]Need help with all of them please help me serious
Answers
we have 4,5,6
In a right triangle
c^2=a^2+b^2
where
c is the hypotenuse (greater side)
a and b are the legs
In an acte triangle
c^2 < a^2+b^2
we have
c=6
a=4
b=5
substitute
c^2=6^2=36
a^2=4^2=16
b^2=5^2=25
36 < 16+25
36 < 41
therefore
is an acute triangle
Part 2
10,24,26 and also classify the triangle
we have
c=26
a=10
b=24
so
c^2=676
a^2=100
b^2=576
in this problem
c^2=a^2+b^2
therefore
Is a right triangle
What is the value of x? Enter your answer in the box. x =
Answers
Step-by-step explanation:
it is an equilateral triangle : all 3 sides are if equal length (indicated by the same symbol on each side).
automatically with that comes the conclusion that all 3 angles have the same size.
and since the sum of all angles in a triangle is always 180°, this means every angle is 180/3 = 60°.
therefore,
2x - 4 = 60
2x = 64
x = 32
and FYI
5y = 60
y = 12
A deck of cards contains RED cards numbered 1,2,3 and BLUE cards numbered 1,2,3,4. Let R be the event of drawing a red card, B the event of drawing a blue card, E the event of drawing an even numbered card, and O the event of drawing an odd card. Drawing the Red 1 is an example of which of the following events? Select all correct answers.
Answers
The event Red 1 is an example of these following events:
R and O.E'.E or R.Which events are included into Red 1?Red cards are represented by the letter R, while the number 1, which is odd, is represented by the letter O.
Both events R and O happen in the, hence the event R and O is one of the possible events to this problem, as the card is both red and has an odd number.
The number is not even, hence the event E' is another one of the events in this problem.
The final event is E or R, as the card has a red number, meaning that at least one of the options E or R are satisfied.
Missing informationThe options which the event respect are missing, and are given by the image at the end of the answer.
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MP is the perpendicular bisector of the side AC of the triangle ABC, in which AB = AC. prove that angle APB = 2 angle B
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We have the following:
[tex]\begin{gathered} \frac{a}{\sin now,[tex]\begin{gathered}I resolved this problem for a test already but it looks like the graph it’s not ok can you help me?
Answers
SOLUTION
The function given is
[tex]f(x)=2x+1[/tex]To obtain the slope, we compare the equation above with the standard form of a slope intercept form.
Hence,, slope intercept is given as
[tex]\begin{gathered} y=mx+c \\ \text{Where m=slope.c=intercept on y (0,c)} \end{gathered}[/tex]Comparing with the function given, we have
[tex]\begin{gathered} M=2,c=1 \\ \text{Hence } \\ \text{slope}=2,\text{ y-intercept=(0,1)} \end{gathered}[/tex]Therefore
The slope = 2 and the y-intercept= (0,1 )
The graph of the functionis given in the image below
What property of equity is this identify the property : if B is between O and K, BK=OK
Answers
Segment addition
The sum of the lenghts of the segments OB and Bk will give the total lenght OK