What is the slope-intercept form for 3x-y=9

Domain: All real numbers (-infinity, infinity)

Range: [9, -infinity)

Answer:

[tex] \sin( \theta) = \frac{opp}{hyp} \\ {c}^{2} = {a}^{2} + {b}^{2} \\ {c}^{2} = {8}^{2} + {15}^{2} \\ = 64 + 225 = 289 \\ c = \sqrt{289} \\ c = 17 \\ \sin( \theta) = \frac{15}{17} = 0.882 \\ \theta = { \sin}^{ - 1} (0.882) \\ \theta = 66.88 \degree\approx 67\degree[/tex]

Answer:

560 cm^3

Step-by-step explanation:

To find volume you will have to multiply all three, length, width and height of an object to determine the answer.

In this problem, 7 cm * 20 cm * 4cm = 560 cm^3

Answer:

5.9987174899

Step-by-step explanation:

9.654km / 1.609344

= 5.9987174899mi

The answer is attached below

Answer:

32 +9w-5=90

9w-5=58

9w=63

w=7

x = 72

Step-by-step explanation:

x + (2x - 36) = 180

3x - 36 = 180

3x = 180 + 36

3x = 216

x = 216/3

x = 72

Answer:

3x + 2 < –7 or 3x + 2 > 7

Answer:

D: 3x + 2 < –7 or 3x + 2 > 7.

Step-by-step explanation:

Answer:

D

Step-by-step explanation:

because I solved generalization and defined to solving for the unknowns

will summarize

Answer:

b

Step-by-step explanation:

Answer:

 y=2x-3

Step-by-step explanation:

slope (m)= 2

The Slope intercept of the line passing through (4,5) is

y=mx+b

5 = 2(4) + b

5 = 8 + b

b = -3

The equation of the line passing through pt. (4,5) is  

 y= mx+b

  y=2x-3

B. The submarine is 125 feet below sea level.

Step-by-step explanation:

-124 feet because - (negative) means the submarine is 124 meters below sea level (masl).

Answer:

The elevation of a submarine with respect to sea level is displayed as - 125 feet. Which statement is correct?

A. The submarine is 125 feet above sea level.

B. The submarine is 125 feet below sea level.

C. The submarine is -125 feet above sea level.

D. The submarine is -125 feet below sea level.

Step-by-step explanation:

Answer:

Step-by-step explanation:

I. the point is is moved 4 to the right of the center point and 2 down. So it is (4, -2)

P. This point is moved negative 4 (to the left) and down 3 . So it is: (-4, -3)

G. This point is moved 5 to the right and then up 2 which makes it (5, 2)

Q.  This point is moved 6 to the right and 4 down which makes it (6, -4)

R. This point is moved 2 to the left and 2 up which makes it (-2, 2)

S. (6, 4)

J. (-2, -4)

U. (-5, 0)

H. (3, -1)

K. (-6, -5)

Answer:

I think the answer is 67.5. Hope this helps! :)

Answer:

B

Step-by-step explanation:

Total(1,968) - x(164) = new value

Answer:

the person above me is correct C

Step-by-step explanation:

or a(2 + 16(2 = 20(2

The correct equation to the missing leg in the triangle is,

⇒ a² + 16² = 20²

What is Pythagoras theorem?

The Pythagoras theorem states that in a right triangle, the square of the hypotenuse is equal to the sum of the square of the other two sides.

Given that;

The triangle is missing the b leg,

And, Two sides are,

c = 20 and a = 16

Hence, By using Pythagoras theorem we get;

⇒ a² + 16² = 20²

Thus, The correct equation to the missing leg in the triangle is,

⇒ a² + 16² = 20²

Learn more about the Pythagoras theorem visit:

https://brainly.com/question/343682

#SPJ7

Complete question is this,

Which equation can be used to find the missing leg in the triangle?

a² + 20² = 16²

20² + 16² = a²

a² + 16² =20²

16 + a² = 20

p.s the triangle is missing the b leg, and c=20 and a=16

Answer:

1. x = -1

2. y = -1, y = 2

3. y = -½ + i [tex]\frac{\sqrt{3} }{2}[/tex]; y = -½ - i [tex]\frac{\sqrt{3} }{2}[/tex]

4. x = -3; x = -6

Step-by-step explanation:

I will only produce work for questions 1 through 4, and you could follow the same steps for questions 5 and 6 so that you could learn and get used to solving quadratic equations. I am practically using the same techniques in solving questions 1 through 4 anyway.

1.) x² + 2x + 1 = 0

where a = 1, b = 2, c = 1

Determine the nature and number of solutions based on the discriminant, b² - 4ac:

b² - 4ac = 2² - 4(1)(1) = 4 - 4 = 0  

This means that the equation has one real root.  

Next, determine the factors of the quadratic equation.  

Use the perfect square trinomial factoring technique:

u² + 2uv + v² = (u + v)²

From the equation, x² + 2x + 1 = 0

where a = 1, b = 2, c = 1

Find factors with product a × c and sum b:

Possible factors:

product a × c :  1 × 1 = 1

sum b :  1 + 1 = 2

Therefore, the binomial factors of x² + 2x + 1 = 0 is (x + 1)²

To find the roots, set x = 0:

x + 1 = 0

Subtract 1 from both sides to isolate x:

x + 1 - 1 = 0 - 1

x = -1  (This is the root of the equation).

2)  y² - y - 2 = 0

where a = 1, b = -1, and c = -2

Determine the nature and number of solutions based on the discriminant, b² - 4ac:  

b²  - 4ac = (-1)² - 4(1)(-2) = 9  

Since b² - 4ac > 0, then it means that the equation will have two real roots.

From the equation, y² - y - 2 = 0

where a = 1, b = -1, and c = -2:

Find factors with product a × c and sum b:

 Product a × c :  

1 × -2 = -2

-1 × 2 = -2

Sum b:  

1+ (-2) = -1

-1 + 2 = 1

Therefore, the possible factors are: 1 and -2:

(y + 1) (y - 2)

To find the roots, set y = 0:

y + 1 = 0

Subtract 1 from both sides:

y + 1 - 1 = 0 - 1

y = -1

y - 2 = 0

Add 2 to both sides:

y -2 + 2 = 0 + 2

y = 2

Therefore, the roots of the quadratic equation, y² - y - 2 = 0 are: y = -1 and y = 2.

3.)  y² + y + 1 = 0

where a = 1, b = 1, and c = 1

Determine the nature and number of solutions based on the discriminant, b² - 4ac:  

b² - 4ac = (1)2 - 4(1)(1) = -3

Since b² - 4ac < 0, then it means that the equation will have two complex roots.

Use the Quadratic Formula:

[tex]y = \frac{-b +/- \sqrt{b^{2} - 4ac} }{2a}[/tex]

[tex]y = \frac{-1 +/- \sqrt{1^{2} - 4(1)(1)} }{2(1)}[/tex]

[tex]y = \frac{-1 +/- \sqrt{1 - 4} }{2}[/tex]

[tex]y = \frac{-1 +/- \sqrt{-3} }{2}[/tex]

[tex]y = \frac{-1 +/- i\sqrt{3} }{2}[/tex]

Therefore, the roots of the quadratic equation, y² + y + 1 = 0 are:

y = -½ + i [tex]\frac{\sqrt{3} }{2}[/tex]; y = -½ - i [tex]\frac{\sqrt{3} }{2}[/tex]

4) x² + 9x + 18 = 0

where a = 1, b = 9, and c = 18.

Determine the nature and number of solutions based on the discriminant, b² - 4ac:  

b² - 4ac = (9)2 - 4(1)(18) = 9

Since b² - 4ac > 0, then it means that the equation will have two real roots.

Use the Quadratic Formula:

[tex]x = \frac{-b +/- \sqrt{b^{2} - 4ac} }{2a}[/tex]

[tex]x = \frac{-9 +/- \sqrt{9^{2} - 4(1)(18)} }{2(1)}[/tex]

[tex]x = \frac{-9 +/- \sqrt{9} }{2}[/tex]

[tex]x = \frac{-9 + 3}{2}; x = \frac{-9 - 3}{2}[/tex]

[tex]x = \frac{-6}{2}; x = \frac{-12}{2}[/tex]

x = -3; x = -6

Therefore, the roots of the quadratic equation, x² + 9x + 18 = 0

are: x = -3 and x = -6.  

Answer:

A. The relation is not a function.

Step-by-step explanation:

Since 2 --> -3, and 2 --> 3, the relation is not a function.

Answer

x+y+z=10

1.25x+2.75x+3.15x+18.90

x=2z

Step-by-step explanation:

x=almonds

y=walnuts

z=cashews

9514 1404 393

Answer:

Step-by-step explanation:

We can let a, w, c represent pounds of almonds, walnuts, and cashews, respectively. Then the given relations are ...

  a +w +c = 10 . . . . . total pounds of nut mix

  a = 2w . . . . . . . . . twice as many almonds as walnuts

  1.25a +2.75w +3.15c = 18.90 . . . . total cost of the mix

__

Solving the system of equations can proceed by any of the methods you have learned for systems of two equations in two unknowns. Substitution, elimination, and matrix methods all work. Graphing methods are also available.

We can easily reduce this system to two equations in two unknowns by using the second equation to substitute for 'a'.

  2w +w +c = 10   ⇒   3w +c = 10

  1.25(2w) +2.75w +3.15c = 18.90   ⇒   5.25w +3.15c = 18.90

Solving the first of these equations for c, then substituting into the second of these equations gives ...

  c = 10 -3w

  5.25w +3.15(10 -3w) = 18.90

  -4.20w +31.50 = 18.90 . . . . simplify

  12.60 = 4.20w . . . . . . . . . . . add 4.20w -18.90

  3 = w . . . . . . . . . . . . . . . . . . . divide by 4.20

  c = 10 -3(3) = 1 . . . . . . . . . . . use the expression for c

  a = 2(3) = 6 . . . . . . . . . . . . . use the expression for a

The nut mix used 6 pounds of almonds, 3 pounds of walnuts, and 1 pound of cashews.

_____

Additional comment

The attached graph shows one way to obtain a graphical solution. The first and third equations were solved for c, and those expressions were set equal to obtain the graph for the red line. The blue line is the second equation. Here, we have used (x, y) for (a, w). The solution for these variables is (a, w) = (6, 3). Using the first expression for c gives c = 10 -(6+3) = 1. This is the same solution as above.

Answer:

9

Step-by-step explanation:

the gcf is 9

Answer:

20 kilograms of paper will be recycled in Sean's office after 10 weeks.

9514 1404 393

Answer:

  domain: (-4, -2) ∪ [-1, 4]

  range: (-5, 3)

Step-by-step explanation:

Domain

The domain is the horizontal extent of the graph. Here, it is comprised of two intervals. The left interval is open, as the function is not defined for x-values of -4 or -2. That interval is (-4, -2). The right interval is closed, as the function is defined for both x=-1 and x=4. That interval is [-1, 4]. The domain is the union of these two intervals.

  D: (-4, -2) ∪ [-1, 4]

__

Range

The range is the vertical extent of the graph. The left portion of the graph has a range from -5 to 3, but neither of those values is included in it. That is, the range is an open interval: (-5, 3).

The right portion of the graph has a range from 1 to 2, including both of those values. This interval is already included in the interval (-5, 3), so only one interval is needed to describe the range:

  R: (-5, 3)

Answer:

6.58 has the greatest value

6.362 < 6.5 < 6.537 < 6.58

the answer is -2¹⁶

mark me as brainlist answer

Answer:

Step-by-step explanation:

The average rate is just the slope of the function between t = 0 and t = 10, so we must calculate change in w / change in t. w(10) = 130. w(0) = 100. So, the slope = (130-100)/(10-0) = 30/10 = 3 gallons per minute.

Answer: 2

Step-by-step explanation: