What is the range of the function f(x) = |x| + 5?

R: {f(x) ∈ ℝ | f(x) < 5}
R: {f(x) ∈ ℝ | f(x) ≥ 5}
R: {f(x) ∈ ℝ | f(x) > 5}
R: {f(x) ∈ ℝ | f(x) ≤ 5}

The determinant of each of the given matrices are:

1) -4269

2) -1988

3) -68.92

The determinant of a matrix is a number that is specially defined only for square matrices. Determinants are mathematical objects that are very useful in the analysis and solution of systems of linear equations.

Thus:

1) [tex]\left[\begin{array}{ccc}7&&31\\142&&19\\\end{array}\right][/tex]

The determinant of this 2 x 2 matrix is:

(7 * 19) - (142 * 31) = -4269

2) [tex]\left[\begin{array}{ccc}7&11&21\\55&8&2\\-16&1&-9\end{array}\right][/tex]

The determinant of this 3 x 3 matrix is:

7((8*-9) - (1*2)) + 11((55*-9) - (2*-6)) + 21((55*1) - (8*-16)) = -1988

3) [tex]\left[\begin{array}{ccc}5.07&6.02&2.01\\-30.7&2.5&3.5\\3.55&-1.1&2.35\end{array}\right][/tex]

The determinant of this 3 x 3 matrix is:

5.07[(2.5 * 2.35) - (-1.1 *  3.5)] + 6.02[(-30.7 * 2.35) - (3.5 * 3.55)] + 2.01[(-30.7 * -1.1) - (2.5 * 3.55)] = -68.92

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The period of the function is 1/60 minutes

As a result, blood pressure changes between each heartbeat as a consequence of these oscilllations happening every second.

Max value = 110 mmHg

the minimum = 50 mmHg.

This suggests that systolic pressure remains at 110 mmHg and diastolic pressure is still maintained at 50 mmHg.

blood pressure peaks occur at times t = (1/2 + 2 * k) / 120 seconds.

(a) The given function is:

p(t) = 80 + 30 * sin(120 * pi * t)

This is equivalent to sinusoidal function in the form of:

p(t) = A + B * sin(C * t)

Where:

A is the baseline value,

B is the amplitude, and

C determines the frequency of the function.

Information given in the problem

A = 80, B = 30, and C = 120 * pi.

The period of a sinusoidal function is given by:

Period = 2 * pi / C

Period = 2 * pi / (120 * pi) = 1/60 minutes

The period of the function is 1/60 minutes, which means that the blood pressure oscillates every 1/60 minutes or 1 second. As a result, blood pressure changes between each heartbeat as a consequence of these oscilllations happening every second.

(b) maximum and minimum values of a sinusoidal function

Max value = A + B

Min value = A - B

Substituting the values of A and B:

Max value = 80 + 30 = 110 mmHg

Min value = 80 - 30 = 50 mmHg

Max value = A + B giving values of 110 mmHg

the minimum is A - B delivering 50 mmHg.

This suggests that systolic pressure remains at 110 mmHg and diastolic pressure is still maintained at 50 mmHg.

(c)  the time at which the blood pressure is at its maximum, we solve for t when the sinusoidal function is at its peak.

sin(120 * pi * t) = 1

Taking the inverse sine of both sides:

120 * pi * t = pi/2 + 2 * pi * k (where k is an integer)

Solving for t:

t = (1/2 + 2 x k)/120 (for k = 0, 1, 2, ......)

implying that blood pressure peaks occur at times t = (1/2 + 2 * k) / 120 seconds.

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a) The slope shows that the appropriate dose c for an older child increase by 6.225 mg if the child is one year older.

b) The dose for newborn baby is: 6.225 mg

The equation of a line in slope intercept form is:

y = mx + c

where: m is slope and c is y-intercept

(a) Let a be an age of an child in years. Then:

c = 0.0417Da + 0.0417D

Where D is a constant

Since D = 150 mg, then we have:

The slope of the graph = 0.0417(150)

= 6.225 mg/year

The slope shows that the appropriate dose c for an older child increase by 6.225 mg if the child is one year older.

(b) Newborn baby:  a=0

Thus:

c(0) = 0 + 6.225

= 6.225 mg

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The value of reserve rate is 5%

Given that;

Solitary savings bank received initially amount of $2000.

Now, Let x% percent be kept as reserve then (100-x)% will be loaned out which would be deposited in other bank.

The other bank would keep x% of (100 - x) and again loan the remaining amount.

Thus the total deposits of this cycle would be a geometric series as

⇒ 2000[1 + (100 - x)% + (100 - x)²%+(100-x)² +...]

Here common ratio is,

(100 - x) / 100 = 1 - 0.01x <

for all possible x

This series is infinite and sum of this would be

= sum of geometric series

= 2000 (1/ (x/100)

= 200000/x

This is given as, 40000

Hence, equate and simplify to get;

⇒ x = 5%

So, The value of reserve rate is 5%

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Answer:

The result for the difference in lung cancer worry between males and females was not statistically significant in Hahn's (2017) study (t(45)=0.69, p > 0.05). The results for the differences in worry between smokers and nonsmokers, and those who did and did not graduate high school, were statistically significant with p values less than 0.05.

Step-by-step explanation:

Domain where x is not equal to 3 and a range where y is not equal to 2 for function  (x+5)/(x-3)

Domain = Set of all input values of a function.

range = set of all output values of a function.

Given: Domain:  x≠3 ; range = y≠2

We do not include a value for domain if it makes the expression indeterminant .

Since all the functions in options are fractions, here the denominator does not equal to 0.

But in option C and D, the denominator can be zero if x=3.

So , domain for then it x ∈ R-3

for option C if 2=2(x+5)/(x-3)

x-3=x+5

-3=5 which is not possible

Where as in option D, 2=(x+5)/(x-3)

2x-6=x+5

x=11

Hence, domain where x is not equal to 3 and a range where y is not equal to 2 for function  (x+5)/(x-3)

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Which function has a domain where x does not =3 and a range where y does not =2? A. f(x)=(x-5)/(x+3) B. f(x)=2(x+5)/(x+3) C. 2(x+5)/(x-3) D. (x+5)/(x-3)

Answer:

I think its 221

Step-by-step explanation:

(1) F(s) = 5+1 / (s^2 + 28s + 2)

To perform partial fraction expansion, we first need to factor the denominator:

s^2 + 28s + 2 = (s + 14 - sqrt(194))(s + 14 + sqrt(194))

We can then write:

F(s) = A / (s + 14 - sqrt(194)) + B / (s + 14 + sqrt(194))

where A and B are constants to be determined.

Multiplying both sides by the denominator and simplifying, we get:

5+1 = A(s + 14 + sqrt(194)) + B(s + 14 - sqrt(194))

Setting s = -14 - sqrt(194), we get:

5+1 = B(2sqrt(194))

Solving for B, we get:

B = (5+1) / (2sqrt(194))

Setting s = -14 + sqrt(194), we get:

5+1 = A(2sqrt(194))

Solving for A, we get:

A = (5+1) / (2sqrt(194))

Thus, the partial fraction expansion of F(s) is:

F(s) = [(5+1) / (2sqrt(194))] / (s + 14 + sqrt(194)) + [(5+1) / (2sqrt(194))] / (s + 14 - sqrt(194))

To find the inverse Laplace transform, we can use the table of Laplace transforms or MATLAB. Using MATLAB, we get:

ilaplace(F(s)) = (5+1) / (2sqrt(194)) * (exp(-14t) / sqrt(194)) * (cosh(sqrt(194)t) + sinh(sqrt(194)t))

(2) F(s) = s^2 + 3s + 1 / (s + 2)(s^2 + 8s + 1)

To perform partial fraction expansion, we first need to factor the denominator:

s^2 + 8s + 1 = (s + 4 - sqrt(15))(s + 4 + sqrt(15))

We can then write:

F(s) = A / (s + 2) + B / (s + 4 - sqrt(15)) + C / (s + 4 + sqrt(15))

where A, B, and C are constants to be determined.

Multiplying both sides by the denominator and simplifying, we get:

s^2 + 3s + 1 = A(s + 4 - sqrt(15))(s + 4 + sqrt(15)) + B(s + 2)(s + 4 + sqrt(15)) + C(s + 2)(s + 4 - sqrt(15))

Setting s = -4 + sqrt(15), we get:

-4 + sqrt(15) = A(-4 + sqrt(15) + 4 + sqrt(15))

Solving for A, we get:

A = (-4 + sqrt(15)) / (2sqrt(15))

Setting s = -4 - sqrt(15), we get:

-4 - sqrt(15) = A(-4 - sqrt(15) + 4 + sqrt(15))

Solving for A, we get:

A = (-4 - sqrt(15)) / (-2sqrt(15))

Setting s = -2, we get:

-1 = B(-2)(-2 + 4 + sqrt(15))

Solving for B, we get:

B = (-1) / (2sqrt(15) + 4)

Setting s =

Answer:

The cost per ounce of the small cup is $0.269

Step-by-step explanation:

To find the cost per ounce, we can divide the cost of the cup by the number of ounces it holds.

Cost per ounce = Cost of the cup ÷ Number of ounces in the cup

Cost of the cup = $2.69

Number of ounces in the cup = 10 oz

So,

Cost per ounce = $2.69 ÷ 10 oz

Cost per ounce = $0.269 per oz (rounded to the nearest thousandth)

Therefore, the cost per ounce of the small cup is $0.269.

Answer:

the simplified expression is 4x - 4y

Step-by-step explanation:

1. Rewrite!

12x - 7y - 8x + 3y

2. Combine like terms:

12x - 8x - 7y + 3y

3. Solve both sides to simplify

12 x - 8x = 4x

and

-7y + 3y = -4y

So, 4x - 4y is your answer.

6,000 mL is equal to 6 litres

A unit of measurement is a definite magnitude of a quantity, defined and adopted by convention or by law, that is used as a standard for measurement of the same kind of quantity.

We know that 6,000 mL  is equal to 6L

One litre is equal to 1000 ml

1 l = 1000 ml

6 l=6000 ml

Hence,  6,000 mL is equal to 6 litres

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The problem with Foofy's conclusion is that she drew a general conclusion from a sample without considering potential biases or confounding factors. To make the report better, she could provide more context, acknowledge potential biases, and make it clear that her conclusion only applies to her sample.

The problem with Foofy's conclusion is that it is based on a biased sample. She only surveyed mothers who were employed outside the home, which does not represent all working women. Therefore, her conclusion cannot be generalized to all working women.

To make the report better, Foofy could specify that her conclusion only applies to mothers who are employed outside the home, rather than all working women.

Additionally, she could improve the study's sampling method by randomly selecting a more representative sample of working women, rather than only surveying mothers who are employed outside the home.

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Answer: Linear

Step-by-step explanation:

I can tell from the table because there is a difference of 4 between each y value.

I dont know what the other blanks will be because i cant see the options. But it shouldnt be too hard to fill out

The meaning of the absolute value of -5.5 is given as follows:

The temperature decreases 5.5 degrees.

The absolute value of a number is the number without the signal, for example:

|-2| = |2| = 2.

The number in this problem is given as follows:

-5.5.

Hence:

Hence the second option is the correct option in the context of this problem.

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Answer: 3

Step-by-step explanation:

The scale factor is the proportional ratio from one figure to another.

Notice the corresponding lengths are CE≅JS, TC≅TJ, and TE≅TS.

Comparing CE and JS, the length for CE is 4, and the length for JS is 12.

[tex]4*3=12[/tex]

This means the scale factor is 3. To be sure, let's try the other side.

TC and TE have the same lengths. They are both 5 in length. TS is 15 in length.

[tex]5*3=15[/tex]

This confirms that the scale factor is 3.

There is sufficient evidence to suggest that the proportion of homes with only a landline phone is less than 7.4%.

Null hypothesis: p ≥ 0.074

proportion of homes with only a landline phone is greater than or equal to 7.4%

Alternative hypothesis: p < 0.074 (proportion of homes with only a landline phone is less than 7.4%)

where p is the true proportion of homes in the population that have only a landline phone.

(b) Compute the test statistic and p-value assuming the null hypothesis is true, using a significance level of α = 0.05.

To compute the test statistic, we first need to calculate the sample proportion:

p cap= 0.0577

The test statistic is given by:

z = (p cap - p) / √p(1-p)/n

where n is the sample size. Substituting the values, we get:

z = (0.0577 - 0.074) / √0.074(1-0.074)/13323)

= -12.28

the p-value is less than 0.0001, which is much smaller than the significance level of 0.05.

Therefore, we reject the null hypothesis and conclude that there is sufficient evidence to suggest that the proportion of homes with only a landline phone is less than 7.4%.

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The coordinates of the focus of the parabola y = -(1/8)x² - 2x - 4 is (-8, 2).

y = -(1/8)x² - 2x - 4

Given by the equation y = -(1/8)x² - 2x - 4,

To find the focus of the parabola we first need to put the equation in standard form:

y = a(x - h)² + k

Where (h, k) is the vertex of the parabola, and a is a constant that determines the shape and size of the parabola.

Completing the square on the x terms, we get:

y = -(1/8)(x² + 16x + 64) - 4 + 8

= -(1/8)(x + 8)² + 4

Comparing this to the standard form, we see that the vertex is (-8, 4) and a = -1/8.

Since the coefficient of x² is negative, the parabola opens downwards.

The focus of the parabola is located at a distance of 1/(4a) units from the vertex, on the axis of symmetry, which is a vertical line passing through the vertex.

Substituting the value of a, we get:

= 1/(4a)

= 1/(4(-1/8))

= 2

Therefore, the focus of the parabola is located 2 units below the vertex, on the line x = -8.

So the focus has coordinates (-8, 2).

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The point (-25, 15) lies in the third quadrant above the x-axis and left to the y-axis.

The four quadrants are formed by the intersection of the x-axis and the y-axis on a Cartesian plane. The point (-25, 15) is represented by the coordinates (-25) and (15) on the x and y-axis, respectively. Since the x-coordinate is negative, the point lies to the left of the y-axis.

Similarly, since the y-coordinate is positive, the point lies above the x-axis. Therefore, the point (-25, 15) is located in the third quadrant, which is below the x-axis and to the left of the y-axis. In this quadrant, both the x and y-coordinates are negative.

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The expressions for [tex]x^6[/tex] can be varied, one such basic expression is [tex](x^n)^m[/tex], where n and m are positive integers equal to 2 and 3.

A grouping of numbers, variables, and operations like addition, subtraction, multiplication, division, exponentiation and more is known as an expression. A single number or variable can be an expression it can also include a combination of terms or functions.

By simplifying the [tex]x^6[/tex] we can get the expression-

[tex]x^6=(x^2)^3 \\\\x^6=(x^3)^2\\\\x^6=x^2 * x^4 \\\\x^6=(x^2 + 1 - 1)^6\\\\x^6=(x^3 - x^2 + x - 1 + 1)^2[/tex]

all these expressions represent [tex]x^6[/tex].

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The Volume of Cone is 84.8 m³.

We have,

d = 9 m

r= 4.5 m

H = 4 m

So, Volume of Cone

= 1/3 πr²h

= 1/3 (3.14) (4.5)² (4)

= 1/3 (3.14) (20.25) (4)

= 84.8 m³

Thus, the volume is 84.8 m³.

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The solution is the missing angle is 74.

Here, we have,

The sum of all the angles of a triangle (of all types) is equal to 180°.

The sum of the length of the two sides of a triangle is greater than the length of the third side.

In the same way, the difference between the two sides of a triangle is less than the length of the third side.

here, we have,

from the given diagram, we get,

the given angles are 55 and 51

let,  the missing angle be x

we know that,

The sum of all the angles of a triangle (of all types) is equal to 180°.

so, x+55+51 = 180

or, x + 106 = 180

or, x = 74

Hence, The solution is the missing angle is 74.

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The expansion and simplification of the expression, (3x - 2)(2x² + 5x - 1) is 6x³ + 11x² - 13x + 2.

In order to expand and simplify an expression, we need to multiply out the brackets and then simplify the resulting expression by collecting the like terms.

Therefore, let's expand and simplify the expression.

Hence,

(3x - 2)(2x² + 5x - 1)

Therefore, let's multiply

(3x - 2)(2x² + 5x - 1)  = 6x³ + 15x² - 3x - 4x² - 10x + 2

6x³ + 15x² - 3x - 4x² - 10x + 2 = 6x³ + 15x² - 4x² - 3x - 10x + 2

6x³ + 15x² - 4x² - 3x - 10x + 2 = 6x³ + 11x² - 13x + 2

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Answer:16.484

Step-by-step explanation:

find the area of a regular polygon with n sides and radius r, we can use the formula:

Area = (n * r^2 * sin(2*pi/n)) / 2

where pi is the mathematical constant pi (approximately equal to 3.14159).

Plugging in n = 14 and r = 1, we get:

Area = (14 * 1^2 * sin(2*pi/14)) / 2

= (14 * sin(pi/7)) / 2

≈ 16.484

Therefore, the area of the polygon with 14 sides and a radius of 1 unit is approximately 16.484 square units.

Answer:twelve million, three hundred and four thousand, six hundred and fifty two

Step-by-step explanation:

The graph that correctly shows the boundary line for y ≤ 2x − 4, is B. Graph B.

The inequality y ≤ 2x − 4, shows that the y - intercept is - 4. What this means is that the boundary line must pass through ( 0, - 4 ). As Graphs C and D do not cross ( 0, - 4 ), neither of them can be the boundary line.

Also, when representing an inequality on a graph, the signs of ≤ and ≥ are presented with a solid line. > and < are the ones presented with a broken line. This means that Graph A cannot the boundary line for the inequality.

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