Answer: 20.16kg.m\s
Explanation: Here is given that M= 7.2 Kg, and v= 2.8 m/s So, momentum ,P=M. v = (7.2*2.8) = 20.16 Kg. m/s, which is a number having four significant digits. but we have to provide the answer in two significant digits. Therefore, to convert
a 0.145 kg baseball is thrown with an intitial volecity of 40 m/s. it is hit with a 0.95 kg bat swung at 35 m/s. find the speed of the baseball after this elastic collision
The speed of the baseball after this elastic collision is 35.825 m/s
What is an elastic collision?In an elastic collision is one in which no net loss of kinetic energy in the system is observed after collision. Elastic collisions conserve, momentum and kinetic energy. It works on the basis of the law of conservation of momentum. This may be explained by following equation:
Pₙ = P₁ + P₂
mₙvₙ = m₁v₁ + m₂v₂
Where, Pₙ = final momentum
mₙ = total mass of the system
vₙ = final velocity of the system
For the given question:
(m₁ + m₂)vₙ = m₁v₁ + m₂v₂
(0.145 + 0.95)vₙ = (0.145 × 40) + (0.95 × 35)
1.09 vₙ = 5.8 + 33.25
1.09 vₙ = 39.05
vₙ = [tex]\frac{39.05}{1.09}[/tex]
vₙ = 35.825 m/s
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