What is the molarity of a solution prepared by diluting 43.72 ml of 1.005 M aqueous K2CR2O7 to 500 ml

Answers

Answer 1

Answer:

43.72

Explanation:

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Answer 2

The molarity of the solution will be "0.088 M".

Given values are:

Volume,

[tex]V_1 = 43.72 \ ml[/tex][tex]V_2 = 500 \ ml[/tex]

Molarity,

[tex]M_1 = 1.005 \ M[/tex][tex]M_2 =?[/tex]

By using the Dilution principle, we get

→ [tex]M_2 = \frac{M_1 V_1}{V_2}[/tex]

By substituting the given values, we get

→       [tex]=\frac{1.005\times 43.72}{500}[/tex]

→       [tex]= \frac{ 43.9586}{500}[/tex]

→       [tex]= 0.088 \ M[/tex]

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Explanation:

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Answers

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Answers

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Here you go its agin me answering you

This is a science question.

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Answers

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Answers

Answer:

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Explanation:

Podemos numerar estos compuestos

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