The multiples of the denominator of 2/5 is,
5,10,15,20,25....
The multiples of the denominator of 3/2 is,
2,4,6,8,10.....
Thus, the required least common denominator is 10.
Find an equation of the line. Write the equation using function notation.Through (4, - 7); perpendicular to 6y=x- 12The equation of the line is f(x)=..
To determine the equation of the line you need to determine its slope first.
You know that the line 6y=x-12 is perpendicular to the line you have to determine, two lines that are perpendicular, their slopes are opposite reciprocals. For example, let "m" represent the slope of one of the lines and "n" represent the slope of the perpendicular line, you can express their relationship as follows:
[tex]m=-\frac{1}{n}[/tex]To determine the slope of the given line, you have to write it in slope-intercept form:
[tex]y=mx+b[/tex]Where
m represents the slope
b represents the y-intercept
Given the line:
[tex]6y=x-12[/tex]-Divide both sides by 6
[tex]\begin{gathered} \frac{6y}{6}=-\frac{x}{6}=-\frac{12}{6} \\ y=-\frac{1}{6}x-2 \end{gathered}[/tex]The slope of this line is the coefficient of the x-term, n=-1/6
Its opposite reciprocal is:
[tex]\begin{gathered} m=-\frac{1}{n} \\ m=-(-\frac{1}{\frac{1}{6}}) \\ m=-(-1\cdot6) \\ m=-(-6) \\ m=6 \end{gathered}[/tex]The slope of the line you have to determine is m=6
Now that you have the slope of the line, using the point-slope form, you can determine the equation of the line:
[tex]y-y_1=m(x-x_1)[/tex]Where
m represents the slope of the line
(x₁,y₁) represent the coordinates of one point of the line
Replace the formula with m=6 and (x₁,y₁)=(4,-7)
[tex]\begin{gathered} y-(-7)=6(x-4) \\ y+7=6(x-4) \end{gathered}[/tex]The next step is to write the equation in slope-intercept form:
-Distribute the multiplication on the parentheses term:
[tex]\begin{gathered} y+7=6\cdot x-6\cdot4 \\ y+7=6x-24 \end{gathered}[/tex]-Pass "+7" to the right side of the equation by applying the opposite operation "-7" to both sides of it:
[tex]\begin{gathered} y+7-7=6x-24-7 \\ y=6x-31 \end{gathered}[/tex]Finally, write the equation of the line using function notation:
[tex]f(x)=6x-31[/tex]A city has a population of 230,000 people. Suppose that each year the population grows by 4.25%. What will the population be after 12 years?
Answer:
379,001.
Explanation:
The population of the city grows by 4.25%.
This is a constant factor and models an exponential function.
An exponential population function is of the form:
[tex]\begin{gathered} P(n)=P_0(1+r)^t \\ P_o=\text{Initial Population} \\ r\text{ = growth rate} \\ t\text{ =time in years} \end{gathered}[/tex]From the given problem:
[tex]P_0=230,000,r=4.25\%=0.0425,t=12years[/tex]This then gives us:
[tex]\begin{gathered} P(12)=230000(1+0.0425)^{12} \\ =230000(1.0425)^{12} \\ =379,001 \end{gathered}[/tex]The population after 12 years will be approximately 379,001.
Find the missing number so that the equation has no solutions.
5x + 12 =
- 2
Submit
By solving the equation 5x + 12 = -2, the value of x in is -2.8
Solution
Bring 12 to the other side of the equation. 12 becomes -125x = -2-12
Add -2 and -12.5x = -14
We get -14
Bring 5 to the other side of the equation and divide -14 and 5x = -14 ÷ 5
Hence the value of x is -2.8x = -2.8
Hence, by solving the equation 5x + 12 = -2, the value of x in is -2.8
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Which of the following functions has an amplitude of 3 and a phase shift of pi over 2 question mark
Remember that f(x) = A f(Bx-C) +D
Where |A| is the Amplitude and C/B is the phase Shift
Options
A, B C all have amplitudes of |3| so we have just eliminated D with the amplitude
We need a phase shift of C/B = pi/2
A has Pi/2
B has -Pi/2
C has pi/2 /2 = pi/4
Choice A -3 cos ( 2x-pi) +4 has a magnitude of 3 and and phase shift of pi/2
Simplify the following expression 6 + (7² - 1) + 12 ÷ 3
You have to simplify the following expression
[tex]6+(7^2-1)+12\div3[/tex]To solve this calculation you have to keep in mind the order of operations, which is:
1st: Parentheses
2nd: Exponents
3rd: Division/Multiplication
4th: Addition/Subtraction
1) The first step is to solve the calculation within the parentheses
[tex](7^2-1)[/tex]To solve it you have to follows the order of operations first, which means you have to solve the exponent first and then the subtraction:
[tex]7^2-1=49-1=48[/tex]So the whole expression with the parentheses calculated is:
[tex]6+48+12\div3[/tex]2) The second step is to solve the division:
[tex]12\div3=4[/tex]Now the expression is
[tex]6+48+4[/tex]3) Third step is to add the three values:
[tex]6+48+4=58[/tex]See photo for problem
The distance, x, from one corner to another corner three corners away is 4. 70cm
The distance, y, from one corner to another corner two corners away is 4. 07cm
How to determine the valueIt is important to note that the image shown is a hexagon and each of the interior angles of a hexagon has a value of 120 degrees
Also note that the have the trigonometric identities;
sinecosinetangentcotangentsecantcosecantUsing the cosine identity, we have;
sin θ = adjacent/ hypotenuse
substitute the values
cos 60 = 2.35/x
cross multiply
x = 2. 35/cos 60
x = 2. 35/ 0. 5
x = 4. 7 cm
Then, we have,
sin 60 = y/ 4. 7
y = sin 60 × 4.7
y = 0. 8660 × 4. 7
y = 4. 07cm
Hence, the values are 4. 7cm and 4. 07cm
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Use properties to rewrite the given equation. Which equations have the same solution as 2.3p – 10.1 = 6.5p – 4 – 0.01p? Select two options. 2.3p – 10.1 = 6.4p – 4 2.3p – 10.1 = 6.49p – 4 230p – 1010 = 650p – 400 – p 23p – 101 = 65p – 40 – p 2.3p – 14.1 = 6.4p – 4
The required equation has the same solution as 2.3p – 10.1 = 6.5p – 4 – 0.01p is 230p – 1010 = 650p – 400 – p.
What is an equivalent expression?Equivalent expressions are even though they appear to be distinct, their expressions are the same. when the values are substituted into the expression, both expressions produce the same result and are referred to be equivalent expressions.
We have the given expression below:
⇒ 2.3p – 10.1 = 6.5p – 4 – 0.01p
Convert the decimal into a fraction to get
⇒ (23/10)p – (101/10) = (65/10)p – 4 – (1/100)p
⇒ (23p – 101)/10 = (650p – 400 – p) /100
⇒ 230p – 1010 = 650p – 400 – p
As a result, the equation that has the same answer as 230p – 1010 = 650p – 400 – p.
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The one-to-one functions 9 and h are defined as follows.g={(0, 5), (2, 4), (4, 6), (5, 9), (9, 0)}h(x)X +811
Step 1: Write out the functions
g(x) = { (0.5), (2, 4), (4,6), (5,9), (9,0) }
[tex]h(x)\text{ = }\frac{x\text{ + 8}}{11}[/tex]Step 2:
For the function g(x),
The inputs variables are: 0 , 2, 4, 5, 9
The outputs variables are: 5, 4, 6, 9, 0
The inverse of an output is its input value.
Therefore,
[tex]g^{-1}(9)\text{ = 5}[/tex]Step 3: find the inverse of h(x)
To find the inverse of h(x), let y = h(x)
[tex]\begin{gathered} h(x)\text{ = }\frac{x\text{ + 8}}{11} \\ y\text{ = }\frac{x\text{ + 8}}{11} \\ \text{Cross multiply} \\ 11y\text{ = x + 8} \\ \text{Make x subject of formula} \\ 11y\text{ - 8 = x} \\ \text{Therefore, h}^{-1}(x)\text{ = 11x - 8} \\ h^{-1}(x)\text{ = 11x - 8} \end{gathered}[/tex]Step 4:
[tex]Find(h.h^{-1})(1)[/tex][tex]\begin{gathered} h(x)\text{ = }\frac{x\text{ + 8}}{11} \\ h^{-1}(x)\text{ = 11x - 8} \\ \text{Next, substitute h(x) inverse into h(x).} \\ \text{Therefore} \\ (h.h^{-1})\text{ = }\frac{11x\text{ - 8 + 8}}{11} \\ h.h^{-1}(x)\text{ = x} \\ h.h^{-1}(1)\text{ = 1} \end{gathered}[/tex]Step 5: Final answer
[tex]\begin{gathered} g^{-1}(9)\text{ = 5} \\ h^{-1}(x)\text{ = 11x - 8} \\ h\lbrack h^{-1}(x)\rbrack\text{ = 1} \end{gathered}[/tex]PLEASE PLEASE HELP
5. Renae Walters is paid a salary of $15,000 per month.
a. How much has she earned for the year after being paid at the end of January? _______________________________
b. How much is deducted in January for Social Security? For Medicare?
Social Security _____________________ Medicare _______________________
c. How much has she earned for the year after being paid at the end of November? ___________________________________
d. How much is deducted in November for Social Security? For Medicare?
Social Security _____________________ Medicare _______________________
e. How much has she earned for the year after being paid at the end of December? ___________________________________
f. How much is deducted in December for Social Security? For Medicare?
Social Security _____________________ Medicare _______________________
The amount for social security for all 3 months will $930 and the contribution for Medicare will be $217.5.
How to estimate the amount for social security for all 3 month?Given that the salary exists paid in US dollars, we can consider that Renae Walters falls under the social security and Medicare tax rates for the United States. These rates, as of 2020, fall at 6.2% for social security and 1.45% for Medicare.
Social security contribution = Social security tax rate × Income earned
January for example Social Security = 0.062 × $15,000 = $930
Medicare contribution = Medicare tax rate × Income earned
January for example Medicare = 0.0145 × $15,000= $217.5
The above method will apply through the months without changes.
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consider the graph of the function f(x)= 10^x what is the range of function g if g(x)= -f(x) -5 ?
SOLUTION
So, from the graph, we are looking for the range of
[tex]\begin{gathered} g(x)=-f(x)-5 \\ where\text{ } \\ f(x)=10^x \\ \end{gathered}[/tex]The graph of g(x) is shown below
[tex]g(x)=-10^x-5[/tex]The range is determined from the y-axis or the y-values. We can see that the y-values is from negative infinity and ends in -5. So the range is between
negative infinity to -5.
So we have
[tex]\begin{gathered} f(x)<-5\text{ or } \\ (-\infty,-5) \end{gathered}[/tex]So, comparing this to the options given, we can see that
The answer is option B
please show and explain this please
only answer ;( c.
Step-by-step explanation:
so hope it help
What is the exact surface area of the right rectangular pyramid below? Leave your answer in simplified radical form.
Usually, to calculate the area of a solid we need to calculate the area of every face. Here we have a rectangle down, and four triangles. Our desired area (TA) will be the sum of those areas. Let's calculate those areas:
Area of the rectangle) The area of the rectangle (R) is
[tex]R=(leng\ldots)(wid\ldots)=(10cm)\cdot(4cm)=40\operatorname{cm}^2[/tex]Area of the front triangle and the back tringle) Note that the front triangle and the back triangle are the "same". So the area of each of them is equal (this simplifies our work...). The area of each of them (FB) is
[tex]FB=\frac{(base)\cdot(high)}{2}[/tex]What is their high?
The triangle with red, blue, and green edges is a right triangle... Its hypotenuse is the blue edge. We know the red edge, its length is 6cm, but what is the length of the green edge? Because our solid is a rectangular pyramid, we can say that the green edge is half of the length of the rectangle. that is, 5cm (10cm/2). Now, we know the red and green edges; so we can apply The Pythagoras theorem to get
[tex](blue)^2=(red)^2+(green)^2[/tex][tex](blue)^2=(6cm)^2+(5cm)2=36\operatorname{cm}+25\operatorname{cm}=61\operatorname{cm}^2[/tex][tex]undefined[/tex]An angle bisector is a ray that divides an angle into two angles with equal measures. If OX bisects ZAOB and mZAOB 142, what is the measure of each of the
angles formed? (Note: Round your answer to one decimal place).
Measure of each of the angles formed between ZAOB is 71° using angle bisector theorem.
What is the angle bisector?In geometry, an angle bisector is a line that divides an angle into two equal angles. The term "bisector" refers to a device that divides an object or a shape into two equal halves. An angle bisector is a ray that divides an angle into two identical segments of the same length.
m(ZAOB)=142°
OX will bisect ZAOB in equal angel both side.
So m(ZAOX) is 71°
And also, m(ZAOB) is 71°
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Complete the description of the piece wise function graphed below
Analyze the different intervals at which the function takes the values provided by the graph. Pay special attention on the circles, whether they are filled up or not.
From the graph, notice that the function takes the value of 3 when x is equal to -4, -2 or any number between them. Therefore, the condition is:
[tex]f(x)=3\text{ if }-4\leq x\leq-2[/tex]If x is greater (but not equal) than -2 and lower or equal to 3, the function takes the value of 5. Therefore:
[tex]f(x)=5\text{ if }-2Notice that the first symbol used is "<" and the second is "≤ ".Finally, the function takes the value of -3 whenever x is greater (but not equal) to 3 and less than or equal to 5. Then:
[tex]f(x)=-3\text{ if }3In conclusion:[tex]f(x)=\mleft\{\begin{aligned}3\text{ if }-4\leq x\leq-2 \\ 5\text{ if }-2Write the equation of this line in point-slope form: The line passes through (−2,22) and (4,-8).
Write the equation of this line in point-slope form: The line passes through (−2,22) and (4,-8).
step 1
Find the slope of the line
m=(-8-22)/(4+2)
m=-30/6
m=-5
step 2
Find the equation in point slope form
y-y1=m(x-x1)
substitute the given values
we have
m=-6
(x1,y1)=(4,-8)
substitute
y+8=-6(x-4)(b) The area of a rectangular painting is 5568 cm².If the width of the painting is 58 cm, what is its length?Length of the painting:
Step 1: Problem
The area of a rectangular painting is 5568 cm².
If the width of the painting is 58 cm, what is its length?
Length of the painting:
Step 2: Concept
Area of a rectangle = Length x Width
Step 3: Method
Given data
Area = 5568 cm square
Width = 58 cm
Length = ?
Area of a rectangle = Length x Width
5568 = 58L
L = 5568/58
L = 96cm
Step 4: Final answer
Length of the painting = 96cm
Lashonda deposits $500 into an account that pays simple interest at a rate of 6% per year. How much interest will she be paid in the first 3 years?
Answer:
The amount of interest she will be paid in the first 3 years is;
[tex]\text{ \$90}[/tex]Explanation:
Given that Lashonda deposits $500 into an account that pays simple interest at a rate of 6% per year. for the first 3 years;
[tex]\begin{gathered} \text{ Principal P = \$500} \\ \text{rate r = 6\% = 0.06} \\ \text{time t = 3 years} \end{gathered}[/tex]Recall the simple interest formula;
[tex]i=P\times r\times t[/tex]substituting the given values;
[tex]\begin{gathered} i=500\times0.06\times3 \\ i=\text{ \$90} \end{gathered}[/tex]Therefore, the amount of interest she will be paid in the first 3 years is;
[tex]\text{ \$90}[/tex]the cake is regular price at $9 and is on sale for 25%. how much would you save with the discount
Let be "x" the amount of money (in dollars) you would save with the discount.
By definition, a percent can be converted to a Decimal number by dividing it by 100. Then, since the cake store is having 25% off sale on all cakes, this can be written as:
[tex]\frac{25}{100}=0.25[/tex]According to the information given in the exercise, the regular price of the cake you want is $9. Based on this, you can set up the following expression for price of the cake with the discount (in dollars):
[tex]9-(9)(0.25)[/tex]Evaluating, you get:
[tex]=6.75[/tex]Knowing this value, you can set up that:
[tex]x=9-6.75[/tex]Finally, evaluating, you get:
[tex]x=2.25[/tex]The answer is: You would save $2.25 with the discount.
Use the following data set to answer the question below.8 12 15 9 101212 18 14 1510 11 12 9 17What is the range for the data set?
Given the following set of data:
8 12 15 9 10 12 12 18 14 15 10 11 12 9 17
We will find the range of the data.
We need to find the maximum and the minimum
The maximum = 18
The minimum = 8
So, the range = maximum - minimum = 18 - 8 = 10
So, the answer will be The range = 10
A special deck of cards has 4 blue cards, and 4 red cards. The blue cards are numbered 1, 2, 3, and 4. The red cards are numbered 1, 2, 3, and 4. The cards are well shuffled and you randomly draw one card.A = card drawn is blueB = card drawn is odd-numbereda) How many elements are there in the sample space? b) P(A) = c) P(B) =
Answer
• a) 8
,• b) 4/8
,• c) 4/8
Explanation
Given
• Blue cards: 4, {B1, B2, B3, B4}
,• Red cards: 4 {R1, R2, R3, R4}
,• A = card drawn is blue
• B = card drawn is odd-numbered {B1, R1, B3, R3}
Procedure
• a) elements in the sample space
There are: S = {B1, B2, B3, B4, R1, R2, R3, R4}
Thus, the number of elements in the sample space is n(S) = 8.
• b) P(A)
Can be calculated as follows:
[tex]P(A)=\frac{n(A)}{n(S)}=\frac{4}{8}[/tex]• c) P(B)
Can be calculated as follows:
[tex]P(B)=\frac{n(B)}{n(S)}=\frac{4}{8}[/tex]Sue wants to plant 545 acres of wheat. She has planted a 128 acre field near the river. Whatpercent of her wheat crop has she planted?
Percentage of the wheat crop planted = 128/ 545 x 100
= 12800/545
= 23.4 percent
In which quadrant is the terminal side of 115° located?+Y43-2+-XX+3 -111841.2IV3.4
ANSWER
Quadrant II
EXPLANATION
• All angles between 0° and 90° are in the first quadrant.
,• All angles between 90° and 180° are in the second quadrant.
,• All angles between 180° and 270° are in the third quadrant.
,• All angles between 270° and 360° are in the fourth quadrant.
115° is an angle measure that is between 90° and 180°. Therefore its terminal end is in the second quadrant.
what is the equation of the line with x-intercept (6,0) and y-intercept (0, 2)
Answer:
3y=6-x
Explanation:
The slope-intercept form of a line is y=mx+b.
First, we determine the slope(m) of the line.
[tex]\begin{gathered} m=\frac{2-0}{0-6} \\ =-\frac{2}{6} \\ m=-\frac{1}{3} \end{gathered}[/tex]Since the y-intercept, b=2
The equation of the line is:
[tex]\begin{gathered} y=-\frac{1}{3}x+2 \\ y=\frac{-x+6}{3} \\ 3y=6-x \end{gathered}[/tex]A local pizza parlor has the following list of toppings available for selection. The parlor is running a special to encourage patrons to try new combinations of toppings. They list all possible three topping pizzas (3 distinct toppings) on individual cards and give away a free pizza every hour to a lucky winner. Find the probability that the first winner randomly selects the card for the pizza topped with spicy italian sausage, banana peppers and beef. Express your answer as a fractionPizza toppings: Green peppers, onions, kalamata olives, sausage, mushrooms, black olives, pepperoni, spicy italian sausage, roma tomatoes, green olives, ham, grilled chicken, jalapeño peppers, banana peppers, beef, chicken fingers, red peppers
First, we need to find out how many possible combinations of pizza toppings there would be.
To do this, we will use the formula for Combination.
Combination is all the possible arrangements of things in which order does not matter. In our example, this would mean that a pizza topped with spicy Italian sausage, banana pepper, and beef is the same as a pizza topped with banana pepper, beef, and Italian sausage.
The formula for combination is
[tex]C(n,r)=^nC_r=_nC_r=\frac{n!}{r!(n-r)!}[/tex]From our given, n would be 17, since there are a total of 17 toppings (including spicy Italian sausage, banana peppers, and beef) and r would be 3 since there are three toppings that you chose.
Substituting it in the formula,
[tex]C(n,r)=\frac{n!}{r!(n-r)!}[/tex][tex]C(17,3)=\frac{17!}{3!(17-3)!}[/tex][tex]C(17,3)=680[/tex]Now, since we know that there are a total of 680 combinations of pizza toppings, we can now solve the probability of the first winner selecting a pizza topped with Italian sausage, banana peppers, and beef.
There are 360° in a circle graph. If 50° of the graph represents rent and 7" of the graph represents savings, what fractional portion of the whole graph is not represented by rent and savings?
The fractional portion of the whole graph is not represented by rent and savings? is 101/120.
How to illustrate the information?From the information, there are 360° in a circle graph and 50° of the graph represents rent and 7" of the graph represents savings.
The part that isn't savings or rent will be:
= 360° - (7° + 50°)
= 360° - 57°
= 303°
Therefore, the fractional part will be:
= Part that isn't savings or rent / Entire degree
= 303/360
= 101 / 120
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A resort rented 62 cabins during its first season in operation. Based on the data for a similar resort, management estimated the equation of the line of best fit for the number cabins rented as y= 4x + 62, where x is the number of seasons since the first season of operation, and y is the number of cabins rented during that season. In reality, unusually bad weather for several years beginning in the first season led to the number of rentals for each season decreasing at the rate they were expected to increase. Which is the best choice for the equation for the line of best fit for the cabin rentals?A) y = 1/4 + 62B) y = - 4x + 62C) y = - 1/4x + 62D) y = 4x - 62
In the equation y = 4x + 62, the increasing rate is 4
If the actual rate decreases at the rate they were expected to increase, then it is -4 instead of 4.
Then, the equation of the line is:
B) y = - 4x + 62
3. Find the value of the function h(x) = 2 when x = 10=
In order to find the value of h(x) when x=10, we replace the value of x along with the function by 10, however, since there are not any variables the function is constant for all variables
[tex]h(10)=2[/tex]find the circumstances of the circle. use 3.14 for pi.
Given:
The radius of the circiel is 4.2 in.
The value of π is 3.14.
The objective is to find the circumference of the circle.
The formula to find the circumference of the circle is,
[tex]\begin{gathered} C=2\cdot\pi\cdot r \\ =2\cdot3.14\cdot4.2 \\ =26.376\text{ inches} \end{gathered}[/tex]Hence, the circumference of the circle is 26.376 inches.
Given a and b are the first-quadrant angles, sin a=5/13, and cos b=3/5, evaluate sin(a+b)1) -33/652) 33/653) 63/65
We know that angles a and b are in the first quadrant. We also know this values:
[tex]\begin{gathered} \sin a=\frac{5}{13} \\ \cos b=\frac{3}{5} \end{gathered}[/tex]We have to find sin(a+b).
We can use the following identity:
[tex]\sin (a+b)=\sin a\cdot\cos b+\cos a\cdot\sin b[/tex]For the second term, we can replace the factors with another identity:
[tex]\sin (a+b)=\sin a\cdot\cos b+\sqrt[]{1-\sin^2a}\cdot\sqrt[]{1-\cos^2b}[/tex]Now we know all the terms from the right side of the equation and we can calculate:
[tex]\begin{gathered} \sin (a+b)=\sin a\cdot\cos b+\sqrt[]{1-\sin^2a}\cdot\sqrt[]{1-\cos^2b} \\ \sin (a+b)=\frac{5}{13}\cdot\frac{3}{5}+\sqrt[]{1-(\frac{5}{13})^2}\cdot\sqrt[]{1-(\frac{3}{5})^2} \\ \sin (a+b)=\frac{15}{65}+\sqrt[]{1-\frac{25}{169}}\cdot\sqrt[]{1-\frac{9}{25}} \\ \sin (a+b)=\frac{15}{65}+\sqrt[]{\frac{169-25}{169}}\cdot\sqrt[]{\frac{25-9}{25}} \\ \sin (a+b)=\frac{15}{65}+\sqrt[]{\frac{144}{169}}\cdot\sqrt[]{\frac{16}{25}} \\ \sin (a+b)=\frac{15}{65}+\frac{12}{13}\cdot\frac{4}{5} \\ \sin (a+b)=\frac{15}{65}+\frac{48}{65} \\ \sin (a+b)=\frac{63}{65} \end{gathered}[/tex]Answer: sin(a+b) = 63/65
For which pair of triangles would you use ASA to prove the congruence of the two triangles?
Solution:
Remember that the Angle-Side-Angle Postulate (ASA) states that if two angles and the included side of one triangle are congruent to two angles and the included side of another triangle, then the two triangles are congruent. According to this, the correct answer is:
C.