The domain can be written as follows:
R - {x = n*12pi or m*4pi | n, m ∈ Z}
where pi = 3.14 and R is the set of real numbers.
What is the domain of the function?Here we want to find the domain of the function:
y = tan(x/8)
The tangent is the quotient between the cosine and the sine, then we will get:
sin(x/8)/cos(x/8)
The problems of the tangent are all the values that make the denominator equal to zero, then we need to remove these.
The zeros are:
cos(x/8) = 0
We know that cos(pi/2) = cos(3pi/2) = 0
Then:
x/8 = pi/2
x = 4pi
x/8 = 3pi/2
x = 12pi
So the domain is the set of all real numbers except the ones in the next set:
{x = n*12pi or m*4pi | n, m ∈ Z}
Where Z is the set of integers.
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n + 8 => 14
what makes it false
6, 8, 22, or 10
Answer:6
Step-by-step explanation: It’s 6 because it’s only greater than, not greater than or equal to
Translate the following verbal statement into an algebraic equation and then solve:
Sara bought a refrigerator on sale for $600, which was three-fifths of the original price. What was the original price of the refrigerator?
Everyone should get 15 points that's how much I'm using i don't know if it's 100% correct.
The box plot that has the smallest interquartile range would be the fourth box plot.
The bar graph that shows Ellen's steps would be B. Second bar graph.
How to find the box plot and bar graph?The interquartile range on a box plot can be found by subtracting the figure where the box starts at, from the figure where the box plot stops.
This means that the figure with the least interquartile range is the fourth box plot with an interquartile range of :
= 8 - 4
= 4
The bar graph that would show Ellen's steps would be the one that has the most steps on the graph, closest to the mean of 10, 000 steps. Only Graph B has steps in the number of days, which are closest to 10, 000 steps consistently so this is the correct graph.
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Sebastian va a elegir el color, el patrón, el tipo de letra y la imagen para el diseño de un suéter para su equipo de danza. Puede escoger entre
10
1010 colores,
4
44 patrones,
12
1212 tipos de letra y
9
99 imágenes. (La imprenta cobra extra para añadir elementos adicionales, así que solo elegirá uno de cada tipo).
Sebastian can choose between 4,320 different sweaters.
How many different sweaters can Sebastian choose?to find the total number of different sweaters, we need to take the product between the numbers of options for each of the given selections, we have the numbers:
Color = 10 options.
Pattern = 4 options.
Letter type = 12 options.
Image = 9 options.
Then the total number of different options is:
D = 10*4*12*9 = 4,320
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Please help me with this for a large reward please someone
The lengths arranged from shortest to longest is [tex]2\frac{7}{8}[/tex], [tex]3\frac{1}{4}[/tex], [tex]3\frac{1}{2}[/tex] , [tex]3\frac{5}{6}[/tex], [tex]4\frac{2}{3}[/tex] (option H).
What is the order of the lengths of the wood?The lengths of the woods are expressed as mixed numbers. Mixed numbers are non-integers that consists of a whole number and a proper fraction. For example, [tex]3\frac{1}{4}[/tex] is a mixed number. 3 is the whole number and [tex]\frac{1}{4}[/tex] is the proper fraction.
In order to arrange the lengths of the woods from shortest to the longest, convert the mixed numbers to decimals for easy comparison.
[tex]3\frac{1}{4}[/tex] becomes 3.25
[tex]2\frac{7}{8}[/tex] becomes 2.875
[tex]3\frac{5}{6}[/tex] becomes 3.833
[tex]4\frac{2}{3}[/tex] becomes 4.667
[tex]3\frac{1}{2}[/tex] becomes 3.5
The lengths arranged from shortest to longest is [tex]2\frac{7}{8}[/tex], [tex]3\frac{1}{4}[/tex], [tex]3\frac{1}{2}[/tex] , [tex]3\frac{5}{6}[/tex], [tex]4\frac{2}{3}[/tex]
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Police body cameras: A survey of New York State residents asked about police officers having to wear video cameras on duty. The question stated, “Do you agree or disagree that police officers should carry video cameras for the purposes of filming their activities while on duty?” Most (88%) respondents agreed with this statement.
Do Californians share the same opinion? A California-based civil rights group conducted a similar survey by randomly selecting 500 California residents, and 425 agreed that police officers should carry video cameras for the purposes of filming their activities while on duty.
Conduct a hypothesis test to determine if the proportion of California residents who agree is different from New York residents. Use a 5% significance level to make your decision. Use the applet (at the top of this Checkpoint) to determine the P‐value.
Which of the following is an appropriate conclusion based on the results?
Group of answer choices
The survey provides strong evidence that the proportion of California residents who agree that police officers should carry video cameras for the purposes of filming their activities while on duty is significantly different from the proportion of New York residents.
The survey suggests that the proportion of California residents who agree that police officers should carry video cameras for the purposes of filming their activities while on duty is 85%.
Of the California residents surveyed, 85% agree that police officers should carry video cameras for the purposes of filming their activities while on duty, but this is not strong enough evidence to conclude that the proportion of California residents who agree is significantly different from the proportion of New York residents.
This survey suggests that 88% of California residents surveyed agree that police officers should carry video cameras for the purposes of filming their activities while on duty.
Based on my experiment, My appropriate conclusion based on the results is option A: The survey provides strong evidence that the proportion of California residents who agree that police officers should carry video cameras for the purposes of filming their activities while on duty is significantly different from the proportion of New York residents.
What was the survey about?This conclusion is based on the truth that the experiment conducted in California found that 85% of the respondents matches with the view, one that is diverse from the extent of Modern York inhabitants (88%) who concurred with the same conclusion .
The "strong evidence" based on the experiment shows that the findings are statistically significant and the conclusion will thus be that the extent of California inhabitants who agree is "essentially wide" from the extent of other York inhabitants, showing some differences between the two populaces.
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PLS ANSWER QUICKLY PLS!!!!!
The annual number of viewers for a new cable television network can be approximated by the expression 49+t • 5-t, where t represents the number of years since its inception. Rewriting this expression will reveal the annual rate of change in viewers.
Which best describes the change in viewers the network is experiencing?
A. Each year, the total number of viewers decreases to approximately 80% of the previous year's total.
B. Each year, the total number of viewers increases to approximately 120% of the previous year's total.
C. Each year, the total number of viewers decreases to approximately 95% of the previous year's total.
D. Each year, the total number of viewers increases to approximately 180% of the previous year's total.
The option that best describes the change in viewers the network is experiencing is B. Each year, the total number of viewers increases to approximately 120% of the previous year's total.
How to explain the dataWhen 't' surpasses 1/ln(5) at 3.5, the expression yields a negative result; connoting the network is witnessing a dwindling viewership.
Consequently, the network initially experiences an intensifying viewership ratio which then fades; in accordance with Option B, "Each year, the total number of viewers increases to roughly 120% of the preceding year's sum". Clearly, this demarcation reveals itself as the accurate answer.
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Please Help Urgent!
Question content area top
Part 1
A certain flight arrives on time percent of the time. Suppose flights are randomly selected. Use the normal approximation to the binomial to approximate the probability that
(a) exactly flights are on time.
(b) at least flights are on time.
(c) fewer than flights are on time.
(d) between and , inclusive are on time.
The probability that exactly 128 flights are on time is 0.0950.
The probability that at least 128 flights are on time is 0.5079.
The probability that fewer than 124 flights are on time is 0.2147.
How to calculate the probabilityIt should be noted that exactly 128 means P(X=128) = P(127.5 < X < 128.5) (By using continues correlation )
At X = 127.5
Z =(127.5-127.6) / 3.91305 = -0.02
At X = 128.5
Z =(128.5-127.6) / 3.91305 = 0.22
P(127.5 < X < 128.5) = P(-0.02 < Z < 0.22)
P(127.5 < X < 128.5) = P(Z < 0.22) - P(Z < -0.02)
P(127.5 < X < 128.5) =0.58706 - 0.49202
P(127.5 < X < 128.5) =0.0950
(b) at least 128 flights are on time.
P(X > 128) = P(X > 127.5) (by using continues correction)
P(X > 127.5) = P(Z > (127.5-127.6)/3.91305)
P(X > 127.5) = P( Z > -0.02)
P(X > 127.5) = 1- P( Z< -0.02)
P(X > 127.5) = 1- 0.49202
P(X > 127.5) = 0.5079
(c) fewer than 124 flights are on time.
P(X < 124 ) =P(X<124.5) (by using continouse correction)
P(X<124.5) = P(Z < (124.5-127.6)/3.91305)
P(X<124.5) = P(Z < -0.79)
P(X<124.5) = 0.2147
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The circle above has a radius of 3 cm. What is the area of the circle?
Answer:
Step-by-step explanation:
Answer:
28.27 CM ^2
Step-by-step explanation:
The formula for area of a circle is pi * r^2 where r = the radius.
Plugging the radius into the formula we get pi3^2, which equals 28.274 cm ^2 (and change)
A financial education time of 34 hours is found to result in an amount of debt of 34215 dollars. What is the predicted amount of debt?
A financial education time of 24 hours is found to result in an amount of debt of 38000 dollars. What is the predicted amount of debt?
The predicted amount of debt for a financial education time of 34 hours is $26,350.
The predicted amount of debt for a financial education time of 24 hours is $31,550.
For the given information, we need to know the regression equation that relates financial education time and amount of debt to predict the amount of debt for different time durations.
Assuming a linear relationship between financial education time and amount of debt, we can estimate the regression equation as:
Amount of Debt = a + b × Financial Education Time + Errorwhere a and b are the intercept and slope of the regression line, respectively, and Error is the random error term.
Using the given data points, we can estimate the regression line as:
Amount of Debt = 41500 - 450 × Financial Education Time(a) For a financial education time of 34 hours:
Amount of Debt = 41500 - 450 × 34 = $26,350Therefore, the predicted amount of debt for a financial education time of 34 hours is $26,350.
(b) For a financial education time of 24 hours:
Amount of Debt = 41500 - 450 × 24 = $31,550Therefore, the predicted amount of debt for a financial education time of 24 hours is $31,550.
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What is the probability that the total team time in the
400-meter freestyle relay is less than 215 seconds?
O 0.056
O 0.1665
O 0.8335
0.944
The probability that the total team time in the 400-meter freestyle relay is less than 215 seconds is: 0.8345
How to find the probability from z-score?From the table given the mean and standard deviation, we can say that:
Total time spent = 54.2 + 57 + 55.3 + 53.7
Total time spent = 220.2 secs
The total standard deviation is:
2.8 + 3 + 2.4 + 2.5 = 10.7 secs
Formula for z-score here is:
z = (x' - μ)/(σ/√n)
where:
x' is sample mean
μ is population mean
σ is standard deviation
n is sample size
Thus:
z = (220.2 - 215)/(10.7/√4)
z = 0.972
From online p-value from z-score calculator, we have:
p(x < 0.972) = 0.8345
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Answer: b
Step-by-step explanation: cause i just did it
HELP ME PLEASE WILL 5 STAR
Answer:
85.84
Step-by-step explanation:
6x4 is the area of 1 rectangle
There r 3 rectangles
6x4 =24
24x3 =72
That’s the area if all the rectangles
There r 2 triangles
(4x3.46)/2 is the area of 1 triangle
=6.92
6.92x2 =13.84
total surface area is all the areas added up
72+13.84
=85.84
what is the mass per running metre of a copper bar with a uniform cross-section in the form of a triangle as shown in the figure? the density of copper is 8 850 kg/m³.
The mass per running metre of a copper bar with a uniform cross-section in the form of a triangle as shown in the figure when the density of copper is 8 850 kg/m³ is 3.
How to calculate the valueMass per running meter = density x area x length
Substituting the values for density, area, and length, you get:
Mass per running meter = 8,850 x [(b x h) / 2] x length
Simplifying the equation, you get:
Mass per running meter = 4,425 x b x h x length
Mass = 8850 / 4425
Mass = 2
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please help solve for x 36 x 4 set up the proportion x/4=? image attached
The equation of proportion will be x/4 = 36/x. Then the value of 'x' will be 12 units.
According to the hypotenuse-leg (HL) principle, a right triangle is harmonious if each of its third side and legs are congruent with its equivalent hypotenuse and legs in another right triangle. The HL theorem proves that these triangles are identical.
The equation is given as,
x/4 = 36/x
Simplify the equation, then we have
x/4 = 36/x
x² = 2² × 6²
x = 2 × 6
x = 12
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Question 1 نت You are interested in constructing a 99% confidence interval for the proportion of all caterpillars that eventually become butterflies. Of the 369 randomly selected caterpillars observed, 45 lived to become butterflies. Round answers to 4 decimal places where possible. a. With 99% confidence the proportion of all caterpillars that lived to become a butterfly is between and b. If many groups of 369 randomly selected caterpillars were observed, then a different confidence interval would be produced from each group. About percent of these confidence intervals will contain the true population proportion of caterpillars that become butterflies and about percent will not contain the true population proportion. Hint: Hints Video [+]
a) The 99% confidence interval for the proportion of all caterpillars that lived to become a butterfly is between 0.078 and 0.166.
b) About 99% of these confidence intervals will contain the true population proportion of caterpillars that become butterflies and about percent will not contain the true population proportion.
What is a confidence interval of proportions?A confidence interval of proportions has the bounds given by the rule presented as follows:
[tex]\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]
In which the variables used to calculated these bounds are listed as follows:
[tex]\pi[/tex] is the sample proportion, which is also the estimate of the parameter.z is the critical value.n is the sample size.The confidence level is of 99%, hence the critical value z is the value of Z that has a p-value of [tex]\frac{1+0.99}{2} = 0.995[/tex], so the critical value is z = 2.575.
The sample size and the estimate for this problem are given as follows:
[tex]n = 369, \pi = \frac{45}{369} = 0.122[/tex]
The lower bound of the interval is given as follows:
0.122 - 2.575 x sqrt(0.122 x 0.878/369) = 0.078.
The upper bound of the interval is given as follows:
0.122 + 2.575 x sqrt(0.122 x 0.878/369) = 0.166.
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If a =5 and b = 9, what is the following fraction in lowest terms? a+1/b
Answer:
2/3
Step-by-step explanation:
since a is 5 and b is 9.
so, 5+1( according to the expression given)/9
5+1/9 equals 6/9 and taking them down to the lowest terms that makes the answer 2/3
A wooden block measures 2cm by 5cm by 10cm and has a density of 18.2 g/ cm3. What is the mass?
Find the missing side of the triangle . leave your answer in simplest radical form
Answer: B: [tex]\sqrt{65}[/tex]
Step-by-step explanation:
The figure indicates this is a right triangle. As such, we can use the pythagorean theorem:
a^2 + b^2 = c^2
16 + 49 = x^2
sqrt(65) = x
.: x = [tex]\sqrt{65}[/tex]
The line plots show the history and mathematics grades for 20 students. What is
the degree of overlap of the two data sets?
The degree of overlap between the two data sets is said to be high degree of overlap
what is degree of overlap of data?Data overlap is a statistical term that analyzes the extent to which data points or distributions intersect.
It is often employed when comparing two or more datasets, determining how similar or dissimilar they are from each other.
A high degree of overlapping indicates an extensive similarity among shared values between multiple sets of data or distributions. Conversely, if there is a low level of overlapping observed between two datasets, it suggests complete distinctness and no sharing of common quantitative baseline measurements or metrics.
The domain of the overlap according to the plot is [55 85]
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F
G
H
J
If the diameter of a circle is 16 cm and the
intercepted arc length is 6m, what is the
measure of the central angle in radians?
3
8
3
7T
3
T
3²7
The measure of the central angle is 0.75 radians
How to solve an equation?An equation is an expression that can be used to show the relationship between two or more numbers and variables using mathematical operators.
The area of a figure is the amount of space it occupies in its two dimensional state.
The length of an arc with an angle of Ф is given by:
Length of arc = (Ф/360) * (π * diameter)
The diameter is 16 cm and intercepted arc length is 6 cm, hence:
Length of arc = (Ф/360) * (π * diameter)
6 = (Ф/360) * (π * 16)
Ф = 42.97°
Ф = 42.97° * π/180 = 0.75 radian
The measure of the central angle is 0.75 radians
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Rewrite the logarithmic equation below as an equivalent exponential equation.
log3(N) = x
[tex]\textit{exponential form of a logarithm} \\\\ \log_a(b)=y \qquad \implies \qquad a^y= b \\\\[-0.35em] ~\dotfill\\\\ \log_3(N)=x\implies 3^x=N[/tex]
Please help !!!!!!!!!!!!
Answer:
C
Step-by-step explanation:
It does not belong because like the other ones it is not side ways, as well as it's common sense.
given u= (-10,-3) and v= (4,8) , what is proj vu
If u= (-10,-3) and v= (4,8) . Proj vu is is (640/109, 192/109).
What is the projection of v onto u?Using this formula to determine the projection of v onto u (proj vu)
proj vu = ((v dot u) / (||u||)^2) × u
Where:
v dot u = dot product of v and u
||u|| = magnitude of u
First step is to find the dot product of v and u:
v dot u = (-104) + (-38)
v dot u = -40 - 24
v dot u = -64
Second step to to calculate the magnitude of u:
||u|| = √((-10)^2 + (-3)^2)
||u|| = √(100 + 9)
||u|| = √(109)
Let plug in the formula
proj vu = ((-64) / (√(109))^2)× (-10,-3)
proj vu = (-64 / 109) × (-10,-3)
proj vu = (640/109, 192/109)
Therefore the correct option is A.
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Two containers designed to hold water are side by side, both in the shape of a cylinder. Container A has a diameter of 32 feet and a height of 16 feet. Container B has a diameter of 30 feet and a height of 18 feet. Container A is full of water and the water is pumped into Container B until Container B is completely full. After the pumping is complete, what is the volume of water remaining in Container A, to the nearest tenth of a cubic foot?
The volume of a cylinder can be found using the formula V = πr^2h, where V is the volume, r is the radius, and h is the height.
For Container A, the radius is half the diameter, or 16 feet. So the volume of Container A is:
V_A = π(16 ft)^2(16 ft) = 8,192π cubic feet
For Container B, the radius is half the diameter, or 15 feet. So the volume of Container B is:
V_B = π(15 ft)^2(18 ft) = 12,735π cubic feet
To find the volume of water that was transferred from Container A to Container B, we can subtract the volume of Container A from the volume of both containers combined:
V_water = V_A + V_B - V_A = V_B
V_water = 12,735π cubic feet
To find the volume of water remaining in Container A, we can subtract the volume of water that was transferred from the volume of Container A:
V_remaining = V_A - V_water
V_remaining = 8,192π - 12,735π
V_remaining ≈ -3,543.7 cubic feet
However, a negative volume doesn't make sense in this context, so we know that there must be no water remaining in Container A after the transfer. Therefore, the volume of water remaining in Container A to the nearest tenth of a cubic foot is 0.
Triangle A’B’C’ is a dilation of triangle ABC with a center of dilation at point D. What is the scale factor of this dilation?
Work Shown:
(A'C')/(AC) = 12/5 = 2.4
or you could say
(B'C')/(BC) = 16.8/7 = 2.4
or
(A'B')/(AB) = 9.6/4 = 2.4
The sides of triangle A'B'C' are 2.4 times longer compared to the corresponding sides of triangle ABC.
Solve the following for θ, in radians, where 0≤θ<2π.
4sin2(θ)−7sin(θ)−4=0
Select all that apply:
0.4
3.61
1.66
5.81
1.4
3.07
Answer:
3.615.81Step-by-step explanation:
You want solutions to the equation 4sin(θ)² -7sin(θ) -4 = 0 on the interval [0, 2π].
GraphA graph of the left-side expression shows it has a value of 0 at ...
θ ≈ 3.61 or 5.81.
CheckUsing a calculator to check the offered answer choices, we find the values of θ that best satisfy the equation are θ = 3.61 or 5.81. (For this purpose, ±0.02 ≈ 0.)
Algebraic solutionWe can let x = sin(θ). Then the equation is ...
4x² -7x -4 = 0
x² -7/4x = 1
(x -7/8)² = 1 +(7/8)² = 113/64
x = (7 ±√113)/8
The value (7+√113)/8 is greater than 1, so the only value of x that is useful here is x = (7-√113)/8. The angles in the desired range are ...
{π - arcsin((7 -√113)/8), 2π +arcsin((7 -√113)/8)} ≈ {3.61, 5.81} . . . radians
Question 1(Multiple Choice Worth 2 points) (Theoretical Probability MC) When rolling a 6-sided die twice, determine P(sum of 4). 1. 3/36 2. 5/36 3 8/36 4. 2/6
Answer:
5/36
Step-by-step explanation:
hope this helps
In a large clinical trial, 395,487 children were randomly assigned to two groups. The treatment group consisted of 198,610 children given a vaccine for a certain disease, and 27 of those children
developed the disease. The other 196,877 children were given a placebo, and 104 of those children developed the disease. Consider the vaccine treatment group to be the first sample. Identify the
values of n₁. P. 9₁. ₂. P₂. Q2. P, and q
Answer:
n₁ = 198,610
P₁ = 27/198,610
n₂ = 196,877
P₂ = 104/196,877
q₁ = 1 - P₁
q₂ = 1 - P₂
Step-by-step explanation:
The list represents the number of students who checked books out of the library in a 10-day period.
48, 63, 75, 40, 32, 52, 35, 68, 83, 40
Find the median and interpret its meaning as it relates to the number of students checking out books.
A. The median is 32, and it represents the difference in the lowest and highest number of students who checked books out.
B. The median is 83, and it represents the highest number of students who checked books out.
C. The median is 40, and it represents the most common number of books that students checked out.
D. The median is 50, and it represents the typical number of students who checked books out.
The median number of students who checked books out of the library in a 10-day period is 50.
We have,
To find the median of the list, we need to first put the numbers in order from least to greatest:
32, 35, 40, 40, 48, 52, 63, 68, 75, 83
The median is the middle value in the list.
If there is an odd number of values, the median is the middle value.
If there is an even number of values, the median is the average of the two middle values.
There are 10 values, which is an even number.
The middle values are 48 and 52.
Median = (48 + 52) / 2
Median = 50
So the median number of students who checked books out of the library in a 10-day period is 50.
Interpretation:
The median represents the middle value in the list, which in this case is 50.
This means that half of the values in the list are greater than 50, and half of the values are less than 50.
In terms of the number of students checking out books, this means that 50 is the typical number of students who checked books out of the library during the 10-day period.
Thus,
The median number of students who checked books out of the library in a 10-day period is 50.
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Round each measurement to the nearest ten. Then estimate the area of the rectangle. 48 Inches 82 inches 4, 500 square inches. O 260 square inches O3,200 square inches. O 4,000 square inches. O
The solution is, : the area of the rectangle is 4000 sq inches.
Here, we have,
A rectangle is given with sides 82 and 48 inches
We have to round off these dimensions to the nearest 10.
82 inches ~80 inches
since 2 <5, we make it 0
Similarly 48 inches ~50 inches since 8>5
Now area
= length x width
=80(50)
=4000 square inches
Hence, the area of the rectangle is 4000 sq inches is correct answer.
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