What is the density of hydrogen sulfide (H2S) at 0.2 atm and 311 K?Answer in units of g/L

Answers

Answer 1

Answer

Density = 0.267 g/L

Explanation

Given:

Pressure of H2S = 0.2 atm

Temperature = 311 K

We know:

The molar mass of H2S = 34,1 g/mol

R constant = 0.08206 L.atm/K.mol

Solution:

From the ideal gas law:

PV = nRT

We know that:

density = m/V

n = m/M

Therefore we can use the following equation to solve for density of H2S

[tex]\begin{gathered} density\text{ = }\frac{PM}{RT} \\ density\text{ = }\frac{(0.2\text{ atm x 34,1 g/mol\rparen}}{(0.08206\text{ }L.atm/K.mol\text{ x 311 K\rparen}} \\ \\ density\text{ = 0.267 g/L} \end{gathered}[/tex]


Related Questions

Some hydrogen and iodine are mixed at 229 degrees Celsius in a 1.00L container. When equilibrium is established, the following concentrations are present: [HI] = 0.490 M, [H2] = 0.080 M, [I2] = 0.060 M. If an additional 0.300 mol of HI is then added, what concentration will be present when the new equilibrium is established?

Answers

The concertation of the HI that would be present in the new equilibrium position is 0.15 M.

What is the new equilibrium position?

We have to first obtain the equilibrium constant that we have under the initial conditions and then we have; H2 + I2 ------> 2HI

K = [HI]^2/[H2] [I2]

K = (0.490)^2/(0.080) (0.060)

K = 0.2401/(0.080) (0.060)

K = 50

Again;

                               H2      +      I2                     ------> 2HI

Initial                     0.080           0.060                        0.060

concentration         +x                   +x                            -2x

Equilibrium     0.080 + x      0.060 + x                 0.490 - 2x

50 = (0.490 - 2x)^2/( 0.080 + x) (0.060 + x)

Working through the quadratic we have;

46x^2 + 10.2 x - 0.38 = 0

x = 0.32 M

In each case we now have;

 H2 =  0.080 +  0.32  = 0.4 M

[I2] = 0.060  +  0.32  = 0.38 M

[HI] = 0.790 - 2( 0.32 ) = 0.15 M

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Using 0.082 as your R value, what mass of NaN3 is required to produce 10L of N2 gas, at 273K and 1.5atm. Show all your work completely.Use the following formula to guide your work: 2NaN3 -> 2Na + 3 N2

Answers

To solve this question, we need to use the Clapeyron formula.

Clapeyron's formula is a mathematical expression that relates quantities such as pressure (P), volume (V), temperature (T) and the number of particles (n) that make up an ideal gas.

The formula is: PV = nRT

First, let's discover the number in moles of N2. We have:

P = 1.5 atm

V = 10 L

n = ???

R = 0.082 atm.L/mol.k

T = 273 K

1.5 x 10 = n x 0.082 x 273

15 = n x 22.386

n = 15/22.386

n = 0.67 moles

As we can see in the chemical reaction equation, the ratio between NaN3 and N2 is 2:3.

So:

2 mol of NaN3 --- 3 mol of N2

x mol of NaN2 --- 0.67 moles

3x = 2 x 0.67

x = 0.45 moles of NaN3

Now we transform this value into grams, using NaN3 formula mass, which is 65 g/mol:

65 g ---- 1 mol

x g ---- 0.45 mol

x = 29 g

Answer: 29 g of NaN3

How many electrons can have the quantum numbers n = 3, l = 2, ml = -2 ?
1
2
5
10

Answers

There are only two electrons that could posses the quantum numbers as shown.

What are quantum numbers?

We now that it is often common to seek to describe the probability of finding the electrons in the atom. While it is know that the electron is not a given point in the atom. The probability of finding the electron in the atom is given by the help of the quantum numbers that can be used to describe the position of the electron as shown.

In tis case, we have an electron that has the quantum numbers; n = 3, l = 2, ml = -2. This describes an orbital and there are two electrons in a given orbital.

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Place these Types of Decay in Order from the LOWEST Energy to the HIGHEST energy.

Answers

Answer:

[tex]\begin{gathered} Alpha\text{ Decay} \\ Beta\text{ Decay} \\ Gamma\text{ Decay} \end{gathered}[/tex]

Explanation:

Here, we want to order the radiations in terms of energy

There is a proportional relationship between the mass and the energy

It is established that the radiation with a higher mass would have the lesser energy

Alpha decay has the highest mass and thus, the lowest energy. This is followed by beta decay, and finally, gamma decay

For an aqueous solution with a H+ concentration of 1.0 × 10−12 M, calculate the concentration of OH−.

Answers

Taking into account the definition of pH and pOH, the concentration of OH⁻ is 1×10⁻² M.

Definition of pH

pH is a measure of acidity or alkalinity that indicates the amount of hydrogen ions present in a solution or substance.

The pH is defined as the negative base 10 logarithm of the activity of hydrogen ions:

pH= - log [H⁺]

Definition of pOH

Similarly, pOH is a measure of hydroxyl ions in a solution and is expressed as the logarithm of the concentration of OH⁻ ions, with the sign changed:

pOH= - log [OH⁻]

Relationship between pH and pOH

The following relationship can be established between pH and pOH:

pOH + pH= 14

Concentration of OH⁻

Being [H⁺]=1.0×10⁻¹² M, the pH is calculated as:

pH= - log (1.0×10⁻¹² M)

Solving:

pH= 12

Being pH= 4.85, and considering the relationship between pH and pOH, pOH is calculated as:

pOH + 12= 14

pOH= 14 - 12

pOH= 2

Replacing in the definition of pOH the concentration of OH⁻ ions is obtained:

- log [OH⁻]= 2

Solving

[OH⁻]= 10⁻²

[OH⁻]= 1×10⁻² M

In summary, the [OH⁻] is 1×10⁻² M.

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Fe2O3 + 3H2 = 2Fe + 3H2OCalculate how many grams of iron can be made from 24.5 grams of iron (III) oxide.

Answers

Explanation:

Iron (III) oxide will react with hydrogen gas to produce iron and water. They will react according to the following equation.

Fe₂O₃ + 3 H₂ -----> 2 Fe + 3 H₂O

We have to find the grams of Fe that can be made from 24.5 g of Fe₂O₃. So, first we have to convert those grams into moles using the molar mass of iron (III) oxide.

molar mass of Fe₂O₃ = 159.69 g/mol

mass of Fe₂O₃ = 24.5 g

moles of Fe₂O₃ = 24.5 g * 1 mol/(159.69 g)

moles of Fe₂O₃ = 0.153 mol

Fe₂O₃ + 3 H₂ -----> 2 Fe + 3 H₂O

According to the coefficients of the equation, we know that 1 mol of Fe₂O₃ will react with 3 moles of H₂ to give 2 moles of Fe and 3 moles of H₂O. So the molar ratio between Fe₂O₃ and Fe is 1 to 2. We can use that relationship to find the number of moles of Fe that can be made from 0.153 moles of Fe₂O₃.

1 mol of Fe₂O₃ : 2 moles of Fe molar ratio

moles of Fe = 0.153 moles of Fe₂O₃ * 2 moles of Fe/(1 mol of Fe₂O₃)

moles of Fe = 0.306 moles

So we found that we can produce 0.306 moles of Fe from 0.153 moles of Fe₂O₃ or 24.5 g of it. Finally we can convert the 0.306 moles of Fe into grams using the molar mass of Fe.

molar mass of Fe = 55.85 g/mol

mass of Fe = 0.306 moles * 55.85 g/mol

mass of Fe = 17.1 g

Answer: 17.1 g of iron can be made from 24.5 g of iron (III) oxide.

Which choice is an element?
carbon dioxide
carbon
water
air

Answers

carbon dioxide and water

Answer:

Explanation:

Carbon is the only element listed. Carbon Dioxide consists of Carbon AND Oxygen x2 so this is a compound. As stated earlier, air is a mixture of compounds. Water is another compound consisting of Hydrogen x2 and Oxygen.

2.65 moles of an ideal gas at 36.9oC and 40,205Pa occupy 54.7mL. Additional gas is added to this container such that the temperature and pressure change to 113.7oC and 131,874Pa, with the volume remaining the same. How many moles of this gas were added?


Answers

The moles of gas added could not be determined because of an apparent error in the data provided for the volume of the container.

What is the number of moles of gas in the container?

The moles of gas in the container is calculated from the ideal gas equation as follows;

PV = nRTn = PV / RT

Data given:

P = 131,874 Pa or 131.874 kPa

V = 54.7 mL = 0.0547 L

T = 113.7 °C or (113.7 + 273) K

T = 386.7 K

R, molar gas constant  = 8.314 L⋅kPa.K/mol

n = (131.874 * 0.0547 L) / (8.314 * 386.7 )

n = 0.000224 moles

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How many moles of sulfur dioxide in 85 grams sulfur dioxide?

Answers

Answer:

1.33 moles

Explanation:

[tex]n = \frac{mass}{molar \: mass} [/tex]

note Molar Mass according to websearch is 64 066

you could calculate this using the individual elements on a periodic table (sulfur and oxygen) and their masses

[tex]n = \frac{85}{64.066} [/tex]

[tex]n = 1.33[/tex]

500 ml of an unknown concentration of KOH solution and 250 ml of 0.01 ml were mixed KOH solution.
The pH of the resulting solution is 12.7. Calculate the concentration of the first KOH solution.

Answers

Answer:

262

Explanation:

using a graduated cylinder and a becker write the detailed steps to measure the volume of a piece of rock

Answers

The detailed steps to measure the volume of a piece of rock using a graduated cylinder and beaker are based on Archimedes' Principle, which states that an object that is displacing fluid has a weight equal to that of the object it is displacing.

Step 1: In order to calculate a stone's volume, we first add water to the graduated cylinder until the stone is fully submerged. Step 2: Following the insertion of the stone into the cylinder, the initial reading, or baseline reading, must now be recorded. Step 3: The last reading of the cylinder needs to be recorded after the stone has been fully immersed. Step 4: We can calculate the stone's millilitre capacity by comparing the cylinder's results. If necessary, this value can be changed to another unit of measurement.

The submersion or dunking method is another name for the displacement method.

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Limestone is a sedimentary rock composed largely of the mineral calcite, (calcium carbonate) CaCO3. To test the purity of the calcium carbonate, a sample of the mineral is reacted with hydrochloric acid to produce calcium chloride, carbon dioxide and water If a 15.70 g sample of calcite is reacted with excess hydrochloric acid and 16.89 g of calcium chloride are produced, what is the percent by mass of the calcium carbonate in the limestone? A) 69.4% B)93.0 % C) 96.94% D)98,22 %

Answers

Answer:

[tex]C\text{ : 96.94 \%}[/tex]

Explanation:

Here, we want to get the percentage by mass of calcium carbonate in the limestone

We start by writing an equation of chemical reaction

The reaction involves calcium carbonate reacting with hydrochloric acid to give calcium chloride, carbon dioxide and water

We have the equation as follows:

[tex]\text{CaCO}_{3(s)\text{ }}+2HCl_{(aq)}\rightarrow CaCl_{2(aq)\text{ }}+CO_{2(g)\text{ }}+H_2O_{(l)}[/tex]

Now, let us work with the extra information

16.89 g of calcium chloride are produced

Let us get the number of moles of calcium chloride produced

We can get that by dividing the mass by the molar mass of calcium chloride

The molar mass of calcium chloride is 111 g/mol

So, the number of moles will be:

[tex]\frac{16.89}{111}\text{ = 0.1522 mole}[/tex]

From the equation,

1 mole of calcite gave 1 mole of calcium chloride, then 0.1522 mole of calcium chloride was produced by 0.1522 mole of calcite

To get the mass of calcite that produced this, we have to multipply the number of moles by the molar mass of calcite

The molar mass of calcite is 100 g/mol

That means the mass of calcite that produced the calcium chloride will be:

[tex]0.1522\text{ }\times\text{ 100 = 15.22 g}[/tex]

What this mean is that 15.22 g of calcite produced the given mass of calcium chloride

The percentage by mass of calcite in the limestone will be:

[tex]\frac{15.22}{15.70}\times\text{ 100\% = 96.94 \%}[/tex]

How do you solve the decomposition of aluminum oxide?

Answers

Aluminum Oxide decomposes to Aluminum metal and Oxygen gas.

- First, write down each compound:

[tex]Al_2O_3\longrightarrow Al+O_2[/tex]

- Second, write the number of moles of each compound, so that we have the same amount of reactants as products. Here, it is important not to change the subscript of compound elements.

For example, let's start by adding a number 2 in front of the aluminum metal to balance:

[tex]Al_2O_3\text{ }\rightarrow2Al+O_2[/tex]

So far, the amount of aluminum has been balanced but the amount of oxygen is unbalanced, so let's add a number 3 for the oxygen gas.

[tex]Al_2O_3\text{ }\rightarrow2Al+3O_2\text{ }[/tex]

Now, to have the same amount of moles of oxygen on both sides, let's put a number 2 in the aluminum oxide:

[tex]2Al_2O_3\text{ }\rightarrow2Al+3O_2[/tex]

Here, the amount of aluminum moles is unbalanced, so we add a number 4 for the aluminum metal to balance:

[tex]2Al_2O_3\text{ }\rightarrow4Al+3O_2[/tex]

- This is the final balanced equation of decomposition of aluminum oxide:

[tex]\begin{gathered} 2Al_2O_3\text{ }\rightarrow4Al+3O_2 \\ \end{gathered}[/tex]

A chemical reaction has the equation 2AgNO3 (aq) + Zn (s) → 2Ag (s) + Zn(NO3)2 (aq). What type of reaction occurs between AgNO3 and Zn?Question 17 options:A) Single displacementB) DecompositionC) SynthesisD) Double displacement

Answers

Combination (also called synthesis): Where two elements or one compound and one element will bond and form a new compound as a product, the representation for this reaction is:

A + B -> AB

Decomposition: The opposite from Combination, now one compound will decompose and form 2 new elements or compounds as the product:

AB -> A + B

Single Replacement: One element will take the place of another element in already existing compound:

A + BC -> AB + C

Double Replacement: Now we have two compounds switching elements and forming two new compounds:

AB + CD -> AC + BD

Combustion: Reactions that involve oxygen as reactant and we have CO2 and H2O as products:

X + O2 -> CO2 + H2O

According to the explanation, what we have in this reaction is a Single Displacement reaction, letter A

How many pounds in 16.1lbmol of pure HCl

Answers

Answer:

586.846 lbs

Explanation:

the molar mass of HCl is 1 + 35.45 = 36.45

this means you can do 16.1 lbmol * 36.45 lb/lbmol = 586.845

How many moles of atoms are in 7 g of 13C

Answers

Answer:

Explanation:

molar mass of 13c = 13 grams

number of moles = mass / molar mass

therefore,

number of moles = 7 / 13

To know the number of atoms in 7/13 moles, we simply multiply the number of moles by Avogadro's number as follows:

number of atoms = (7/13) x 6.022 x 10^23 = 3.2426 x 10^23 atoms

Given the following, find the number of grams 0.3672 moles SmO

Answers

Answer:

61.09 grams SmO

Explanation:

To find the number of grams SmO, you need to multiply the moles by the molar mass of SmO. The molar mass is a ratio which represents the mass of SmO per every 1 mole. It is important to arrange the ratio in a way that allows for the cancellation of units (moles should be in the denominator). The final answer should have 4 sig figs like the given value (0.3672 = 4 sig figs).

Atomic Mass (Sm): 150.36 g/mol

Atomic Mass (O): 15.999 g/mol

Molar Mass (SmO): 150.36 g/mol + 15.999 g/mol

Molar Mass (SmO): 166.359 g/mol

 0.3672 moles SmO           166.359 grams
--------------------------------  x  --------------------------  =  61.09 grams SmO
                                                   1 mole

61.89 moles SmO
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What is the pH of a solution in which 15 mL of 0.10 M NaOH is added to 25 mL of 0.10 M HCl?

Answers

Answer:

The pH of the solution is 1.60.

Explanation:

1st) It is necessary to write and balance the chemical reaction:

[tex]NaOH+HCl\rightarrow NaCl+H_2O[/tex]

Now we can see that 1 mole of NaOH reacts with 1 mole of HCl.

2nd) We have to calculate the moles contained in 15mL of 0.10M NaOH solution and the moles contained in 25mL of 0.10M HCl solution:

• Moles contained in NaOH solution:

[tex]\begin{gathered} 1000mL-0.10moles \\ 15mL-x=\frac{15mL*0.10moles}{1000mL} \\ x=1.5*10^{-3}moles \end{gathered}[/tex]

• Moles contained in HCl solution:

[tex]\begin{gathered} 1000mL-0.10moles \\ 25mL-x=\frac{25mL*0.10moles}{1000mL} \\ x=2.5x10^{-3}moles \end{gathered}[/tex]

Now we know that there are 1.5x10^-3 moles of NaOH and 2.5x10^-3 moles of HCl.

3rd) According to the stoichiometry of the reaction, 1 mole of NaOH reacts with 1 mole of HCl, so in this case, 1.5x10^-3 moles of NaOH will react with 1.5x10^-3 moles of HCl, because NaOH will be the limiting reactant and HCl will be the excess reactant.

So, now we have to calculate the excess of HCl:

2.5x10^-3moles - 1.5x10^-3moles = 1x10^-3moles

Now we know that there are 1x10^-3 moles of HCl left.

4th) Excess HCl will remain dissociated into H+ and Cl-, according to the following equation:

[tex]HCl\rightarrow H^++Cl^-[/tex]

That means that for every mole of HCl, 1H+ dissociates. So, in this case, there are 1x10^-3 moles of H+.

Remember that these moles are contained in 40mL, so the molarity of H+ is 0.025M:

[tex]\begin{gathered} 40mL-1x10^{-3}moles \\ 1000mL-x=\frac{1000mL*1x10^{-3}moles}{40mL} \\ x=0.025moles \end{gathered}[/tex]

5th) Finally, we can calculate the pH of the solution, by replacing the H+ concentration in the pH formula:

[tex]\begin{gathered} pH=-log\lbrack H^+\rbrack \\ pH=-log\lbrack0.025\rbrack \\ pH=1.60 \end{gathered}[/tex]

So, the pH of the solution is 1.60.

What are the products of the neutralization reaction between HNO3 andCa(OH)2?OA. CaO, NO₂, and H₂OB. Ca3N₂ and H₂OOC. Ca(NO3)2 and H₂OOD. CaNO3 and H30+

Answers

Answer:

Ca(NO3)2 and H₂O. Option C is correct

Explanations:What is a neutralization reaction?

The combination of acid and base to form salt and water at the product is known as a neutralization reaction.

Hence the products of the neutralization reaction between HNO3 and Ca(OH)2 must be salt and water

From the given option, the equivalent product that are salt and water is Ca(NO3)2 and H₂O which gives the required product.

_Ca +_AlCl3 --> _CaCl2 + _AIWhen the reaction is balanced, what is the coefficient in front of the Al? Answer options 2, 4, 1, 3

Answers

To balance the given equation remember to start by the elements that are different from oxygen and hydrogen, in this case, let's start by chlorine:

As chlorine in AlCl3 is 3 times and in CaCl2 is 2 times, we have to write a 2 in AlCl3 and a 3 in CaCl2, with this coefficients we will have 6 chlorines in total at each side of the equation.

Then, as we put that 2 in front of AlCl3, we will also have 2 aluminium. After the reaction we have only one aluminium, it means that we need to write 2 in front of Al to balance the number of aluminium in the equation.

The correct option is 2.

Light below the necessary critical frequency doesn't eject electrons from metal because

Answers

Light below the necessary critical frequency doesn't eject electrons from metal because no electrons will be emitted when the light shines on the metal.

What is Frequency?

This is a term in physics which is used to describe the number of occurrences of a repeating event per unit of time.

The amount of energy which is present in each photon in the beam is determined by and proportional to the frequency of the beam. This therefore means that if there is light which is below the threshold frequency, there will be no electrons emitted when light shines on the metal thereby making it the correct choice.

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NaCl + _Cal2 → Nal + CaCI2

Answers

Answer

2NaCl + Cal₂ → 2Nal + CaCI₂

Explanation

Given unbalanced equation;

NaCl + _Cal₂ → Nal + CaCI₂

Step 1: Balance the Cl atom on both the reactant and product sides of the equation by putting 2 as the coefficient of NaCl in the reactant side.

2NaCl + _Cal₂ → Nal + CaCI₂

Step 2: Balance the Na atom on both the reactant and product sides of the equation by putting 2 as the coefficient of NaI in the product side.

2NaCl + Cal₂ → 2Nal + CaCI₂

Therefore, the balanced equation is: 2NaCl + Cal₂ → 2Nal + CaCI₂

Calculate the wavelength and energy of light that has a frequency of 1.1 * 10^17 Hz

Answers

The wavelength and the energy would be 2.72 × 10⁻⁹  meter 6.886 × 10⁻¹⁷ Joules and respectively if the light has s a frequency of 1.1 × 10¹⁷ Hz.

What is Wavelength?

It can be understood in terms of the distance between any two similar successive points across any wave.

C = λν

As given in the problem we have to calculate the energy of the light if the frequency of light is  1.1 × 10¹⁷ Hz

The wavelength of the light = 3 × 10⁸ / 1.1 × 10¹⁷

                                               = 2.72 × 10⁻⁹  meter

The energy of the light = h ν

                                       = 6.26 × 10⁻³⁴ × 1.1 × 10¹⁷

                                        = 6.886 × 10⁻¹⁷ Joules

Thus, the wavelength and the energy would be 2.72 × 10⁻⁹  meter 6.886 × 10⁻¹⁷ Joules and respectively if the light has s a frequency of 1.1 × 10¹⁷ Hz.

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How is percent composition related to alkene stability?

Answers

The stability of alkene can be determined by measuring the amount of energy that is associated with the hydrogenation of the molecule.

What is alkene stability?

Because those branched alkanes are more stable than their linear isomers (Figure 1), the origins of this stability are unclear. For each branch in an alkane, the measured heat of formation is lower than expected by about 2 kcal mol−1 in comparison to the linear isomer. The fullness structures in which all atoms have complete valence shells are more stable. The structures with the least number of ritual charges are more stable. The structures with a negative charge on the further electronegative atom will be more stable. The three main factors determining the relative stability of alkenes are i) the number of substituents attached to the double-bond carbon atoms, ii) hyperconjugation, and iii) the stereochemistry of the double bond.

So we can conclude that the more electron-donating alkyl groups are the more stable the alkene

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Sodium hydroxide is extremely soluble in water. At a certain temperature, a saturated solution contains 573 g NaOH(s) per liter of solution. Calculate the molarity of this saturated NaOH(aq) solution.Concentration: ____________ M

Answers

[tex]\text{Molarity (}\frac{mol}{L})=\text{ }\frac{mass\text{ NaOH (solute)}}{\text{molecular mass NaOH x volume solution (L)}}[/tex]

Remember: solution = NaOH + water

Volumen here = 1 L

Molecular mass NaOH = 39.99 g/mol

[tex]M\text{ = }\frac{573\text{ g}}{39.99\text{ }\frac{g}{\text{mol}}x\text{ 1 L}}=\text{ 14.32 }\frac{mol}{L}[/tex]

Answer: Contration = 14.32 M

Express the following in liters at STP: 0.804 moles CCl4

Answers

Considering the definition of STP conditions, 4.83 × 10⁻³ moles of HF will occupy a volume of 0.108192 L at STP.

STP conditions

STP conditions is the abbreviation that refers to standard temperature and pressure. The standard value for pressure is 1 atmosphere and the standard value for temperature is 0°C. They are valid reference values for all gases, and under these conditions 1 mole of any gas occupies an approximate volume of 22.4 liters.

Volume in this case

In this case, you have 0.804 moles CCl₄. You can apply the following rule of three: if by definition of STP conditions 1 mole of CCl₄ occupies a volume of 22.4 liters, 0.804 moles occupies how much volume?

volume= (0.804 moles ×22.4 L)÷ 1 mole

volume= 18.0096 L

Finally, the volume will be 18.0096 L at STP.

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PLEASE HELP, IT’S DUE TODAY!
Isotopes of certain ___ elements that spontaneously emit ____ and ____ from the _____.

Answers

Isotopes of certain __radioactive__ elements that spontaneously emit __radiation__ and _rays___ from the __nuclei____

What causes isotopes to emit radiation ?

Any of multiple species of the same chemical element with differing masses whose nuclei are unstable and spontaneously produce radiation in the form of alpha, beta, and gamma rays are known as radioactive isotopes, also known as radioisotopes, radionuclides, or radioactive nuclides.

Isotopes are identical elemental atoms with differing quantities of neutrons. Numerous elements have one or more radioactive isotopes. Due to the instability of their nuclei, they decay and release radiation.

Many of the radioisotopes in the uranium, thorium, and actinium natural radiation decay series, as well as the naturally occurring radioisotopes potassium-40 and carbon-14, generate gamma radiation.

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Complete the second column of the table.Express your answer using two significant figures.

Answers

Avogadro's Law is

[tex]\frac{V_1}{n_1}=\frac{V_2}{n_2}[/tex]

In the second column of the table, we have to find n1 when V1 = 51 mL, V2 = 13 mL, and n2 = 2.68x10^-4 mol. Solve the equation for n1.

[tex]\begin{gathered} n_1=\frac{V_1\cdot n_2^{}}{V_2}=\frac{51mL\cdot2.68\times10^{-4}mol}{13mL} \\ n_1=11\times10^{-4}mol \\ n_1=0.0011mol \end{gathered}[/tex]

Therefore, the number of moles of n1 is 0.0011 moles.

Write the complete ground-state electron configuration of Mn⁴⁺.

Answers

The complete ground-state electronic configuration of Mn⁺⁴ is:

Mn⁺⁴: [Ar] 4s⁰ 3d³

The electronic configuration is written according to the following principles:

Aufbau's rulePauling's exclusion principleHund's rule of maximum multiplicity

Manganese being a d-block element possesses d-orbitals in the electron cloud. There are 25 electrons present in the ground-state configuration.

In order to reach the excited state, electrons will be removed from the ground state. The removal of electrons is centripetal in nature. Initially, 2 electrons will be removed from 4s, followed by the removal of 2 electrons from 3d.

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explain the process of photosynthesis with these

Words:
Photosynthesis,
light,
water,
energy,
Carbon Dioxide,
Oxygen,
xylem,
stomata,
Sugar(Glucose),
phloem,
chloroplasts,
leaves,
roots

Be legible and neat please and thank you

Answers

The process of photosynthesis used by plant in which they produce sugar ( glucose ).

Photosynthesis is the process in which plants produced sugar by using sun - light , water and carbon dioxide. In the process of photosynthesis plants use carbon dioxide ( CO₂ ) and water H₂O from the air and the soil  then this carbon dioxide and water transforms to oxygen and sugar (glucose). the oxygen produced by plant back into the air and the sugar produces stores by the plant as the form of energy.

                                                sunlight

carbon dioxide  +   water       -------------->     glucose   +   oxygen

In the leaf cell a part called chloroplast in it energy in sunlight used to break oxygen and hydrogen. T he water required in the process of photosynthesis taken by the roots from soil and then it transport with the help of xylem cell to the different parts of plant. phloem takes sugar from leaves to different parts of plant. The stomata is for the transpiration exchange that means it takes carbon dioxide and the release oxygen back to air after the photosynthesis end.

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