What average net force is required to stop a 1950 kg car in 10.5 s if it’s initially traveling at 28m/s
Answer:
An average net force of 5200 N is needed to stop the car
Explanation:
Cinematics and Dynamics
Cinematics describes the variables involved in the movement without dealing with its causes. There are four main concepts in cinematics: Velocity (or its scalar equivalent, the speed), acceleration, time, and displacement (or the scalar equivalent, distance).
The acceleration can be calculated by:
[tex]\displaystyle a=\frac{v_f-v_o}{t}[/tex]
The initial speed is vo=28 m/s, it stops (vf=0) in t=10.5 seconds, thus the acceleration is:
[tex]\displaystyle a=\frac{0-28}{10.5}[/tex]
[tex]a = -2.67~m/s^2[/tex]
The acceleration is negative because the car loses speed.
Knowing the mass of the car m=1950 Kg, we can calculate the net force required to stop the car by using the formula:
F = m.a =1950*2.67
F = 5200 N
An average net force of 5200 N is needed to stop the car
according to newtons third law of motion what happened to the back of a skateboard when the person pushes down on the front of the skateboard
Answer:I think it would start moving
Explanation:
A 615.00 kg race car is uniformly traveling around a circular race track. It takes the race car 20.00 seconds to do one lap around the 80.00 m radius circular track. What is the frequency of the race car's circular motion?
Answer:
The value is [tex]f = 0.05 \ Hz[/tex]
Explanation:
From the question we are told that
The mass of the car is [tex]m = 615 \ kg[/tex]
The period of the circular motion is [tex]T = 20 \ s[/tex]
The radius is [tex]r = 80 \ m/s[/tex]
Generally the frequency of the circular motion is
[tex]f = \frac{1}{T }[/tex]
=> [tex]f = \frac{1}{ 20 }[/tex]
=> [tex]f = 0.05 \ Hz[/tex]
I WILL GIVE BRAINLIEST IF SOMEONE GETS THIS......
A eureka can of mass 100g and cross-section area 100cm2 is filled with water of density 1g/cm3. A piece of metal of mass 20g and density 8g/cm3 is lowered into the can. ( height of can 10cm ) calculate:
a) the total mass of can before the metal was lowered.
b) the volume of water that overflowed
c) the final mass of can and its content
Answer:
Explanation:
a)
Firstly to calculate the total mass of the can before the metal was lowered we need to add the mass of the eureka can and the mass of the water in the can. We don't know the mass of the water but we can easily find if we know the volume of the can. In order to calculate the volume we would have to multiply the area of the cross section by the height. So we do the following.
100[tex]cm^{2}[/tex] x 10cm = 1000[tex]cm^{3}[/tex]
Now in order to find the mass that water has in this case we have to multiply the water's density by the volume, and so we get....
[tex]\frac{1g}{cm^{3} }[/tex] x 1000[tex]cm^{3}[/tex] = 1000g or 1kg
Knowing this, we now can calculate the total mass of the can before the metal was lowered, by adding the mass of the water to the mass of the can. So we get....
1000g + 100g = 1100g or 1.1kg
b)
The volume of the water that over flowed will be equal to the volume of the metal piece (since when we add the metal piece, the metal piece will force out the same volume of water as itself, to understand this more deeply you can read the about "Archimedes principle"). Knowing this we just have to calculate the volume of the metal piece an that will be the answer. So this time in order to find volume we will have to divide the total mass of the metal piece by its density. So we get....
20g ÷ [tex]\frac{8g}{cm^{3} }[/tex] = 2.5 [tex]cm^{3}[/tex]
c)
Now to find out the total mass of the can after the metal piece was lowered we would have to add the mass of the can itself, mass of the water inside the can, and the mass of the metal piece. We know the mass of the can, and the metal piece but we don't know the mass of the water because when we lowered the metal piece some of the water overflowed, and as a result the mass of the water changed. So now we just have to find the mass of the water in the can keeping in mind the fact that 2.5[tex]cm^{3}[/tex] overflowed. So now we the same process as in number a) just with a few adjustments.
[tex]\frac{1g}{cm^{3} }[/tex] x (1000[tex]cm^{3}[/tex] - 2.5[tex]cm^{3}[/tex]) = 997.5g
So now that we know the mass of the water in the can after we added the metal piece we can add all the three masses together (the mass of the can. the mass of the water, and the mass of the metal piece) and get the answer.
100g + 997.5g + 20g = 1117.5g or 1.1175kg
Bile is a compound that helps in the digestion of fat and eliminates waste products from the blood. True O False
Answer:
That should be true because bile is ¨a bitter greenish-brown alkaline fluid that aids digestion and is secreted by the liver and stored in the gallbladder.¨
Explanation:
Earthquakes
Shaking of the ground
Seismographs
Scientific method
Answer:
C. seismographs
Explanation:
Theirs another name for seismographs but c is correct
What force must be applied to the end of a rod along the x-axis of length 2.25 m in order to produce a torque on the rod about the origin of 11 z-hat N·m? Choose among the available options below. x,y,z,-z
Answer:
4.9N approx.Explanation:
Step one:
given data
length of rod r= 2.25m
Required torque = 11 Nm
Required
The force needed to produce a torque of 11Nm
Step two:
"By definition, Torque is the twisting force that tends to cause rotation.
The point where the object rotates is known as the axis of rotation."
Mathematically,
[tex]\tau = rF\sin\theta[/tex]
[tex]\tau[/tex] = torque
r = radius
F = force
[tex]\theta[/tex] = angle between F and the lever arm
in this case is zero
[tex]\tau = rF\\\\F=\tau/r[/tex]
substituting we have
F=11/2.25
F=4.88N
F=4.9N approx.
A car of mass of 1000 ks in accelerating at 2 ms. What resultant force acts on the car? If the
resistance to the motion is 1000 N, what is the force due to engine?
Answer:
Explanation:
Opp
A jet aircraft is traveling at 214 m/s in hor-
izontal flight. The engine takes in air at a
rate of 115 kg/s and burns fuel at a rate of
2.53 kg/s. The exhaust gases are ejected at
276 m/s relative to the aircraft.
Find the thrust of the jet engine.
Answer in units of N.
Answer:
The thrust is [tex]F = 7828.3 \ N [/tex]
Explanation:
From the question we are told that
The speed of the jet aircraft is [tex]v = 214 \ m/s[/tex]
The rate at which the engine takes in air is [tex]\^ Q = 115 \ kg/s[/tex]
The rate at which the engine burns fuel is [tex]\r m = 2.53 \ kg/s[/tex]
The speed of the exhaust gases is [tex]u = 276 \ m/s[/tex]
Generally the thrust of the engine is mathematically represented as
[tex]F =[ \^ Q * ( u - v )] + (\r m * u)[/tex]
=> [tex]F =[ 115 * ( 276 - 214 )] + (2.53 * 276)[/tex]
=> [tex]F = 7828.3 \ N [/tex]
Two ice-skaters are skating in circles on a frozen pond. Maria is making large circles with a radius of 12 m and skating 4.5 m/s. Her friend, Samantha, is making smaller circles with a radius of 6 m but is not skating as quickly, going only 3.8 m/s.
How could each skater increase her centripetal acceleration without changing the size of her path? Explain your reasoning.
Answer: Samantha has the largest centripetal acceleration of 2.4 m/s^2. Maria has only 1.69 m/s^2.
Explanation:
Chemical reactions occur due to sharing or transferring of blank. Please help ASAP!!!!
Answer: valence electrons?
Explanation:
a toy car is wound up and released on the floor. it accelerates at a rate of 0.4 m/s/s . the mass of the care is 3kg. what is the force that the cars wheels exert on the floor.
Answer:
1.2N
Explanation:
f=m×a
m=3kg
a=.4m/s/s
3×.4=1.2
kg×m/s/s = N
Which of the following equations accurately defines acceleration?
Plz help ASAP
Answer:
Acceleration (a) is the change in velocity (Δv) over the change in time (Δt), represented by the equation a = Δv/Δt. This allows you to measure how fast velocity changes in meters per second squared (m/s^2). Acceleration is also a vector quantity, so it includes both magnitude and direction.
Explanation:
Answer: i think its b
sorry if im wrong
Explanation:
Where does compression often occur?
Answer:
a convergent boundary^^
Explanation:
hope it helped
The temp of the metal in a running car engine is 388 K. Find this temp in Celsius.
Answer:
115°c
Explanation:
°c=k-273
388-273=115
A 3900 kg truck is moving at 6.0 m/s what is the kinetic energy
Answer:
70200J
Explanation:
k.E = 1/2mv^2
K.E = 1/2(3900)(6)^2
Which of the following is related to a person’s self-concept?
A) what neighborhood he or she lives in
B) his or her sense of self-worth
C) how good an athlete he or she is
D) how attractive he or she is
Answer:
Im not a 100 percent sure but i thinks it za A
Explanation:
what is the mass and volume of 1000kg/m3 of water?
Answer: The mass would be 1000m3 and the volume would be 1000kg
Explanation:
What types of energy is used to make a lamp work
Answer:
Electrical energy
Explanation:
A train travels at a speed of 30mph and travelled a distance of 240 miles. How long did it take the train to complete its journey? Must show your work
Answer:
8
Explanation:
240 divided by 30 = 8
What does the half life for a radioactive material mean?
How much power is used if a force of 35 newtons is used to push a box a distance of 10 meters in 5 seconds?w=350j
Answer:
How much power is used if 350J of work is done when pushing a box for 5 seconds.
Explanation:
the answer is 70watts
3. If I run 150m in 30 seconds, what speed will I have been running at?
Answer:
speed = distance/time
Explanation:
speed = 150/30
speed =5m/s
you were running fast .....5m/s is a good speed
Which point has the most Potential energy? [Select]
Which point has the most Kinetic energy? [ Select ]
Answer:
Most potential energy: A
Most kinetic energy: D
Explanation:
Kinetic Energy is the type of energy an object has due to its state of motion. It's proportional to the square of the speed.
The equation for the kinetic energy is:
[tex]\displaystyle K=\frac{1}{2}mv^2[/tex]
Where:
m = mass of the object
v = speed at which the object moves
The gravitational potential energy is the energy stored in an object because of its height h in a gravitational field.
It can be calculated with the equation:
U=m.g.h
The point where the object has the most potential energy is that where it has more height. It corresponds to point A.
When the object is at zero height, all of its potential energy was transformed to kinetic, thus the point where the kinetic energy is D.
Most potential energy: A
Most kinetic energy: D
Answer:
potentail enegry at point a and kinetic enegy at point c
Explanation:
i did this i fourth grade please mark brainlist
Witch TWO types of rock are formed as particles get pushed closer together A. Intrusive igneous B. Extrusive igneous C. Sedimentary D. Metamorphosis
Answer:
C
Explanation:
Sedimentary rocks are the product of
1) weathering of preexisting rocks,
2) transport of the weathering products,
3) deposition of the material
4) compaction (two rocks pushed together)
5) cementation of the sediment to form a rock.
What 2 factors affect the impulse on an object in a collision?
The weight of an object is measured in air to be 7.0 N. The
object is then immersed in water and its apparent weight is
measured to be 4.0 N. Determine the buoyant force and state
whether or not the object floats.
Answer:
Buoyant force = 3.0 N
The object will not float.
Explanation:
Apparent weight of a body immersed in water is the actual weight of object minus buoyant force
Given in the question that;
Weight of object in air = 7.0 N
Apparent weight of object = 4.0 N
4.0 N = 7.0 N - Buoyant force
Buoyant force = 7.0 - 4.0 = 3.0 N
In this case, the buoyant force is less than weight of the object thus the object will sink.
3. Riddle:
I am black when you buy me, red when you use me and grey when you throw me away.
What am I?
Answer:
The answer is charcoal
Answer:
Charcoal
Explanation:
As the amount of surface area increases, what happens to the rate of this reaction? If the antacid tablet were broken into eight pieces, what would be a reasonable estimate for the time of
as the surface area increases the rate of reaction also increases.
Explanation:
Answer:
A.) The rate is faster.
C.) 28 Seconds
A boy is exerting a force of 70 N at a 50-degree angle on a lawnmower. He is accelerating at 1.8 m/s2. Round the answers to the nearest whole number.
What is the mass of the lawnmower?
What is the normal force exerted on the lawnmower?
The lawnmower accelerates in the positive horizontal direction, so that the net horizontal force is, by Newton's second law,
(70 N) cos(-50°) = m (1.8 m/s²)
where m is the mass of the lawnmower. Solve for m :
m = ((70 N) cos(-50°)) / (1.8 m/s²)
m ≈ 25 kg
The lawnmower presumably doesn't get lifted off the ground, so that the net vertical force is 0. If n is the magnitude of the normal force, then by Newton's second law,
n - m g + (70 N) sin(-50°) = 0
n = m g + (70 N) sin(50°)
n = (25 kg) (9.8 m/s²) + (70 N) sin(50°)
n ≈ 300 N