What is the area of the real object that the scale drawing models?Scale factor: 1:3Area =6 square cmScale drawingOA. 54 square cmOB. 2 square cmO C. 18 square cmD. 6 square cmReal object
Answers
We have a drawing object with an area of 6 square centimeters. Since we have a scale factor of 1 : 3, it means that the real object is 3 times greater than the drawing object.
Therefore, if the drawing object has an area of 6 square centimeters, then the real object will have:
[tex]6cm^2*3=18cm^2[/tex]The real object will be 3 times greater than the one in the drawing.
Therefore, in summary, the real object will have 18 square centimeters (.
Related Questions
Round 7488 to the nearest thousand
Answers
The thousand place value is the 4th digit to the left of the decimal point. This means that the digit is 7.
If the first digit after 7 is greater than or equal to 5, 7 would increase by 1. If it is less than 5, 7 remains the same. Since 4 is less than 5, 7 remains. The rest digits turns to 0. Thus, the answer is
7000
Write a explicit formula for the given recursive formulas for each arithmetic sequence
9,15,21,27 and 7,0,-7,-14
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In arithmetic progression, 9,15,21,27,33,39 is a₅ and a₆ .
What is arithmetic progression?
A series of numbers is called a "arithmetic progression" (AP) when any two subsequent numbers have a constant difference. It also goes by the name Arithmetic Sequence.a₁ = 9
a₂ = 15
a₃ = 21
Notice that a₂ - a₁ = 6 and a₃ - a₂ = 6
We can deduce that aₙ₊₁ = aₙ + 6
We can test this on the 4th term : a₄ should equal 21 + 6 = 27
Since this checks out we can say that the sequence is an arithmetic progression with a common difference of 6.
a₅ = 27 + 5 = 33
and
a₆ = 33 + 6 = 39
7,0,-7,-14
find the common difference by substracting any term in the sequence from the term that comes after it.
a₂ - a₁ = 0 - 7 = -7
a₃ - a₂ = -7 - 0 = -7
a₄ - a₃ = -14 - -7 = -7
the difference of the sequence is constant and equals the difference between two consecutive terms.
d = -7
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If R is between G and Z, GZ = 12in., and RG =3in., then RZ =
Answers
Given R is between G and Z.
GZ=12 inches
RG=3 inches.
Since, R is between G and Z,
[tex]GZ=GR+RZ[/tex]It follows
[tex]\begin{gathered} RZ=GZ-GR \\ =12-3 \\ =9 \end{gathered}[/tex]So, RZ is 9 inches.
Help on math question precalculus ChoicesVertical shift Period DomainRange Phase shift Amplitude
Answers
All the x-values that satisfy the function - Domain
Translating the sine or cosine curve up or down - Vertical shift
How long a given function takes to repeat itself - Period.
A horizontal shift of a sine or cosine function- Phase shift
All the y-values that satisfy the function- Range
Distance from the horizontal axis or midline to the maximum and minimum points - Amplitude
find the minimum value of the function f(x)=2x2-22x+68 to the nearest hundredth
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Minimum value of the function
[tex]f(x)=2x^2-22x+68[/tex]To calculate the minimum value we will use the derivative.
[tex]\begin{gathered} f^{\prime}(x)=4x-22 \\ 4x-22=0 \\ 4x=22 \\ x=\frac{22}{4} \\ x=5.5 \end{gathered}[/tex]The answer would be 5.5
Caitlyn is 160 centimeters tall. How tall is she in feet and inches, rounded to the nearest inch?
Answers
Answer:
5 ft 3 in.
Explanation:
First, recall the standard conversion rates below.
• 1 foot = 30.48 cm
,• 1 foot = 12 inches
First, convert 160 cm to feet.
[tex]\begin{gathered} \frac{1ft}{30.48\operatorname{cm}}=\frac{x\text{ ft}}{160\text{ cm}} \\ 30.48x=160 \\ x=\frac{160}{30.48} \\ x=5.2493\text{ ft} \\ x=(5+0.2493)\text{ ft} \end{gathered}[/tex]Next, we convert the decimal part (0.2493 ft) of the result above to inches.
[tex]\begin{gathered} 1ft=12\text{ inches} \\ \frac{1\text{ ft}}{12\text{ inches}}=\frac{0.2493\text{ ft}}{y\text{ inches}} \\ y=0.2493\times12 \\ y=2.9916 \\ y\approx3\text{ inches (to the nearest inch)} \end{gathered}[/tex]Therefore, 160 centimeters in feet and inches is:
[tex]5\text{ feet 3 inches}[/tex]Determine whether the statement is true or false, and explain why.
If a function is positive at x = a, then its derivative is also positive at x = a.
Choose the correct answer below.
OA. The statement is true because the sign of the rate of change of a function is the same as the sign of its value.
OB. The statement is false because the derivative gives the rate of change of a function. It expresses slope, not
value.
OC. The statement is false because the sign of the rate of change of a function is opposite the sign of its value.
OD. The statement is true because the derivatives of increasing functions are always positive.
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Answer: B. The statement is false because the derivative gives the rate of change of a function. It expresses slope, not value.
using the converse of the same-side interior angles postulate what equation shows that g∥h
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Answer: [tex]\angle 2+\angle 4=180^{\circ}[/tex] or [tex]\angle 1+\angle 3=180^{\circ}[/tex]
Solve each system of the equation by elimination method. x+3y=-204x+5y=-38
Answers
Given the equation system:
[tex]\begin{gathered} x+3y=-20 \\ 4x+5y=-38 \end{gathered}[/tex]To solve this system using the elimination method, the first step is to multiply the first equation by 4 so that the leading coefficient is the same, i.e., both equations start with "4x"
[tex]\begin{gathered} 4(x+3y=-20) \\ 4\cdot x+4\cdot3y=4\cdot(-20) \\ 4x+12y=-80 \end{gathered}[/tex]Then subtract the second equation from the first one
From the resulting expression, you can calculate the value of y
[tex]\begin{gathered} 7y=-42 \\ \frac{7y}{7}=-\frac{42}{7} \\ y=-6 \end{gathered}[/tex]Next, you have to substitute the value of y in either the first or second equation to find the value of x:
[tex]\begin{gathered} x+3y=-20 \\ x+3\cdot(-6)=-20 \\ x-18=-20 \\ x=-20+18 \\ x=-2 \end{gathered}[/tex]The solution of the system is (-2,-6)
DataNot ReceivingReceivingFinancial AidFinancial AidUndergraduates422238988120Graduates18797312610Total6101462910730If a student is selected at random, what is theprobability that the student receives aid and is agraduate (rounded to the nearest percent)? [? ]%UniversityTotal
Answers
There are 10730 students total as shown in the bottom right hand corner. So, the probability that the student receives aid and is a graduate is given by:
[tex]P=\frac{1879}{10730}\times100=17.51[/tex]Round to the nearest percent is 17.5%
Answer: 17.5%
Answer:
There are a total of 10730 students and 1879 students who are graduates as well as receiving financial aid. So the probability would be
(1879/10730)*100 = 17.51%
Blossom's Computer Repair Shop started the year with total assets of $318000 and total liabilities of $211000. During the year, the
business recorded $505000 in computer repair revenues, $311000 in expenses, and Blossom paid dividends of $50200. Stockholders'
equity at the end of the year was
Answers
Ur welcome
-Given that f(x) = 6(x - 1). Choose the correct statement. A. f-1(12) = 3.5 B. f-1(3) = 1 c. f-16) = 3 D. f-1(9) = 2.5
Answers
Given that function is f(x) = 6(x - 1).
Let y = 6(x - 1). Replace x with y and then solve for y.
[tex]\begin{gathered} x=6(y-1) \\ \Rightarrow x=6y-6 \\ \Rightarrow6y=x+6 \\ \Rightarrow y=\frac{x+6}{6} \end{gathered}[/tex]Thus, f^-1(x) = (x + 6)/6.
[tex]f^{-1}(12)=\frac{12+6}{6}=3[/tex][tex]f^{-1}(3)=\frac{3+6}{6}=1.5[/tex][tex]f^{-1}(6)=\frac{6+6}{6}=2[/tex][tex]f^{-1}(9)=\frac{9+6}{6}=2.5[/tex]Thus, option D is correct.
Keeshonbought Packages of pens represented by P there were four pence in each package Keyshawn gave six to his friends which expression shows this situation
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The expression that shows when Keeshon bought Packages of pens represented by P is 24p.
What is an expression?An expression is used to illustrate the information that's given regarding a data.
Let the pens be represented by p.
In this case, there there were four pend in each package and Keyshawn gave six to his friends. This will be:
= 6(4 × p)
= 6(4p)
= 24p
This shows the expression.
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What are the coordinates of the point on the directed line segment from (−8,−4)(−8,−4) to (−5,8)(−5,8) that partitions the segment into a ratio of 5 to 1?
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Write a cosine function that has a midline of 4, an amplitude of 3 and a period of 8/5
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A cosine function has the form
[tex]y=A\cdot\cos (Bx+C)+D[/tex]Where A is the amplitude, B is 2pi/T, and C is null in this case because the phase is not being specified, and D is the vertical shift (midline).
Using all the given information, we have
[tex]y=3\cdot\cos (\frac{2\pi}{T}x)+4[/tex]Then,
[tex]y=3\cdot\cos (\frac{2\pi}{\frac{8}{5}}x)+4=3\cdot\cos (\frac{10\pi}{8}x)+4=3\cdot\cos (\frac{5\pi}{4}x)+4[/tex]Hence, the function is
[tex]y=3\cos (\frac{5\pi}{4}x)+4[/tex]Please help me I need this done fast I will give brainliest to whoever answers first
Answers
Consider that a standard quadratic equation is given by,
[tex]y=ax^2+bx+c[/tex]The curve passes through the point (-5,0),
[tex]\begin{gathered} 0=a(-5)^2+(-5)b+c \\ 0=25a-5b+c \\ c=-25a+5b\ldots\ldots\ldots(1) \end{gathered}[/tex]The curve passes through the point (3,0),
[tex]\begin{gathered} 0=a(3)^2+(3)b+c \\ 0=9a+3b+c \end{gathered}[/tex]Substitute value from equation (1),
[tex]\begin{gathered} 0=9a+3b+(-25a+5b) \\ 0=-16a+8b \\ b=2a\ldots\ldots\ldots(2) \end{gathered}[/tex]The curve passes through the point (4,9),
[tex]\begin{gathered} 9=a(4)^2+(4)b+c \\ 9=16a+4b+c \end{gathered}[/tex]Substitute tha values from (1) and (2),
[tex]\begin{gathered} 9=16a+4(2a)+(-25a+5(2a)) \\ 9=16a+8a-25a+10a \\ 9=9a \\ a=1 \end{gathered}[/tex]Substitute in equation (2),
[tex]\begin{gathered} b=2(1) \\ b=2 \end{gathered}[/tex]Substitute the values in equation (1),
[tex]\begin{gathered} c=-25(1)+5(2) \\ c=-25+10 \\ c=-15 \end{gathered}[/tex]Substitute the values of a, b, and c, in the standard equation,
[tex]\begin{gathered} y=(1)x^2+(2)x+(-15) \\ y=x^2+2x-15 \end{gathered}[/tex]This is the equation of the given parabola.
Therefore, option B is the correct choice.
The sum of three numbers is140 . The first number is 8 more than the third. The second number is 4 times the third. What are the numbers? First number: Second number: Third number:
Answers
Answer:
x= 30
y= 88
z= 22
Step-by-step explanation:
x= z+8
y= 4z
x + y + z = 140
we substitute to the third equation (z+8) + (4z) + z= 140 so we obtain 6z+8= 140. Z is then equal to 140-8/6= 22.
Then x= 22+8= 30, y=22(4)= 88
30+88+22= 140
find the distance between the given points. if the answer is not exact, use a calculator and give an approximation to the nearest tenth (-7,-2), (5,3)
Answers
The distance is:
[tex]d=\sqrt[]{(x2-x1)^2+(y2-y1)^2}[/tex]By replacing x and y
[tex]d=\sqrt[]{(5-(-7))^2+(3-(-2))^2}[/tex]Then solve
[tex]\begin{gathered} d=\sqrt[]{(5+7)^2+(3+2)^2} \\ d=\sqrt[]{12^2+5^2} \\ d=\sqrt[]{144+25}^{} \\ d=\sqrt[]{169} \\ d=13 \end{gathered}[/tex]Answer: 13
Write using set-builder notation: -2x + 1 < 27
Answers
Instead of describing the constituents of a set, a set-builder notation describes them. The set-builder notation exists A = {x: x is a natural number less than 27}.
What is meant by set-builder notation?A set can be represented by its elements or the properties that each of its members must meet can be described using set-builder notation.
Set-builder notation is a mathematical notation for defining a set by enumerating its elements or by specifying the properties that each of its members must satisfy. It is used in set theory and its applications to logic, mathematics, and computer science.
Let the given inequality be 2x+1 < 27
Subtract 1 from both sides, we get
-2x+1-1 < 27-1
Simplifying the above equation, we get
-2 x < 26
Multiply both sides by - 1 (reverse the inequality)
(-2 x)(-1) > 26(-1)
Simplifying the above equation, we get
2x > -26
Divide both sides by 2
[tex]$\frac{2 x}{2} > \frac{-26}{2}[/tex]
x > -13
Therefore, the set-builder notation exists
A = {x: x is a natural number less than 27}.
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The next algebra test is worth 100 points and contains 35 problems. Multiple-Choice questions are worth 2 points each and word problems are 7 points each. How many of each type equation are there?
Answers
Let
x ----->number of multiple-choice questions
y ----> number of word problems
so
we have
x+y=35 --------> equation 1
2x+7y=100 -----> equation 2
solve the system of equations
Solve by graphing
using a graphing tool
see the attached figure
therefore
x=29
y=6
number of multiple-choice questions is 29
number of word problems is 6
At a carry-out pizza restaurant, an order of 3 slices of pizza, 4 breadsticks, and 2 juice drinks costs $12. A second order of 5 slices of pizza, 2 breadsticks, and 3 juice drinks costs $15. If four breadsticks and a juice drink cost $.30 more than a slice of pizza, write a system that represents these statements. p: slices of pizza b: bread sticks d: juice drinks Choose the correct verbal expressions for problems into a system of equations or inequalities.
Answers
p = slices of pizza
b = bread sticks
d = juice drinks
Equation 1
3p + 4b + 2d = 12
Equation 2
5p + 2b + 3d = 15
Equation 3
4b + 1d = 1p + 0.3
That's all
9 to the power of -3 as a fraction or number without exponents (simplified fractions).
Answers
Answer:
1/729
Step-by-step explanation:
A number raised to a negative exponent is the same as 1 divided by the number raised the the exponent
9⁻³
1/9³
1/729
What is the slope of the line with points (3,7) and (3,-2)
Answers
Answer:
slope = 0
Given:
(3, 7)
(3, -2)
The formula for the slope is solved by the following formula:
[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]From the given, we know that:
x₁ = 3
x₂ = 3
y₁ = 7
y₂ = -2
Substituting these values to the formula, we will get:
[tex]\begin{gathered} m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}} \\ m=\frac{-2-7}{3-3} \\ m=\frac{-9}{0} \\ m=0 \end{gathered}[/tex]Therefore, the slope would be 0.
5 cm3 cm3 cm5 cm3 cmPrisma5 cmPrism BWhich of the following statements are true about the solids shown above?Check all that apply.A. Prisms A and B have different values for lateral surface area.O B. Prism B has a total surface area of 110 cm?O C. Prism A has a lateral surface area of 60 cm?D D. Prism B has a larger surface area.
Answers
Note that the lateral surface area is the area of the faces of the solid, excluding the cross-sectional faces i.e. faces which are perpendicular to the longitudinal axis.
The lateral surface area of prism A is calculated as,
[tex]\begin{gathered} LSA_A=2(5\times3)+2(5\times3)_{} \\ LSA_A=30+30 \\ LSA_A=60 \end{gathered}[/tex]Similarly, the lateral surface area of prism A is calculated as,
[tex]\begin{gathered} LSA_B=2(3\times5)+2(5\times5)_{} \\ LSA_B=30+50 \\ LSA_B=80 \end{gathered}[/tex]Clearly, prisms A and B have different values of lateral surface area.
So option A is the correct statement.
The total surface area is the sum of all the faces of the solid.
Since we have already calculated the LSA i.e. sum of area of 4 faces of the prism, we can add the area of the two remaining cross sectional faces to get the total area.
The total cross section area of prism B is calculated as,
[tex]\begin{gathered} A_B=2(5\times3) \\ A_B=30 \end{gathered}[/tex]So the total surface area of prism B becomes,
[tex]\begin{gathered} TSA_B=LSA_B+A_B_{} \\ TSA_B=80+30 \\ TSA_B=110 \end{gathered}[/tex]The total surface area of prism B is 110 sq. cm.
So option B is also correct.
Note that we have already found that the lateral surface area of prism A is 60 sq. cm.
Therefore, option C is also correct.
The total cross section area of prism A is calculated as,
[tex]\begin{gathered} A_A=2(3\times5) \\ A_A=30 \end{gathered}[/tex]So the total surface area of prism A becomes,
[tex]\begin{gathered} TSA_A=LSA_A+A_A \\ TSA_A=60+30 \\ TSA_A=90 \end{gathered}[/tex]The total surface area of prism A is 90 sq. cm.
It is oberved that prism B has a larger surface area.
So, option D is also correct.
Hence, we can conclude that all the given statements are correct.
Sarina throws a ball up into the air, and it falls on the ground nearby. The ball's height, in feet, is modeled by the function ƒ(x) = –x2 – x + 3, where x represents time in seconds. What's the height of the ball when Sarina throws it?Question 12 options:A) 1 footB) 3 feetC) 4 feetD) 2 feet
Answers
Answer:
3 feet
Explanation:
We are told from the question that the ball's height, in feet, is modeled by the below function;
[tex]f(x)=-x^2-x+3[/tex]where x = time in seconds
To determine the height of the ball when Sarina throws the ball, all we need to do is solve for the initial height of the ball, i.e, the height when x = 0. So we'll have;
[tex]\begin{gathered} f(0)=-(0)^2-(0)+3 \\ f(0)=3\text{ f}eet \end{gathered}[/tex]A rectangular parking lot has length that is 3 yards less than twice its width. If the area of the land is 299 square yards, what are the dimensions of the land?The parking lot has a width of square yards.
Answers
Answer:
• Width = 13 yards
,• Length = 23 yards
Explanation:
Let the width of the parking lot = w yards.
The length is 3 yards less than twice its width.
[tex]\implies\text{Length}=(2w-3)\text{ yards}[/tex]The area of the land = 299 square yards.
[tex]w(2w-3)=299[/tex]We then solve the equation above for w.
[tex]\begin{gathered} 2w^2-3w=299 \\ \implies2w^2-3w-299=0 \end{gathered}[/tex]Factor the resulting quadratic expression.
[tex]\begin{gathered} 2w^2-26w+23w-299=0 \\ 2w(w-13)+23(w-13)=0 \\ (2w+23)(w-13)=0 \end{gathered}[/tex]Solve for w.
[tex]\begin{gathered} 2w+23=0\text{ or }w-13=0 \\ 2w=-23\text{ or }w=13 \\ w\neq-\frac{23}{2},w=13 \end{gathered}[/tex]Since w cannot be negative, the parking lot has a width of 13 yards.
Finally, find the length of the parking lot.
[tex]\begin{gathered} 13l=299 \\ l=\frac{299}{13}=23\text{ yards} \end{gathered}[/tex]The length of the parking lot is 23 yards.
A faraway planet is populated by creatures called Jolos. All Jolos are either green or purple and either one-headed or two-headed. Balan, who lives on this planet, does a survey and finds that her colony of 500 contains 100 green, one-headed Jolos; 125 purple, two-headed Jolos; and 270 one headed-jolos.How many green Jolos are there in Balan's colony?A. 105B. 170C. 205D. 230
Answers
According to the table, there are 270 one-headed in total, and there are 500 Jolos, we just have to subtract to find the total of two-headed Jolos
[tex]500-270=230[/tex]There are 230 two-headed Jolos.
Now, we subtract the total of two-headed Jolos and the two-headed purple Jolos to find the total green.
[tex]230-125=105[/tex]There are 105 two-headed green Jolos.
At last, we have to sum the number of one-headed green Jolos and the two-headed green Jolos,
[tex]100+105=205[/tex]Hence, there are 205 green Jolos in total.According to the theory of the color yellow + red = orange. If Luisa has x liters of yellow paint and/ 4 liters of red paint. How many liters of orange paint will he get Louise? And if I had 4 liters of yellow paint, could I get exact 5 liters of paint orange?
Answers
Yellow + red = Orange
Yellow paint , x liters
Red paint , 4 liters
a) Because addition applies , adding x liters of Yellow + 4 liters of red and the result is x + 4 liters of orange
b) for second question apply equation
4 • yellow + Red •N = 5
then find N
its possible to obtain 5 liters of paint orange with
2 liters of yellow, 2 liters of red, and adding
0.5 liters of yellow, 0.5 liters of red.
Julian is decorating the outside of a box in the shape of a right rectangular prism. Thefigure below shows a net for the box.
Answers
The surface area of the box equals the sum of the surface area of each of its parts.
And the area of each rectangle that form the box is found by multiplying the width by the height of that rectangle.
We have two ractangles with sides 7 ft and 10 ft. So the area of each one is:
7 ft * 10 ft = 7 * 10 * ft * ft = 70 ft²
Since there's two of this rectangle, their areas sum up to
2 * 70 ft² = 140 ft²
Now, we also have two rectangles with sides 7 ft and 14 ft (the second and the fourth rectangles from left to right in the image). So, their areas sum up to:
2 * (7 ft * 14 ft) = 2 * (98 ft²) = 196 ft²
Finally, we also have two rectangles with sides 10 ft and 14 ft. Then, their area together is:
2 * (10 ft * 14 ft) = 2 * (140 ft²) = 280 ft²
Therefore the total surface area of the box is the sum:
140 ft² + 196 ft² + 280 ft² = 616 ft²
Given that line S and line T are parallel, and line R is a transversal that cuts through lines S and T, which angles are alternate interior anglesZА A
Answers
The alternate interior angles theorem states that, when two parallel lines are cut by a transversal, the resulting alternate inferior angles are congruent.
In this case: