What is the area of the parallelogram shown? A) 60in B) 120in C) 140in D) 180in. + What is the area of a parallelogram that has a base 5 inches longer and the height 5 inches taller than a parallelogram shown? A) 230in B) 260in C) 290in D) 310in.

Answer:

6x+50=92

Step-by-step explanation:

The x is for how much the classes cost plus the amount they charged her for the gear.

Answer:

Read the explanation

Step-by-step explanation:

look at the photo

Applying the angles of intersecting chords theorem, the value of x in the first figure is: x = 7.

If two chords of a circle intersect, the angles of intersecting chords theorem states that, the measure of the angle formed equals 1/2(sum of the measure of the arcs which are intercepted.

Thus, we can use the angles of intersecting chords theorem to find missing angles or value of x in the questions given.

For example, let's find the value of x in the first figure given:

12x + 5 = 1/2(83 + 95)

12x + 5 = 89

12x = 89 - 5

12x = 84

x = 7

Using same strategy, you can solve the rest of the problem given.

Learn more about the angles of intersecting chords theorem on:

https://brainly.com/question/1626547

[tex]\text{A quadratic function is in the form of } ~ f(x)=ax^2 +bx+c.\\\\\\y=x+5 ~ \text{is linear so it is not in a form of quadratic function.}[/tex]

[tex]\dfrac 6p = x+a\\\\\implies \dfrac 6p \times\dfrac 16 = (x+a) \times\dfrac 16 ~~~~~~;\left[\text{Multiply both sides by}~ \dfrac 16 \right]\\\\\implies \dfrac 1p = \dfrac{x+a}6\\\\\implies p= \dfrac{6}{x+a}~~~~~~~~~~~~~~~~~~~~;[\text{Cross multiply}][/tex]

With ϕ ≈ 1.61803 the golden ratio, we have 1/ϕ = ϕ - 1, so that

[tex]I = \displaystyle \int_0^\infty \frac{\sqrt[\phi]{x} \tan^{-1}(x)}{(1+x^\phi)^2} \, dx = \int_0^\infty \frac{x^{\phi-1} \tan^{-1}(x)}{x (1+x^\phi)^2} \, dx[/tex]

Replace [tex]x \to x^{\frac1\phi} = x^{\phi-1}[/tex] :

[tex]I = \displaystyle \frac1\phi \int_0^\infty \frac{\tan^{-1}(x^{\phi-1})}{(1+x)^2} \, dx[/tex]

Split the integral at x = 1. For the integral over [1, ∞), substitute [tex]x \to \frac1x[/tex] :

[tex]\displaystyle \int_1^\infty \frac{\tan^{-1}(x^{\phi-1})}{(1+x)^2} \, dx = \int_0^1 \frac{\tan^{-1}(x^{1-\phi})}{\left(1+\frac1x\right)^2} \frac{dx}{x^2} = \int_0^1 \frac{\pi2 - \tan^{-1}(x^{\phi-1})}{(1+x)^2} \, dx[/tex]

The integrals involving tan⁻¹ disappear, and we're left with

[tex]I = \displaystyle \frac\pi{2\phi} \int_0^1 \frac{dx}{(1+x)^2} = \boxed{\frac\pi{4\phi}}[/tex]

Answer:

Maybe 8

Step-by-step explanation:

because its the same side

Answer:

See below ↓

Step-by-step explanation:

A) The Western Beach width decreases with increase in time whereas the Dune Beach width increases with increase in time.

B) Between Year 11 and Year 12

C) Find out the exact change in width per year for both beaches and plot them lines of change on a graph or as equations. Find where they intersect on the graph or solve the pair of equations to find out when they will both have the same width.

Answer:

  442 ft²

Step-by-step explanation:

The amount of insulation needed is the amount that covers the area of the side walls and the ceiling. The area of the side walls is the product of the perimeter and height. The area of the ceiling is the product of length and width.

__

Lateral area = Ph = 2(L+W)h = 2(15 ft +8 ft)(7 ft) = 322 ft²

Ceiling area = LW = (15 ft)(8 ft) = 120 ft²

__

Insulation needed = lateral area + ceiling area = 322 ft² +120 ft²

Insulation needed = 442 ft²

Answer:

f(x)-2x+4

Step-by-step explanation:

f(x)-g(x)

f(x)-g(x)=f(x)-(2x-4)

f(x)-(2x-4) remove parentheses for addition or subtraction

f(x)-2x+4

go into settings and click on subscription

Answer:   i think it will take 48 hours

Step-by-step explanation:

here's how to get 48 so basically 450-400-2= 48

now if you end up doing 400 - 450 then you will get -50 if you do 400-450-2 you will get a -52 so you want to make sure you do the biggest number first and then do the smaller numbers to get 48 like 450 - 400 - 2 and then you will have 48

i hope this helps!

Answer: C. 6t

Step-by-step explanation:

T is unknown, but because you are only asked for the equation to figure out the total,  you simply multiply the 6 chairs per t, or table together, 6t

Answer:

I would say 120 but that could be also be wrong but ill go with 120

Answer:

total mass is equal to

450g+840g+366g+1kg

=1626g+1000g

=2626g

mass is in kg so it is 2.626kg

2a means = 2 x a

if a = 4

3 x (2 x 4 + 6) = 3 x (8 + 6) = 3 x 14 = 42

Answer:

12x−9y−12z

Step-by-step explanation:

1. 16x−12y−3z−4x−(−3y)−9z

2. Combine 16x and −4x to get: (12x−12y−3z+3y−9z)

3. Combine −12y and 3y to get: (12x−9y−3z−9z)

4. Combine −3z and −9z to get: (12x−9y−12z)

Answer: 12x−9y−12z Step-by-step

explanation: 1. 16x−12y−3z−4x−(−3y)−9z 2. Combine 16x and −4x to get: (12x−12y−3z+3y−9z)3. Combine −12y and 3y to get: (12x−9y−3z−9z) 4. Combine −3z and −9z to get: (12x−9y−12z)

Answer: She would have to visit the movie theater 10 times.

Step-by-step explanation:

Step-by-step explanation:

I am not sure what the actual question is.

the general function for the amount of gathered reward points p with v visits to the theater is

p(v) = 14.5×v + 40 (40 starting points, 14.5 points per visit)

to know how many visits are needed for a certain amount of points (185) we need to solve that equation for v :

185 = 14.5×v + 40

145 = 14.5×v

v = 145/14.5 = 10

so, she needs at least 10 visits to gather the desired 185 points for a free ticket.

but that applies only to the first free ticket.

after that the function behavior kind of changes, because we have no more starting points :

so to get 2×185 = 370 points for 2 free tickets she will need

370 = 14.5×v + 40

330 = 14.5×v

v = 330/14.5 = 22.75862069...

we need to round up to the next whole number (because there can be no "part-visits").

so, she will need 23 visits for 2 free tickets (that means 13 more visits for the second free ticket).

Answer:

2 patients had more than 5 cavities.

step-by-step explanation:

Here cavities > 5

so only 2 patients had more than 5 cavities also as had total 7 cavities.

Answer:

2 patients had more than 5 cavities

Step-by-step explanation:

Each dot represents a different patient.

"More than 5" means numbers greater than 5 (so from 6 onwards).

From inspection of the dot plot, there are 2 dots above all the numbers that are greater than 5.

Therefore, there are 2 patients who had more than 5 cavities.

**see annotated dot plot**

The area shaded with a pink rectangle is "more than 5 cavities"

Answer:

it is .925 which is very close to 9/10 so C would be correct

Step-by-step explanation:

Answer:

0.925 so I would pick option C.

Answer:

B

Step-by-step explanation:

Answer:

The other personis wrong its answer A: a rotation and a dilation.

Step-by-step explanation:

I mean its kind of self explanatory but i hope it helps.

i got a 100% on my quiz with this question btw.

The price of the pen and the erasers Raphael and his friend bought are GHC 3 and GHC 1 respectively.

let

x = price of pen

y = price of erasers

The equation

8x + 9y = 33

5x + 6y = 21

48x + 54y = 198

45x + 54y = 189

48x - 45x = 198 - 189

3x = 9

x = 9/3

x = 3

substitute into (1)

8x + 9y = 33

8(3) + 9y = 33

24 + 9y = 33

9y = 33 - 24

9y = 9

y = 9/9

y = 1

How to solve simultaneous equation:

https://brainly.com/question/16863577

Answer:

[tex]90^{\circ}[/tex]. In other words, these two vectors are perpendicular (orthogonal) to one another.

Step-by-step explanation:

Let [tex]\|a\|[/tex] and [tex]\|b\|[/tex] denote the magnitudes of vector [tex]a[/tex] and vector [tex]b[/tex]. The dot product between these two vectors is represented as [tex]a^{T}\, b[/tex].  Let [tex]\theta[/tex] denote the angle between the two vectors. The cosine of this angle would be equal to:

[tex]\begin{aligned}\cos(\theta) &= \frac{a^{T}\, b}{\|a\| \|b\|}\end{aligned}[/tex].

The dot product between vector [tex]a = \langle 1,\, 2\rangle[/tex] and [tex]b = \langle 1,\, -1/2\rangle[/tex] is:

[tex]\begin{aligned}a^{T}\, b &= {\begin{bmatrix}1 \\ 2\end{bmatrix}}^{T}\, \begin{bmatrix}1 \\ -1/2\end{bmatrix} \\ &= 1 \times 1 + 2 \times \left(-\frac{1}{2}\right) \\ &= 0\end{aligned}[/tex].

The magnitudes of the two vectors are:

[tex]\begin{aligned}\| a \| &= \sqrt{1^{2} + 2^{2}} \\ &= 5\end{aligned}[/tex].

[tex]\begin{aligned}\| b \| &= \sqrt{1^{2} + \left(-\frac{1}{2}\right)^{2}} \\ &= \frac{1}{2}\, \sqrt{5}\end{aligned}[/tex].

Therefore:

[tex]\begin{aligned}\cos(\theta) &= \frac{a^{T}\, b}{\|a\| \|b\|} \\ &= \frac{0}{5 \times (\sqrt{5} / 2)} \\ &= 0\end{aligned}[/tex].

Among all angles between [tex]0^{\circ}[/tex] and [tex]180^{\circ}[/tex], the only angle with a cosine of [tex]0[/tex] is [tex]90^{\circ}[/tex]. Therefore, the angle between vector [tex]a[/tex] and vector [tex]b[/tex] must be [tex]90^{\circ}\![/tex]. Hence, these two vectors are perpendicular to one another.

The amount of water that the tank will contain at 6:10 PM that day is 4174 L.

The conversion rate of a physical quantity is the method by which a unit of measurement is changed from one process to another by following a standard conversion rate and dimensional analysis.

From the information given:

The difference in the water in the tank within these two periods is:

= 22917 L - 8077 L

= 14840 L

In one minute, the amount of Liter is:

= 14840/160

= 92.75 Liter/minute

Similarly, between 6:10 pm and 5:25 pm, there are 45 minutes difference.

Therefore, the amount of water that the tank will contain at 6:10 PM that

day is;
= 45 minutes × 92.75 Liter/minute

= 4174 Liters

Learn more about conversion rate here:

https://brainly.com/question/1810058

Answer:

Step-by-step explanation:

4x² - 0x - 9 = 4x² - 9 = (2x)² - 3² = (2x - 3)(2x + 3)

used: (a - b)(a + b) = a² - b²

Answer:

85cm^3

Step-by-step explanation:

Volume = Base Area * Height

17*5=85

Answer:

A

Step-by-step explanation:

because -98.4 is the opposite of 98.4 and 98.4 is it's absolute value

Answer:

Step-by-step explanation:

[tex]=5\displaystyle\int_{0}^{\pi/6}dx\displaystyle\int_{0}^{2}x\sec^2(xy)dy\\=5\displaystyle\int_{0}^{\pi/6}dx\displaystyle\int_{0}^{2}\sec^2(xy)d(xy)\\=5\displaystyle\int_{0}^{\pi/6}dx\tan(xy)|_{y=0}^{y=2}[/tex]

[tex]=5\displaystyle\int_{0}^{\pi/6}\tan(2x)dx\\=-\frac{5}{2}\ln\cos(2x)|_{0}^{\pi/6}\\=-\frac{5}{2}[\ln\cos(\pi/3) - \ln\cos(0)]\\[/tex]

[tex]=-\frac{5}{2}\ln{\frac{1}{2}[/tex]