What is the acceleration of a car that increases its velocity from 0 to 100 kilometers per hour in 10 seconds?

From the calculations and the free body diagram, the net force that acts on the body is 34.5 N

The net force refers to the force that is acting on a body. Let us note that the gravitational force and the normal force cancel out each other. Thus the two force that act on the body are the applied force and the frictional force.

Thus;

The  net force that acts on the body is;

40.2 N - 5.7 N = 34.5 N

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Answer:

the free body diagram models the forces acting on an object. The object or 'body' is usually shown as a box or a dot. The forces are shown as thin arrows pointing away from the centre of the box or dot. ... It is important to label each arrow to show the magnitude of the force it represents.

Answer:

put an X on the second one, the third one, the forth one, and the last one

Explanation:

can i get braineist pls

Answer:

I can't see the pic so I cannot ans

Answer:

55 km

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Explanation:

Answer:

Explanation:

The momentum of an object can be found by using the formula

momentum = mass × velocity

From the question

mass = 2 kg

velocity/speed = 3 m/s

We have

momentum = 2 × 3 = 6

We have the final answer as

Hope this helps you

Answer:

(Question) Which of these quantities is a vector?

(Answer) momentum

(Question) What is the representation of the momentum vector?

(Answer) an arrow

(Question) What is the formula for the momentum p?

(Answer) p=m⋅v

(Question) What happens to the total momentum in a system of two interacting objects when a net force is exerted upon the system?

(Answer) The total momentum is conserved.

(Question) What is the magnitude momentum of a 2 kg body that moves with a speed of 3 m/s?

(Answer) 6.0

Explanation:

just finished the quick check UwU

Explanation:

mass

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4

4

mass

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mass

4

4

4

4

4

Answer:

See Below

Explanation:

It is a change in the distribution of electric charge on one object because of  the influence a nearby object that has an electric charge.  So if an object with a negative charge is brought near to a neutral object, the neutral object will alter itself so that one side becomes more positive and the other side becomes more negative.

Electrostatic induction occurs whenever any object is placed in an electric field.

V = IR

6 V = I × 15 Ohms

I = 6 V : 15 Ohms

I = 0,4 A

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We want to find at what angle a projectile is launched given that at the highest point, the speed is 6m/s.

The launch angle of the projectile is 60°.

Remember that the only acceleration will appear on the vertical axis, and this is the gravitational acceleration, this means that on the horizontal axis we will have a constant speed.

Also remember that when an object is on its highest point, the vertical velocity is equal to zero, then it only has horizontal velocity (which we know it is a constant).

Then we can conclude that the horizontal velocity is equal to 6m/s.

If the angle is measured from the horizontal axis, we will have that the horizontal velocity is a projection on the x-axis of the initial speed, this is:

12m/s*cos(θ) = 6m/s

Now we can solve this for theta.

cos(θ) = (6m/s)/(12 m/s) = 1/2

θ = Acos(1/2) = 60°

The launch angle of the projectile is 60°.

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Answer:  15.9 m/s

Explanation:

KE = 1/2(mv^2)

190,000J = 1/2(3000kg)*v^2

1 J = 1 kg*m^2/s^2

190,000 kg*m^2/s^2 = 1/2(3000kg)*v^2

v^2 = (190,000 kg*m^2/s^2)/(1/2(3000kg))

v^2 = (190,000 kg*m^2/s^2)/(1500kg))

v^2 = 126.6667 m^2/s^2

v = 11.25 mm/s velocity of 3000kg vehicle

With the same kinetic energy, a vehicle of 1500kg would have a different velocity:

190,000 kg*m^2/s^2 = 1/2(1500kg)*v^2

190,000 kg*m^2/s^2 =(750kg)*v^2

v^2 = 253.33 m^2/s^2

v = 15.9 m/s

Answer:

C

Explanation:

Answer:

telescope

Explanation:

| AMNH. Before telescopes were invented, people gazed at the night sky with amazement and dreamed of a closer look. The invention of the telescope in 1608 gave humans their chance to explore the vastness of the Universe.

Answer:

The invention of the telescope

PLS MARK BRAINLIEST

Answer:

Displacement=10 meters

Explanation:

The displacement is the direct path from the first contact with the ball and the last spot it was seen in. The ball was kicked north 8 meters, meaning it was kicked vertically upward, and then it was kicked east 6 meters, or to the right. If we were to draw the displacement we would see that this is a right triangle. That means we can use the Pythagorean Theorem:

[tex]a^2+b^2=c^2\\8^2+6^2=c^2\\64+36=c^2\\c^2=100\\\sqrt{c} =\sqrt{100} \\c=10[/tex]

Boom.

The displacement is 10 m toward the northeast. The first option is correct.

The displacement is a vector quantity having both magnitude and direction. It is equal to the path length between the initial and final positions.

Given:

North displacement, y=8 m

East displacement, x= 6 m

The net displacement is calculated using Pythagoras' theorem as the displacements are perpendicular to each other.

The displacement is given by:

d=√(x²+y²)

d=√(8²+6²)

d=10 m

So, the displacement is 10 m.

Therefore, the displacement is 10 m toward the northeast. The first option is correct.

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Answer:

Virchow

Explanation:

Rudolf Virchow

Answer:

It is Rudolf Virchow! Hope this help and if I could get brainliest that would be much appreciated.

Explanation:

Answer:

7 feet because 2 feet and 5 feet make seven.

The acceleration is approximately 4 m/s². Therefore, the correct answer is:

A. 4 m/s²

To determine the acceleration from the graph, we need to look at how the velocity changes over time. Acceleration is defined as the rate of change of velocity with respect to time. In other words, it is the slope of the velocity-time graph.

Looking at the graph, we can see that the velocity changes from 0 m/s to 4 m/s over a time interval of 2 seconds. To calculate the acceleration, we use the formula:

Acceleration (a) = Change in velocity / Change in time

Acceleration (a) = (4 m/s - 0 m/s) / (2 s) = 4 m/s²

So, the acceleration is approximately 4 m/s². Therefore, the correct answer is:

A. 4 m/s²

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Find the distance traveled by a car that travels with an average speed of 110 km/h for 3.5 h

To solve for distance:

d = v t

d = 110 × 3.5

d = 385 km

How long does it take a baseball moving with an average speed of 35 m/s to travel 18 m?

To solve for time:

t = d/v

t = 18 / 35

t = 0.514286

t = 0.5 s

What is the average speed of a car that travels 870 km in 14.5 h?

To solve for average speed:

v = d/t

v = 870 / 14.5

v = 60 km/h

Answer:

Displacement = 8.4m

Explanation:

Hope that this is helpful.

Have a great day.

[tex]v = 60.7m {s}^{ - 1} \: u \: = 5.26m {s}^{ - 1 } \: t = 15s \: \: \: \: \: \\ a \: = \frac{v - u}{t} \\ a \: = \frac{60 .7- 5.26}{15} \\ a = 3.7m {s}^{ - 28} \\ {v}^{2} = {u}^{2} + 2as \\ {60.7}^{2} = {5.26}^{2} + 2 \times 3.7 \times s \\ 60.7 =27 .7 + 2 \times 3.7s \\60.7 = 29.7 \times 3.7s \\ 60.7 - 29.7 = 3.7s \\ 31 = 3.7s \\ \frac{31}{3.7} = \frac{3.7s}{3.7} \\ s = 8.4m[/tex]

Answer:

The acceleration of the car was one meter per second squared.

Explanation:

We can use one of the kinematic equations:

[tex]\displaystyle v_f = v_i + at[/tex]

Where v_f is the final velocity, v_i is the initial velocity, a is the acceleration, and t is the time (in seconds).

The final velocity is 40 m/s, the initial velocity is 35 m/s, and the time is 5 s. Substitute and solve for a:

[tex]\displaystyle \begin{aligned}(40 \text{ m/s}) &= (35 \text{ m/s}) + a(5\text{ s}) \\ \\ 5 \text{ m/s} &= a(5\text{ s}) \\ \\ a &= 1\text{ m/s$^2$} \end{aligned}[/tex]

In conclusion, the acceleration of the car was one meter per second squared.

This cart would move with constant velocity or be at rest because the net force is equal to zero (0), which means the three (3) forces acting on the cart opposes each other.

Given the following data:

To find the net force acting on the cart:

A net force can be defined as the vector sum of all the forces that are acting on a physical object or body.

This ultimately implies that, a net force is a single (one) force that substitutes the effect of all the forces acting on a physical object or body.

Mathematically, net force is given by the following:

[tex]Net \;force = F_1 + F_2 + F_3 + F_4 + .....F_n[/tex]

Where:

[tex]Net\; force = 60 + 30 + (-90)\\\\Net\; force = 90 - 90[/tex]

Net force = 0 Newton

Based on Newton's First Law of Motion, this cart would move with constant velocity or be at rest because the net force is equal to zero (0), which means the three (3) forces acting on the cart opposes each other.

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Answer:

1.0147 rounded to the nearest thousandths place is 1.015

Answer:

1.015

Explanation:

If you put the number in place value, you have 1 in the ones place, 0 in the tenths place, 1 in the hundreds place, 4 in the thousandths place, and 7 in the ten thousandths place. In order to know how to round 4, you must look at the number directly after it. Since 7 is greater than five, round up to ten. This increases 4 by 1 which would give you the answer 1.015.

We have that  the final velocity of a ball thrown downward at 10 m/s after 2 seconds is

V=29.6m/s

From the question we are told

What is the final velocity of a ball thrown downward at 10 m/s after 2 seconds?

Where

Generally the Newton's equation for Motion   is mathematically given as

[tex]V=U+at\\\\V=U+gt\\\\V=10+9.8*2\\\\V=29.6m/s[/tex]

Therefore

the final velocity of a ball thrown downward at 10 m/s after 2 seconds is

V=29.6m/s

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Answer:

95

Explanation:

Answer:

Explanation:

oh wait you ask what type of light on the electricity as the lowest energy per photo so is like taking a photo yet to be like make up your mind

Answer:

C) the heat needed to boil some water

Explanation: