The third quadrant of the unit circle is the region of the circle that lies between 180 degrees and 270 degrees
The unit circle is a circle with a radius of 1 centered at the origin of the coordinate plane.
In the coordinate plane, the third quadrant is the quadrant that lies below the x-axis and to the left of the y-axis.
To find what is in the third quadrant of the unit circle, we need to look for the points on the circle that have negative x-coordinates and negative y-coordinates.
Since the radius of the unit circle is 1, we know that any point on the circle can be represented in terms of sine and cosine. Specifically, for any point (x, y) on the circle, we have:
x = cos(θ)
y = sin(θ)
where θ is the angle between the positive x-axis and the line connecting the origin and the point (x, y).
In the third quadrant, both the x-coordinate and the y-coordinate are negative. Therefore, we need to find the angle θ such that cos(θ) is negative and sin(θ) is negative.
We know that cos(θ) is negative in the second and third quadrants, and sin(θ) is negative in the third and fourth quadrants. Therefore, the third quadrant of the unit circle contains the points where:
cos(θ) is negative (i.e., θ is between 90 and 270 degrees or π/2 and 3π/2 radians), and
sin(θ) is negative (i.e., θ is between 180 and 360 degrees or π and 2π radians).
So the third quadrant of the unit circle contains all the points where:
-1 ≤ x ≤ 0 (cosine is negative in this quadrant), and
-1 ≤ y ≤ 0 (sine is also negative in this quadrant).
In other words, the third quadrant of the unit circle is the region of the circle that lies between 180 degrees and 270 degrees (or π and 3π/2 radians) and has both x and y values that are negative.
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Let f(x) = √ x − 1 x − 3 .
(i) Evaluate f(4), f(5) and f(a + 1).
(ii) Find the domain of f.
(i) a
(ii) {x | x ∈ R, x ≠ 3, x ≥ 1}
(i) To evaluate f(4), f(5), and f(a + 1), we replace x with 4, 5, and a + 1 in f(x) respectively. We have; f(4) = √ 4 − 1 4 − 3= √ 3 1= √ 3f(5) = √ 5 − 1 5 − 3= √ 4 2= 2f(a + 1) = √ a + 1 − 1 a + 1 − 3= √ a 2= a
(ii) Domain of f:The expression in the denominator cannot be equal to zero, so we must ensure that x − 3 ≠ 0. Therefore, x ≠ 3The expression in the square root must be greater than or equal to zero, so we must ensure that x − 1 ≥ 0. Therefore, x ≥ 1The domain of f is {x | x ∈ R, x ≠ 3, x ≥ 1}.
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I need help, thank you.
Answer:
x ≈ 12.33
Step-by-step explanation:
given 2 secants from an external point to the circle, then the product of the measures of one secant's external part and the entire secant is equal to the product of the measures of the other secant's external part and that entire secant, that is
DC × (DC + x) = BC × (BC + AB) , that is
6(6 + x) = 5 × (5 + 17) = 5 × 22 = 110
36 + 6x = 110 ( subtract 36 from both sides )
6x = 74 ( divide both sides by 6 )
x = 12.33 ( to the nearest hundredth )
-26 ___ 25
=
<
≤
≠
>
≥ im being timed hurry pls
Answer:25 percent means one fourth. To calculate 25 percent of a number, simply divide it by 4. For example, 25 percent of 12 is 12 divided by 4, or 3
A helicopter hovers 500 feet
above a small island. The figure
shows that the angle of
depression from the helicopter
to point P is 48°
How far off
the coast, to the nearest foot, is
the island?
kira will rent a car for the weekend. she can choose one of two plans. the first plan has an initial fee of $45 and costs an additional $0.30 per mile driven. the second plan has no initial fee but costs $0.80 per mile driven. for what amount of driving do the two plans cost the same? miles what is the cost when the two plans cost the same? $
The two plans will cost the same if Kira drives 90 miles over the weekend.
The two plans cost the same when Kira drives 90 miles, and the cost of each plan is $72.
To find the mileage for which the two plans cost the same and the cost at that mileage, you should set the cost expressions for both plans equal to each other. After that, you will solve for the mileage (x).
The steps to do this are as follows:Let the mileage be x
The cost of plan 1 (C1) is given by:
C1 = 45 + 0.30x
The cost of plan 2 (C2) is given by:
C2 = 0.80 x
To find the mileage at which both plans cost the same, set C1 equal to C2 and solve for x:
45 + 0.30 x = 0.80 x x (0.30 - 0.80) = - 45- 0.50 x = -45 x = -45/-0.50 x = 90
To find the cost when the two plans cost the same,
substitute x = 90 into one of the expressions for cost.
C1 = 45 + 0.30x = 45 + 0.30(90) = 45 + 27 = $72C2 = 0.80x = 0.80(90) = $72
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Find the missing number 11:15=—:135
Answer:99
Step-by-step explanation:
Answer: 99
Step-by-step explanation:
135 is 9 times of 15
To get the missing number, multiply 11 by 9,
11 x 9 = 99
I NEED HELP ASAP
Solve the polynomial
x^3-7x^2-x+7=0
Answer:
x = 1, x = 7, and x = -1.
Step-by-step explanation:
o solve the polynomial equation x^3 - 7x^2 - x + 7 = 0, we can use a combination of synthetic division and factoring by grouping:
First, we need to find a root of the polynomial using the Rational Root Theorem. The possible rational roots of the polynomial are the factors of 7 (the constant term) divided by the factors of 1 (the leading coefficient), or ±1, ±7. By trying each of these values in the polynomial, we find that x = 1 is a root.
Using synthetic division, we can divide the polynomial by (x - 1) to obtain a quadratic equation:
1 | 1 -7 -1 7
| 1 -6 -7
|_____________
1 -6 -7 0
Therefore, (x - 1) is a factor of the polynomial, and we have:
x^3 - 7x^2 - x + 7 = (x - 1)(x^2 - 6x - 7)
Now we need to solve the quadratic equation x^2 - 6x - 7 = 0. We can factor it as (x - 7)(x + 1) = 0, so the solutions are x = 7 and x = -1.
Therefore, the solutions to the original polynomial equation x^3 - 7x^2 - x + 7 = 0 are x = 1, x = 7, and x = -1.
Enter an equation for the balance,b, in the account after n months
An equation for the balance, b, in the student's savings account after n months is b = d - wn.
What is an equation?An equation is a mathematical or algebraic statement showing that two or more mathematical or algebraic expressions are equal or equivalent.
An equation is denoted using the equal symbol (=), which an algebraic expression lacks.
Mathematical expressions combine variables with numbers, constants, or values using mathematical operands.
The amount in the savings account = d
Monthly withdrawals = w
The period of withdrawals = n
Let the balance in the account after n months = b
Therefore, the balance after n months will be represented by the equation, b = d - wn.
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Complete Question:A student has a savings account with d dollars in it. The student plans to withdraw w dollars each month for n months. Enter an equation for the balance, b, in the account after n months.
A rectangular Inflatable swimming pool is 3 yards long, 14/5 yards wide, and
7/2 yards tall
. What is the volume of the pool? Round to the nearest tenth
The volume of the rectangular inflatable swimming pool is approximately 29.4 cubic yards.
The volume of an object is the amount of space it occupies in three dimensions, typically measured in cubic units. In this case, we're trying to find the volume of a rectangular pool that is 3 yards long, 14/5 yards wide, and 7/2 yards tall.
To find the volume of a rectangular object, we use the formula:
Volume = length x width x height
In this case, we can plug in the values we have:
Volume = 3 yards x 14/5 yards x 7/2 yards
To simplify the calculation, we can convert the fractions to decimals:
Volume = 3 yards x 2.8 yards x 3.5 yards
Volume = 29.4 cubic yards
In this case, the second decimal place is a 4, so we leave the digit in the first decimal place (9) as-is.
Therefore, we round our answer to 29.4 cubic yards to the nearest tenth.
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For [tex]x^8-1=0[/tex], find all complex solutions, magnitudes of the roots, and draw them on the complex plane.
For the equation [tex]x^8-1=0[/tex], the graph with magnitudes of the roots is plotted on complex plane.
What is an equation?
A mathematical definition of an equation is a claim that two expressions are equal when they are joined by the equals sign ("=").
The equation is given as [tex]x^8-1=0[/tex].
We can start by factoring the left-hand side of the equation using the difference of squares formula -
[tex](x^4 - 1)(x^4 + 1) = 0[/tex]
Now we have two factors that can each be set equal to zero and solved separately -
[tex]x^4 - 1 = 0[/tex] or [tex]x^4 + 1 = 0[/tex]
The first equation can be factored as a difference of squares again -
(x² - 1)(x² + 1) = 0
Setting each factor equal to zero gives -
x² - 1 = 0 or x² + 1 = 0
These equations have solutions x = ±1 and x = ±i, respectively.
For the second equation, we can use the fact that i^2 = -1 to rewrite it as -
[tex]x^4 + 1 = (x^2)^2 + 1 = (x^2 + i)(x^2 - i) = 0[/tex]
Setting each factor equal to zero gives -
x² + i = 0 or x² - i = 0
These equations have solutions [tex]x = \pm i\sqrt{2}[/tex] and [tex]x = \pm i\sqrt{-2} = \pm i\sqrt{2i} = \pm \sqrt{2}i[/tex], respectively.
Therefore, the complete set of solutions to the original equation is -
x = ±1, ±i, ±i√(2), ±√2 i
To find the magnitudes of these roots, we can use the formula -
|a + bi| = √(a² + b²)
For example, the magnitude of the root x = i is -
|i| = |0 + 1i| = √(0² + 1²) = 1
Similarly, we can find the magnitudes of the other roots -
|x| = 1 for x = ±1, ±i
|x| = √2 for x = ±i√(2)
|x| = √2 for x = ±√2 i
To draw these roots on the complex plane, we can plot them according to their real and imaginary parts.
The roots ±1 and ±i lie on the unit circle centered at the origin, while the roots ±i√(2) and ±√2 i lie on circles centered at the origin with radii equal to √2.
Therefore, the roots are plotted in complex plane.
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Solve for x.
a. 4°
b. 4. 5°
c. 6°
d. 11. 5°
The cοrrect answer is d. 11.5°, This is because the equatiοn 4x = 46 can be rearranged tο x = 46/4 = 11.5.
What is equatiοn?An equatiοn is a mathematical statement that describes the relatiοnship between twο values using an equal sign. It cοnsists οf twο expressiοns οn either side οf the equal sign, and the expressiοns must be equal in οrder fοr the equatiοn tο be true. Equatiοns are used tο sοlve prοblems and tο understand hοw different variables interact with each οther.
Fοr example, the equatiοn "2 + 2 = 4" is true because twο plus twο dοes in fact equal fοur. Equatiοns can alsο be used tο represent physical phenοmena, such as the equatiοn F = ma, which describes the relatiοnship between fοrce and mass. Equatiοns can be used tο sοlve many prοblems in mathematics, science, engineering, ecοnοmics, and οther fields.
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A line is breaking a segment into two making two angles, one of the angle is 46° which 4 times the other angle x. Solve for x
a. 4°
b. 4. 5°
c. 6°
d. 11. 5°
by applying the compound angles and without using a calculator. Determine the value of sin105
Therefore, the value of sin105° is: = 0.7123
What is value?Value is a measure of the worth or importance of something. It is a subjective measure, as it is based on a person's individual beliefs, experiences, and values. Value can be seen in the monetary cost of a product or service, the quality of a product or service, the time spent on a task, or the amount of effort put into creating something. Value can also be intangible, such as the feeling of having achieved a goal or a sense of accomplishment. Value can be used to assess the worth of something, as well as to determine whether something is worth pursuing or investing in.
The value of sin105° can be determined by applying the compound angles formula. The formula states that the sine of an angle is equal to the product of the sine and cosine of the other two angles that make up the original angle.
For the angle 105°, the two other angles are 75° and 30°. Therefore, the sine of 105° can be calculated as follows:
sin105° = sin75° x cos30° + cos75° x sin30°
Using the values of sin75° and cos30° from a trigonometry table, we can calculate the sine of 105° as:
sin105° = 0.9659 x 0.5 + 0.2588 x 0.5
Therefore, the value of sin105° is:
sin105° = 0.7123
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Agriculture: You own an empty one acre lot. (640 acres = 1 mi²; 1 mi = 5,280 ft)
a. If 1 inch of rain fell over your one acre lot, how many cubic inches of water fell on your lot?
b. How many cubic feet of water fell on your lot?
c. If 1 cubic foot of water weighs about 62 pounds, what is the weight of the water that fell on your lot?
d. If the weight of 1 gallon of water is approximately 8.3 pounds, how many gallons of water fell on your lot?
a) 6272640 cubic inches of water fell on the lot
b) 3630 cubic feet of water fell on the lot
c) the weight of the water that fell on the lot = 112.53 tons
d) gallons of water fell on the lot = 27,115.7 gallons
Converting acre into sq ft460 acre=1 [tex]mi^{2}[/tex]
1 acre=1/460 [tex]mi^{2}[/tex]
1 mi=5280 ft
1 mi2=5280×5280[tex]ft^{2}[/tex]
1 acre=(5280×5280)/460
1 acre= 43560 sq ft
Solving the part (a)As one inch is equal to one-twelfth of a foot, one acre of water that is 1 inch deep takes up 3630 cubic feet (43560×(1/12)).
One cubic foot is equal to 12 inches by 12 inches by 12 inches,
or 12×12×12=1728 cubic inches.
6272640 cubic inches are contained in 3630 cubic feet, or 3630 × 728.
Hence, 6272640 cubic inches of water fell on the lot.
Solving the part (b)If 1 inch of rain fell over your one acre lot, 3630 cubic feet of water fell on the lot.
Solving the part (c)3630 times 62 is 225,060 pounds, the weight in pounds.
We are aware that a tons weighs 2000 lb.
225060/2000 = 112.53 tons
Hence, the weight of the water that fell on the lot=112.53 tons.
Solving the part (d)If there are around 8.3 pounds in 1 gallon of water,
Number of gallons of water fell on the lot
=225060/8.3
=27,115.7 gallons
Hence, gallons of water fell on the lot=27,115.7 gallons.
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Ellen has three packages of markers. Exactly 10 of the markers in each package are yellow markers. • Package T contains 10 markers. • Package V contains 40 markers. • Package W contains 40 markers.
Ellen will randomly select one marker from each package. Which statements are true?
Select the three that apply.
A. The probability of selecting a yellow marker from Package T is 1.
B. The probability of selecting a yellow marker is equal for packages V and W.
C. The probability of randomly selecting a yellow marker from Package V is 1 / 3 .
D. The probability of selecting a yellow marker is less for Package W than it is for Package T.
E. The probability of selecting a yellow marker from Package V is four times the probability of selecting a yellow marker from Package T.
Answer: B and D
Step-by-step explanation:
Bianca said that if k is a real number, then the solution set of the compound inequality xk is all real numbers. Do you agree? Justify your argument.
Well, I do agree that if k is a real number, then the compound inequality xk's solution set contains only real numbers.
A sentence with two inequality statements connected by the words "or" or "and" is referred to as a compound inequality. The word "and" indicates that both claims in the compound sentence are true at the same time. It occurs when the multiple statement's solution sets overlap or intersect. Compound inequalities are those that have the conjunctions "and" or "or" between them. It should be understood that plimb[/[/ofs (Ors Or/ Orss ultras "is larger than -2 and less than or equal to 5" should be translated as 2 x 5. x is greater than or equal to 3 or equal to -4, or "x 3." You'll observe that each of these differences has two inequality signals. Inequality that is compounded by two or more factors.
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Model Real Life A recipe calls for (1)/(2) cup of soy sauce. You only have a quarter cup for measuring. How many quarter cups do you need for the recipe?
This implies that since (1/2) cup is equal to 2 quarter cups, the amount of soy sauce required for the recipe is 2 quarter cups.
what is unitary method ?By first determining the value of one unit and afterwards multiplying or dividing to determine the value of another unit, the unitary method is a mathematical strategy used to solve proportional problems. The "single unit" or "one unit" technique is another name for it. The unitary technique entails segmenting a problem into manageable pieces before determining the value of one unit of the specified quantity.
given
We must establish how many quarter cups are equal to (1/2) cup in order to quantify soy sauce using a quarter cup.
Starting with the knowledge that 1 cup is equal to 4 quarter cups, we can write:
4 quarter glasses equal 1 cup.
(1/2) cup is therefore equal to:
1/2 cup equals 1/2 * 4 quarter cups, or 1/2 cup equals 2 quarter cups.
This implies that since (1/2) cup is equal to 2 quarter cups, the amount of soy sauce required for the recipe is 2 quarter cups.
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Divide 81 into scale 2:1
Answer:
Below
Step-by-step explanation:
You want to divide 81 into (2+1 = 3) parts
81 / 3 = 27 for each part
2 parts would be 2 * 27 = 54
so 2:1 would be 54:27
The following table shows the order in which certain ingredients labeled a - f need to be mixed
The final component, either before or after C, is F.
Ingredients A through F must be combined (left goes first, right goes last). Also, we are aware that: Ingredients A and D are introduced in succession; B is added before to A; and F is not added immediately prior to or following C.
Which component should be inserted last?
The aforesaid issue is easily resolved by doing the following:
Ingredient labeling: A, B, C, D, E, and F
It is given,
Ingredient A is added before D in the order of adding ingredients A and D.
To A, B is added first.
F is no longer put immediately before or after C.
The leftover ingredients are C, E, and F.
F cannot come before or after C because of this.
C can therefore come after D.
component following C = E
Ingredient list = F
The complete question is-
The following table shows the order in which certain ingredients, labeled A through F, need to be mixed (left goes first, right goes last). Additionally, we know that: Ingredients A and D are added in consecutive steps; B is added before A; F is not added right before or after C. Which ingredient needs to be added last?
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Write an exponential function in the form y=ab^xy=ab
x
that goes through points (0, 14)(0,14) and (3, 3024)(3,3024).
The exponential function that passes through the points (0, 14) and (3, 3024) is [tex]$$y = 14\cdot 6^x$$[/tex]
How to find the function using points?To find the values of a and b in the exponential function [tex]$y=ab^x $[/tex]that goes through the given points (0, 14) and (3, 3024), we can use the following system of equations:
[tex]$\begin{align*}a\cdot b^0 &= 14 \a\cdot b^3 &= 3024\end{align*}[/tex]
Simplifying the first equation, we get a=14. Substituting this value into the second equation, we get:
[tex]14(b)^3=3024\\= b^3= 216\\= b=6[/tex]
Therefore, the exponential function that goes through the given points is:
[tex]$$y = 14\cdot 6^x$$[/tex]
We can check that this function satisfies both of the given points:
[tex]$\begin{align*}y &= 14\cdot 6^0 = 14 &&\text{when } x=0 \y &= 14\cdot 6^3 = 3024 &&\text{when } x=3\end{align*}[/tex]
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3. 8, 15, 100, 123.
4. line the numbers up to multiply them from the y side or x side
5. adding the word problem to find the solution
There are four numbers: 8, 15, 100 and 123.
What is number?Number is a mathematical object used to count, measure, and label. It is used in many different contexts, from everyday life to scientific research. Numbers can be represented in various forms, such as symbols, digits, and words. They are used to represent quantities, distances, time, and other concepts. Numbers can also be used to represent relationships, such as equations, which are statements that describe how two or more things are related.
To solve this problem, it is best to line the numbers up on the y axis or x axis. To multiply the numbers, start by multiplying the numbers on the y axis first. So, 8 x 15 = 120. Then, multiply the result by the number on the x axis which is 100. 120 x 100 = 12,000. Finally, multiply 12,000 by the last number on the x axis which is 123. 12,000 x 123 = 1,476,000. Therefore, the answer to the problem is 1,476,000.
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In Princeton, the library is due south of the courthouse and due west of the community swimming pool. If the distance between the library and the courthouse is 7 miles and the distance between the courthouse and the city pool is 8 miles, how far is the library from the community pool? If necessary, round to the nearest tenth.
Please respond.
Thank you!
Answer:
3.9 miles
Step-by-step explanation:
To find:-
Distance between library and community pool .Answer:-
The given situation is represented in the attachment.
We can see that there is a formation of right angled triangle , hence we can use Pythagoras theorem here , according to which,
[tex]\rm\implies a^2+b^2=h^2 \\[/tex]
where h is the longest side (hypotenuse) of the triangle of the triangle . From the attached figure we can see that 8miles is hypotenuse and one of the other side is 7miles .
On substituting the respective values, we have;
[tex]\rm\implies 7^2+b^2=8^2 \\[/tex]
[tex]\rm\implies 49+b^2=64 \\[/tex]
[tex]\rm\implies b^2 = 64-49\\[/tex]
[tex]\rm\implies b =\sqrt{15}\\[/tex]
[tex]\rm\implies \red{b = 3.9 } \\[/tex]
Hence the distance between the swimming pool and the Library is 3.9 miles .
100 pts and brainlist for SIMPLE math problem
Stockton lake lost the least amount of water.
What is Denominator?
In mathematics, the denominator is the bottom number in a fraction that indicates the number of equal parts into which a whole is divided.
To compare the amount of water lost by each lake, we need to express the amounts lost in the same units. One way to do this is to find a common denominator for the fractions and percentages involved.
Lake Jensen lost 5/6 of its water, which can be expressed as a fraction with a common denominator of 300:
5/6 = 250/300
Lake Parlow lost 85% of its water, which can be expressed as a fraction with a denominator of 100:
85% = 85/100 = 255/300
Lake Stockton lost 246/300 of its water, which is already in terms of a common denominator of 300.
Now we can compare the amounts lost directly:
Lake Jensen lost 250/300 of its water
Lake Parlow lost 255/300 of its water
Lake Stockton lost 246/300 of its water
To determine which lake lost the least amount of water, we need to find the smallest fraction among these three.
We can see that Lake Stockton lost the least amount of water, since 246/300 is smaller than both 250/300 and 255/300. Therefore, Lake Stockton lost the least amount of water.
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Write the equation of the trigonometric graph. Use a positive coefficient on cosine for this activity.
The cosine function's positive coefficient ensures that the curve moves trigonometry downward from its highest point rather than upward from its lowest point.
what is trigonometry?The area of mathematics called trigonometry examines how triangle side lengths and angles relate to one another. The subject first came to light in the Hellenistic era, roughly in the third century BC, as a result of the use of geometry in astronomical investigations. The area of mathematics known as exact techniques deals with several trigonometric functions and possible computations using them. There are six common trigonometric functions in trigonometry. These go by the designations sine, cosine, tangent, cotangent, secant, and cosecant, respectively (csc). The study of triangle properties, particularly those of right triangles, is known as trigonometry. Consequently, studying geometry entails learning about the characteristics of all geometric shapes.
A trigonometric equation involving a cosine function with a positive coefficient looks like this:
y = 2cos(x) (x)
If this equation were graphed, a cosine curve with a period of 2 would be visible, oscillating between a maximum value of 2 and a minimum value of -2. The cosine function's positive coefficient ensures that the curve moves downward from its highest point rather than upward from its lowest point.
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Reflect (-3, -8) across the y-axis.
Then reflect the result across the x-axis.
What are the coordinates of the final point?
Answer:
(3, 8)
Step-by-step explanation:
Coordinate (-3, -8)
Reflect across the y-axis. The x will change to the opposite, and the y will remain the same. So, the coordinate is (3, -8)
Then reflect the result across the x-axis. The y will change to the opposite, and the x will remain the same. So, the coordinate is (3, 8)
So, the coordinate of the final point is (3, 8)
any answers for these two questions?
[tex]\large\textsf{Answer:}[/tex]
[tex]\mathtt{x = 9.4}[/tex]
[tex]\mathtt{y = 14.3}[/tex]
[tex]\textsf{Please see below.}[/tex]
[tex]\large\textsf{Step-by-step explanation:}[/tex]
[tex]\textsf{For these problems, we are asked to solve for the missing variables.}[/tex]
[tex]\textsf{To start, we have \underline{2 exterior angles} and \underline{2 secant lines }that \underline{intersect} at a \underline{vertex}.}[/tex]
[tex]\boxed{\Large\textsf{What is a Vertex?}}[/tex]
[tex]\textsf{A \underline{Vertex} is a \underline{point of intersection} of \underline{2} or more \underline{lines.}}[/tex]
[tex]\boxed{\Large\textsf{What are Exterior Angles?}}[/tex]
[tex]\textsf{\underline{Exterior Angles} are \underline{angles} that are \underline{outside} of a circle.}[/tex]
[tex]\boxed{\Large\textsf{What are Secant Lines?}}[/tex]
[tex]\textsf{\underline{Secent Lines} are \underline{lines} that intersect a circle \underline{twice}.}[/tex]
[tex]\textsf{Because we have Intersecting Secants \underline{outside} of the circle, we should use this formula;}[/tex]
[tex]\mathtt{a(a+b)=c(c+d)}\\[/tex]
[tex]\textsf{Smaller segment is first, then the larger segment is inside the parentheses.}[/tex]
[tex]\underline{\textsf{Substitute values from 10;}}[/tex]
[tex]\mathtt{5(5+x)=6(6+6)}[/tex]
[tex]\underline{\textsf{Multiply:}}[/tex]
[tex]\mathtt{25+5x = 72}[/tex]
[tex]\underline{\textsf{Subtract 25 from both sides:}}[/tex]
[tex]\mathtt{5x = 47}[/tex]
[tex]\underline{\textsf{Divide by 5:}}[/tex]
[tex]\boxed{\mathtt{x = 9.4}}[/tex]
[tex]\textsf{Let's do the same for 11.}[/tex]
[tex]\underline{\textsf{Substitute values from 11;}}[/tex]
[tex]\mathtt{10(10+y)=9(9+18)}[/tex]
[tex]\underline{\textsf{Multiply:}}[/tex]
[tex]\mathtt{100+10y=243}[/tex]
[tex]\underline{\textsf{Subtract 100 from both sides:}}[/tex]
[tex]\mathtt{10y=143}[/tex]
[tex]\underline{\textsf{Divide by 10:}}[/tex]
[tex]\boxed{\mathtt{y=14.3}}[/tex]
Sean throws the discus at a school meet and the height of the discus is given by the function h=-16+2 + 38t + 5, where h is in feet and t represents the seconds after throwing. A. What is the initial height of the discus? b. After how many seconds does it take for the discus hit the ground?
Hence, in response to the provided question, we can say that As a result, function the discus takes approximately 0.03125 seconds to strike the ground.
what is function?Mathematicians research numbers and their variants, equation and related structures, objects and their locations, and prospective locations for these things. The term "module" is used to describe the connection that exists in between set of inputs, each of which has a corresponding output. A function is an input-output connection in which each inputs results in something like a single, distinct return. A domain, codomain, or scope is assigned to each function. Functions are usually denoted by the letter f. (x). An x is used for entry. On capabilities, one-to-one capabilities, multiple prowess, in capabilities, and on capabilities are the four major types of accessible functions.
The supplied function for discus height is as follows:
[tex]h(t) = -16t^2 + 38t + 5\\h(0) = -16(0)^2 + 38(0) + 5 = 5[/tex]
As a result, the discus's starting height is 5 feet.
[tex]-16t^2 + 38t + 5 = 0\\[/tex]
To find t, we can apply the quadratic formula:
t = (-b \sqrt(b2 - 4ac)) (2a)
where a=-16, b=38, and c=5.
[tex]t = (-38 + \sqrt(38^2 - 4(-16)(5))) / (2(-16))\\t = (-38 + \sqrt(1524)) / (-32) (-32)\\t = (-38 + 39) / (-32) (-32)\\[/tex]
As a result, [tex]t = (-38 + 39) / (32) or t = (-38 - 39) / (32) (-32)[/tex]
t = 1/32 or t = 77/32
As the negative value doesn't make sense in this situation, we chose the positive value:
t = 1/32
As a result, the discus takes approximately 0.03125 seconds to strike the ground.
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please help
30 points
The baker can decorate 1.4 or 1 1/3 of cupcakes in a minute.Step-by-step explanation: 42 cupcakes in 30 minutes so if you divide 42 cupcakes in 30 groups you get 1 in each group and 12 left so if make 30 in 3 it makes 4 in each group but it is 30 so you make the four in to a 0.4 or 1/3 which is 1.4.You can also multiply if you make 1.4 into 14 x 3 = 42 same as 1.4 x 30 = 42 so the answer is 1.4.
Q8) What sum of money lent out at 12 per cent p.a. simple interest would produce * 9000 as interest in 2 years?
simple interest would produce ₹ 9000 as interest in 2 years? Rate = 12% p.a. Principal = ? Hence, the required principal amount = ₹ 37500
Answer:
SI=P*R*T/100
SI=9000*12*2/100
SI=2160
TOTAL AMOUNT=2160+9000=11160
Please help. I have a test today
at point E(-7, -24) lies on the circle whose equation is x^2+y^2=625. if an angle is drawn in standard position and its terminal ray passes through E, what is the value of sine of this angle
The sine of the angle passing through point E on the circle is given as follows:
sin(x) = 24/25.
What are the trigonometric ratios?The three trigonometric ratios are the sine, the cosine and the tangent, and they are defined as follows:
Sine of angle = length of opposite side to the angle divided by the length of the hypotenuse.Cosine of angle = length of adjacent side to the angle divided by the length of the hypotenuse.Tangent of angle = length of opposite side to the angle divided by the length of the adjacent side to the angle.The equation of the circle is of x² + y² = 625, meaning that the radius, representing the hypotenuse, is of 25 units.
The center of the circle is of (0,0), hence the opposite side to the angle has length of 24 - 0 = 24 units, hence the sine of the angle is given as follows:
sin(x) = 24/25.
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