what is 18 + (31-19) x 3​

Answer:

Step-by-step explanation:

[2,∞)

Answer:

it's 2

Step-by-step explanation:

Answer:

Value of f[g(x)] = 3x² + 5

Step-by-step explanation:

Given:

f(x) = 3x - 1

g(x) = x² + 2

Find:

Value of f[g(x)]

Computation:

f(x) = 3x - 1

g(x) = x² + 2

So,

f[g(x)] = 3(x² + 2) - 1

f[g(x)] = 3x² + 6 - 1

Value of f[g(x)] = 3x² + 5

Answer: -11

Step-by-step explanation:

4(-2)-3

-8-3

=-11

Answer:

[tex]BA = 6.0[/tex]

[tex]BC = 13.4[/tex]

Step-by-step explanation:

Given

The attached triangle

Solving (a) BA

Considering the tangent of angle C, we have:

[tex]tan\ C = \frac{BA}{AC}\\[/tex]

This gives:

[tex]tan\ 25 = \frac{BA}{12}[/tex]

Make BA the subject

[tex]BA = 12 * tan\ 25[/tex]

[tex]BA = 12 * 0.4663[/tex]

[tex]BA = 6.0[/tex] --- approximated

Solving (a) BC

Using Pythagoras theorem

[tex]BC^2 = BA^2 + AC^2[/tex]

[tex]BC^2 = 6.0^2 + 12^2[/tex]

[tex]BC^2 = 180[/tex]

Square root of both sides

[tex]BC = \sqrt{180[/tex]

[tex]BC = 13.4[/tex]

The correct answer is System B can be obtained from System A by replacing x in the second equation with the expression 1 + 4y and simplifying the resulting equations.

To obtain System B from System A, we can perform the following steps:

Start with System A:

System A:

x - 4y = 1

5x + 6y = -5

Solve the first equation in System A for x:

x = 1 + 4y

Substitute the value of x in the second equation of System A:

5(1 + 4y) + 6y = -5

Simplify and solve for y:

5 + 20y + 6y = -5

26y = -10

y = -10/26

y = -5/13

Substitute the value of y back into the equation we found in step 2:

x = 1 + 4(-5/13)

x = 1 - 20/13

x = (13 - 20)/13

x = -7/13

Write down the equations with the values of x and y:

System B:

x = -7/13

5x + 6y = -5

Therefore, System B can be obtained from System A by replacing x in the second equation with the expression 1 + 4y and simplifying the resulting equations.

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Answer:

domain:{10,28,42,52}

range:{-10,6,10}

Step-by-step explanation:

Hello There!

If you didn´t know the domain is the set of x values

the x values in the given relation are

10,28,42,10 and 52

so the domain is {10,28,42,52}

The range is the set of y values

the y values in the given relations are

6,-10,6,10,10

so the range is {-10,6,10}

Answer:

Step-by-step explanation:

Given that:

Find the volume of the cuboid!

Volume equation =

W × H × L =

5/8 × 2/3 × 3/4 =

(5×2×3)/(8×3×4) =

30/96 =

The volume = 5/16 cubic centimetres

____________________

#IndonesianPride - kexcvi

Answer:

7.02

Step-by-step explanation:

20 ¢ x 5 = 1.00

3 x 3.99 = 11.97

11.97 + 1.00 = 12.97

20.00 - 12.97 = 7.02

Answer:

[tex]\huge\boxed{\sf 1}[/tex]

Step-by-step explanation:

Given the expression:

= 9 - b

Given that b = 8

= 9 - 8

= 1

[tex]\rule[225]{225}{2}[/tex]

Hope this helped!

Okay so we are asked to solve 9 - b, and we are told that b=8

Therefore this is just a matter of substitution:

9 - b

Substitute 8 for b:

9 - 8

Now just finish solving:

1

Therefore, the answer is 1

Hope this helped :)

Answer:

she should set up a budget on how much she makes

Step-by-step explanation:

Answer:

Well, since x is bigger than negative 4, it cant be -5, so its either from -3 to 5.

since your question says to graph it,  i attached a blank graph. put the points on the blank graph and this will help you find your answer. hope i helped.

Step-by-step explanation:

Answer:

45 cm

Step-by-step explanation:

You use the formulas 1/2*base*height for area of a triangle and edge squared for the square so you do 1/2*2.24*3 for the area of one triangle, then times this by 4 to account for all triangles, then you add this to 3*3 which is the area of the square

Answer:

i think that will be 27 because thats 3/5 of the total

Step-by-step explanation:

tell me if i got it right or wrong no hate

Answer:

Probability:

1. probability of rain < 1/2            -------- Unlikely

2. probability of rain = 0             --------  Impossible

3. probability of rain = 1               -------- Certain

4. probability of rain > 1/2           --------- Likely

Step-by-step explanation:

Given -

Terms:

• impossible

• likely

• unlikely

• certain

Probability:

1. probability of rain < 1/2

2. probability of rain = 0

3. probability of rain = 1

4. probability of rain > 1/2

To find - Watching the weather channel, you can see the probability of it raining tomorrow. drag the term to the corresponding probability of it raining tomorrow. drag the term to the corresponding probability of it raining tomorrow.

Proof -

Probability:

1. probability of rain < 1/2            -------- Unlikely

2. probability of rain = 0             --------  Impossible

3. probability of rain = 1               -------- Certain

4. probability of rain > 1/2           --------- Likely

Reason -

A ratio is a number that is  between 0 and 1 and can include 0 and 1.

Having 13 months in a year has the  probability of 0.

The probability that the sun will rise  tomorrow morning is 1

Answer:

[tex]x = \frac{3}{2} [/tex]

Step-by-step explanation:

[tex] \frac{x + 6}{x + 1} = \frac{6}{2} [/tex]

[tex] \frac{6}{2} = 3[/tex]

so, the solution of the equation will be as follows:

[tex] \frac{x + 6}{x + 1} = 3[/tex]

3(x+1) = x + 6

3x + 3 = x + 6

3x - x = 6 - 3

[tex]x = \frac{3}{2} [/tex]

so, the answer will be x = 3/2

Answer:

i dont see a picture?

Step-by-step explanation:

Step-by-step explanation:

the student who has the highest grades in a particular group of students and who gives the valedictory speech at a graduation ceremony compare salutatorian.

Answer:

B.

Step-by-step explanation:

We are given:

[tex]\displaystyle \int \sqrt{x}\Big(9x^3-2\sqrt{x}+\frac{8}{x}\Big)\, dx[/tex]

And we want to select its equivalent form.

Note that A is not valid. No integration property allows us to separate factors unless that factor is a constant.

We can simply rewrite and then distribute. First, by rewriting:

[tex]\displaystyle =\int x^{1/2}\Big(9x^3-2x^{1/2}+8x^{-1}\Big)\, dx[/tex]

Distribute. Recall exponent properties;

[tex]\displaystyle =\int(9x^{3+1/2}-2x^{1/2+1/2}+8x^{-1+1/2})\, dx[/tex]

Simplify:

[tex]\displaystyle=\int9x^{7/2}-2x+8x^{1/2}\, dx[/tex]

This can then be separated (since its addition/subtraction) and integrated individually.

Hence, our answer is B.

Answer:

Sometimes. Say x = 3 and y = 4. 3 + 4 = 7, 3 - 4 = -1. However, the subtraction problem can be greater than the addition if you add some negatives into the mix. Say x = 3 and y = -4. 3 + (-4) is the same as subtracting 4, which give you -1. However, when you subtract negative four, it's the same as adding four, which gives you seven.

Answer:

the answer is d

Step-by-step explanation:

<1=97°

steps:

<1+83=180 co interior angle

<1=180-83=97°

9514 1404 393

Answer:

  3 ft

Step-by-step explanation:

The post is 4/24 = 1/6 as tall as the streetlight, so we expect its shadow to be 1/6 as long as that of the streetlight:

  (1/6)(18 ft) = 3 ft

The parking meter post shadow is 3 feet long.

Answer:

Step-by-step explanation:

I don't think u can tell from that because u need the length of each movie

Step-by-step explanation:

Due to the time it took to solve this question, I had little time to type the answers fully

The answers are contained fully in the attachment I have uploaded.

A. H0: u1 = u2

H1: u1 not equal to u2

The t statistics was solved to be 3.03

The degree of freedom was solved to be 26

Given this information, this is a 3 tailed test, critical value at 5% = +-2.056

T stat > critical value

We therefore reject the null hypothesis at 5% and conclude they have different mean wear

The p value is calculated using excel and the result is 0.00544

We reject null at 5% since p value is less than 0.05

B. H0: u1 = u2

H1: u1>u2

Alpha = 0.05

Following a,

Test stat = 3.03

Df = 26

Critical value for 1 tailed test = 1.706

Test stat > 1.706

We reject H0 and conclude company 1 has higher mean wear.

We find p value for a right tailed distribution using excel

Tdist(3.03,26,1)

= 0.002722

We reject h0

C. Confidence interval

1.610 < u < 8.390

Answer:

16 every 2 years, or 8 more per year

Answer:

(x,y) ---→ ( x + 3 , y + 1 )

Step-by-step explanation:

Hello There!

All we have to do is pick one letter and count the units from the preimage to the translated image

To get to A' you have to from A and go up one unit to the right 3 units

So the translation is 1 unit up 3 units to the right or (x,y) ---→ ( x + 3 , y + 1 )

Answer:

A. 72×9=1/8

Step-by-step explanation:

the other two are decimals so it is A

Hope this helps!!

Answer:

0.7769 = 77.69% probability that the owner will experience at least one Category III hurricane during the mortgage period

Step-by-step explanation:

We have only the mean, so we use the Poisson distribution to solve this question.

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

[tex]P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}[/tex]

In which

x is the number of sucesses

e = 2.71828 is the Euler number

[tex]\mu[/tex] is the mean in the given interval.

It uses the estimate that the probability of a named Category III hurricane or higher striking that particular region of the coast in any one year is 0.05.

This means that [tex]\mu = 0.05n[/tex], in which n is the number of yeas.

If a homeowner takes a 30-year mortgage on a recently purchased property, what is the likelihood that the owner will experience at least one Category III hurricane during the mortgage period

30 years means that [tex]\mu = 0.05*30 = 1.5[/tex].

This probability is:

[tex]P(X \geq 1) = 1 - P(X = 0)[/tex]

In which

[tex]P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}[/tex]

[tex]P(X = 0) = \frac{e^{-1.5}*(1.5)^{0}}{(0)!} = 0.2231[/tex]

[tex]P(X \geq 1) = 1 - P(X = 0) = 1 - 0.2231 = 0.7769[/tex]

0.7769 = 77.69% probability that the owner will experience at least one Category III hurricane during the mortgage period

Let X become a variable refer to the number of Category ll hurricanes that occurred during the mortgage period. As per the information given, the variable x has a random variable.

For point a:

     [tex]\to P(X > 1) = 1 - P(X = 0)\\\\ \to P(X > 1) = 1^{-30} C_o (0.05)^0 (1 -0.05)^{30}\\\\ \to P(X > 1) = 0.7854[/tex]

For point b:

[tex]\to P(X > 2) = 1 - P(X =0) - P(X = 1)\\\\ \to P(X > 2) = 1 ^{-30} C_0(0.05)^0 (1 -0.05)^{30 -30} C_1 (0.05)^1+(1 - 0.05)^{29}\\\\ \to P(X > 2) = 0.4465[/tex]

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