Answer: Jupiter is made up predominantly of hydrogen. Jupiter's Moon, Europa, might be able to support life. Jupiter has 3 skinny rings. Usually around -234 degrees Fahrenheit.
What is molarity measured the concentration of
All the radioactive elements are found in the last group of the Periodic Table.
True
False
Answer:
False
Explanation:
A chemist prepares a solution of barium acetate BaCH3CO22 by weighing out 52.9g of barium acetate into a 100.mL volumetric flask and filling the flask to the mark with water. Calculate the concentration in /gL of the chemist's barium acetate solution. Round your answer to 3 significant digits.
Answer:
529g/L
Explanation:
The concentration in chemistry is defined as the amount of solute in a determined amount of solution. The concentration in g/L means the amount of grams of solute (In this case, barium acetate), per liter of solution.
To solve this problem we need to find grams of solute (52.9g, already given) and the volume in liters (Converting 100mL to liters):
Volume:
100mL * (1L / 1000mL) = 0.100L
And concentration in g/L is:
52.9g / 0.100L =
529g/Lg A chemist must prepare of hydrochloric acid solution with a pH of at . He will do this in three steps: Fill a volumetric flask about halfway with distilled water. Measure out a small volume of concentrated () stock hydrochloric acid solution and add it to the flask. Fill the flask to the mark with distilled water. Calculate the volume of concentrated hydrochloric acid that the chemist must measure out in the second step. Round your answer to significant digits.
The question is incomplete, here is the complete question:
A chemist must prepare 550.0 mL of hydrochloric acid solution with a pH of 1.60 at [tex]25^oC[/tex]. He will do this in three steps: Fill a 550.0 mL volumetric flask about halfway with distilled water. Measure out a small volume of concentrated (8.0M) stock hydrochloric acid solution and add it to the flask. Fill the flask to the mark with distilled water. Calculate the volume of concentrated hydrochloric acid that the chemist must measure out in the second step. Round your answer to 2 significant digits.
Answer: The volume of concentrated hydrochloric acid solution is 1.7 mL.
Explanation:
To calculate the hydrogen ion concentration, we use the formula:
[tex]pH=-\log [H^+][/tex]
We are given:
pH = 1.60
Putting values in above equation, we get:
[tex]1.60=-\log [H^+][/tex]
[tex][H^+]=antilog (-1.60)[/tex]
[tex][H^+]=0.0251M[/tex]
To calculate the volume of concentrated solution, we use the equation:
[tex]M_1V_1=M_2V_2[/tex]
where,
[tex]M_1\text{ and }V_1[/tex] = molarity and volume of concentrated acid solution
[tex]M_2\text{ and }V_2[/tex] = molarity and volume of diluted acid solution
We are given:
[tex]M_1=8.0M\\V_1=?mL\\M_2=0.0251M\\V_2=550mL[/tex]
Putting values in above equation, we get:
[tex]8.0\times V_1=0.0251\times 550\\\\V_1=\frac{0.0251\times 550}{8.0}=1.7mL[/tex]
Hence, the volume of concentrated hydrochloric acid solution is 1.7 mL.
Why is your body going through physical and chemical changes?
Answer:
Physical and chemical changes can occur almost everywhere, even in our bodies! Food must be broken down into a form that our cells can use. When we eat, our bodies physically break down food into small pieces. Our bodies also chemically break down those small pieces of food into tiny organic molecules.
Explanation:
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what element is in group 13, period 4
Answer:
Gallium
Explanation:
Answer:
Gallium
Explanation:
Fungus is an example of a/an-
A:tissue
B:cell type
C:organ
D:organism
Answer:
D.organism
Explanation:
A fungus from the kingdom fungi is an organism
Answer:
D. organism
......................
How many pounds of gold ore would need to be processed to obtain 5 grams of gold (Au) if the ore is 0.1% gold by mass?
Pounds of gold ore : 11,02311
Further explanationGiven
5 g of gold
0.1% gold by mass
Required
Pounds of gold ore
Solution
[tex]\tt \%mass~gold=\dfrac{mass~gold}{mass~ore}\times 100\%[/tex]
For percent mass = 0.1%, than mass of gold ore :
[tex]\tt 0.1\%=\dfrac{5~g}{mass~ore}\times 100\%\\\\mass~ore=\dfrac{5\times 100}{0.1}\\\\mass~ore=5000~g[/tex]
Conversion factor :
1 g = 0,00220462 pound, than for 5000 g = 11,02311 pounds
How do sound waves travel? PLEASE HELP IF YOU WANT BRAINLEIST AND ME TO LIKE URE COMMENT!!
A. Sound causes the air near it to vibrate inwards.
B. waves radiate outward from a central point.
C. Sound moves randomly in different directions.
D. Sound transforms waves into different frequencies.
The answer is A. The vibration caused by the waves through the air eventually weaken, which is why sound diminishes easily over distance.
What is the molecular formula for a compound with a molar mass of 42.08g/mol and an empirical formula of ch2
Answer:
[tex]C_3H_6[/tex]
Explanation:
Hello!
In this case, since the empirical formula is the smallest representation of the molecular formula, it is known that the times in which the empirical formula is into the molecular formula is a whole number and is computed by dividing the molar mass of the molecular formula by that of the empirical formula as shown below:
[tex]\frac{42.08g/mol}{12.01+1.01x2}= \frac{42.08g/mol}{14.03g/mol}=3[/tex]
Thus, the molecular formula times the empirical formula by 3 to obtain:
[tex]C_3H_6[/tex]
Regards!
what is the volume of the rock? if the water rose from 50L to 70mL
How many protons, neutrons, and electrons does k^1+ have
Answer:
protons 19
nuetorns 20
electrons 19
metling point 63.65 C
Explanation:
how are Ionic and Covalent Bonds are formed with examples ?
Answer:Comparison of Ionic and Covalent Bonds
In an ionic bond, the atoms are bound together by the electrostatic forces in the attraction between ions of opposite charge. ... For example, sodium (Na), a metal, and chloride (Cl), a nonmetal, form an ionic bond to make NaCl. In a covalent bond, the atoms bond by sharing electrons.
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A 2.26 M solution of KOH is prepared. Calculate the moles and mass of solute present in a 15.2-mL sample of this solution. The molar mass of KOH is 56.11 g/mol.
Answer:
0.0344 moles and 1.93g.
Explanation:
Molarity is defined as the ratio between moles of a solute (In this case, KOH), and the volume. With molarity and volume we can solve the moles of solute. With moles of solute we can find mass of the solute as follows:
Moles KOH:
15.2mL = 0.0152L * (2.26mol / L) = 0.0344moles
Mass KOH:
0.0344 moles * (56.11g/mol) = 1.93g of KOH
What would happen to the volume of a gas if you increased the temperature?
Answer:
The volume of the gas increases as the temperature increases.
Explanation:
Gas volume does increase with increasing temperature providing that the pressure remains constant. Temperature and pressure both interact with the gas volume according to the gas Laws and both variables must be accounted for at the same time.
9. Which of these is not a mixture? *
Solution
Alloy
Amalgam
They are all mixtures.
Answer:
They are all mixture
Explanation:
last option
The number of electrons in 1.6 gram CH, is:
Answer:
6.022 x 10²³ electrons
Explanation:
GIVING OUT BRAINLIEST!!!!!!!!!
Which substance has the lowest specific heat?
O Beach sand
O
Beach water
O Ice
Pool water
What is the molarity of a solution of 10% by mass cadmium sulfate, CdSO4 (molar mass = 208.46 g/mol) by mass? The density of the solution is 1.10 g/mL.
a. 0.528 M
b. 0.436 M
c. 0.479 M
d. 0.048 M
e. 22.9 M
Answer:
a. 0.528 M .
Explanation:
Hello!
In this case, since the given by-mass percent can be written as:
[tex]\frac{10gCdSO_4}{100g\ sol}[/tex]
By using the density and molar mass of the solute, cadmium sulfate, we can compute the molarity, by also making sure we convert from mL to L of solution:
[tex]M=\frac{10gCdSO_4}{100g\ sol}*\frac{1molCdSO_4}{208.46gCdSO_4} *\frac{1.10g\ sol}{1mL\ sol}*\frac{1000mL}{1L} \\\\ M=0.528M[/tex]
Thereby, the answer is a. 0.528 M .
Best regards.
The molarity of the solution of 10% by mass cadmium sulfate [tex](CdSO_4)[/tex] is approximately 0.479 M. The correct option is C.
To calculate molarity we need to find out how many moles of CdSO4 are present in the solution.
Given:
Mass of [tex]CdSO_4[/tex]= 10% by mass of the solutionMolar mass of [tex]CdSO_4[/tex] = 208.46 g/molDensity of the solution = 1.10 g/mLWe need to calculate the mass of [tex]CdSO_4[/tex]:
Mass of [tex]CdSO_4[/tex] = (10% / 100%) * Total mass of the solution
Mass of [tex]CdSO_4[/tex] = (10 / 100) * 1000 g (since the volume is 1 L, and the density is 1.10 g/mL)
Mass of [tex]CdSO_4[/tex] = 100 g
So, the number of moles of CdSO4:
Number of moles of [tex]CdSO_4[/tex] = Mass of CdSO4 / Molar mass of CdSO4
Number of moles of [tex]CdSO_4[/tex] = 100 g / 208.46 g/mol
Number of moles of [tex]CdSO_4[/tex] ≈ 0.479 moles
Then, we calculate the molarity of the solution:
Molarity = Number of moles of CdSO4 / Volume of the solution (in liters)
Molarity = 0.479 moles / 1 L
Molarity ≈ 0.479 M
Hence, the molarity of the solution of 10% by mass cadmium sulfate [tex](CdSO_4)[/tex] is approximately 0.479 M. The correct option is C.
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I need a answer ASAP
Answer:
3.2 millions years oldExplanation:
i hope it helps :)
What carpet Burns in a deficiency of O2 a mixture of CO and CO2 forms.Carbon Burns in excess O2 to form only CO2 and CO Burns in excess O2 to form only CO2. Calculate ΔH for C(graphite +1/2O2) →CO(g).
Answer:
Explanation:
From the combustion of carbon, the reactions occurring in limited oxygen conditions are:
[tex]C(graphite) + \dfrac{1}{2}O_{2(g)} \to CO_{(g)}[/tex]
[tex]C(graphite) + O_{2(g)} \to CO_{2(g)}[/tex]
If it occurs in excess, then any leftover CO changes to CO2. i.e.
[tex]C(graphite) + O_{2(g)} \to CO_{2(g)}[/tex] ---- (1)
[tex]CO_{(g)} + \dfrac{1}{2}O_{(g)} \to CO_{2(g)}[/tex] ----- (2)
From (1), the enthalpy change is:
[tex]\Delta H_{rxn1} = \Delta H^0_{fCO_2(g)} - ( \Delta H^0_{f C(graphite)}+ \Delta H^0_{fCO_2(g)}[/tex]
[tex]\Delta H_{rxn1} =-393.5 \ kJ/mol -(0+0)[/tex]
[tex]\Delta H_{rxn1} =-393.5 \ kJ/mol[/tex]
From (2), the enthalpy change is:
[tex]\Delta_{rxn2} = \Delta H^0_{fCO_2(g)} - ( \Delta H^0_{fCO(g)} + \dfrac{1}{2} \Delta H^0_{fO_2(g)})[/tex]
[tex]\Delta_{rxn2} = -393.5 \ kJ/mol -(-110.5 + \dfrac{1}{2}(0))[/tex]
[tex]\Delta_{rxn2} = -283.0 \ kJ/mol[/tex]
Subtracting (2) from (1), we get:
[tex]C(graphite) + O_{2(g)} \to CO_{2(g)} \ \ \ \Delta H_{rxn} = -393.5 \ kJ/mol}[/tex]
[tex]CO_{(g)} + \dfrac{1}{2} O_2(g) \to CO_{2(g)}} \ \ \ \Delta H _{rxn2} = -283.0 \ kJ/mol[/tex]
[tex]C(graphite) + O_{2(g)} \to CO (g) + \dfrac{1}{2}O_{2(g)} \ \ \ \Delta H_{rxn} = -110.5 \ kJ/mol[/tex]
[tex]C(graphite) + \dfrac{1}{2} O_{2(g)} \to CO (g) \ \ \ \Delta H_{rxn} = -110.5 \ kJ/mol[/tex]
The enthalpy change ΔH of the reaction = -110.5 kJ/mol
if 3.26 g is dissolved in enough water to make exactly 323 ml of solution, what is the molar cocentration of nitrate ion g
And electro chemical cell has the following standard cell notation:
Mg(s) | Mg2+ (aq) || Ag+(aq)| Ag(s)
Write a balanced redox reaction for the cells using the oxidation and reduction half reactions. (be sure to equalize charge by multiplying the correct number before adding and simplifying)
2Ag⁺(aq) + Mg(s)→ 2Ag(s) + Mg²⁺ (aq)
Further explanationGiven
Standard cell notation:
Mg(s) | Mg2+ (aq) || Ag+(aq)| Ag(s)
Required
a balanced redox reaction
Solution
At the cathode the reduction reaction occurs, the anode oxidation reaction occurs
In reaction:
Ag⁺ + Mg → Ag + Mg²⁺
half-reactions
at the cathode (reduction reaction)Ag⁺ (aq) + e⁻ ---> Ag (s) x2
2Ag⁺ (aq) + 2e⁻ ---> 2Ag (s)
at the anode (oxidation reaction)Mg (s) → Mg²⁺ (aq) + 2e−
a balanced cell reaction
2Ag⁺(aq) + Mg(s)→ 2Ag(s) + Mg²⁺ (aq)
Answer:2Ag⁺(aq) + Mg(s)→ 2Ag(s) + Mg²⁺ (aq)
Explanation:
just took test
what is the empirical formula of A compound is found to contain 39.12 % carbon, 8.772 % hydrogen, and 52.11 % oxygen by mass.
Answer:
C₃H₈O₃
Explanation:
Let's assume we have 100 g of said compound. Then we would have:
39.12 g of C8.772 g of H52.11 g of ONow we convert those masses into moles, using their respective atomic weights:
C ⇒ 39.12 g ÷ 12 g/mol = 3.26 mol CH ⇒ 8.722 g ÷ 1 g/mol = 8.722 mol HO ⇒ 52.11 g ÷ 16 g/mol = 3.26 mol OThen we divide those moles by the smallest number among them:
C ⇒ 3.26 mol C / 3.26 = 1H ⇒ 8.722 mol H / 3.26 = 2.68O ⇒ 3.26 mol O / 3.26 = 1Finally we multiply those numbers by 3, so as to convert the 2.68 of H into an integer:
C ⇒ 1 * 3 = 3H ⇒ 2.68 * 3 = 8O ⇒ 1 * 3 = 3Thus the empirical formula is C₃H₈O₃
Queston
Which equation shows how to calculate how many grams (g) of KOH would
be needed to fully react with 4 mol Mg(OH)2? The balanced reaction is:
MgCl2 + 2KOH → Mg(OH)2 + 2KCI
OA. mol Mg(OH),
2 mol KOH
mol Mg(0H),
56.10 g KOH
1 mol KOH
2 mol KOH
1 mol Mg Cl,
56.10 g KOH
1mol KOH
OB. mol Mgch
1
1mol Mg(OH),
2 mol KOH
1mol Ma(0H),
56.10 g KOH
1 molkOH
mol Mg (OH,
1 mol KOH
2 mol Ma(OH)
56 10 g KOH
1mol KOH
OD.
Answer:
C
Explanation:
We know that the molar mass of KOH is 56 gmol-1
Molar mass of Mg(OH)2 is 58.31 g/mol
Now; the balanced reaction equation is; MgCl2 + 2KOH → Mg(OH)2 + 2KCI
Hence;
2 moles of KOH yields 1 mole of Mg(OH)2
4 moles of KOH yields;
4 moles of KOH/1 mol * 1 mole Mg(OH)2 /2 moles KOH * 58.31 g Mg(OH)2 / 1 mole Mg(OH)2
So option c is correct
Answer:
4mol MG(OH)2/1 * 2mol KOH/1 mol MG(OH2) * 56.10g KOH/1 mol KOH
Explanation:
Took the test
what is fractional distillation what is fractional distillation explain it with the help of an activity
Answer:
Fractional distillation is a method for separating liquids with different boiling points. For example, liquid ethanol can be separated from a mixture of ethanol and water by fractional distillation. ... The boiling point of ethanol is 78°C and the boiling point of water is 100°C.
How many moles are 5.55 x 104 atoms of Mg?
Answer:
23 atoms. I hope this helped u
Explanation:
Throwing a snowball during snowball fight is most like an example of
How can you use density to separate mixtures like sand and small plastic pellets?
Answer:
Slide a magnet through the mixture. When you take the magnet off, the iron filings are going to be attracted to the magnet and the sand will stay in the bowl
Explanation:
Answer:
Density can be used to separate the substances that make up a mixture, because each substance in a mixture has its own density. For example, if a mixture of sand and oil is placed in water, the sand will sink to the bottom of the container. The sand is more dense than the water.
Explanation:
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