What are the values of x and y if this equation is true?

22(x + yi) + (28 + 4i) 72 – 62i

Answers

Answer 1

Answer:

x = 2

y = -3

Step-by-step explanation:

The given equation is,

22(x + yi) + (28 + 4i) = 72 - 62i

By solving this equation further,

22x + 22yi + 28 + 4i = 72 - 62i

(22x + 28) + (22y + 4)i = 72 - 62i

Now both the sides of the equation is in the form of complex number,

By comparing real and imaginary parts given on both the sides,

22x + 28 = 72

22x = 72 - 28

22x = 44

x = 2

22y + 4 = -62

22y = -62 - 4

22y = -66

y = -3

Therefore, x = 2 and y = -3 are the values for which the given equation is true.


Related Questions

what is the constant of proportionality of p=5a

Answers

Answer:

=5x

Step-by-step explanation:

your question might have a different variable witch is the letter at the end

Please find X. I need help!

Answers

There are 2 overlapping triangles here. If the vertical lines are parallel, then these triangles are similar, and corresponding sides occur in a fixed ratio. In particular, we have

2/3 = (2 + x) / (3 + (x + 7))

Solve for x :

2/3 = (2 + x) / (10 + x)

2 (10 + x) = 3 (2 + x)

20 + 2x = 6 + 3x

14 = x