What are the three symbols used in Ohm's law. Explain what each symbol represents and give the units for each of the variables.

All of the following are examples of physical properties except tearing.

This is used to describe the state of a physical system and is usually measurable.

Examples include:

Tearing isn't an example of a physical property which was why option A was chosen as the most appropriate choice.

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Answer:

Explanation:

Use that:

[tex]F=-\vec{\nabla}U(x,y)=-\left(\hat{i} \frac{\partial U}{\partial x}+\hat{j}\frac{\partial U}{\partial y}\right)=-11.6x\hat{i}+10.8y^{2}\hat{j}[/tex]

Then use the 2nd Newton's Law of Motion:

[tex]\vec{a}=\frac{\vec{F}}{m}=\frac{-11.6x\hat{i}+10.8y^{2}\hat{j}}{0.04}=-290x\hat{i}+270y^{2}\hat{j}[/tex]

At x = 0.3 and y = 0.6, we can find the acceleration as:

[tex]\vec{a}=-87\hat{i}+97.2\hat{j}[/tex] (in SI unit)

Then the magnitude of the acceleration on that point is:

[tex]a=\sqrt{(-87)^{2}+(97.2)^{2}}\approx 130.44[/tex] (SI Unit)

Answer:

(A) 0.8 kgm/s

Explanation:

because of the even ground it would only slow down

If a jogger runs a 10 kilometer race in 60 minutes, her average speed is 10km/hr. Details about average speed can be found below.

Average speed can be calculated by dividing the distance moved by a body by the time taken. That is;

Average speed = Distance/Time

According to this question, a jogger runs a 10 kilometer race in 60 minutes. The average speed is calculated as follows:

Average speed = 10km/1hr

Average speed = 10km/hr.

Therefore, if a jogger runs a 10 kilometer race in 60 minutes, her average speed is 10km/hr.

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[tex]\qquad\qquad\huge\underline{{\sf Answer}}♨[/tex]

Heat capacity of body 1 :

[tex]\qquad \sf  \dashrightarrow \:m_1s_1[/tex]

Heat capacity of body 2 :

[tex]\qquad \sf  \dashrightarrow \:m_2s_2[/tex]

it's given that, the the head capacities of both the objects are equal. I.e

[tex]\qquad \sf  \dashrightarrow \:m_1s_1 = m_2s_2[/tex]

[tex]\qquad \sf  \dashrightarrow \:m_1 = \dfrac{m_2s_2}{s_1} [/tex]

Now, consider specific heat of composite body be s'

According to given relation :

[tex]\qquad \sf  \dashrightarrow \:(m_1 + m_2) s' = m_1s_1 + m_2s_2[/tex]

[tex]\qquad \sf  \dashrightarrow \:s' = \dfrac{ m_1s_1 + m_2s_2}{m_1 + m_2}[/tex]

[tex]\qquad \sf  \dashrightarrow \:s' = \dfrac{ m_2s_2+ m_2s_2}{ \frac{m_2s_2}{s_1} + m_2 }[/tex]

[ since, [tex] m_2s_2 = m_1s_1 [/tex] ]

[tex]\qquad \sf  \dashrightarrow \:s' = \dfrac{ 2m_2s_2}{ m_2(\frac{s_2}{s_1} + 1)}[/tex]

[tex]\qquad \sf  \dashrightarrow \:s' = \dfrac{ 2 \cancel{m_2}s_2}{ \cancel{m_2}(\frac{s_2}{s_1} + 1)}[/tex]

[tex]\qquad \sf  \dashrightarrow \:s' = \dfrac{ 2 s_2}{ (\frac{s_2 + s_1}{s_1} )}[/tex]

[tex]\qquad \sf  \dashrightarrow \: s' = \dfrac{2s_1s_2}{s_1 + s_2} [/tex]

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Answer:25

Explanation: because higher means less kinetic energ

Based on the data provided, the value of the constant b is 3.27 × 10^-5 kg/s and the time required to reach 63% of terminal velocity is 0.58 s.

The terminal velocity of a body is the velocity at which the body falls at constant velocity through a fluid.

For the falling raindrop, let positive direction be downwards and negative direction upwards,

The raindrop experiences a downward gravitational force mg, and an upward drag force -bv.

The total force at a time t is given as

a)

Terminal velocity is achieved then the total force is 0,

0 = mg - bv0

Therefore

b = mg/v0

Substitutingthe values:

b = (3 × 10^-5 × 9.8)/9

b = 3.27 × 10^-5 kg/s

b) Applying Newton's Second Law

F = ma

where

Therefore,

mg = mv/t t = v/g

however, t is at 63% velocity

thus:

t = 0.63v/g

t = 0.63 × 9 /9.8

t = 0.58 s

Therefore, the value of the constant b is 3.27 × 10^-5 kg/s and the time required to reach 63% of terminal velocity is 0.58 s

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Answer:

A) nucleus, ribosomes, and chloroplasts

B) mitochondria, cell wall, chloroplasts

D) cell membrane, ribosomes, small vacuoles

E) cell wall, central vacuole, and cell membrane

Explanation:

It cannot be C as the list features centrioles, which is an animal-cell only structure.

Hello!

We know that at the BOTTOM of the pendulum's trajectory, the bob has a maximum speed. This means that its KINETIC ENERGY is at a maximum, while its Gravitational POTENTIAL ENERGY is at a minimum.

On the other hand, when the bob is at its highest points, the bob has a velocity of 0 m/s, so its KE is at a minimum and its PE is at a maximum.

We can use the work-energy theorem to solve. Let the Initial Energy equal the bob's energy at one of the sides, while the final Energy equals the bob's energy at the bottom.

[tex]E_i = E_f\\\\PE = KE[/tex]

Recall that:
PE = mgh

m = mass (kg)

g = acceleration due to gravity (m/s²)

h = height (m)

KE = 1/2mv²

m = mass (kg)

v = velocity (m/s)

Set the two equal and solve for 'h'.

[tex]mgh = \frac{1}{2}mv^2[/tex]

Cancel mass.

[tex]gh = \frac{1}{2}v^2[/tex]

Solve for 'h'.

[tex]h = \frac{v^2}{2g}\\\\h = \frac{3^2}{2(9.8)} = \boxed{0.459 m}[/tex]

Answer:

m = 4.5 kg

Explanation:

w = - 1800 j

Fd = - 1800 j

mgd = - 1800 j

m = - 1800 ÷(gd)

m = - 1800 ÷( 10×-40)

m = 4.5 kg

The momentum, in the x-direction, that was transferred to the more massive cart after the collision is 19.38 kgm/s.

The momentum transfered to the more massive cart is determined by applying the principle of conservation of linear momentum as shown below;

m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂

where;

⁻ΔP₁ = ΔP₂

ΔP₂ = m₂v₂ - m₂u₂

ΔP₂ = m₂(v₂ - u₂)

ΔP₂ = 3m₁(v₂ - u₂)

ΔP₂ = 3 x 3.8 x (1.7 - 0)

ΔP₂ = 19.38 kgm/s

Thus, the momentum, in the x-direction, that was transferred to the more massive cart after the collision is 19.38 kgm/s.

The complete question is beblow

A cart of mass 3.8 kg is traveling to the right (which we will take to be the positive x-direction for this problem) at a speed of 6.9 m/s. It collides with a stationary cart that is three times as massive. After the collision, the more massive cart is moving at a speed of 1.7 m/s, to the right.

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Answer:

a

Explanation:

Distance is simply the distance travelled which in this case would be 4km + 3km = 7km

To work out displacement, try to imagine the situation.

Draw a straight line to the east (label it 3) and then draw another line from the end of the first line upwards (label this one 4). Thus, you've created a right angles triangle. Now use pythagorean theorem to work out the displacement

4^2 + 3^2 = 25

sqrt 25 = 5 = displacement

Answer:

I can only define a few of them, hope you don't mind.

Seismic- It means connected with or caused by earthquakes

Epicenter- It means the point on the earth's surface where the effects of an earthquake are most felt strongly.

Fault- A place where there is a break that is longer than usual in the layers of rock in the earth's crust.

Tectonic waves- Waves connected with the structure of the earth's surface.

Plate boundaries- The boundaries that differentiates the large sheets of rock (called PLATES) that form the earth's surface. Plate tectonics is the movement of the large sheets of rocks that form the earth's surface

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Answer:

Fundamental quantities are quantities that were created to measure a object/substance which are the basis on which derived quantities are formed, where as derived quantities are created by extracting variables from the fundamental quantities.

The magnitude of the force each plate experiences due to the other plate as a function of V, the potential drop across the capacitor is determined as [tex]\frac{V^2 A \varepsilon _o }{2d^2}[/tex].

The magnitude of the force each plate experiences due to the other plate is determined as follows;

F = U/d

where;

[tex]F = \frac{1}{2} \frac{Q^2}{C} \times \frac{1}{d} \\\\[/tex]

Q = CV

[tex]F = \frac{1}{2} \frac{C^2V^2}{C d} = \frac{CV^2}{2d}[/tex]

where;

The capacitance is given as;

[tex]C = \frac{\varepsilon _o A }{d}[/tex]

[tex]F = \frac{\varepsilon _o A }{d} \times \frac{V^2}{2d} \\\\F = \frac{V^2 A \varepsilon _o }{2d^2}[/tex]

Thus, the magnitude of the force each plate experiences due to the other plate as a function of V, the potential drop across the capacitor is determined as [tex]\frac{V^2 A \varepsilon _o }{2d^2}[/tex].

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Answer:

In a series circuit, the same amount of current flows through all the components placed in it. On the other hand, in parallel circuits, the components are placed in parallel with each other due to which the circuit splits the current flow.

Answer:

300N

Explanation:

in your drawing make sure to put 230n and 160n on the same side with arrows facing the same direction on the opposite side of the box add an arrow with 0n and an arrow to represent friction

Since there is no temperature change which drives heat flow, thus no heat will be released by the water.

The heat released by the water when it freezes is calculated as follows;

Q = mcΔФ

where;

when water freezes, the temperature, Фf = 0 °C

Q = 82 x 4200 x (0 - 0)

Q = 0

Since there is no temperature change which drives heat flow, thus no heat will be released by the water.

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If the comb and the paper are attracted to each other the charge on the paper, is D)must be positive

This states that

Now, given that a negatively charged plastic comb is brought close to, but does not touch, a small piece of paper. If the comb and the paper are attracted to each other the charge on the paper, this implies that both the negatively charged plastic comb and the paper have opposite charges.

Since the charge on the plastic comb is negative, this means that the charge on the paper must be positive

So, if the comb and the paper are attracted to each other the charge on the paper, is D)must be positive

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[tex] \tt{Difference \: Between \: \underline\red {Horticulture} \: And \: \underline\green{Agriculture}}[/tex]

[tex] \text{\underline\red {Horticulture}}[/tex]

The Cultivation of Fruits, Vegetables and Flowers for domestic and international markets are called Horticulture.

[tex] \text{\underline\green{Agriculture}}[/tex]

It is science, art and occupation of cultivating the soil, producing crops and livestock. It is systematic and controlled use of living organisms and the environment to improve the human condition.

Answer:

Burning coal and boiling water are both chemical changes. Burning coal is a chemical change, and boiling water is a physical change. Burning coal is a physical change, and boiling water is a chemical change.

Explanation:

Answer:

did you get it done if not lmk I will help you out tomorrow when I get up

Answer: 20 m/s

Explanation:

Acceleration = change in velocity / time → 10 m/s^2 = final velocity - 0 (original velocity) / 2s → final velocity = 20 m/s

The volume of the material that must be used to make a star with the mass of the sun is 1.2×10⁵¹ m³.

Volume is the amount of space occupied by an object or a plane figure.

To calculate the volume of the material that must be used to make a star with the mass of the sun, we use the formula below.

Formula:

Where:

Make V the subject of the equation

From the question,

Given:

Substitute these values into equation 2

Hence, The volume of the material that must be used to make a star with the mass of the sun is 1.2×10⁵¹ m³.

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Alpha

I hope this helps you

:)

Try this solution, all the details are in the attachment. note, the answer is marked with orange colour. If it is possible, check the provided solution in other sources.

Answer: ≈0.81c.

Answer:

the process of bending of light when travling throw different mediume is called refraction of light.