Explanation:
In Newton's 1 law, an object will not change its motion unless a force acts on it.
The motion of a ball falling down through the atmosphere, or a model rocket being launched up into the atmosphere are both examples of Newton's first law.
In Newton's 2 law, the force on an object is equal to its mass times its acceleration.
Riding your bicycle is a good example of this law of motion at work. ... Your leg muscles pushing pushing on the pedals of your bicycle is the force. When you push on the pedals, your bicycle accelerates.
In Newton's 3 law, when two objects interact, they apply forces to each other of equal magnitude and opposite direction.
For example, when you jump, your legs apply a force to the ground, and the ground applies and equal and opposite reaction force that propels you into the air.
what is projectile motion
If an object is given an initial velocity in any direction and then allowed to travel freely under gravity, it is called a projectile motion.
It is basically 3 types.
horizontally projectile motion oblique projectile motion included plane projectile motionsomeone please help with this
Answer:
The new force is 2/3 of the original force
Explanation:
Coulomb's Law
The electrical force between two charged objects is directly proportional to the product of their charges and inversely proportional to the square of the distance between the two objects.
Written as a formula:
[tex]\displaystyle F=k\frac{q_1q_2}{d^2}[/tex]
Where:
[tex]k=9\cdot 10^9\ N.m^2/c^2[/tex]
q1, q2 = the objects' charge
d= The distance between the objects
Suppose the first charge is doubled (2q1) and the second charge is one-third of the original charge (q2/3). Now the force is:
[tex]\displaystyle F'=k\frac{2q_1*q_2/3}{d^2}[/tex]
Factoring out 2/3:
[tex]\displaystyle F'=\frac{2}{3}k\frac{q_1*q_2}{d^2}[/tex]
Substituting the original force:
[tex]F'=\frac{2}{3}F[/tex]
The new force is 2/3 of the original force
substances found in the food that the body needs
Answer:
There are six major nutrients: Carbohydrates (CHO), Lipids (fats), Proteins, Vitamins, Minerals, Water.
Explanation:
As the hot gas from a space shuttle is released downward, what does this cause to happen?
A. The shuttle will explode.
B. Negligible force on the shuttle.
C. Downward force on the shuttle.
D. Upward force on the shuttle
Answer:
D. Upward force on the shuttle
Explanation:
The hot gas from space shuttles released downward causes an upward force on the shuttle and propels it up the more.
This hot gas is produced from super cooled oxygen and hydrogen tanks within the shuttle. The upward force on the shuttle allows the craft to escape the gravitational pull of the earth on the shuttle Special level of rapid acceleration must be attained for the shuttle to escape the earth pull.A body with mass 2 kg absorbs heat 418.4J when its temperature raises from 293K to 343K . What is the specific heat of the body?
Answer:
C M (change in T) = heat absorbed thermal equation for heat gained
C = 418.4 J / (2 kg * 50 deg K) = 4.184 J / kg * deg K specific heat
Note: 1 gm =.001 kg
So C = .004184J / gm * deg K
Also, 1 J = .239 cal so in conventional terms
C = .001 cal / gm deg K (very low, water would be 1 cal / gm deg C
A 5.0 kg chunk of putty moving at 10m/s collides and sticks to a 7.0 kg bowling ball that is initially at rest.What is the total momentum of the bowling ball and the putty after they collide?
Answer:
Total momentum = 50kgm/s
Explanation:
Given the following data;
Mass, M1 = 5kg
Mass, M2 = 7kg
Velocity, V1 = 10m/s
Velocity, V2 = 0m/s (since it's at rest).
To find the total momentum;
Momentum can be defined as the multiplication (product) of the mass possessed by an object and its velocity. Momentum is considered to be a vector quantity because it has both magnitude and direction.
Mathematically, momentum is given by the formula;
[tex] Momentum = Mass * Velocity [/tex]
The law of conservation of momentum states that the total linear momentum of any closed system would always remain constant with respect to time.
Total momentum = M1V1 + M2V2
Substituting into the equation, we have;
Total momentum = 5*10 + 7*0
Total momentum = 50 + 0
Total momentum = 50 kgm/s
Therefore, the total momentum of the bowling ball and the putty after they collide is 50 kgm/s.
1) Which of the following is not a type of energy?
A: Thermal
B: Potential
C: Kinetic
D: Frictional
a) Las siglas M. RU significan
Answer:
Ver la explicación a continuación.
Explanation:
En física estas siglas significan movimiento rectilíneo uniforme, es decir es el tipo de movimiento donde la velocidad es constante. La velocidad no cambia con el tiempo.
Este tipo de movimiento se puede describir con la siguiente ecuación.
[tex]x=x_{0}+v*t[/tex]
Donde:
x = posición final [m]
xo = posición inicial [m]
v = velocidad [m/s]
t = tiempo [s]
A bobsled has a momentum of 4000 kg•m/s to the south. Friction on the
track reduces its momentum to 2500 kg•m/s to the south. What impulse is
applied to the bobsled by the friction?
Answer:
1500 north
Explanation:
Answer: 1500 north
Explanation:
Impulse is change of momentum. Since the numbers are already in units of momentum, you just need to subtract one from the other to find the impulse. 4000 - 2500 = 1500. Because the bobsled is traveling south and slowing down, the impulse will be in the opposite direction, or north.
1500 north.
A dog playing fetch starts at rest and accelerates at 4.5m/s2 north. It takes the dog 7 seconds to catch the ball. What was the speed of the dog when he caught the ball?
Answer:
31.5m/s
Explanation:
Given the following
acceleration a = 4.5m/s²
Time t= 7secs
Required
Final speed v = ?
Using the equation of motion
v = u+at
v = 0+4.5(7)
v = 31.5m/s
Hence the speed of the dog is 31.5m/s
Calculate speed...
D=40 m
T=10 s
a
40 m/s
b
400 m/s
c
4 m/s
Answer:
c
Explanation:
speed=distance÷time
40÷10=4
Gamma radiation is composed of neutrons and protons.
A. True
B. False
Answer:
false
Explanation:
Answer:
The answer is B false
Explanation:
Gamma radiation is not composed of both neutrons and protons.
Is work being done on a barbell when a weight lifter is holding the barbell
over his head?
Answer:
Because in order for work to be done on an object, the object must be moving. Why isn't work being done on a barbell when a weight lifter is holding the barbell over his head? Work is maximized when force is applied in the same direction that the object is moving. ... In order to do work faster, more_is required.
A negative charge of 20 x 10-6C and another charge of 15 x 10-6C are separated by as distance of 0.7 m.
What is the magnitude of the electrical force between the two charges:
answer to the closest 0.1 N
Answer:
Approximately [tex]5.5\; \rm N[/tex], assuming that the volume of these two charged objects is negligible.
Explanation:
Assume that the dimensions of these two charged objects is much smaller than the distance between them. Hence, Coulomb's Law would give a good estimate of the electrostatic force between these two objects regardless of their exact shapes.
Let [tex]q_1[/tex] and [tex]q_2[/tex] denote the magnitude of two point charges (where the volume of both charged object is negligible.) In this question, [tex]q_1 = 20 \times 10^{-6}\; \rm C[/tex] and [tex]q_2 = 15 \times 10^{-6}\; \rm C[/tex].
Let [tex]r[/tex] denote the distance between these two point charges. In this question, [tex]r = 0.7\; \rm m[/tex].
Let [tex]k[/tex] denote the Coulomb constant. In standard units, [tex]k \approx 8.98755\times 10^{9}\; \rm kg \cdot m^{3}\cdot s^{-2}\cdot C^{-2}[/tex].
By Coulomb's Law, the magnitude of electrostatic force (electric force) between these two point charges would be:
[tex]\begin{aligned}F &= \frac{k \cdot q_1 \cdot q_2}{r^{2}}\end{aligned}[/tex].
Substitute in the values and evaluate:
[tex]\begin{aligned}F &= \frac{k \cdot q_1 \cdot q_2}{r^{2}}\\ &\approx 8.98755 \times 10^{9}\; \rm kg \cdot m^{3}\cdot s^{-2}\cdot C^{-2} \\ &\quad \times 20\times 10^{-6}\; \rm C\\ &\quad \times 15\times 10^{-6}\; \rm C \\ &\quad \times \frac{1}{{(0.7\; \rm m)}^{2}}\\ &\approx 5.5\; \rm N \end{aligned}[/tex].
320 joules of work were done by a force of 80 newtons. Over what
distance was the force applied?
44m
80m
4m
40m
Answer:
[tex]4\:\mathrm{m}[/tex]
Explanation:
The formula for work is given as [tex]W=F\Delta x[/tex] where [tex]F[/tex] is force applied and [tex]\Delta x[/tex] is displacement.
Rearranging this equation, we have:
[tex]\Delta x=\frac{W}{F}[/tex].
Plugging in given values, we get:
[tex]\Delta x=\frac{W}{F}=\frac{320}{80}=\fbox{$4\:\mathrm{m}$}[/tex].
Answer:
The answer is 4m
Explanation:
hope this helps!
Look at the atoms below
a. Atom W: 9 protons and 9 neutrons
b. Atom X: 8 protons and 9 neutrons
c. Atom Y: 9 protons and 9 neutrons
d. Atom Z: 9 protons and 10 neutrons
Which ones below are isotopes of each other and why?
element z are isotopes because number of netron are different and number of protons are same
5
A cyclist travels 125 km in 5 hours. How fast is the cyclist moving?
Answer:
25 km/h
Explanation:
speed=distance÷time
125÷5=speed
125÷5=25 (then add units)
Explain how we perceive objects as they are
pls help, I will mark u as the brainliest
The lens present in our eyes forms a real and inverted image on the retina. The optic nerves carry this image from the retina to the brain. The brain then processes this info to generate clear and virtual images. That's how we perceive objects as they are.
When the image is formed on our "Retina", the light sensitive cells of our Retina gets activated and they generate electric signals. These signals are send to brain by the optic nerves. The brain interprets the electric signals in such a way that we see an image in erect and of the same size as the object... MÅRK ÅS THE ẞRÅÏÑLÏËST.......
Determine the force of gravitational attraction between the earth (m = 5.98 x 1024 kg) and a 70-kg physics student if the student is in an airplane at 40000 feet above earth's surface. This would place the student a distance of 6.39 x 106 m from earth's center.
Answer:
[tex]F=683.790939[/tex]N
Explanation:
From the Question we are told that
Earth mass [tex]m_1= 5.98 * 10^2^4 kg[/tex]
Students mass [tex]m_2=70kg[/tex]
Distance of student from earth center Radius [tex]r=6.39 * 10^6 m[/tex]
Generally the equation for Force of attraction b/w the earth and the boy is mathematically given by
[tex]F=\frac{Gm_1m_2}{r^2}[/tex]
[tex]F=\frac{6.67.10^-^1^1*( 5.98 x 10^2^4)(70)}{(6.39 *10^6)^2}[/tex]
Therefore the force of attraction b/w the student and the earth is
[tex]F=683.790939N[/tex]
[tex]F\approx 684N[/tex]
the mass of the car is 1400 kg. The car , initially at rest is moved along a level road by a resultant force of 3500N.The car reaches speed of 30m/s ... calculate the average acceleration and use newtons seconds law , F=m×a
Answer:
2.5m/s²
Explanation:
Given parameters:
Mass of car = 1400kg
Resultant force = 3500N
Speed = 30m/s
Unknown:
Average acceleration = ?
Solution:
According to the Newton's second law of motion:
Force = mass x acceleration
Now;
3500 = 1400 x acceleration
Acceleration = [tex]\frac{3500}{1400}[/tex] = 2.5m/s²
The diagram shows a wave traveling through a medium.
Identify point B.
amplitude
crest
trough
wavelength
The point B represent the crest of the wave. The crest is the peak of the wave. While the trough is the lowest.
What is wavelength?The distance between two successive troughs or crests is known as the wavelength.
The wavelength is also defined as the distance between two locations in a wave that have the same oscillation phase.
The point B represent the crest of the wave. The crest is the peak of the wave. While the trough is the lowest.
Hence, option B is correct.
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Can someone please help?
Answer:
B
Explanation:
Speed is distance divided by time.
Who was the most famous member of the Underground Railroad?
Answer:
Harriet Tubman
Explanation:
Answer:
Harriet Tubman
Explanation:
She was an abolitionist and fought for women's rights.
Harriet was also the first woman to lead a combat assault.
3. The velocity of sound is 332 m/s. Answer the following questions:
i) What is the minimum and maximum frequency of sound which
is heard to the human ear?
ii) What is the wavelength of the shortest and longest waves heard
to the human ear?
Answer:
20 Hz, 20000 Hz
0.0166 m, 16.6 m
Explanation:
The minimum frequency that a human ear can hear is 20 Hz
The maximum frequency that a human ear can hear is 20000 Hz.
v = Velocity of sound = 332 m/s
Wavelength is given by
[tex]\lambda=\dfrac{v}{f}\\\Rightarrow \lambda=\dfrac{332}{20}\\\Rightarrow \lambda=16.6\ \text{m}[/tex]
The longest wavelength that can be heard by the human ear is 16.6 m
[tex]\lambda=\dfrac{332}{20000}\\\Rightarrow \lambda=0.0166\ \text{m}[/tex]
The shortest wavelength that can be heard by the human ear is 0.0166 m.
A 50Kg girl jumps off a 5-meter-high diving board. What is her kinetic energy right before she
hits the water?
A. 0 J
B. 25 J
C. 1225 J
D. 2450 J
Answer:
D is the correct answer
Explanation:
Ek=m*g*h=50*9.8*5=2450
The kinetic energy right before she hits the water is 2450J. So, the correct option is D.
What is Kinetic energy?Kinetic energy is defined as the energy that is due to the motion of an object. If we want to accelerate an object, we must apply a force, by applying a force we need to do work. After the work is done, energy has been transferred to the object, and the object will continue to move with a new constant speed.
A 50Kg girl jumps off a 5-meter-high diving board.
We need to find the kinetic energy of the girl before she enters the water which means that the kinetic energy becomes equal to the potential energy such that,
P.E.=K.E. = mgh
where, m=mass of the object
g= acceleration due to gravity [tex](9.8m/s^2)[/tex]
h= height
So, K.E= 50* 9.8*5 = 2450 J
Thus, the kinetic energy right before she hits the water is 2450J. So, the correct option is D.
Learn more about Kinetic energy, here:
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Which statement about plant and animal cells is true?
A. Both have a cell wall to give them support.
B. Both have a large vacuole to store water.
C. Both use mitochondria to release energy.
D. Both use chloroplasts to store energy.
Answer:
C. Both use mitochondria to release energy
Explanation:
Plant cells have a cell wall, a large vacuole and chloroplasts but animal cells do not.
What is the mass of the object if it exerted a
force of 62.2 Newtons and has an acceleration
of 15.3 m/s2?
Answer:
The object has an approximate mass of 4.06 kilograms.
Explanation:
Force is equal to mass times acceleration, so all we need to do is divide the force provided by the acceleration provided.
[tex]m = \frac{62.2N}{15.3 \frac{m}{s^2}}\\\\m = \frac{62.3kg\frac{m}{s^2}}{15.3 \frac{m}{s^2}}\\\\m = \frac{62.2kg}{15.3}\\\\m = 4.06kg[/tex]
A cart falls from a track with an acceleration of 10 m/s2 (which is always the acceleration due to gravity). If it falls for 9 seconds before hitting the ground, what is it’s velocity at impact? (show work plz)
Answer:
90m/s
Explanation:
Given parameters:
Acceleration = 10m/s²
Time of fall = 9s
Unknown:
Final velocity = ?
Solution:
We can assume that the cart falls from rest.
Initial velocity = 0m/s
Using
v = u + gt
v is the final velocity
u is the initial velocity
g is the acceleration due to gravity
t is the time
v = 0 + 10 x 9 = 90m/s
Answer:
90m/s
Explanation:
What is the gravitational force of attraction between a 55 kg boy and a 40 kg girl if they are 0.10 meters apart?
Answer:
[tex]1.5\cdot 10^{-5}\:\mathrm{N}[/tex]
Explanation:
Newton's Law of Gravitation is given as:
[tex]F=G\frac{m_1m_2}{r^2}[/tex], where [tex]G[/tex] is gravitational constant [tex]6.67\cdot 10^{-11}[/tex] and [tex]r[/tex] is the distance between their centers of mass.
Therefore, the gravitational force between them is:
[tex]F=6.67\cdot 10^{-11}\frac{55\cdot40}{0.1^2}= \fbox{$1.5\cdot 10^{-5}\:\mathrm{N}$}[/tex] (two significant figures).
A car starts from rest and accelerates at a constant rate of 3.5 m/s2. What is the car’s velocity after the car has traveled 800 m?
Answer:
Attached is the answer
Explanation:
The car’s velocity after the car has traveled 800 m is 74.83 m/sec.
What is velocity?When an item is moving, its velocity is the rate at which its direction is changing as seen from a certain point of view and as measured by a specific unit of time.
Using equation of motion, initial velocity u = 0 and acceleration a = 3.5 unit and distance travelled is 800 m.
v² = u² + 2as
v² = 0 + 2*3.5*800
v² = 5600
v = 74.83 m/sec
The car’s velocity after the car has traveled 800 m is 74.83 m/sec.
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