The forklift overturning is a very common way of getting injured from a forklift. Overturning the forklift means it tips over onto it's side due to the operator turning it too fast.
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What is a specialized accreditation? A. evaluation of the quality of instruction B. evaluation of a particular program C. evaluation of students studying in an organization D. evaluation of recreational facilities in an organization
Answer:
B. evaluation of a particular program
Explanation:
Before students enrol into any given discipline, they should first ensure that their program of choice is well accredited. In a specific program, specialized accreditation has the function of telling would be students if the program meets up with academic standards in the field
Accreditation is a way of assessing faculty and curriculum quality of schools to make sure that they are up to academic standards and are also preparing students to future success in the field.
The production process of rods from machine "A" yields specimen with the following specs. Mean: µ(LA)=20.00mm, STD: s(LA)=0.50mm. You need to purchase new machine to increase the production capacity and accuracy together. If the new machine "B" will produce half of the total rods, what is the STD, s(LB), that needs to achieve the total STD, s(LT)=0.4mm? Assume Corr(A,B)=0.4
Answer: the standard deviation STD of machine B is s (Lb) = 0.4557
Explanation:
from the given data, machine A and machine B produce half of the rods
Lt = 0.5La + 0.5Lb
so
s² (Lt) = 0.5²s²(La) + 0.5²s²(Lb) + 0.5²(2)Cov (La, Lb)
but Cov (La, Lb) = Corr(La, Lb) s(La) s(Lb) = 0.4s (La) s(Lb)
so we substitute
s²(Lt) = 0.25s² (La) + 0.25s² (Lb) + 0.4s (La) s(Lb)
0.4² = 0.25 (0.5²) + 0.25s² (Lb) + (0.5)0.4(0.5) s(Lb)
0.64 = 0.25 + s²(Lb) + 0.4s(Lb)
s²(Lb) + 0.4s(Lb) - 0.39 = 0
s(Lb) = { -0.4 ± √(0.16 + (4*0.39)) } / 2
s (Lb) = 0.4557
therefore the standard deviation STD of machine B is s (Lb) = 0.4557
What are the common approximations made in the analysis of heat exchangers?
Answer: making sure that they are up to date
Explanation:
Use the diagram to determine total resistance. (Round the FINAL answer to one decimal place.) Note: Use the rated voltage and wattage to determine resistance. Note: Ra and Rb represent the resistance of the wire. The 120 volts of the motor and lamps is their rated voltage and not the actual voltage. I know the answer is 22.7 Ohms. I get very close, but I am not 100%.. I need to be 100%. If you can also: with the same diagram I need the total current as well! Thank you very much.
Answer:
22.6622 Ω ≈ 22.7 Ω5.29516 A ≈ 5.3 AExplanation:
For an electric motor, 1 hp = 746 W, so 1/2 hp = 373 W. Then the total wattage of the load is ...
Pl = 373 +100 +100 +75 = 648 W
The equivalent resistance is ...
R = V^2/P = (120 V)^2/(648 W) = 22 2/9 Ω
Adding the wiring resistance, we get a circuit resistance of ...
22.2222 +0.22 +0.22 = 22.6622 Ω . . . . total circuit resistance
Then the circuit current is ...
120 V/(22.6622 Ω) ≈ 5.29516 A
Circuit resistance is about 22.7 Ω; circuit current is about 5.3 A.
_____
Exact values are 5099/225 ohms and 27000/5099 amps. Of course, these assume the motor and lamps are purely resistive, which they are not.
The heat transfer rate per unit area in a thermal circuit is equivalent to what quantity in an electric circuit? A. voltage B. current C. resistance D. inductance
Answer:
A. voltage
Explanation:
The rate of heat transfer per unit area in a thermal circuit is equivalent to the voltage in an electrical circuit.
This is because, within an electrical circuit the voltage is supplied by a generator, which can be batteries, batteries, or others. The moment the electrical voltage acts within a circuit, it will consist of the gradient of electrical potential between two points, which will cause the electrons to move from the point with the highest concentration to the point with the lowest concentration (similar to the transfer of heat from the thermal circuit) generating the electric current.
how do you make coke for steel?
__________ use cleaning solutions that eventually become spent and must be disposed of properly
a sump pits
b car washers
c part washers
d tire cleaners
Answer:Part washers
Explanation:
I did it..
The only option that uses cleaning solutions that become spent and must be disposed properly is;
Option C; Parts Washers
To answer this question, let us examine each option;
Option A; Sump Pits; These are basins at the lowest part of specific areas designed to allow all water collected in that basin area to drain into it. This has no business with cleaning solution.
Option B; Car washers; These are like machine dryers used to clean the exterior and interior parts of motor vehicles.
Option C; Part Washers; These are mechanical devices that are designed for cleaning to remove debris, grime, oil dirt, paint, and other substances that could potentially cause contamination from parts in order to get them ready for assembling, packaging, or even coating. They are basically used to clean parts to get them ready for functional use.
Option D; Tire cleaner is just used to clean tire but is not something that becomes spent and should be disposed properly as it is more like a liquid.
The only correct option is Option C.
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What are materials engineers trying to discover when they study different materials? Whether or not materials corrode and oxidize how materials perform and deteriorate if certain materials have been used in the past and at which historical ages which metals conduct heat
Answer:
Material engineers study various materials to discover the reason and cause of its existence, the chemical properties, how long it has been there, and how it impacts human life.
Explanation:
Material engineer is an engineering discipline that focuses to improve human life by studying the environment and the various elements or materials it holds.
It uses the power of pure science to test and analysis its findings, documents its features and exposes them to the world. Materials like metals and other elemental forms were all tested by these engineers to determine its history and chemical and biological use.
Answer:
how materials perform and deteriorate
Explanation:
A tensile test uses a test specimen that has a gage length of 50 mm and an area = 206 mm2. During the test, the specimen yields under a load of 97,944 N. The corresponding gage length = 50.2 mm - this is at the 0.2 percent yield point. The maximum load of 162,699 N is reached at a gage length = 63 mm. If fracture occurs at a gage length of 71 mm, determine the percent elongation in % - enter your answer as a whole number, not as a fraction.
Answer:
The percent elongation in the length of the specimen is 42%
Explanation:
Given that:
The gage length of the original test specimen [tex]L_o[/tex] = 50 mm
The final gage length [tex]L_f[/tex] = 71 mm
The area = 206 mm²
maximum load = 162,699 N
To determine the percent elongation in %, we use the formula:
[tex]\%EL = \dfrac{L_f-L_o}{L_o}\times 100[/tex]
[tex]\%EL = \dfrac{71 \ mm-50 \ mm}{50 \ mm}\times 100[/tex]
[tex]\%EL = \dfrac{21 mm}{50 \ mm}\times 100[/tex]
[tex]\%EL = 0.42 \times 100[/tex]
[tex]\mathbf{\%EL = 42 \%}[/tex]
The percent elongation in the length of the specimen is 42%