The three isotopes of carbon are C-12, C-13, and C-14. The carbon isotope 14C, which is the most commonly used radioactive cosmogenic isotope, can be used to date occurrences that took place within the last 60,000 years or so.
There are three types of carbon isotopes. Carbon-12 (12C) is by far the most prevalent isotope of carbon and it has six neutrons in relation to its six protons. Carbon-13 (13C), the second-heaviest carbon isotope, has seven neutrons. Since neither 12C nor 13C undergoes radioactive decay over time, they are both referred to as stable isotopes. The nucleus of the rare carbon-14 (14C) isotope has eight neutrons. This isotope, in contrast to 12C and 13C, is unstable or radioactive. A 14C atom will eventually transform into a stable byproduct.
The process of radiocarbon dating, also known as carbon dating or carbon-14 dating, uses the characteristics of radiocarbon (14C), a radioactive isotope of carbon, to estimate the age of an object made of organic material.
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Two physics students, Ben and Bonnie, are in the weightlifting room. Bonnie lifts the 50 kg barbell over her head (approximately .60 m) 10 times in one minute; Ben lifts the 50 kg barbell the same distance over his head 10 times in 10 seconds. Which student does the most work? Which student delivers the most power? Explain your answers.
Answer:
Both of them
Explanation:
Bile is a compound that helps in the digestion of fat and eliminates waste products from the blood. True O False
Answer:
That should be true because bile is ¨a bitter greenish-brown alkaline fluid that aids digestion and is secreted by the liver and stored in the gallbladder.¨
Explanation:
What force must be applied to the end of a rod along the x-axis of length 2.25 m in order to produce a torque on the rod about the origin of 11 z-hat N·m? Choose among the available options below. x,y,z,-z
Answer:
4.9N approx.Explanation:
Step one:
given data
length of rod r= 2.25m
Required torque = 11 Nm
Required
The force needed to produce a torque of 11Nm
Step two:
"By definition, Torque is the twisting force that tends to cause rotation.
The point where the object rotates is known as the axis of rotation."
Mathematically,
[tex]\tau = rF\sin\theta[/tex]
[tex]\tau[/tex] = torque
r = radius
F = force
[tex]\theta[/tex] = angle between F and the lever arm
in this case is zero
[tex]\tau = rF\\\\F=\tau/r[/tex]
substituting we have
F=11/2.25
F=4.88N
F=4.9N approx.
Earthquakes
Shaking of the ground
Seismographs
Scientific method
Answer:
C. seismographs
Explanation:
Theirs another name for seismographs but c is correct
A boy is exerting a force of 70 N at a 50-degree angle on a lawnmower. He is accelerating at 1.8 m/s2. Round the answers to the nearest whole number.
What is the mass of the lawnmower?
What is the normal force exerted on the lawnmower?
The lawnmower accelerates in the positive horizontal direction, so that the net horizontal force is, by Newton's second law,
(70 N) cos(-50°) = m (1.8 m/s²)
where m is the mass of the lawnmower. Solve for m :
m = ((70 N) cos(-50°)) / (1.8 m/s²)
m ≈ 25 kg
The lawnmower presumably doesn't get lifted off the ground, so that the net vertical force is 0. If n is the magnitude of the normal force, then by Newton's second law,
n - m g + (70 N) sin(-50°) = 0
n = m g + (70 N) sin(50°)
n = (25 kg) (9.8 m/s²) + (70 N) sin(50°)
n ≈ 300 N
A 3900 kg truck is moving at 6.0 m/s what is the kinetic energy
Answer:
70200J
Explanation:
k.E = 1/2mv^2
K.E = 1/2(3900)(6)^2
Two ice-skaters are skating in circles on a frozen pond. Maria is making large circles with a radius of 12 m and skating 4.5 m/s. Her friend, Samantha, is making smaller circles with a radius of 6 m but is not skating as quickly, going only 3.8 m/s.
How could each skater increase her centripetal acceleration without changing the size of her path? Explain your reasoning.
Answer: Samantha has the largest centripetal acceleration of 2.4 m/s^2. Maria has only 1.69 m/s^2.
Explanation:
A 125,000 kg locomotive is traveling south at 1.0 m/s through a switching yard. A connected set of parked gondola cars weighing 1,750,000 kg are directly ahead. Determine the speed and direction of the completed train after the locomotive has been coupled to the cars.
Answer:
The speed of the completed train is 0.0[tex]\bar 6[/tex] m/s
The direction of the completed train is South
Explanation:
The given parameters are;
The mass of the locomotive, m₁ = 125,000 kg
The initial speed of the locomotive, v₁ = 1.0 m/s
The mass of the gondola cars, m₂ = 1,750,000 kg
The initial sped of the gondola cars, v₂ = 0
Let v₃ represents the speed of the completed train. From the principle of conservation of linear momentum, we have;
m₁·v₁ + m₂·v₂ = (m₁ + m₂)×v₃
Substituting the known values, gives;
125,000 × 1.0 + 1,750,000 × 0 = (125,000 + 1,750,000) × v₃
∴ v₃ = (125,000 × 1.0 + 1,750,000 × 0)/(125,000 + 1,750,000) = 1/15 = 0.0[tex]\bar 6[/tex]
v₃ = 0.0[tex]\bar 6[/tex] m/s
The speed of the completed train = 0.0[tex]\bar 6[/tex] m/s
The direction of the completed train = The direction of the locomotive = South.
How much power is used if a force of 35 newtons is used to push a box a distance of 10 meters in 5 seconds?w=350j
Answer:
How much power is used if 350J of work is done when pushing a box for 5 seconds.
Explanation:
the answer is 70watts
A train travels at a speed of 30mph and travelled a distance of 240 miles. How long did it take the train to complete its journey? Must show your work
Answer:
8
Explanation:
240 divided by 30 = 8
Which of the following is related to a person’s self-concept?
A) what neighborhood he or she lives in
B) his or her sense of self-worth
C) how good an athlete he or she is
D) how attractive he or she is
Answer:
Im not a 100 percent sure but i thinks it za A
Explanation:
what is the mass and volume of 1000kg/m3 of water?
Answer: The mass would be 1000m3 and the volume would be 1000kg
Explanation:
Where does compression often occur?
Answer:
a convergent boundary^^
Explanation:
hope it helped
A 0.85-kg arrow flies through the air at a speed of 19 m/s. What is the momentum of the arrow?
16 kg m/s
22 kg m/s
160 kg m/s
360 kg m/s
Answer:
16 kg m/sExplanation:
The momentum of an object can be found by using the formula
momentum = mass × velocity
From the question we have
momentum = 0.85 × 19 = 16.15
We have the final answer as
16 kg m/sHope this helps you
I WILL GIVE BRAINLYIST
Which of the following types of stars had the smallest initial mass? (10 points)
Group of answer choices
Blue main sequence
Neutron star
Red supergiant
White dwarf
Answer:
White dwarf
Explanation:
What types of energy is used to make a lamp work
Answer:
Electrical energy
Explanation:
The temp of the metal in a running car engine is 388 K. Find this temp in Celsius.
Answer:
115°c
Explanation:
°c=k-273
388-273=115
A 0.25-kilogram ball is observed to accelerate at 4,000 m/sec2 as it is hit with a bat.
How much force is exerted on the bat by the ball?
Answer:
1000 NExplanation:
The force acting on an object given it's mass and acceleration can be found by using the formula
force = mass × acceleration
From the question we have
force = 0.25 × 4000
We have the final answer as
1000 NHope this helps you
3. If I run 150m in 30 seconds, what speed will I have been running at?
Answer:
speed = distance/time
Explanation:
speed = 150/30
speed =5m/s
you were running fast .....5m/s is a good speed
A 615.00 kg race car is uniformly traveling around a circular race track. It takes the race car 20.00 seconds to do one lap around the 80.00 m radius circular track. What is the frequency of the race car's circular motion?
Answer:
The value is [tex]f = 0.05 \ Hz[/tex]
Explanation:
From the question we are told that
The mass of the car is [tex]m = 615 \ kg[/tex]
The period of the circular motion is [tex]T = 20 \ s[/tex]
The radius is [tex]r = 80 \ m/s[/tex]
Generally the frequency of the circular motion is
[tex]f = \frac{1}{T }[/tex]
=> [tex]f = \frac{1}{ 20 }[/tex]
=> [tex]f = 0.05 \ Hz[/tex]
As the amount of surface area increases, what happens to the rate of this reaction? If the antacid tablet were broken into eight pieces, what would be a reasonable estimate for the time of
as the surface area increases the rate of reaction also increases.
Explanation:
Answer:
A.) The rate is faster.
C.) 28 Seconds
Matter can go through a phase change and still have the same mass.
Answer:
True
Explanation:
In a physical change such as melting, can change its form but the total mass will remain the same. For example, in a chemical reaction, the total mass of substances that react will equal the mass of the products. However, it is important to mention that some phase changes such as from solid to liquid, the mass of an ice will be turned to the liquid what and during this phase change period, the mass of the ice consequently decreases.
What 2 factors affect the impulse on an object in a collision?
a toy car is wound up and released on the floor. it accelerates at a rate of 0.4 m/s/s . the mass of the care is 3kg. what is the force that the cars wheels exert on the floor.
Answer:
1.2N
Explanation:
f=m×a
m=3kg
a=.4m/s/s
3×.4=1.2
kg×m/s/s = N
Witch TWO types of rock are formed as particles get pushed closer together A. Intrusive igneous B. Extrusive igneous C. Sedimentary D. Metamorphosis
Answer:
C
Explanation:
Sedimentary rocks are the product of
1) weathering of preexisting rocks,
2) transport of the weathering products,
3) deposition of the material
4) compaction (two rocks pushed together)
5) cementation of the sediment to form a rock.
A jet aircraft is traveling at 214 m/s in hor-
izontal flight. The engine takes in air at a
rate of 115 kg/s and burns fuel at a rate of
2.53 kg/s. The exhaust gases are ejected at
276 m/s relative to the aircraft.
Find the thrust of the jet engine.
Answer in units of N.
Answer:
The thrust is [tex]F = 7828.3 \ N [/tex]
Explanation:
From the question we are told that
The speed of the jet aircraft is [tex]v = 214 \ m/s[/tex]
The rate at which the engine takes in air is [tex]\^ Q = 115 \ kg/s[/tex]
The rate at which the engine burns fuel is [tex]\r m = 2.53 \ kg/s[/tex]
The speed of the exhaust gases is [tex]u = 276 \ m/s[/tex]
Generally the thrust of the engine is mathematically represented as
[tex]F =[ \^ Q * ( u - v )] + (\r m * u)[/tex]
=> [tex]F =[ 115 * ( 276 - 214 )] + (2.53 * 276)[/tex]
=> [tex]F = 7828.3 \ N [/tex]
HOW CAN AN APPLE DEMONSTRATE POTENTIAL AND ENERGY
Answer and Explanation in one:
In physics, potential energy is the energy held by an object because of its position relative to other objects, stresses within itself, its electric charge, or other factors. So basically, you could possibly demonstrate with a variety of examples. One example may be just sitting on a table, waiting to get rolled off. I know it sounds silly, so here's another example. You are holding a bow and arrow, you pull back the arrow, aiming at the target. You are holding the arrow, filling it with potential energy. When it is let go, it is kinetic energy, the act of an object in motion, slowly riding of it's potential energy.
I WILL GIVE BRAINLIEST IF SOMEONE GETS THIS......
A eureka can of mass 100g and cross-section area 100cm2 is filled with water of density 1g/cm3. A piece of metal of mass 20g and density 8g/cm3 is lowered into the can. ( height of can 10cm ) calculate:
a) the total mass of can before the metal was lowered.
b) the volume of water that overflowed
c) the final mass of can and its content
Answer:
Explanation:
a)
Firstly to calculate the total mass of the can before the metal was lowered we need to add the mass of the eureka can and the mass of the water in the can. We don't know the mass of the water but we can easily find if we know the volume of the can. In order to calculate the volume we would have to multiply the area of the cross section by the height. So we do the following.
100[tex]cm^{2}[/tex] x 10cm = 1000[tex]cm^{3}[/tex]
Now in order to find the mass that water has in this case we have to multiply the water's density by the volume, and so we get....
[tex]\frac{1g}{cm^{3} }[/tex] x 1000[tex]cm^{3}[/tex] = 1000g or 1kg
Knowing this, we now can calculate the total mass of the can before the metal was lowered, by adding the mass of the water to the mass of the can. So we get....
1000g + 100g = 1100g or 1.1kg
b)
The volume of the water that over flowed will be equal to the volume of the metal piece (since when we add the metal piece, the metal piece will force out the same volume of water as itself, to understand this more deeply you can read the about "Archimedes principle"). Knowing this we just have to calculate the volume of the metal piece an that will be the answer. So this time in order to find volume we will have to divide the total mass of the metal piece by its density. So we get....
20g ÷ [tex]\frac{8g}{cm^{3} }[/tex] = 2.5 [tex]cm^{3}[/tex]
c)
Now to find out the total mass of the can after the metal piece was lowered we would have to add the mass of the can itself, mass of the water inside the can, and the mass of the metal piece. We know the mass of the can, and the metal piece but we don't know the mass of the water because when we lowered the metal piece some of the water overflowed, and as a result the mass of the water changed. So now we just have to find the mass of the water in the can keeping in mind the fact that 2.5[tex]cm^{3}[/tex] overflowed. So now we the same process as in number a) just with a few adjustments.
[tex]\frac{1g}{cm^{3} }[/tex] x (1000[tex]cm^{3}[/tex] - 2.5[tex]cm^{3}[/tex]) = 997.5g
So now that we know the mass of the water in the can after we added the metal piece we can add all the three masses together (the mass of the can. the mass of the water, and the mass of the metal piece) and get the answer.
100g + 997.5g + 20g = 1117.5g or 1.1175kg
Which point has the most Potential energy? [Select]
Which point has the most Kinetic energy? [ Select ]
Answer:
Most potential energy: A
Most kinetic energy: D
Explanation:
Kinetic Energy is the type of energy an object has due to its state of motion. It's proportional to the square of the speed.
The equation for the kinetic energy is:
[tex]\displaystyle K=\frac{1}{2}mv^2[/tex]
Where:
m = mass of the object
v = speed at which the object moves
The gravitational potential energy is the energy stored in an object because of its height h in a gravitational field.
It can be calculated with the equation:
U=m.g.h
The point where the object has the most potential energy is that where it has more height. It corresponds to point A.
When the object is at zero height, all of its potential energy was transformed to kinetic, thus the point where the kinetic energy is D.
Most potential energy: A
Most kinetic energy: D
Answer:
potentail enegry at point a and kinetic enegy at point c
Explanation:
i did this i fourth grade please mark brainlist
The weight of an object is measured in air to be 7.0 N. The
object is then immersed in water and its apparent weight is
measured to be 4.0 N. Determine the buoyant force and state
whether or not the object floats.
Answer:
Buoyant force = 3.0 N
The object will not float.
Explanation:
Apparent weight of a body immersed in water is the actual weight of object minus buoyant force
Given in the question that;
Weight of object in air = 7.0 N
Apparent weight of object = 4.0 N
4.0 N = 7.0 N - Buoyant force
Buoyant force = 7.0 - 4.0 = 3.0 N
In this case, the buoyant force is less than weight of the object thus the object will sink.