What are Robert Godard’s ideas

A. The ball is moving 17.15 m/s when it was 10 m above the ground

B. The time required for the ball to reach the ground is 2.26 s

h = ½gt²

15 = ½ × 9.8 × t²

15 = 4.9 × t²

Divide both side by 4.9

t² = 15 / 4.9

Take the square root of both side

t = √(15 / 4.9)

t = 1.75 s

v = gt

v = 9.8 × 1.75

v = 17.15 m/s

h = ½gt²

25 = ½ × 9.8 × t²

25 = 4.9 × t²

Divide both side by 4.9

t² = 25 / 4.9

Take the square root of both side

t = √(25 / 4.9)

t = 2.26 s

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A hallmark of courage is being ready and willing to face challenging or uncomfortable circumstances. The word "bravery" is similar. It can also include doing so, even though confronting these situations fearlessly is generally thought of as showing courage.

In reality, courage is the capacity to move forward in the face of fear. The ability to behave bravely in the face of any anxiety or tension is what is meant by having courage. One of the finest ways to be courageous is to recognize your fears and then decide not to let them stop you. having the guts to handle risk in a responsible manner as opposed to acting cowardly or irrationally confident.

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The gravitational acceleration on the top of Mount Everest is 9.773 m/s^2.

What is gravitational acceleration?

Gravitational acceleration (symbolized g) is an expression used in physics to indicate the intensity of a gravitational field. It is expressed in meters per second squared. At the surface of the earth, 1 g is about 9.8 meter per squared second.

So, as mentioned in question g at surface of the earth is 9.81.

and the height of the Mount Everest is 8848 m.

Let, g' be the acceleration due to gravity on the top of Mount Everest.

By the equation,

[tex]g' = g(1-\frac{2h}{h})[/tex]

[tex]g' = 9.8(1-\frac{17696}{6500000})[/tex]

[tex]g' = 9.8(1-0.00276)[/tex]

[tex]g' = 9.8(0.99724)[/tex]

[tex]g' = 9.773[/tex]

Therefore, the gravitational acceleration at the top of the Mount Everest is [tex]9.773 \frac{m}{s^2}[/tex] (9.773 meter per squared second).

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Answer:

metric

Explanation:

The number of stars present in the galaxy is 10 raised to the power of 14. So the exponent is equal to 14.

Given in the question

Total mass of the particular galaxy = 10 to the power of 47 grams

The average mass of the star in the galaxy = 10 to the power of 33 grams

We know that the total mass of the galaxy which is a collection of several thousand stars is equal to the sum of all the stars present in it. Also, the total mass of the galaxy can be calculated by multiplying the average mass of a star in the galaxy by the number of stars that are there in the galaxy.

So, Total mass = Average mass × Number of stars in the galaxy

Number of stars in the galaxy = Total mass of the galaxy/ Average mass of the star

Put in the values, we get

Number of stars in the galaxy = 10^47/10^33

Number of stars in the galaxy = 10^(47-33)

Number of stars in the galaxy = 10^14

So, the number of stars present in the galaxy is 10 raised to the power of 14. So the exponent is equal to 14.

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The additional charge that flows to the positive plate from the 8 Volts battery is  12 x 10⁻³ Coulomb's.

We have an uncharged capacitor which is charged in two different ways using battery of two different voltages. Firstly, it is connected to the terminals of a 4.0 V battery, and 12 μc of charge flows to the positive plate. Then, the 4.0 V battery is disconnected and replaced with a 8.0 V battery

We have to determine the Additional charge that flows to the Positive plate from this 8 V battery.

Capacitance is the ability of an object to collect and store energy in the form of an electrical charge. Mathematically -

C = Q/V

According to the question, we have -

Electric potential of battery 1 = V[1] = 4 V

Charge flow from battery 1 to the positive plate = Q[1] = 12 x 10⁻³ C

Electric potential of battery 2 = V[2] = 8 V

Now, using the following relation, we will find Q[2] {Charge flow from battery 2 to the positive plate} →

V[1] / V[2] = Q[1] / Q[2]

Substituting the values -

Q[2] = (12 x 10⁻³ x 8)/4 = 24 x 10⁻³ C

Additional Charge that flowed to the positive plate →

Q[2] - Q[1] = 12 x 10⁻³ Coulomb's

Hence, the additional charge that flows to the positive plate is  [tex]12\times 10^{-3}[/tex] Coulomb's.

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[ The question given is incomplete, the complete question is -

"An uncharged capacitor is connected to the terminals of a 4.0 v battery,  and 12 μc flows to the positive plate. the 4.0 v battery is then disconnected and replaced with a 8.0 v battery, with the positive and negative terminals connected in the same manner as before. How much additional charge flows to the positive plate" ]

The acceleration of the ball is zero.

The term acceleration refers to the rate of change of velocity with time thus we can write;

a = d(v)/dt. This simply means the change in velocity with respect to time in the calculus notation.

This implies that before we can talk of acceleration the velocity must be changing. We can not have acceleration when the velocity is constant. It violates the very definition of acceleration. As such, the acceleration of the ball is zero.

Thus whether over a period of three seconds or over an infinite period of time, the acceleration would remain zero because the velocity is constant and does not change over the time interval as given.

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The annual 10-k report costco wholesale corporation is

a. 4.28 billion dollars.

b. 1.128 billion.

c. $2,393 billion

d. $481 million less.

Costco Wholesale Corporation: What is it?

The fee is a multibillion-dollar large container retail organisation that operates a network of comrades for the large container shops. it's miles the fifth-biggest retailer inside the globe as of the year 20220. It offers wine and natural goods for sale. From these operations, price receives $4,285 in coins. The coins spent on the brand new assets become system for sales of $2,393 million USD, and the depreciation expenditure changed into $1,127 USD. The value increases its holdings to roughly 481 million USD.

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Therefore, the net force acting on particle 3 is 139.68 × 10—5 N, and the angle made it by with at the +x axis is 19.1°.

The charge of particle 1 is q1.

q1 = -6.6nC

The charge of particle 2 is q2.

q2 = -13.2 nC

Sides of the equilateral triangle = 3 cm = 3 × 10 —² m.

The force acting on particle 1 is,

[tex]F _{1} = \frac{kq_{1} q_{3}}{a ^{2} } [/tex]

[tex] = \frac{9 \times 10 ^{9} \times 6.6 \times 10 ^{ - 9} \times 8 \times 10 ^{ - 9} }{9 \times 10 ^{ - 4} } [/tex]

[tex]F _{1} = 52.8 \times 10 ^{ - 5} \: N[/tex]

[tex]F _{1} = F _{1} \: cos(60°)i + F _{1} \: sin(60°)j[/tex]

[tex]= ( - 26.4 \: i \: + 45.7 \: j \: ) ×10 ^{ - 5} [/tex]

The force acting on particle 2 is,

[tex] = \frac{9 \times 10 ^{9} \times 3.2 \times 10 ^{ - 9} \times 8 \times 10 ^{ - 9} }{9 \times 10 ^{ - 4} } [/tex]

[tex] = - 105.6 \times 10 ^{ - 5} \: j[/tex]

The net force acting on particle 3 is,

[tex]F_{Net} =F _{1} + F _{2}[/tex]

[tex] = ( - 132 \times 10 ^{ - 5} \: i + 45.7 \times 10 ^{ - 5} \: j)[/tex]

[tex]F_{Net} =139.68 \times \: 10 ^{ - 5} \: N[/tex]

Thus, the net force acting on particle 3 is 139.68 × 10—5 N.

Let the angle made by it with at the +x axis be θ.

[tex]cos \: θ = \frac{ - 132 \times 10 ^{ - 5} }{139.6 \times 10 ^{ - 5} } [/tex]

θ = 19.1°

Therefore, the net force acting on particle 3 is 139.68 ×

10—5 N and the angle made it by with at the +x axis is 19.1°.

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The time of flight of the launched particle will be 2v₀ sinθ / g.

The study of motion without considering the mass and the cause of the motion.

A projectile is launched from level ground with an initial speed v₀ at an angle θ with the horizontal. If air resistance is negligible.

Then the time of flight of the launched particle will be given as,

Determine how long it requires the projectile to reach its highest point in order to calculate the flight duration. Just twice as long as the maximum altitude is the travel time.

[tex]\rm v_y = v_{o_y} + a_y t[/tex]

At maximum height, [tex]\rm v_y = 0[/tex].

The time to reach maximum height is given as

[tex]\rm t_{1/2} = - \dfrac{v_{o_y} }{ a_y}[/tex]

The time of flight is given as,

[tex]\rm t = 2 \times t_{1/2} = - \dfrac{2v_{o_y}}{ a_y}[/tex]

Substituting in [tex]\rm v_{o_y} = v_o \ \sin(\theta ) \ and \ a_y = -g[/tex], then we have

The time of flight of the launched particle will be 2v₀ sinθ / g.

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Data can be displayed as graphs, which are graphic representations, to help identify trends more quickly.

A graph is a visual representation of the relationship between two variables, typically two variables that are measured along an axis that is perpendicular to the other two axes. A graph, in a nutshell, is a visual representation of data for easy comprehension. Graphs are commonly used to show scientific data so that readers may immediately see trends. Graphs are often used in the social sciences to visually convey important information. A network's connection between lines and points is represented mathematically by a graph. The points and arcs that connect them make form a graph.

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The distance of Uranus from the Sun in astronomical units is 9.13 AU.

What is astronomical unit?

In our solar system, distances are really great. Therefore, astronomers frequently avoid using miles or kilometers when describing the distances to planets, asteroids, comets, or spacecraft. They substitute astronomical units, or AU, which represent the typical separation of the Earth from the sun. That translates to around 93 million miles, 150 million kilometers, or 8 light-minutes.

By above definition, we can say that

1 astronomical unit (AU) = 150 million kilometers (km)

In order to find the distance in astronomical units multiply the given distance expressed in kilometers of Uranus, which is 2870 million kilometers, by the unit ratio, 1 AU per 150 million kilometers, as shown on the expression:

[tex](2870 million Km)(\frac{1Au}{150millionKm})[/tex]

Therefore, the distance of Uranus from the Sun is 19.13 AU.

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​

Answer:

1,188.25 J

Explanation:

PE= mgh

PE=(97)(9.8)(1.25)

PE= 1,188.25 J

The frequency of these vibrations if the car moves at 43.0 m/s is 1954.54 Hz.

Given that,

The speed of the car = 43m/s.

or the speed of the car = 4300cm/s

A tire has a tread pattern with a crevice = 2.20cm

Since the crevice hits every 2.20cm,

This happens,

= 4300cm / 2.20

= 1954.54.

Therefore,

The frequency is 1954.54Hz

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University physics with modern physics and mastering physics access code (15th edition), by h. young and r. freedman.

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Low-energy state of condensed matter is characterized by structural rigidity and resistance to changes of shape or volume is solid.

When particles are arranged and packed closely -- compared to those in a gas or liquid -- and are relatively stable, they are considered to be in solid state. Solids tend to have a rigid shape, as the atoms or molecules of matter in the solid state are generally compressed and tightly connected through the chemical bonds. These bonds can produce an amorphous shape or regular lattice.

In electronics, the solid state refers to components and systems based entirely on semiconductor materials, such as silicon, germanium or gallium arsenide. Transistors and diodes -- the most common solid-state devices -- are often combined with resistors, capacitors and other components to create the integrated circuits (ICs). All the electronic systems incorporate ICs and, therefore, transistors.

The particles that make up solid have the lowest energy, and vibrate in place. This results in the characteristics of a solid, such as definite shape and volume. A solid is actually the frozen state of matter for substance. A substance does not have to freeze at cold temperature. For example, the faucet you have at your lab station in chemistry, and the faucets in your home are frozen the stainless steel; and so is your desk, pencils, pens, cell phones, and computers are all frozen. In fact anything solid is frozen.

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By ideal gas approximation, the final to initial density ratio is 1/2.

We need to know about the ideal gas theory to solve this problem. The ideal gas is assumed that there is no interaction between particles in a gas. It can be determined by the equation

P . V = n . R . T

where P is pressure, V is volume, n is the number of moles gas, R is the ideal gas constant (8.31 J/mol.K) and T is temperature.

From the question above, we know that

P2 = 0.5 P1

Pressure is inversely proportional to pressure, hence it can be written as

P ~ (1/V)

Assuming the temperature does not change, the ratio of pressure is

P1 / P2 = (1/V1) / (1/V2)

P1 / P2 = V2 / V1

P1 / 0.5P1 = V2 / V1

V2 = 2 V1

Find the density ratio

ρ2 / ρ1 = (m/V2) / (m/V1)

ρ2 / ρ1 = V1 / V2

ρ2 / ρ1 = V1 / 2V1

ρ2 / ρ1 = 1 / 2

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A rock is thrown vertically upward at an initial velocity of 70 m/s.

The approximate acceleration of the rock when it reaches its maximum heigh is- zero

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The change in the internal energy of the system is 96 j.

The change in the internal energy of the system is given by

              Δ U = Q + W

Q = 71.0 j

W = 25.0j

Δ U = Q + W

Δ U = 71 +25

Δ U = 96 j

The system's kinetic energy and potential energy together make up the system's internal energy. When a reaction is conducted at a constant pressure, the internal energy change (U) of the reaction is equal to the heat acquired or lost (enthalpy change).

A thermodynamic system's internal energy is its total internal energy. It is the energy required to build or prepare the system in the internal state that it is in at the time.

In thermodynamics, internal energy is a quantity or state function that characterizes a substance's energy when capillary effects and other external fields, such as electric and magnetic forces, are absent.

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Purpose, accuracy, and authority.

The first paragraph of your essay should outline your topic provide the background information you need to understand your claim, outline the evidence you present, and state your thesis. dissertation statement. This is part of the first paragraph. The five parts include a strong introductory paragraph with a clear thesis, three main paragraphs supported by detailed evidence, and a compelling conclusion.

Students should also use transition words and phrases to help readers explain their points of view. Developed by philosopher Stephen E. Toulmin, his Toulmin Method is a style of reasoning in which he decomposes claims into six components Claim Inference Warrant Limitation Refutation and Support. In Toulmin's method, each argument begins with three basic parts assertion justification and justification. These are the thesis statement the target audience needs, and support.

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The pig is moving slower in the negative direction during the next 2 seconds.

The term acceleration refers to the change in the velocity of the object with time. Now we know that velocity is a vector quantity. This implies that we have to take the magnitude and the direction into focus when we are discussing about the velocity.

Similarly, the acceleration is a vector quantity and the magnitude and the direction must also be taken into account when dealing with the acceleration.

In this case, it is clear that a  pig on roller skates is moving with an initial velocity of -10 m/s and is accelerating at a rate of 2m/s/s.

Seeing that the velocity is negative, we can see that the pig roller coaster is moving the negative direction. Recall that the axes must be defined such that one is negative and one is positive.

Having said that, we can conclude that; the pig is moving slower in the negative direction during the next 2 seconds.

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Light is emitted, energy is  9.16 × [tex]10^{-20}[/tex] J , frequency is 1.38 × [tex]10^{-14}[/tex] [tex]s^-[/tex]    

and wavelength is  2.17 × [tex]10^{-6}[/tex] m      

n = 7 → n = 4

higher → lower

Light is emitted

[tex]\Delta[/tex]E = [tex]\frac{-13.6}{7^2} - (\frac{-13.6}{4^2})[/tex]

[tex]\Delta[/tex]E = 0.85 - 0.277

     = 0.572 eV

[tex]\Delta[/tex]E = 9.16 × [tex]10^{-20}[/tex] J              -> [energy calculated]

[tex]\Delta[/tex]E = hv           (h is Planck's constant and v is frequency)

v = [tex]\frac{\Delta E}{h}[/tex]  = [tex]\frac{9.16 * 10^{-20}}{6.626 * 10^{-39}}[/tex]

v = 1.38 × [tex]10^{-14}[/tex] [tex]s^-[/tex]                 ->[frequency calculated]

[tex]\Delta[/tex]E = [tex]\frac{hc}{\Lambda}[/tex]            (c is speed of light)

[tex]\Lambda[/tex] = [tex]\frac{hc}{\Delta E}[/tex]

[tex]\Lambda[/tex] = [tex]\frac{6.626 * 10^{-34} . 3*10^8 m/s}{9.16 *10^{-20 J} }[/tex]

[tex]\Lambda[/tex] = 2.17 × [tex]10^{-6}[/tex] m                    ->[wavelength calculated]

Energy, according to scientists, is the capacity for work. The ability to transform energy from one form to another and use it to perform tasks is what makes modern civilization possible. People utilize energy to travel by foot and bicycle, drive vehicles on land and in water, prepare meals on stoves, create ice in freezers, illuminate our homes and workplaces, create goods, and launch people into space.

Energy comes in a wide variety of forms, including:

These energies can be divided into two categories for working energy:

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The speed of a moving rod that has a length 55 % that of an identical rod in terms of c will be v/c= 0.824

or v = 0.824c.

The formula for length contraction rod is,

L = L1{√(1-v^2/c^2)}

Here L is the length of the moving rod

L1 is the length of the stationary rod

v is the velocity with which the rod is moving

c is the speed of light

We are given that

L = 55% of L1 = 0.55L1

Putting the values in the above equation,

0.55L1 = L1{√(1-v^2/c^2)}

0.55 = {√(1-v^2/c^2)}

Squaring both sides

(0.55)^2 = 1- v^2/c^2

V^2/c^2 = 1 - 0.3025

V^2/c^2 = 0.6975

v/c = 0.824

Thus, the speed of  a moving rod that has  a length 55 % that of an identical rod in terms of c will be v/c= 0.824 or v = 0.824c.

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The statement is false, that the greatest magnification on the compound light microscope can be achieved by the use of the high-power objective lens.

A microscope with numerous lenses and its own light source is referred to as a compound light microscope. In this type of microscope, the rotating nosepiece is positioned closer to the specimen and contains the objective lenses, while the binocular eyepieces house the ocular lenses.

The compound binocular microscope is now more often utilized, even though it can occasionally be found as monocular with only one ocular lens.

Zacharias Jansen's 1595 invention of the compound microscope with collapsible tubes and a 9X magnification produced the first light microscope.

Since then, microscopes have advanced significantly; the strongest compound microscopes available today have magnifications of 1,000 to 2,000X.

Hence, the statement is false that it can be achieved by using the high power objective lens.

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1.72*10^-9

On an empty capacitor, there is no dielectric so E= 8.85E-12

C=EA/(d)

c is capacitance, A is area , d is distance between the parallel plate and E is dielectric constant.

C=(8.85E-12 c2/Nm2)(0.535m2)/ (2.75*10^-3m)

C= 1.72*10^-9

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The change in the internal energy of the gas is ΔE int =0 J.

Q=250J heat is absorbed by the gas in this process.

What is  ​isothermal process?

A thermodynamic process known as an isothermal process keeps the system's temperature constant. Because heat is transferred into or out of the system so slowly, thermal equilibrium is preserved.

Givens:

Vi =0.5 L=0.5×10^ −3 m^3

Vf =4.0 L=4.0×10^−3 m^3

W= 250 J

T= 300 K

Because the gas temperature is constant, the process is ISOTHERMAL. As a result, the system's internal energy is constant.

ΔE int =0 J

We know that, ΔE int =Q−W

And we are aware that there has been no change in the system's inherent energy.

Therefore,0=Q−W

Q=W=250J

Q=250J

​

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Question:

When a dilute gas expands quasi-statically from 0.50 to 4.0 L, it does 250 J of work. Assuming that the gas temperature remains constant at 300 K, (a) what is the change in the internal energy of the gas? (b) How much heat is absorbed by the gas in this process?

The electric field between the plates is 50,000 N/C.

It is provided that the separation d between the plates is 4.4 mm and the potential difference V between the plates is 220 V.

The electric field E between the plates can be formulated as follows.

E=[tex]\frac{V}{d}[/tex]

substituting the values in the equation,

E= [tex]\frac{220}{0.0044}[/tex]

E= 50,000 N/C

Hence, we can say that the electric field between the plates is 45833.33 N/C.

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The number of walking paces as you walk down main street (0.25 miles) is 720 walking paces

1 mile = 5280 feet

Therefore,

0.25 mile = (0.25 mile × 5280 feet) / 1 mile

0.25 mile = 1320 feet

1 feet = 12 inches

Therefore,

1320 feet = (1320 feet × 12 inches) / 1 feet

1320 feet = 15840 inches

22 inches = 1 walking pace

Therefore,

15840 inches = (15840 inches × 1 walking pace) / 22 inches

15840 inches = 720 walking paces

Thus, we can conclude that as you walk down main street (0.25 miles), there are 720 walking paces

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