What are 3 items that need to be addressed in the coding quality plan that will help achieve the kpi of 98 ccuracy?

The expression (2⁷ · 3⁻⁵ · 9)⁴ is equivalent to the power expression 2²⁸ / 3¹² = 505.109.

In this problem we find an expression involving several numbers in power form and we must simplify into a single real number by using algebra properties:

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The statement lim infn sₙ > lim infn tₙ and lim sup sₙ ≤ lim sup tₙ is proved such that sₙ ≤ tₙ for all n≥n₀.

The biggest element in P, if one exists, that is less than or equal to each element of S is known as the infimum of a subset S of a partially ordered set P. As a result, the phrase largest lower bound is also frequently employed. A set's infimum is its highest upper bound, while its supremum is its lowest upper bound. The supremum is the smallest upper bound of a set, whereas the maximum is the largest member of a set. The largest number in one column that is less than or equal to the target value in the other column is found using the greatest lower bound (glb) operator. The smallest number that is larger than or equal to the target number is discovered using the least upper bound (lub) operator.

Let us suppose that sₙ ≤ tₙ if n≥N, but that

lim infn sₙ > lim infn tₙ.

Let [tex]E_{s}[/tex] denote the set of all subsequential limits of {sₙ}, and let [tex]E_{t}[/tex] denote the set of all subsequential limits of {tₙ}. Then

inf [tex]E_{s}[/tex] >inf [tex]E_{t}[/tex].

This implies that there exists some x∈[tex]E_{t}[/tex] such that inf [tex]E_{s}[/tex] >x>inf [tex]E_{t}[/tex]., since otherwise inf [tex]E_{t}[/tex]. would not be the greatest lower bound of [tex]E_{t}[/tex]. Hence some subsequence of {tₙ}, say {tₙ}, converges to x< inf [tex]E_{s}[/tex].

lim sup sₙ ≤ lim sup tₙ.

Let [tex]E_{s}[/tex] denote the set of all subsequential limits of {sₙ}, and let [tex]E_{t}[/tex] denote the set of all subsequential limits of {tₙ}. Then

sup [tex]E_{s}[/tex] ≤ sup [tex]E_{t}[/tex].

This implies that there exists some x∈[tex]E_{t}[/tex] such that sup [tex]E_{s}[/tex] ≤ x ≤ sup [tex]E_{t}[/tex]., since otherwise sup [tex]E_{t}[/tex]. would be the greatest lower bound of [tex]E_{t}[/tex]. Hence some subsequence of {tₙ}, say {tₙ}, converges to x< sup [tex]E_{s}[/tex].

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Answer:

5 days

Step-by-step explanation:

as the photo saying

Answer:

both are rational numbers

Step-by-step explanation:

Answer:

both are irrational numbers.

Step-by-step explanation:

Answer: y=3x+1

Step-by-step explanation:

Slope formula: m=(y2-y1)/(x2-x1)

m=(-5-(-2))/(-2-(-1))

m=(-5+2)/(-2+1)

m=(-3)/(-1)

m=3/1

m=3

y=mx+b

-2=3(-1)+b

-2=-3+b

b=1

y=3x+1

Certain polynomials with integer coefficients fall into the category of substantially prime polynomials in q[x] if and only if the ideal they create in z[x] contains a (nonzero) integer.

A polynomial is an expression in mathematics that consists of indeterminates (also known as variables and coefficients) that exclusively uses the operations of addition, subtraction, multiplication, and non-negative integer exponentiation of variables. x2 4x + 7 is an illustration of a polynomial of one uncertain x.

In both mathematics and science, polynomials are widely used. For instance, they are used to define polynomial functions, which can be found in a variety of contexts, from basic chemistry and physics to economics and social science, and they are used in calculus and numerical analysis to approximate other functions. Polynomial equations are used to encode a wide range of problems, from simple word problems to complex scientific problems.

Calculations:

Let d=degP.

Then the Q-vector space V=Q[X]/(P) is d-dimensional.

The residue classes modulo (P) of X2,X3,X5,… are linearly dependent over Q, so there exist a2,a3,a5,…∈Z not all zero such that a2X2+a3X3+a5X5+⋯∈(P).

This shows that there is Q∈Z[X], Q≠0 such that PQ=a2X2+a3X3+a5X5+⋯.

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The length of a side of cube is 4.56 Inches whose surface area is 125 square inches .

It is given that surface area of a cube is 125 square inches

Putting area = 125 in equation (1) , we get

[tex]125=6a^2\\a^2=20.33\\a=4.56 \ in[/tex]

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The number of gasolines is 1,800,000 miles driven.

­Gas is known as an aliphatic hydrocarbon. All in all, gas comprised of particles made out of nothing, yet hydrogen and carbon organized in chains. Fuel particles have from seven to 11 carbons in each chain. Gas or petroleum is a straightforward, oil determined combustible fluid that is utilized principally as a fuel in most flash touched off gas powered motors. Fuel is as of now thought to be frozen in the event that it transforms into a thick slop or wax. To absolutely keep away from frozen gas inside the vehicle, center around forestalling the fuel line from freezing during winter. Fuel fumes are heavier than air, so they choose the ground and travel like a fluid. Along these lines, they frequently track down their direction into channels, storm cellars, and sewer lines.

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the minimum possible number of rows of zeros in any row echelon form is 2

If a matrix in linear algebra has the structure that comes from a Gaussian elimination, it is said to be in echelon form. The bottom row has solely zeros, as do all other rows. A nonzero row's pivot, also known as the leading coefficient, is always located strictly to the right of the leading coefficient of the row above it.

The row echelon form of 5 × 3 matrix is given by -

                                        [tex]\left[\begin{array}{ccc}1&a&b\\0&1&d\\0&0&1\\0&0&0\\0&0&0\end{array}\right][/tex]

As we can see, the number of rows containing zeros are 2.

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Answer: It is m<BAE or measure of angle BAE

Step-by-step explanation:

1. Based by the m<CAE, 135 - 45 equals to 90, so that is not an obtuse angle, m<BAD is the same thing, so those 2 aren't it

2. m<CAD is 65, which is way too low for an obtuse angle, and m<DAE is way too small as well since it's angle is 25, making m<BAE a correct answer

Answer:

Step-by-step explanation:

C

Rewriting 15 1/6 as a decimal, rounded to the nearest thousandths, is: 1,516.667.

To rewrite the percentage, 15 1/6% as a decimal do the following as shown below:

Convert 15 1/6 from mixed number to an improper fraction:

91/6

Multiply 91/6 by 100:

91/6 × 100

= 9,100/6

Divide

9,100/6 = 1,516.667

Thus, rewriting 15 1/6 as a decimal, rounded to the nearest thousandths, is: 1,516.667.

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Nepali rupees that the person requires to exchange $4500 will be equal to NRs. 555,022.8.

We know that:

$ 1 = NRs. 120.92

We are also given that a person needs $ 4500 to visit foreign countries.

Also, for the conversion, bank charges commission as 2 %

Now, $ 4500 in NRs. will be calculated by multiplying 120.92 with $ 4500.

$ 4500 = NRs. 120.92 × 4500

$ 4500 = NRs. 544,140

Now the commission charged by the bank will be:

2 % of 544,140

Commission = 2 / 100 × 544,140

Commission = NRs. 10,882.8

So, the amount the person will require to get $ 4500 will be = NRs. 544,140 + 10,882.8

= NRs. 555,022.8

Therefore, Nepali rupees that the person requires to exchange $4500 will be equal to NRs. 555,022.8.

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When the sum of the squared deviation scores is SS=20 for a population n=5 scores, then the variance for this population is 4

Given,

The sum of the squared deviation scores SS= 20

Population of n= 5

Then the variance = SS/n

Substitute the values in the equation

The variance = [tex]\frac{20}{5}[/tex]

=4

Hence, when the sum of the squared deviation scores is SS=20 for a population n=5 scores, then the variance for this population is 4

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Answer:

85

Step-by-step explanation:

To find the mean, you have to add all the scores up and divide it by how many scores there are. In this case, there are seven scores, so we first add them up.

70+75+80+85+90+95+100=595

Now, we divide 595 by 7.

595/7=85

Hope this helps!

Have a wonderful day! :D

Answer: It is 5.3 based by rounding by it's tenth

Step-by-step explanation:

1. Add it all, in this case (3*2) + (7*2) + (8*2) + 1 which equals to 6 + 14 + 16 + 1

2. This then becomes 20 +17, which is 37, which we then divide by 7 becomes 5.285, or 5.3

Answer: -1

Step-by-step explanation:

Multiply -3 to (1+6r)

-3 - 18r = 14 - r

Then, group like terms and change the signs

-18r + r = 14 + 3

Add

-17r = 17

Divide 17 by 17 to solve for r

r = 17/-17

r = -1

Suni needs to deposit $12,304.45 semiannually to have $100,000 to repay the loan at 0.9% interest.

Periodic payments are equal payments made periodically to settle a mortgage loan.

The periodic payment for a loan can be computed using an online finance calculator.

N (# of periods) = 8 times (4 years x 2)

I/Y (Interest per year) = 0.9%

PV (Present Value) = $0

FV (Future Value) = $100,000

Results:

PMT = $12,304.45

Sum of all periodic payments = $98,435.60 ($12,304.45 x 8)

Total Interest $-1,564.40

Thus, the periodic deposit that Suni needs to make semiannually to have $100,000 to repay the loan at 0.9% interest is  $12,304.45.

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The expression uses the greatest common factor and the distributive property to rewrite the sum 75+45 is 15(5+3)

The greatest common factor is the greatest factor that divides both numbers.

The distributive Property States that when a factor is multiplied by the sum/addition of two terms, it is essential to multiply each of the two numbers by the factor, and finally perform the addition operation

Given,

75=3×5×5

45=3×3×5

The greatest common factor = 3×5=15

Then,

(75+45)=15(5+3)

Hence, the expression uses the greatest common factor and the distributive property to rewrite the sum 75+45 is 15(5+3)

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Answer:

write an expression to repersent the number of seconds since that hare began the race in terms of the number of seconds x since the tortise started the race

Step-by-step explanation:

Answer:

Step-by-step explanation:

If the snacks are to be identical without any food left over only one snack bags can  be made by Angela

The number of granola bars = 28

The number of pieces of dried fruit = 45

If the snack bags should be identical without any food left over, then we need to find out  the greatest number of snack bags, we should find out the Greatest common factor(GCF) or highest common factor(HCF) between 28  granola bars and 45 packages of string cheese

Since , factors of 28 = 1, 2, 4,7,14,28

Factors of 45 = 1, 3,5,9,15,45

Common factors of 28 and 45 = 1

Greatest Common factors of 28 and 45 = 1

Hence, the greatest common factor of 28 and 45 is 1 as only 1 is the common factor in the factors of 28 and the factors of 45.

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Answer:

- 1 and 74

Step-by-step explanation:

a

substitute d = - 1 into the expression

4d + 3

= 4(- 1) + 3

= - 4 + 3

= - 1

b

substitute x = 7 and y = 5 into the expression

x² + y²

= 7² + 5²

= 49 + 25

= 74

Final answer:

The statement that the median net worth of families headed by a person thirty-five to forty years old was 30 percent is a true statement.

In statistics, the median is the value that, when placed in order, falls in the middle of the supplied collection of data. Either ascending or descending order can be used to organize the data or observations. The median of 2,3,4, for instance, is 3. The median is a type of average used to determine the middle value in mathematics. The median is the value that falls in the middle when a group of values are arranged from smallest to greatest. The value that appears the most frequently in the set is the mode. In cases where the distribution is skewed or contains outliers, the median is the most illuminating indicator of central tendency.

Explanation:

The net-worth of families have a drastic change when compared to previous years as the economy has developed and while comparing the net-worth of income between years, the median method is useful in all ways and so the median net worth of families headed by a person thirty-five to forty years old was 30 percent less in 2010 than it was for their counterparts in 1983 is proved to be true.

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Hey there!

b(9 - c) / a^2

= 6(9 - 8) / 4^2

= 6(1) / 4^2

= 6/4 * 4

= 6/16

= 6 ÷ 2 / 16 ÷ 2

= 3/8

Therefore, your answer should be:

3/8

Good luck on your assignment & enjoy your day!

~Amphitrite1040:)

The expressions that have numeric value of less than 2 when x = 5 are:

A. x to the power of zero divided by 4.

C. (50 divided by x to the power of 2) to the power of zero

E. x to the power of zero divided by x to the power of 2

To find the numeric value of a function, we replace each instance of the variable by the desired value.

For item a, the expression is:

x^0/4 = 1/4 < 2.

For item b, the expression is:

x/(7^0) = x.

When x = 5, the expression has a numeric value of 5 > 2.

For item c, the expression is:

(50/x^2)^0 = 1 < 2.

For item d, the expression is:

2(10/x)^0 = 2 x 1 = 2 = 2.

For item e, the expression is:

x^0/x^2 = 1/x^2.

When x = 5, the expression has a numeric value of 1/25 < 2.

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The value of probability density function in the interval between 2 and 10 is 0.125.

A probability density function (PDF), also referred to as the density of a continuous random variable (CRV), is a mathematical function whose value at any particular sample (or point) in the sample space (the range of possible values that the RCV can take), can be interpreted as providing a relative likelihood that the RCRV's value would be close to that sample. Since there are an infinite number of possible values to begin with, the probability per unit length for a continuous random variable to take on any particular value is 0, but the value of the PDF at two different samples can be used to infer, in any given draw of the random variable, even though the absolute likelihood is zero.

Given the assembly time for a product is uniformly distributed between 2 to 10 minutes.

The Probability density function in the internal between 2&10

pdf=1/10-2      = 1/8pdf = 0.125

The probability density function in the interval between 2 and 10 is 0.125.

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Answer:

(

Step-by-step explanation:

(135+115+x)/3=125.

250+x=375

x=125.

thus third score must be 125

Answer: x = 20

Step-by-step explanation:

step 1: Multiply all terms by the same value to eliminate fraction denominators
3/x+4 = 2/x-4
(x-4)(x+4)*3/x+4 = (x-4)(x+4)*2/x-4
step 2: Cancel multiplied terms that are in the denominator
(x-4)(x+4) * 3/x+4 = (x-4)(x+4) *2/x-4
(x-4) *3 =(x+4) *2
step 3: Re-order terms so constants are on the left
(x-4) *3 = (x+4) *2
3(x-4) = 2(x+4)
Step 4: Distribute
step 5: Add 12 on both sides
3x - 12 = 2x + 8
    +12          +12
step 6: Subtract 2x both sides
3x = 2x + 20
-2x  -2x
step 7: Divide both side
1x/1 = 20/1
x = 20