Answer:
None have backbones
No cell walls
Multicellular
Includes radial or bilateral body symmetry.
Explanation:
Why is your body going through physical and chemical changes?
Answer:
Physical and chemical changes can occur almost everywhere, even in our bodies! Food must be broken down into a form that our cells can use. When we eat, our bodies physically break down food into small pieces. Our bodies also chemically break down those small pieces of food into tiny organic molecules.
Explanation:
All the radioactive elements are found in the last group of the Periodic Table.
True
False
Answer:
False
Explanation:
Throwing a snowball during snowball fight is most like an example of
what is the volume of the rock? if the water rose from 50L to 70mL
What is molarity measured the concentration of
Fungus is an example of a/an-
A:tissue
B:cell type
C:organ
D:organism
Answer:
D.organism
Explanation:
A fungus from the kingdom fungi is an organism
Answer:
D. organism
......................
What is the molecular formula for a compound with a molar mass of 42.08g/mol and an empirical formula of ch2
Answer:
[tex]C_3H_6[/tex]
Explanation:
Hello!
In this case, since the empirical formula is the smallest representation of the molecular formula, it is known that the times in which the empirical formula is into the molecular formula is a whole number and is computed by dividing the molar mass of the molecular formula by that of the empirical formula as shown below:
[tex]\frac{42.08g/mol}{12.01+1.01x2}= \frac{42.08g/mol}{14.03g/mol}=3[/tex]
Thus, the molecular formula times the empirical formula by 3 to obtain:
[tex]C_3H_6[/tex]
Regards!
what is the empirical formula of A compound is found to contain 39.12 % carbon, 8.772 % hydrogen, and 52.11 % oxygen by mass.
Answer:
C₃H₈O₃
Explanation:
Let's assume we have 100 g of said compound. Then we would have:
39.12 g of C8.772 g of H52.11 g of ONow we convert those masses into moles, using their respective atomic weights:
C ⇒ 39.12 g ÷ 12 g/mol = 3.26 mol CH ⇒ 8.722 g ÷ 1 g/mol = 8.722 mol HO ⇒ 52.11 g ÷ 16 g/mol = 3.26 mol OThen we divide those moles by the smallest number among them:
C ⇒ 3.26 mol C / 3.26 = 1H ⇒ 8.722 mol H / 3.26 = 2.68O ⇒ 3.26 mol O / 3.26 = 1Finally we multiply those numbers by 3, so as to convert the 2.68 of H into an integer:
C ⇒ 1 * 3 = 3H ⇒ 2.68 * 3 = 8O ⇒ 1 * 3 = 3Thus the empirical formula is C₃H₈O₃
what element is in group 13, period 4
Answer:
Gallium
Explanation:
Answer:
Gallium
Explanation:
Which of the following would be most likely to experience strong intermolecular forces?
A. Molecules that contain no electrically charged regions.
B. Molecules that contain atoms of oxygen.
C. Molecules that are composed of solely ions.
D. Molecules that have both negatively and positively charged parts.
Answer:
The correct answer is D
Explanation:
Just took quiz
Solid mercury (II) oxide produces liquid mercury and oxygen gas
Mercury(II) oxide, a red solid, decomposes when heated to produce mercury and oxygen gas. Mercury(II) oxide is a red solid. When it is heated, it decomposes into mercury metal and oxygen gas. A reaction is also considered to be a decomposition reaction even when one or more of the products are still compounds.
what is fractional distillation what is fractional distillation explain it with the help of an activity
Answer:
Fractional distillation is a method for separating liquids with different boiling points. For example, liquid ethanol can be separated from a mixture of ethanol and water by fractional distillation. ... The boiling point of ethanol is 78°C and the boiling point of water is 100°C.
Write down the possible types of atomic
Orbitals of n=4
Answer:
2
Explanation:
because first shell ( k shell ) needs only 2 electron to complete its octet .
hope it helps
THE WEATHER BALLOON DATA WE STUDIED WAS MEASURED AND RECORDED AT MIDNIGHT. THE TEMPERATURE OF THE AIR AT Earth's SURFACE IS DIFFERENT DURING DIFFERENT TIME OF THE DAY. WHAT OTHER TIMES OF THE DAY COULD WE MEASURE THE SURFACE TEMPERATURES OUTSIDE THE SCHOOL BUILDING? WHY? Write your thought on a sticky note and add it to our board. (Please initial your note.)
Answer night
Explanation:
because day is to hot
A 2.26 M solution of KOH is prepared. Calculate the moles and mass of solute present in a 15.2-mL sample of this solution. The molar mass of KOH is 56.11 g/mol.
Answer:
0.0344 moles and 1.93g.
Explanation:
Molarity is defined as the ratio between moles of a solute (In this case, KOH), and the volume. With molarity and volume we can solve the moles of solute. With moles of solute we can find mass of the solute as follows:
Moles KOH:
15.2mL = 0.0152L * (2.26mol / L) = 0.0344moles
Mass KOH:
0.0344 moles * (56.11g/mol) = 1.93g of KOH
How many moles are 5.55 x 104 atoms of Mg?
Answer:
23 atoms. I hope this helped u
Explanation:
How would a long period without sunlight affect the food web? PLEZZ HELP MEH IF YOU WANT BRAINEIST AND LIKE COMMENTED
It would cause consumers to consume more food.
It would have no effect on the food web.
It would stop decomposers from breaking down matter.
It would stop producers from producing food.
Answer:
im pretty sure its the last one
Explanation:
if plants dont have sun light they will die because the sunlight gives them the nutrients to survive
Which is the weakest type of intramolecular force/bond?
a. Polar covalent b. Ionic c. Metallic d. Nonpolar covalent
Answer:
Non polar covlant
Explanation:
How do sound waves travel? PLEASE HELP IF YOU WANT BRAINLEIST AND ME TO LIKE URE COMMENT!!
A. Sound causes the air near it to vibrate inwards.
B. waves radiate outward from a central point.
C. Sound moves randomly in different directions.
D. Sound transforms waves into different frequencies.
The answer is A. The vibration caused by the waves through the air eventually weaken, which is why sound diminishes easily over distance.
help please thank you
And electro chemical cell has the following standard cell notation:
Mg(s) | Mg2+ (aq) || Ag+(aq)| Ag(s)
Write a balanced redox reaction for the cells using the oxidation and reduction half reactions. (be sure to equalize charge by multiplying the correct number before adding and simplifying)
2Ag⁺(aq) + Mg(s)→ 2Ag(s) + Mg²⁺ (aq)
Further explanationGiven
Standard cell notation:
Mg(s) | Mg2+ (aq) || Ag+(aq)| Ag(s)
Required
a balanced redox reaction
Solution
At the cathode the reduction reaction occurs, the anode oxidation reaction occurs
In reaction:
Ag⁺ + Mg → Ag + Mg²⁺
half-reactions
at the cathode (reduction reaction)Ag⁺ (aq) + e⁻ ---> Ag (s) x2
2Ag⁺ (aq) + 2e⁻ ---> 2Ag (s)
at the anode (oxidation reaction)Mg (s) → Mg²⁺ (aq) + 2e−
a balanced cell reaction
2Ag⁺(aq) + Mg(s)→ 2Ag(s) + Mg²⁺ (aq)
Answer:2Ag⁺(aq) + Mg(s)→ 2Ag(s) + Mg²⁺ (aq)
Explanation:
just took test
What carpet Burns in a deficiency of O2 a mixture of CO and CO2 forms.Carbon Burns in excess O2 to form only CO2 and CO Burns in excess O2 to form only CO2. Calculate ΔH for C(graphite +1/2O2) →CO(g).
Answer:
Explanation:
From the combustion of carbon, the reactions occurring in limited oxygen conditions are:
[tex]C(graphite) + \dfrac{1}{2}O_{2(g)} \to CO_{(g)}[/tex]
[tex]C(graphite) + O_{2(g)} \to CO_{2(g)}[/tex]
If it occurs in excess, then any leftover CO changes to CO2. i.e.
[tex]C(graphite) + O_{2(g)} \to CO_{2(g)}[/tex] ---- (1)
[tex]CO_{(g)} + \dfrac{1}{2}O_{(g)} \to CO_{2(g)}[/tex] ----- (2)
From (1), the enthalpy change is:
[tex]\Delta H_{rxn1} = \Delta H^0_{fCO_2(g)} - ( \Delta H^0_{f C(graphite)}+ \Delta H^0_{fCO_2(g)}[/tex]
[tex]\Delta H_{rxn1} =-393.5 \ kJ/mol -(0+0)[/tex]
[tex]\Delta H_{rxn1} =-393.5 \ kJ/mol[/tex]
From (2), the enthalpy change is:
[tex]\Delta_{rxn2} = \Delta H^0_{fCO_2(g)} - ( \Delta H^0_{fCO(g)} + \dfrac{1}{2} \Delta H^0_{fO_2(g)})[/tex]
[tex]\Delta_{rxn2} = -393.5 \ kJ/mol -(-110.5 + \dfrac{1}{2}(0))[/tex]
[tex]\Delta_{rxn2} = -283.0 \ kJ/mol[/tex]
Subtracting (2) from (1), we get:
[tex]C(graphite) + O_{2(g)} \to CO_{2(g)} \ \ \ \Delta H_{rxn} = -393.5 \ kJ/mol}[/tex]
[tex]CO_{(g)} + \dfrac{1}{2} O_2(g) \to CO_{2(g)}} \ \ \ \Delta H _{rxn2} = -283.0 \ kJ/mol[/tex]
[tex]C(graphite) + O_{2(g)} \to CO (g) + \dfrac{1}{2}O_{2(g)} \ \ \ \Delta H_{rxn} = -110.5 \ kJ/mol[/tex]
[tex]C(graphite) + \dfrac{1}{2} O_{2(g)} \to CO (g) \ \ \ \Delta H_{rxn} = -110.5 \ kJ/mol[/tex]
The enthalpy change ΔH of the reaction = -110.5 kJ/mol
1pt Copper chloride and aluminum react to produce
aluminum chloride and copper. Which of the
following is the correctly balanced chemical
equation for this reaction?
O A. CuCl, + Al -> AICI, + u
O B. 3CuCl, + Al -> AlCl, + 2Cu
OC. 3CUCI, + 2Al -> 2AICI, + 3Cu
OD. CuCl, + 3Al -> AICI, + 2Cu
Answer:
None of the above
but it must be:
for Copper(I)chloride
3CuCl + Al ==> AlCl3 + 3Cu
for Copper (II) chloride
3CuCl2 + 2Al ==> 2AlCl3 + 3Cu
how are Ionic and Covalent Bonds are formed with examples ?
Answer:Comparison of Ionic and Covalent Bonds
In an ionic bond, the atoms are bound together by the electrostatic forces in the attraction between ions of opposite charge. ... For example, sodium (Na), a metal, and chloride (Cl), a nonmetal, form an ionic bond to make NaCl. In a covalent bond, the atoms bond by sharing electrons.
pls add Brainliest
The number of electrons in 1.6 gram CH, is:
Answer:
6.022 x 10²³ electrons
Explanation:
if 3.26 g is dissolved in enough water to make exactly 323 ml of solution, what is the molar cocentration of nitrate ion g
A chemist prepares a solution of barium acetate BaCH3CO22 by weighing out 52.9g of barium acetate into a 100.mL volumetric flask and filling the flask to the mark with water. Calculate the concentration in /gL of the chemist's barium acetate solution. Round your answer to 3 significant digits.
Answer:
529g/L
Explanation:
The concentration in chemistry is defined as the amount of solute in a determined amount of solution. The concentration in g/L means the amount of grams of solute (In this case, barium acetate), per liter of solution.
To solve this problem we need to find grams of solute (52.9g, already given) and the volume in liters (Converting 100mL to liters):
Volume:
100mL * (1L / 1000mL) = 0.100L
And concentration in g/L is:
52.9g / 0.100L =
529g/L9. Which of these is not a mixture? *
Solution
Alloy
Amalgam
They are all mixtures.
Answer:
They are all mixture
Explanation:
last option
A 52 gram sample of an unknown metal requires 714 Joules of energy to heat it from
30.5◦C to 82◦C. What is the specific heat of
this metal?
Answer in units of J/g ·
◦ C.
Answer: Approximately [tex]0.267 \frac{\text{J}}{\text{g}^{\circ}\text{C}}[/tex]
===================================================
Work Shown:
We have the following variables
Q = 714 joules = heat requiredm = 52 grams = massc = specific heat = unknown[tex]\Delta t[/tex] = 82-30.5 = 51.5 = change in temperaturenote: the symbol [tex]\Delta[/tex] is the uppercase Greek letter delta. It represents the difference or change in a value.
Apply those values into the formula below. Solve for c.
[tex]Q = m*c*\Delta t\\\\714 = 52*c*51.5\\\\714 = 52*51.5*c\\\\714 = 2678*c\\\\2678*c = 714\\\\c = \frac{714}{2678}\\\\c \approx 0.26661687826737\\\\c \approx 0.267\\\\[/tex]
The specific heat of the unknown metal is roughly [tex]0.267 \frac{\text{J}}{\text{g}^{\circ}\text{C}}[/tex]
How can you use density to separate mixtures like sand and small plastic pellets?
Answer:
Slide a magnet through the mixture. When you take the magnet off, the iron filings are going to be attracted to the magnet and the sand will stay in the bowl
Explanation:
Answer:
Density can be used to separate the substances that make up a mixture, because each substance in a mixture has its own density. For example, if a mixture of sand and oil is placed in water, the sand will sink to the bottom of the container. The sand is more dense than the water.
Explanation:
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