Question 16 of 25According to the Gibbs free energy equation, AG = AH-TAS, when is areaction always spontaneous?A. When AH and AS are both positiveB. When AH is negative and AS is positiveC. When AH is positive and AS is negativeD. When AH and AS are both negativeSUBMIT
Answer
B. When ΔH is negative and ΔS is positive
Explanation
The spontaneity of a reaction can be determined by the sign of the Gibbs free energy change. For a spontaneous reaction, the change in Gibbs free energy should be negative, that is:
[tex]\Delta G=\Delta H-T\Delta S[/tex]The spontaneity of a process can depend on the temperature. Since the temperature value here corresponds to the absolute temperature, this implies that T > 0 for any T. Therefore, to have a negative difference for any temperature value, the change in enthalpy (ΔH), should be negative and the change in entropy (ΔS) should be positive so that we always subtract a positive number from a negative number. This corresponds to a negative value in ΔG.
Hence, the
How many grams of solute would you use to prepare the following solutions?241.0 mL of 1.11 M NaOHExpress your answer with the appropriate units.
10.7 grams
Explanations:The formula for calculating the molarity of a solution is given as:
[tex]\begin{gathered} molarity=\frac{moles}{volume} \\ moles=molarity\times volume \end{gathered}[/tex]Given the following parameters
molarity of NaOH = 1.11M
volume of solution = 241.0mL = 0.241L
Find the moles of NaOH
[tex]\begin{gathered} moles\text{ of Na}OH=\frac{1.11mol}{L}\times0.241L \\ moles\text{ of Na}OH=0.2675moles \end{gathered}[/tex]Determine the mass of solute (NaOH)
[tex]\begin{gathered} Mass\text{ of NaOH}=mole\times molar\text{ mass} \\ Mass\text{ of NaOH}=0.2675\times40 \\ Mass\text{ of NaOH}=10.7grams \end{gathered}[/tex]Hence the grams of solute that would be used to prepare the solution is 10.7grams
How many milliliters of a 2.59 M H2SO4 solution are needed to neutralize 47.50 mL of a 0.827 M KOH solution?
Given Data:
Concentration of acid, H2SO4 = 2.59 M
For, H2SO4, n-factor = 2, i.e., the number of [tex]H^{+}[/tex] ions on dissociation
Thus, the concentration in normality, N1 = 2.59 x 2 = 5.18 N
Concentration of base, KOH = 0.827 M
For, KOH, n-factor = 1, i.e., the number of [tex]OH^{-}[/tex] ions on dissociation
Thus, the concentration in normality, N2 = 0.827 x 1 = 0.827 N
Volume of base, V2 = 47.50 mL
Using the formula, N1 x V1 = N2 x V2, where, V1 = volume of acid
Thus, volume of acid required to neutralize, V1 = [tex]\frac{N_{2}X V_{2} }{N_{1} }[/tex] = [tex]\frac{0.827 X 47.50}{5.18}[/tex]
= 7.58 mL.
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Which quantum state (n,ℓ,mℓ) is NOT possible? and why
2,0,0
3,1,-1
3,0,1
3,2,2
16,14,15
The quantum numbers that are not possible are 16,14,15.
What are quantum numbers?The quantum numbers are used to address the position of the electron in an atom. They are the set of numbers that show the most probable position of the electron in an atom. There are four sets of quantum numbers that describe the position of an electron and they are;
1) Principal quantum number
2) Orbital quantum number
3) Magnetic quantum number
4) Spin quantum number.
The set of quantum numbers 16,14,15 is not possible because ml must have values of -l to +l as we know.
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A new alloy is designed for use in a car radiator. If the 17.6 kg radiator required 8.69 × 105 J of heat to warm from 22.1°C to 155.8°C, what is the specific heat of the new alloy?
A new alloy is designed for use in a car radiator. If the 17.6 kg radiator required 8.69 × 105 J of heat to warm from 22.1°C to 155.8°C, the specific heat of the new alloy is 369.2 J / kg °C.
Specific heat formula is given as :
Q = mcΔT
given that :
mass , m = 17.6 kg
Q = 8.69 × 10⁵ J
ΔT , change in temperature = 22.1 °C - 155.8 °C = 133.7 °C
c = specific heat = ?
Substituting the values in the formula we get:
Q = mcΔT
c = Q / mΔT
c = 8.69 × 10⁵ J / 17.6 kg × 133.7 °C
c = 8.69 × 10⁵ J / 2353.12 kg °C
c = 369.2 J / kg °C
Thus, A new alloy is designed for use in a car radiator. If the 17.6 kg radiator required 8.69 × 10⁵ J of heat to warm from 22.1°C to 155.8°C, the specific heat of the new alloy is 369.2 J / kg °C.
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Cobalt(II) chloride reacts with fluorine in a single replacement reaction to produce cobalt(II) fluoride and chlorine gas. How many grams of fluorine are required to produce 124.13 g of cobalt(II)fluoride?
The balanced equation of the reaction is:
CoCl2 + F2 → CoF2 + Cl2
Now, we will follow the next steps to solve the question.
1. We find the moles present in 124.13 g of cobalt(II)fluoride (CoF2) using the molar molar mass of CoF2. The molar mass of CoF2 is: 96.93g/mol
2. By stoichiometry we find the moles of fluorine (F2) needed. Since the ratio CoF2 to F2 is 1, the moles will be the same as those produced from cobalt(II)fluoride.
3. We find the grams of fluorine by multiplying the moles by the molar mass of fluorine. The molar mass of fluorine is 38.00 g/mol
Let's proceed with the calculations:
1. Moles of CoF2
[tex]\begin{gathered} molCoF_2=givengCoF_2\times\frac{1molCoF_2}{MolarMass,gCoF_2} \\ molCoF_2=124.13gCoF_2\times\frac{1molCoF_2}{96.93gCoF_2}=1.28molCoF_2 \end{gathered}[/tex]2. Moles of F2
[tex]molF_2=1.28molCoF_2\times\frac{1molF_2}{1molCoF_2}=1.28molF_2[/tex]3. Grams of F2
[tex]\begin{gathered} gF_2=givenmolF_2\times\frac{MolarMass,gF_2}{1molF_2} \\ gF_2=1.28molF_2\times\frac{38.00gF_2}{1molF_2}=48.66gF_2 \end{gathered}[/tex]Answer: To produce 124.13 grams of cobalt(II)fluoride are required 48.66grams of fluorine
3) Water is a polar solvent; gasoline is a non-polar solvent. Which compounds are
more likely to dissolve in water? Check all that apply.
CCI4
NaCI
CH4
Oil
According to given statement NaCI compounds are more likely to dissolve in water.
What is polar solvent with example?Polar solvents, which do have "positive" and "negative" charges at different points throughout their structures, can dissolve other polar compounds. Acetone, methanol, dimethylformamide (DMF), dimethylsulfoxide (DMSO), isopropanol, and ethanol are some other polar solvents. A few of these solvents is water.
Why water is a polar solvent?Due to the uneven distribution of its electron density, water is a polar molecule. This demonstrates that water is indeed a polar molecule because hydrogen and oxygen have different electronegativities. The fact that water can dissolve more chemicals compared to any other liquid makes it known as the "universal solvent."
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10. When a metal atom combines with a nonmetal
atom, the nonmetal atom will
A. lose electrons and decrease in size
B. lose electrons and increase in size
C. gain electrons and decrease in size
D. gain electrons and increase in size
When a metal atom combines with a nonmetal atom, the nonmetal atom will gain electrons and decrease in size
What happen when metal react with non metal ?In a reaction between metals and non-metals, electrons are moved from the metal atoms to the non-metal atoms, resulting in the formation of ions. An ionic compound is the name given to the resulting substance.
Ions are created when metals and non-metals interact because the metal atoms' electrons are transferred to the non-metal atoms.The end result of this procedure is an ionic compound. Metal atoms provide their electrons to non-metal atoms. Metal atoms change into positive ions, whereas non-metal atoms change into negative ions.Learn more about Metals and non metal here:
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What other things can you think of that might be preserved?
Answer:
Bones, teeth, shells, and other hard body parts can be fairly easily preserved as fossils. However, they might become broken, worn, or even dissolved before they are buried by sediment. The soft bodies of organisms, on the other hand, are relatively hard to preserve.
The molecular formula of Allicin, The compound responsible for the characteristics smell of garlic, is C6H 10 OS2. A) what is the molar mass of a Allicin?B) how many moles of allicin are present in 4.20 mg of the substance?C) how many molecules of Allicin are in 4.20 mg of the substance?D) how many C atoms are present in 4.20 mg of allicin?
1) Molar mass of Allicin.
1.1- Write the formula.
[tex]C_6H_{10}OS_2[/tex]1.2- Look for the molar mass of each element in the formula.
C: 12.011 g/mol
H: 1.008 g/mol
O: 15.999 g/mol
S: 32.06 g/mol
1.3- Count how many atoms are there in the formula.
C: 6
H: 10
O: 1
S: 2
1.4- Set the equation.
[tex]TheMolarMass=(6*C)+(10*H)+(1*O)+(2*S)[/tex]Plug in the known values.
[tex]TheMolarMass=(6*12.011\text{ }g/mol)+(10*1.008\text{ }g/mol)+(1*15.999\text{ }g/mol)+(2*32.06\text{ }g/mol)[/tex][tex]MM=72.066\text{ }g/mol+10.08\text{ }g/mol+15.999\text{ }g/mol+64.12\text{ }g/mol[/tex][tex]MM=162.265\text{ }g/mol[/tex]The molar mass (MM) of Allicin (C6H10OS2) is 162.265 g/mol.
2) Moles of Allicin in the sample.
Allicin sample: 4.20 mg
The molar mass of Allicin (C6H10OS2) is 162.265 g/mol.
2.1- Convert mg to g.
1g = 1000 mg
[tex]g=4.20\text{ }mg*\frac{1\text{ }g}{1000\text{ }mg}=0.00420\text{ }g[/tex]2.2- Convert grams to moles.
The molar mass of Allicin (C6H10OS2) is 162.265 g/mol.
Allicin sample: 0.00420 g
[tex]mol\text{ }C_6H_{10}OS_2=0.00420\text{ }g\text{ }C_6H_{10}OS_2*\frac{1\text{ }mol\text{ }C_6H_{10}OS_2}{162.265\text{ }g\text{ }C_6H_{10}OS_2}=0.00002588\text{ }mol\text{ }C_6H_{10}OS_2[/tex]There are 0.00002588 moles of Allicin (C6H10OS2) in 4.20 mg of substance.
The result can also be expressed as 2.588*10^(-5) mol.
3) Molecules of Allicin in the sample.
The Avogadro's number is 6.022*10^(23).
1 mol C6H10OS2 = 6.022*10^(23) molecules C6H10OS2
Allicin sample: 0.00002588 mol.
[tex]molecules\text{ }of\text{ }C_6H_{10}OS_2=0.00002588\text{ }mol\text{ }C_6H_{10}OS_2*\frac{6.022*10^{23}\text{ }molecules}{1\text{ }mol\text{ }C_6H_{10}OS_2}=1.558*10^{19}\text{ }molecules\text{ }of\text{ }C_6H_{10}OS_2[/tex]There are 1.558*10^(19) molecules in the sample.
4) C atoms in the sample of Allicin.
The ratio of carbon in one molecule of Allicin is 6 C atoms: 1 molecule of Allicin.
Allicin sample: 1.558*10^(19) molecules C6H10OS2.
[tex]C\text{ }atoms=1.588*10^{19}\text{ }molecules*\frac{6\text{ }C\text{ }atoms}{1\text{ }molecule\text{ }C_6H_{10}OS_2}=9.35*10^{19}\text{ }C\text{ }atoms.[/tex]There are 9.35*10^(19) C atoms in the sample.
4 Fe + 3 O2 = 2 Fe2O3How many grams of oxygen (O2) do you needto produce 75 g Fe203?
Answer
mass of oxygen = 22.54 g
Explanation
Given:
4 Fe + 3 O2 = 2 Fe2O3
Mass of Fe203 = 75 g
Required: Mass of O2
We know:
Molar mass of Fe2O3 = 159,69 g/mol
Molar mass of O2 = 31.998 g/mol
Solution:
Step 1: Calculate the moles of Fe2O3
n = m/M where n is the moles, m is the mass and M is the molar mass
n = 75g/159,69 g/mol
n = 0.469 mol
Step 2: Use the stoichiometry to find the moles of O2
The molar ratio between Fe2O3 and O2 is 2:3
Therefore moles of O2 = 0.469 mol x (3/2) = 0.704 mol
Step 3: Find the mass of O2
m = n x M
m = 0.704 mol x 31.998 g/mol
m = 22.54 g
Volume of syringes reading read as 4cc when the weight (pressure) was 600g. Determine the pressure used (weight) when the volume is 2.5 cc?
Answer:
[tex]960\text{ g}[/tex]Explanation:
Here, we want to calculate the pressure used at the new volume
It is expected that at a higher pressure, the volume will decrease
Thus, the weight and the pressure are inversely proportional
Mathematically:
[tex]P_1V_1\text{ = P}_2V_2[/tex]The above is according to Boyle's law which states that volume and pressure are inversely proportional
where:
V1 is the initial volume which is 4 cc
P1 is the initial weight which is 600 g
V2 is the final volume which is 2.5 cc
P2 is the final pressure which is unknown
Substituting the values:
[tex]P_2\text{ = }\frac{600\times4}{2.5}\text{ = 960 g}[/tex]Leslie incorrectly balances an equation as 2C4H10 + 12O2 → 8CO2 + 10H2O.Which coefficient should she change?281012
Answer: 13 O2 instead of 12 O2
Explanation:
Which state of matter is being described below?It cannot be squashed easily, will not spread out & is high densityA. GasB. SolidC. LiquidD. Plasma
There are 3 main states of matter: gas, solid, and liquid.
The solid is characterized by its rigid structure, its high density (it means that's there's a lot of mass per unit of volume). Also, it doesn't take the container's shape as a liquid does.
Then, the description corresponds to the solid state (option B).
Suppose 2.68 g of barium acetate is dissolved in 300. mL of a 45.0 m Maqueous solution of ammonium sulfate.
Calculate the final molarity of acetate anion in the solution. You can assume the volume of the solution doesn't change when the barium
acetate is dissolved in it.
Round your answer to 3 significant digits.
Explanation
Final Molarity of acetate ion is 0.0394 M. The number of moles of solute per liter of solution is referred to as molarity.
What is Molarity?The amount of a substance in a given volume of solution is measured in molarity (M). Molarity is defined as the number of moles of a solute in one liter of solution. A solution's molarity is also known as its molar concentration.
Therefore,
We first assume that the reaction completes and that the volume of the reaction remains constant.
The balanced stoichiometric equation is as follows:
Ba(CH₃COO)₂ + (NH₄)₂SO₄ → BaSO₄ + 2NH₄(CH₃COO)
First, we must determine which reactant is in excess and which has been completely consumed by the reaction. To do so, we count the number of moles of each reactant at the beginning of the reaction.
For Ba(CH₃COO)₂
The number of moles = (Mass)/(Molar Mass)
Barium acetate mass = 2.68 g
Barium acetate molar mass = 255.43 g/mol
The number of moles = (2.68/255.43) = 0.0104 moles.
For (NH₄)₂SO₄,
Number of moles = (Concentration in mol/L) × (Volume in L)
Concentration of Ammonium surface in mol/L = 45 M
Volume in L = (300/1000) = 0.3 L
Number of moles = 45 × 0.3 = 13.5 moles
From the stoichiometric balance of the reaction,
1 mole of Ba(CH₃COO)₂ responds with 1 mole of (NH₄)₂SO₄
As a result, it is clear that Ba(CH₃COO)₂ is the limiting reagent; the chemical specie that is depleted during the reaction and determines the number of other reactants and products formed.
1 mole of Ba(CH₃COO)₂ provide 2 moles of NH₄(CH₃COO)
0.0591 moles of Ba(CH₃COO)₂ will give 2 × 0.0591 moles of NH₄(CH₃COO); 0.1182 moles of NH₄(CH₃COO).
The molarity of NH₄(CH₃COO) exist then provide as (number of moles) ÷ (Vol in L)
The number of moles = 0.1182 moles
L volume of the solution = 0.3 L
Molarity of NH₄(CH₃COO) = (0.01182/0.3)
= 0.0394 M
Note that 1 mole of NH₄(CH₃COO) contains 1 mole of acetate ion,
Hence, 0.0394 M of NH₄(CH₃COO) also contains 0.0394 M of acetate ion.
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The empirical formula for a compound that contains 6.34 grams carbon and 1.06 grams hydrogen is
Answer:
[tex]CH_2[/tex]Explanation:
Here, we want to get an empirical formula
We start by dividing each of the masses by the corresponding atomic masses
The atomic mass of carbon is 12 amu
The atomic mass of hydrogen is 1 amu
We start the division as follows:
[tex]\begin{gathered} C\text{ = }\frac{6.34}{12}\text{ = 0.5283333} \\ \\ H\text{ = }\frac{1.06}{1}\text{ = 1.06} \end{gathered}[/tex]Now, we divide the results by the smaller of the two:
[tex]\begin{gathered} C\text{ = }\frac{0.528333}{0.529333}\text{ = 1} \\ \\ H\text{ = }\frac{1.06}{0.528333}\text{ = 2} \end{gathered}[/tex]Thus, we have the empirical formula as:
[tex]CH_2[/tex]The polarity of the covalent bond between two given atoms is determined/estimated byGroup of answer choicesOctet RuleElectronegativity differencesNumber of bonds between the atomsSolubility
1) Covalent bond polarity.
To determine the polarity, we use a property called electronegativity. This is a tendency to attract shared electrons in a chemical bond. If the difference in electronegativity is greater than 1.7, the bond is polar. If the difference is less than 1.7, the bond is nonpolar.
3.0 x 10 ^23 atoms of calcium to moles
Answer:
[tex]0.5\text{ mole}[/tex]Explanation:
Here, we want to get the number of moles
Mathematically:
[tex]1\text{ mole has 6.02 }\times\text{ 10}^{23}\text{ atoms}[/tex]The number of moles in the question would be:
[tex]\frac{3.0\times10^{23}\text{ atoms}}{1}\times\frac{1\text{ mole}}{6.02\times10^{23}\text{ atoms}}\text{ = 0.5 mole}[/tex]A gas occupies a constant volume at 35.0 celsius and 97 kPa. What is the pressure of the gas when the temperature is increased to 75 celsius?
For this question we are going to use Gay-Lussac's Law, which is an experimental gas law that shows the relationship between temperature and pressure in a gas. The formula is:
P1/T1 = P2/T2
We have:
P1 = 97 kPa
T1 = 308 K, we need to use Kelvin
P2 = ?
T2 = 348 K
Now we add these values into the formula:
97/308 = P2/348
0.315 = P2/348
P2 = 109.6 kPa, this will be new pressure
C2H4 + 3O2 ——> 2CO2 + H2OWhat volume of oxygen at STP is needed to react with 5.75 mol of C2H4 (Show all work and data charts)
Explanation:
C₂H₄ + 3 O₂ ——> 2 CO₂ + H₂O
According to the coefficients of the equation 1 mol of C₂H₄ will react with 3 moles of O₂. Then, the molar ratio between C₂H₄ and O₂ is 1 to 3. We can use that relationship to find the number of moles of oxygen that are needed to react with 5.75 moles of C₂H₄.
1 mol of C₂H₄ = 3 moles of O₂
moles of O₂ = 5.75 moles of C₂H₄ * 3 moles of O₂/(1 mol of C₂H₄)
moles of O₂ = 17.25 moles
One mol of a gas at STP always occupies 22.4 L. We can use that relationship to find the volume of oxygen.
1 mol of O₂ = 22.4 L
volume = 17.25 moles of O₂ * 22.4 L/(1 mol of O₂)
volume = 386.4 L
Answer: 386.4 L at STP is needed to react.
Calculate the pH if [H+] = 2.79 x 10^-11 M
Answer:
10.6.
Explanation:
What is given?
[H⁺] = 2.79 x 10⁻¹¹ M.
Step-by-step solution:
Let's see the formula of pH:
[tex]pH=-\log_{10}[H^+]=-\log_{10}[H_3O^+].[/tex]Where [H⁺] is the proton concentration in M. So we have to replace the given data in the formula:
[tex]pH=-\log_{10}{}\lbrack2.79\cdot10^{-11}]=10.55\approx10.6.[/tex]The pH of a [H⁺] = 2.79 x 10⁻¹¹ M solution would be 10.6.
Which of the following describes a physical property?Corrosiveness of sodiumToxcity of cadmiumWater when heated forms steamFlammability of hydrogen
Physical properties are the ones that describe the behavior of the substances when exposed to different physical changes.
In this case, the one that describes a physical change is water when heated forms steams. In this case water changes its state of matter but it is still the same substance, there is not chemical change, just physical.
The correct answer is Water when heated forms steams.
Balance the following equation:ZnO(s)⟶ΔZn(l)+O2(g) Express your answer as a chemical equation. Identify all of the phases in your answer.
Answer:2ZnO(s)→2Zn(l)+O2(g)
Explanation:
How many groups are attached to a center atom with trigonal planar geometry? 3 groups 1 group 5 groups 4 groups
Answer:
The number of groups attached to a center atom with trigonal planar geometry is 3 groups.
1. How would an element be classified?a. homogeneous mixtureb. pure substancec. solutiond. heterogeneous mixture
Hello
To solve this question, we should understand that an element is is the base form in which a particule exit. However, it can either be in a molecule, atom or in a compound. Elements are pure substance which form up the molecule, atom or compounds. An element can said to be an identity of a substance. Elements are generally classified using the periodic table into metals, non-metals, metalliods.
In this question, the most possibe defination is that an element is a pure substance
A homogenous mixture is a mixture that is said to have one phase of substance throughout. I.e the comprising substance are all in a single phase.
A solution is the mixture of a solute that is completely dissolved in a solvent.
A heterogeneous mixture is a solution that the substance are not in a single phase.
The answer to this question is option B
At a pressure of 1.00atm the solubility of nitrogen in water is 23.5mg gas/100g water. Indicate whether each of the following changes would increase or decrease the solubility of nitrogen in water
Solubility of a substance changes as the pressure changes. If the pressure is high, solubility increases. When pressure is low, solubility decreases.
At 1 atm the solubility of Nitrogen in water is 23.5 mg gas/110g water.
The solution is submerged 40 m under water. Solubility increase.
The solution is carried to the top of a mountain. Solubility decrease.
The solution is placed in a chamber where the pressure is 0.50 atm. Solubility decrease.
The solution is brought into outer space. Solubility decrease.
The solution is canned at a pressure of 2.04 atm. Solubility increase.
4. Collaborate with a partner, make a brochure that highlights an example of a
technology that you have seen in which density is important.
The common use of density in ships and submarines is to predict whether or not a thing will float. Objects that have densities lower than those of water will sink if their densities are lower than water's.
What does density mean ?A product's density is a measure of how heavy it is relation to its size. If added to water, an object will float if its density is less than that of the water, while it will sink if its higher density. The density of a material is a distinguishing quality that is independent of the substance's volume.
Why is density important in chemistry?Because density is an intense property, it remains constant regardless of how much of a substance is present. Because it enables us to predict which compounds will float and which will sink in a liquid, density is a crucial notion.
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Calculate the percent by volume of 75 mL of concentrated juice if the juice is diluted with 200 mL of water.
The percent by volume is 27.27%
Is NH4OH soluble or insoluble in water
Answer:
Ammonium hydroxide. Ammonium hydroxide is an inorganic herbicide, fungicide and microbiocide.It is non-volatile and highly soluble in water.
Explanation:
According to the concept of solubility, ammonium hydroxide is insoluble in water.
What is solubility?Solubility is defined as the ability of a substance which is basically solute to form a solution with another substance. There is an extent to which a substance is soluble in a particular solvent. This is generally measured as the concentration of a solute present in a saturated solution.
The solubility mainly depends on the composition of solute and solvent ,its pH and presence of other dissolved substance. It is also dependent on temperature and pressure which is maintained.Concept of solubility is not valid for chemical reactions which are irreversible. The dependency of solubility on various factors is due to interactions between the particles, molecule or ions.
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A 0.016773-m^3 tank contains 1kg of refrigerant-134a at 110C. Determine the pressure of the refrigerant using (a) the ideal-gas equation, (b) the generalized compressibility chart, and (c) the refrigerant tables.
Answers:(a)1.861MPa,(b)1.583MPa,(c)1.6MPa
The pressure of the refrigerant using the ideal-gas equation is 1.861 MPa, the generalized compressibility chart is 1.583 MPa and the refrigerant tables is 1.6 MPa.
What is ideal gas equation?Ideal gas equation is defined as the state equation for a fictitious perfect gas. Although it has significant drawbacks, it is a decent approximation of the behavior of many gases under various conditions.
Ideal gas equation is expressed as
PV = nRT
By using Ideal gas equation
P x 0.016773 = 1 x 81.49 x 483
P = 1.861 MPa
By using generalized compressibility chart
For r134a
Temperature = 374.2 K
Pressure = 4.06 MPa
vR = V / R x Tc / Pc
= 0.016773 / 81.49 x ( 374.2 / 4.06 x 10⁶ )
= 2.2332
Tr = T/Tc = 383 / 374.2 = 1.024
Therefore from the chart Z = 0.85
So, P = Z mRT / V
P = 0.85 x 1 x 81.49 x 383 / 0.016773
= 1.582 MPa
By using refrigerant tables
T = 110 C and v = 0.0167763
So, P = 1.6 MPa
Thus, the pressure of the refrigerant using the ideal-gas equation is 1.861 MPa, the generalized compressibility chart is 1.583 MPa and the refrigerant tables is 1.6 MPa.
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