want 75 total points? for 75 total you could also answer this other optional thing if you want
either way would appreciate some help with this question and/or this other one
https://brainly.com/question/27237838

Answer:

Step-by-step explanation:

The usual English meanings of the words "reduction" and "enlargement" apply to geometrical figures.

Figure A'B'C'D' is smaller than figure ABCD, so represents a reduction.

__

Every coordinate of every image point is half as far from the origin in A'B'C'D' as in the original figure ABCD. For example, the x-coordinate of C' is 2, and the x-coordinae of C is 4. The dilation factor is the ratio of these values:

  k = Cx'/Cx = 2/4 = 1/2

The scale factor is 1/2.

Answer:

42 Pages

Step-by-step explanation:

7x5=35

7+35=42

Answer:

Cite evidence from the text to explain Her as role in Greek mythology

A vertical line going through any given point would pass through the x-coordinate.

In this case, the x-coordinate is 3. Therefore, the vertical line that would pass through the point (3, 5) is x = 3.

Hope this helps!

Answer:

  180 cm^2

Step-by-step explanation:

For similar figures the ratio of areas is the square of the ratio of linear dimensions.

We take "tripled in size" to mean that the linear dimensions of the larger rectangle are 3 times those of the smaller rectangle. That means the area of the larger rectangle will be 3² = 9 times the area of the smaller one.

  Area = (3²)(20 cm²) = 180 cm² . . . . area after tripled in size

Answer:

30%

Step-by-step explanation:

The sign means that x can be equal to or LESS than -3. The only ones are -3 and -5. 0.17+0.13=0.30

Answer:

a) 3

b) 1/3

Step-by-step explanation:

I've never used Brainly math before, but I can help you out with the work for these problems.

Part A

3(x + 1) - x = 15

3x + 3 - x = 15

4x + 3 = 15

4x = 12

x = 3

Part B

5(x + 2) - 2x = 11

5x + 10 - 2x = 11

3x + 10 = 11

3x = 1

x = 1/3

Hope this helps!

24/8 = 3

the 24 to 8 gear = 3:1 ratio which is greater than 2:1

Answer:

Depends on how many points the star has. For example, a 5 pointed star will have 5 lines of symmetry. Knowing this, you should be able to count using a diagram or drawing of the star

Answer:

53

Step-by-step explanation:

[tex]sum \: of \: angles = 180 \\ 180 = 74 + 2x \: where \: x \: is \: the \: measure \: of \: the \: other \: angles \\ 180 - 74 = 2x \\ 106 = 2x \\ x = \frac{106}{2} \\ x = 53[/tex]

Always welcome

Step-by-step explanation:

2. since there are 15 shirt

the probability of her wearing a blue shirt is 5/15

the probability of her wearing a blue shirt is 4/15

The equation that can be used to determine the number of bean bags in the instuctor's box is b = 17 x 4.

The number of bean bags in the instructor's box is 68.

Multplication is a mathematcial operation that can be used to determine the product of two or more numbers. The sign used to represent multiplication is ×.

To learn more about multiplication, please check: https://brainly.com/question/13814687

Step-by-step explanation:

[tex]see \: if \: 10 \: are \: left \: then \: we \: hve \: spent \\ 250 - 10 = 240 \: dollars \\ [/tex]

hence

[tex]six \: flasks \: cost \: 240 \: dollars \\ so \: if \: we \: divide \: 240 \: by \: 6 \: we \: get \: 40 \: \\ [/tex]

so one flask costs 40$

Answer:

Median

Step-by-step explanation:

I know that you can't do Range, since it's skewed right.

The mean can't be it since it's also not representative when it's skewed right.

I'd say Median, or IQR at first glance but if you look at a graph, the IQR might follow with the skewed and move over a bit.

That leaves Median.

The correct statistical measure which represents the spread of the data best is, Median.

Given that;

The data for the heights of players on a basketball team is skewed right.

Since, We know that;

For the data for the heights of players on a basketball team is skewed right,

We can use Median for the spread of the data best.

Hence, The correct statistical measure which represents the spread of the data best is, Median.

Learn more about the median visit:

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Answer:

<1 = 88° , <2 = 129°, <3 = 82°, <4 = 147°, <5 = 94°, <6 = 86°

Step-by-step explanation:

<1 + 92° = 180°

<1 = 88°

<2 + 51° = 180°

<2 = 129°

<3 + 98° = 180°

<3 = 82°

<4 + 33° = 180°

<4 = 147°

<1 + <2 + <3 + <4 + <5 = 540°

88° + 129° + 82° + 147 + <5 = 540°

<5 = 94°

<5 + <6 = 180°

94° + <6 =180°

<6 = 86°

Answer:

See below for answers and explanations

Step-by-step explanation:

Problem 1

Recall that the projection of a vector [tex]u[/tex] onto [tex]v[/tex] is [tex]\displaystyle proj_vu=\biggr(\frac{u\cdot v}{||v||^2}\biggr)v[/tex].

Identify the vectors:

[tex]u=\langle-10,-7\rangle[/tex]

[tex]v=\langle-8,4\rangle[/tex]

Compute the dot product:

[tex]u\cdot v=(-10*-8)+(-7*4)=80+(-28)=52[/tex]

Find the square of the magnitude of vector v:

[tex]||v||^2=\sqrt{(-8)^2+(4)^2}^2=64+16=80[/tex]

Find the projection of vector u onto v:

[tex]\displaystyle proj_vu=\biggr(\frac{u\cdot v}{||v||^2}\biggr)v\\\\proj_vu=\biggr(\frac{52}{80}\biggr)\langle-8,4\rangle\\\\proj_vu=\biggr\langle\frac{-416}{80} ,\frac{208}{80}\biggr\rangle\\\\proj_vu=\biggr\langle\frac{-26}{5} ,\frac{13}{5}\biggr\rangle\\\\proj_vu=\langle-5.2,2.6\rangle[/tex]

Thus, B is the correct answer

Problem 2

Treat the football and wind as vectors:

Football: [tex]u=\langle42\cos172^\circ,42\sin172^\circ\rangle[/tex]

Wind: [tex]v=\langle13\cos345^\circ,13\sin345^\circ\rangle[/tex]

Add the vectors: [tex]u+v=\langle42\cos172^\circ+13\cos345^\circ,42\sin172^\circ+13\sin345^\circ\rangle\approx\langle-29.034,2.481\rangle[/tex]

Find the magnitude of the resultant vector:

[tex]||u+v||=\sqrt{(-29.034)^2+(2.481)^2}\approx29.14[/tex]

Find the direction of the resultant vector:

[tex]\displaystyle \theta=tan^{-1}\biggr(\frac{2.841}{-29.034}\biggr)\approx -5^\circ[/tex]

Because our resultant vector is in Quadrant II, the true direction angle is 6° clockwise from the negative axis. This means that our true direction angle is [tex]180^\circ-5^\circ=175^\circ[/tex]

Thus, C is the correct answer

Problem 3

We identify the initial point to be [tex]R(-2,12)[/tex] and the terminal point to be [tex]S(-7,6)[/tex]. The vector in component form can be found by subtracting the initial point from the terminal point:

[tex]v=\langle-7-(-2),6-12\rangle=\langle-7+2,-6\rangle=\langle-5,-6\rangle[/tex]

Next, we find the magnitude of the vector:

[tex]||v||=\sqrt{(-5)^2+(-6)^2}=\sqrt{25+36}=\sqrt{61}\approx7.81[/tex]

And finally, we find the direction of the vector:

[tex]\displaystyle \theta=tan^{-1}\biggr(\frac{6}{5}\biggr)\approx50.194^\circ[/tex]

Keep in mind that since our vector is in Quadrant III, our direction angle also needs to be in Quadrant III, so the true direction angle is [tex]180^\circ+50.194^\circ=230.194^\circ[/tex].

Thus, A is the correct answer

Problem 4

Add the vectors:

[tex]v_1+v_2=\langle-60,3\rangle+\langle4,14\rangle=\langle-60+4,3+14\rangle=\langle-56,17\rangle[/tex]

Determine the magnitude of the vector:

[tex]||v_1+v_2||=\sqrt{(-56)^2+(17)^2}=\sqrt{3136+289}=\sqrt{3425}\approx58.524[/tex]

Find the direction of the vector:

[tex]\displaystyle\theta=tan^{-1}\biggr(\frac{17}{-56} \biggr)\approx-17^\circ[/tex]

Because our vector is in Quadrant II, then the direction angle we found is a reference angle, telling us the true direction angle is 17° clockwise from the negative x-axis, so the true direction angle is [tex]180^\circ-17^\circ=163^\circ[/tex]

Thus, A is the correct answer

Problem 5

A vector in trigonometric form is represented as [tex]w=||w||(\cos\theta i+\sin\theta i)[/tex] where [tex]||w||[/tex] is the magnitude of vector [tex]w[/tex] and [tex]\theta[/tex] is the direction of vector [tex]w[/tex].

Magnitude: [tex]||w||=\sqrt{(-16)^2+(-63)^2}=\sqrt{256+3969}=\sqrt{4225}=65[/tex]

Direction: [tex]\displaystyle \theta=tan^{-1}\biggr(\frac{-63}{-16}\biggr)\approx75.75^\circ[/tex]

As our vector is in Quadrant III, our true direction angle will be 75.75° counterclockwise from the negative x-axis, so our true direction angle will be [tex]180^\circ+75.75^\circ=255.75^\circ[/tex].

This means that our vector in trigonometric form is [tex]w=65(\cos255.75^\circ i+\sin255.75^\circ j)[/tex]

Thus, C is the correct answer

Problem 6

Write the vectors in trigonometric form:

[tex]u=\langle40\cos30^\circ,40\sin30^\circ\rangle\\v=\langle50\cos140^\circ,50\sin140^\circ\rangle[/tex]

Add the vectors:

[tex]u+v=\langle40\cos30^\circ+50\cos140^\circ,40\sin30^\circ+50\sin140^\circ\rangle\approx\langle-3.661,52.139\rangle[/tex]

Find the magnitude of the resultant vector:

[tex]||u+v||=\sqrt{3.661^2+52.139^2}\approx52.268[/tex]

Find the direction of the resultant vector:

[tex]\displaystyle\theta=tan^{-1}\biggr(\frac{52.139}{-3.661} \biggr)\approx-86^\circ[/tex]

Because our resultant vector is in Quadrant II, then our true direction angle will be 86° clockwise from the negative x-axis. So, our true direction angle is [tex]180^\circ-86^\circ=94^\circ[/tex].

Thus, B is the correct answer

Answer:

There would be 104 rooms on 4 floors in total.

Step-by-step explanation:

If there were 26 rooms on 2 floors, then you multiply 26 x 4, the result would be 104 rooms on 4 floors in total.

Answer:

52 rooms

Step-by-step explanation:

you could set up a proportion to solve this

26 rooms/ 2 floors = ?/4 floors

to find the answer for the question mark you can divide the amount of rooms by floors and get 13.

With the 13 you can multiply that by 4 to get 52 rooms. You basically used the 13 as the amount of increase

i hope this helped

if you have anymore questions feel free to ask again:3

Answer:

e): m=18.50d + 25

Step-by-step explanation:

Answer:

  A, D

Step-by-step explanation:

You want to know the bound for the values of Sn and Tn, given their definitions as ...

  [tex]\displaystyle S_n=\sum_{k=1}^n{\dfrac{n}{n^2+kn+k^2}}\\\\T_n=\sum_{k=1}^{n-1}{\dfrac{n}{n^2+kn+k^2}}[/tex]

All we need to do to determine the correct answer choices is evaluate the sums for some value of n.

For n=2, the value of S2 is ...

  S2 = 2/(4+2+1) +2/(4+4+4) = 2/7 +2/12 = 19/42 ≈ 0.4524

For n=2, the value of T2 is ...

  T2 = 2/(4+2+1) = 2/7 ≈ 0.2857 . . . . . 1/(3n) less than the value of Sn

Both of these values are less than π/(3√3) ≈ 0.6046.

The correct answer choices are ...

  A) Sn < π/(3√3)

  D) Tn < π/(3√3)

__

Additional comment

For the purpose here, it is not necessary to determine the limiting value of either Sn or Tn. It is only necessary to demonstrate which side of the given value the terms of either sequence lie.

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Answer:

from my side it's blurry

Margin of error = 0.8226401

Confidence interval = (9.17736,10.82264)

We have given data for one week recorded for 6 plants.

With a sample standard deviation of 1 inch and a sample mean of 10 inches.

For this sample, it is given that,

Sample size = n = 6

Sample SD = s = 1

Sample mean = x = 10

At a 0.10 significance level, the critical point is with t-distribution (n-1)df=5 df,

t*  =2.015048

Margin of error = E=2.015048*s/ √n = 0.8226401

Confidence interval

= (9.17736,10.82264)

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Answer:

choice for your help today 12 m is not answering me, sorry I think 25m

Answer:

Since the least number of digits in the number is 2 decimal places

Round 3.0478 to 2 dp

3.05+4.92=7.97

B is the answer

Step-by-step explanation:

Give brainliest please

Answer:

B

Step-by-step explanation:

Answer:

A. evaluate progress

Step-by-step explanation:

common sense

Answer:

I Think the answer is B I'm sorry if I'm wrong

Answer:

Infinitely many

Step-by-step explanation:

Given:

[tex]y + 12 = y + 10 + 2[/tex]

Solve:

Subtract y from  both sides

[tex]y+12-y=y+10+2-y[/tex]

Simplify

[tex]12=10+2[/tex]

Now add : 10 + 2

[tex]12=12[/tex]

Both side are equal

Since both sides are equal then answer = Infinitely many

[RevyBreeze]

[tex]sin\left(\cfrac{\theta}{2}\right)=\pm \sqrt{\cfrac{1-cos(\theta)}{2}} \qquad cos\left(\cfrac{\theta}{2}\right)=\pm \sqrt{\cfrac{1+cos(\theta)}{2}} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ sin\left( \cfrac{30^o}{2} \right)\implies \sqrt{\cfrac{1-cos(30^o)}{2}}\implies \sqrt{\cfrac{1-\frac{\sqrt{3}}{2}}{2}}\implies \sqrt{\cfrac{~~\frac{2-\sqrt{3}}{2}~~}{2}}[/tex]

[tex]\sqrt{\cfrac{2-\sqrt{3}}{2}\cdot \cfrac{1}{2}}\implies \sqrt{\cfrac{2-\sqrt{3}}{4}}\implies \boxed{\cfrac{\sqrt{2-\sqrt{3}}}{2}} \\\\[-0.35em] ~\dotfill\\\\ cos\left( \cfrac{30^o}{2} \right)\implies \sqrt{\cfrac{1+cos(30^o)}{2}}\implies \sqrt{\cfrac{1+\frac{\sqrt{3}}{2}}{2}}\implies \sqrt{\cfrac{~~\frac{2+\sqrt{3}}{2}~~}{2}} \\\\\\ \sqrt{\cfrac{2+\sqrt{3}}{2}\cdot \cfrac{1}{2}}\implies \sqrt{\cfrac{2+\sqrt{3}}{4}}\implies \boxed{\cfrac{\sqrt{2+\sqrt{3}}}{2}} \\\\[-0.35em] ~\dotfill[/tex]

[tex]\cfrac{~~ sin\left( \frac{30^o}{2} \right)~~}{cos\left( \frac{30^o}{2} \right)}\implies \cfrac{~~\frac{\sqrt{2-\sqrt{3}}}{2} ~~}{\frac{\sqrt{2+\sqrt{3}}}{2}}\implies \cfrac{\sqrt{2-\sqrt{3}}}{2}\cdot \cfrac{2}{\sqrt{2+\sqrt{3}}} \\\\\\ \cfrac{\sqrt{2-\sqrt{3}}}{\sqrt{2+\sqrt{3}}}\implies \blacktriangleright \sqrt{\cfrac{2-\sqrt{3}}{2+\sqrt{3}}} \blacktriangleleft[/tex]

Answer:

[tex]5x^{3} y^3 \sqrt{15y}[/tex] is the right answer and other are wrong

Answer:I drew a quadratic function with a vertex and axis of symmetry, hope this helps