Answer:
6+4,8-6, 4x2,8-2
Step-by-step explanation:
Please helpppppp!!!!!!!!!!!!!!!!!!!!!!!!3|x_5|-|4y|/|x+y|when x=8 & y=4
Answer:
29/49
Step-by-step explanation:
x:y = 3:4
let x = 3x , y = 5k
3x+4y/8x+5y
= 3(3k)+4(5k)/8(3k)+5(5k)
= 9k+20k/24k+25k
=29/49
PLEASE HELP SOON!!!! Pre-calc, Trig, Calculus studentsss
Answer:
Step-by-step explanation:
A rental car company charges $37.50 per day to rent a car and $0.05 for every mile
driven. Alyssa wants to rent a car, knowing that:
. She plans to drive 100 miles.
. She has at most $200 to spend.
Write and solve on
Hello!
Knowing that Alyssa wants to rent a car where the company charges $37.50 per day to rent a car and $0.05 for each mile driven we have to find out how many days she is planning on renting a car for.
Step-by-step explanation:
Using the information we have we can see that it will be an additional $5 based on how many miles she is planning on driving.
If the base cost to rent a car is $37.50 you will have to add an additional $5 for the number of miles she plans to drive making the total $42.50.
Since she has at most $200 to spend on a car rental she can rent a car for a total of 5 days at a total cost of $192.50
[tex]37.50[/tex] × [tex]4=150[/tex] + [tex]42.50[/tex] = [tex]192.50[/tex]
Hope this helps!
The inequality will be 37.5x + (0.05 ×100) ≤ 200, and Alyssa can afford 5.2 days to rent while staying within her budget
How to write and solve an inequality to determine the number of days?Given that the rental car company charges $37.50 per day to rent a car and $0.05 for every mile driven
She plans to drive 100 miles and has at most $200 to spend.
Let x is the number of days, Alyssa can afford to rent while staying within her budget
The inequality can be written as;
37.5x + (0.05 ×100) ≤ 200
Now solve for x:
37.5x + (0.05 ×100) ≤ 200
37.5x + 5 ≤ 200
37.5x ≤ 200 - 5
37.5x ≤ 195
x ≤ 195/37.5
x ≤ 5.2
Therefore, she can afford 5.2 days to rent while staying within her budget.
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Please help ASAP! Compare and contrast the formulas for P(A and B) for dependent and independent events. What is the relationship between P(B) and P(B|A) and can one equation be used for both independent and dependent events?
Dependent events;
The probability of one event DOES effect the probability of a 2nd event.
Independent events;
The probability of one event DOES NOT effect the probability of a 2nd event
Give the equation for calculating the likelihood that events A and B will occur when A and B are dependent events. The equation P(A and B) = P(A) P(B|A) yields the likelihood that A and B will occur.If the events A and B are not mutually exclusive, the probability is: (A or B) = p(A) + p(B) – p(A and B).We cannot use one equation for both independent and dependent events.Learn more about dependent and independent events here;
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A blueprint for a rectangular warehouse has a length of 18 inches and a width of 10 inches. It uses a scale of 1 inch for every 20 feet. 1. What is the actual area of the warehouse in square feet? 2. How do you know?
Answer:
The actual area of the warehouse would be:
[tex]72000~\text{feet}^{2}[/tex]
Step-by-step explanation:
Step 1: Convert all the blueprint lengths into real lengths:
Each inch in the blueprint represents 20 feet in the real world.
So, the real-life length (18 inches in blueprint) would be:
[tex]1~\text{inch}= 20~\text{feet}\\\\\text{Multiply by 18 on both sides}:\\1\times18~\text{inch}= 20\times18~\text{feet}\\18~\text{inch}= 360~\text{feet}\\[/tex]
Similarly, the real-life width would be:
[tex]1~\text{inch}= 20~\text{feet}\\\\\text{Multiply by 18 on both sides}:\\1\times10~\text{inch}= 20\times10~\text{feet}\\10~\text{inch}= 200~\text{feet}\\[/tex]
Step 2: Calculate the area
The area of the warehouse would be given by:
[tex]\text{Area}=\text{Length}\times \text{Width}[/tex]
The length is 360 feet, and the width is 200 feet, so the total area would be:
[tex]\text{Area}=\text{Length}\times \text{Width}\\\\\text{Substitute the values for the length and width}\\\text{Area}= 360\times 200\\\text{Area}=72000[/tex]
What is the maximum volume of a rectangular prism (or box) if the prism has a square base and a total surface area of 100 cm^2?
A) First, let x = the side length of the base and h = the height of the prism. Write and solve the equation for h.
B) Write a function for the volume of the box, V, in terms of x.
Answer: A. 100/x^2 = h, B. v(x) = x^2*h
Step-by-step explanation:
A. Volume = b * h
100 cm^2 = x^2 * h
100/x^2 = h
B. v(x) = x^2*h
15:4y2 – 30:23 + 4554The quotient of517is7. When this quotient is divided bythe result is 3-35-5I3y – 25y2 + 3
We are given the following expression:
[tex]\frac{15x^4y^2-30x^2y^3+45xy}{5xy}[/tex]To determine the quotient of the expression we will factor the numerator. To do that we take the Greatest Common Multiple of the denominator.
The denominator is the following expression:
[tex]15x^4y^2-30x^2y^3+45xy[/tex]To get the greatest common multiple we need to determine the multiples of the coefficients first.
For 15 we have:
[tex]factors\text{ 15= 1, 3, 5, 15}[/tex]For 30 we have:
[tex]\text{factors 30 = }1,2,3,5,6,10,15,30[/tex]For 45 we have:
[tex]\text{factors 45 =}1,3,5,9,15,45[/tex]We notice that the factors that are repeated for each of the numbers are:
[tex]\text{repeated = 1,3,5,15}[/tex]The greatest of the repeated factors is 15, therefore, the greatest common factor is 15.
Now, we take the variables that are repeated in the expression and we take the ones with smaller exponents. The variables repeated are:
[tex]xy[/tex]Of these, the ones with smaller exponents are:
[tex]xy[/tex]Now, combining the two parts we get that the greatest common factor of the denominator is:
[tex]15xy[/tex]We take out that factor and re arrange the expression, like this:
[tex]\frac{15x^4y^2-30x^2y^3+45xy}{5xy}=\frac{15xy(x^3y-2xy^2+3)}{5xy}[/tex]Now, we cancel out the "xy" and simplify 15/5:
[tex]\frac{15xy(x^3y-2xy^2+3)}{5xy}=3(x^3y-2xy^2+3)[/tex]And thus we get the quotient.
We notice that the quotient is multiplied by 3, therefore, if we divide by 3:
[tex]\frac{3(x^3y-2xy^2+3)}{3}[/tex]We can cancel out the 3 and we get:
[tex]\frac{3(x^3y-2xy^2+3)}{3}=x^3y-2xy^2+3[/tex]Therefore, the quotient is divided by 3.
31. a statistics class has 26 students. the instructor would like to select a random sample of 3 students to work together on a group project. a. how many different samples are possible? b. if 13 of the 26 students in class are freshmen, what is the probability that all 3 of the selected students are freshmen?
a. 2600 ways different samples are possible.
b. 0.11 is the probability that all 3 of the selected students are freshmen.
total student = 26
3 students are randomly selected on group project
a. the possible different sample are
[tex]26 C_{3}[/tex] = [tex]\frac{26}{3 (26-3)}[/tex]
= [tex]\frac{26}{3 (23)}[/tex]
= 2600 ways.
b. 13 students are freshmen
Pr ( 3 selected students is freshman)
[tex]\frac{13C_{3} }{26C_{3} }[/tex] = [tex]\frac{286}{2600}[/tex] = 0.11
What is probability?Probability refers to potential. A random event's occurrence is the subject of this area of mathematics. The range of the value is 0 to 1. Mathematics has incorporated probability to forecast the likelihood of various events. The degree to which something is likely to happen is basically what probability means. You will understand the potential outcomes for a random experiment using this fundamental theory of probability, which is also applied to the probability distribution. Knowing the total number of outcomes is necessary before we can calculate the likelihood that a specific event will occur.
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Rewrite in simplest terms: -4f-6(6f-10)
The given expression: -4f-6(6f-10) in simplified form
is: -40f + 60.
What is an algebraic expression and how is it simplified?
The concept of algebraic expressions is the use of letters or alphabets to represent numbers without providing their precise values. We learned how to express an unknown value using letters like x, y, and z in the fundamentals of algebra. Here, we refer to these letters as variables. Variables and constants can both be used in an algebraic expression. A coefficient is any value that is added before a variable and then multiplied by it. Simplifying the algebraic expressions is to carry out operations on the expressions and then clear it out.
Given, the expression for simplification is: y = -4f-6(6f-10)
Working on the expression above, we have:
y = -4f-6(6f-10) = -4f -36f + 60 = -40f + 60
Therefore the given expression: -4f-6(6f-10) in simplified form
is: -40f + 60.
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Ivy is competing in a Read-A-Thon. Each day , she reads for 25 minutes before school and 45 minutes after school. Find the total number of minutes Ivy spends reading after 5 days. How can you find the total number of minutes Ivy spends reading?
A) Multiply 5 and 25. Then, add 45
B) Multiply 5 and 45. Then, add 25
C) Add 25 and 45. Then, Multiply by 5
D) Add 25 and 45. Then, add 5
Answer: C
Step-by-step explanation:
It the only one that includes both.
O EQUATIONS AND INEQUALITIESSolving a word problem with two unknowns using a linear...
Given:
Total number of hamburgers and cheeseburgers sold = 439
There were 61 fewer cheeseburgers than hamburgers sold.
Let's determine the number of hamburgers sold.
Let C represent the number of cheeseburgers
Let H represent the number of hamburgers sold.
We have the system of equations:
• H + C = 439
,• C = H - 61
Now, let's solve the equations simultaneously using the substitution method.
Substitute (H - 61) for C in the first equation.
We have:
H + (H - 61) = 439
H + H - 61 = 439
2H - 61 = 439
Add 61 to both sides:
2H - 61 + 61 = 439 + 61
2H = 500
Divide both sides by 2:
[tex]\begin{gathered} \frac{2H}{2}=\frac{500}{2} \\ \\ H=250 \end{gathered}[/tex]Therefore, they sold 250 hamburgers on Friday.
ANSWER:
250 hamburgers
A car can be rented for $95 per week plus $0.95 per mile. How many miles can be driven if you have at most $380 to spend for weekly transportation? The car should be driven ....... miles a week?
We have the next inequality
[tex]95+0.95x\le380[/tex]where x is the number of miles.
Then we solve the inequality
[tex]\begin{gathered} 0.95x<380-95 \\ \end{gathered}[/tex][tex]\begin{gathered} 0.95x\le285 \\ x\le\frac{285}{0.95} \\ x\le300 \end{gathered}[/tex]The car should be driven 300 miles a week
A Ford F-150 truck is considered a half-ton truck because that is how much it can haul. How many pounds can the truck haul?
The truck can haul 1102 pounds.
According to the question,
We have the following information:
A Ford F-150 truck is considered a half-ton truck because that is how much it can haul.
(More to know: ton, pounds and kilograms are the most commonly used units for measuring weight.)
Now, we already have the knowledge that 1 ton is equal to 1000 kilograms.
So, half ton will make 500 kg.
Now, in order to convert this into pounds, we will multiply 500 kg by 2.205 because we know that 1 kg makes 2.205 pounds.
1 kg = 2.205 pounds
500 kg = (500*2.205) pounds
500 kg = 1102.5 pounds
Hence, the truck can haul 1102.5 pounds.
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Write the equation of the line that is perpendicular to the x-axis and contains point (0,
4).
The line of the equation which passes through the point (0, 4) and is parallel to the x-axis is 2y = 8.
What are equations?A mathematical statement that has an "equal to" symbol between two expressions with equal values is called an equation. As in 3x + 5 = 15, for instance. Equations come in a variety of forms, including linear, quadratic, cubic, and others. A mathematical equation is a formula that uses the equals sign to express the equality of two expressions.So, the equation is as:
A line formed needs to be parallel to the x-axis which means x = 0.Should pass through points (0, 4)Then, the equation can be:
2y = 8(Refer to the graph attached below)
If you solve will become:
2y = 8y = 4Therefore, the line of the equation which passes through the point (0, 4) and is parallel to the x-axis is 2y = 8.
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Rewrite one eighth times x cubed times y plus seven eighths times x times y squared using a common factor.
Equation y (1/8 x3 + 7) is rewritten by using a common factor. A literal equation is regarded as having at least two variables.
Given that,
Use a common factor to rewrite one eighth times x cubed times y plus seven eighths times x times y squared.
This is how the equation can be rewritten:
The first equation is written as 1/8 x3y + 7/8 xy2.
It is possible to rewrite the equation 1/8 xy(x2 + y) using the common factor.
Equation two:
1/4x.y.4x2 + 28y
1/4 .4 x³ .y + 28y
x3.y + 28y equation to be solved
Using the formula
y = (x3 + 28).
Third claim:
1/4. x. y. x2 + 7y
Fix the problem.
1/4 . x³ .y + 7y
Write y = (1/4x3 + 7) in a new way.
Fourth assertion:
1/8 x3y2.y + 7 x 1/8 x3y3 + 7 x
After removing the common element x(1/8 x2y3+ 7), rewrite the equation.
Fifth Declaration
1/8 x. y. x² + 7y
1/8 x³. y + 7y
Equation y (1/8 x3 + 7) is rewritten.
Thus, a literal equation is one that contains at least two variables. Solve for one variable in terms of the other variable to rephrase a literal equation.
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Question 2
help pls its hard i forgt how to do it
Answer: 52
Step-by-step explanation:
a^2+b^2=c^2
x is the hypotenuse (c). You can find the hypotenuse by finding the opposite of the right angle
48^2+20^2=2304+400=2704
√2704=52
x=52
What’s 4/6 - 1/3 simplified
Answer:
1/3
Step-by-step explanation:
(4/6) - (1/3)
The denominators need to be the same, so let's convert the second term to (2/6), which is the same as (1/3)
(1/3)*(2/2) = (2/6)
Now we can wite:
(4/6) - (2/6)
This is equal to 2/6 or 1/3
Hello!
The equation [tex]\frac{4}{6} - \frac{1}{3}[/tex] simplified is [tex]\frac{1}{3}[/tex].
Step-by-step explanation:
Begin by giving both equations common denominators in this case we will use 18.
For the first set of fractions we multiply 4 by 3 to get 12 and for the second set of fractions we multiply 1 by 6 to get 6.
Our new set of fractions will look like this [tex]\frac{12}{18}[/tex][tex]- \frac{6}{18}[/tex]
Now we can subtract the numerators since our denominators match.
[tex]12-6=6[/tex] so the new answer will be [tex]\frac{6}{18}[/tex]
It's time to simplify both sets of fractions before we can completely solve the equation. (divide by 2, then 3)
[tex]\frac{6}{18}[/tex] ÷ [tex]2=\frac{3}{9}[/tex] ÷ [tex]3=\frac{1}{3}[/tex]
Since 3 is larger than 1 we are done reducing, time to solve for the final answer.
[tex]\frac{4}{6} -\frac{1}{3} =\frac{1}{3}[/tex]
Hope this helps!
In a sale, the normal price of a TV is reduced by 20%.
The sale price of the TV is £660
Work out the normal price of the TV.
Jessica wants to make a spinner that has all of the following characteristicsSketch a possible spinner for Jessica. Be sure to label each section of thespinner with a name and with its theoretical probability.• Blue, red, purple, and green are the only colors on the spinner.• It is half as likely to land on blue as to land on red.• It is three times as likely to land on purple as green.• There is a 50% probability of landing on either blue or red and a 50%probability of landing on either purple or green.
First we have to split the spinner into two equal parts. One half belongs to the blue and red sections, and the other half belongs to the green and purple sections.
Formulating an equation for the first part, we have:
P(b) + P(r) = 0.5 ( P(b): probability of landing on blue section, P (r): probability of landing on red section)
P(r) + 1/2*P(r) = 0.5 ( Since it is half as likely to land on blue as to land on red)
3/2*P(r) = 0.5 (Adding like terms)
P(r)= 0.5 / (3/2) (Dividing on both sides by 3/2)
P(r)= 1/3 (Dividing)
P(b)=1/2*P(r) (Finding the probability of landing on blue section)
P(b)= 1/6
Formulating an equation for the second part, we have:
P(g) + P(p) = 0.5 ( P(g): probability of landing on green section, P (r): probability of landing on purple
section)
P(g) + 3*P(g) = 0.5 ( Since it is three times as likely to land on purple as green)
4*P(g) = 0.5 ( Adding like terms)
P(g) = 0.5/4 (Dividing by 4 on both sides of the equation)
P(g) = 1/8 (Dividing)
P(p) = 3*P(g) (Finding the probability of landing on purple section)
P(p)= 3/8
2 1/3 - 4/7
what is the answer to this question
The solution for the algebraic expression 2 1/3 - 4/7 is 37/21
Given,
The algebraic expression ; 2 1/3 - 4/7
We have to solve this expression;
First lets solve the mixed fraction 2 1/3
2 1/3 = (2 x 3) + 1 / 3 = 6 + 1 / 3 = 7/3
Mixed fraction;
A mixed fraction is one that is represented by both its quotient and remainder. A mixed fraction is, for instance, 2 1/3, where 2 is the quotient and 1 is the remainder. An amalgam of a whole number and a legal fraction is a mixed fraction.
Now,
7/3 - 4/7 = (7 x 7) / (3 x 7) - (4 x 3) / (7 x 3) = 49/21 - 12/21
That is,
49/21 - 12/21 = (49 - 12) / 21 = 37/21
That is,
The solution for the algebraic expression 2 1/3 - 4/7 is 37/21
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the probability of observing a window given there is no window at its location is 0.2, and the probability of observing a window given there is a window is 0.9. after incorporating the observation of a window, what are the robot's new probabilities for being in
Updated Probabilities are: P(L1/W) = 0.341 & P(L1/w) = 0.949
Let W be the event that the robot's camera observes a window
It is given that the Probability of observing a window there is no window at its location is given 0.2
P(W/ L1) = 0.2 ( L1 which does not have a window)
Also, probability of observing a window is 0.9
P(W/ L2) = 0.9 ( L2 has window)
Now we have to find updated probabilities for the robot being in L1 i.e:- P(L1/W) & P(L1/w)
w means the camera does not observe a window.
By Bayes Rule,
P(L1/W) = P(L1)P(W/L1)/P(L1)P(W/L1)+P(L2)P(W/L2)
= (0.7x 0.2)/ (0.7x0.2) + (0.3x0.9)
= (0.14)/ 0.14+0.27
≈0.341 (rounded to 3. decimal places)
Thus the probability of being in L1 if the camera observes a window is nearly 0.341.
P(L1/w) = P(L1)P(w/L1)/P(L1)P(w/L1)+P(L2)P(w/L2)
As P(W/L1) = 0.2;
P(w/L1) = 1 - P(w/L1) = 1-0.2 = 0.8
Also P(W/L2) = 0.1;
P(w/L2) = 1 - P(w/L2) = 1-0.9 = 0.1
P(L1/w) = (0.7 X 0.8)/ (0.7X0.8) + (0.3X0.1)
=(0.56)/ (0.56+0.03) = (0.56/ 0.59)
≈ 0.949 (rounded to 3 decimal places).
Thus the probability of being in L1 if observe not the window is nearly 0.949.
Updated Probabilities are: P(L1/W) = 0.341 & P(L1/w) = 0.949
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Y = 17x - 8, y = 24x +6 Parallel Perpendicular Neither
Two parallel lines in the coordinate system share the same slope, this means that if you have two parallel lines:
[tex]\begin{gathered} y_1=m_1x_1+b_1 \\ y_2=m_2x_2+b_2 \\ \text{Their slopes must be equal:} \\ m_1=m_2 \end{gathered}[/tex]For the given equations, the slopes are:
[tex]\begin{gathered} y=17x-8 \\ m=17 \end{gathered}[/tex][tex]\begin{gathered} y=24x+6 \\ m=24 \end{gathered}[/tex]The slopes are different, so this lines are not parallel.
Two lines are perpendicular, when the slope of one of them is the negative inverse of the first one, this is for the perpendicular lines:
[tex]\begin{gathered} y_1=m_1x_1+b_1 \\ y_2=m_2x_2+b_2 \\ m_2=-\frac{1}{m_1} \end{gathered}[/tex]For the given equations, using y=17x-8 as reference, the slope of a line perpendicular to this one must be:
[tex]m_{}=-\frac{1}{17}[/tex]The slope of a perpendicular line to y=17x-8 is different from the slope of the second given line, so you can conclude that these lines are not perpendicular.
The correct choice is Neither
Determine whether each order pair is a solution of the equation
Answer:
Given equation is, x+3y=6
To determine whether each order pair is a solution of the equation
(3,1)
we have that, when x=3 we get y=1
Let us check this in the equation.
Put x=3, we get
[tex]3+3y=6[/tex][tex]\begin{gathered} 3y=6-3 \\ 3y=3 \end{gathered}[/tex][tex]y=1[/tex]Hence (3,1) is the solution of the equation.
(6,0)
Put x=6, we get,
[tex]6+3y=6[/tex][tex]y=0[/tex]
Hence (6,0) is the solution of the equation.
(-2,2/3)
Put x=-2, we get,
[tex]-2+3y=6[/tex][tex]3y=6+2[/tex][tex]y=\frac{8}{3}[/tex]Hence (-2,2/3) is not the solution of the equation.
PLS HELP, IN A HURRY. Would Appreciate!!!!!
Answer:
y = w/(h - 5c^3)
Step-by-step explanation:
w = yh - 5yc^3
factorise out y:
w = y(h - 5c^3)
rearrange:
y = w/(h - 5c^3)
I think this is correct.
ships a and b leave port together. for the next two hours, ship a travels at 20 mph in a direction 30o west of north while the ship b travels 20o east of north at 25 mph. a) what is the distance between the two ships two hours after they depart? b) what is the speed of ship a as seen by ship b?
Two hours after depart, the distance between two ships is 39.2 miles and the relative speed of ship A seen by ship B is 19.6 mph heading to 18.4⁰ South of East.
The situation can be depicted on the attached picture.
Let North - South be the y-axis and East - West ne the x-axis.
The velocities vector can be represented as:
Ship A, 20 mph 30⁰ west of north:
vA = - 20 . cos( 60⁰) i + 20 . sin( 60⁰) j
vA = -10 i + 10√3 j
Ship B, 25 mph 20⁰ east of north:
vB = 25 . cos( 70⁰) i + 25 . sin( 70⁰) j
vB = 8.55 i + 23.5 j
b) The speed of ship A relative to ship B is:
vAB = vA - vB
= ( -10 i + 10√3 j) - (8.55 i + 23.5 j)
= -18.55 i - 6.18 j
or vAB = sqrt (18.55² + 6.18²) = 19.6 mph with the angle tan⁻¹ (6.18/18.55) = 18.4⁰ South of East.
a) The distance between 2 ships after 2 hours:
d = vAB . 2 hours
d = 19.6 . 2 = 39.2 miles
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Please help me i dont the answer
[tex] \huge\underline\mathcal{Answer \: -} [/tex]
We know that ,
exterior angle equals sum of two interior opposite angles.
therefore ,
[tex]\bold{x + x + 14 = 136\degree} \\ \\ \longrightarrow \: 2x + 14 = 136\degree \\ \\ \longrightarrow \: 2x = 136\degree - 14 \\ \\ \longrightarrow \: 2x = 122\degree \\ \\ \longrightarrow \: x = \cancel\frac{122}{2} \\ \\ \longrightarrow\boxed{ \: x = 61\degree}[/tex]
hence , the first option is correct.
hope helpful ! ;-;
Answer:
First find the last angle of the triangle.
180 - 136 = 44° (sum of angles on a straight line=180)
Form an equation with the unknown angles with the knowledge that sum of angles in a triangle add up to 180°.
x + (x + 14) + 44 = 180
Simplify and solve for x.
2x + 58 = 180
2x = 122
x = 61
Which statement about the data in the table is true?
O The data represent a proportional relationship, and the constant of proportionality is $10.
The data do not represent a proportional relationship, but the rate of change of the data is $5 per shirt.
There is not a constant rate of change for these data.
The data represent a proportional relationship, and the constant of proportionality is $5.
B) The data does not represent a proportional relation, but it has constant rate of change of $5 per shirt.
A)
Take number of T-shirts up to 3 and calculate their proportions.
2/1 = 15/10 = 1.5 (3/2) = 20/15 = 1.33
Clearly the rate of T- shirts is not proportional.
B)
From option (A) we found the given data is not proportional but from the table given in question the rate of change of T- shirts is indeed $5.
C)
No, there is a constant rate of change of $5 as shown in the table below.
D)
No, the data does not represent a constant proportionality. The rate varies.
2/1 = 15/10 = 1.5 (3/2) = 20/15 = 1.33
What is rate of change ?Rate of change is the rate that describes how one quantity changes relative to another quantity. If x is the independent variable and y is the dependent variable, then
rate of change change=change in y / change x
Rate of change can be positive or negative. This corresponds to an increase or decrease in the y-value between two data points. If a quantity does not change over time, it is called zero rate of change.
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can someone please answer this step by step asap? im confused and dont know how to solve this
3 equations that can be used to solve the given scenario are:
10x + 15x + 20x = 500045x = 500010x + 15x + 20x = 300What exactly are equations?In mathematical equations, the equals sign is used to show that two expressions are equal.An equation is a mathematical statement that uses the word "equal to" in between two expressions of the same value.As an illustration, 3x + 5 equals 15.There are many different types of equations, including linear, quadratic, cubic, and others.The three primary types of linear equations are slope-intercept, standard, and point-slope equations.So, equations that can be used to solve the following scenario are:
Let, the number of students in each group is 'x'.Then,
10x + 15x + 20x = 500045x = 500010x + 15x + 20x = 300Therefore, 3 equations can be used to solve the given scenario are:
10x + 15x + 20x = 500045x = 500010x + 15x + 20x = 300Know more about equations here:
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Elijah put 2x+3
2
x
+
3
dollars in the bank the first week. The following week he doubled the first week’s savings and put that amount in the bank. The next week, he doubled what was in the bank and put that amount in the bank. He now has $477 in the bank. How much money did he put in the bank the first week?
Elijah put $53 in the Bank in the first week .
In the question ,
it is given that Elijah put (2x+3) in the first week .
In the second week Elijah put double the first week savings
that means second week deposit = 2*(2x+3) = 4x+6
in the third week he doubled the amount that was in the bank ,
which means third week deposit = 2*(first week + second week deposit)
= 2*(2x+3+4x+6)
Also given that total amount in the bank = $477
total amount = first week + second week + third week deposit
substituting the values we get
477 = (2x+3) + (4x+6) + 2*(2x+3+4x+6)
477 = 2x+3+4x+6+4x+6+8x+12
477 = 18x + 27
18x = 477-27
18x = 450
x = 450/18
x = 25
the amount deposited in the first week = 2x+3
= 2(25)+3
= 50+3 = $53
Therefore , Elijah put $53 in the Bank in the first week .
The given question is incomplete , the complete question is
Elijah put 2x+3 dollars in the bank the first week. The following week he doubled the first week’s savings and put that amount in the bank. The next week, he doubled what was in the bank and put that amount in the bank. He now has $477 in the bank. How much money did he put in the bank the first week?
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A company makes concrete bricks shaped like rectangular prisms. Each brick is 11 inches long, 8 inches wide, and 5 inches tall. If they used 11,000in3 of concrete, how many bricks did they make?
Answer:
25 bricks
Step-by-step explanation:
Calculate the volume of one brick:
Volume = (11')(8")(5") = 440 in^3
Divide the volume of a one brick into the volume of concrete that will be used:
(11000 in^3 concrete)/(440 in^3 concrete/brick) = 25 bricks