Use the quadratic formula f(x)=3x2−18x+23
to determine the coordinates of the vertex of the best-fitting parabola. Write the exact answer. Do not round.

The value of x is given as follows:

x = 4.

The exponential expression for this problem is defined as follows:

8^x = 4096.

Both 8 and 4096 are powers of 2, and can be represented as follows:

Hence the expression can be written as follows:

(2³)^x = 2^12.

Applying the power of power rule, we have that:

2^(3x) = 2^(12).

Applying the one-to-one property of the family of functions powers of x, the value of x is obtained as follows:

3x = 12

x = 4.

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Step-by-step explanation:

Out of the given options, only √196 is a rational number.

A rational number is a number that can be expressed as the ratio of two integers. In other words, it can be written in the form of p/q where p and q are integers and q is not equal to zero.

√56 cannot be simplified further and has no integer factors that can be canceled out to express it as a ratio of two integers. Therefore, it is an irrational number.

Similarly, √63 and √240 cannot be simplified further and do not have any integer factors that can be canceled out to express them as a ratio of two integers. Therefore, they are also irrational numbers.

On the other hand, √196 simplifies to 14 which is a ratio of two integers (14/1). Hence, it is a rational number.

In summary, only √196 is a rational number out of the given options.

Answer:

8,415

Step-by-step explanation:

2+2+2+2+20+41+20+8252+74 = 8,415

Answer:

8,415

Step-by-step explanation:

Copy and pasted into a calc

The correct answer is 5.88 × 1013 miles. This is because a light-year is the distance that light can travel in one year, or approximately 5.88 × 1012 miles.

A light year is a unit of distance used to measure astronomical distances. It is the distance that light travels in a vacuum in one year, which is equal to 9.46 trillion kilometres. This means that light travelling at a speed of 300,000 kilometres per second would take one year to travel nine trillion kilometres. T

To find the distance of a star from Earth, one must multiply the number of light-years by 5.88 × 1012. In this case, the star is 9.8 × 101 light-years away, meaning that it is 9.8 × 101 times 5.88 × 1012 miles, or 5.88 × 1013 miles, away from Earth.

Light-years are a unit of distance used by astronomers to measure the great distances between stars and galaxies. Light travels at a speed of approximately 186,000 miles per second, and one light-year is the distance that light can travel in one year. For example, a star that is 9.8 × 101 light-years away from Earth is approximately 5.88 × 1013 miles away from Earth. To convert the number of light-years to the number of miles, one must multiply the number of light-years by 5.88 × 1012.

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Answer:

We'll start with the left-hand side (LHS) of the identity, which is:

sin x (1 + cot^2 x)

We can rewrite cot^2 x as (cos x / sin x)^2, since cotangent is the reciprocal of tangent. Substituting this into the LHS, we get:

sin x (1 + (cos x / sin x)^2)

Now we can simplify the expression in the parentheses by using the identity:

tan^2 x + 1 = sec^2 x

Rearranging this identity, we get:

tan^2 x = sec^2 x - 1

Substituting this into our expression, we get:

sin x (1 + (cos x / sin x)^2) = sin x (1 + (cos^2 x / sin^2 x))

= sin x (sin^2 x / sin^2 x + cos^2 x / sin^2 x)

= sin x ((sin^2 x + cos^2 x) / sin^2 x)

= sin x (1 / sin^2 x)

= sin x / sin^2 x

= 1 / sin x

Now we'll simplify the right-hand side (RHS) of the identity, which is:

csc x

We know that csc x is the reciprocal of sin x, so we can rewrite the RHS as:

1 / sin x

This is the same as the expression we obtained for the LHS, so we have shown that:

sin x (1 + cot^2 x) = csc x

And this proves the identity!

Remember, when you're proving trigonometric identities, it's important to be familiar with the fundamental trigonometric identities and the basic algebraic rules of manipulating equations

good luck with your exam

Answer:

90(3^10) is divisible by 90.

Step-by-step explanation:

9^7+3^12=(3^2)^7+3^12

=(3^7)^2+3^12

=(3^14)+(3^12)

=(3^12)(3^2)+3^12

=(3^12)(3^2+1)

=(3^12)(4)

=90(3^10)

The following angle pairs represent vertical angles (C) ∠DCE ≅ ∠BCA.

Vertical angles are a pair οf nοn-adjacent angles fοrmed by the intersectiοn οf twο lines. Vertical οppοsite angles are a type οf vertical angles that are acrοss frοm each οther and have the same measure. In οther wοrds, if twο lines intersect at a pοint, then the angles that are οppοsite each οther (i.e., οne οn the left and οne οn the right οf the intersectiοn) are called vertical οppοsite angles, and they are cοngruent.

Vertical angles are fοrmed by the intersectiοn οf twο lines. They are cοngruent, which means they have the same measure.

Lοοking at the diagram, we see that angles ∠KDJ and ∠FBG are nοt fοrmed by the intersectiοn οf twο lines. They are bοth interiοr angles οf the quadrilateral KDFB. Therefοre, they are nοt vertical angles.

∠LAC and ∠GBC are nοt fοrmed by the intersectiοn οf twο lines. They are bοth interiοr angles οf the quadrilateral KDFB. Therefοre, they are nοt vertical angles.

Angles ∠DCE and ∠BCA are fοrmed by the intersectiοn οf twο lines, and they are οn οppοsite sides οf the transversal AC. Therefοre, they are vertical angles, and chοice (C) is the cοrrect answer.

Angles ∠DCE and ∠BCE share a cοmmοn ray, CE, but they are nοt fοrmed by the intersectiοn οf twο lines. Therefοre, they are nοt vertical angles.

Sο the cοrrect answer is (C) ∠DCE ≅ ∠BCA.

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The company should produce 5 units of Metakeb tractors, 8 units of Mewesson tractors, and 16 units of Metekem tractors in a month to use up all the available resources.

What is equations ?

An equation is a mathematical statement that shows that two expressions are equal. It consists of two expressions separated by an equals sign. For example, 3x + 5 = 14 is an equation that states that the sum of 3 times x and 5 is equal to 14.

Let x, y, and z be the number of units of Metakeb, Mewesson, and Metekem tractors produced, respectively.

Then we have the following system of equations based on the time required in each department:

[tex]1200x + 1800y + 3000z &\leq 63000 \\&&\text{(machining department)}\2400x + 1200y + 1200z &\leq 69600 \\&&\text{(assembly department)}\600x + 3000y &\leq 49800 \\&&\text{(inspection department)}[/tex]

Converting the hours to minutes, we get:

Machining department: 1050 hours = 63,000 minutes

Assembly department: 1160 hours = 69,600 minutes

Inspection department: 830 hours = 49,800 minutes

We can rewrite the system of equations as follows:

[tex]20x + 30y + 50z &\leq 1050 &&\text{(machining department)}\\ \\10x + 5y + 5z &\leq 580 &&\text{(assembly department)}\\ \\x + 5y &\leq 83 &&\text{(inspection department)}\\ \\[/tex]

To use Gaussian elimination to solve the system of equations, we first write the augmented matrix:

[tex]\begin{bmatrix}20 & 30 & 50 & | & 1050 \\10 & 5 & 5 & | & 580 \\1 & 5 & 0 & | & 83\end{bmatrix}[/tex]

Performing row operations to obtain row echelon form:

[tex]\begin{bmatrix}20 & 30 & 50 & | & 1050 \\0 & -55 & -95 & | & -790 \\0 & 1 & -5/4 & | & -1.35\end{bmatrix}[/tex]

Next, perform additional row operations to get the matrix in reduced row echelon form:

[tex]\begin{bmatrix}20 & 30 & 50 & | & 1050 \\0 & 1 & 19/55 & | & -14.36 \\0 & 0 & 367/55 & | & 105.36\end{bmatrix}[/tex]

Finally, solve for the variables:

[tex]z &= \frac{105.36}{367/55} = 16 \\ \\y + \frac{19}{55}z &= 14.36 \\ \\y + \frac{19}{55}(16) &= 14.36 \\ \\y &= 8 \\ \\20x + 30y + 50z &= 1050 \\ \\20x + 30(8) + 50(16) &= 1050 \\ \\20x &= 90 \\ \\x &= 4.5[/tex]

Therefore, the company should produce 4.5 units of Metakeb tractors, 8 units of Mewesson tractors, and 16 units of Metekem tractors in a month to use up all the available resources. Since we cannot produce fractional units, we can round up the values of x and y to obtain a feasible production plan of 5 units of Metakeb tractors and 8 units of Mewesson tractors.

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The present value of the security is $2142.86, rounded to the nearest cent.

Value is a subjective concept that is based on personal beliefs, experiences, and backgrounds. It is the appreciation of something, whether tangible or intangible, that is based on a person's perception of its worth. Value is often used to describe the worth or importance of something or someone, and can be expressed in monetary terms or in terms of the usefulness of something. Ultimately, value is the measure of how much something is worth to an individual.

The present value of this security is $2142.86. This is determined by using the formula:

Present Value = Dividend / (1 + R)t

Where Dividend is the annual dividend of $150, R is the rate of return which is 7%, and T is the time in years which is 1.

Therefore, the present value of the security is:

150 / (1 + 0.07)¹ = $2142.86

Thus, the present value of the security is $2142.86, rounded to the nearest cent.

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The linear functions of the graph is y = 2x + 5

The complete question is added as attachment

From the question, we have the following parameters that can be used in our computation:

(0, 5) and (-2.5, 0)

From the question, we understand that the function is a linear function

A linear function is represented as

y = mx + c

Using the above as a guide, we have the following equations

0 * m + c = 5

-2.5 * m + c = 0

When evaluated, we have

c = 5

So, we have

-2.5 * m + 5 = 0

This gives

-2.5m = -5

Evaluate

m = 2

So, the equation is y = 2x + 5

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The seismic waves of the Chernobyl disaster were approximately 400 times stronger than the standard seismic waves.

The Chernobyl disaster was a catastrophic nuclear accident that occurred on April 26, 1986 at the Chernobyl Nuclear Power Plant in Ukraine. The accident occurred due to a sudden power increase that caused an unexpected power surge in one of the reactors, resulting in a series of explosions and a fire that released large quantities of radioactive particles into the atmosphere.

This is because the Chernobyl disaster was a nuclear explosion, which released a vast amount of energy, much greater than that released by a standard earthquake.

The nuclear reactor exploded at the Chernobyl site, releasing a large amount of energy into the atmosphere. This energy was then converted into seismic waves, which spread out in all directions. These seismic waves were much stronger than the waves produced by a standard earthquake, and they were felt around the world.

The seismic waves generated by the Chernobyl disaster had an estimated magnitude of 5.5, while standard seismic waves usually have a magnitude of 2.0 or less. This means that the Chernobyl disaster seismic waves were around 400 times more powerful than the standard seismic waves.

The Chernobyl disaster is one of the most devastating nuclear accidents in history. The seismic waves that were generated were far stronger than those of a standard earthquake, and the energy released was devastating for the region and the world. The effects of the disaster are still felt today, and it serves as a reminder of the dangers of nuclear energy.

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Answer

1) 58    2) 57   3) 65   4) 65   5) 58   6) 57   7) 58   8) 122   9) 65   10) 115 11) 122   12) 58

Step-by-step explanation:

Answer:

One possible equation that represents the data in the table is: y = 4x^2.

The formula for the linear function in the graph is f(x) = -2x + 4.

The graph is a data structure that is used to represent relationships between objects. It is composed of nodes (or vertices) that are connected by edges (or lines). Graphs can be used to represent many types of data, such as networks of people, roads, and even abstract concepts like language. Graphs are used in a variety of fields, such as computer science, mathematics, and sociology. They allow for efficient storage and retrieval of data, as well as efficient traversal of the data.

The graph shown below is a linear graph with a slope of -2 and a y-intercept of 4.

To find the formula for the linear function, we can use the slope-intercept form, which is y = mx + b. In this equation, m is the slope of the line and b is the y-intercept.

Therefore, the formula for the linear function in the graph is f(x) = -2x + 4.

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complete question:

Find a formula for the linear function depicted in the following graph.

f(x)=

The domain of the function is x ≥ 1 and the range of the function is f(x) ≤ 0.

The given function is:

f(x) = -√(x-6+5)

Simplifying inside the square root gives:

f(x) = -√(x-1)

For this function, the value inside the square root must be non-negative, so we have:

x - 1 ≥ 0

x ≥ 1

So, the domain of the function is all real numbers greater than or equal to 1.

To find the range of the function,

We can note that the square root is always non-positive since it has a negative coefficient.

So, the range of the function is all real numbers less than or equal to 0.

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Answer:

429

Step-by-step explanation:

Option C, The two packages have the same volume because their bases are congruent and they have the same height.

Volume is a measure of the amount of space occupied by a three-dimensional object. It is typically measured in cubic units, such as cubic meters or cubic centimeters.

The volume of cylinder A = πr²h

= 6πr²

The volume of cylinder B= πr²h

= 6πr²

As both the cylinder have same values, Option C, The two packages have the same volume because their bases are congruent and they have the same height.

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Rounding to the nearest whole number, we get that approximately 340 students in the random sample of 431 IRSC students are under the age of 22.

Percentages are commonly used to express ratios, proportions, or rates in many fields, such as mathematics, science, economics, and everyday life. They can be used to compare quantities, indicate changes, or make predictions based on data. For instance, we can use percentages to calculate discounts, taxes, interest rates, or probabilities, or to analyze trends, surveys, or experiments. Percentages are also often used in visual representations, such as pie charts, bar graphs, or maps, to show the distribution or magnitude of data.

Here,

To determine how many IRSC students are under the age of 22, we need to find 67% of the total number of students. Using the percentage formula, we get:

67% × 19,026 = 12,739.42

Rounding to the nearest whole number, we get that approximately 12,739 IRSC students are under the age of 22.

To determine how many students in the random sample of 431 students are under the age of 22, we need to find 79% of the sample size. Using the percentage formula, we get:

79% × 431 = 340.49

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The length of the side AB in the triangle is AB = 13.9 inches

You should be aware that the Pythagoras' Theorem states that the square of the hypotenuse is equal to the sum of the squares of the other two sides.

The given sides are

AC = 8.5 inches

BC = 11 inches

AB = x

Using the Pythagoras rule we have

x² = 11² + 8.5²

x² = 121 + 72.25

x² = 193.25

x = √193.25

x = 13.9 inches

Therefore AB = 13.9 inches

3  The sine and cosine ratios for angles A and B are

Sine A = opposite/Hypotenuse

Sin A = 11/13.9

Sine A = 0..7914

A = Sin⁻¹0.7914

The ratio cos B = Adjacent /Hypo

Cos B = 8.5/13.9

Cos B = 0.6115

B = Cos⁻¹0.6115

4   The relationship between sine of angle A and cosine angle B is that

Sin A + Cos B = 1 approximately

The sum of angles A and B. are 1

7    a   sin40 = cos 50

      b   cos27 = sin63

      c    sin 90 = cos0

      d    cos 65 = sin 25

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Answer: In a parallelogram, opposite angles are congruent. So we know that angle A is congruent to angle C. Let's call the measure of angle A "y".

Therefore, we have:

angle A = y

angle B = 3x + 36

angle C = y (because opposite angles in a parallelogram are congruent)

angle D = 6x - 6

The sum of the measures of the angles in a parallelogram is 360 degrees. So we can write an equation:

angle A + angle B + angle C + angle D = 360

Substituting in the values we know:

y + (3x + 36) + y + (6x - 6) = 360

Simplifying:

2y + 9x + 30 = 360

2y + 9x = 330

Now we have an equation with two variables. But we also know that angle A and angle C are congruent, so y = angle A = angle C. Substituting this into the equation above:

2(angle A) + 9x = 330

2(angle A) = 330 - 9x

angle A = (330 - 9x)/2

Therefore, the measure of angle A is (330 - 9x)/2.

Step-by-step explanation:

Answer:

2502

Step-by-step explanation:

8,794-2,670-3,622=

Answer:

y = -1/16 (x+9)^2 - 4

Step-by-step explanation:

y = -1/16 (x^2 + 18x + 81) - 4

y = -1/16 x^2 - 18/16 x - 81/16 - 4

y = -1/16 x^2 - 18/16 x - 85/16

7,310 cm^2 is the area of the paper that needed to be covered with colored paper as per the given cuboid box dimensions.

The Given data is:

The total surface area of the given cuboid box can be calculated by the sum of the areas of all six faces.

The given dimensions of cuboid box = 70 cm×28 cm×35 cm

The Area of the Base of the cuboid  box is:

70 × 35  = 2450 cm^2

The Area of each face of the cuboid box is:

28  × 35  = 980 cm^2

The Area of each back of the cuboid box is:

70  × 28 cm= 1960 cm^2

The total surface area =

2450 cm^2+ 2 × 980 cm^2+ 2 × 1960 cm^2 = 7,310 cm^2

Therefore, we can conclude that 7,310 cm^2 is the area of the paper that needed to be covered with colored paper.

The required function is f(m) = -53.33m + 360, where f(m) represents the number of frogs in the lake after m months.

What is function ?

In mathematics, a function is a rule that assigns a unique output or "dependent variable" to each input or "independent variable" in a set. It is a relation between a set of inputs and a set of possible outputs, with the property that each input is related to exactly one output.

Based on the given graph, it appears that the number of frogs in the lake is decreasing linearly over time. We can use the slope-intercept form of a linear equation to represent this relationship:

y = mx + b

where y is the number of frogs, x is the time in months, m is the slope (or rate of decrease) of the line, and b is the initial number of frogs at time zero.

To find the slope of the line, we can use the two points (0, 360) and (3, 200) from the graph:

m = (change in y) / (change in x) = (200 - 360) / (3 - 0) = -53.33

So the slope of the line is -53.33, which means that the number of frogs is decreasing by an average of 53.33 per month.

To find the initial number of frogs, we can use the y-intercept of the line, which appears to be around 360 on the graph. So we have:

b = 360

Putting it all together, the function that represents the number of frogs in the lake after m months is:

f(m) = -53.33m + 360

Therefore, the required function is f(m) = -53.33m + 360, where f(m) represents the number of frogs in the lake after m months.

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An angle whose vertex lies on a circle and whose sides intercept the circle (the sides contain chords of the circle) is called an inscribed angle. The measure of an inscribed angle is half the measure of the arc it intercepts