Given the points:
[tex](-9,3),(7,-6)[/tex]You need to use the formula for calculating the distance between two points:
[tex]d=\sqrt{(x_2-x_1)^2+(y_2-y_1^})^2[/tex]Where the points are:
[tex]\begin{gathered} (x_1,y_1) \\ (x_2,y_2) \end{gathered}[/tex]In this case, you can set up that:
[tex]\begin{gathered} x_2=7 \\ x_1=-9 \\ y_2=-6 \\ y_1=3 \end{gathered}[/tex]Then, you can substitute values into the formula and evaluate:
[tex]d=\sqrt{(7-(-9))^2+(-6-3)^2}[/tex][tex]d=\sqrt{(7+9)^2+(-9)^2}[/tex][tex]d=\sqrt{(16)^2+(-9)^2}[/tex][tex]d=\sqrt{256+81}[/tex][tex]d=\sqrt{337}[/tex][tex]d\approx18.36[/tex]Hence, the answer is:
[tex]d\approx18.36[/tex]You are trying to put together a chart depicting how many people by age group attended the most recent blockbuster movie What type of chart would best to use to display this Information and why-column graphs -line graphs-pie charts -bar graphs -Area charts -scatter charts
The first step will be to review all of the types of graphs or charts mentioned in the options.
The following diagram shows an example of each type of graph:
In this case, we need a graph to show the number of people by age group that attended the movie.
In this case, the line graph, the area chart, and the scatter chart will not represent the information in the best way, but a column graph, a bar graph, or a pie chart will give a better idea of the number of people by age group that went to see the movie.
Answer:
-Column graphs
-Pie charts
-Bar graphs
In a class of 6, there are 4 students who are secretly robots. If the teacher chooses 2 students, what is the probability that neither of them are secretly robots?i know how to get 2/6 but how do i get the other fraction?
The chance of the first student chosen not secretly being a robot is 2/6, but if the student is secretly a robot, then it doesn’t matter who the second student chosen is, because “neither” cannot be obtained.
So, 2/6th the time we care about the second student. There is in this case 1 non robot among the 5 remaining students, so the chance is 1/5 of picking that second non robot.
Hence;
2/6 x 1/5 = 2/30 = 1/15
Jason is making bookmarks to sell to raise money for the local youth center. He has 29 yards of ribbon, and he plans to make 200 bookmarks.Approximately how long is each bookmark, in centimeters?
The Solution:
The correct answer is 13.26 centimeters.
Explanation:
Given that Jason has 29 yards of ribbon, and he plans to make 200 bookmarks.
We are asked to find the approximate length (in centimeters) of each bookmark.
Step 1:
Convert 29 yards to centimeters.
[tex]\begin{gathered} \text{ Recall:} \\ \text{ 1 yard = 91.44 centimeters} \end{gathered}[/tex]So,
[tex]29\text{ yards = 29}\times91.44=2651.76\text{ centimeters}[/tex]Step 2:
To get the length of each bookmark, we shall divide 2651.76 by 200.
[tex]\text{ Length each bookmark = }\frac{2651.76}{200}=13.2588\approx13.26\text{ centimeters}[/tex]Therefore, the correct answer is 13.26 centimeters.
Rewrite 20 - 4x³ using a common factor.
O 4x(5-x²)
O4(5 - 4x³)
02x(10-2x²)
02(10-2x³)
Answer:
[tex]20 - 4 {x}^{3} = 4(5 - {x}^{3} )[/tex]
Rewrite 4x + 16 using a common factor.
Answer 4(x + 4)
a quadratic function has its vertex at the point (4,6) the function passes through the point (-5,-2) find the quadratic and linear coefficients and the constant term of the function The quadratic coefficient is_____The linear coefficient is_______the constant term is_____
We have to find the equation of the quadratic function.
We know the vertex, located in (4,6), and one point (-5,-2).
The x-coordinate of the vertex (4) is equal to -b/2a, being a the quadratic coefficient and b the linear coefficient.
Now, we have 2 points to define the 3 parameters, so one of the parameters is undefined.
[tex]y=ax^2+bx+c[/tex]We start with the vertex, that we know that is:
[tex]\begin{gathered} x=-\frac{b}{2a}=4 \\ -b=4\cdot2a=8a \\ b=-8a \end{gathered}[/tex]Then, we can write the equation as:
[tex]y=ax^2-8ax+c=a(x^2-8x)+c[/tex]If we replace the point (-5,-2) in the equation, we get:
[tex]\begin{gathered} -2=a((-5)^2-8\cdot(-5))+c \\ -2=a(25+40)+c \\ -2=65a+c \\ c=-2-65a \end{gathered}[/tex]We replace the vertex coordinates and get:
[tex]\begin{gathered} 6=a(4^2-8\cdot4)+c \\ 6=a(16-32)+(-2-65a) \\ 6=-16a-2-65a \\ 6=-81a-2 \\ 81a=-2-6 \\ a=-\frac{8}{81}\approx-0.01 \end{gathered}[/tex]Then, the linear coefficient b is:
[tex]b=-8a=-8\cdot(-\frac{8}{81})=\frac{64}{81}\approx0.79[/tex]And the constant term is:
[tex]c=-2-65a=-2-65\cdot(-\frac{8}{81})=-2+\frac{520}{81}=\frac{-162+520}{81}=\frac{358}{81}\approx4.42[/tex]The quadratic coefficient is a=-0.01
The linear coefficient is b=0.79
the constant term is c=4.42
Using the equation and the ordered-pairs found previously, plot the points on the graph that would best satisfy theequation.y= 2^x
Given the following equation:
[tex]y=x^2[/tex]We will graph the given function using the points that will be written in ordered-pairs.
The given function is a quadratic function with a vertex = (0, 0)
We will graph the points using five points
The vertex and 4 points, 2 points before the vertex and 2 points after the vertex.
So, we will substitute x = -4, -2, 2, 4
[tex]\begin{gathered} x=-4\rightarrow y=16 \\ x=-2\operatorname{\rightarrow}y=4 \\ x=2\operatorname{\rightarrow}y=4 \\ x=4\operatorname{\rightarrow}y=16 \end{gathered}[/tex]So, the points are: (-4, 16), (-2, 4), (0, 0), (2, 4), (4, 16)
The graph using the points will be as follows:
You have to write 1/2 page for an assignment. You write 1/5 page. How many pages do you have left to write ?
To find the number of missing pages:
[tex]\frac{1}{2}-\frac{1}{5}=[/tex]rewriting the expression as homogeneous fractions:
[tex]\frac{1}{2}\times\frac{5}{5}-\frac{1}{5}\times\frac{2}{2}=[/tex]simplifying it:
[tex]\frac{5}{10}-\frac{2}{10}=\frac{3}{10}[/tex]ANSWER
you have left 3/10 page.
Kirsten is driving to a city that is 400 miles away. When Kirsten left home, she had 15 gallons of gas in her car. Assume that her car gets 25 miles per gallon of gas. Define a function f so that f(x) is the amount of gas left in her car after she has driven x miles from home. What are intercepts for that function. What do they represent.
The equation that gives us the amount of gas left in her car, given the driven miles, is
[tex]f(x)=15-\frac{x}{25}[/tex]Notice that when x=25, there will remain 14 gallons of gas in the tank.
The x-intercept is
[tex]\begin{gathered} f(x)=0 \\ \Rightarrow0=15-\frac{x}{25} \\ \Rightarrow x=15\cdot25=375 \end{gathered}[/tex](375,0). This is the maximum distance one can drive when the amount of gas in the tank reaches zero gallons.
On the other hand, the y-intercept is
[tex]\begin{gathered} x=0 \\ \Rightarrow f(x)=15 \end{gathered}[/tex](0,15). This is the number of gallons in the tank when we have driven 0 miles.
a.a + 0 = 0Additive Identityb. Multiplicative IdentityCommutative Property of Additiond. Associative Property of AdditionC.
Answer:
a. Additive Identity
Explanation:
Given the equation:
[tex]a+0=a[/tex]When zero(0) is added to 'a', the result is still 'a'.
The number 0 is the additive identity of 'a'.
How do I find the gif and distributive property
By using the GCF and distributive property, the sum of 15+27 = 42
The expression is
15 + 27
GCF is the greatest common factor, the greatest common factor is the highest number that divides exactly into two or more numbers.
The distributive property states that multiplying the sum of two or more variables by a number will produce the same result as multiplying each variables individually by the number and then adding the products together.
The expression is
= 15 + 27
= 3(5 + 9)
= 3 × 14
= 42
Hence, by using the GCF and distributive property, the sum of 15 + 27 = 42
Learn more about distributive property here
brainly.com/question/5637942
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Write a quadratic function whose graph passes through (3,6) and has the vertex (-2,4) what is the value of Y
The representation of a quadratic eqauation in vertex form is
[tex]y=a(x-k)^2+h[/tex]The given vertex is,
[tex](k,h)=(-2,4)[/tex]And the given point through which the graph passes is,
[tex](x,y)=(3,6)[/tex]Substitute the values in the formula of quadratic equation.
[tex]\begin{gathered} 6=a(3-(-2))+4 \\ 6=a(3+2)+4 \\ 6=5a+4 \\ 5a=6-4 \\ 5a=2 \\ a=\frac{5}{2} \end{gathered}[/tex]Hence, the equation in vertex form will be,
[tex]\begin{gathered} y=\frac{5}{2}(x-(-2))+4 \\ y=\frac{5}{2}(x+2)+4 \end{gathered}[/tex]Please get help with us for I am confused as to have should draw the rotation after a 90° clockwise rotation
In the given figure we can observe a triangle with vertices located at:
(-3,-2)
(-5,-4)
(1,-5).
We need to draw it after a 90° clockwise rotation.
We can apply the rule for 90° clockwise rotation, which is:
Each point of the given figure has to be changed from (x, y) to (y, -x) and then we need to graph the new coordinates.
By applying the rule to the given coordinates we obtain:
[tex]\begin{gathered} (x,y)\to(y,-x) \\ (-3,-2)\to(-2,3) \\ (-5,-4)\to(-4,5) \\ (1,-5)\to(-5,-1) \end{gathered}[/tex]Now we have to draw the new coordinates:
What is the current population of elk at the park?
Given the following function:
[tex]\text{ f\lparen x\rparen= 1200\lparen0.8\rparen}^{\text{x}}[/tex]1200 represents the initial/current population of elk in the national park.
Therefore, the answer is CHOICE A.
Mark is roofing an old gymnasium that measures 270’x390’, and needs to calculate how many “squares “ he will need.(1 “square=100 ft square). The gym’s roof is a standard gable roof with 3’ of overhang on all sides. The roof angle measures 22.55 degrees from horizontal. How many squares of roofing does mark need ?
First, because of the roof having an inclination, we need to calculate the lenght of the surface we want to roof. The width will be the same.
Let's take a look at the situation:
Since we're on a right triangle, we can say that:
[tex]\cos (22.25)=\frac{G}{R}[/tex]Solving for R,
[tex]\begin{gathered} \cos (22.25)=\frac{G}{R}\rightarrow R\cos (22.25)=G \\ \\ \Rightarrow R=\frac{G}{\cos (22.25)} \end{gathered}[/tex]Since we already know that the lenght of the gym's floor is 390',
[tex]\begin{gathered} R=\frac{390^{\prime}}{\cos (22.25)} \\ \\ \Rightarrow R=421.38^{\prime} \end{gathered}[/tex]We get that the lenght of the surface we want to roof is 421.38'
Now, let's take a look at the surface we want to roof:
Since the roof is a standard gable roof with 3’ of overhang on all sides, we add 6' to each dimension:427
Our total roofing area would be:
[tex]427.38^{\prime}\cdot276^{\prime}=117956.88ft^2[/tex]We then divide this total area by the area of one of our "squares":
[tex]\frac{117956.88}{100}=1179.56[/tex]We round to the nearest integer from above, since we can't buy a fraction of a square.
(this is called ceiling a number)
[tex]1179.56\rightarrow1180[/tex]Therefore, we can conclude that Mark needs 1180 squares of roofing.
In exercises 1 and 2 , identify the bisector of ST then find ST
Given: The line segment ST as shown in the image
To Determine: The bisector of ST and the value of ST
Solution
It can be observed from the first image, the bisector of ST is line MW
[tex]\begin{gathered} ST=SM+MT \\ SM=MT(given) \\ MT=19(given) \\ Therefore \\ ST=19+19 \\ ST=38 \end{gathered}[/tex]For the second image, the bisector of ST is line LM
[tex]\begin{gathered} ST=SM+MT \\ SM=3x-6 \\ MT=x+8 \\ SM=MT(given) \\ Therefore \\ 3x-6=x+8 \\ 3x-x=8+6 \\ 2x=14 \\ x=\frac{14}{2} \\ x=7 \end{gathered}[/tex][tex]\begin{gathered} SM=3(7)-6=21-6=15 \\ MT=7+8=15 \\ ST=SM+MT \\ ST=15+15 \\ ST=30 \end{gathered}[/tex]For first exercise, the bisector is MW, ST = 38
For the second exercise, the bisector is LM, ST = 30r
Find the missing quantity with the information given. Round rates to the nearest whole percent and dollar amounts to the nearest cent% markdown = 40Reduced price = $144$ markdown = ?
The given information:
% mark up = 40
Reduced = $144
Markdown = ?
The formula for percentage markup is given as
[tex]\text{ \%markup }=\frac{markup}{actual\text{ price}}\times100[/tex]Let the actual price be x
Hence,
Reduced price = 60% of actual price
[tex]60\text{\% of x = 144}[/tex]Solving for x
[tex]\begin{gathered} \frac{60x}{100}=144 \\ x=\frac{144\times100}{60} \\ x=240 \end{gathered}[/tex]Therefore, actual price = $240
Inserting these values into the %markup formula gives
[tex]40=\frac{\text{markup}}{240}\times100[/tex]Solve for markup
[tex]\begin{gathered} 40=\frac{100\times\text{markup}}{240} \\ 40\times240=100\times\text{markup} \\ \text{markup}=\frac{40\times240}{100} \\ \text{markup}=96 \end{gathered}[/tex]Threefore, markup = $96
Could I assistance receive some on this question it’s very confusing
We need to translate the vertex F of triangle BDF. When we translate it 2 units to the left and 4 units down, we obtain the point F'.
We know that triangle BDF has vertices B(4,3), D(6,3), and F(6,1).
The first coordinate of each point represents its x-coordinate (the distance from the y-axis). And the second coordinate of each point represents its y-coordinate (the distance from the x-axis).
So, this triangle is shown below:
Now, we need to translate the point F 2 units to the left, to obtain the redpoint below. And then translate it 4 units down, to obtain F' (the yellow point):
Therefore, the F' has coordinates:
F'(4,-3)
how to get standar form from point 1,4 and a slope of 5
Radicals and Exponents Identify the choices that best completes the questions 3.
3.- Notice that:
[tex]\sqrt[]{12}=\sqrt[]{4\cdot3}=2\sqrt[]{3}\text{.}[/tex]Therefore, we can rewrite the given equation as follows:
[tex]2\sqrt[]{3}x-3\sqrt[]{3}x+5=4.[/tex]Adding like terms we get:
[tex]-\sqrt[]{3}x+5=4.[/tex]Subtracting 5 from the above equation we get:
[tex]\begin{gathered} -\sqrt[]{3}x+5-5=4-5, \\ -\sqrt[]{3}x=-1. \end{gathered}[/tex]Dividing the above equation by -√3 we get:
[tex]\begin{gathered} \frac{-\sqrt[]{3}x}{-\sqrt[]{3}}=\frac{-1}{-\sqrt[]{3}}, \\ x=\frac{1}{\sqrt[]{3}}\text{.} \end{gathered}[/tex]Finally, recall that:
[tex]\frac{1}{\sqrt[]{3}}=\frac{\sqrt[]{3}}{3}\text{.}[/tex]Therefore:
[tex]x=\frac{\sqrt[]{3}}{3}\text{.}[/tex]Answer: Option C.
1. Is this figure a polygon?2. Is this polygon concave or convex?3. Is this polygon regular, equiangular, Equilateral, or none of these?4. What is the name of this polygon?
A polygon is a closed shape with straigh sides, then
2. Is the figure a polygon? YES.
Since the figure is a polygon
1a. Is this polygon concave or convex? It is concave. A concave polygon will always have at least one reflex interior angle, tha is, it has on interior angle greater than 180 degrees.
1b. Is this polyogn regular, equiangular, equilateral or none of these? The marks on the picture mean that all the sides have the same length. This is the definition of equilateral. Then the answer is equilateral.
1c. What is the name of this polygon? We can see it has 4 equal sides and is concave, then his name is Concave Equilateral Quadrilateral.
Finding a specify term of a geometric sequence given the common ratio and first term
A geometric sequence is defined as:
[tex]\begin{gathered} a_1=a*r^0=a*r^{1-1}, \\ a_2=a*r^1=a*r^{2-1}, \\ a_3=a*r^2=a*r^{3-1}, \\ ... \\ a_7=a*r^6=a*r^{7-1}, \\ ... \end{gathered}[/tex]Where r ≠ 0 is the common ratio and a ≠ 0 is the first term of the sequence.
From the statement, we know that r = 2/3 and the first term is a = 5.
Replacing these numbers in the expression of the 7th term, we get:
[tex]a_7=5*(\frac{2}{3})^6=5*\frac{64}{729}=\frac{320}{729}.[/tex]Answer320/729
Find the length of AB given that DB is a median of the triangle AC is 46
ANSWER:
The value of AB is 23
STEP-BY-STEP EXPLANATION:
We know that AB is part of AC, and that DB cuts into two equal parts (half) since it is a median, therefore the value of AB would be
[tex]\begin{gathered} AB=\frac{AC}{2} \\ AB=\frac{46}{2} \\ AB=23 \end{gathered}[/tex]gus bought 2/3 pound of turkey and 1/4 pound of ham.The tukey cost 9 dollars per pound, and the ham cost 7 dollars per pound.In all,how much did Gus spend?
From the information given,
gus bought 2/3 pound of turkey. If tukey costs 9 dollars per pound, it means that the cost of 2/3 pound of turkey is
2/3 x 9 = 6
gus bought 1/4 pound of ham. If ham costs 7 dollars per pound, it means that the cost of 1/4 pound of ham is
1/4 x 7 = 7/4 = 1.75
Total amount spent = amount spent on turkey + amount spent on ham
Total amount = 6 + 1.75
Total amount = $7.75
THIS IS URGENT
A line includes the points (2,10) and (9,5). What is its equation in point-slope form?
Use one of the specified points in your equation. Write your answer using integers, proper fractions, and improper fractions. Simplify all fractions.
Answer:
Step-by-step explanation:
y = 13x -12
A man realizes he lost the detailed receipt from the store and only has the credit card receipt with theafter-tax total. If the after-tax total was $357.06, and the tax rate in the area is 8.2%, what was the pre-tax subtotal?
Answer: the pre-tax subtotal is $330
Explanation:
Let x represent the pre tax total
If the tax rate in the area is 8.2%, it means that the amount of tax paid is
8.2/100 * x = 0.082x
pretax total + tax = after tax subtotal
Given that after tax subtotal is $357.06, then
x + 0.082x = 357.06
1.082x = 357.06
x = 357.06/1.082
x = 330
the pre-tax subtotal is $330
May I please get help with this math. I have tried several times but still could not get the right answer
Given:
m∠3 = 63°
Let's find the m∠5 and m∠8.
• m∠5:
Angle 5 and angle 3 are alternate interior angles.
Alternate interior angles are angles formed on the opposite sides of the transversal.
To find the measure of angle 5, apply the Alternate Interior Angles theorem which states that when two parallel lines are cut by a transversal, the alternate interior angles are congruent.
The measure of angle 5 will also be 63 degrees.
Thus, we have:
m∠3 = m∠5 = 63°
m∠5 = 63°
• m∠8:
Angle 8 and angle 5 are linear pair of angles.
Angles that form a linear pair are supplementary.
Supplementary angles are angles that sum up to 180 degrees.
Thus, we have:
m∠8 + m∠5 = 180
m∠8 + 63 = 180
Subtract 63 from both sides:
m∠8 + 63 - 63 = 180 - 63
m∠8 = 117°
Therefore, the measure of angle 8 is 117 degrees.
ANSWER:
• m,∠,5 = 63°
,• m∠8 = 117°
V256 rational or irrational
First, in order to get to know if 256 it is a rational or irrational number we have to begin with the definition of what is rational and irrational number.
Rational numbers are all the number that can be represented as fractions, while the irrational numbers are all the numbers that can not be expressed as fractions.
In this case, then we can confirm that the number 256 can be considered as a rational number because it can be expressed as the quotient of the two integers: for example 256/1.
Wayne has a bag filled with coins. the bag contains 7 quarters,8 dimes,3 nickels, and 9 pennies. he randomly chooses a coins from the bag. what is the probability that Wayne chooses a quarter or nickel?
Wayne has a bag filled with coins.
Number of quarters = 7
Number of dimes = 8
Number of nickels = 3
Number of pennies = 9
So, the total number of coins is
Total = 7 + 8 + 3 + 9 = 27
What is the probability that Wayne chooses a quarter or nickel?
How many coins are either quarter or nickel?
quarter or nickel = 7 + 3 = 10
So, the probability is
[tex]P(quarter\: or\: nickel)=\frac{10}{27}[/tex]Therefore, the probability that Wayne chooses a quarter or nickel is 10/27
What is the simplified form of the expression square root of -64
What is the simplified form of the expression square root of -64
we have
[tex]\sqrt[]{-64}[/tex]Remember that
64=2^6
and
i^2=-1
substitute
[tex]\sqrt[]{-64}=\sqrt[]{(-1)(2^6)}=\sqrt[]{i^2\cdot2^6}=2^3i=8i[/tex]option BWrite an expression to show how much Gretchen paid for drama,action, and comedy videos if she paid $4 for each at a sale. Evaluate the expression
explanation
To determine how much Gretchen paid, we will have to list out the number of Video purchases made for drama, action, and comedy videos.
Let the Action videos be represented by A
Let the Comedy videos be represented by C
Let the Drama videos be represented by D
Also,
A has 3 purchases
C has 5 purchases
D has 2 purchases
Therefore, we will have the expression
[tex]3A+5C+2D[/tex]If she paid $4 for each, then
The total videos purchased = 3+5+2=10
Thus, the total amount paid will be
[tex]\begin{gathered} 10p \\ \text{where p is the price she paid for each video} \\ \text{Thus, } \\ \text{she paid} \\ 10(4)=\text{ \$40} \end{gathered}[/tex]Thus, Gretchen paid $40