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Related Questions
Determine if the two triangles shown are similar. If so, write the similarity statement.Question options:A) Impossible to determine.B) ΔBCG ∼ ΔEFGC) ΔGCB ∼ ΔGFED) The triangles are not similar.
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ANSWER
Option D: The triangles are not similar
STEP BY STEP EXPLANATION
Now, two (2) triangles are said to be similar if the three (3) angles of triangle A are congruent or equal to the corresponding three (3) angles of triangle B.
If you take a close look at the two (2) triangles, you will notice that the only angle in ∆BCG that is equal to the corresponding angles in ∆EFG is ∆BGC; the two (2) remaining angles in ∆BCG are not congruent with the two (2) corresponding angles in ∆EFG
Hence, it can be concluded that both triangles are not similar.
I need help with the problem!
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a)The vertex of the function is (3, -1)
b)The line of symmetry is x= 3
c) The maximum is no maximum and minimum is (3, -1)
a) What is the vertex of the function of the parabola ?
[tex]f(x) = x^{2} -6x+8[/tex]
Transforming the function in the vertex form,
[tex]f(x) = a(x-h)^{2} +k[/tex]
[tex]f(x)=(x-3)^{2} -1[/tex]
The vertex of the function is given by,
(h, k) = (3, -1)
So ,the vertex of the function of the parabola is (3, -1)
b) What is the line of symmetry in the function?
In a parabola , the axis of symmetry is x = h.
Here, x = 3
So, the line of symmetry of the function of the parabola is x= 3
c) What is the maximum and minimum?
There is no maximum for the function because, the parabola opens upward. (Refer image for graph)The minimum for the function is the vertex (h, k) = (3, -1)What is a function of a parabola?
A parabola is the shape of a quadratic function's graph. Although the width or steepness of a parabola can vary as well as its direction of opening, they share the same fundamental U form. Regarding a line known as the axis of symmetry, all parabolas are symmetric. The vertex of a parabola is the location where the axis of symmetry of the curve crosses.To learn more about function of a parabola , refer:
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What is the surface area of fish tank in the shape of a cube that has a volume of 90 cubic inches.
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You know that the volume of the fish tank in the shape of a cube:
[tex]V=90in^3[/tex]By definition, the formula for calculating the volume of a cube is:
[tex]V=a^3[/tex]Where "a" is the length of each edge of the cube.
If you solve for "a", you get this formula:
[tex]a=\sqrt[3]{V}[/tex]In this case, knowing the volume of the cube, you can substitute it into the second formula and evaluate, in order to find the length of each edge of the cube:
[tex]\begin{gathered} a=\sqrt[3]{90in^3} \\ \\ a\approx4.48in \end{gathered}[/tex]The surface area of a cube can be found using this formula:
[tex]SA=6a^2[/tex]Where "a" is the length of each edge of the cube.
Substituting the value of "a" into the formula and evaluating, you get:
[tex]SA=6(4.48in)^2\approx120in^2[/tex]Hence, the answer is: Second option.
determine if each expression is equivalent to [tex] \frac{ {7}^{6} }{ {7}^{3} } [/tex]
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The question says we are to check the options that are equal
[tex]\frac{7^6}{7^3}[/tex]Using the law of indices
[tex]\frac{7^6}{7^3}=7^{6-3\text{ }}=7^3[/tex]So we will check all the options(applying the laws of indices)
The first option is
[tex]7^9(7^{-6})=7^{9-6}=7^3[/tex]yes, the first option is equivalent
We will move on and check the second option
[tex]\frac{7^{-8}}{7^{-11}}\text{ = }7^{-8+11}=7^3[/tex]Yes the second option is equivalent
We will move on to check the third option
[tex](7^5)(7^3)divideby7^{4\text{ }}=7^{5+3-4\text{ }}=7^4[/tex]No the third option is not eqquivalent to the question
We will move to tthe next option, fourth option
[tex]7^{-3\text{ }}\times7^{6\text{ }}=7^{-3+6}=7^3[/tex]yes this option is equivalent to the fraction
Moving on to the fifth option
[tex](7^3)^{0\text{ }}=7^{3\times0}=7^0=\text{ 1}[/tex]No the fifth option is not equivalent to the question
Consider an investment whose return is normally distributed with a mean of 10% and a standard deviation of 5%. (2.4)
Justify which statistics methodology needs to be used in the above context and
a) Determine the probability of losing money.
b) Find the probability of losing money when the standard deviation is equal to 10%.
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a) The probability of losing money when standard deviation is 5% is 2.27%
b) The probability of losing money when standard deviation is 10% is 15.87%
Given,
There is an investment whose return is normally distributed.
The mean of the distribution = 10%
The standard deviation of the distribution = 5%
a) We have to determine the probability of losing money:
Lets take,
x = -0.005%
Now,
P(z ≤ (-10.005 / 5) ) = P(z ≤ - 2.001) = 0.02275
Now,
0.02275 × 100 = 2.27
That is,
The probability of losing money is 2.27%
b) We have to find the probability of losing money when the standard deviation is 10%
Let x be 0.01%
Now,
P(z ≤ (-10.01/10)) = P(z ≤ -1.001) = 0.15866
Now,
0.15866 × 100 = 15.87
That is,
The probability of losing money is 15.87%
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I need to make 500$ per week after tax in order to pay all my bills. The income tax is 20% What is the smallest pre-tax weekly salary I can earn and still be able to pay my bills after I pay my income tax?
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I must earn at least $625 (or more) per week before tax to pay my bills.
Given,
To make $500 per week after tax in order to pay all my bills.
and, The income tax is 20%
To find the smallest pre-tax weekly .
Now, According to the question:
Let x be the amount to earn pre - tax.
The income tax is 20% = 20/100 = 0.2
Set up an inequality:
x - 0.2x > = 500
0.8 > = 500
x >= 500/0.8
x >= 625
Hence, I must earn at least $625 (or more) per week before tax to pay my bills.
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For what value of x does 32x93x-4?oo 2o 3o 4
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Solution
[tex]3^{2x}=9^{3x-4}[/tex]We can do the following:
[tex]3^{2x}=3^{2(3x-4)}[/tex]And we have this:
[tex]2x=6x-8[/tex][tex]4x=8[/tex][tex]x=\frac{8}{4}=2[/tex]I need help with my pre-calculus homework, please show me how to solve them step by step if possible. The image of the problem is attached. The homework was a pdf so the choices can't expand, my teacher told me to just write the transformation of the given function in the format.
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Answer:
• Amplitude: 3
,• Period: π/2
,• Phase Shift: 1/8 (to the left)
,• Vertical Shift: -0.5
Explanation:
Given the trigonometric function:
[tex]y=3\sin (4x+\frac{1}{2})-0.5[/tex]Comparing with the form below:
[tex]\begin{gathered} y=A\sin (Bx-C)+D\text{ where:} \\ \text{Amplitude}=A \\ Period=\frac{2\pi}{B} \\ Phase\text{ Shift}=\frac{C}{B} \\ \text{Vertical Shift}=D \end{gathered}[/tex]Thus, we have that:
[tex]\begin{gathered} \text{Amplitude,}A=3 \\ Period,\frac{2\pi}{B}=\frac{2\pi}{4}=\frac{\pi}{2} \\ Phase\text{ Shift,}\frac{C}{B}=-\frac{1}{2}\div4=-\frac{1}{8} \\ \text{Vertical Shift, }D=-0.5 \end{gathered}[/tex]The phase shift, -1/8 indicates a shift to the left.
The maintenance department at the main campus of a large state university receives daily requests to replace fluorescent lightbulbs. The distribution of the number of daily requests is bell-shaped and has a mean of 42 and a standard deviation of 10. Using the 68-95-99.7 rule, what is the approximate percentage of lightbulb replacement requests numbering between 42 and 62.
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we are given
mean=42
Std=10
if the mean=42 + std =10 42+10=52
if the mean=42 - std=10 42-10=32
Rule -- 68-95-99.7
68% of the measures are within 1 standard deviation of the mean.
42+10=52
95% are within 2.
42+20=62
99.7% are within 3.
42+30=72
The normal distribution is symmetric, which means that 50% of the measures are above the mean and 50% are below.
we are ask for the porcentage of request between 42-62 (between the mean and 2+std)
62 is two standard deviations above the mean.
Of the 50% of the measures below the mean, 95% are between 42 and 62, so
0.95(50)=47.5
The approximate percentage of light bulb replacement requests numbering between 42 and 62 is of 47.5%
Suppose that $2000 is invested at a rate of 3.9%, compounded monthly. Assuming that no withdrawals are made, find the total amount after six years.Round your answer to the nearest cent.
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Compound interest formula:
[tex]\begin{gathered} A=P(1+\frac{r}{n})^{nt} \\ \\ A\colon\text{Amount} \\ P\colon\text{ Principal} \\ r\colon\text{ interest rate (in decimals)} \\ n\colon\text{ number of times interest is compounded in a year} \\ t\colon\text{ time (in years} \end{gathered}[/tex]Given data:
P= $2,000
r= 3,9% =0.039
n=monthly= 12
t= 6 years
[tex]\begin{gathered} A=2000(1+\frac{0.039}{12})^{12(6)} \\ \\ A=2000(1.00325)^{72} \\ \\ A\approx2526.33 \end{gathered}[/tex]Then, the total amount after six years is $
what number need to be changed to make a linear function? And what does it have to turn into?
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In order to have a linear function, the rate of change needs to be the same in each point
[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]For
(-18,2)=(x1,y1)
(-14,4)=(x2,y2)
[tex]m=\frac{4-2}{-14+18}=\frac{1}{2}[/tex]for
(-14,4)=(x1,y1)
(-12,5)=(x2,y2)
[tex]m=\frac{5-4}{-12+14}=\frac{1}{2}[/tex]for
(-12,5)=(x1,y1)
(0,12)=(x2,y2)
[tex]m=\frac{12-5}{0+12}=\frac{7}{12}[/tex]as we can see here are the two numbers so we will obtain the equation in order to know the number that needs to be change
[tex]y=\frac{1}{2}x+11[/tex]therefore if x=0
[tex]y=\frac{1}{2}(0)+11=11[/tex]the number we need to change is 12 and need to be changed for 11
(0,11)
a. The number that needs to be changed in order to create a linear function is 12
b. That number needs to be changed to 11 in order for the function to be linear
Find the AreaA. 314.2 IN2B. 1256.6 IN2C. 31.4 IN2D. 62.8 IN2
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Given:
Diameter = 20 in
Find-:
Area of circle
Explanation-:
The area of circle is:
[tex]A=\pi r^2[/tex]The radius of circle is:
[tex]r=\frac{D}{2}[/tex]Where,
[tex]\begin{gathered} r=\text{ Radius} \\ \\ D=\text{ Diameter} \end{gathered}[/tex]So the radius of given circle is:
[tex]\begin{gathered} D=20\text{ in} \\ \\ r=\frac{D}{2}\text{ in} \\ \\ r=\frac{20}{2}\text{ in} \\ \\ r=10\text{ in} \end{gathered}[/tex]The area of circle is:
[tex]\begin{gathered} A=\pi r^2 \\ \\ A=\pi(10)^2 \\ \\ A=100\pi \\ \\ A=314.159 \\ \\ A=314.2\text{ in}^2 \end{gathered}[/tex]So, the area of a circle is 314.2
need help asap look at attachment
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Answer: Width =14, Length = 18
Step-by-step explanation:
L = W + 4
2W + 2L = 64
W+ L = 32
2W+ 4 = 32
2W = 28
W = 14
Hello I'd like some help on my practice question I'd prefer if it's quick because I have other questions I need to solve thank you
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f(x) = -2
the answer is the second option
The horizontal line at y = -2 which is parallel to x-axis
You use substitution to solve a system of equations and after simplifying end with a statement that says 7=7 discrible what this statement means about the number of solutions and about the graph of the system
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Hence there are infinite solutions and the graphs of the system are concurrent.
If the system used straight lines then they would be on top of each other.
This is Calculus 1 Linear Optimization Problem! MUST SHOW ALL THE JUSTIFICATION!!!
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Given:
Required:
We need to find the value of AB
Explanation:
Here ABC is the right anglr triangle
so
[tex]\begin{gathered} AB^2=BC^2+AC^2=36+36=72 \\ AB=6\sqrt{2} \end{gathered}[/tex]Final answer:
The minimum length of crease is
[tex]6\sqrt{2}[/tex]Mike made $120 last week working d days. Express the amount he made each day in terms of d.
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Since he made $120 in d days
To find his earn in eac
Kaitlin races her bicycle for 98 m. A wheel of her bicycle turns 49 times as the bicycle travels this distance. What is the diameter of the wheel? Use the value 3.14 for n. Round your answer to the nearest tenth
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Answer:
0.6m
Explanation:
Given the following
Total distance covered = 98m
pi = 3.14
Circumference of the wheel is the distance travelled in one rotation. Hence;
distance travelled in one rotation = \pi d
d is the diamter of the wheel
distance travelled in 49 rotation = 49*\pi d
Since distance travelled in 49 rotation = 98m, then;
98 = 49*\pi d
Divide both sides by 49
98/49 = \pi d
2 = 3.14d
d = 2/3.14
d = 0.6m
Hence the diameter of the wheel is 0.6m
. In a 30°-60-90° triangle, the hypotenuse is 7 yards long.Find the exact lengths of the legs?
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ANSWER
The lengths of the legs of the triangle are 6.06 yards and 3.6 yards.
EXPLANATION
First, let us make a sketch of the problem:
To find the length of the legs, we have to apply trigonometric ratios SOHCAHTOA.
We have that:
[tex]\sin (60)=\frac{\text{opposite}}{\text{hypotenuse}}[/tex]From the diagram:
[tex]\begin{gathered} \sin (60)=\frac{x}{7} \\ \Rightarrow x=7\cdot\sin (60) \\ x\approx6.06\text{ yds} \end{gathered}[/tex]We also have that:
[tex]\sin (30)=\frac{\text{opposite}}{\text{hypotenuse}}[/tex]From the diagram:
[tex]\begin{gathered} \sin (30)=\frac{y}{7} \\ \Rightarrow y=7\cdot\sin (30) \\ y=3.5\text{ yds} \end{gathered}[/tex]The lengths of the legs of the triangle are 6.06 yards and 3.5 yards.
Solve each of the following equations. Show its set on a number line. |4x-4(x+1)|=4
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Solving this equation, we have:
[tex]\begin{gathered} |4x-4\mleft(x+1\mright)|=4 \\ |4x-4x-4|=4 \\ |-4|=4 \\ 4=4 \end{gathered}[/tex]Since the final sentence is always true, the solution set is all real numbers.
Showing it in the number line in blue, we have:
Apply the product rule to rewrite the product below using a single base and exponent then simplify: 3^2 *3^3 our base is Answerour exponent is Answerthis simplifies to Answer
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Explanation:
[tex]3^2\text{ }\times3^3[/tex][tex]\begin{gathered} \text{The expression has same base.} \\ \text{Base = 3} \\ We\text{ take one base and bring the exponents together} \\ \text{The sign betw}en\text{ them changes from multiplication to addition} \end{gathered}[/tex][tex]\begin{gathered} 3^2\text{ }\times3^3\text{ = }3^{2\text{ + 3}} \\ \text{Exponent = 2 + 3} \\ \text{Exponent = 5} \end{gathered}[/tex][tex]\begin{gathered} \text{Simplifying:} \\ 3^{2+3}=3^5 \\ 3^5\text{ = 243} \end{gathered}[/tex]10. A $152,000 home has an assessment rate of 52% and a tax rateof $48 per $1,000. Use the effective tax method to calculate theproperty tax .Hint: When you determine the effective tax rate, round the rateto three places.
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Given
$152,000
52% assessment rate
$48 per $1,000
Procedure
First, let's calculate the assessment rate.
[tex]152000\cdot0.52=79040.0[/tex]Now let's calculate the taxes
[tex]79040.0\cdot\frac{48}{1000}=3793.92[/tex]Property taxes are equal to $3,793.92.
Put these five fractions in order, left to right, from least to greatest. 1 /3 2 /7 3/10 4/13 5/17
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The five fractions can be arranged in order, from the left to right, from least to greatest as : 5/17 , 3/10 , 4/13 , 1 /3.
How can the fraction can be arranged from the from least to greatest?The fraction can be arranged from the from least to greatest by firstly convert the fraction to the decimal numbers so that one c b able to identify the highest and the lowest values.
The given fractions 1 /3 2 /7 3/10 4/13 5/17 can be converted to decimal numbers as 0.33 , 0.67 , 0.30 , 0.31 , 0.29 respectively and this can be arranged as 5/17 , 3/10 , 4/13 , 1 /3.
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divide fraction2*1/3 / 7*3/8 =
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Step-by-step explanation:
3.999 is the correct answer
use your theorem from 2-37 about the angles in a triangle to find in the diagram below. show all work.
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We have that, for any triangle, the sum of all its angles equals 180. In this case, we have the following:
[tex]96+2x+(x+12)=180[/tex]Now we solve for x to get the following:
[tex]\begin{gathered} 96+2x+x+12=180 \\ \Rightarrow2x+x=180-96-12 \\ \Rightarrow3x=72 \\ \Rightarrow x=\frac{72}{3}=24 \\ x=24 \end{gathered}[/tex]We have that x = 24, now to find the angles, we substitute this value on each expression:
[tex]\begin{gathered} 2x \\ x=24 \\ \Rightarrow2(24)=48 \\ x+12 \\ \Rightarrow24+12=36 \end{gathered}[/tex]therefore, the remaining angles are 48° and 36°
Create a quadratic function in one of the forms and show how to convert it to the other two forms.
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Create a quadratic function in one of the forms and show how to convert it to the other two forms.
Step-by-step explanation:
1) Standard form: y = ax2 + bx + c where the a,b, and c are just numbers.
[tex]y=ax^2+bx+c[/tex]2) Factored form: y = (ax + c)(bx + d) again the a,b,c, and d are just numbers.
[tex]y=(ax+c)(bx+d)[/tex]3) Vertex form: y = a(x + b)2 + c again the a, b, and c are just numbers.
[tex]y=a(x+b)^2+c[/tex]The vertex of the parabola is written as (h, k) where b is the x - coordinate and c - is the y - coordinate
10 ptQuestion 10A can of soup has a volume of 80 in and mass of 10 ounces. A can of tuna has a volume of 56 in and mass of 8ounces. About how much less is the density of the soup than the tuna (give your answer in ounces/square inch).Round your answer to the nearest 1000th.SOUPSTUNA CHUNKSBrineLENTIL0.0179 ounces per per square inches less0.1429 ounces per per square inches less0.1250 ounces per per square inches less0.0099 ounces per per square inches less
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We have that the general formula for the density given the volume and the mass is:
[tex]d=\frac{m}{v}[/tex]in this case, the densities for the can of soup and the can of tuna are:
[tex]\begin{gathered} d_{soup}=\frac{10}{80}=\frac{1}{8} \\ d_{tuna}=\frac{8}{56}=\frac{1}{7} \end{gathered}[/tex]the difference between these two densities is:
[tex]\frac{1}{7}-\frac{1}{8}=\frac{1}{56}=0.0179[/tex]therefore, there is 0.0179 less density of the soup than the tuna
The start of a quadratic
sequence is
8, 18, 30, 44, 60, …
What is the nth term rule for this sequence?
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Answer:
The correct option is D
98
The general term of the sequence is n(n+7)
8 = 1x8, 18 = 2x9, 30 = 3x10, 44 = 4x11, 60 = 5x12 … so in general T(n) = n(n + 7)
Or because the second differences are constant we know it uses squares
8 = 1^2 + 7, 18 = 2^2 + 14, 30 = 3^2 + 21, 44 = 4^2 + 28, 60 = 5^2 + 35 … so in general T(n) = n^2 + 7n
Triangle HJK has vertices at H(2, 2) J(2, 4) and K(0, 2). What is the midpoint of the longest side of the triangle?
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The coordinates of the vertices of triangle are given as H(2,2), (J(2, 4), K(0,2)
We would determine the longest side by applying the formula for finding the distance between two points which is expressed as
[tex]\begin{gathered} \text{Distance = }\sqrt[]{x2-x1)^2+(y2-y1)^2} \\ \text{For HJ, x1 = 2, y1 = 2, x2 = 2, y2 = 4} \\ \text{Distance = }\sqrt[]{(2-2)^2+(4-2)^2}\text{ = }\sqrt[]{2^2}\text{ = 2} \\ \text{For JK, x1 = 2, y1 = 4, x2 = 0, y2 = 2} \\ \text{Distance = }\sqrt[]{(0-2)^2+(2-4)^2}=\sqrt[]{(4+4)}=\text{ }2.83 \\ \text{For HK, x1 = 2, y1 = 2, x2 = 0, y2 = 2} \\ \text{Distance = }\sqrt[]{0-2)^2+(2-2)^2}=\text{ }\sqrt[]{4}\text{ = 2} \end{gathered}[/tex]Thus, the longest side is JK. The formula for finding midpoint is
Midpoint = (x1 + x2)/2, (y1 + y2)/2
Midpoint = (2 + 0)/2, (4 + 2)/2
Midpoint = 2/2, 6/2
Midpoint = 1, 3
Given the following function, find f(-3), f(0), and f (2) f(x)=5x-2
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The output values of f(-3), f(0) and f(2) of the function f( x ) = 5x - 2 are -17, -2 and 8 respectively.
What are the output values of f(-3), f(0) and f(2) in the given function?A function is simply a relationship that maps one input to one output.
Given the data in the question;
f( x ) = 5x - 2f( -3 ) = ?f( 0 ) = ?f( 2 ) = ?For f( - 3 );
To find the output value of f( -3 ), replace all the occurrence of x with -3 in the function and simplify.
f( x ) = 5x - 2
f( -3 ) = 5(-3) - 2
f( -3 ) = -15 - 2
f( -3 ) = -17
For f( 0 );
To find the output value of f( 0 ), replace all the occurrence of x with 0 in the function and simplify.
f( x ) = 5x - 2
f( 0 ) = 5(0) - 2
f( 0 ) = 0 - 2
f( 0 ) = -2
For f( 2 );
To find the output value of f( 2 ), replace all the occurrence of x with 2 in the function and simplify.
f( x ) = 5x - 2
f( 2 ) = 5(2) - 2
f( 2 ) = 10 - 2
f( 2 ) = 8
Therefore, the output value of f( 2 ) is 8, this forms an ordered pair of ( 2, 8 ).
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