Answer:
Explanation:
Standard International (SI) units of measurement is the acceptable global units of measure for physical quantities. they are majorly fundamental units.
Thus,
(a) The mass of a sport car is measured in kilograms (kg).
(b) The distance from your home to your school is measured in meters (m).
(c) The mass of an elephant is measured in kilograms (kg).
(d) The diameter of a large pizza is measure in meters (m).
(e) A semester at your school is measured in weeks.
(f) The time for light to travel from the sun to the earth is expressed in seconds (s).
(g) The time it takes to fly from New York to California is in seconds (s).
(h) Your mass is measured in kilograms (kg).
(i) The length of the Prime Meridian is expressed in meters (m).
(j) Your height is expressed in meters (m).
what is static electricity? explain how electrons are involved
please answer asap
Answer:
Electricity produced via friction is a development of electric charges on articles. Energizes construct when negative electrons are moved starting with one article then onto the next. The article that surrenders electrons turns out to be decidedly charged, and the item that acknowledges the electrons turns out to be contrarily charged. This can occur in a few different ways.
Explanation:
[tex]\mathrm {All, done!}[/tex]
While the boys were playing baseball, one of the boys decides to kick his soccer ball high into the air. As the ball goes upward, which type of energy is increasing?
A.) Kinetic Energy
B.) Thermal Energy
C.) Potential Energy
D.) Mechanical Energy
a ball is rolling ar 4.80m/s over level ground when it encounters a ramp which gives it an acceleration of -0.875m/s^{2. if the ramp is 0.750m long, what is the final velocity of the ball when it reaches the top of the ramp?
Answer:
4.66m/s
Explanation:
Given parameters:
Initial velocity = 4.8m/s
Acceleration = -0875m/s²
Length of the ramp = 0.75m
Unknown:
Final velocity = ?
Solution:
To solve this problem, we apply the right motion equation;
V² = U² + 2aS
V is the final velocity
U is the initial velocity
a is the acceleration
S is the distance = length of ramp
Insert the parameters;
V² = 4.8² + 2(-0.875)0.75
V² = 23.04 - 1.31
V² = 21.73
V = √21.73 = 4.66m/s
can somone pls help me??!! i’m very stuck
Answer:
graph b
Explanation:
graph a isnt constant
graph c is slower (less steep slope)
graph d is slowing down (starts high ends low)
My Lou Vee Air Car's propeller rotates, but it does not move the car forward. Can someone please help?? This is due on Monday!
Answer:
The force to get the plane moving, and to balance the friction so it does not stop, is provided by the propeller. However, the wheels provide the acceleration of the car.
Explanation:
How is the atomic mass of an atom determined?
Answer:
Atomic mass is defined as the number of protons and neutrons in an atom
Una curva de radio R = 75 [m] tiene un peralte hecho de tal forma que un auto andando a v1 = 35 [m/s] no derrape incluso con el piso congelado (sin roce). ¿Cuál es el coeficiente de roce estático mínimo necesario entre las ruedas y el pavimento para que, en un día seco y soleado, el auto no derrape cuando avanza a v2 = 118 [m/s]?
Answer:
053.
Explanation:
Given that the radius of curvature of the path, R = 75 m.
Speed of the car on that path , [tex]v_1 = 35 m/s[/tex]
The centripetal force,[tex]F_c[/tex] acting on the body having mass, m, when it moves with the velocity v on curved path having radiusR
Ris[tex]F_c = mv^2/R[/tex]
Gravitational force, [tex]F_g[/tex] = mg.
Let tha angle of superelevation is [tex]\theta.[/tex]
As the car does not skid even with zero friction, so
[tex]mg\sin\theta = (mv_1^2)/2 \cos\theta[/tex]
[tex]\Rightarrow \tan\theta = v_1^2/2g=\cdots(i)[/tex]
On sunny day, let the minimun static friction coefficient between the wheels and the pavement is [tex]\mu.[/tex]
As [tex]v_2[/tex] = 118 m/s is greater than v_so the car tends to skid in upper direction and the frictional
force,f, will acts is downward direction.
As there is no skidding, so
[tex]f+ mg\sin\theta= (m(v_2)^2)/R\cos\theta[/tex]
[tex]\Rightarrow f=(m(v_2)^2)/R\cos\theta - mg\sin\theta[/tex]
where [tex]f= \mu N.[/tex]
[tex]So, \mu = \frac {(m(v_2)^2)/R\cos\theta - mg\sin\theta}{N} \cdots(ii)[/tex]
Where N is the normal reaction can be determined by balancing the force in perpendicular direction of the plane.
[tex]N= mg\cos\theta+\frac {m(v_2)^2}{R}\sin\theta[/tex]
From equation (ii)
[tex]\mu = \frac {(m(v_2)^2)/R\cos\theta - mg\sin\theta}{mg\cos\theta+\frac {m(v_2)^2}{R}\sin\theta}[/tex]
[tex]=\frac{-g\tan\theta+v^2/R}{v_2^2\tan\theta+g}[/tex]
[tex]= \frac {(m(v_2)^2)/R\cos\theta - mg\sin\theta}{mg\cos\theta+\frac {m(v_2)^2}{R}\sin\theta}[/tex]
[tex]=\frac{-g(v_1^2/2g)+v^2/R}{v_2^2(v_1^2/2g)+g}[/tex]
[tex]= \frac{v_2^2/R-v_1^2/R}{g+v_2^2/R\times v_1^2/Rg}[/tex]
[tex]=\frac{118^2/75-35^2/75}{9.81+118^2/75\times 35^2/(75\times 9.81)}[/tex]
=0.53
Hence, the minimum coefficient of friction is 0.53.
why the gaps left between succesive rails on a railway tracks
Small gaps which function as expansion joints are deliberately left between the rail ends to allow for expansion of the rails in hot weather. ... Because of these small gaps, when trains pass over jointed tracks they make a "clickety-clack" sound.
Witch statement about electric force is true?
The place where potential energy is zero is
a) At height equal to double the radius of the earth
b) At infinity
c) At a height equal to half the radius of the earth
d) At a depth equal to 1/3 radius of the earth
Answer:
D. At a depth equal to 1/3 radius of the earth
Which object has the most momentum?
A) a mass of 100, kg with a velocity of 2.0 m/sec
B) a mass of 100 kg with a velocity of 32.0 m/sec
C) a mass of 15 kg with a velocity of 200. m/ sec
Which of the following statement(s) about electrical charges are correct?
A. Point charges of the same charge only attract.
B. Charged and neutral extended objects can attract.
C. Charged and neutral extended objects do not interact.
D. Point charges of the same charge only repel.
E. Extended objects of opposite charge can only attract.
F. Point charges of opposite charge only attract.
G. Point charges of opposite charge only repel.
H. Extended objects of the same charge can both repel and attract.
I. Extended objects of the same charge can only attract.
J. Extended objects of the same charge can only repel.
K. Extended objects of opposite charge can both repel and attract.
Answer:
The true statements are;
F, D, E, J
Explanation:
F and D are true because they agree with our knowledge of electrostatic interaction. Like charges repel while unlike charges attract. Statements B and C are not in line with the principles of electrostatics because neutral objects do not interact with charged bodies in an electric field.
E and J are true for the same reasons outlined above. Remember that like charges always repel each other and unlike charges always attract each other.
if a truck goes 30 kilometers in 30 minutes what is the average speed
Answer:
60 km per hour
Explanation:
if you drive for 30 min and go 30km then if you drive for 60 min(1hr) then you would have driven 60km.
Answer:
60
Explanation:
hope this helps
A group of students is making paper airplanes. They think that the kind of paper and the design of the airplane may affect how for each paper airplane fles. The students first test if the kind of paper affects how far the
airplane fies. They make
several otrplanes out of different kinds of paper, using
the same design Why is it important that all the airplanes have the same design?
Help please !!
Answer:
The reason why it is important that all the airplanes have the same design is that the students first test is an experiment to determine the effect of the paper kind on the distance the airplane flies
The first experiment, therefore measures the effect of the independent variable, which is the kind of paper on the dependent variable, which is how far the paper flies
The constant or the factor held constant in the experiment is the design of the airplane, so as to ensure that changes in the distance flown by the airplane are due to the changes in the kind of paper alone
Explanation:
In which case would electrical potential energy be built up and stored in the electric field?
a) A positive charge is moved toward a negative charge.
b) A positive charge is moved toward a positive charge.
c) A negative charge is moved away from a negative charge.
d) none of the above.
Thank you!
Answer: b) A positive charge is moved toward a positive charge.
Which material rises from cracks in oceanic crust?
Answer:
trenchs and magma
Explanation:
Answer: Ridges form along cracks (divergent boundaries) in the oceanic crust (Molten rock (magma) rises through these cracks and pushes to both sides. When it cools, it forms new oceanic crust. The old crust is pushed away and new crust takes over. This is called Sea-Floor Spreading.
1. A pendulum is 0.25 m long. What is the frequency of its oscillations?
How do you solve this
Answer:
hi
Explanation:
hi
Which procedure would best demonstrate that moving magnet causes an electric current to flow in a wire coil?
Answer:
D
Explanation:
I took the test
The procedure that would best demonstrate that moving magnet causes an electric current to flow in a wire coil is connect a wire coil to an ammeter. Move a bar magnet into and out of the wire coil as you observe the ammeter. The correct option is D.
What is electric current?The flow of electricity in an electronic circuit, as well as the amount of electricity flowing through a circuit, are referred to as electric current. It is expressed in amperes (A).
The greater the value in amperes, the more electricity flows through the circuit.
When an electron is introduced into a wire, a free electron is attracted to a proton in order to be neutral.
Forcing electrons out of their orbits can result in an electron shortage. Electric current is the continuous movement of electrons in a wire.
Connecting a wire coil to an ammeter is the best way to demonstrate that a moving magnet causes an electric current to flow in a wire coil. As you watch the ammeter, move a bar magnet in and out of the wire coil.
Thus, the correct option is D.
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A ball is released from a hot air balloon moving downward with a velocity of
-10.0 meters/second and a height of 1,000 meters. How long did it take the ball to reach the surface of Earth? Given: g = -9.8 meters/second2.
A
11.2 seconds
B.
12.1 seconds
C.
13.3 seconds
D.
13.5 seconds
E.
14.2 seconds
During a laboratory experiment, the temperature of the gas in a balloon is varied and the
volume of the balloon is measured.
A)
Which quantity is the independent variable?
B)
Which quantity is the dependent variable?
A ball weighing 2.0 N falls through a distance of 4 m.
Answer:
This question is incomplete, a possible question would be to calculate the work done by the ball.
Work done = 8J
Explanation:
Work done by an object is calculated my multiplying the force by the distance.
The weight of this ball is 2.0N, which also represents the force exerted by the ball. The ball travels through a distance of 4m
Hence, work done = F × d
Work done = 2N × 4m
Work done = 8Nm or 8J
Just wondering, what do you guys think the 5th dimension is? I've always believed it to be light.
Answer: In the 5th dimension, they who claim to know, say that there is only one time, including the past and the future.
Two children are spinning on a miracle round. What is 50 cm from the center and the other is 100 cm from the center. Which child has the larger linear speed?
Answer:
The one that is 100 cm from the center.
Explanation:
Given that merry-go-round means moving at uniform circular motion or constant angular speed. Hence the person who is closer to the center is moving at a slower speed, while the one far away from the center has a larger linear speed because he has moved a long distance in the same amount of time, despite being on these objects.
To illustrate
A with the 50 cm
B with the 100 cm
Hence, to get speed, we have
A = 2 * pi * 50 / T
B = 2 * pi * 100 / T
And by the explanation of angular speed
We have w = 2*pi/T where w is the angular speed in radians/s
Hence we have
A = 50w
B = 100w
Therefore, the one that is 100 cm from the center has a larger linear speed.
1. Discuss how we use trial and error, algorithms, heuristics, and insight to solve problems. For each concept, define the term and then describe an incident (either from your own experience or that of a friend) in which the concept was used to determine a solution to a specific problem. You must use specific details of the incident and terms from our module to show me you understand the concept. (Total 64 points)
2., How can confirmation bias and fixation can interfere with effective problem solving. In this portion of your response, for each concept, define the term and then describe an incident (either from your own experience or that of a friend) in which the concept interfered with an appropriate solution being determined. You must use specific details of the incident and terms from our module to show me you understand the concept. (Total 32 pts).
Answer: used concepts to simplify and order the world around us, categories: objects, events, ideas, or people
hierarchies: subdivide categories into smaller more detailed units, prototypes: best example
algorithm: time-consuming but thorough set of rules or procedures
heuristics: simpler way of thinking, solve problems but maybe incorrect solutions
insight: flash of inspiration that solves problem
representativeness heuristic: judge likelihood of things in terms of how they represent our prototype
availability heuristic: judge likelihood of things based on how vivid they are or how readily they come to mind.
Explanation: i hope that helped!
Why is the Earth generally warmer at the equator than at the poles?
Answer: The Sun's energy is more concentrated on the equator than the poles. This is because the Sun's energy (in the form of warmth) is more direct at the equator, and less direct at the poles.
Explanation: You can see this with a flashlight. When you point the flashlight directly toward a tale, the light is very concentrated and right. However, when you point the flashlight toward the table at an angle, the light becomes more spread out and less concentrated. This is why even though sometimes the North Poles and South Poles have 24 hours of sunlight, it never actually reaches a high temperature and instead, keeps it's cold temperature.
PLEASE
HELP!!!
Jacob and Matthew are pulling a 20 kg box filled with chocolate along the ground, while Savannah is trying to pull it back in the other direction. Jacob is pulling with 50 N, Matthew with 40 N, and Savannah is pulling with 60 N in a negative direction. Draw an FBD; it should have 5 forces on it. Find the net Force. Then calculate the acceleration of the box. Lastly, calculate the acceleration if Mathew decides to run for his life and stop pulling.
Explanation:
N/B: Please see attached a rough sketch of the free body diagram for your reference.
From the diagram, the weight W is acting downward and the resultant R is in the positive direction
Given data
mass m=20kg
Forces
Jacob is pulling with 50 N,
Matthew with 40 N, and
Savannah is pulling with 60 N in a negative direction
Required
The net force
Net force= 50+40-(60)
=90-60
=30N in the possitive direction(in Jacob and Mathew's direction)
we know that F=ma
a=F/m
a= 30/20
a=1.5m/s^2
if Mathew decides to run for his life and stop pulling the net force will be
Net force=50-60=-10N (in Savannah's direction)
a=F/m
a=10/20
a=0.5m/s^2
1. A ball is thrown straight up.if the launch velocity is 15 m/s, at what velocity will the ball return to the thrower's hand?
2. A boat moves across a river going 18 m/s. At the same time there is a current flowing at a right angle to the boat at 6 m/s. What is the resulting velocity of the boat?
Answer:
1) The velocity of the ball return to the thrower's hand is -15 meters per second.
2) The resulting velocity of the boat is [tex]\vec v_{B} = 6\,\hat{i}+18\,\hat{j}\,\left[\frac{m}{s} \right][/tex].
Explanation:
1) Let suppose that ball experiments a free fall, that is an uniform accelerated motion, in which effects from gravity and Earth's rotation can be neglected. The velocity of the ball is represented by the following equations of motion:
Position
[tex]v_{o}\cdot t -\frac{1}{2}\cdot g\cdot t^{2} = 0[/tex]
[tex]t\cdot \left(v_{o}-\frac{1}{2}\cdot g\cdot t \right) = 0[/tex] (1)
Velocity
[tex]v = v_{o}-g\cdot t[/tex] (2)
Where:
[tex]t[/tex] - Time, measured in seconds.
[tex]g[/tex] - Gravitational acceleration, measured in meters per square second.
[tex]v_{o}[/tex] - Initial velocity of the ball, measured in meters per second.
[tex]v[/tex] - Final velocity of the ball, measured in meters per second.
From (1), we get the time when the ball returns to the thrower's hand:
[tex]v_{o}-\frac{1}{2}\cdot g\cdot t = 0[/tex]
[tex]t = \frac{2\cdot v_{o}}{g}[/tex]
And then we apply this result in (2):
[tex]v = v_{o}-g\cdot \left(\frac{2\cdot v_{o}}{g} \right)[/tex]
[tex]v = -v_{o}[/tex] (3)
Then, the velocity of the ball return to the thrower's hand is -15 meters per second.
2) The resulting velocity of the boat ([tex]\vec v_{B}[/tex]) is represented by the vectorial sum of the velocity of the boat relative to the river ([tex]\vec v_{B/R}[/tex]) and the velocity of the river ([tex]\vec v_{R}[/tex]), both measured in meters per second, that is:
[tex]\vec v_{B} = \vec v_{R}+\vec {v}_{B/R}[/tex] (4)
If we know that [tex]\vec v_{R} = 6\,\hat{i}\,\left[\frac{m}{s} \right][/tex] and [tex]\vec v_{B/R} = 18\,\hat{j}\,\left[\frac{m}{s} \right][/tex], then the resulting velocity of the boat is:
[tex]\vec v_{B} = 6\,\hat{i}+18\,\hat{j}\,\left[\frac{m}{s} \right][/tex]
The resulting velocity of the boat is [tex]\vec v_{B} = 6\,\hat{i}+18\,\hat{j}\,\left[\frac{m}{s} \right][/tex].
What is the weight of a 500g ball? (gravity is 9.8 m/s)
Answer:
4,900
Explanation:
you find the weight by multiplying the ball in grams to the gravity
The weight or force due to gravity of a 500 g ball is 4.9 N.
What is force?A force is an effect that can alter an object's motion according to physics. An object with mass can change its velocity, or accelerate, as a result of a force. An obvious way to describe force is as a push or a pull. A force is a vector quantity since it has both magnitude and direction.
Given in the question a 500 g ball,
Weight = mass.gravity
Weight = .5*9.8
Weight = 4.9 N
The weight or force due to gravity of a 500 g ball is 4.9 N.
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1. A motorcycle stunt driver rides his motorcycle off a small ledge
that is 8.4 meters high. His initial velocity as he rides off the cliff is
24 m/s in the horizontal direction.
a. How long does it take before he lands on the ground below?
b. How far away from the base of the cliff does he travel while in
the air?
Answer:
Explanation:
Given
Height S = 8.4m
Initial velocity u = 24m/s
Required
Time it will take to reach the ground
Using the equation of motion
S = ut +1/2gt²
8.4 = 24t + 1/2(9.8)t²
8.4 = 24t+4.9t²
4.9t²+24t - 8.4 = 0
Multiply through by 10
49t²+240t-84 = 0
Factorize
t = -240±√240²-4(49(-84)/2(49)
t = -240±√57600+16464/98
t = -240±√74064/98
t = -240±272.15/98
t = 32.15/98
t = 0.328seconds
Hence it takes 0.328seconds before it lands on the ground below.
b) The horizontal distance is the range expressed as;
R = u²/g
R = 27²/9.8
R = 729/9.8.
R = 74.39m
a. The time it took before the motorcycle stunt driver lands on the ground below is 1.31 seconds.
b. The distance from the base of the cliff that the motorcycle stunt driver traveled while in the air is 31.44 meters.
Given the following data:
Maximum height = 8.4 meters.Initial velocity = 24 m/s.We know that the acceleration due to gravity (g) of an object on planet Earth is equal to 9.8 [tex]m/s^2[/tex]
a. To determine how long (time) it took before the motorcycle stunt driver lands on the ground below:
At maximum height, time is given by the formula:
[tex]Time = \sqrt{\frac{2H}{g} }[/tex]
Where:
g is the acceleration due to gravity.H is the maximum height.Substituting the given parameters into the formula, we have;
[tex]Time = \sqrt{\frac{2\times 8.4}{9.8} }\\\\Time = \sqrt{\frac{16.8}{9.8} }\\\\Time =\sqrt{1.7413}[/tex]
Time = 1.31 seconds.
b. To determine how far (distance) away from the base of the cliff the motorcycle stunt driver traveled while in the air:
[tex]Horizontal\;distance = horizontal\;speed \times time\\\\Horizontal\;distance = 24 \times 1.31[/tex]
Horizontal distance = 31.44 meters.
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function Of The glottis
Answer:
Their function is to produce sound by allowing the free edges of the folds to vibrate against one another and also to act as the laryngeal sphincter when they are closed.