The largest centric load P that can be applied is 67.2 kN.
To determine the largest centric load P that can be applied, we need to analyze the stress distribution in the glued scarf splice. The maximum allowable stresses given are 400 kPa in tension and 600 kPa in shear.
First, let's calculate the tensile stress in the splice perpendicular to the joint (tension stress):
σ_tension = P / (2 * t * b) [Formula for tensile stress in a rectangular cross-section]
Here, t = thickness of the members, and b = width of the members.
Next, let's calculate the shear stress in the splice parallel to the joint (shear stress):
τ_shear = P / (2 * t * h) [Formula for shear stress in a rectangular cross-section]
Here, h = height of the members.
We can use Mohr's circle to determine the combined stress at the point where maximum stress occurs. This is given by:
σ_max = (σ_tension + σ_shear) / 2 + √[((σ_tension - σ_shear)/2)^2 + τ_shear^2]
The largest centric load P that can be applied is obtained when the combined stress σ_max is equal to the maximum allowable stress in tension (400 kPa):
P = σ_max * (2 * t * b)
By substituting the given values into the calculations, we can determine the largest centric load P.
The largest centric load that can be applied is 67.2 kN, considering the maximum allowable stresses in the joint and using Mohr's circle to analyze the stress distribution.
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when a light wave passes through a calcite crystal, two waves are formed. the amount of light bending for an extraordinary wave depends on the .
the amount of light bending for an extraordinary wave passing through a calcite crystal depends on the orientation of the crystal. To give you a more long answer, calcite crystals are anisotropic, meaning that they have different physical properties in different directions.
When a light wave enters a calcite crystal, it is split into two waves, an ordinary wave that follows Snell's law of refraction, and an extraordinary wave that does not follow Snell's law. The amount of bending that the extraordinary wave experiences depends on the orientation of the crystal, as well as the wavelength and polarization of the light.
When light passes through a calcite crystal, it experiences a phenomenon called birefringence, which causes the light wave to split into two separate waves: an ordinary wave and an extraordinary wave. The amount of light bending, or refraction, for the extraordinary wave depends on the crystal's refractive index. This refractive index is a measure of how much the speed of light is reduced when it travels through the crystal, which in turn determines the angle at which the light bends. In calcite crystals, the refractive index varies with the polarization and direction of the light wave, causing the extraordinary wave to experience a different amount of bending compared to the ordinary wave
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if he had replaced the lead spheres with copper spheres of equal mass, his value of g would have been
If the lead spheres were replaced with copper spheres of equal mass, the value of g would not be affected. This is because the value of g is dependent on the mass of the Earth and the distance between the object and the Earth's center. The mass and composition of the object being measured do not affect the value of g. Therefore, whether the spheres were made of lead or copper, the value of g would remain constant. However, the experiment may have different results due to differences in the density and physical properties of the two metals, which could affect the accuracy and precision of the measurements taken.
If the lead spheres were replaced with copper spheres of equal mass, the value of g would remain the same. Here's a step-by-step explanation:
1. In the experiment, two spheres with equal masses are used to measure the gravitational force between them.
2. The gravitational force (F) depends on the mass of the objects (m1 and m2) and the distance between their centers (r) according to the formula: F = G * (m1 * m2) / r^2, where G is the gravitational constant.
3. If you replace the lead spheres with copper spheres of equal mass, the masses (m1 and m2) remain the same in the formula.
4. Since the mass and distance between the spheres have not changed, the gravitational force (F) remains the same as well.
5. The value of g (acceleration due to gravity) is calculated using the formula: g = F / m, where m is the mass of the object experiencing the gravitational force.
6. Since the gravitational force (F) and mass (m) have not changed, the value of g will remain the same even if the material of the spheres is changed from lead to copper, as long as their masses are equal.
In summary, replacing lead spheres with copper spheres of equal mass in an experiment to measure the gravitational constant (g) would not change the value of g.
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question 5: kinetic energy of a two-bar linkage two uniform rigid rods are connected with pin joints at and as shown, and they have masses, positions, and angular velocities given by:
The kinetic energy of a two-bar linkage can be determined by analyzing the motion of the two uniform rigid rods connected by pin joints. The masses, positions, and angular velocities of the rods are also taken into consideration.
In this case, we have two uniform rigid rods connected by pin joints. The kinetic energy (KE) of such a system can be calculated by considering the individual kinetic energies of each rod, which are determined by their masses, positions, and angular velocities.
For each rod, the kinetic energy can be calculated using the formula KE = 1/2 * I * ω², where I is the moment of inertia and ω is the angular velocity. The moment of inertia depends on the mass and the length of the rod.
For the two-bar linkage system, the total kinetic energy is the sum of the kinetic energies of both rods. By calculating and adding the kinetic energies of each rod based on their given masses, positions, and angular velocities, you can find the overall kinetic energy of the two-bar linkage system.
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A 2.0 kg block is attached to a spring of spring constant 72 N/m. The block is released from x=1.5 m. What's the potential energy of the block as it passes through the equilibrium position? a 140J b. 110J C.81J d.0
The potential energy of the 2.0 kg block as it passes through the equilibrium position is 0 J (Option d).
The potential energy of the block at its maximum displacement from the equilibrium position is given by the formula U = 1/2 kx^2, where k is the spring constant and x is the displacement. At the maximum displacement, x=1.5m, so the potential energy is U = 1/2 (72 N/m) (1.5m)^2 = 81J.
The potential energy of a block attached to a spring can be calculated using the formula PE = (1/2)kx^2, where PE is the potential energy, k is the spring constant, and x is the displacement from the equilibrium position.
When the block passes through the equilibrium position, the displacement x becomes 0, since the block is at its resting position. Therefore, the potential energy at this point is:
PE = (1/2)(72 N/m)(0 m)^2 = 0 J.
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A bag weighing 20 newtons is lifted 2 meters onto a shelf. How much work has been done?
The work done in lifting the bag onto the shelf by 2 meters is 40 Newtons.
Given: Force required to lift the bag onto a shelf(F)= 20 Newton
Displacement(d)= 2 meters
The work done by a force is defined to be the product of the component of the force in the direction of the displacement and the magnitude of this displacement.
W= F.dr cosФ = F.d
Where W is the work done, F is the force, d is the displacement, θ is the angle between force and displacement and F cosФ is the component of force in the direction of displacement.
Ф - the angle between the applied force and the direction of the motion
A force is said to do positive work if when applied it has a component in the direction of the displacement of the point of application. A force does negative work if it has a component opposite to the direction of the displacement at the point of application of the force.
Putting all the values in the formula,
W= F.d cosФ
cosФ=1, as force is acting vertically upwards in the direction of motion
W= 20×2×1
W= 40 Newtons
Therefore, The work done in lifting the bag onto the shelf by 2 meters is 40 Newtons.
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for two resistors with resistances of 10 ω and 23.7 ω, what is the equivalent resistance if they are: connected in parallel?
When two resistors are connected in parallel, the equivalent resistance (R_eq) can be calculated using the formula: 1/R_eq = 1/R_1 + 1/R_2
where R_1 and R_2 are the resistances of the individual resistors.
In this case, the resistances of the two resistors are given as 10 Ω and 23.7 Ω.
Using the formula, we can calculate the equivalent resistance:
1/R_eq = 1/10 Ω + 1/23.7 Ω
To combine the fractions, we find the common denominator:
1/R_eq = (23.7 + 10) / (10 * 23.7) Ω
1/R_eq = 33.7 / 237 Ω
To find R_eq, we take the reciprocal of both sides:
R_eq = 237 Ω / 33.7
R_eq ≈ 7.03 Ω
Therefore, when the two resistors with resistances of 10 Ω and 23.7 Ω are connected in parallel, the equivalent resistance is approximately 7.03 Ω.
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.Which of the following describes a difference in the behavior of an electrically conducting sphere and that of an insulating sphere?
A conducting sphere can be charged by friction, but an insulating sphere cannot.
An uncharged object can be charged by touching it to a charged conducting sphere, but not by touching it to a charged insulating sphere.
When a conducting sphere is brought near a positively charged object, some of the sphere’s electrons move closer to that object. No polarization occurs in the atoms of an insulating sphere.
Excess charge placed on a conducting sphere becomes distributed over the entire surface of the sphere. Excess charge placed on an insulating sphere can remain where it is placed.
There are several differences in behavior between an electrically conducting sphere and an insulating sphere.
Firstly, a conducting sphere can be charged by friction, whereas an insulating sphere cannot. This is because the conducting sphere allows electrons.
Secondly, an uncharged object can be charged by touching it to a charged conducting sphere, but not by touching it to a charged insulating sphere. This is because the conducting sphere allows charge to flow easily between objects, while an insulating sphere does not.
Excess charge placed on a conducting sphere becomes distributed over the entire surface of the sphere. Excess charge placed on an insulating sphere can remain where it is placed. conducting spheres have mobile electrons that can move freely, allowing the charge to distribute evenly over the surface Insulating spheres have electrons that are not as mobile, which means the charge cannot move as freely and tends to remain where it was placed. the fact that polarization occurs in conducting spheres when brought near a charged object, while insulating spheres do not experience this effect.
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Reverberation time of a room can be increased by covering the walls with better reflectors of sound. True or False
False. Reverberation time of a room can be increased by adding sound-absorbing materials to the walls, such as acoustic panels or curtains. These materials reduce the reflection of sound waves, thus reducing the overall reverberation time in the room.
Reverberation time refers to the duration it takes for sound to decay in a room after the sound source stops. It is a measure of how long sound lingers in the room before it fades away. In rooms with longer reverberation times, sound reflections bounce off the walls, ceiling, and other surfaces multiple times, creating a prolonged and sustained sound.
When the walls of a room are covered with sound-absorbing materials, such as acoustic panels or curtains, these materials absorb a significant portion of the sound energy instead of reflecting it back into the room. As a result, the sound waves lose their energy more quickly, reducing the overall reverberation time.
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Which of the following sets of two charges is experiencing the strongest
attraction?
Charges of +2 C and -2 C, separated by 1 m.
Charges of +1 C and -3 C, separated by 1 m.
Charges of +2 C and +2 C, separated by 1 m.
Charges of +1 C and +3 C, separated by 1 m.
The set of two charges experiencing the strongest attraction is charges of +2 C and -2 C, separated by 1 m. Option A.
How to identify the two charges experiencing the strongest attraction?+2 C and -2 C is an attracting force because the charges are opposite
For Charges of +2 C and -2 C the force of attraction between two charges is directly proportinal to the product of their charges and inversely proportional to the square of the distnce between them.
The product of the charges is 2 × -2 = -4 C², and the square of the distance between them is 1² = 1 m².
The force of attraction between these two charges is -4 / 1 = -4 N.
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For the curve defined by r(t) = (e-t, 2t, et) = find the unit tangent vector, unit normal vector, normal acceleration, and tangential acceleration at t T(t) = Ñ(t) = ат aN = 2.
The unit tangent vector T(t) for the curve defined by r(t) = (e², 2t, e) at t = 2 is [tex]\[T(2) = \left(\frac{e^2}{\sqrt{e^4 + 16 + e^2}}, 4, e\right)\][/tex]. The unit normal vector N(t) for the curve at [tex]\[N(2) = \left(\frac{-2e^2}{\sqrt{4e^4 + 1}}, 1, 0\right)\][/tex].
The normal acceleration ar at [tex]\[ar(2) = \frac{\sqrt{4e^4 + 1}}{\sqrt{e^4 + 16 + e^2}}\][/tex]. The tangential acceleration at t = 2 is aT(2) = 0 since the curve is defined as a straight line and has no curvature.
Determine how to find the tangent vector?To find the unit tangent vector T(t), we take the derivative of the position vector r(t) with respect to t and normalize it by dividing by its magnitude. The derivative of [tex]\[T(t) = \frac{(e^2, 4, e)}{\sqrt{e^4 + 16 + e^2}}\][/tex].
To find the unit normal vector N(t), we differentiate T(t) with respect to t and normalize the resulting vector. The derivative of T(t) is (0, 0, 0), which means the curve is a straight line. Therefore, N(t) is constant and given by [tex]\[N(t) = \frac{(-2e^2, 1, 0)}{\sqrt{4e^4 + 1}}\][/tex].
The normal acceleration ar at t = 2 is the magnitude of the derivative of T(t) with respect to t, which simplifies to [tex]\[\frac{\sqrt{4e^4 + 1}}{\sqrt{e^4 + 16 + e^2}}\][/tex].
Since the curve is a straight line, there is no change in the direction of the velocity vector, and therefore, the tangential acceleration aT is zero.
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air modeled as an ideal gas enters a well-insulated diffuser operating at steady state at 270 k with a velocity of 180 m/s and exits with a velocity of 48.4 m/s. assume negligible potential energy effects. ideal gas constant for air: r
The ideal gas constant for air, denoted as R, has a value of 287 J/(kg·K). It is a constant used in gas laws to relate the properties of air to temperature, pressure, and volume.
Determine the air is modeled?In this problem, air is modeled as an ideal gas. We are given the following information:
- Inlet conditions: Temperature (T₁) = 270 K, Velocity (V₁) = 180 m/s
- Outlet conditions: Velocity (V₂) = 48.4 m/s
Since the diffuser is well-insulated, we can assume negligible heat transfer (Q) and potential energy effects. Therefore, the process can be considered adiabatic and isentropic.
In an adiabatic and isentropic process, the total energy per unit mass remains constant. Therefore, we can use the stagnation properties (denoted by a subscript "0") to analyze the process.
The stagnation temperature (T₀) is the temperature that the gas would reach if it were brought to rest isentropically. The stagnation temperature is related to the static temperature and velocity by the equation: T₀ = T + (V² / (2·Cp)), where Cp is the specific heat at constant pressure.
Since the process is isentropic, the ratio of specific heats (γ) remains constant. For air, γ ≈ 1.4.
Using the stagnation temperature equation, we can calculate the stagnation temperature at the inlet and outlet:
T₀₁ = T₁ + (V₁² / (2·Cp))
T₀₂ = T₂ + (V₂² / (2·Cp))
Since the process is adiabatic, the stagnation temperature remains constant throughout the diffuser: T₀₁ = T₀₂
By equating the expressions for T₀₁ and T₀₂ and rearranging the terms, we can solve for Cp:
T₁ + (V₁² / (2·Cp)) = T₂ + (V₂² / (2·Cp))
Simplifying the equation and solving for Cp, we get:
Cp = (V₁² - V₂²) / (2·(T₂ - T₁))
Finally, using the ideal gas equation: Cp - Cv = R, where Cv is the specific heat at constant volume, and Cp = γ·Cv, we can substitute Cp with γ·Cv and rearrange the equation to solve for R:
R = Cp - Cv
R = γ·Cv - Cv
R = (γ - 1)·Cv
For air, the value of γ is approximately 1.4. Therefore, we can calculate R as follows:
R = (1.4 - 1)·Cv
The specific heat at constant volume (Cv) for air is approximately 717 J/(kg·K). Substituting this value into the equation, we find:
R = (1.4 - 1)·717 J/(kg·K)
R ≈ 287 J/(kg·K)
Hence, the ideal gas constant for air is approximately 287 J/(kg·K).
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a) The speed of a motor supplied with a voltage input of 30V, assuming the system is without damping, can be expressed as: 30 = (0.02)+(0.06)w dt If the initial speed is zero and a step size of h = 0.
Using Runge-Kutta 2nd order Heun's method, the speed (w) at t = 0.8s is approximately 0.0081.
Given:
Voltage input (V) = 30V
Initial speed (w) = 0
Step size (h) = 0.4s
Time at which speed is to be determined (t) = 0.8s
We need to determine the speed (w) at t = 0.8s using Heun's method.
We have k₁ = f(t₁, W₁) = 0.02 + 0.06w₁ (using the given equation)
At t = 0 and w = 0 (initial conditions), we have:
k₁ = 0.02 + 0.06(0) = 0.02
We have k₂ = f(t₁ + h, w₁ + k₁h) = 0.02 + 0.06(w₁ + 0.02h)
So, at t = 0.4s and w = 0 (initial conditions), we have:
k₂ = 0.02 + 0.06(0.02 * 0.4) = 0.02 + 0.00048 = 0.02048
So, W₂ = w₁ + (k₁ + k₂)(h/2)
= 0 + (0.02 + 0.02048)(0.4/2)
= 0.04048(0.2)
= 0.008096
Therefore, using Runge-Kutta 2nd order Heun's method, the speed (w) at t = 0.8s is approximately 0.0081.
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The complete question is:
The speed of a motor supplied with a voltage input of 30V, assuming the system is without damping, can be expressed as 30 = (0.02)+(0.06)w dt If the initial speed is zero and a step size of h = 0.4 s, determine the speed w at t = 0.8 s by using the Runge-Kutta 2nd order Heun's method. Heun's method: Wi+1=W₁ = w₁ + (-/-^₁ + = -K ₂ ) h where, k₁ = f(t₁, W₁) and k₂ = f(t₁ + h, w₁ + k₁h), the speed (w) at t = 0.8s is approximately 0.0081.
You walk 60 m forward and then 40 m back in 20 s. What is your velocity?
a. 1 m/s
b. 2 m/s
c. 3 m/s
d. 5 m/s
Answer:
The velocity is 1 m/s.
Explanation:
The velocity is the displacement of an object per unit of time.The Person walked 60 m forward, then 40 m backward.The time taken to walk is 20 s.so, t = 20 s.The total Displacement is equal to the forward walk - the backward walk.Displacement =60 m -40 m =20 m.so, The formula for velocity is displacement divided by time.velocity = Displacement/Time velocity = 20 m / 20 s = 1 m/s.The final velocity of my walk is 1 m/sTo learn more about velocity,
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at what distance from a 21 mw point source of electromagnetic waves is the electric field amplitude 0.050 v/m ?
The distance from a 21 MW point source of electromagnetic waves where the electric field amplitude is 0.050 V/m is approximately 1291.55 meters.
To find the distance from the point source, we use the formula P = (1/2)ε₀cE²A, where P is the power of the source, ε₀ is the permittivity of free space, c is the speed of light, E is the electric field amplitude, and A is the surface area of the sphere.
Rearranging the formula for distance (radius of the sphere), we get r = √((2P) / (ε₀cE²)). Plugging in the given values: P = 21 MW, E = 0.050 V/m, ε₀ ≈ 8.85 x 10⁻¹² F/m, and c ≈ 3 x 10⁸ m/s, we can solve for r, which is approximately 1291.55 meters.
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25.17: A person has a far point of 14 cm.
(a)What power glasses would correct this vision if the glasses were placed 2.0 cm from the eye? [Answer: -8.3 D]
(b)What power contact lenses, placed on the eye, would the person need? [Answer: -7.1 D]
(a) The person would need glasses with a power of approximately -8.3 D when placed 2.0 cm from the eye to correct their vision.
(b) The person would need contact lenses with a power of approximately -7.1 D when placed directly on the eye to correct their vision.
(a) To calculate the power of glasses needed to correct the person's vision, we can use the lens formula:
1/f = 1/v - 1/u
where f is the focal length of the lens, v is the image distance (negative for virtual image), and u is the object distance.
Far point = 14 cm (object distance)
Distance between glasses and eye (u) = 2.0 cm
Since the person has myopia (nearsightedness), we need to correct their vision by using a concave lens, which will diverge the incoming light.
We can rearrange the lens formula to solve for the focal length of the lens:
1/f = 1/v - 1/u
Since the glasses are placed 2.0 cm from the eye, the image distance (v) will be equal to the object distance (u) for the lens equation. So, v = u = 2.0 cm.
1/f = 1/2.0 - 1/14
Simplifying the equation:
1/f = 7/14 - 1/14
1/f = 6/14
1/f = 3/7
To find the power of the glasses, we can use the formula:
Power (P) = 1/f
P = 7/3
Converting the power to the correct sign convention (since the person has myopia), the power of the glasses needed to correct their vision when placed 2.0 cm from the eye is approximately -8.3 D.
(b) To calculate the power of contact lenses needed to correct the person's vision when placed directly on the eye, we can use the same approach as in part (a).
Using the same lens formula and given:
Far point = 14 cm (object distance)
Distance between lens and eye (u) = 0 cm (since it's placed on the eye)
1/f = 1/v - 1/u
Since the contact lenses are placed directly on the eye, the image distance (v) will be equal to the object distance (u) for the lens equation. So, v = u = 0 cm.
1/f = 0 - 1/14
1/f = -1/14
To find the power of the contact lenses, we can use the formula:
Power (P) = 1/f
P = -14
Converting the power to the correct sign convention (since the person has myopia), the power of the contact lenses needed to correct their vision when placed on the eye is approximately -7.1 D.
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the copper sheet shown below is partially in a magnetic field. when it is pulled to the right, a resisting force pulls it to the left. explain. what happen if the sheet is pushed to the left?
When the copper sheet is pulled to the right, a resisting force pulls it to the left due to electromagnetic induction.
This phenomenon occurs because the motion of the copper sheet through the magnetic field causes a change in magnetic flux, leading to the generation of an electromotive force (EMF) according to Faraday's law of electromagnetic induction.
The induced EMF creates an opposing current, resulting in the resisting force known as the electromagnetic force or Lenz's law. It acts in such a way as to oppose the change in the magnetic flux.
Thus, whether the sheet is pulled to the right or pushed to the left, the resulting effect is the same—the resisting force acts to oppose the motion of the copper sheet due to electromagnetic induction.
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suppose the charge on the inner conducting sphere is 4 µc, while 8 µc of charge is deposited on the conducting shell. (a) Find the surface charge (in μC) on the inner surface of the shell. (b) Find the surface charge (in μC) on the outer surface of the shell.
(a) The surface charge on the inner surface of the conducting shell is **-4 μC**.
Since the inner conducting sphere has a charge of 4 µC, according to the principle of charge conservation, the total charge on the inner surface of the conducting shell must be equal in magnitude but opposite in sign. Therefore, the surface charge on the inner surface of the shell is -4 μC.
(b) The surface charge on the outer surface of the conducting shell is **8 μC**.
The total charge deposited on the conducting shell is 8 µC. This charge distributes itself uniformly on the outer surface of the shell. Hence, the surface charge on the outer surface of the shell is 8 μC.
In summary, the surface charge on the inner surface of the conducting shell is -4 μC, while the surface charge on the outer surface of the shell is 8 μC.
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For a concentration cell, the standard cell potential is always:
Select the correct answer below:
a. positive.
b. negative.
c. zero.
d. need more information.
A concentration cell is a type of electrochemical cell in which the same electrode material is used as both the anode and cathode, but the concentrations of the reactants or products are different in each half-cell.
The correct answer is: c. zero.
In a concentration cell, the standard cell potential is always zero because there is no net driving force for electron transfer since both electrodes are identical in composition and potential. However, there will be a non-zero voltage if the concentrations of the solutions are different, which can cause a flow of electrons from the more concentrated half-cell to the less concentrated half-cell until equilibrium is reached.
A concentration cell is an electrochemical cell where the two electrodes are made of the same material and are immersed in solutions with different concentrations. The standard cell potential, denoted as E°, is the difference in potential between the two half-cells under standard conditions (1 M concentration, 1 atm pressure, and 25°C temperature). In a concentration cell, both half-cells have the same standard reduction potential, so their difference (E°) will be zero.
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.In a Michelson interferometer, in order to shift the pattern by half a fringe, one of the mirrors at the end of an arm must be moved by
Select answer from the options below
It depends on which mirror is moved.
It depends on the wavelength.
one-quarter wavelength.
half a wavelength.
one wavelength.
To shift the pattern by half a fringe in a Michelson interferometer, one of the mirrors at the end of an arm must be moved by half a wavelength.
This is because the interference pattern is created by the superposition of light waves that have traveled different distances. Moving one of the mirrors changes the length of one of the arms, altering the path length difference between the two beams of light. When this path length difference equals half a wavelength, destructive interference occurs and the pattern shifts by half a fringe. Therefore, the specific distance that the mirror needs to be moved depends on the wavelength of the light being used.
In a Michelson interferometer, to shift the pattern by half a fringe, one of the mirrors at the end of an arm must be moved by one-quarter wavelength. This movement alters the path difference by half a wavelength, resulting in the half-fringe shift. The wavelength is crucial in determining the required mirror movement for the desired fringe shift.
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a weight of 800 n is hung from a spring with a spring constant of 2000 n/m and lowered slowly. how much will the spring strech
The amount that the spring will stretch can be calculated using Hooke's Law, which states that the force exerted by a spring is proportional to its displacement. The spring will extend a distance of 0.4 meters.
Hooke's Law can be expressed as:
F = k * x
Where F is the force applied to the spring, k is the spring constant, and x is the displacement or stretch of the spring.
In this case, the force applied to the spring is 800 N and the spring constant is 2000 N/m. We can rearrange the equation to solve for x:
x = F / k
x = 800 N / 2000 N/m
x = 0.4 m
Therefore, the spring will stretch by 0.4 meters (or 40 centimeters) when a weight of 800 N is hung from it.
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the average life expectancy in madagascar is 66 years. what is this time in si units? (assume one year is 365 days.)
To convert the average life expectancy in Madagascar from years to SI units, we need to convert years to seconds.
Average life expectancy = 66 years
One year = 365 days
To convert years to seconds, we need to consider the number of days in a year and the number of seconds in a day.
Number of seconds in a day = 24 hours * 60 minutes * 60 seconds = 86,400 seconds
Number of days in 66 years = 66 years * 365 days/year = 24,090 days
Total time in seconds = Number of days * Number of seconds in a day
Total time in seconds = 24,090 days * 86,400 seconds/day
Total time in seconds = 2,081,376,000 seconds
Therefore, the average life expectancy in Madagascar of 66 years is equivalent to approximately 2,081,376,000 seconds in SI units.
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the symbolic expression for the magnitude of the current i through the resistor
The symbolic expression for the magnitude of the current (i) through a resistor can be determined using Ohm's Law, which states that the current flowing through a resistor is directly proportional to the voltage across it and inversely proportional to its resistance.
Mathematically, Ohm's Law can be expressed as: i = V/R
Where:
i is the magnitude of the current flowing through the resistor,
V is the voltage across the resistor, and
R is the resistance of the resistor.
This equation shows that the current (i) is equal to the voltage (V) divided by the resistance (R). Therefore, to calculate the magnitude of the current through a resistor, you need to know the applied voltage and the resistance of the resistor. By substituting these values into the equation, you can find the value of the current.
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