Two lamps rated 60W; 240V and 100W, 240Vrespectively are connected in series to a 240V power source. Calculate;
a) The resistance of each lamp.
b) The effective resistance of the circuit.
c) The current passing the lamps. pls answer correctly ​

Answers

Answer 1

Answer:

See the answers below.

Explanation:

The total power of the circuit is equal to the sum of the powers of each lamp.

[tex]P=60+100\\P=160 [W][/tex]

Now we have a voltage source equal to 240 [V], so by means of the following equation we can find the current circulating in the circuit.

[tex]P=V*I[/tex]

where:

P = power [W]

V = voltage [V]

I = current [amp]

[tex]I = P/V\\I=160/240\\I=0.67 [amp][/tex]

So this is the answer for c) I = 0.67 [amp]

We know that the voltage of each lamp is 240 [V]. Therefore using ohm's law which is equal to the product of resistance by current we can find the voltage of each lamp.

a)

[tex]V=I*R[/tex]

where:

V = voltage [V]

I = current [amp]

R = resistance [ohms]

Therefore we replace this equation in the first to have the current as a function of the resistance and not the voltage.

[tex]P=V*I\\and\\V = I*R\\P = (I*R)*I\\P=I^{2}*R[/tex]

[tex]60 = (0.67)^{2}*R\\R_{60}=133.66[ohm] \\and\\100=(0.67)^{2} *R\\R_{100}=100/(0.66^{2} )\\R_{100}=225 [ohm][/tex]

b)

The effective resistance of a series circuit is equal to the sum of the resistors connected in series.

[tex]R = 133.66 + 225\\R = 358.67 [ohms][/tex]


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A spiral spring of natural length 20.00cm has a scale
pan hanging on its lower end while the other end is
fixed firmly to a support.When an object of mass 50g
is placed in the pan, the length of the spring becomes
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Answers

The  mass of the scale pan : 0.11 kg

Further explanation

Given

A spiral spring's length = 20 cm

mass 50 g ⇒ the length = 22 cm

mass 70 g ⇒ the length = 22.25 cm

Required

the  mass of the scale pan

Solution

Hooke's Law :

[tex]\tt F=k.\Delta x[/tex]

The spring constant (k) :

[tex]\tt k=\dfrac{\Delta F}{\Delta x}=\dfrac{g.(70-50)}{22.25-22}=\dfrac{g.20}{0.25}=g.80~g/cm=10~m/s^2\times 8~kg/m=80~N/m[/tex]

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Calculate the mass of a man jogging north along the highway at a rate of 2.65 m/s and a momentum of 225.3 kg*m/s

Answers

Answer:

85.02 kg

Explanation:

The mass of the man can be found by using the formula

[tex]m = \frac{p}{v} \\ [/tex]

v is the velocity

p is the momentum

From the question we have

[tex]m = \frac{225.3}{2.65} \\ = 85.01886...[/tex]

We have the final answer as

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Explanation:

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Answer:

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Answer:

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(a) As you ride on a Ferris wheel, your apparent weight is different at the top and at the bottom. Explain. (b) Calculate your apparent weight at the top and bottom of a Ferris wheel, given that the radius of the wheel is 7.2 m, it completes one revolution every 28 seconds, and your mass is 55 kg.

Answers

Answer:

a. The component of the net force which make up the apparent weight are added to each other at the bottom and subtracted (the centripetal force from the weight) at the top)

b. Apparent weight at the top is approximately 519.06 N

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Therefore;

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Apparent weight at the top ≈ 519.06 N

At the bottom of the Ferris wheel the weight is acting downwards and the centripetal force is also acting downwards

Therefore;

The net force at the bottom, which is the apparent weight of the passenger at the bottom [tex]F_{NET_{bottom}}[/tex] = 539 N + 19.94 N ≈ 558.94 N

Apparent weight at the bottom ≈ 558.94 N.

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Explanation:

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