We have that the cost is $80 plus $3 per mile, and also we now that the car is 20 to 30 miles from the car repair shop. So we have that Trini have to pay
[tex]\begin{gathered} 80\text{ + 3(20) }\leq\text{ M }\leq\text{ 80 + 3(30)} \\ 80\text{ + 60 }\leq\text{ M }\leq\text{ 80 + 90} \\ 140\text{ }\leq\text{ M }\leq170 \end{gathered}[/tex]So the answer is: b.140 greater than sign M greater than sign 150.
Solve each of the following equations. Show its set on a number line. |4x-4(x+1)|=4
Solving this equation, we have:
[tex]\begin{gathered} |4x-4\mleft(x+1\mright)|=4 \\ |4x-4x-4|=4 \\ |-4|=4 \\ 4=4 \end{gathered}[/tex]Since the final sentence is always true, the solution set is all real numbers.
Showing it in the number line in blue, we have:
This is Calculus 1 Linear Optimization Problem! MUST SHOW ALL THE JUSTIFICATION!!!
Given:
Required:
We need to find the value of AB
Explanation:
Here ABC is the right anglr triangle
so
[tex]\begin{gathered} AB^2=BC^2+AC^2=36+36=72 \\ AB=6\sqrt{2} \end{gathered}[/tex]Final answer:
The minimum length of crease is
[tex]6\sqrt{2}[/tex]Solve the following system of equations by graphing. Graph the system below and enter the solution set as an ordered pair in the form (x,y).if there are no solutions, enter none and enter all if there are infinite solutions.X - y = 0X + y = - 4
EXPLANATION
Since we have the system of equations:
(1) x - y = 0
(2) x + y = -4
Isolating x in (1):
x = y
Plugging in x=y into (2):
y + y = -4
Adding like terms:
2y = -4
Dividing both sides by 2:
y = -4/2
Simplifying:
y = -2
Plugging in y=-2 into (1):
x - (-2) = 0
Removing the parentheses:
x + 2 = 0
Subtracting -2 to both sides:
x = -2
The solution of the system of equations is (-2, -2)
Representing the graph:
Suppose that $2000 is invested at a rate of 3.9%, compounded monthly. Assuming that no withdrawals are made, find the total amount after six years.Round your answer to the nearest cent.
Compound interest formula:
[tex]\begin{gathered} A=P(1+\frac{r}{n})^{nt} \\ \\ A\colon\text{Amount} \\ P\colon\text{ Principal} \\ r\colon\text{ interest rate (in decimals)} \\ n\colon\text{ number of times interest is compounded in a year} \\ t\colon\text{ time (in years} \end{gathered}[/tex]Given data:
P= $2,000
r= 3,9% =0.039
n=monthly= 12
t= 6 years
[tex]\begin{gathered} A=2000(1+\frac{0.039}{12})^{12(6)} \\ \\ A=2000(1.00325)^{72} \\ \\ A\approx2526.33 \end{gathered}[/tex]Then, the total amount after six years is $
A pottery factory purchases a continuous belt conveyor kiln for $68,000. A 6.3% APR loan with monthly payments is taken out to purchase the kiln. If the monthly payments are $765.22, over what term is this loan being paid?
Based om the cost of the continuous belt conveyor kiln and the monthly payments, as well as the APR of the loan, the term this loan will be paid is 120 months or 10 years.
How to find the term of the loan?When given the cost of a loan, the APR, and the monthly payments, you can find out the term of the loan by using the NPER function on a spreadsheet.
The Rate would be:
= 6.3% / 12 months in a year
= 0.525%
The Pmt is the payment of $765.22. This amount should be in negatives.
The Present Value or Pv should be the loan amount of $68,000.
The term on the loan would then be 120 months which is 10 years.
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10 ptQuestion 10A can of soup has a volume of 80 in and mass of 10 ounces. A can of tuna has a volume of 56 in and mass of 8ounces. About how much less is the density of the soup than the tuna (give your answer in ounces/square inch).Round your answer to the nearest 1000th.SOUPSTUNA CHUNKSBrineLENTIL0.0179 ounces per per square inches less0.1429 ounces per per square inches less0.1250 ounces per per square inches less0.0099 ounces per per square inches less
We have that the general formula for the density given the volume and the mass is:
[tex]d=\frac{m}{v}[/tex]in this case, the densities for the can of soup and the can of tuna are:
[tex]\begin{gathered} d_{soup}=\frac{10}{80}=\frac{1}{8} \\ d_{tuna}=\frac{8}{56}=\frac{1}{7} \end{gathered}[/tex]the difference between these two densities is:
[tex]\frac{1}{7}-\frac{1}{8}=\frac{1}{56}=0.0179[/tex]therefore, there is 0.0179 less density of the soup than the tuna
Put these five fractions in order, left to right, from least to greatest. 1 /3 2 /7 3/10 4/13 5/17
The five fractions can be arranged in order, from the left to right, from least to greatest as : 5/17 , 3/10 , 4/13 , 1 /3.
How can the fraction can be arranged from the from least to greatest?The fraction can be arranged from the from least to greatest by firstly convert the fraction to the decimal numbers so that one c b able to identify the highest and the lowest values.
The given fractions 1 /3 2 /7 3/10 4/13 5/17 can be converted to decimal numbers as 0.33 , 0.67 , 0.30 , 0.31 , 0.29 respectively and this can be arranged as 5/17 , 3/10 , 4/13 , 1 /3.
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Apply the product rule to rewrite the product below using a single base and exponent then simplify: 3^2 *3^3 our base is Answerour exponent is Answerthis simplifies to Answer
Explanation:
[tex]3^2\text{ }\times3^3[/tex][tex]\begin{gathered} \text{The expression has same base.} \\ \text{Base = 3} \\ We\text{ take one base and bring the exponents together} \\ \text{The sign betw}en\text{ them changes from multiplication to addition} \end{gathered}[/tex][tex]\begin{gathered} 3^2\text{ }\times3^3\text{ = }3^{2\text{ + 3}} \\ \text{Exponent = 2 + 3} \\ \text{Exponent = 5} \end{gathered}[/tex][tex]\begin{gathered} \text{Simplifying:} \\ 3^{2+3}=3^5 \\ 3^5\text{ = 243} \end{gathered}[/tex]Mike made $120 last week working d days. Express the amount he made each day in terms of d.
Since he made $120 in d days
To find his earn in eac
I need help with this problem, please help
Answer:
d.
Step-by-step explanation:
the slope is the factor of x.
a perpendicular slope turns the original slope upside-down and flips the sign.
the original slope is -3/7.
the perpendicular slope is then 7/3.
the only answer option with the correct slope is d.
so, d. must be correct.
let's check that (-2, 2) is on this line :
2 = 7/3 × -2 + 20/3 = -14/3 + 20/3 = 6/3 = 2
2 = 2
correct.
so yes, the point (-2, 2) is on this line, and d. is indeed correct.
I need to make 500$ per week after tax in order to pay all my bills. The income tax is 20% What is the smallest pre-tax weekly salary I can earn and still be able to pay my bills after I pay my income tax?
I must earn at least $625 (or more) per week before tax to pay my bills.
Given,
To make $500 per week after tax in order to pay all my bills.
and, The income tax is 20%
To find the smallest pre-tax weekly .
Now, According to the question:
Let x be the amount to earn pre - tax.
The income tax is 20% = 20/100 = 0.2
Set up an inequality:
x - 0.2x > = 500
0.8 > = 500
x >= 500/0.8
x >= 625
Hence, I must earn at least $625 (or more) per week before tax to pay my bills.
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Determine if the two triangles shown are similar. If so, write the similarity statement.Question options:A) Impossible to determine.B) ΔBCG ∼ ΔEFGC) ΔGCB ∼ ΔGFED) The triangles are not similar.
ANSWER
Option D: The triangles are not similar
STEP BY STEP EXPLANATION
Now, two (2) triangles are said to be similar if the three (3) angles of triangle A are congruent or equal to the corresponding three (3) angles of triangle B.
If you take a close look at the two (2) triangles, you will notice that the only angle in ∆BCG that is equal to the corresponding angles in ∆EFG is ∆BGC; the two (2) remaining angles in ∆BCG are not congruent with the two (2) corresponding angles in ∆EFG
Hence, it can be concluded that both triangles are not similar.
1)Find the probability of randomly selecting the correct access code on the first try 4 digits (0 through 9)2)find the probability of NOT selecting the correct access code on the first try
There are 10 digits from 0 to 9.
First digit 10 ways
Second digit 10 ways
Third digit 10 ways
Fourth digit 10 ways
[tex]\text{There are 10}\times10\times10\times10\text{ ways for four digits.}[/tex][tex]\text{There are 10}000\text{ ways for four digits.}[/tex]Hence the total outcomes =10000
Selecting the correct access code on the first try given favorable outcomes =1.
[tex]\text{The probability of randomly selecting the correct access code on the first try=}\frac{favorable\text{ outcome}}{\text{Total outcomes}}[/tex][tex]\text{=}\frac{1}{10000}[/tex][tex]=0.0001[/tex]Hence the probability of randomly selecting the correct access code on the first try is 0.0001.
The probability of not selecting the correct access code on the first try=1-The probability of selecting the correct access code on the first try
The probability of not selecting the correct access code on the first try=1-0.0001
Hence the probability of not selecting the correct access code on the first try=0.9999.
The maintenance department at the main campus of a large state university receives daily requests to replace fluorescent lightbulbs. The distribution of the number of daily requests is bell-shaped and has a mean of 42 and a standard deviation of 10. Using the 68-95-99.7 rule, what is the approximate percentage of lightbulb replacement requests numbering between 42 and 62.
we are given
mean=42
Std=10
if the mean=42 + std =10 42+10=52
if the mean=42 - std=10 42-10=32
Rule -- 68-95-99.7
68% of the measures are within 1 standard deviation of the mean.
42+10=52
95% are within 2.
42+20=62
99.7% are within 3.
42+30=72
The normal distribution is symmetric, which means that 50% of the measures are above the mean and 50% are below.
we are ask for the porcentage of request between 42-62 (between the mean and 2+std)
62 is two standard deviations above the mean.
Of the 50% of the measures below the mean, 95% are between 42 and 62, so
0.95(50)=47.5
The approximate percentage of light bulb replacement requests numbering between 42 and 62 is of 47.5%
I need help with my pre-calculus homework, please show me how to solve them step by step if possible. The image of the problem is attached. The homework was a pdf so the choices can't expand, my teacher told me to just write the transformation of the given function in the format.
Answer:
• Amplitude: 3
,• Period: π/2
,• Phase Shift: 1/8 (to the left)
,• Vertical Shift: -0.5
Explanation:
Given the trigonometric function:
[tex]y=3\sin (4x+\frac{1}{2})-0.5[/tex]Comparing with the form below:
[tex]\begin{gathered} y=A\sin (Bx-C)+D\text{ where:} \\ \text{Amplitude}=A \\ Period=\frac{2\pi}{B} \\ Phase\text{ Shift}=\frac{C}{B} \\ \text{Vertical Shift}=D \end{gathered}[/tex]Thus, we have that:
[tex]\begin{gathered} \text{Amplitude,}A=3 \\ Period,\frac{2\pi}{B}=\frac{2\pi}{4}=\frac{\pi}{2} \\ Phase\text{ Shift,}\frac{C}{B}=-\frac{1}{2}\div4=-\frac{1}{8} \\ \text{Vertical Shift, }D=-0.5 \end{gathered}[/tex]The phase shift, -1/8 indicates a shift to the left.
. In a 30°-60-90° triangle, the hypotenuse is 7 yards long.Find the exact lengths of the legs?
ANSWER
The lengths of the legs of the triangle are 6.06 yards and 3.6 yards.
EXPLANATION
First, let us make a sketch of the problem:
To find the length of the legs, we have to apply trigonometric ratios SOHCAHTOA.
We have that:
[tex]\sin (60)=\frac{\text{opposite}}{\text{hypotenuse}}[/tex]From the diagram:
[tex]\begin{gathered} \sin (60)=\frac{x}{7} \\ \Rightarrow x=7\cdot\sin (60) \\ x\approx6.06\text{ yds} \end{gathered}[/tex]We also have that:
[tex]\sin (30)=\frac{\text{opposite}}{\text{hypotenuse}}[/tex]From the diagram:
[tex]\begin{gathered} \sin (30)=\frac{y}{7} \\ \Rightarrow y=7\cdot\sin (30) \\ y=3.5\text{ yds} \end{gathered}[/tex]The lengths of the legs of the triangle are 6.06 yards and 3.5 yards.
For what value of x does 32x93x-4?oo 2o 3o 4
Solution
[tex]3^{2x}=9^{3x-4}[/tex]We can do the following:
[tex]3^{2x}=3^{2(3x-4)}[/tex]And we have this:
[tex]2x=6x-8[/tex][tex]4x=8[/tex][tex]x=\frac{8}{4}=2[/tex]You use substitution to solve a system of equations and after simplifying end with a statement that says 7=7 discrible what this statement means about the number of solutions and about the graph of the system
The start of a quadratic
sequence is
8, 18, 30, 44, 60, …
What is the nth term rule for this sequence?
Answer:
The correct option is D
98
The general term of the sequence is n(n+7)
Use Part Il of the Fundamental Theorem of Calculus to evaluate the definite integral
Answer:
[tex]4\ln (2)+\frac{49}{3}\approx19.1059[/tex]Given:
[tex]\int ^{-1}_{-2}\frac{7x^5-4x^2}{x^3}dx[/tex]Simplify:
[tex]\int \frac{7x^3-4}{x}dx[/tex]Expand:
[tex]\int (7x^2-\frac{4}{x})dx[/tex]Apply linearity:
[tex]7\int x^2dx-4\int \frac{1}{x}dx[/tex]Apply power rule and the standard integral ln(x)
[tex]7(\frac{x^3}{3})-4\ln (x)[/tex]Now, applying the Fundamental Theorem of Calculus Part 2
[tex]\int ^{-1}_{-2}\frac{7x^5-4x^2}{x^3}dx=(7(\frac{(-1)^3}{3})-4\ln (-1))-(7(\frac{(-2)^3}{3})-4\ln (-2))[/tex][tex]=4\ln (2)+\frac{49}{3}[/tex]Or approximately
[tex]\approx19.1059[/tex]What is the surface area of fish tank in the shape of a cube that has a volume of 90 cubic inches.
You know that the volume of the fish tank in the shape of a cube:
[tex]V=90in^3[/tex]By definition, the formula for calculating the volume of a cube is:
[tex]V=a^3[/tex]Where "a" is the length of each edge of the cube.
If you solve for "a", you get this formula:
[tex]a=\sqrt[3]{V}[/tex]In this case, knowing the volume of the cube, you can substitute it into the second formula and evaluate, in order to find the length of each edge of the cube:
[tex]\begin{gathered} a=\sqrt[3]{90in^3} \\ \\ a\approx4.48in \end{gathered}[/tex]The surface area of a cube can be found using this formula:
[tex]SA=6a^2[/tex]Where "a" is the length of each edge of the cube.
Substituting the value of "a" into the formula and evaluating, you get:
[tex]SA=6(4.48in)^2\approx120in^2[/tex]Hence, the answer is: Second option.
Hello I'd like some help on my practice question I'd prefer if it's quick because I have other questions I need to solve thank you
f(x) = -2
the answer is the second option
The horizontal line at y = -2 which is parallel to x-axis
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Find (w ∘ w)(−1) for w(x)=3x^2+3x−3.
Answer: (w ∘ w)(−1)=
Answer:
15
Step-by-step explanation:
wow(-1) means w(w(-1))
so we can find out what w(-1) is
3(-1)^2+3(-1)-3=3-3-3
which is -3
then we can find w(-3)
3(-3)^2+3(-3)-3
which is 15
Given the following function, find f(-3), f(0), and f (2) f(x)=5x-2
The output values of f(-3), f(0) and f(2) of the function f( x ) = 5x - 2 are -17, -2 and 8 respectively.
What are the output values of f(-3), f(0) and f(2) in the given function?A function is simply a relationship that maps one input to one output.
Given the data in the question;
f( x ) = 5x - 2f( -3 ) = ?f( 0 ) = ?f( 2 ) = ?For f( - 3 );
To find the output value of f( -3 ), replace all the occurrence of x with -3 in the function and simplify.
f( x ) = 5x - 2
f( -3 ) = 5(-3) - 2
f( -3 ) = -15 - 2
f( -3 ) = -17
For f( 0 );
To find the output value of f( 0 ), replace all the occurrence of x with 0 in the function and simplify.
f( x ) = 5x - 2
f( 0 ) = 5(0) - 2
f( 0 ) = 0 - 2
f( 0 ) = -2
For f( 2 );
To find the output value of f( 2 ), replace all the occurrence of x with 2 in the function and simplify.
f( x ) = 5x - 2
f( 2 ) = 5(2) - 2
f( 2 ) = 10 - 2
f( 2 ) = 8
Therefore, the output value of f( 2 ) is 8, this forms an ordered pair of ( 2, 8 ).
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Please help me with this problem just wanted to be sure that I am correct in order to help my son to under stand the break down of this problem. I believe that the answer is -3 but I am not sure please help?Solve for x.14x−1/2(4x+6)=3(x−4)−18 Enter your answer in the box.x =
SOLUTION
We want to solve for x in the equation
[tex]14x-\frac{1}{2}\mleft(4x+6\mright)=3\mleft(x-4\mright)-18[/tex]First we expand the brackets in both sides of the equation, this becomes
[tex]\begin{gathered} 14x-\frac{1}{2}(4x+6)=3(x-4)-18 \\ 14x-2x-3=3x-12-18 \end{gathered}[/tex]Note that the minus sign multiplies the items in the brackets too
Now, we collect like terms we have
[tex]\begin{gathered} 14x-2x-3x=-12-18+3 \\ 9x=-27 \\ \text{divide both sides by 9, we have } \\ \frac{9x}{9}=\frac{-27}{9} \\ x=-3 \end{gathered}[/tex]Hence x = -3
Triangle HJK has vertices at H(2, 2) J(2, 4) and K(0, 2). What is the midpoint of the longest side of the triangle?
The coordinates of the vertices of triangle are given as H(2,2), (J(2, 4), K(0,2)
We would determine the longest side by applying the formula for finding the distance between two points which is expressed as
[tex]\begin{gathered} \text{Distance = }\sqrt[]{x2-x1)^2+(y2-y1)^2} \\ \text{For HJ, x1 = 2, y1 = 2, x2 = 2, y2 = 4} \\ \text{Distance = }\sqrt[]{(2-2)^2+(4-2)^2}\text{ = }\sqrt[]{2^2}\text{ = 2} \\ \text{For JK, x1 = 2, y1 = 4, x2 = 0, y2 = 2} \\ \text{Distance = }\sqrt[]{(0-2)^2+(2-4)^2}=\sqrt[]{(4+4)}=\text{ }2.83 \\ \text{For HK, x1 = 2, y1 = 2, x2 = 0, y2 = 2} \\ \text{Distance = }\sqrt[]{0-2)^2+(2-2)^2}=\text{ }\sqrt[]{4}\text{ = 2} \end{gathered}[/tex]Thus, the longest side is JK. The formula for finding midpoint is
Midpoint = (x1 + x2)/2, (y1 + y2)/2
Midpoint = (2 + 0)/2, (4 + 2)/2
Midpoint = 2/2, 6/2
Midpoint = 1, 3
Create a quadratic function in one of the forms and show how to convert it to the other two forms.
Create a quadratic function in one of the forms and show how to convert it to the other two forms.
Step-by-step explanation:
1) Standard form: y = ax2 + bx + c where the a,b, and c are just numbers.
[tex]y=ax^2+bx+c[/tex]2) Factored form: y = (ax + c)(bx + d) again the a,b,c, and d are just numbers.
[tex]y=(ax+c)(bx+d)[/tex]3) Vertex form: y = a(x + b)2 + c again the a, b, and c are just numbers.
[tex]y=a(x+b)^2+c[/tex]The vertex of the parabola is written as (h, k) where b is the x - coordinate and c - is the y - coordinate
Consider an investment whose return is normally distributed with a mean of 10% and a standard deviation of 5%. (2.4)
Justify which statistics methodology needs to be used in the above context and
a) Determine the probability of losing money.
b) Find the probability of losing money when the standard deviation is equal to 10%.
a) The probability of losing money when standard deviation is 5% is 2.27%
b) The probability of losing money when standard deviation is 10% is 15.87%
Given,
There is an investment whose return is normally distributed.
The mean of the distribution = 10%
The standard deviation of the distribution = 5%
a) We have to determine the probability of losing money:
Lets take,
x = -0.005%
Now,
P(z ≤ (-10.005 / 5) ) = P(z ≤ - 2.001) = 0.02275
Now,
0.02275 × 100 = 2.27
That is,
The probability of losing money is 2.27%
b) We have to find the probability of losing money when the standard deviation is 10%
Let x be 0.01%
Now,
P(z ≤ (-10.01/10)) = P(z ≤ -1.001) = 0.15866
Now,
0.15866 × 100 = 15.87
That is,
The probability of losing money is 15.87%
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determine if each expression is equivalent to [tex] \frac{ {7}^{6} }{ {7}^{3} } [/tex]
The question says we are to check the options that are equal
[tex]\frac{7^6}{7^3}[/tex]Using the law of indices
[tex]\frac{7^6}{7^3}=7^{6-3\text{ }}=7^3[/tex]So we will check all the options(applying the laws of indices)
The first option is
[tex]7^9(7^{-6})=7^{9-6}=7^3[/tex]yes, the first option is equivalent
We will move on and check the second option
[tex]\frac{7^{-8}}{7^{-11}}\text{ = }7^{-8+11}=7^3[/tex]Yes the second option is equivalent
We will move on to check the third option
[tex](7^5)(7^3)divideby7^{4\text{ }}=7^{5+3-4\text{ }}=7^4[/tex]No the third option is not eqquivalent to the question
We will move to tthe next option, fourth option
[tex]7^{-3\text{ }}\times7^{6\text{ }}=7^{-3+6}=7^3[/tex]yes this option is equivalent to the fraction
Moving on to the fifth option
[tex](7^3)^{0\text{ }}=7^{3\times0}=7^0=\text{ 1}[/tex]No the fifth option is not equivalent to the question
divide fraction2*1/3 / 7*3/8 =
Step-by-step explanation:
3.999 is the correct answer