Trey was asked to build a working model of a landform for a science project. He chose to build a model of a volcano.
Trey formed a base out of clay and then painted the model so it resembled a cinder cone volcano.
Finally, Trey mixed baking soda, vinegar, and red food coloring in the base, so it mimicked lava flowing out of the volcano. Once
he was finished with his project, Trey's teacher asked how useful his model was.
What factor best determines the usefulness of the model?
A. how closely the model's color matches the real world
how closely the model's behavior matches the real world
C. how closely the model's size matches the real world
how closely the model's composition matches the real world
B.
D.

Answers

Answer 1
Can you please give me more details so I can help you
Answer 2

Answer:

The answer is "how closely the model's behavior matches the real world "

Explanation:

Your options were glitched out, so it only showed A and C, and B and D were blank so lol


Related Questions

How many grams of Fe will be produced if 705.0g of H20 are produced?
Fe3O4 + 4H2
-->
3 Fe + 4H2O

Answers

Answer:

2265 g Fe₃O₄

General Formulas and Concepts:

Math

Pre-Algebra

Order of Operations: BPEMDAS

Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to Right

Chemistry

Atomic Structure

Reading a Periodic Table

Stoichiometry

Using Dimensional AnalysisExplanation:

Step 1: Define

[RxN - Balanced] Fe₃O₄ + 4H₂ → 3Fe + 4H₂O

[Given] 705.0 g H₂O

Step 2: Identify Conversions

[RxN] 4 mol H₂O → 1 mol Fe₃O₄

Molar Mass of H - 1.01 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of Fe - 55.85 g/mol

Molar Mass of H₂O - 2(1.01) + 16.00 = 18.02 g/mol

Molar Mass of Fe₃O₄ - 3(55.85) + 4(16.00) = 231.55 g/mol

Step 3: Convert

Set up stoich:                              [tex]\displaystyle 705.0 \ g \ H_2O(\frac{1 \ mol \ H_2O}{18.02 \ g \ H_2O})(\frac{1 \ mol \ Fe_3O_4}{4 \ mol \ H_2O})(\frac{231.55 \ g \ Fe_3O_4}{1 \ mol \ Fe_3O_4})[/tex]Multiply/Divide/Cancel units:                                                                           [tex]\displaystyle 2264.74 \ g \ Fe_3O_4[/tex]

Step 4: Check

Follow sig fig rules and round. We are given 4 sig figs.

2264.74 g Fe₃O₄ ≈ 2265 g Fe₃O₄

2 NaOH (s) + CO2(g) → Na2CO3 (s) + H20 (I)

How many grams of water can be produced with 1.85 moles of NaOH​

Answers

Answer:

16.7 g H₂O

General Formulas and Concepts:

Math

Pre-Algebra

Order of Operations: BPEMDAS

Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to Right

Chemistry

Stoichiometry

Reading a Periodic TableUsing Dimensional AnalysisExplanation:

Step 1: Define

[RxN - Balanced] 2NaOH (s) + CO₂ (g) → Na₂CO₃ (s) + H₂O (l)

[Given] 1.85 mol NaOH

Step 2: Identify Conversions

[RxN] 2 mol NaOH → 1 mol H₂O

Molar Mass of H - 1.01 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of H₂O - 2(1.01) + 16.00 = 18.02 g/mol

Step 3: Stoichiometry

Set up:                               [tex]\displaystyle 1.85 \ mol \ NaOH(\frac{1 \ mol \ H_2O}{2 \ mol \ NaOH})(\frac{18.02 \ g \ H_2O}{1 \ mol \ H_2O})[/tex]Multiply/Divide:                 [tex]\displaystyle 16.6685 \ g \ H_2O[/tex]

Step 4: Check

Follow sig fig rules and round. We are given 3 sig figs.

16.6685 g H₂O ≈ 16.7 g H₂O

As a heavy metal ball rolls down a hill, it goes faster and faster. Which statement is true?

Answers

The ball's potential energy is transferring into kinetic energy

Brainly if correct? Thanks!

Answer:

A

Explanation:

The balls potential energy is changing to kinetic energy

When performing a multiplication or division calculation, significant figures in the calculated result are dictated by the _____ of the measured numbers.
The calculated result should have ______ the measured number in the calculation with the fewest _______.

Answers

Answer:

fewest; the same significant figures with; measured numbers.

Explanation:

Without mincing words let us dive straight into the solution to the above question. In order to be able to use the significant figures properly one must know the rules attached to it uses. This is so, because they contributes to the precision of measurements.

When performing multiplication or division calculation, the number of significant figures in the answer[result] will be determined by the one with the smallest number of significant figure in the problem. Therefore, if we have 6.56 which is three[3] significant figures and 1.2 which is two[2] significant figures, then the number of significant figures will be two[2].

6.56 × 1.2= 7.872 = 7.9[ to 2 significant figures].

A control. during a experiment

Answers

A scientific control is an experiment or observation designed to minimize the effects of variables other than the independent variable. This increases the reliability of the results, often through a comparison between control measurements and the other measurements.

How much heat do you need to raise the temperature of 100 g of aluminum from 30°C to 150°C?

Answers

Answer:

Heat energy can be calculated by using the specific heat of a substance multiplying it to the mass of the sample and the

change in temperature. It is expressed as:

Energy = mCAT

Energy = 100 (0.90) (150 - 30)

Energy = 10800 J

My question my question

Answers

H2O as an oxidant only

Further explanation

Given

Reaction

2 Na + 2 H2O → 2 NaOH + H2

Required

The function of water in the equation

Solution

Water : oxidizing agent

Na : reducing agent

Na⁰ → Na⁺ (oxidation)

H⁺- → H⁰ (reduction)

Acids and bases according to Bronsted-Lowry

Acid = donor (donor) proton (H⁺ ion)

Base = proton (receiver) acceptor (H⁺ ion)

If water is acting as an acid it should only give 1 H +, so that becomes:

H₂O (l) ⇔ OH⁻ (aq) not H₂

a sample of solid is decomposed and found to contain 6.52g of potassium, 4.34 g of chromium and 5.34 of oxygen, what is the empirical formula of the compound? help asap​

Answers

Answer:

K₂CrO₅

Explanation:

The empirical formula is the simplest formula of a compound. To find the empirical formula, we follow the procedure below:

Elements                         Potassium                 Chromium         Oxygen

Mass                                  6.52                             4.34                  5.34

Molar mass                          39                               60                      16

Number of moles             6.52/39                     4.34/60             5.34/16

                                             0.167                          0.072              0.333

Divide through by

the smallest                      0.167/0.072             0.072/0.072          0.333/0.072

                                            2.3                               1                                4.6

                                             2                                 1                                  5

Empirical formula K₂CrO₅

How many grams of Fe3+ are present in 2.56 grams of iron(III) iodide?

Answers

Answer:

436.55841 grams.

Explanation:

The molecular formula for Iron(III) Iodide is FeI3. The SI base unit for amount of substance is the mole. 1 mole is equal to 1 moles Iron(III) Iodide, or 436.55841 grams.

You use the 1 / 436.55841 conversion rate. This is different for each element, according to the stoichiometry tables. Iron(II) oxide would be 2/3 of the 1/436.55841 conversion rate, that is, multiplying the fraction to denominator.

what is the difference between the number of electrons in an atom of selenium, Se and the number of electrons in an atom of aluminum, Al?

Answers

Answer:

Well, electrons can be converted into a atomic number so if SE atomic number is 34 that means it has 34 electrons. AI has a atomic number of 13 meaning it has 13 electrons. So the difference is that SE has more electrons then AI.

How many lead atoms in Pb(OH) 4 ?

Answers

4 in hydrogen 4 in oxygen

Explanation:

hope this helps

which mineral is composed of calcium and fluorine?

Answers

Answer:

Fluorite

What is Fluorite? Fluorite is an important industrial mineral composed of calcium and fluorine (CaF2). It is used in a wide variety of chemical, metallurgical, and ceramic processes

Exactly what the first person said. Fluorite.

What chemicals need to make liquid bakelite ?

Answers

It begins with heating of phenol and formaldehyde in the presence of a catalyst such as hydrochloric acid, zinc chloride, or the base ammonia. This creates a liquid condensation product, referred to as Bakelite A, which is soluble in alcohol, acetone, or additional phenol.

Which best describes why NH4+ can form an ionic bond with Cl–?
Its outermost shell gains one or more electrons from Cl–.
Its positive charge is attracted to the negative charge of Cl–.
It has a negative charge that is spread over the entire ion.
It has a nitrogen atom that is strongly attracted to Cl–.

Answers

Answer:

Its positive charge is attracted to the negative charge of Cl–.

Explanation:

The best description of why NH₄⁺ forms an ionic bond with Cl⁻ is that its positive charge is attracted to the negative charge of Cl⁻.

An ionic bond forms as a result of transfer of electrons. As a result the seemingly metal ion is attracted to the negative non-metal ion.

The electrostatic force of attraction between these ions is the ionic or electrovalent bond.

So, the attraction between these opposite charges will form the ionic bond.

Answer:

B: Its positive charge is attracted to the negative charge of Cl–

Explanation:

right on edge2021

A student sets up the following equation to convert a measurement.
(The ? stands for a number the student is
going to calculate.)
Fill in the missing part of this equation.
Note: your answer should be in the form of one or more fractions multiplied together.
gcm
3 kg.m
-2.9 x 10
0x0
.
X Х
5

Answers

Answer:

9 . this was not able the first one. it has to go on, I will not sure about

please help me please help me ​

Answers

Answer for the first question

Description: When a carboxylic acid is treated with an alcohol and an acid catalyst, an ester is formed (along with water). This reaction is called the Fischer esterification. Notes: The reaction is actually an equilibrium. The alcohol is generally used as solvent so is present in large excess.

Which of the following would likely occur as a result of an oil spill in the ocean?

I. The levels of salt and other nutrients typically present in ocean water would greatly increase.
II. There would be no more upwelling of nutrients from cold ocean depths.
III. Humans would be less able to use fish and shellfish from the affected area as food.
IV. There would be global interruptions in the water cycle.
A. III only
B. IV only
C. I and III only
D. I, II, III, and IV

Answers

Answer:

D.

Explanation:

The Oil spill effects on environments and habitats can be catastrophic: they can kill plants and animals, disturb salinity/pH levels, pollute air/water and more. Read more about the types of oil pollution.

Statements that express occurrences as a result of oil spill in the ocean are:

C: I. The levels of salt and other nutrients typically present in ocean water would greatly increase.

III. Humans would be less able to use fish and shellfish from the affected area as food.

An oil spill can be regarded as a of release liquid petroleum hydrocarbon into the environment.

This release can be on land or in the body of water especially ocean, however this spillage is very dangerous to aquatic lives which indirectly affects man.

Once spillage occur, levels of salt and other nutrients will increase in the ocean and this can harm aquatic lives.

especially the marine ecosystem, due to human activity, and is a form of pollution.

Therefore option C is correct.

Learn more at:

https://brainly.com/question/19722933?referrer=searchResults

How many electrons does a single hydrogen gain or lose in the following reaction?
H2 + O2 - H20

Answers

Answer:

One electron per single hydrogen atom.

Explanation:

Hello!

In this case, given the reaction:

[tex]H_2+O_2\rightarrow H_2O[/tex]

Whereas we can identify the following half-reaction for hydrogen:

[tex]H_2^0\rightarrow H_2^+[/tex]

Whereas we see that each single hydrogen atom gains one electron in order to go from 0 to +1, which is also related to an oxidation half-reaction.

Best regards!

Calculate the mass of beryllium (Be) needed to completely react with 18.9 g nitrogen gas (N2) to produce Bez N2, which is the only product of the reaction.
A. 6.19
B. 12.29
C. 18.29
D. 36.69

Answers

Answer:

C = 18.29 g  

Explanation:

Given data:

Mass of beryllium needed = ?

Mass of nitrogen = 18.9 g

Solution:

Chemical equation:

3Be + N₂    →    Be₃N₂

now we will calculate the number of moles of nitrogen:

Number of moles = mass/molar mass

Number of moles = 18.9 g/ 28 g/mol

Number of moles = 0.675 mol

Now we will compare the moles of nitrogen and Be from balance chemical equation.

                     N₂        :       Be        

                       1          :       3

                  0.675       :      3/1×0.675 = 2.03 mol

Number of moles of Be needed are 2.03 mol.

Mass of Beryllium:

Mass = number of moles × molar mass

Mass = 2.03 mol ×   9.01 g/mol

Mass = 18.29 g  

. Predict the possible products for the following reaction and include
molecular, complete ionic, and net ionic equations.

NA2SO4 (aq) +γ (BrO3)2 (aq) --->

Answers

Answer:

Introduction

As a diligent student of chemistry, you will likely encounter tons of reactions that occur in aqueous solution (perhaps you are already drowning in them!). When ions are involved in a reaction, the equation for the reaction can be written with various levels of detail. Depending on which part of the reaction you are interested in, you might write a molecular, complete ionic, or net ionic equation.

Definitions of molecular, complete ionic, and net ionic equations

A molecular equation is sometimes simply called a balanced equation. In a molecular equation, any ionic compounds or acids are represented as neutral compounds using their chemical formulas. The state of each substance is indicated in parentheses after the formula. [Huh?]

Let's consider the reaction that occurs between \text{AgNO}_3AgNO

3

start text, A, g, N, O, end text, start subscript, 3, end subscript and \text{NaCl}NaClstart text, N, a, C, l, end text. When aqueous solutions of \text{AgNO}_3AgNO

3

start text, A, g, N, O, end text, start subscript, 3, end subscript and \text{NaCl}NaClstart text, N, a, C, l, end text are mixed, solid \text{AgCl}AgClstart text, A, g, C, l, end text and aqueous \text{NaNO}_3NaNO

3

start text, N, a, N, O, end text, start subscript, 3, end subscript are formed. Using this information, we can write a balanced molecular equation for the reaction:

\text{AgNO}_3(aq) + \text{NaCl}(aq) \rightarrow \text{AgCl}(s) + \text{NaNO}_3(aq)AgNO

3

(aq)+NaCl(aq)→AgCl(s)+NaNO

3

(aq)start text, A, g, N, O, end text, start subscript, 3, end subscript, left parenthesis, a, q, right parenthesis, plus, start text, N, a, C, l, end text, left parenthesis, a, q, right parenthesis, right arrow, start text, A, g, C, l, end text, left parenthesis, s, right parenthesis, plus, start text, N, a, N, O, end text, start subscript, 3, end subscript, left parenthesis, a, q, right parenthesis

[What kind of reaction is this?]

If we could zoom in on the contents of the reaction beaker, though, we wouldn't find actual molecules of \text{AgNO}_3AgNO

3

start text, A, g, N, O, end text, start subscript, 3, end subscript, \text{NaCl}NaClstart text, N, a, C, l, end text, or \text{NaNO}_3NaNO

3

start text, N, a, N, O, end text, start subscript, 3, end subscript. Since \text{AgNO}_3AgNO

3

start text, A, g, N, O, end text, start subscript, 3, end subscript, \text{NaCl}NaClstart text, N, a, C, l, end text, and \text{NaNO}_3NaNO

3

start text, N, a, N, O, end text, start subscript, 3, end subscript are soluble ionic compounds, they dissociate into their constituent ions in water. For example, \text{NaCl}NaClstart text, N, a, C, l, end text dissociates into one ion of \text{Na}^+Na

+

start text, N, a, end text, start superscript, plus, end superscript for every ion of \text{Cl}^-Cl

start text, C, l, end text, start superscript, minus, end superscript; these ions are stabilized by ion-dipole interactions with the surrounding water molecules. [I don't get it!]

Image of crystalline sodium chloride next to image of chloride and sodium ions dissociated in water. Each chloride ion is interacting with multiple water molecules through the positive dipole of the water, and each sodium ion is interacting with water molecules through the negative dipole of the water.

Image of crystalline sodium chloride next to image of chloride and sodium ions dissociated in water. Each chloride ion is interacting with multiple water molecules through the positive dipole of the water, and each sodium ion is interacting with water molecules through the negative dipole of the water.

Sodium chloride dissociates into sodium and chloride ions in water, and these ions become solvated by the highly polar water molecules. Image credit: "Salts: Figure 1" by OpenStax Anatomy and Physiology, CC-BY-NC-SA 4.0.

From the molecular formula, we can rewrite the soluble ionic compounds as dissociated ions to get the complete ionic equation:

\text{Ag}^+(aq) + \blueD{{\text{NO}_3}^-(aq)} + \maroonD{\text{Na}^+(aq)} + \text{Cl}^-(aq) \rightarrow \text{AgCl}(s) + \maroonD{\text{Na}^+(aq)} + \blueD{{\text{NO}_3}^- (aq)}Ag

+

(aq)+NO

3

 

(aq)+Na

+

(aq)+Cl

(aq)→AgCl(s)+Na

+

(aq)+NO

3

 

 

(aq)

+

Na

+

(aq)

+Cl

(aq)→AgCl(s)+

Na

+

(aq)

+

NO

3

 

(aq)

Weigh out the appropriate amount of HEPES sodium salt required to prepare 100 mL of a HEPES buffer that has pH 7.50 and is 90 mM in HEPES. FW for the HEPES sodium salt is 260.31. Transfer to a 150 mL beaker. Flowchart: Calculate the amount of HEPES sodium salt required to make the buffer.

Answers

Answer:

2.343 g of HEPES sodium salt is needed.

Explanation:

So, from the question above we have the following parameters which is going to help in solving this particular question.

The number of moles = 90mM, the pH = 7.50, FW for the HEPES sodium salt = 260.31, and the volume of HEPES sodium salt required = 100mL.

Therefore, the amount of HEPES sodium salt required to make the buffer = 260.31 × 9 × 0.001 = 2.343 grams of HEPES sodium salt is needed in 10mL.

according to the bohr model of an atom, what happens when an electron moves from the second energy level to the third energy level and then back to the second energy level?​

Answers

Answer:

when the atom moves to the third energy level, its energy increases. However, when it goes back to the second energy level its overall energy decreases.

Explanation:

the smallest (or innermost) energy level has the least amount of energy and the largest (or outer most) level needs the most amount of energy. In order for the electron to move from one level to the other, it would need to match the energy of that level.

what is the magnification of the eye piece on the microscope?

Answers

Answer:

The magnification is 10x

Explanation:

Answer: The magnification of the eyepiece on the microscope is the lens at the top of the microscope that the user looks through. This lens most commonly magnifies a sample by 10x

Explanation: The eyepiece magnifies the primary image produced by the objective; the eye can then use the full resolution capability of the objective. The microscope produces a virtual image of the specimen at the point of the distinct vision.

The density of toluene (C7H8) is 0.867 g/mL, and the density of thiophene (C4H4S) is 1.065 g/mL. A solution is made by dissolving 8.10 g of thiophene in 250.0 mL of toluene.
(a) Calculate the mole fraction of thiophene in the solution.
(b) Calculate the molality of thiophene in the solution.
(c) Assuming that the volumes of the solute and solvent are additive, what is the molarity of thiophene in the solution?

Answers

Considering the solution of mole fraction, molality and molarity, you obtain that:

(a) the mole fraction of thiophene in the solution is 0.039.

(b) the molality of thiophene in the solution 0.4429 [tex]\frac{moles}{kg}[/tex].

(c)  the molarity of thiophene in the solution is 0.373[tex]\frac{moles}{L}[/tex].

You know that:

Density toluene (C₇H₈)= 0.867 [tex]\frac{g}{mL}[/tex]Density thiophene (C₄H₄S)= 1.065 [tex]\frac{g}{mL}[/tex] Volume of toluene (C₇H₈)= 250 mL= 0.250 L (being 1000 mL= 1 L)Mass of thiophene (C₄H₄S)= 8.10 grams

(a) Mole fraction

The molar fraction is a way of measuring the concentration that expresses the proportion in which a substance is found with respect to the total moles of the solution.

Being the molar mass of each compound equals to:

Toluene (C₇H₈)= 92 [tex]\frac{g}{mol}[/tex]Thiophene (C₄H₄S)= 84 [tex]\frac{g}{mol}[/tex]

the number of moles of each compound can be calculated as:

Toluene (C₇H₈)= [tex]250 mLx\frac{0.867 grams}{1 mL} x \frac{1 mole}{92 grams}[/tex]= 2.35 molesThiophene (C₄H₄S)= [tex]8.10 gramsx\frac{1 mole}{84 grams}[/tex]= 0.096 moles

The total moles is obtained from the addition of the moles of the solute (C₄H₄S) and the solvent (C₇H₈):

total moles = moles C₄H₄S + moles C₇H₈ = 0.096 moles + 2.35 moles = 2.45 moles

Then, the mole fraction of thiophene in the solution can be calculated as:

[tex]mole fraction of thiophene=\frac{0.096 moles}{2.45 moles}[/tex]

Solving:

mole fraction of thiophene= 0.039

Finally, the mole fraction of thiophene in the solution is 0.039.

(b) Molality

Molality is the ratio of the number of moles of any dissolved solute to kilograms of solvent.

The Molality of a solution is determined by the expression:

[tex]Molality=\frac{number of moles of solute}{kilograms of solvent}[/tex]

In this case, you know:

number of moles of solute (C₄H₄S)= 0.096 moles Mass of solvent = [tex]250 mLx\frac{0.867 grams}{1 mL}[/tex] = 216.75 g = 0.21675 kg (being 1000 g=1 kg)  

Replacing:

[tex]Molality C_{4} H_{4}S =\frac{0.096 moles}{0.21675 kg}[/tex]

molality C₄H₄S= 0.4429 [tex]\frac{moles}{kg}[/tex]

Finally, the molality of thiophene in the solution 0.4429 [tex]\frac{moles}{kg}[/tex].

(c) Molarity

Molarity is the number of moles of solute that are dissolved in a certain volume and is determined by the following expression:

[tex]Molarity=\frac{number of moles of solute}{volume}[/tex]

Assuming that the volumes of solute and solvent are additive, you can add the volume of C₄H₄S and C₇H₈.

But first, you need yo know the volume of C₄H₄S, which can be calculated from the mass and density:

[tex]Volume C_{4} H_{4}S =8.10 grams\frac{1 mL}{1.065 grams}[/tex]= 7.606 mL= 0.007606 L

Then, the total volume of the solution is calculated as:

total volume of the solution= volume C₇H₈ + volume C₄H₄S

total volume of the solution= 0.250 L + 0.007606 L = 0.257606 L

So, the molarity of thiophene in the solution can be calculated as:

[tex]Molarity C_{4} H_{4} S=\frac{number of moles of C_{4} H_{4} S}{totalvolumeof the solution}[/tex]

Replacing:

[tex]Molarity C_{4} H_{4} S=\frac{0.096 moles}{0.257606 L}[/tex]

Solving:

Molarity C₄H₄S= 0.373 [tex]\frac{moles}{L}[/tex]

Finally, the molarity of thiophene in the solution is 0.373[tex]\frac{moles}{L}[/tex].

In summary, you get:

(a) the mole fraction of thiophene in the solution is 0.039.

(b) the molality of thiophene in the solution 0.4429 [tex]\frac{moles}{kg}[/tex].

(c)  the molarity of thiophene in the solution is 0.373[tex]\frac{moles}{L}[/tex].

Learn more about

density: brainly.com/question/952755?referrer=searchResults brainly.com/question/1462554?referrer=searchResults mole fraction: brainly.com/question/14434096?referrer=searchResults brainly.com/question/10095502?referrer=searchResults molality brainly.com/question/20366625?referrer=searchResults brainly.com/question/4580605?referrer=searchResults molarity with this example: brainly.com/question/15406534?referrer=searchResults

A solution was diluted 1/40, and the final concentration was 20%. What was the original concentration?

Answers

The original concentration : 800%

Further explanation

Given

Diluted 1/40

Final concentration 20%

Required

The original concentration

Solution

Dilution is the process of adding solvent to get a more dilute solution.

The moles(n) before and after dilution are the same.

Can be formulated :

 n₁ = n₂

M₁.V₁ = M₂.V₂

diluted 1/40(dilution factor)⇒ V₁/V₂=1/40⇒V₂/V₁=40

M₂ = 0.2(20%)

Input the value for M₁ :

M₁=M₂ x (V₂/V₁)

M₁ = 0.2 x 40

M₂ = 8(800%)

=

Which of the statements about liquids and gases are true?
Both liquids and gases have a definite volume.
O The particles in liquids and gases can move past one another
freely
Both liquids and gases have a definite shape.
Neither liquids nor gases have a definite shape.

Answers

Question:

Which of the statements about liquids and gases are true?

Answer:

The particles in liquids and gases can move past one another freely.

#CARRYONLEARNING #STUDYWELL
Question:

Which of the statements about liquids and gases are true?

Choosing:

Both liquids and gases have a definite volume.

The particles in liquids and gases can move past one another freely

Both liquids and gases have a definite shape.

Neither liquids nor gases have a definite shape.

Answer:

The particles in liquids and gases can move past one another freely.

#READINGHELPSWITHLEARNING #CARRYONLEARNING #STUDYWELL

John Dalton determined that the concept of atoms could be used to describe matter.
Which of the following is FALSE regarding John Dalton's four points about atomic theory.
A. Atoms are very small indivisible, indestructible particles.
B. Chemical compounds form when two or more kinds of atoms combine.
C. All matter is made up of atoms.
D. All molecules are identical in mass and other properties.

Answers

Answer:

D

Explanation:

I don't exactly remember his four points, but the D. is just not true anyway. For example, a molecule of water (H20) does that have the same properties or mass as Nitrogen dioxide or sulfer dioxide or something else

Answer:

The answer is D

Explanation:

As it is true that molecules are identical in mass.

dicyclopropyl ether?

Answers

Answer:

??????????????????

Explanation:

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the gravitational force between two objects depends on the distance between the objects and each object? ​

Answers

Answer:

Gravitational force between two objects depends on: a. The weight of the objects c. The mass of each object b. The distance between the objects d. Both b and c Please select the best answer from the choices provided A B C D

✓d

All the iron in a 2.000 g tablet was dissolved in an acidic solution and converted to Fe2+. This was then titrated with KMnO4. The titration required 27.50 cm3 of 0.100 mol dm-3 KMnO4. Calculate the total mass of iron in the tablet and its percentage by mass.

Answers

Answer:

0.768g of Fe are in the tablet = 38.4% by mass of Fe in the tablet

Explanation:

The balanced redox equation of Fe²⁺ with KMnO₄ in acidic medium is:

5Fe²⁺ + MnO₄⁻ + 8H⁺ → 5Fe³⁺ + Mn²⁺ + 4H₂O

Where 5 moles of Fe²⁺ react per mole of KMnO₄

The moles required of KMnO₄ are:

27.50cm³ * (1dm³ / 1000cm³) = 0.0275dm³ * (0.100mol / dm³) = 0.00275mol KMnO₄

Moles of Fe²⁺ are:

0.00275mol KMnO₄ * (5 moles Fe²⁺ / 1mol KMnO₄) = 0.01375moles of Fe²⁺

In grams (Molar mass Fe: 55.845g/mol):

0.01375moles of Fe²⁺ * (55.845g/mol) =

0.768g of Fe are in the tablet

And percentage is:

0.768g Fe / 2.000g * 100 =

38.4% by mass of Fe in the tablet
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