translate this into an equation, use n for the number: "the different of 3 times a number and 6 is twice the number."

Answer:

y= 80/9

Step-by-step explanation:

Given

" y varies directly as x" and "as the square of z" so y = x* z²* some number

if y =25/9 when x= 5, z= 1 and y = x*z²* some number

then 25/9  = 5 * 1² * some number

      5*(5/9) = 5 * some number

therefore y = x* z²* (5/9)

y= ? when x=1 , z= 4

y = x * z² * (5/9)

y = 1 * 4² * (5/9)

y = 16*5 / 9

y = 80/9

Answer:

18 units

Step-by-step explanation:

You don't need to use slope since both are using 13 for y.

22 - 4 (both x values) = 18

B. 18 units

Answer:

2/3multiply by20 u get 13.3 pounds

Answer:

∆K = 98°

∆M = 82°

∆G = 118°

∆H = 62°

Step-by-step explanation:

∆K & ∆G is by corresponding angle

and

∆M & ∆H is by linear pairs

Answer:

A,B,E,F

Step-by-step explanation:

Answer:

[tex]- 5 {x}^{3} - {x}^{2} - 11x + 7 \\ [/tex]

Step-by-step explanation:

Before solving that we have to know that,

[tex]( + ) \times ( + ) = ( + ) \\ ( - ) \times (- ) = ( + ) \\ ( + ) \times ( - ) = (- )[/tex]

Let's solve now.

[tex]7 {x}^{3} - 11x - 1 - (12 {x}^{3} + {x}^{2} - 8) \\ 7 {x}^{3} - 11x - 1 - 12 {x}^{3} - {x}^{2} + 8 \\ 7 {x}^{3} - 12 {x}^{3} - {x}^{2} - 11x - 1 + 8 \\ = - 5 {x}^{3} - {x}^{2} - 11x + 7[/tex]

Hope this helps you.

Let me know if you have any other questions :-):-)

Answer:

Step-by-step explanation:

300/100 = 3 = 1%

if 3 = 1% then 3/2 or 1.5 = 0.5%

5 x 3 = 15 = 5%

15 + 1.5 = 16.5 = 5.5%

Answer:

keep the car at a friends house untill you find a place to get it fixed at... or keep it at a trustworthy family members house.

If these don't help then im sorry.

Answer:

None of the option is correct.

The right answer is 18/7 or 2.57

Step-by-step explanation:

The sequence of the number of girl attendees at each Barangay is nonzero, given by multiplying the number of attendees in the previous Barangay by 2

The required values are;

a. The completed table is presented as follows;

[tex]\underline{\begin{array}{|l|c|c|c|c|c|c|c|}\mathbf{Barangay}&1&2&3&4&5&6&7\\\mathbf{Number \ of \ attandees}&4&8&16&32&64&128&256\end{array}}[/tex]

b. The sequence of the number of girls attendees aₙ = 4×2⁽ⁿ⁻¹⁾

c. The sum of beneficiaries of the lecture from the twelve Barangay is 16,384 girls

Reason:

Known parameters are;

Number of girls that attended the lecture at Barangay 1 = 4 girls

Number of girls that attended from Barangay 2 = 8 girls

Number that attended from Barangay 3 = 16 girls

a. The required table with the assumption that the number of girls that attended at each Barangay from Barangay 1 to Barangay 7 doubles, is presented as follows;

b. The sequence of the number of girls who attended the lecture from Barangay 1 to Barangay 7 is presented as follows;

The sequence is a geometric progression having the form, aₙ = a·r⁽ⁿ⁻¹⁾

The first term of the sequence, a = 4

The common ratio, r = 2 (each term is twice the previous term)

n = The number of terms

The sequence is therefore;

c. The total number of girls in the geometric progression, (G. P.) is given by the sum of a G. P. as follows

[tex]S_n = \dfrac{a \cdot (r^n - 1 )}{r - 1}[/tex]

Where;

n = The number of terms = 7 + 5 = 12

Which gives;

The total number of girls who will benefit from the lectures, S₁₂ = 16,384 girls

Learn more about geometric progression here:

https://brainly.com/question/14256037

Answer:

N+5

Step-by-step explanation:

4,9,14,19

4+5=9+5=14+5=19….

Answer:

75 times

Step-by-step explanation:

Answer: 0.8333

Step-by-step explanation:

As we know :

now let's plug the value of given terms :

Answer:

babawi lang sana

Step-by-step explanation:

naul pi

Answer:

The other angle's measure is 2/3 (54) = 108/3 = 36 degrees.

Answer:

a

Step-by-step explanation:

Answer:

Depends, rise over run could be considered a fraction, or if it's a number that has a whole number like one and 3/4 then you just plot the point to the best of your ability. In other words guess.

Answer:

A. Personal vacation expenses

Step-by-step explanation:

Because everything else either helps the community or is a required expense

Answer: 5h+9

Step-by-step explanation:

10h + (-5h)

5h+(6(+3))

Answer:

answer is below

Step-by-step explanation:

so 32.14 is breakable. first break it up by the tens place you have 3 tens.

next the ones place you have 2 ones

then the tenths place you have 1 tenth

then the hundredth place you have 4 hundreths

so the 3 tens is equal to 30

the 2 ones is equal to 2

the 1 tenth is equal to 0.1

the 4 hundredth is equal to 0.04  

this is easier to understand and is a good way to think about more complext numbers

Answer:

82 - 2i

Step-by-step explanation:

(5 - 2i) + (-4 + 81)

5 - 2i + 77

= 82 - 2i

1 + 6i

we open the brackets to give us

5 - 2i - 4 + 8i

collecting like terms, we have,

-2i + 8i + 5 - 4

6i + 1

or

1 + 6i

(1)

(a) Use the fact that [tex]\sqrt{x^2} = |x|[/tex] for all [tex]x[/tex]. Since [tex]x\to+\infty[/tex], we have [tex]x>0[/tex] and [tex]|x| = x[/tex].

[tex]\displaystyle \lim_{x\to\infty} \frac{\sqrt{9x^2 - 2}}{x + 4} = \lim_{x\to\infty} \frac{\sqrt{x^2} \sqrt{9 - \frac2{x^2}}}{x + 4} \\\\= \lim_{x\to\infty} \frac{ x \sqrt{9 - \frac2{x^2}}}{x+4} \\\\= \lim_{x\to\infty} \frac{\sqrt{9 - \frac2{x^2}}}{1 + \frac4x} \\\\= \frac{\sqrt9}1 = \boxed{3}[/tex]

(b) This time [tex]x\to-\infty[/tex], so [tex]x < 0[/tex] and [tex]|x| = -x[/tex].

[tex]\displaystyle \lim_{x\to\infty} \frac{\sqrt{9x^2 - 2}}{x + 4} = \lim_{x\to\infty} \frac{\sqrt{x^2} \sqrt{9 - \frac2{x^2}}}{x + 4} \\\\= \lim_{x\to\infty} \frac{ \boxed{-x} \sqrt{9 - \frac2{x^2}}}{x+4} \\\\= (-1) \times \lim_{x\to\infty} \frac{\sqrt{9 - \frac2{x^2}}}{1 + \frac4x} \\\\= -\frac{\sqrt9}1 = \boxed{-3}[/tex]

(c) We immediately have

[tex]\displaystyle \lim_{x\to\infty} (x - \sqrt x) = \boxed{\infty}[/tex]

since [tex]x > \sqrt x[/tex] for all [tex]x > 1[/tex].

(d) Introduce a difference of squares by factoring in the limand's conjugate. The rest mirrors what we did in (a)/(b).

[tex]\displaystyle \lim_{x\to\infty} \left(\sqrt{x^2 + 12x} - x\right) = \lim_{x\to\infty} \frac{\left(\sqrt{x^2+12x} - x\right) \left(\sqrt{x^2+12x} + x\right)}{\sqrt{x^2 + 12x} + x} \\\\ = \lim_{x\to\infty} \frac{\left(\sqrt{x^2+12x}\right)^2 - x^2}{\sqrt{x^2+12x}+x} \\\\ = \lim_{x\to\infty} \frac{12x}{\sqrt{x^2+12x}+x} \\\\ = \lim_{x\to\infty} \frac{12}{\sqrt{1 + \frac{12}x} + 1} = \frac{12}{\sqrt1 + 1} = \boxed{6}[/tex]

(e) Divide through by the highest-degree exponential term.

[tex]\displaystyle \lim_{x\to\infty} \frac{12e^{2x} - 3e^{3x}}{2e^{2x} + 4e^{3x}} = \lim_{x\to\infty} \frac{12e^{-x} - 3}{2e^{-x} + 4} = \frac{0 - 3}{0 + 4} = \boxed{-\frac34}[/tex]

(2) By definition of the derivative, we have

[tex]f'(x) = \displaystyle \lim_{h\to0} \frac{f(x+h) - f(x)}h[/tex]

For [tex]f(x) = \sqrt{x^2+1}[/tex], the limit becomes

[tex]f'(x) = \displaystyle \lim_{h\to0} \frac{\sqrt{(x+h)^2+1} - \sqrt{x^2+1}}h[/tex]

Factor in the conjugate.

[tex]f'(x) = \displaystyle \lim_{h\to0} \frac{\left(\sqrt{(x+h)^2+1} - \sqrt{x^2+1}\right) \left(\sqrt{(x+h)^2+1} + \sqrt{x^2+1}\right)}{h \left(\sqrt{(x+h)^2+1} + \sqrt{x^2+1}\right)}[/tex]

[tex]f'(x) = \displaystyle \lim_{h\to0} \frac{\left(\sqrt{(x+h)^2+1}\right)^2 - \left(\sqrt{x^2+1}\right)^2}{h \left(\sqrt{(x+h)^2+1} + \sqrt{x^2+1}\right)}[/tex]

[tex]f'(x) = \displaystyle \lim_{h\to0} \frac{\bigg((x+h)^2+1\bigg) - (x^2+1)}{h \left(\sqrt{(x+h)^2+1} + \sqrt{x^2+1}\right)}[/tex]

[tex]f'(x) = \displaystyle \lim_{h\to0} \frac{2xh + h^2}{h \left(\sqrt{(x+h)^2+1} + \sqrt{x^2+1}\right)}[/tex]

[tex]f'(x) = \displaystyle \lim_{h\to0} \frac{2x + h}{\sqrt{(x+h)^2+1} + \sqrt{x^2+1}}[/tex]

[tex]\implies \boxed{f'(x) = \displaystyle \lim_{h\to0} \frac{x}{\sqrt{x^2+1}}}[/tex]

(3) The tangent line to

[tex]y = \frac1{x^2+1}[/tex]

at the point (2, 1/5) has slope equal to the derivative [tex]\frac{dy}{dx}[/tex] when [tex]x = 2[/tex]. Compute the derivative; since [tex]y = \frac1{f(x)^2}[/tex] where [tex]f(x)[/tex] is the function from the previous problem, using the chain rule gives

[tex]y = \dfrac1{f(x)^2} \implies \dfrac{dy}{dx} = -\dfrac{2f'(x)}{f(x)^3} = -\dfrac{2 \times \frac{x}{\sqrt{x^2+1}}}{\left(\sqrt{x^2+1}\right)^3} \\\\ \implies \dfrac{dy}{dx} = -\dfrac{2x}{(x^2+1)^2}[/tex]

The tangent line at (2, 1/5) then has slope

[tex]\dfrac{dy}{dx}\bigg|_{x=2} = -\dfrac{2\times2}{(2^2+1)^2} = -\dfrac4{25}[/tex]

Using the point-slope formula, the equation of the tangent line is

[tex]y - \dfrac15 = -\dfrac4{25} (x - 2) \implies \boxed{y = -\dfrac{4x - 13}{25}}[/tex]

Answer:

[tex]D)\:(3x^{2} +2)(x+4)[/tex]

Step-by-step explanation:

[tex]3x^{3} + 12x^{2} + 2x + 8[/tex]

Group, [tex]3x^3+12x^2+2x+8[/tex]  [tex]=(3x^{3} +12x^{2} )+(2x+8)[/tex]factor out [tex]3x^{2}[/tex]in the first and 2 in the second group.

[tex]3x^{2} (x+4)+2(x+4)[/tex]

Factor out common term [tex]x+4[/tex] by using distributive property.

polynomial [tex]3x^{2} +2[/tex] is not factored since it does not have any rational roots.

[tex](3x^{2} +2)(x+4)[/tex]

_____________________________

Answer:d

Step-by-step explanation:

Answer:

2nd option is the correct answer

Answer:

we can do it again and I am a great time with you and your family and friends and family is not good

Answer:

x = 36 , y = 64 , z = 80

Step-by-step explanation:

Exterior angle equals the sum of opposite interior angle.

3x +  8 = x +  z

3x - x - z = -8

2x  -  z = -8   ------------ (I)

z + 3x - 8 = 180 {linear pair}

3x + z = 180 + 8

3x + z = 188 --------------(II)

Add (I) and (II) and z will be eliminated and we can find the value of 'x'

(I)            2x - z = -8

(II)           3x + z = 188   {Now add}

               5x      = 180

x = 180/5

x = 36

Plugin x = 36 in equation (II)

     3*36 +z = 188

        108 + z = 188

                z = 188- 108

z = 80

x + y + z = 180 ----------------(III)  {angle sum property of triangle}

36 + 80 +y = 180

       116 + y = 180

               y = 180 - 116

y = 64