Answer: 16 - C
Step-by-step explanation:
So basicly, what it is asking is to solve this problem. I would like to call it a puzzle because there is a missing part that we have to find. Let's get this started!
Here is the equaiton: 2 x (8 - C)
First, we will multiply 8 by 2.
8 x 2 = 16
Now the equation is: 16 - C
We don't know what C is, so this equation is as done as we can do it.
help with math pls pls
Answer:
62 degrees
Step-by-step explanation:
If 167 degrees is the whole angle measurement, then you take 167-105.
If c = 2m + d , which equation represents m ?
A.m=c- d/2
B.m=d-2c
C.m=c/2-d
D.m= c-d/2
Answer:
c
Step-by-step explanation:
c/2-d
Big chickens: The weights of broilers (commercially raised chickens) are approximately normally distributed with mean 1387 grams and standard deviation 192 grams. Use the TI-84 Plus calculator to answer the following. (a) What proportion of broilers weigh between 1150 and 1308 grams? (b) What is the probability that a randomly selected broiler weighs more than 1510 grams? (c) Is it unusual for a broiler to weigh more than 1610 grams? Round the answers to at least four decimal places.
Answer:
a) 0.2318
b) 0.2609
c) No it is not unusual for a broiler to weigh more than 1610 grams
Step-by-step explanation:
We solve using z score formula
z-score is is z = (x-μ)/σ, where x is the raw score, μ is the population mean, and σ is the population standard deviation.
Mean 1387 grams and standard deviation 192 grams. Use the TI-84 Plus calculator to answer the following.
(a) What proportion of broilers weigh between 1150 and 1308 grams?
For 1150 grams
z = 1150 - 1387/192
= -1.23438
Probability value from Z-Table:
P(x = 1150) = 0.10853
For 1308 grams
z = 1308 - 1387/192
= -0.41146
Probability value from Z-Table:
P(x = 1308) = 0.34037
Proportion of broilers weigh between 1150 and 1308 grams is:
P(x = 1308) - P(x = 1150)
0.34037 - 0.10853
= 0.23184
≈ 0.2318
(b) What is the probability that a randomly selected broiler weighs more than 1510 grams?
1510 - 1387/192
= 0.64063
Probabilty value from Z-Table:
P(x<1510) = 0.73912
P(x>1510) = 1 - P(x<1510) = 0.26088
≈ 0.2609
(c) Is it unusual for a broiler to weigh more than 1610 grams?
1610- 1387/192
= 1.16146
Probability value from Z-Table:
P(x<1610) = 0.87727
P(x>1610) = 1 - P(x<1610) = 0.12273
≈ 0.1227
No it is not unusual for a broiler to weigh more than 1610 grams
What is the slope of the line that passes through the points (4,2) and (-16, -10)?
Write your answer in simplest form.
Answer:
3/5
Step-by-step explanation:
Answer:
Yup the answer is 3/5 :))
Step-by-step explanation:
Help me plz
8th grade math
Answer
I would say the 3rd one.
Step-by-step explanation:
I do not really remember this but I am in 8th grade math to (Algebra)
An electrican's shop charges $55
service fee plus $50 per hour for labor.
The linear equation that models
C= $50+ $55, where h is the number of labor hours and C is the total cost.
How much would the shop charge a customer for a job that takes 17hrs?
Answer:
$905
Step-by-step explanation:
$50×h+55=?
h=17 and you pay so $50×h
so $50×h=850
so now that you calculated the cost of the labor add the $55 dollar service fee
850+55=905
In , the Pew Internet & American Life Project asked teens aged to several questions about their attitudes toward social media. The results showed that say social media makes them feel more connected to what is going on in their friends' lives; say social media helps them interact with a more diverse group of people; and feel pressure to post content that will get a lot of likes and comments.
Round your answers to four decimal places.
a. Develop a point estimate of the proportion of teens aged to who say social media makes them feel more connected to what is going on in their friends' lives.
b. Develop a point estimate of the proportion of teens aged to who say social media helps them interact with a more diverse group of people.
c. Develop a point estimate of the proportion of teens aged to who feel pressure to post content that will get a lot of likes and comments.
Complete Question
The complete question is shown on the first uploaded image
Answer:
a
[tex]\^ p_1 = 0.8102 [/tex]
b
[tex]\^ p_2 = 0.6904 [/tex]
c
[tex]\^ p_3 = 0.3701 [/tex]
Step-by-step explanation:
From the question we are told that
The sample size is n = 743
The number that said social media makes them feel more connected to what is going on in their friends' lives is k = 602
The number that said social media helps them interact with a more diverse group of people is y = 513
The number that said feel pressure to post content that will get a lot of likes and comments is c = 275
Generally a point estimate of the proportion of teens aged 13 to 17 who say social media makes them feel more connected to what is going on in their friends' lives is mathematically represented as
[tex]\^ p_1 = \frac{k}{n}[/tex]
=> [tex]\^ p_1 = \frac{602}{743 }[/tex]\
=> [tex]\^ p_1 = 0.8102 [/tex]
Generally a point estimate of the proportion of teens aged 13 to 17 who say social media helps them interact with a more diverse group of people is mathematically represented as
[tex]\^ p_2 = \frac{k}{n}[/tex]
=> [tex]\^ p_2 = \frac{513}{743 }[/tex]\
=> [tex]\^ p_2 = 0.6904 [/tex]
Generally a point estimate of the proportion of teens aged 13 to 17 who feel pressure to post content that will get a lot of likes and comments is mathematically represented as
[tex]\^ p_3 = \frac{k}{n}[/tex]
=> [tex]\^ p_3 = \frac{275}{743 }[/tex]
=> [tex]\^ p_3 = 0.3701 [/tex]
The point estimate of the teens aged to who say social media makes them feel more connected is 0.8102.
How to calculate the point estimateThe point estimate of the proportion of teens aged to who say social media makes them feel more connected to what is going on in their friends' lives will be:
= Number of teens / Sample size
= 602/743
=™0.8102
The point estimate of the proportion of teens aged to who say social media helps them interact with a more diverse group of people will be:
= 513/743
= 0.6904
The point estimate of the proportion of teens aged to who feel pressure to post content that will get a lot of likes and comments will be:
= 275/743
= 0.3701
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Felipe has a flower bed with area 25/4 ft.squared. He expands the flower bed to have area 75/4 ft.squared. How many square ft of space does the larger flower bed have for every square foot of the smaller flower bed?
Answer: 3
Step-by-step explanation:
Given data:
Area of smaller flower bed = 25/4
Area of bigger flower bed = 75/4.
Solution:
75/4 = 25/4
Divide both sides 5
15/4 = 5/4
= 15/4 / 5/4
= 15/4 / 4/5
= 3
Answer:
The larger flower bed has 3 square ft of space for every square foot of the smaller flower bed
Step-by-step explanation:
In other words in this question, we are asked to calculate how many of the smaller flower bed is contained in the larger one.
Mathematically, that would be 25/4 squares ft divided by 75/4 squared feet
Thus will be 75/4 divided by 25/4
Hence 75/4 * 4/25 = 3
Question 1. Write a function called simulate that generates exactly one simulated value of your test statistic under the null hypothesis. It should take no arguments and simulate 50 area codes under the assumption that the result of each area is sampled from the range 200-999 inclusive with equal probability. Your function should return the number of times you saw the 781 area code in those 50 random spam calls.
Answer:
The function written in python is as follows:
import random
def simulate():
count = 0
for i in range(1,51):
num = random.randint(200,1000)
if num == 781:
count = count + 1
print(count)
Step-by-step explanation:
This line imports the random library
import random
This line defines the function
def simulate():
This line initializes count to 0
count = 0
This line iterates from 1 to 50
for i in range(1,51):
This line generates random number between 200 and 999
num = random.randint(200,1000)
This line checks if random number is 781
if num == 781:
If yes, the count variable is incremented by 1
count = count + 1
This line prints the number of times 781 is generated
print(count)
There are 3,785 milliliters in 1 gallon, and there are 4 quarts in 1 gallon.
How many milliliters are in 3 gallons? Explain.
there are 11356.2 milliliters in 3 us gallons
Divide polynomials using long division
(10h+20)÷(h+2)
Answer:
10
Step-by-step explanation:
Put the h+2 on the outside and 10h+20 on the inside
h+2 can go into 10h+20 ten times.
So the final answer is 10
what is the sum a 23 and 4 /4
Answer:
the anwser is 24 please mark brianliest
Answer:
The answer is 24.
#9A
What is a reasonable first step to solve for y?
1/ 4x + 3y = 2z
Based only on the given information, it is guaranteed that Ac = bc
Answer:
True
Step-by-step explanation:
True because if AC = BC, then the triangles are the same.
The side AC is congruent to the side BC the statement is true.
What is congruency?The Side-Angle-Side Congruence Theorem (SAS) defines two triangles to be congruent to each other if the included angle and two sides of one are congruent to the included angle and corresponding two sides of the other triangle.
In the given figure we can see that the ∠ACD ≅ ∠BCD and AB ⊥ CD mean that the line CD is dividing the line AB into two equal parts.
Therefore, the side AC is congruent to the side BC the statement is true.
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The output from the machine depends on the input to to
A.
B.
C.
D.
Answer:
i think its B
Step-by-step explanation:
Andy is scuba diving. He starts at sea level and then descends 10 feet in 212 minutes.
Descent = 10 feet
Time required = 2 1/2 minutes.
The rate of descent = (10 feet)/(2.5 mn) = 4 ft/min
In 6 minutes, the descent will be
(4 ft/min)*(6 min) = 24 ft
Answer:
(a) 4 feet/minute
(b) 24 feet
COLLE
past d
see co
A boat capsized and sank in a lake Based on an assumption of a mean weight of 131 lb, the boat was rated to carry 60 assengers (s the load lin was 7,860 lb).
After the boat sank, the assumed mean weight for similar boats was changed from 131 lb to 173 lb Complete parts a and below.
a. Assume that a similar boat is loaded with 60 passengers, and assume that the weights of people are normally distributed with a mea of 176 1 lb end a standard
deviation of 40.2 lb. Find the probability that the boat is overloaded because the 60 passengers have a mean weight greater than 131 ||
The probability is
(Round to four decimal places as needed)
b. The boat was later rated to carry only 17 passengers, and the load limit was changed to 2,941 lb. Find the probability t at the boat is erloaded bause the
mean weight of the passengers is greater than 173 (so that their total weight is greater than the maximum capacity of 29 1 lb)
The probability is
(Round to four decimal places as needed)
Do the new ratings appear to be safe when the boat is loaded with 17 passengers? Choose the correct answer below.
sees o
ents
see sc
see sco
past do
O A. Because the probability of overloading is lower with the new ratings than with the old ratings, the new ratings appes to be safe
OB. Because there is a high probability of overloading, the new ratings appear to be safe when the boat is loaded with passengers
OC. Because there is a high probability of overloading, the new ratings do not appear to be safe when the boat is loaded with 17 passe ers:
Click to select your answer(s)
past due
find the value of each missing variable?
Step-by-step explanation:
9x - 2 = 5x + 54 because these angles are corresponding
9x - 5x = 54 + 2 add/subtract like terms
4x = 56 and this divided by 4
x = 14
9x - 2 + 10y + 6 = 180° because these two angles makes a straight line
9×14 - 2 + 10y + 6 = 180°
126 - 2 + 10y + 6 = 180° add like terms
130 + 10y = 180° subtract 130 from both sides
10y = 50 divide by 10
y = 10
To find the quotient of 8 divided by one-third, multiply 8 by
One-eighth.
One-third.
3.
8.
Answer:
The answer is 3
Step-by-step explanation:
To find the quotient of 8 divided by 1/3 multiply 8 by
8/1 divided by 1/3
8 x 3
-------
1 x 1
=
24/1
=
24
The quotient of 8 divided by one-third is same as multiply 8 by 3.
What is Division method?Division method is used to distributing a group of things into equal parts. Division is just opposite of multiplications.
For example, dividing 20 by 2 means splitting 20 into 2 equal groups of 10.
We have to given that;
The quotient of 8 divided by one-third.
Now, We get;
The quotient of 8 divided by one-third.
⇒ 8 ÷ 1/3
⇒ 8 × 3
Thus, It is clear from the above steps that dividing 8 by 1/3 is equivalent to multiplying 8 by 3.
Therefore, Multiplying 8 by 3 will give the same quotient.
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Every time you have your cholesterol measured, the measurement may be slightly different due to random fluctuations and measurement error. Suppose that for you, the population of possible cholesterol measurements if you are healthy has a mean of 190 and a standard deviation of 10. Further, suppose you know you should get concerned if your measurement ever gets up to the 97th percentile. What level of cholesterol does that represent?
Complete Question
The complete question is shown on the first uploaded image
Answer:
a i
[tex]P(X < 185 ) = 0.3085 [/tex]
a ii
[tex]P(X > 195 ) = 0.3085 [/tex]
a iii
[tex]P(185 < X < 195 ) = 0.3829 [/tex]
b
[tex]x = 208.8[/tex]
Step-by-step explanation:
From the question we are told that
The mean is [tex]\mu = 190[/tex]
The standard deviation is [tex]\sigma = 10[/tex]
Generally the probability is less than 185 is mathematically represented as
[tex]P(X < 185 ) = P(\frac{X - \mu }{\sigma } < \frac{185 - 190 }{10 } )[/tex]
Generally [tex]\frac{X - \mu }{\sigma } = Z (The \ standardized \ value \ \ of \ X)[/tex]
=> [tex]P(X < 185 ) = P(Z< -0.5)[/tex]
From the z-table the p value of (Z< -0.5) is
[tex]P(Z< -0.5) = 0.3085[/tex]
So
[tex]P(X < 185 ) = 0.3085 [/tex]
Generally the probability is less than 185 is mathematically represented as
[tex]P(X > 195 ) = P(\frac{X - \mu }{\sigma } > \frac{195 - 190 }{10 } )[/tex]
=> [tex]P(X > 195 ) = P(Z > 0.5)[/tex]
From the z-table the p value of (Z > 0.5) is
[tex]P(Z > 0.5) = 0.3085[/tex]
So
[tex]P(X > 195 ) = 0.3085 [/tex]
Generally the probability is less than 185 is mathematically represented as
[tex]P(185 < X < 195 ) = P( \frac{185 - 190 }{10 } < \frac{X - \mu }{\sigma } < \frac{195 - 190 }{10 } )[/tex]
=> [tex]P(185 < X < 195 ) = P(-0.5 < Z > 0.5)[/tex]
=> [tex]P(185 < X < 195 ) = P(Z < 0.5 ) - P(Z < -0.5) [/tex]
From the z-table the p value (Z < 0.5) and (Z < -0.5) is
[tex]P(Z < 0.5) = 0.6915 [/tex]
and
[tex]P(Z < - 0.5) = 0.3085[/tex]
So
=> [tex]P(185 < X < 195 ) = 0.6915 - 0.3085 [/tex]
=> [tex]P(185 < X < 195 ) = 0.3829 [/tex]
Generally the level of cholesterol the 97th percentile represents is mathematically evaluated as
[tex]P(X < x ) = 0.97[/tex]
=> [tex]P(X < x ) = P(\frac{X - \mu}{\sigma } < \frac{x - 190}{10 } ) = 0.97[/tex]
=> [tex]P(X < x ) = P(Z < \frac{x - 190}{10 } ) = 0.97[/tex]
From the z-table the z-score for 0.97 is
[tex]z-score = 1.88[/tex]
=>
[tex]\frac{x - 190}{10 } = 1.88[/tex]
=>[tex]x = 208.8[/tex]
find the slope of the graphed line
Answer:
B
Step-by-step explanation:
y2-y1/x2-x1
4-2/4-0
2/4=1/2
Answer: 1/2
Explanation: the equation is y = 1/2x + 2
Wite the number
in standered form 80+9=
Answer:
89
eighty-nine
I need help with this question
Answer:
49 or 1
Step-by-step explanation:
answer 1 14+10+13+12=49 answer 2 (14+10)-(13+12)=1
Helppp need help (p.s: Zearn
(50×20) - (1×20)
Step-by-step explanation:
there is 50 twenties (20) so its 50 × 20 and 1 twenty is 20
Help please
-x^3 = 216
a. +/- 6
B. 6
C. -6 ∛6
D. -6
Answer:
D. -6
Step-by-step explanation:
SInce x is negative, the - before the six would be cancelled out leaving the equation to be 6^3=216 which is correct
find the value of 2 devide3times16
Answer:
32/3
Step-by-step explanation:
Benjamin owns a small Internet business. Besides himself, he employs nine other people. The salaries earned by the employees are given next in thousands of dollars (Benjamin's salary is the largest, of course): 30, 30, 45, 50, 50, 50, 55, 55, 60, 75.
Required:
a. Determine the mean, median, and mode for salary.
b. Business has been good! As a result. Benjamin has a total of $25.000 in bonus pay to distribute to his employees. One option for distributing bonuses is to give each employee (including himself) $2500. Add the bonuses under this plan to the original salaries to create a new data set. Recalculate the mean, median, and mode. How do they compare to the originals?
c. As a second option. Benjamin can give each employee a bonus of 5% of his or her original salary. Add the bonuses under this second plan to the original salaries to create a new data set. Recalculate the mean, median, and mode. How do they compare to the originals?
d. As a third option, Benjamin decides not to give his employees a bonus at all. Instead, he keeps the $25,000 for himself. Use this plan to create a new data set. Recalculate the mean, median, and mode. How do they compare to the originals?
Answer:
a) mean μ = 50 median M = 50 mode Md = 50
b) mean μ₂ = 52,5 median M = 52,5 mode Md = 52,5 all vales increased in 2,5 ( thousands of $) the same quantity of individuals incements
c) mean μ₃ = 52,50 median M = 52,5 mode Md = 52,5 The same values obtain in b)
d) mean μ₃ = 52,50 median M = 50 and Mode 50
Step-by-step explanation:
a) Mean μ is the average then:
30 30 45 50 50 50 55 55 60 75
μ = 50
The median M, is the central (fifth value) 50
And the mode
Md = 50
b) Adding 2,5 ( in thousands of $) to each one of the employees
32,5 32,5 47,5 52,5 52,5 52,5 57,5 57,5 62,5 77,5
The mean μ₂ = 52,5 $, since the average value has to be increased by the common increased number
The median M = 52,5 and also the mode Md = 52,5
c) 31,5 31,5 47,25 52,5 52,5 52,5 57,75 57,75 63 78,75
The mean μ₃ = 52,50
The median M = 52,50
The Mode Md = 52,50
d) 30 30 45 50 50 50 55 55 60 100
μ₄ = 52,5
Median M = 50
Mode Md = 50
Would 3.99. million flies or 47,000,000 ants have a greater mass
Ants
Step-by-step explanation:
this is an simplified or not?
[tex] \frac{3}{x - 5?} [/tex]
A manufacturer has designed a process to produce pipes that are 10 feet long. The distribution of the pipe length, however, is actually Uniform on the interval 10 feet to 10.57 feet. Assume that the lengths of individual pipes produced by the process are independent. Let X and Y represent the lengths of two different pipes produced by the process. h)What is the probability that the second pipe (with length Y) is more than 0.11 feet longer than the first pipe (with length X)
The probability that the second pipe (with length Y) is more than 0.11 feet longer than the first pipe (with length X) is approximately 2.6092%.
Here,
Since the length of the pipes follows a uniform distribution on the interval [10 feet, 10.57 feet], the probability density function (PDF) for each pipe is:
f(x) = 1 / (10.57 - 10) = 1 / 0.57 ≈ 1.7544 for 10 ≤ x ≤ 10.57
Since the lengths of the pipes are independent, the joint probability density function (PDF) of X and Y is the product of their individual PDFs:
f(x, y) = f(x) * f(y) = 1.7544 * 1.7544 = 3.0805 for 10 ≤ x ≤ 10.57 and 10 ≤ y ≤ 10.57
Now, we want to find the probability that the second pipe (Y) is more than 0.11 feet longer than the first pipe (X).
Mathematically, we want to find P(Y > X + 0.11).
Let's set up the integral to calculate this probability:
P(Y > X + 0.11) = ∬[10 ≤ x ≤ 10.57] [y > x + 0.11] f(x, y) dx dy
We integrate with respect to x first and then with respect to y:
P(Y > X + 0.11) = ∫[10 ≤ y ≤ 10.57] ∫[10 ≤ x ≤ y - 0.11] f(x, y) dx dy
P(Y > X + 0.11) = ∫[10 ≤ y ≤ 10.57] [∫[10 ≤ x ≤ y - 0.11] 3.0805 dx] dy
P(Y > X + 0.11) = ∫[10 ≤ y ≤ 10.57] [3.0805 * (x)] from x = 10 to x = y - 0.11 dy
P(Y > X + 0.11) = ∫[10 ≤ y ≤ 10.57] [3.0805 * (y - (10 - 0.11))] dy
P(Y > X + 0.11) = 3.0805 * ∫[10 ≤ y ≤ 10.57] (y - 9.89) dy
P(Y > X + 0.11) = 3.0805 * [(y² / 2) - 9.89y] from y = 10 to y = 10.57
P(Y > X + 0.11) = 3.0805 * [((10.57)² / 2) - 9.89 * 10.57 - (((10)² / 2) - 9.89 * 10)]
P(Y > X + 0.11) = 3.0805 * [((111.7249 / 2) - 104.9135 - (50 / 2 - 98.9)]
P(Y > X + 0.11) = 3.0805 * [(55.86245 - 104.9135 + 49.9)]
P(Y > X + 0.11) = 3.0805 * [0.84895]
P(Y > X + 0.11) ≈ 2.6092
Therefore, the probability that the second pipe (with length Y) is more than 0.11 feet longer than the first pipe (with length X) is approximately 2.6092%.
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