The conservationist expects to be in the lake would be; 142 trouts.
What is an equation?An equation is an expression that shows the relationship between two or more numbers and variables.
Given, that determine the number of trout in a lake, a conservationist catches 200 trout, tags them, and throws them back into the lake.
We have to find conservationists who expect to be in the lake.
Now, initially, trout count = 200
Then, again 56 trouts caught then, trout count = 200 + 56
But 14 of them are tagged that means; they are part of 200 trouts so we should not count again in 56 trouts.
So, trout count = 200 + 56 – 14 = 142.
Hence, the conservationist expects would be; 142 trouts.
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Apply the laws of exponents to evaluate the expression.
(0.5) (0.5) 4
(0.5)²
After evaluation using the exponential laws, the expression "(0.5)∧(0.5)∧4 + (0.5)²" is evaluated as 2(0.5)².
What are exponents?Exponentiation is a mathematical operation that involves the base b and the exponent or power n. It is written as bn and is pronounced as "b to the n." There are four different types of exponents: positive, negative, zero, and rational/fractional. By interpreting the exponent as the total number of times the base number must be multiplied by the same base, one can determine the value of the number. Exponents laws: Keep the base constant when multiplying like bases and add the exponents. Keep the base constant and multiply the exponents when raising a base with power to another power. When dividing with like bases, keep the base constant and deduct the exponents of the numerator and denominator.So, evaluate "(0.5)∧(0.5)∧4 + (0.5)²" using laws of exponents:
Then,
(0.5)∧(0.5)∧4 + (0.5)By law: Power of power rule
(0.5)∧(0.5)×4 + (0.5)(0.5)²+ (0.5)²2(0.5)²Therefore, after evaluation using the exponential laws, the expression "(0.5)∧(0.5)∧4 + (0.5)²" is evaluated as 2(0.5)².
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The correct question is given below:
Apply the laws of exponents to evaluate the expression.
(0.5)∧(0.5)∧4 + (0.5)²
What is the equation, in slope-intercept form, of the line that is perpendicular to the given line and passes through the point (2, −1)? y = Negative one-thirdx − One-third y = Negative one-thirdx − Five-thirds y = 3x − 3 y = 3x − 7
1st , 3rd & 5th choices
Step-by-step explanation:
perpendicular line would have a slope that is a
negative reciprocal
so if the slope is 3 then a perpendicular line would have a slope of -1/3
y - 1 = 1/3 (x + 2)
make the line look like y = mx + b
y = 1/3 (x + 2) + 1
y = 1/3 (x + 2) + 3/3
y = 1/3x + 2/3 + 3/3
y = 1/3x + 5/3
m = 1/3
perpendicular line has a slope of
m = -3
Past due I don't really understand, what's the answer??
Answer:
$50.16
Step-by-step explanation:
id.k if it's actually right but i believe the tip would be $8.36 if it's 20% so adding it together is $50.16
Draw and label a figure that shows line z intersecting plane R at point M.
A figure that shows line z intersecting plane R at point M could be like:
The plane is black, the line is red and the point is blue.
PLEASE HELP! this is probably easy, THANK YOU!
Answer:
The percent change in attendance from the 2014 to 2015 school year is a 11.5385% decrease, or 12% when rounded.
Make sure to mark as Brainliest if this is correct so others know that this is the correct answer.
Answer:
r u cheating or just need "HELP"
Step-by-step explanation:
Solve the trig equation on the interval [tex]0 \leqslant theta \: \ \textless \ 2\pi[/tex][tex]3 sec \: \: theta \: - 2 \sqrt{3 } = 0[/tex]
Answer:
pi/6 and 11pi/6
Explanation
Given the trigonometry equation:
[tex]\begin{gathered} 3\text{sec}\theta\text{ - 2}\sqrt[]{3}=0 \\ \end{gathered}[/tex]Add 2\sqrt[3] to both sides as shown;
[tex]\begin{gathered} 3\sec \theta-2\sqrt[]{3}=0+2\sqrt[]{3} \\ 3\sec \theta\text{ = 2}\sqrt[]{3} \\ \sec \text{ }\theta\text{ = }\frac{2\sqrt[]{3}}{3} \\ \frac{1}{\cos \theta}=\frac{2\sqrt[]{3}}{3} \\ \cos \theta\text{ =}\frac{3}{2\sqrt[]{3}} \\ \cos \text{ }\theta\text{ = }\frac{3\sqrt[]{3}}{2\cdot3} \\ \cos \text{ }\theta\text{ = }\frac{\sqrt[]{3}}{2} \\ \end{gathered}[/tex]Take the cos inverse of both sides
[tex]\begin{gathered} \cos ^{-1}(\cos \theta)=cos^{-1}\frac{\sqrt[]{3}}{2} \\ \theta=cos^{-1}\frac{\sqrt[]{3}}{2} \\ \theta=30^0 \end{gathered}[/tex]Since theta is between 0 and 2pi
theta = 360 - 30
theta = 330^0
Convert to radians
180^0 = pi rad
30^0 = x
180x = 30pi
x = 30pi/180
x = pi/6
Similarly;
180^0 = pi rad
330^0 = x
180x = 330pi
x = 330pi/180
x = 11pi/6
Hence the value of thets between 0 and 2pi are pi/6 and 11pi/6
3. Arrange the like terms in columns and add them. - a) 2x³ - 7x⁴ + 7x⁵ and 11x³ - 4x⁴ – x b) -2p - 3p² and 1 - 5p + 8p²
The required solution of the expressions is (a) 7x⁵ + 13³ - 11x⁴ - x, (b) 5p² - 7p + 1.
Given that,
To arrange the like terms in columns and add them. - a) 2x³ - 7x⁴ + 7x⁵ and 11x³ - 4x⁴ – x b) -2p - 3p² and 1 - 5p + 8p².
The algebraic expression consists of constant and variable. eg x, y, z, etc.
Here,
(a)
= 2x³ - 7x⁴ + 7x⁵ + 11x³ - 4x⁴ – x
= 7x⁵ - 7x⁴ - 4x⁴+ 2x³ + 11x³– x
= 7x⁵ + 13³ - 11x⁴ - x,
(b)
= -2p - 3p² + 1 - 5p + 8p²
= 1 -2p - 5p -3p² + 8p²
= 1 - 5p + 8p²
Thus, the required solution of the expressions is (a) 7x⁵ + 13³ - 11x⁴ - x, (b) 5p² - 7p + 1.
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The required solutions to the given polynomials are 13x³- 11x⁴+ 7x⁵ – x and - 7p + 5p²+ 1.
What is a polynomial?A polynomial is defined as a mathematical expression that has a minimum of two terms containing variables or numbers.
The polynomials are given in the question :
2x³ - 7x⁴ + 7x⁵, and 11x³ - 4x⁴ – x
-2p - 3p² and,1 - 5p + 8p²
According to the question,
⇒ 2x³ - 7x⁴ + 7x⁵ + 11x³ - 4x⁴ – x
Rearrange the terms and apply the arithmetic operation,
⇒ 2x³ + 11x³- 7x⁴- 4x⁴ + 7x⁵ – x
⇒ 13x³- 11x⁴+ 7x⁵ – x
⇒ -2p - 3p² + 1 - 5p + 8p²
Rearrange the terms and apply the arithmetic operation,
⇒ -2p - 5p - 3p² + 8p²+ 1
⇒ - 7p + 5p²+ 1
Thus, the required solutions to the given polynomials are 13x³- 11x⁴+ 7x⁵ – x and - 7p + 5p²+ 1.
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a department store chain is expanding into a new market, and is considering 16 different sites on which to locate 7 stores. assuming that each site is equally likely to be chosen, in how many ways can the sites for the new stores be selected?
A department store chain that is entering a new area is looking at 16 possible locations for the placement of its 7 outlets. There are 57657600 many possible ways to the sites for the new stores.
Given that,
A department store chain that is entering a new area is looking at 16 possibility locations for the placement of its 7 outlets.
We have to find how many different possibility are there to choose the locations for the new businesses, provided that each site has an equal chance of being chosen.
By multiplying the number of possibilities each store has, we may determine the total number of ways.
It can be put on 16 sites for store 1. 15 locations can accommodate Store 2 (since store 1 is already on site 1). Up until shop 7, which has 10 sites, store 3 can be situated on 14 sites.
The quantity of ways is thus:
= 16 × 15 × 14 × 13 × 12 × 11 × 10
= 57657600
Therefore, there are 57657600 many possible ways to the sites for the new stores.
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A farm is being divided so that each section of land has equal access
to the canal running through the property for watering crops. If the road on the
opposite side of the property runs parallel to the canal, explain how this can be
done.
The best way to divide the land having canal and road parallel, is divide land with the line perpendicular to the road and canal.
What is parallel and perpendicular?
In simple geometry, two geometric objects cross at a right angle (90 degrees or /2 radians) if they are perpendicular to one another. The perpendicular symbol,⟂, can be used to graphically depict the condition of perpendicularity. It can be defined between two planes, between two lines (or line segments), and between two lines.
In geometry, parallel lines are coplanar, straight lines that never intersect. Any parallel planes in the same three-dimensional space are those that never intersect. Parallel curves are those that have a predetermined minimum separation between them and do not touch or intersect.
We need to give equal access of canal to each section of land so, the best way to divide land is divide land perpendicularly to canal and the road.
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Write a verbal sentence to represent each equation.
9.3n-3579
10. 2(n³ + 3n²) = 4n
11.
5n
n+3
-=n-8
The expression's variables can be represented by a different symbol than the conventional x and y.
A mathematical assertion represented in English is known as a verbal expression.What does an algebraic verbal model mean?Talking Model is a formula utilizing the terms found in the problem. Labels matching variables or numerical values to the linguistic model Equational Expression Modification of the Verbal Model by the substitution of mathematical values and variables.How to Convert Algebraic Expressions to Verbal Expressions.
Step 1: Recognize the algebraic operations—such as addition, subtraction, multiplication, and division—used in the expression.Step 2: Write a statement in which a vocabulary word is combined with the numbers to represent each of these processes.Therefore, the expression's variables can be represented by a different symbol than the conventional x and y.
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a bike that goes from 6m/s to 16m/s in 20 seconds.
The initial velocity = vi = 6m/s
The final velocity = vf = 16 m/s
The total time = t = 20 seconds
The rate of change in velocity is called acceleration (a) that can be written as:
[tex]a\text{ = }\frac{Change\text{ in velocity}}{time}[/tex]
or
[tex]a\text{ = }\frac{vf-vi}{t}[/tex]Put the values in the equation to get the value of 'a'.
[tex]a\text{ = }\frac{16\text{ - 6}}{20}[/tex][tex]a\text{ = }\frac{10}{20}[/tex]or
[tex]a\text{ = }\frac{1}{2}[/tex]hence, the value of a is 1/2.
Select the correct answer.
Which of the following represents a function?
A. The first graph
B. The second graph
C. {(0,1), (3,2), (-8,3), (-7,2), (3,4)}
D.
x -5 -1 9 8 -1
y 1 7 23 17 1
Answer:
The answer is to the question A
Answer:
Its B 100%
i took the test and got it right
k bye :):):):):):):)
Step-by-step explanation:
How many students age 15 and above take a car to school? Show work
A. 18
B. 38
C. 87
im pretty sure its B or most likeley C
What is the slope of a line perpendicular to the line whose equation is 3x+18y=108. Fully simplify
The slope of the line which is perpendicular to the given line 3x+18y=108 is (6).
What is the slope?The slope is the ratio of the vertical changes to the horizontal changes between two points of the line.
We already know the equation of a line in slope intercept form y = mx + b and we also know that perpendicular lines that have slopes which are negative reciprocals of each other.
Given a line 13x + 18y=108, this slope intercept form can be written as,
3x + 18y = 108
18y = 108 - 3x
y = (108 /18) - (3/18)x.
y = (6) - 1x/6.
y = -(1/6)x + 6.
∴ The slope of the given line is (-1/6), thus the slope of the line which is perpendicular is (6).
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Evaluate log2 10 using the change of base formula. Round your answer to the nearest thousandth.
Take into account the following property:
[tex]\log _ab=\frac{\log b}{\log a}[/tex]Then, for the given expression you have:
[tex]\log _210=\frac{\log10}{\log2}=\frac{1}{\log }\approx3.322[/tex]Hence, the answer is approximately 3.322
Determine the number of terms in the arithmetic sequence below:-70, -69, -68, ..., 37, 38, 39, 40
Number of terms of sequence N
Difference D = -1
Then there are here
In negative part, 70 numbers
In positive x line, 40 numbers
And add also zero
Then, ANSWER IS
N= 70 + 40 + 1
. = 111
There are 111 numbers
Find the range, the standard deviation, and the variance for the given samples. Round non-integer results to the nearest tenth.−10, −16, −21, −24, −4, −30, −32 range ________standard deviation __________variance __________
From the given values, we can see that the lowest values is -32 and the highest value ie -4. Since the range is the difference betwwwn the highest and the lowest value, the range is
[tex]\begin{gathered} \text{Range}=-4-(-32) \\ \text{Range}=28 \end{gathered}[/tex]On the other hand, the sample variance formula is
[tex]S^2=\sqrt[]{\frac{\sum ^7_{n\mathop=1}(x-\bar{x})^2}{n-1}}[/tex]where x^bar is the mean and n is the total number of sample elements. In our case, n=7 and the mean is
[tex]\begin{gathered} \bar{x}=\frac{-10-16-21-24-4-30-32}{7} \\ \bar{x}=-\frac{137}{7} \\ \bar{x}=-19.5714 \end{gathered}[/tex]Then, the sample variance is given by
[tex]\begin{gathered} S^2=\frac{(-10-19.57)^2+(-16-19.57)^2+(-21-19.57)^2+\cdot\cdot\cdot+(-32-19.57)^2}{6} \\ S^2=105.2857 \end{gathered}[/tex]Since the standard deviation is the square root of the sample variance, we have
[tex]\begin{gathered} S=\sqrt[]{105.2857} \\ S=10.26088 \end{gathered}[/tex]By rounding the solutions to the nearest tenth, the answers are:
[tex]\begin{gathered} \text{Range}=28 \\ \text{Variance}=105.3 \\ \text{ Standard deviation = 10.3} \end{gathered}[/tex]Find the mean and population standar deviation for each data set.
Hours slept
Mean of given set is 7.8
Define mean.The sum of all values divided by the total number of values determines the mean (also known as the arithmetic mean, which differs from the geometric mean) of a dataset. The term "average" is frequently used to describe this measure of central tendency. The most typical or average value among a group of numbers is called the mean. It is a statistical measure of a probability distribution's central tendency along the median and mode. It also goes by the name "anticipated value." It is a statistical idea with significant financial implications.
Given,
Mean:
Formula:
Sum = 118.25
Total = 15
[tex]\frac{sum}{total}[/tex]
[tex]\frac{6.75 + 6.5 + 7 +8 +7+8.75+7.25+5.75+9.25+7.75+7+7.5+8+7.5+8+6.25}{15}[/tex]
= [tex]\frac{118.25}{15}[/tex]
= 7.8
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7/5 convert improper fractions
Answer:
1 2/5
Step-by-step explanation:
Improper Fraction - A fraction that has a numerator that is larger than the denominator
Mixed Fraction - A fraction with a whole number, or a quotient with its remainder
In order to convert improper fractions to mixed fractions, you must divide the numerator by the denominator.
So, 7/5 = 7 ÷ 5 = 1 2/5
The quotient being 1, and the remainder being 2/5 because there is 2 left out of the 5.
find the derivative:f(x)= -3/ x^4
Given the function f(x), we can write it like this:
[tex]\begin{gathered} f(x)=-\frac{3}{x^4} \\ \Rightarrow f(x)=-3x^{-4} \end{gathered}[/tex]Using the formula for polynomial derivatives, we get:
[tex]\begin{gathered} f(x)=-3x^{-4} \\ \Rightarrow f^{\prime}(x)=-3\cdot(-4)x^{-4-1}=12x^{-5} \\ f(x)=\frac{12}{x^5} \end{gathered}[/tex]Therefore, the derivative f'(x) is 12/x^5
The standard height from the floor to the bull's-eye at which a standard dartboard is hung is 5 feet 8 inches. A standard dartboard is 18 inches in diameter.
Suppose a standard dartboard is hung at standard height so that the bull's-eye is 12 feet from a wall to its left.
Brian throws a dart at the dartboard that lands at a point 11.5 feet from the left wall and 5 feet above the floor.
Does Brian's dart land on the dartboard?
Drag the choices into the boxes to correctly complete the statements.
Considering the equation of a circle, it is found that:
The equation of the circle that represents the dartboard is [tex](x - 12)^2 + \left(y - \frac{17}{3}\right)^2 = 81[/tex], where the origin is the lower left corner of the room and the unit of the radius is in inches;The position of Brian's dart is represented by the coordinates (11.5, 5). Brian's dart does land on the dartboard.What is the equation of a circle?The equation of a circle of center [tex](x_0, y_0)[/tex] and radius r is given as follows:
[tex](x - x_0)^2 + (y - y_0)^2 = r^2[/tex]
In the context of this problem, we have that:
The radius of the circle is of 9 inches, as the diameter is of 18 inches and the radius is half the diameter.The height is of 5 feet 8 inches = 5 feet and 2/3 feet = 17/3 feet, which is the y-coordinate of the center.The bull's-eye is 12 feet from a wall to its left, hence the x-coordinate of the center is of 12.Hence the equation of the circle is given by:
[tex](x - 12)^2 + \left(y - \frac{17}{3}\right)^2 = 81[/tex]
Brian's dart lands at the following position:
(11.5, 5)
All the points that land on the dartboard respect the following equation:
[tex](x - 12)^2 + \left(y - \frac{17}{3}\right)^2 \leq 81[/tex]
For the coordinate where the dart landed, we have that:
(11.5 - 12)² + (5 - 17/3)² = 0.7 < 81, meaning that Brian's dart lands on the dartboard.
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12 is 150% of what number
To get 150% of a given number x, we multiply it by 1.5
This way, we'll have that:
[tex]1.5x=12[/tex]Solving for x,
[tex]1.5x=12\rightarrow x=\frac{12}{1.5}\rightarrow x=8[/tex]Therefore, we can conclude that 12 is 150% of 8
What is the slope of the line shown?
Answer:
-11/6
Step-by-step explanation:
you can use rise over run to find your answer
Please help!
2|x-1| >2
5
Answer: 6, -4
Step-by-step explanation:
[tex]\frac{2}{5}|x-1| \geq 2\\\\|x-1| \geq 5\\\\x-1 \leq -5, x-1 \geq 5\\\\x \leq -4, x \geq 6[/tex]
Please help asap
this is an assignment due today please help real quick
no fake answers
Answer:
where???????????????
Which system of linear inequalities is represented by the graph? O y=x-2 and x-2y 4 O y=x + 2 and x + 2y = 4 O y=x-2 and x + 2y = 4 O y =x-2 and x + 2y =-4
The two inequalities are (option c) y > x - 2 and2y + x < 4
Given,
Let's start by locating the red-hued area.
If the shadow is visible to be over the line, then the situation will be as follows:
y > ax + b
Hence the equation for the line is ax + b.
The slope is a, and the y-intercept is b.
The line in the graph intersects the y-axis at y = -2, which results in:
b = -2
Two points on the line are required to determine the slope; these points are (0, -2), and (2, 0)
We are aware of the slope for a line passing through the points (x1, y1) and (x2, y2) as follows:
a = (y2 - y1)/(x2 - x1) (x2 - x1)
The slope for this line will then be:
a = (0 - (-2))/(2 - 0) = 2/2 = 1
Then this line's equation is:
1x - 2
And here's the inequality:
y > x - 2.
The shaded area of the blue one is below the line, thus we will have:
y < ax + b
The y-intercept in this situation is y = 2.
This line crosses through the points (0, 2) and, as can be seen (4, 0)
The slope is then:
a = (0 - 2)/(4 - 0) (4 - 0) = -2/4 = -1/2
This inequality is then:
y < (-1/2)x + 2
If we rewrite this using the choices, we get the following:
y < (-1/2)x + 2
2y < -x + 2 ×2
2y + x < 4
The two inequalities are (option c) y > x - 2 and2y + x < 4
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Answer: C
Step-by-step explanation:
help me please
help me :>
Based on the graphs and equations given, the simultaneous equations can be solved to give x = 1.5 and y = 5.5.
How to solve the simultaneous equation?To solve the simultaneous equation, come up with the values of y using values of x in the given formulas:
For y = 3x + 1: the values of y will be:
When x = 1, then y will be:
= 3(1) + 1
= 4
When x = 2, then y will be:
= 3(2) + 1
= 7
When x = 3, then y will be:
= 3(3) + 1
= 9
For the equation, x + y = 7:
When x = 1, then y will be:
y = 7 - 1
= 6
When x = 2, then y will be:
= 7 - 2
= 5
When x = 3, then y will be:
= 7 - 3
= 4
When these are plotted on a graph, we find that the value of x is 1.5 and the value of y is 5.5. This is the point where the lines intersect.
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Trenton’s scouting group made 100 T-shirts for a charity fundraiser. The circle graph below compares how many of each different-colored T-shirt they made.
If the angle measure of the section for purple is 54°, how many purple T-shirts did Trenton’s scouting group make?
(Get it right, I will give you brainliest, thanks and 5* rating)
Trenton’s scouting group make 15 purple T-shirts.
How to find how much percent 'a' is of 'b'?Suppose a number is 'a'. Suppose another number is 'b'. We want to know how much percent of 'b' is 'a'. Then, it is calculated as:
[tex]\dfrac{a}{b} \times 100[/tex]
We have been given that Trenton’s scouting group made 100 T-shirts for a charity fundraiser.
Also the angle measure of the section for purple is 54°, then;
54 / 360 = percent /100
percent = 15
Therefore, 15 percent of 100 T shirt would be;
15/100 x 100
15
Hence, Trenton’s scouting group make 15 purple T-shirts.
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Given: angle CDE congruent to angle CED,
Angle A = angle B
Prove: DE || AB
Please explain the statement and reasoning
Ex: AB is congruent (the sign) to DE. Given
Ill reward brainliest to the one who explains it best ty
1) [tex]\angle CDE \cong \angle CED, \angle A \cong \angle B[/tex] (given)
2) [tex]m\angle CDE=m\angle CED, m\angle A=m\angle B[/tex] (definition of congruent angles)
3) [tex]m\angle C+m\angle CDE+m\angle CED=180^{\circ}, m\angle C+m\angle A+m\angle B=180^{\circ}[/tex] (sum of angles in a triangle)
4) [tex]m\angle C+2m\angle CDE=180^{\circ}, m\angle C+2m\angle A=180^{\circ}[/tex] (substitution)
5) [tex]m\angle C=180^{\circ}-2m \angle CDE, m\angle C=180^{\circ}-2m\angle A[/tex] (subtraction)
6) [tex]180^{\circ}-2m \angle CDE=180^{\circ}-2m \angle A[/tex] (transitive)
7) [tex]-2m\angle CDE=-2m\angle A[/tex] (subtraction)
8) [tex]m\angle CDE=m\angle A[/tex] (division)
9) [tex]\angle CDE \cong \angle A[/tex] (definition of congruent angles)
10) [tex]\overline{DE} \parallel \overline{AB}[/tex] (converse of corresponding angles theorem)
complete the two-column proof.
pleasee
∠2 ≅ ∠4 and m∠2 = 110°, and proved m<3 = 70⁰.
The answers of the blank lines are:
A . Vertically opposite angle.
B . Linear angle .
C . Hence proved .
Solution:Given ,
∠2 ≅ ∠4 and m∠2 = 110°.
We have to prove
m<3 = 70⁰
Here ,
m<2 = m<4 => They are vertically opposite angles.
And here ,
m<3 and m<4 are supplementary angles.
m∠3 + m∠4 = 180° => linear angle .
m<4 = 110⁰ => since m<2 = m<4
By substituting m∠4 we get,
m∠3 + m∠4 = 180°
= m∠3 + 110 = 180
= 180 - 110
m∠3 = 70°
Hence proved.
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