(Time limit)

Tell me the domain
Tell me the range
Tell me whether the graph is a function or not
The answer choices are below

(Time Limit)Tell Me The Domain Tell Me The Range Tell Me Whether The Graph Is A Function Or Not The Answer

Answers

Answer 1
The graphs does not represent a function, as it has vertically aligned points.The domain is: x ≥ -3.The range is: all real numbers.

When does a graphed relation represents a function?

A relation represents a function when each input value is mapped to a single output value.

On a graph, a function is represented if the graph contains no vertical aligned points, that is, if there are no values of x at which we could trace a vertical line that would cross the graph of the function more than once.

Tracing a vertical line for any x > -3, the vertical line would cross the graph at two points, meaning that the relation is not a function.

As for the domain and the range, we have that:

The domain is: x ≥ -3 -> values of x on the graph.The range is: all real numbers -> values of y on the graph.

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Related Questions

1 point
Find the area of the following composite figures, round your answer to the nearest tenth:
Line AD = 6
Line DC = 6
Line AB - 20
Type your answer...

Answers

The area of the following composite figures is 78 square units.

How the area is computed:

The area of the square is computed as 36 (length x width) or 2(Length).

The area of the triangle is computed as (base x height) ÷ 2.

The areas of the composite figures are added to determine the total area.

Line AD = 6

Line DC = 6

Line AB = 20

Base of the triangle = 14 (20 - 6)

Area of triangle = (h x b) ÷ 2

= (6 x 14) ÷ 2

= 42

Area of square portion = 36 (6 x 6)

Total area = 78 square units

Thus, we can conclude that the area of the composite figures are 78 square units.

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Verify
8. sin²a + cot²a sin²a = 1

Answers

Yes, the trigonometric identity 8sin²a + cot²a sin²a = 1 is true.

Answer:

8sin²a + cot²a sin²a = 1 is true.

Step-by-step explanation:

Please help show work 11 points

Answers

The solution to the system of equations in this problem is given as follows:

(0.6, 2.4).

How to solve the system of equations?

The system of equations in the context of this problem is defined as follows:

y = 4x.y = -x + 3.

Equaling the two equations, we can obtain the value of x, as follows:

4x = -x + 3

5x = 3

x = 3/5

x = 0.6.

Substituting the value of x into the second equation, we obtain the value of y as follows:

y = -0.6 + 3

y = 2.4.

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Find the value of f (-1).

Answers

The value of f (-1) by virtue of the given absolute value function graph as required is; 8.

What is the value of the function instance f (-1)?

It follows from the task content that the value of the function instance; f (-1) is required to be determined.

On this note, the value of the function instance can be determined as the point of intersection of the line; x = -1 with the given graph.

Ultimately, the value of the instance f (-1) is; 8.

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You want to purchase a new car in 4 years and expect the car to cost ​$76,000. Your bank offers a plan with a guaranteed APR of 4.5 %if you make regular monthly deposits. How much should you deposit each month to end up with ​$76,000 in 4​years?

Answers

Monthly you should deposit approximately $43 to accumulate ​$76,000 in 4 ​years.

Given that,

f = $76,000

r = 4% = 0.04/12 = 0.0033

n = 4×12 = 48

We know that, a = (f×r)/((1+r)ⁿ⁻¹)

a is the annuity.

f is the future amount.

r is the interest rate per time period.

n is the number of time periods.

Here,

a = (76,000 ×0.0033)/((1.0033)⁴⁸⁻¹)

a = 76,000 ×0.0033×0.17132

a = 42.96

a ≈ $43

Therefore, monthly you should deposit approximately $43 to accumulate ​$76,000 in 4 ​years.

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For each equation complete the table of values and draw its graph for values of x from -1 to 3

Answers

Answer:

Step-by-step explanation:

Answer:

where is the question.

send it so I'll answer it

Find an equivalent equation in rectangular coordinates

Answers

Answer:

[tex]x^2+y^2 = 2x - 2y}[/tex]

Third answer option

Step-by-step explanation:

We are given the polar equation as
[tex]r = 2(\sin \theta - \cos \theta)[/tex]
and asked to convert it into rectangular form

We have the following equations which relate (r, θ) in polar form to (x, y) in rectangular form

[tex]\cos \theta=\dfrac{x}{r} \rightarrow x=r \cos\theta\\\\\sin \theta=\dfrac{y}{r} \rightarrow y=r \sin \theta\\\\[/tex]

[tex]r^2=x^2+y^2[/tex]

Original polar equation:
[tex]r = 2(\sin \theta - \cos \theta)[/tex]

Expand the right side:
[tex]r = 2\sin \theta - 2\cos \theta[/tex]

Substitute for sinθ and cosθ in terms of x and y
[tex]r & = 2\left(\dfrac{y}{r} - \dfrac{x}{r}\right)\\[/tex]

Multiply both sides by r:

[tex]r^2 = 2(x - y)\\r^2 = 2x - 2y\\[/tex]

Substitute [tex]r^2=x^2+y^2[/tex] on the left side:
[tex]\boxed{x^2+y^2 = 2x - 2y}[/tex]

This would be the third answer opton

I need help with math!!!

Please answer this question (picture is provided with question) I just need to find the area.

Answers

The value of area of the figure is,

⇒ 10√10 units²

We have to given that;

To find the area of figure.

Here, We have to find length of AD and AB for area of figure.

Coordinate of A = (- 2, 2)

Coordinate of B = (- 4, -4)

Coordinate of D = (3, 2)

Since, The distance between two points (x₁ , y₁) and (x₂, y₂) is,

⇒ d = √ (x₂ - x₁)² + (y₂ - y₁)²

Hence, Length of AD;

AD = √ (-2 - 3)² + (2 - 2)²

AD = √25

AD = 5

Length of AB;

AB = √ (- 2 + 4)² + (2 + 4)²

AB = √4 + 36

AB = √40

AB = 2√10

Thus, The value of area of the figure is,

⇒ AD x AB

⇒ 5 × 2√10

⇒ 10√10

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Solve the following for θ, in radians, where 0≤θ<2π.
−sin2(θ)−2sin(θ)+1=0
Select all that apply:

0.75
2.5
2.71
0.95
0.43
2.04

Answers

Answer:2.71

0.43 are correct

Step-by-step explanation:We can solve this quadratic equation in sin(θ) by using the substitution u = sin(θ):

-u^2 - 2u + 1 = 0

Multiplying both sides by -1, we get:

u^2 + 2u - 1 = 0

We can use the quadratic formula to solve for u:

u = (-b ± sqrt(b^2 - 4ac)) / 2a

where a = 1, b = 2, and c = -1. Substituting these values, we get:

u = (-2 ± sqrt(4 + 4)) / 2

u = (-2 ± 2sqrt(2)) / 2

Therefore, either:

Find the area of a triangle with base of
​inches and a height of
inches.
A
100100100 square inches
B
505050 square inches
C
252525 square inches
D
12.512.512.5 square inches

Answers

The area of the triangle with base of 5 ​inches and a height of 10 inches is 25 square inches. The correct answer is C.

The formula for the area of a triangle is A = 1/2 * b * h, where A is the area, b is the base, and h is the height. Using this formula, we can calculate the area of the triangle in question.

Given that the base of the triangle is 5 inches and the height is 10 inches, we can plug these values into the formula and solve for A:

A = 1/2 * b * h

A = 1/2 * 5 * 10

A = 25

Therefore, correct answer is C.

The height of a triangle is the perpendicular distance between the base and the opposite vertex. The base is the side of the triangle on which the height is measured.

By multiplying the base and the height and dividing the result by 2, we can find the area of a triangle. This formula works for all types of triangles, regardless of their size or shape.

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Complete question is:

Find the area of a triangle with base of 5 ​inches and a height of 10 inches.

A 100 square inches

B 50 square inches

C 25 square inches

D 12.5 square inches

These two bottles are similar.
The width of the small size is 5.5 cm and its height is 10 cm.
The width of the large size bottle is 9.9 cm.
10 cm
5.5 cm
hcm
9.9 cm
Calculate the height of the large bottle.

Answers

Answer:

To calculate the height of the large bottle, we can use proportions. We know that the small bottle has a width of 5.5 cm and a height of 10 cm. We also know that the large bottle has a width of 9.9 cm. If we set up a proportion with the widths and heights of the two bottles, we can solve for the height of the large bottle.

5.5 cm / 10 cm = 9.9 cm / h

Multiplying both sides by h, we get:

5.5 cm * h = 10 cm * 9.9 cm

Dividing both sides by 5.5 cm, we get:

h = (10 cm * 9.9 cm) / 5.5 cm

h = 18 cm

Therefore, the height of the large bottle is 18 cm.

Step-by-step explanation:

2y+3y-18=-83?????????????

Answers

y= 13

First you start by adding the numbers with variables.

2y+3y=5y

Then you add 18 on both sides

5y-18=-83
+18 +18

5y=-65

Then you divide 5 on both sides


5y=-65
5. 5


Then the equation ends up as

Y=-13

the graph of y=g(x) is shown. draw the graph of y=g(-x)

Answers

To draw the graph of y = g(-x), we need to replace x with -x in the original function.

If y = g(x) is given by the following graph:

(see attachment labeled "Attachment1")

Then y = g(-x) can be obtained by reflecting the graph of y = g(x) about the y-axis:

(see attachment labeled "Attachment 2")

Therefore, the graph of y = g(-x) is the reflection of the graph of y = g(x) about the y-axis.

I hope this helps you! Mark brainliest if you can :D

Consider the following initial value problem, in which an input of large amplitude and short duration has been idealized as a delta function.
y''-5y'=δ(t-1), y(0)=7, y'(0)=0.
a.) Find the Laplace transform of the solution.
b.) obtain the solution y(t)
c.)express the solution as a piecewise-defined function and think about what happens to the graph of the solution at t=1.

Answers

The laplace transform is Y(s) = (7 + e^{-s}/s) / (s² - 5s)

The solution y(t) is y(t) = (-e^{5-t} + 2e^{-5} - 6(t-1) + 7u(t-1))/25.

The solution can be expressed as a piecewise-defined function:

y(t) = -e^{5-t}/25 + 2e^{-5}/25 - 6(t-1)/25 + 7/25, t < 1

y(t) = -e^{5-t}/25 + 2e^{-5}/25 - 6(t-1)/25 + 7/25 + (t-1)/25, t ≥ 1

We have,

a.)

To find the Laplace transform of the solution, we first take the Laplace transform of both sides of the differential equation using the initial value theorem, which states that the Laplace transform of the derivative of a function y(t) is sY(s) - y(0):

s²Y(s) - s y(0) - y'(0) - 5(sY(s) - y(0)) = e^{-s}

Simplifying and solving for Y(s), we get:

Y(s) = (7 + e^{-s}/s) / (s² - 5s)

b.)

To obtain the solution y(t), we use partial fraction decomposition to separate Y(s) into two terms:

Y(s) = A/(s-5) + B/s + C/(s-5)^2

Multiplying both sides by the denominator, we get:

7 + e^{-s}/s = A(s-5)² + Bs (s - 5) + C(s)

Setting s = 0, we get:

7 = 25A - 5B + 0C

Setting s = 5, we get:

7 + e^{-5}/5 = 0A + 5B + 5C

Taking the derivative with respect to s and setting s=0, we get:

0 = 10A - B

Solving these equations, we get:

A = -1/25

B = -2/5

C = 6/25

Therefore, the solution y(t) is:

y(t) = (-e^{5-t} + 2e^{-5} - 6(t-1) + 7u(t-1))/25

Where u(t) is the unit step function.

c.)

The solution can be expressed as a piecewise-defined function as follows:

y(t) = -e^{5-t}/25 + 2e^{-5}/25 - 6(t-1)/25 + 7/25, t < 1

y(t) = -e^{5-t}/25 + 2e^{-5}/25 - 6(t-1)/25 + 7/25 + (t-1)/25, t ≥ 1

At t = 1, there is a discontinuity in the first derivative of the solution due to the presence of the delta function in the original differential equation.

This causes a sudden jump in the slope of the graph of the solution.

Thus,

The laplace transform is Y(s) = (7 + e^{-s}/s) / (s² - 5s)

The solution y(t) is y(t) = (-e^{5-t} + 2e^{-5} - 6(t-1) + 7u(t-1))/25.

The solution can be expressed as a piecewise-defined function as:

y(t) = -e^{5-t}/25 + 2e^{-5}/25 - 6(t-1)/25 + 7/25, t < 1

y(t) = -e^{5-t}/25 + 2e^{-5}/25 - 6(t-1)/25 + 7/25 + (t-1)/25, t ≥ 1

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A small box in the shape of a cube for packaging has a volume of 216 cubic inches.
(a) For a medium box, the length, width, and height are all tripled. What is the ratio of the sides, area of
the bases, and volumes of the boxes? Show your work.
(b) What is the volume of a medium box? Show your work.

Answers

The ratio of the sides of the medium box to the small box is 3:1, the ratio of the area of the bases is 9:1, and the ratio of the volumes is 27:1 and the volume of the medium box is 5832 cubic inches.

Let's denote the side length of the small cube as "s". Since it is a cube, all sides are equal.

Given that the volume of the small box is 216 cubic inches, we can set up the equation;

Volume of small box = s³ = 216

Taking the cube root of both sides, we get;

s = ∛216 = 6 inches

So, the side length of the small cube is 6 inches.

For the medium box, the length, width, and height are all tripled, so the new side length of the medium cube is 3 times the side length of the small cube:

Side length of medium cube = 3s = 3 × 6 = 18 inches

Now, let's calculate the ratio of the sides, area of the bases, and volumes of the small and medium boxes;

Ratio of sides: Side length of medium cube / Side length of small cube = 18 / 6 = 3

Ratio of area of bases: (Side length of medium cube)² / (Side length of small cube)² = (18)² / (6)² = 9

Ratio of volumes: (Volume of medium box) / (Volume of small box) = (Side length of medium cube)³ / (Side length of small cube)³ = (18)³ / (6)³ = 27

So, the ratio of the sides of the medium box to the small box is 3:1, the ratio of the area of the bases is 9:1, and the ratio of the volumes is 27:1.

The volume of the medium box is given by;

Volume of medium box = (Side length of medium cube)³ = 18³

= 5832 cubic inches

Therefore, the volume of the medium box is 5832 cubic inches.

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Question 7
0 / 2 pts
On March 1, Imhoff Co. began construction of a small building. Payments of $267,596 were made monthly for several months. The payments begin on the first day of April; the last payment was made August 1. The building was completed and ready for occupancy on the first day of September. In determining the amount of interest cost to be capitalized, the weighted-average accumulated expenditures are
Y Correct Answer 334,495 margin of error +/- 5

Answers

The solution is : the weighted-average accumulated expenditures are $101,269.5.

Explanation:

Calculation to determine the weighted-average accumulated expenditures

Weighted-average accumulated expenditures=$202,539* (3/12 + 2/12 + 1/12)

Weighted-average accumulated expenditures=$202,539*0.5

Weighted-average accumulated expenditures=$101,269.5

Therefore In determining the amount of interest cost to be capitalized, the weighted-average accumulated expenditures are $101,269.5.

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2. Given: y varies inversely with x.
If y=-24 when x =36, what is the value of x
when y = 45?

Answers

Using inverse variation, the value of x = -19.2

What is inverse variation?

Inverse variation is when a quantity varies inversely as the other.

Given: y varies inversely with x.

If y=-24 when x =36, what is the value of x when y = 45.

To splve this, we proceed as follows

Since y varies inversely with x, we have that

y ∝ 1/x

y = k/x where k = constant of proportionality

So, making k subject of the formula, we have that

k = yx

Now, If y=-24 when x =36, we have that

k = - 24 × 36

= -864

So, substituting k into y, we have that

y = k/x

= -864/x

So, to find the value of x when y = 45, making x subject of the formula, we have that

x = -864/y

So, substituting y into the equation, we have that

x = -864/y

= -864/45

= -19.2

So, the value of x = -19.2

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Write a function of the form y= A sin (Bx-C)+D that has period 8, phase shift -2, and the range -12 ≤y≤-4.

y =

Answers

A function of the form y= A sin (Bx-C)+D that has period 8, phase shift -2, and the range -12 ≤y≤-4 is y = 4 sin (π/4 x + π/2) - 8

To write a function of the form y = A sin (Bx - C) + D that has a period of 8 and phase shift of -2, we can use the general formula:

y = A sin [(2π/P)(x - C)] + D

where P is the period, C is the phase shift, and D is the vertical shift. In this case, P = 8 and C = -2, so we have:

y = A sin [(2π/8)(x + 2)] + D

Simplifying the equation, we get:

y = A sin (π/4 x + π/2) + D

To find the amplitude A and vertical shift D that satisfy the range -12 ≤ y ≤ -4, we can use the fact that the sine function oscillates between -1 and 1. If we set A = 4, then the maximum value of y is 4 + D, and the minimum value of y is -4 + D. To ensure that the range is -12 ≤ y ≤ -4, we need to choose D such that:

4 + D ≤ -4 and -4 + D ≥ -12

Solving these inequalities, we get:

-8 ≤ D ≤ 0

Therefore, a function that satisfies the given conditions is:

y = 4 sin (π/4 x + π/2) - 8

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Find the area of triangle ABC with the given parts. Round to the nearest tenth as necessary

Answers

The area of the given triangle is expressed as: 25.6 in²

What is the area of the triangle?

We are only given two sides of the triangle and an angle and so we must find the length of the third side to be able to find the area. The length of the third side is gotten from cosine rule to get:

a = √(14.1² + 7.2² - 2(14.1 * 7.2)*cos 30.3)

a = 8.68 in

In order for us to calculate the area of triangle which has 3 sides, we will have to utilize the Heron's Formula.

From the formula, the area of a triangle (A) that has 3 sides a, b, and c is calculated via the formula:

A = √[s(s - a)(s - b)(s - c)]

where:

s denotes the semi-perimeter of the specific triangle given by the formula: s = (a + b + c)/2.

s = (8.68 + 14.1 + 7.2)/2

s = 14.99 in

Thus:

Area = √[14.99(14.99 - 8.68)(14.99 - 14.1)(14.99 - 7.2)]

Area = 25.6 in²

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Which of the following functions has the largest value when x = 3 (1 point)?

c(x) = 3x2 + 5x + 22
j(x) = 12x
a(x) = 9x

Group of answer choices

All the functions are equal at x = 3.

c(x)

j(x)

a(x)

Answers

Answer:

x = 3

c(x) = 3x² + 5x + 22

⇒ c(3) = 3(3²) + 5(3) + 22

⇒ c(3) = 3(9) + 15 + 22

⇒ c(3) = 27 + 15 + 22

⇒ c(3) = 64

j(x) = 12x

⇒ j(3) = 12(3)

⇒ j(3) = 36

a(x) = 9x

⇒ a(3) = 9(3)

⇒ a(3) = 27

c(x) = 3x² + 5x + 22 is the function that has the largest value when x = 3.

False. Not all functions are equal at x = 3.

Exponential model. Further research of the new disease has confirmed that its spread is
not linear, but exponential. Experts have estimated it to double every 7 days when it is
first introduced to a population.
Suppose there were 3 cases reported on the morning of day 1 of the outbreak. How many
cases will there be by the end of day 21?

Answers

Answer:

Since the disease doubles every 7 days, the number of cases on day 21 will be 2^3 times the number of cases on day 14, which will be 2^2 times the number of cases on day 7, which will be 2^1 times the number of cases on day 1.

Starting with 3 cases on day 1, we can use the formula:

N = 3 * 2^(t/7)

where N is the number of cases after t days.

Plugging in t = 21, we get:

N = 3 * 2^(21/7) = 3 * 2^3 = 24

Therefore, there will be 24 cases by the end of day 21.

Step-by-step explanation:

NEED HELP WILL GIVE BRAINLIEST AND WILL RATE. Show work and do all 3. :)

Answers

Step-by-step explanation:

5 (4x^8) ^(-1/2)    -   2 x^-3

p ^(1/2)

r ^5/3  

The answer choices are distributive property, associative property, communicative property

Answers

Answer:

Step 1: Distributive Property

Step 2: Distributive Property

Step 3: Commutative Property

Step-by-step explanation:

Step 1: This is distributing the (x + 4y + z) into the (x - 7y), so each term in the prior expression is multiplied by (x - 7y). Hence, Distributive Property.

Step 2: This is doing the same thing but to each individual term. The x in the first term is multiplied by each term in the (x - 7y), the 4y in the second term is multiplied by each term in the (x - 7y), and the same for z. Hence, Distributive Property.

Step 3: This is reordering the variables in the terms. For example, 4yx is changed to 4xy, and that is possible because of the Commutative Property. zx is also reordered into a xz and 7zy into a 7yz.

Feel free to ask any more questions. Hope this helps!!!

128 3 мы - 5 20 14 ) 448 320 (20X14) 128 80 (5х16) 48 -48 (3 XI) vaku С​

Answers

What are we solving for and I’m confused about your question

In a choir, the number of girls is twice the number of bovs. The avera height of the boys is 150 cm and the average height of the girls is 159 cm
What is the average height of all the choir members?

Answers

Answer:

Step-by-step explanation: mark me brainliest

Citywide Delivery Inc. budgets $190 per month for telephone costs, which include the 3% federal excise tax. Citywide uses approximately 4,000 minutes per month, so the company signed up for the $96.00 plan. What is the maximum number of lines Citywide can sign up for and stay within their budget? Use the figure below:

Answers

Since we can't have a fractional number of lines, Citywide can sign up for a maximum of 1 line and still stay within their budget.

Let's start by calculating the total amount Citywide pays for their telephone costs without the federal excise tax. We can do this by subtracting the 3% tax from the total budget:

$190 / 1.03 = $184.47

The $96 budget plan includes 4,000 minutes, which means that each minute costs:

$96 / 4,000 = $0.024

If Citywide wants to stay within their budget, they need to make sure that the total cost of the lines they sign up for plus the federal excise tax is less than or equal to $190.

Let's represent the number of lines Citywide signs up for as "n". The total cost of the lines plus tax can then be represented as:

n * $96 * 1.03

Setting this expression less than or equal to $190, we get:

n * $96 * 1.03 <= $190

Simplifying, we get:

n <= $190 / ($96 * 1.03)

n <= 1.945

Thus, Citywide can sign up for a maximum of 1 line and still stay within their budget.

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Few families can survive on a single salary.
Please select the best answer from the choices provided
T
F

Answers

Few families can survive on a single salary is true statement

Many families rely on dual incomes to make ends meet, especially in areas with high living costs.

However, there are still many families that rely on a single salary to support themselves.

While it may be challenging to make ends meet on a single salary, it is still possible for families to survive and even thrive in these circumstances.

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2. There is another surface that Molly does not need to paint, because it won’t show when she displays the model house. Describe that surface. (2 points)

Answers

Without additional information about the model house, it is impossible to accurately describe the surface that Molly does not need to paint. It could be any surface that will not be visible when the model house is displayed, such as the underside of a roof, the back of a wall, or the bottom of a floor.

Assignment I 1. Prepare a questionare on Expenditures and Consumptions behaviours and attitudes of polytechnic Students (Case Study of TOPS)​

Answers

Some questions that can be asked on the Expenditures and Consumptions behaviours and attitudes of polytechnic Students in a questionnaire are:

What is the average of your total proceeds each month?How much money, on average, do you disburse to purchase perishables and staples each month?Transit consumption - On an ordinary basis, how much are you spending periodically?To participate in reposeful activities or entertainments, monthly expenditure- How much would that amount to?When it comes to periodic expenses, do you have a pre-defined plan in paper?Do you rule over your costings every thirty days with rigorousness?Have any credits or financial obligations been dispensed for the satisfaction of debts?Utilizing a student loan, have you ever funded your current education or living outlays?

How to make a questionnaire ?

One must carefully consider the purpose of a questionnaire, as well as the information required before starting to design it. Also crucial are factors such as the target audience, number and type of questions (i.e., multiple-choice or open-ended), and its format (e.g., Likert scale).

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Math Algebra Help needed

Answers

The composite functions are (f · g) (x) = (x + 2)² and (f / g) (x) = 1, whose domains are all real numbers. The value of each function at x = 2 is listed below:

(f · g) (2) = 16 (f / g) (2) = 1

How to find and to analyze composite functions

In this problem we must determine and analyze composite functions. Composite functions can be found by combining two simpler functions thanks to operators. There are four operators to make composite functions:

Addition: (f + g) (x) = f(x) + g(x)Subtraction: (f - g) (x) = f(x) - g(x)Multiplication: (f · g) (x) = f(x) · g(x)Division: (f / g) (x) = f(x) / g(x)

The domain of a function is the set of all possible of x-values.

First, we determine the two composite functions: f(x) = g(x) = x + 2.

Case A:  

(f · g) (x) = (x + 2)²

Case B:

(f / g) (x) = 1

Second, determine the domain for each case:

Case A:

All real numbers.

Case B:

All real numbers.

Third, evaluate each case at x = 2:

Case A:

(f · g) (2) = (2 + 2)² = 4² = 16

Case B:

(f / g) (2) = 1

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