A 52 gram sample of an unknown metal requires 714 Joules of energy to heat it from
30.5◦C to 82◦C. What is the specific heat of
this metal?
Answer in units of J/g ·
◦ C.
Answer: Approximately [tex]0.267 \frac{\text{J}}{\text{g}^{\circ}\text{C}}[/tex]
===================================================
Work Shown:
We have the following variables
Q = 714 joules = heat requiredm = 52 grams = massc = specific heat = unknown[tex]\Delta t[/tex] = 82-30.5 = 51.5 = change in temperaturenote: the symbol [tex]\Delta[/tex] is the uppercase Greek letter delta. It represents the difference or change in a value.
Apply those values into the formula below. Solve for c.
[tex]Q = m*c*\Delta t\\\\714 = 52*c*51.5\\\\714 = 52*51.5*c\\\\714 = 2678*c\\\\2678*c = 714\\\\c = \frac{714}{2678}\\\\c \approx 0.26661687826737\\\\c \approx 0.267\\\\[/tex]
The specific heat of the unknown metal is roughly [tex]0.267 \frac{\text{J}}{\text{g}^{\circ}\text{C}}[/tex]
Which of the following is a radioactive element?Sodium, Fluorine,Oxygen
francium
Answer:
Fluorine
Explanation:
These particles stick in the atoms and make them radioactive.
what is the mass of 8.07 x 10^24 molecules of 02?
Answer:Avogadro's number 6.02 x 10^23 of O2 molecules has a mass of 32 gm (atomic weight of O = 16 gm, 2 x 16 = 32).
Explanation:pls brainless
help please thank you
What carpet Burns in a deficiency of O2 a mixture of CO and CO2 forms.Carbon Burns in excess O2 to form only CO2 and CO Burns in excess O2 to form only CO2. Calculate ΔH for C(graphite +1/2O2) →CO(g).
Answer:
Explanation:
From the combustion of carbon, the reactions occurring in limited oxygen conditions are:
[tex]C(graphite) + \dfrac{1}{2}O_{2(g)} \to CO_{(g)}[/tex]
[tex]C(graphite) + O_{2(g)} \to CO_{2(g)}[/tex]
If it occurs in excess, then any leftover CO changes to CO2. i.e.
[tex]C(graphite) + O_{2(g)} \to CO_{2(g)}[/tex] ---- (1)
[tex]CO_{(g)} + \dfrac{1}{2}O_{(g)} \to CO_{2(g)}[/tex] ----- (2)
From (1), the enthalpy change is:
[tex]\Delta H_{rxn1} = \Delta H^0_{fCO_2(g)} - ( \Delta H^0_{f C(graphite)}+ \Delta H^0_{fCO_2(g)}[/tex]
[tex]\Delta H_{rxn1} =-393.5 \ kJ/mol -(0+0)[/tex]
[tex]\Delta H_{rxn1} =-393.5 \ kJ/mol[/tex]
From (2), the enthalpy change is:
[tex]\Delta_{rxn2} = \Delta H^0_{fCO_2(g)} - ( \Delta H^0_{fCO(g)} + \dfrac{1}{2} \Delta H^0_{fO_2(g)})[/tex]
[tex]\Delta_{rxn2} = -393.5 \ kJ/mol -(-110.5 + \dfrac{1}{2}(0))[/tex]
[tex]\Delta_{rxn2} = -283.0 \ kJ/mol[/tex]
Subtracting (2) from (1), we get:
[tex]C(graphite) + O_{2(g)} \to CO_{2(g)} \ \ \ \Delta H_{rxn} = -393.5 \ kJ/mol}[/tex]
[tex]CO_{(g)} + \dfrac{1}{2} O_2(g) \to CO_{2(g)}} \ \ \ \Delta H _{rxn2} = -283.0 \ kJ/mol[/tex]
[tex]C(graphite) + O_{2(g)} \to CO (g) + \dfrac{1}{2}O_{2(g)} \ \ \ \Delta H_{rxn} = -110.5 \ kJ/mol[/tex]
[tex]C(graphite) + \dfrac{1}{2} O_{2(g)} \to CO (g) \ \ \ \Delta H_{rxn} = -110.5 \ kJ/mol[/tex]
The enthalpy change ΔH of the reaction = -110.5 kJ/mol
Write down the possible types of atomic
Orbitals of n=4
Answer:
2
Explanation:
because first shell ( k shell ) needs only 2 electron to complete its octet .
hope it helps
How would a long period without sunlight affect the food web? PLEZZ HELP MEH IF YOU WANT BRAINEIST AND LIKE COMMENTED
It would cause consumers to consume more food.
It would have no effect on the food web.
It would stop decomposers from breaking down matter.
It would stop producers from producing food.
Answer:
im pretty sure its the last one
Explanation:
if plants dont have sun light they will die because the sunlight gives them the nutrients to survive
Fungus is an example of a/an-
A:tissue
B:cell type
C:organ
D:organism
Answer:
D.organism
Explanation:
A fungus from the kingdom fungi is an organism
Answer:
D. organism
......................
A chemist prepares a solution of barium acetate BaCH3CO22 by weighing out 52.9g of barium acetate into a 100.mL volumetric flask and filling the flask to the mark with water. Calculate the concentration in /gL of the chemist's barium acetate solution. Round your answer to 3 significant digits.
Answer:
529g/L
Explanation:
The concentration in chemistry is defined as the amount of solute in a determined amount of solution. The concentration in g/L means the amount of grams of solute (In this case, barium acetate), per liter of solution.
To solve this problem we need to find grams of solute (52.9g, already given) and the volume in liters (Converting 100mL to liters):
Volume:
100mL * (1L / 1000mL) = 0.100L
And concentration in g/L is:
52.9g / 0.100L =
529g/LWhy is your body going through physical and chemical changes?
Answer:
Physical and chemical changes can occur almost everywhere, even in our bodies! Food must be broken down into a form that our cells can use. When we eat, our bodies physically break down food into small pieces. Our bodies also chemically break down those small pieces of food into tiny organic molecules.
Explanation:
g What amounts of 45% pure silver and 50% pure silver should be mixed to obtain 14 grams of 46% pure silver
Answer:
11.2g of the 45% pure silver and 2.8g of the 50% pure silver.
Explanation:
14g of 46% pure silver contains:
14g*46% = 6.44g of silver are required. Thus, we can write:
6.44 = X*50% + Y*45% (1)
Where X is the mass of 50% pure silver and Y the mass of 45% pure silver.
As the mass of the sample must be 14g:
14g = X + Y (2)
Replacing (2) in (1):
6.44 = (14-Y)*50% + Y*45%
6.44 = 7 - 0.5Y + 0.45Y
-0.56 = -0.05Y
Y = 11.2g of the 45% pure silver
And:
14g-11.2g = X
X =
2.8g of the 50% pure silver
The required amount to obtain 14g of 46% pure silver is 2.8g of 50% silver and 11.2g of 45% silver.
To solve this question, we can assume it's a mathematical problem more than a chemistry problem.
let x represent the amount of 45% of pure Ag
let y represent the amount of 50% of pure Ag
But from the question, we only need 14g from both x and y
We can write an equation to represent this
[tex]x+y=14...equation(i)[/tex]
likewise, we can say that
[tex]0.45x+0.50y=14*0.46\\0.45x+0.50y=6.44...equation(ii)[/tex]
Solving both equations simultaneously,
[tex]x+y=14...equation(i)\\0.45x+0.5y=6.44...equation(ii)[/tex]
from equation (i)
[tex]x+y=14\\x=14-y...equation(iii)[/tex]
substitute equation (iii) into equation (ii)
[tex]0.45x+0.5y=6.44\\x=14-y\\0.45(14-y)+0.5y=6.44\\6.3-0.45y+0.5y=6.44\\[/tex]
collect like terms
[tex]-0.45y+0.50y=6.44-6.3\\0.05y=0.14\\y=\frac{0.14}{0.05}\\y=2.8[/tex]
Now we know the value of the 50% Ag which is 2.8g. Let's substitute it's value into equation (i) and solve for x
[tex]x+y=14\\x+2.8=14\\x=14-2.8\\x=11.2g[/tex]
Learn more about definite proportions here
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if 3.26 g is dissolved in enough water to make exactly 323 ml of solution, what is the molar cocentration of nitrate ion g
All the radioactive elements are found in the last group of the Periodic Table.
True
False
Answer:
False
Explanation:
Solid mercury (II) oxide produces liquid mercury and oxygen gas
Mercury(II) oxide, a red solid, decomposes when heated to produce mercury and oxygen gas. Mercury(II) oxide is a red solid. When it is heated, it decomposes into mercury metal and oxygen gas. A reaction is also considered to be a decomposition reaction even when one or more of the products are still compounds.
what element is in group 13, period 4
Answer:
Gallium
Explanation:
Answer:
Gallium
Explanation:
Which list of elements contains a metal, a melalloid and a nonmetal
Answer:
group 15 ( the nitogen group)
Explanation:
What is the molar mass of magnesium sulfate, MgSO4?
Answer:
120.37 g/mol is the molar mass of magnesium sulfate
please helpppppppppp
Answer:
Environmental factors such as diet, temperature, oxygen levels, humidity, light cycles
And the presence of mutagens can all impact which of an animal's genes are expressed, which ultimately affects the animal's phenotype.
3
Directions: Drag each tile to the correct box.
Three phases of waler are shown below.
Put the phases in order from fastest particle molion to slowest particle molion.
liquid water
>
steam
ice
Reset
Submit
Answer:
In order from fastest to slowest, Steam > Liquid Water > Ice
Explanation:
As temperatures rise, particles are allowed to move faster and more freely. If you think about the phases of matter, the more compact something is (solids), the less the particles are able to move. Taking the temperate of ice into consideration, the cold further restricts fast movement of particles, whereas gas (especially steam in this case), in hot temperatures, is able to move quickly and freely in the atmosphere.
Is burning physical or chemical change?
Answer:
a chemical change
Explanation:
lighting a match is a chemical change. chemical reactions cause chemical change. in a chemical reaction two or more substances, called the reactants, form different substances called products. hope this helped :)
Why was Niels Bohr’s atomic model superior to all the earlier models?
A.
It proved that the atom was indivisible and therefore the smallest unit of matter.
B.
It showed how the electron could orbit the nucleus without falling into it.
C.
It was the first to show that the atom had no net charge.
D.
It used wave behavior to explain the positions of electrons around the nucleus.
Answer:
B
Explanation:
The Niels Bohr's atomic model superior to all the earlier models is because it showed how the electron could orbit the nucleus without falling into it
How can both the pitcher and the glass contain the same volume of iced
tea?
Answer: $6,600[tex]\alpha \sqrt[n]{x} \lim_{n \to \infty} a_n[/tex]
Explanation:
1pt Copper chloride and aluminum react to produce
aluminum chloride and copper. Which of the
following is the correctly balanced chemical
equation for this reaction?
O A. CuCl, + Al -> AICI, + u
O B. 3CuCl, + Al -> AlCl, + 2Cu
OC. 3CUCI, + 2Al -> 2AICI, + 3Cu
OD. CuCl, + 3Al -> AICI, + 2Cu
Answer:
None of the above
but it must be:
for Copper(I)chloride
3CuCl + Al ==> AlCl3 + 3Cu
for Copper (II) chloride
3CuCl2 + 2Al ==> 2AlCl3 + 3Cu
What is the molarity of a solution of 10% by mass cadmium sulfate, CdSO4 (molar mass = 208.46 g/mol) by mass? The density of the solution is 1.10 g/mL.
a. 0.528 M
b. 0.436 M
c. 0.479 M
d. 0.048 M
e. 22.9 M
Answer:
a. 0.528 M .
Explanation:
Hello!
In this case, since the given by-mass percent can be written as:
[tex]\frac{10gCdSO_4}{100g\ sol}[/tex]
By using the density and molar mass of the solute, cadmium sulfate, we can compute the molarity, by also making sure we convert from mL to L of solution:
[tex]M=\frac{10gCdSO_4}{100g\ sol}*\frac{1molCdSO_4}{208.46gCdSO_4} *\frac{1.10g\ sol}{1mL\ sol}*\frac{1000mL}{1L} \\\\ M=0.528M[/tex]
Thereby, the answer is a. 0.528 M .
Best regards.
The molarity of the solution of 10% by mass cadmium sulfate [tex](CdSO_4)[/tex] is approximately 0.479 M. The correct option is C.
To calculate molarity we need to find out how many moles of CdSO4 are present in the solution.
Given:
Mass of [tex]CdSO_4[/tex]= 10% by mass of the solutionMolar mass of [tex]CdSO_4[/tex] = 208.46 g/molDensity of the solution = 1.10 g/mLWe need to calculate the mass of [tex]CdSO_4[/tex]:
Mass of [tex]CdSO_4[/tex] = (10% / 100%) * Total mass of the solution
Mass of [tex]CdSO_4[/tex] = (10 / 100) * 1000 g (since the volume is 1 L, and the density is 1.10 g/mL)
Mass of [tex]CdSO_4[/tex] = 100 g
So, the number of moles of CdSO4:
Number of moles of [tex]CdSO_4[/tex] = Mass of CdSO4 / Molar mass of CdSO4
Number of moles of [tex]CdSO_4[/tex] = 100 g / 208.46 g/mol
Number of moles of [tex]CdSO_4[/tex] ≈ 0.479 moles
Then, we calculate the molarity of the solution:
Molarity = Number of moles of CdSO4 / Volume of the solution (in liters)
Molarity = 0.479 moles / 1 L
Molarity ≈ 0.479 M
Hence, the molarity of the solution of 10% by mass cadmium sulfate [tex](CdSO_4)[/tex] is approximately 0.479 M. The correct option is C.
Learn more about Molarity, here:
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HELP ME PLEASE
Over time, which cell will look the smallest?
A student places four identical cells into four different
liquids
Cell
cell W
cell x
cell Y
cell z
W:Saltier than the cell
X:Less salty than the cell
Y:Equally as salty as the cell
Z:Pure water with no salts
Answer:
This description can be expressed as follows:
Y > W > XY>W>X
And,
W=ZW=Z
From these expressions we are able to find out that the saltiest cell description is Y, while the less salty is X.
Now, salt is well known as a dehydrating agent. In a process called osmosis cells placed in a salty liquid environment lose water, how?
Well, cells have a semipermeable membrane, in which some substances can get inside. Cells also have water inside. If a cell is placed in a quite salty liquid environment, salt will make the water inside the cells to come out, drying the cell and diminishing its size.
So, in this case, according to the expressions above, Cell Y will look the smallest, while cell X will look the biggest.
If we pour pure water in each liquid, the salt concentration will change and each cell will begin to grow bigger, but the saltiest cell will still be smaller than the others with less salt concentration.
Finally, to answer the question: Y cell will look the smallest after this processPLEASE HELP ASAPPPP I WILL VENMO YOU MONEY IF YOU DO THIS CORRECTLY Write the name for the following compounds.
1. N2O (Covalent)
2. Cu2S (Ionic)
Write the Chemical Formula for the following compounds.
3. Dichlorine heptoxide (Covalent)
4. Magnesium bromide (lonic)
Answer:
Dichlorine heptoxide=Cl₂O₇
magnesium bromide=MgBr2
Explanation:
A 4.0g Glass was heated from 5°C to 45°C after absorbing 32 J of heat. What is the specific heat of the glass? 
Answer:
[tex]c=0.2\ J/g^{\circ} C[/tex]
Explanation:
Given that,
Mass of a glass, m = 4 g
Initial temperature, [tex]T_i=5^{\circ} C[/tex]
Final temperature, [tex]T_f=45^{\circ} C[/tex]
Heat absorbed, Q = 32 J
We need to find the specific heat of the glass. The formula for the heat absorbed is given by :
[tex]Q=mc\Delta T\\\\c=\dfrac{Q}{m\Delta T}\\\\c=\dfrac{32\ J}{4\ g\times (45-5)^{\circ} C}\\\\=0.2\ J/g^{\circ} C[/tex]
So, the required specific heat of the glass is [tex]0.2\ J/g^{\circ} C[/tex].
what is the empirical formula of A compound is found to contain 39.12 % carbon, 8.772 % hydrogen, and 52.11 % oxygen by mass.
Answer:
C₃H₈O₃
Explanation:
Let's assume we have 100 g of said compound. Then we would have:
39.12 g of C8.772 g of H52.11 g of ONow we convert those masses into moles, using their respective atomic weights:
C ⇒ 39.12 g ÷ 12 g/mol = 3.26 mol CH ⇒ 8.722 g ÷ 1 g/mol = 8.722 mol HO ⇒ 52.11 g ÷ 16 g/mol = 3.26 mol OThen we divide those moles by the smallest number among them:
C ⇒ 3.26 mol C / 3.26 = 1H ⇒ 8.722 mol H / 3.26 = 2.68O ⇒ 3.26 mol O / 3.26 = 1Finally we multiply those numbers by 3, so as to convert the 2.68 of H into an integer:
C ⇒ 1 * 3 = 3H ⇒ 2.68 * 3 = 8O ⇒ 1 * 3 = 3Thus the empirical formula is C₃H₈O₃
What would you use to determine whether an acid or alkali has been added to a solution?
A. Reactant
B. Indicator
C. Adjustor
D. Identifier
Answer:
B. Indicator
Explanation:
An indicator is used to determine whether an acid or alkali has been added to a solution.
An acid or alkali changes the hydrogen ion concentration in solution. This is indicated by the pH of the solution after which the acid or alkali has been added.
To see this change, indicators are used. An indicator employs color changes to show a change in chemical properties which pertains to the pH. There are several indicators used which are litmus paper, phenolphthalein, methyl orangeA 2.26 M solution of KOH is prepared. Calculate the moles and mass of solute present in a 15.2-mL sample of this solution. The molar mass of KOH is 56.11 g/mol.
Answer:
0.0344 moles and 1.93g.
Explanation:
Molarity is defined as the ratio between moles of a solute (In this case, KOH), and the volume. With molarity and volume we can solve the moles of solute. With moles of solute we can find mass of the solute as follows:
Moles KOH:
15.2mL = 0.0152L * (2.26mol / L) = 0.0344moles
Mass KOH:
0.0344 moles * (56.11g/mol) = 1.93g of KOH