Thompson and Thompson is a steel bolts manufacturing company. Their current steel bolts have a mean diameter of 149 millimeters, and a standard deviation of 8 millimeters.

If a random sample of 50 steel bolts is selected, what is the probability that the sample mean would differ from the population mean by more than 3.3 millimeters? Round your answer to four decimal places.

Answers

Answer 1

The probability that the sample mean will differ from the population mean by more than 1.8 mm = 0.9949

Given,

In the question:

According to the given problem the mean diameter μ= 149 mm (population mean) and the standard deviation is σ = 8mm

random sample size, n= 50 steel bolts is selected

Let the random variable that represents the diameter of steel bolts be denoted by x and from the problem we have x = 3.3mm

Let z = (x-μ) / (σ/√n ) ....(1)

using formula (1) and when the sample mean differs from the population mean by more than 1.8mm

z = (3.3 - 149) /(8/√50 )

⇒z = -2.575

The probability that the sample mean will differ from the population mean by more than 1.8 mm

P( z > -2575) = 1 - P(z< -2.575) = 1 - 0.0051 = 0.9949

Hence, The probability that the sample mean will differ from the population mean by more than 1.8 mm = 0.9949.

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Related Questions

The table below shows the relationship between the number of hours a student studied and theirgrade on a certain test.

Answers

It is necessary to adjust the given points of the graph to a line. The general form of the equation of a line is given by:

y = mx + b

where m is the slope of the line and b is the y-intercept of the line.

To calculate the slope m, use the following formula:

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Monica did an experiment to compare two methods of warming an object. The results are shown in thetable below. Which statement best describes her results?

Answers

The correct answer is,

The temperature using method 2 changed exponentially.

Complete each equation so that it has infinitely many solutions. 12x - x + 8 + 3x = __x + __ (__ are blanks)

Answers

A linear equation is an algebraic equation of the form y=mx+b, where m is the slope and b is the y-intercept, and only a constant and a first-order (linear) term are included. The variables in the preceding equation are y and x, and it is occasionally referred to as a "linear equation of two variables."

What are a definition and an example of a linear equation?Linear formula first-degree algebraic equation with the variables y = 4x + 3 or similar (that is, raised only to the first power). Such an equation has a straight line for its graph.

-12-x=8-3x

Add what is to the right of the equal sign to both sides of the equation, then rewrite the equation as follows:

-12-x-(8-3*x)=0

Take like variables away:

 -20 + 2x  =   2 • (x - 10)

Solve: 2 = 0There is no answer to this equation.A constant that is not zero can never equal zero.

x-10 = 0

On both sides of the equation, add 10:

x = 10.

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Which of the following shows the division problem down below

Answers

Question:

Solution:

Synthetic division is a quick method of dividing polynomials; it can be used when the divisor is of the form x-c. In synthetic division, we write only the essential parts of the long division. Notice that the long division of the given problem is written as:

thus, the synthetic division of the given problem would be:

Writing 6 instead of -6 allows us to add instead of subtracting. We can conclude that the correct answer is:

A.

The cost of a laptop computer decreased from $600 to $480. By what percentage did the cost of the computer decrease?

Answers

[tex]\begin{gathered} \text{Percentage decrease =} \\ \frac{\text{initial value - new value}}{\text{initial value}}\times100 \end{gathered}[/tex]

Initial value= $600

new value = $ 480

[tex]\begin{gathered} =\frac{600-480}{480}\times100 \\ =\text{ }\frac{120}{480}\times100 \\ =\text{ 25\%} \end{gathered}[/tex]

25% decrease is the answer

Ingrid is preparing a budget. She is first calculating her income. She makes $2,000 a month as a tutor, but she is going to school to become a lawyer who will eventually make close to $10,000 a month. What is the BEST thing for Ingrid to do to prepare an accurate budget?A. She should use the difference between both incomes--$8,000.B. She should average both incomes and use $6,000.C. She should use her future income of $10,000.D. She should use her current income of $2,000.

Answers

Given:

Ingrid is preparing a budget. She is first calculating her income.

She makes $2,000 a month as a tutor.

And she is going to school to become a lawyer.

Eventually, she will make close to $10,000 a month

So, the best thing is to calculate her earnings when she becomes a lawyer.

So, the answer will be option A

She should use the difference between both incomes--$8,000.

Use the give right triangle to find ratios. In reduced form, for sin A, cos A, and tan A

Answers

[tex]\sin \theta=\frac{opposite}{hypotenuse}[/tex]

From the figure given, if theta = A

opposite = 28 and hypotenuse =53

substitute the values into the formula

[tex]\sin A=\frac{28}{53}[/tex]

[tex]\cos A=\frac{adjacent}{\text{hypotenuse}}[/tex][tex]\cos A=\frac{45}{53}[/tex][tex]\tan \theta=\frac{opposite}{adjacent}[/tex][tex]\tan A=\frac{28}{45}[/tex]

4-10x = 3+5x subtract 4 from both sides

Answers

S={1/15}

1) Solving that expression

4-10x = 3+5x Subtract 4 from both sides

4-4-10x=3-4+5x

-10x =-1+5x Subtract 5x from both sides, to isolate x on the left side

-10x -5x = -1 +5x -5x

-15x=-1 Divide both sides by -15 to get the value of x, not -15x

x=1/15

S={1/15}

Go on the head 120 eggs delivered to her bakery she used to 98 eggs to bake cakes which equation can she use find the number of eggs r she has left

Answers

Yolanda has 120 eggs, but she used 98 eggs

r represents the equation for the number of eggs that she left:

To find this, subtract the total of eggs by the eggs used

Then, r = 120 - 98

solve 6 + 5 on the sqr root of 249 - 2x = 7

Answers

ANSWER

x = 124

EXPLANATION

First we have to clear the term that contains x in the equation. In this case, this term is the second term. So we have tu subtract 6 from both sides of the equation:

[tex]\begin{gathered} 6-6+\sqrt[5]{249-2x}=7-6 \\ \sqrt[5]{249-2x}=1 \end{gathered}[/tex]

Then, we have to eliminate the root. Note that in the expression inside the root there are two terms. To do this, we have to apply the "opposite" operation on both sides of the equation, which in this case is exponent 5:

[tex]\begin{gathered} (\sqrt[5]{249-2x})^5=1^5 \\ 249-2x=1 \end{gathered}[/tex]

Now we do something similar to the first step. We want to leave on one side of the equation only the term that contains x and the rest on the other side. To do this we can either add 2x on both sides, or subtract 249 from both sides. We'll apply the first option because then we'll have a positive coefficient for x:

[tex]\begin{gathered} 249-2x+2x=1+2x \\ 249=1+2x \end{gathered}[/tex]

However, we now have to subtract 1 from both sides of the equation:

[tex]\begin{gathered} 249-1=1-1+2x \\ 248=2x \end{gathered}[/tex]

Finally, to find x, we have to divide both sides by 2:

[tex]\begin{gathered} \frac{248}{2}=\frac{2x}{2} \\ 124=x \end{gathered}[/tex]

Hence, the solution to the equation is x = 124.

Solve for x. Write the reasons next to each step.Submit723x+10

Answers

x = 26/3

Explanation:

We would apply the mid-segment theorem:

The base of the smaller triangle = 1/2 (the base of the bigger triangle)

The base of the smaller triangle = 3x + 10

the base of the bigger triangle = 72

3x + 10 = 1/2(72)

Reason: Mid segment is parallel to the base of the large triangle. And it is equal to half the length of the base of the large triangle

simplifying:

3x + 10 = 72/2

3x + 10= 36

subtract 10 from both sides:

3x + 10 - 10 = 36 - 10

3x = 26

DIvide both sides by 3:

3x/3 = 26/3

x = 26/3

or x = 8 2/3

The high school soccer booster club sells tickets to the varsity matches for $4 for students and $8
for adults. The booster club hopes to earn $200 at each match.
what does the slope mean in terms of the situation?

Answers

4x + 8y = 200
8y= -4x +200
y= -1/2x +25

Slope = -1/2

What value n makes the eauqation n x 3/4 = 3/16

Answers

Answer:

N = 1/4

Step-by-step explanation:

Okay, so 1/4 is equal to N.

3/4 x1/4=3/16

i need help solving this with the statements and reasons

Answers

Given that:

[tex]\bar{AB}\mleft\Vert \mright?\bar{DC}[/tex]

To prove that:

[tex]\Delta ABE\cong\Delta\text{CDE}[/tex]

We know that congruent parts of congruent triangles are congruent

[tex]\angle\text{AEB }\cong\angle CDE\text{ (vertically opposite angles)}[/tex]

Given that E is the midpoint of AC, therefore,

[tex]\begin{gathered} EA=EC\text{ } \\ EB=ED \end{gathered}[/tex]

By the SAS congruency theorem as illustrated above, it is sufficient to prove that the triangles are congruent

A choir concert platform consists of 6 rows. The number of performers increases by 2 witheach successive row. How many performers are there in all if the back row has 36performers?A 48B 84C 186D 372

Answers

In this problem, we have the sequence

inverse sequence

36,34,32,30,28,26

The sum is equal to

S=36+34+32+30+28+26

S=186

The answer is option C

In this problem, we have the sequence

inverse sequence

36,34,32,30,28,26

The sum is equal to

S=36+34+32+30+28+26

S=186

The answer is option C

Brett colors 25% of the total shapes on his paper. He colors 14 shapes. How many total shapes are there on Brett’s paper?

Answers

Answer:

56 i think because if 25% = 1/4 and 14 is 25% you would need to multiply 14 by 4 to get 100% or 4/4

it’s 24, this question has already been answered.

please help ………………. …………. ………… i already have the answer for part A but im having trouble with Parts B and C

Answers

In part B we must perform the following operation:

[tex](5a^3+4a^2-3a+2)+(a^3-3a^2+3a-9)[/tex]

The key here is to group the terms according to the power of a they have:

[tex](5a^3+4a^2-3a+2)+(a^3-3a^2+3a-9)=(5a^3+a^3)+(4a^2-3a^2)+(-3a+3a)+(2-9)[/tex]

Then, we can use the distributive property of the multiplication but in reverse:

[tex]b\cdot a+c\cdot a=(b+c)\cdot a[/tex]

If we do this in each of the terms between parenthesis we get:

[tex]\begin{gathered} (5a^3+a^3)+(4a^2-3a^2)+(-3a+3a)+(2-9)= \\ =(5+1)a^3+(4-3)a^2+(-3+3)a-7 \\ (5+1)a^3+(4-3)a^2+(-3+3)a-7=6a^3+a^2-7 \end{gathered}[/tex]

Then the answer for part B is:

[tex]6a^3+a^2-7[/tex]

In part C we must simplify:

[tex](4y^3-2y+9)-(2y^3-3y^2+4y+7)[/tex]

Here is important to remember that a negative sign before a parenthesis means that you have to change the sign of all the terms inside it. Then we have:

[tex](4y^3-2y+9)-(2y^3-3y^2+4y+7)=4y^3-2y+9-2y^3+3y^2-4y-7[/tex]

Now we can do the same thing we did in part B, we group the terms according to the powers of y:

[tex]4y^3-2y+9-2y^3+3y^2-4y-7=(4y^3-2y^3)+3y^2+(-2y-4y)+(9-7)[/tex]

Then we apply the distributive property in reverse:

[tex]\begin{gathered} (4y^3-2y^3)+3y^2+(-2y-4y)+(9-7)=(4-2)y^3+3y^2+(-2-4)y+2 \\ (4-2)y^3+3y^2+(-2-4)y+2=2y^3+3y^2-6y+2 \end{gathered}[/tex]

Then the answer for part C is:

[tex]2y^3+3y^2-6y+2[/tex]

Erin is buying produce at a store. She buys c cucumbers at $0.89 each and a apples at $0.99 each. What does the expression 0.89c + 0.99a represent? The expression represents the

Answers

One cucumber costs $0.89, so with Erin buys "c" cucumbers, the price he will pay for the cucumbers is the unitary price (0.89) times the number of cucumbers ("c"), so the price is 0.89c.

One apple costs $0.99, so with Erin buys "a" apples, the price he will pay for the apples is the unitary price (0.99) times the number of apples ("a"), so the price is 0.99a.

Then, to find the final price Erin will pay, we just need to sum both prices: all the cucumbers and all the apples:

Final price = 0.89c + 0.99a

So the expression represents the final price (or cost) Erin will pay for all products.

Part I: Domain and Range-identify the domain and range of each graph. Problem / Work Answe 2+ 6+ 2+ 1. Week 15 Homework Packet pdf 2003

Answers

Domain is the set of input values,

In the graph x axis show the domain

Where the x values is lies at -2,-1,0,1,2

Sothe domain will be :

[tex]\text{Domain =-2}\leq x\leq2[/tex]

Range is the set of output values,

In the graph the value of function at y axis is : 0,2,4,6,8-2,-4.....

So, the range will be :

[tex]\text{Range = -}\infty\leq y\leq\infty[/tex]

Inside. Make sure you don’t enter any spaces in your answers. This answer needs to be rounded to the nearest hundredth.

Answers

ANSWER

c = 14.14

EXPLANATION

To find the length of side AB, which is the hypotenuse of the right triangle ABC, we have to apply the Pythagorean Theorem,

[tex]AB^2=AC^2+BC^2[/tex]

Replace the known values and solve for c,

[tex]c^2=10^2+10^2=100+100=200\Rightarrow c=\sqrt{200}\approx14.14[/tex]

Hence, the value of c is 14.14, rounded to the nearest hundredth.

3.2 Similar FiguresIf ASRT - ACBD, find the value of x.Show all work.Hint: Don't let your eyes deceive you pay attention tothe similarity statement.

Answers

Find the ratio of corresponding sides:

SRT to CBD =

70/50 = 1.4

SR / 60 = 1.4

SR = 60 x 1.4

SR = 84

84= 11x-4

Solve for x:

84+4 = 11x

88= 11x

88/11 = x

8=x

A cannery needs to know the volume-to-surface-area ratio of a can to find the size that will create the greatest profit. Find the volume-to-surface-area ratio of a can.Hint : For a cylinder, S = 2πr2 + 2πrh and V = πr2h.a. 1/2b. 2(r+h) / rhc. πr(2r + 2h − rh)d. rh / 2(r+h)

Answers

SOLUTION

[tex]Volume\text{ }of\text{ }can=\pi r^2h[/tex][tex]Surface\text{ }area\text{ }of\text{ }can=2\pi r^2+2\pi rh[/tex]

The ratio can be established as shown below

[tex]\begin{gathered} \frac{\pi r^2h}{2\pi r^2+2\pi rh} \\ \frac{\pi r^2h}{2\pi r(r+h)} \\ \frac{rh}{2(r+h)} \end{gathered}[/tex]

The correct answer is OPTION D

May I please get help with this. For I have tried multiple times but still can’t get the right answer or the triangle after dilation?

Answers

Solution:

Given the triangle ABC as shown below:

To draw the image,

step 1: Determine the coordinates of the vertices of the triangle.

In the above graph,

[tex]\begin{gathered} A(6,7) \\ B(9,9) \\ C(8,6) \end{gathered}[/tex]

step 2: Evaluate the new coordinates A'B'C' of the triangle after a dilation centered at the origin with a scale factor of 2.

After a dilation centered at the origin with a scale factor of 2, the iniatial coordinates of the vertices of the triangle are multiplid by 2.

Thus,

[tex]\begin{gathered} A(6,7)\to A^{\prime}(12,14) \\ B(9,9)\to B^{\prime}(18,18) \\ C(8,6)\to C^{\prime}(16,12) \end{gathered}[/tex]

step 3: Draw the triangle A'B'C'.

The image of the triangle A'B'C' is as shown below:

Find the slope of the line in the graph below using: rise m= 0 6 -2)

Answers

Given data:

The given graph of the line.

The slope of the line passing through (4, 0) and (12, 2) is,

[tex]\begin{gathered} m=\frac{2-0}{12-4} \\ =\frac{2}{8} \\ =\frac{1}{4} \end{gathered}[/tex]

Thus, the solpe of the line is 1/4.

Step-by-step explanation:

Given data:

The given graph of the line.

The slope of the line passing through (4, 0) and (12, 2) is,

\begin{gathered}\begin{gathered} m=\frac{2-0}{12-4} \\ =\frac{2}{8} \\ =\frac{1}{4} \end{gathered}\end{gathered}

m=

12−4

2−0

=

8

2

=

4

1

Thus, the solpe of the line is 1/4.

is A square with a perimeter of 38 units is graphed on a coordinate grid. The square dilated by a scale factor of 0.8 with the origin as the center of dilation. If (x,y) represents the location of any point on the original square, which ordered pair represents the coordinates of the corresponding point on the resulting square? 0 (0.8x, 0.8y) 0 (x + 38, y + 38) O (x + 0.8, y + 0.8) O (38x, 38y)

Answers

Answer:

(0.8x, 0.8y)

Step-by-step explanation:

in a dilation with the origin as the center all point coordinates are multiplied by the scaling factor.

hi I need on this. $6000 invested at 5.5% interest, compounded annually. how how would i have in 6years?

Answers

In this case, we'll have to carry out several steps to find the solution.

Step 01:

Data:

principal = $6000

rate (interest) = 5.5%

time = 6 years

Step 02:

compound interest:

n = annually

n = 1

r = 5.5 % = 5.5 / 100 = 0.055

A = amount

[tex]A\text{ = P \lparen1 + r/n\rparen}^{nt}[/tex][tex]A\text{ = 6000 * \lparen1 + }\frac{0.055}{1})\placeholder{⬚}^{1*6}[/tex][tex]A\text{ = 6000 * \lparen1.3877\rparen = 8273.06}[/tex]

The answer is:

$8273.06

The confidence interval on estimating the heights of students is given as (5.4, 6.8). Find the sample mean of the confidence interval. A.6.8B.6.1C. 5.4D. 0.7

Answers

Solution

- The formula for finding the sample mean from the confidence interval is given below

[tex]\begin{gathered} \text{Given the Confidence interval,} \\ (A_1,A_2) \\ \\ \therefore\operatorname{mean}=\frac{A_1+A_2}{2} \end{gathered}[/tex]

- Thus, we can find the sample means as follows

[tex]\begin{gathered} A_1=5.4 \\ A_2=6.8 \\ \\ \therefore\operatorname{mean}=\frac{5.4+6.8}{2} \\ \\ \operatorname{mean}=\frac{12.2}{2} \\ \\ \operatorname{mean}=6.1 \end{gathered}[/tex]

Final Answer

The sample mean is 6.1 (OPTION B)

determine the number of real solutions for the following quadratic equation using the discriminate

Answers

Given equation:

[tex]y=x^2-3x-4[/tex][tex]a=1,b=-3,c=-4[/tex]

Discriminant:

[tex]\begin{gathered} b^2-4ac \\ (-3)^2-4(1)(-4) \\ =9+16 \\ =25 \end{gathered}[/tex]

Number of real solutions:

Since the discriminant is > 0 (that is ,it is a positive value)

Samuel and Kathleen deposit $700.00 into a savings account which earns 4% interestcompounded monthly. They want to use the money in the account to go on a trip in 2 years.How much will they be able to spend?

Answers

To find how much they will be able to spend, we have to use the compoud interest formula, so:

[tex]\text{Amount}=700000\cdot(1+0.04)^{24}[/tex][tex]Amount=1794312.92[/tex]

Find sin 2x, cos 2x, and tan 2x if tan x= -3/2 and x terminates in quadrant IV.

Answers

Answer:

• sin 2x = -12/13

,

• cos 2x = -5/13

,

• tan 2x = 12/5

Explanation:

Given that

[tex]\tan x=-\frac{3}{2}[/tex]

Then

[tex]\begin{gathered} \sin2x=\frac{2\tan x}{1+\tan^2x} \\ \\ =\frac{2(-\frac{3}{2})}{1+(-\frac{3}{2})^2}=\frac{-3}{\frac{13}{4}} \\ \\ =-3\times\frac{4}{13}=-\frac{12}{13} \end{gathered}[/tex][tex]\begin{gathered} \cos2x=\frac{1-\tan^2x}{1+\tan^2x}=\frac{1-(-\frac{3}{2})^2}{1+(-\frac{3}{2})^2} \\ \\ =\frac{1-\frac{9}{4}}{1+\frac{9}{4}}=\frac{-\frac{5}{4}}{\frac{13}{4}}=-\frac{5}{4}\times\frac{4}{13}=-\frac{5}{13} \end{gathered}[/tex][tex]\begin{gathered} \tan2x=\frac{2\tan x}{1-\tan^2x}=\frac{2(-\frac{3}{2})}{1-(-\frac{3}{2})^2} \\ \\ =\frac{-3}{1-\frac{9}{4}}=\frac{-3}{-\frac{5}{4}}=-3\times\frac{-4}{5}=\frac{12}{5} \end{gathered}[/tex]

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