This type of bond is between two metals described as a "Sea of Electrons'?

Explanation:

If n = 2 we have this posibility:

This shell contains 2 subshells: s and p

Subshell 2s can only contain 2 electrons

Subshell 2p can only contain 6 electrons

Answer: In total, we can have 8 electrons in n = 2

Answer

2.5 moles of N₂ are needed to react with 7.5 moles of hydrogen gas

Explanation

Given:

Equation: N₂ + 3H₂ → 2NH₃

Moles of H₂ = 7.5 moles

What to find:

The moles of nitrogen gas (N₂) needed to react with 7.5 moles of hydrogen gas

Step-by-step solution:

Let the mole of N₂ needed be x.

From the given balanced chemical equation:

3 moles of H₂ react with 1 mole of N₂

Therefore, 7. 5 moles of H₂ will react with x moles of N₂

Cross multiply

Answer

HBr is the limiting reactant

Al is the excess reactant.

Explanation

Given:

Moles of Al = 3.22 mol

Moles of HBr = 6.96 mol

Equation: 2 Al + 6 HBr → 2 AlBr₃ + 3 H₂

What to find;

The limiting and excess reactants.

Solution:

Note: The limiting reactant is the reactant that is completely used up in a reaction, and thus determines when the reaction stops. While the excess reactant is the opposite.

From the given balanced chemical equation;

2 moles of Al require 6 moles of HBr

Therefore, the given 3.22 moles of Al will require (3.22/2) x 6 = 9.66 moles of HBr

Since the given moles of HBr is 6.96 mol not up to 9.66 moles required, then HBr is the limiting reactant and Al is the excess reactant.

HBr is the limiting reactant

Al is the excess reactant.

Answer:

5.546262 x 10^24 formula units

Explanation:

Use avogadro's number

9.21 mol CaO ((6.022 x 10^23 formula units CaO)/1 mol CaO)) = 5.546 x 10^24.

I rounded to 3 sig figs.

Answer

Explanation

Given:

Mass composition: 3.758 g carbon, 0.316 g hydrogen, and 1.251 grams oxygen.

What to find:

The empirical formula for the substance.

Step-by-step solution:

The first step is to convert the number of grams of each element into moles as shown below using the molar masses of H = 1.00784 g/mol and C = 12.011 g/mol and O = 15.999 g/mol

Note: Mole = Mass/Molar mass

Moles C = 3.758g/12.011 g/mol = 0.31 mol

Moles H = 0.316g/1.00784 g/mol = 0.31 mol

Moles O = 1.251g/15.999 g/mol = 0.078 mol

Now, let's divide the number of moles of each element by the smallest number obtained:

C = 0.31/0.078 = 4

H = 0.31/0.078 = 4

O = 0.078/0.078 = 1

The empirical formula for the compound is C₄H₄O₁

Step 1

The reaction provided:

2 Mg (s) + O2 (g) => 2 MgO (s) (completed and balanced)

-----------

Step 2

Information provided:

40.0 g of O2 which react completely

---

Information needed:

The molar masses of:

O2) 32.0 g/mol

MgO) 40.3 g/mol

-----------

Step 3

By stoichiometry,

2 Mg (s) + O2 (g) => 2 MgO (s)

32.0 g O2 ------- 2 x 40.3 g MgO

40.0 g O2 ------- X

X = 40.0 g O2 x 2 x 40.3 g MgO/32.0 g O2

X = 101 g MgO

Answer: C 101 g

She will keep evidence separated so it doesn’t get contaminated demonstrates the understanding of Locard’s Exchange Principle and is denoted as option C.

This principle states that an individual who commits a crime will bring something into the crime scene and leave with something from it. This also explains that they can be used as evidence during investigation by the appropriate authorities.

Since we are aware that new substances are always brought into and carried away from the crime scene then it is best to keep the evidence separated so it doesn’t get contaminated.

This ensures that the results gotten from the analysis and investigation are accurate and is therefore the reason why option C was chosen as the correct choice.

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The formula of magnesium hydroxide is Mg(OH)2.

Magnesium hydroxide is an inorganic compound having the chemical formula of Mg(OH)2. It is present in nature as mineral brucite. It is a white solid substance with low solubility in water. Magnesium hydroxide is a component of antacids such as milk of magnesia. Extended use or overuse of this medication for constipation results in dependence on laxatives and constipation. Overuse of Magnesium hydroxide also causes diarrhea that does not go away, dehydration, and mineral imbalances. Severe nausea, vomiting, or diarrhea are the symptoms of using a high dose of magnesium hydroxide. After using a medicine such as a laxative, nausea, vomiting or diarrhea can be cured.

So we can conclude that Mg(OH)2 is the correct formula for magnesium hydroxide.

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Answer:

Reducing the activation energy and providing an alternative reaction pathway for the reaction to happen

Explanation:

A lower activation energy means that reactants will need less energy to successfully react to make products, meaning that more successful collisions will happen between reactants, increasing the rate of reaction

A catalyst reduces the activation energy of the reaction, speeding it up. By decreasing the activation energy, the energy hurdle that must be cleared for a chemical reaction to take place, catalysts improve the efficiency of this process.

By decreasing the activation energy, the energy hurdle that must be cleared for a chemical reaction to take place, catalysts improve the efficiency of this process.

As a result, catalysts facilitate the formation of chemical bonds between atoms to create novel combinations and new compounds.

A catalyst is a chemical that may be included in a reaction to speed up the process without being consumed. Typically, catalysts shorten the activation energy of a process or alter its mechanism. Proteins called enzymes serve as catalysts in biological processes.

Thus, the catalyst reduces the activation energy of the reaction, speeding it up

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In order to properly balance an equation, we need to make sure that the same amount of elements on the reactants side matches the number of elements on the products side, we can do that by increasing the number in front of each molecule, the so called stoichiometric coefficient. In the reaction from the question we can properly balance by adding the following stoichiometric coefficients

For this question we have:

CaCl2 -> Ca + 2 Cl

The balanced reaction is:

According to this, 3 moles of H2 produce 2 moles of NH3. Use this ratio to find the number of moles of NH3 produced:

It means that 18 moles of H2 are needed to produce 12 moles of NH3

Dalton's Law or Law of Partial Pressures says that the total pressure of a mixture of gases is equal to the sum of the partial pressures of each gas that composes it. The partial pressure of a gas on the other hand is defined as the pressure it would exert if it were alone in the container.

So we need to sum all the values:

64 + 50.8 = 114.8 kPa

Answer: 114.8 kPa

Answer

None of these

Explanation

The option for 2-bromo-5propylbenzaldehyde does not seem to be provided

ANSWER

The original concentration of the solution is 0.147 mol

EXPLANATION

Given that;

The volume of water is 350.0mL

The volume of NaCl solution is 2.3L

The final concentration of the solution is 0.967M

To find the original concentration of the solution, follow the steps below

Step1: Write the dilution formula

Where

• M1 is the original concentration of the solution

• V1 is the original volume of the of the solution

• M2 is the final concentration of the solution

• V2 is the final volume of the solution

Step 2: Convert the volume of water to L

Recall, that 1mL is equivalent to 0.001L

Step 3; Find the original concentration of the solution by substituting by the given data into the formula in step 1

Hence, the original concentration of the solution is 0.147 mol

Answer

a. 74.2

Explanation

Given that:

The initial temperature, T₁ = 63.2 °C + 273 = 336.2 K

Initial pressure, P₁ = 57.3 kPa

The final volume, V₂ = 15.56 mL

Final temperature, T₂ = 138.7°C + 273 = 411.7 K

Final pressure, P₂ = 334.6 kPa

What to find:

The initial volume, V₁.

Step-by-step solution:

The initial volume, V₁ can be calculated using the combined gas law equation.

Hence, its initial volume at 63.2 °C and 57.3 kPa is 74.2 mL

Answer:

D- Br

Explanation:

The correct answer in this case is binding energy, which is the energy released when a collection of nucleons form a nucleus.

The correct answer is the last choice.

Answer:

18.82L of oxygen gas are needed.

Explanation:

1st) It is necessary to write and balance the chemical reaction:

2nd) From the balanced reaction, we can see that 3 moles of oxygen gas (O2) react with 4 moles of aluminum (Al). To convert moles to grams, it is necessary to use the molar mass of oxygen (32g/mol) and aluminum (27g/mol):

- O2 conversion:

- Al conversion:

Now we can see that 96g of O2 react with 108g of Al.

3rd) We have to calculate the grams of O2 that will react with 30.25g of Al:

Using the molar mass of oxygen, we know that 26.89g represent 0.84 moles of O2.

4th) Finally, a mole of a gas at STP conditions occupies a volume of 22.4L. With this number and the moles of oxygen gas, we can calculate the liters:

So, 18.82L of oxygen gas are needed.

When the magnesium ribbon is burned, it enters the carbon dioxide gas jar and continues to burn. The carbon is left behind as a black soot and extra energy is released as a result of the reaction where the magnesium atoms join the oxygen in the carbon dioxide to form magnesium oxide.

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We need to first write the balanced equation:

we are given the following:

mass of butane = 29.0 g

mass of carbon = 88.0 g

mass of water = 45.0 g

We want the mass of O2 that reacted.

C4H10 is the limiting reactant, and we know the masses of products produced. We can use that to find out how much oxygen reacted.

We can use CO2:

number of moles of CO2 = 88.0/44.01 = 1.9995 mol

The molar ratio between O2 and CO2 is 13:8

Therefore the number of moles of O2 = 1.9995 x (13/8) = 3.249 mol

Now that we have the number of moles, we can calculate the mass.

m = n x M

m = 3.249 mol x 31.998 g/mol

m = 103.97 g

In this question, we have to find the number of atoms in 12.5 moles of Sulfur, and the way to do it is by using the Avogadro's number, which is 6.02*10^23 atoms, this value represents how many atoms we have in 1 single mol of any element. Therefore in 12.5 moles we will have:

1 mol = 6.02*10^23 atoms

12.5 moles = x atoms

x = 7.52*10^24 atoms of Sulfur in 12.5 moles

The concentration of fluoride ions after the addition of 10.00 mL of 0.0100 M HCl to 25.0 mL of this solution is 0.009 M

One of the terms for concentration that is used frequently in solutions would be molarity. It would be explained as the number of moles of solute in one liter of solution.

Molarity can be determined by the formula:

Molarity = moles of solute/ volume of solution

Moles of the HCl can be determined by using the formula:

Moles of solute = molarity × volume of the solution.......(i)

It is given that,

Molarity = 0.0100 M.

Volume = 10.0 mL .

Put the value of given data in above equation:

Moles of solute = (0.0100 M) × (10.0 mL) ×([tex]10^{-3}[/tex]/1 mL)

Moles of solute =  [tex]10^{-7}[/tex] M

Now, determine moles of HF.

Moles of solute = (0.126 M) × (25 mL) ×([tex]10^{-3}[/tex]/1 mL)

Moles of solute = 0.00315 M

Total moles = 0.00315 M + 0.0000001 M =0.0031501 M

Total volume = 10.00 mL + 25 mL = 35 mL.

Molarity can be determined by the formula:

Molarity = moles of solute/ volume of solution

Molarity = 0.0031501 M / 35 (1/[tex]10^{-3}[/tex])

Molarity = 0.009 M

Therefore, molarity will be 0.009 M.

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This elements or substances that are not a metal are called non-metals.

I think that the answer is Non-metal

When salt dissolves in water, dissociation occurs. This dissociation forms two ions, one positive and one negative. Water is polar and its molecules has poles negatives and positives. So positive poles of water will surround the negative ions. While negative poles will surround the positive ions.

Answer: Alternative "B"

a. If XF is covalent, X couldn't be a metal. Because covalent bonding occurs between nonmetals. So this alternative is False.

b. If XF is ionic, X could be a nonmetal. Also False. Ionic bonding occurs between a metal and a nonmetal. In this case, we already have a nonmetal, which is F.

c. If XF is covalent, the name uses prefixes. True. When we have a covalent compound, the name of the nonmetal on the left has a prefix indicating the number of atoms of it.

d. If XF is covalent, X has a charge of +1. False. This would happen if it was ionic.

Answer: Alternative "C"

we are required to determine the significant figures in each of the numbers.

1) 4 significant figures

2) 5 significant figures

3) 9 significant figures

4) 5 significant figures

5) 3 significant figures

6) 4 significant figures

7) 5 significant figures

8) 3 significant figures

9) 3 significant figures

10) 3 significant figures

If the photon has a frequency of   3.16 × 10 ⁷ Hz, then the energy of the the photon as per Planck's law would be 1.978× 10⁻²⁶ Joules

It can be understood in terms of the distance between any two similar successive points across any wave.

C = λν

As given in the problem we have to calculate the energy of the light if the frequency of light is  3.16 × 10 ⁷ Hz

The energy of the photon = h ν

                                           = 6.26 × 10⁻³⁴ × 3.16 × 10 ⁷

                                           = 1.978× 10⁻²⁶ Joules

Thus, If the photon has a frequency of   3.16 × 10 ⁷ Hz, then the energy of the the photon as per Planck's law would be 1.978× 10⁻²⁶ Joules.

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According to the Planck's equation,the energy and frequency of blue light are 4.699×10[tex]^-19[/tex] J and 2.363×10⁶ m[tex]^-1[/tex] respectively.

Max Planck discovered the theory which stated that energy is transferred in the form of discrete packs which are called quanta and thus proposed an equation called the Planck's equation which relates energy and frequency of a photon and is given as, E=hcυ or in terms of wavelength it is ,E=hc/λ.

The equation makes use of a constant which is called the Planck's constant and it's value is 6.626×10[tex]^-34[/tex] Js.

In the given problem, energy is calculated as,E=6.626×10[tex]^-34[/tex]×3×10⁸/4.23×10[tex]^-7[/tex]=4.699×10[tex]^-19[/tex] J.

The frequency  of light is calculated as follows,4.699×10[tex]^-19[/tex]/19.878×10[tex]^-26[/tex]=2.363×10⁶ m[tex]^-1[/tex].

Thus , the energy and frequency of blue light are  4.699×10[tex]^-19[/tex] J and 2.363×10⁶ m[tex]^-1[/tex] respectively.

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